Will the current increase or decrease if you increase voltage?

Yes, an object can have zero displacement even if it has moved through a distance.

Displacement is a vector quantity that represents the change in position from the initial point to the final point.Yes, an object can have zero displacement even if it has moved through a distance. It takes into account the direction of motion as well as the magnitude.To illustrate this, consider a scenario where an object moves in a circular path and returns to its initial position. In this case, the object has covered a certain distance along the circumference of the circle. However, since it ends up at the same position it started, the displacement is zero because there is no change in its position relative to the initial point.

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The gravitational force from the sun controls the orbit of the moon and the planet besides gravity.

Anything in the universe if has mass, then it is tends to have some gravitational interaction with other objects having some mass.

The moon and the planet interact with each other due to the gravity of the planet. Beside this gravity, one more force that is responsible is the gravitational force due to the sun.

The gravitational force of the sun makes the earth rotate around the sun, and it indeed result in the rotation of the moon around the planet.

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Answer: 180

Explanation: Acellus

This equation gives the magnitude of the electric field generated by a point charge Q. The distance r in the denominator is the separation between the point of interest and the point charge Q. Or the center of a spherical charge.

It is simple to determine the size of the electric field by calculating the force per charge on the test charge. From this definition, the common metric units for electric field strength are derived. Electric field units would be force units divided by charge units, as the definition of an electric field is a force per charge.

F = |qvBsin()| calculates the magnetic force's magnitude. The following factors are involved in determining the force's direction. A plane is first defined by the magnetic field vector, B, and the velocity vector, v. In or out of this plane, the magnetic force is perpendicular to it.

Therefore, The electric force F, or Coulomb force, exerted per unit positive electric charge q at that place can be used to determine an electric field's strength, or E = F/q.

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Answer:

the velocity of the car is 30 m/s.

Explanation:

Given;

Centripetal force on the car, F = 900 N

mass of the car, m = 10 kg

diameter of the circular path, d = 20 m

radius of the circular path, r = 10 m

The velocity of the car is calculated as follows;

\(F = \frac{mv^2}{r} \\\\mv^2 = Fr\\\\v^2 = \frac{Fr}{m} \\\\v = \sqrt{\frac{900 \times 10}{10} } \\\\v = 30 \ m/s\)

Therefore, the velocity of the car is 30 m/s.

Answer:

V = 0.87 volt

Explanation:

Given that,

Charge, \(q=7.3\times 10^{-17}\ C\)

Electric potential energy, \(U=6.4\times 10^{-17}\ J\)

We need to find the value of electric potential at a point. The relation is as follows :

\(V=\dfrac{U}{q}\)

Where

V is electric potential

So,

\(V=\dfrac{6.4\times 10^{-17}}{7.3\times 10^{-17}}\\\\V=0.87\ V\)

So, the value of the electric potential at a point is equal to 0.87 Volts.

The time frame and scale of a landslide can vary greatly, and it's necessary to have more specific information to give a more precise answer.

The time frame of a landslide can vary widely depending on the circumstances. Some landslides can occur suddenly and quickly, while others can happen gradually over a longer period of time. Therefore, it's difficult to provide a general answer without more information about the specific landslide in question. Similarly, the scale of the area affected by a landslide can also vary widely, ranging from small localized events to large-scale disasters that affect entire communities or regions. Once again, the size of the area affected by a landslide depends on many factors, including the type of landslide.

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Maintaining open spaces with healthy vegetation will probably limit water flow through urban areas and reduce the likelihood of flooding downstream.

In a drainage basin, flash floods happen in the top portion, whereas downstream floods happen in the bottom portion.

Contrary to popular belief, flood stage downstream of a dam can actually be increased for moderate and big floods, even though it is lower for minor floods.

Because of the increase in discharge downstream, both width and depth increase. The cross sectional shape of the stream will change as discharge rises, becoming deeper and wider.

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If you weigh 150 lb on Earth and you stood on a planet having twice the mass of Earth and a radius twice as big as Earth's radius, you would weigh 75 lb.


The weight of an object on a planet is given by the formula:

W = m*g

Where W is the weight, m is the mass of the object, and g is the acceleration due to gravity on the planet.

The acceleration due to gravity on a planet is given by the formula:

g = (G*M)/r^2

Where G is the gravitational constant, M is the mass of the planet, and r is the radius of the planet.

So, if the mass of the planet is twice the mass of Earth, and the radius is twice the radius of Earth, the acceleration due to gravity on the planet would be:

g = (G*2M)/(2r)^2

Simplifying the equation gives:

g = (G*2M)/(4r^2)

g = (G*M)/(2r^2)

Since the acceleration due to gravity on Earth is given by:

g = (G*M)/r^2

The acceleration due to gravity on the planet is half the acceleration due to gravity on Earth.

So, if you weigh 150 lb on Earth, you would weigh:

W = m*g

W = 150*(g/2)

W = 75 lb

So, you would weigh 75 lb on the planet.

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At the lowest point of her swing, she can withstand a maximum speed of 10.78 m/s.

Given that,

Mass of the carpenter = 61.7 kg

Length of the rope = 11.5 m

Capable force = 1229 N

Centripetal force acting on the body,

F = mv²/r = (61.7× v²)/11.5 = 5.37 v²

Gravitational force acting on her is

F = m × g = 61.7 × 9.81 = 605.28 N

By summing up gravitational and centripetal forces to get the total available force,

5.37 v² + 605.28 = 1229

5.37 v² = 623.72

v² = 116.15

v = 10.78 m/s

Hence, the maximum speed at the low point of her swing is 10.78 m/s.

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Answer:

observation

hypothesis

theory

matter

agent

experimental group

control group

temperature

particle

criteria

Explanation:

Answer:

Q=mc∆tita.

490J= m× 0.5J/Kg/C × (18-0°C)

490J= m × 9J/kg

490J

9J/Kg = m.

m= 54.4Kg

Answer: freezing

Explanation:

Answer:

Without seeing the image of the air mass, it is difficult to determine the exact type of air mass that is moving south from Canada into the United States. However, based on the general principles of air masses, we can make an educated guess.

In general, when a cold air mass moves into an area, it is likely to be a continental polar (cP) air mass. A continental polar air mass is characterized by cold and dry air that forms over land in high latitudes. It is typically stable and brings clear skies and cold temperatures.

So, it is possible that a continental polar air mass is moving south from Canada into the United States. However, other types of air masses could also be involved, depending on the specific weather patterns and atmospheric conditions in the region.

Explanation:

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Answer:

Ek = 4250 J

Explanation:

Data:

Formula:

Replace and solve:

It has 4250 Joules of Kinetic Energy.

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most common finishes applied to aluminum curtain wall componets is fluoropolymer paint or anodized finish.

Anodizing is an electric process that forms a very thick oxide layer with integral color .

An anodized surface is very durable and can be had in many colors , although it is not generally capable of producing very bright colors .

Anodizing is commonly used to improve the corrosion resistance and wear resistance of aluminum parts. It can also provide other desirable benefits, like improved heat dissipation and the ability to accept dyes.

Unlike paints and coatings, anodizing does not apply an external product to the exterior of the aluminum. Instead, an electrochemical process is used to stimulate the naturally-occurring layer of aluminum oxide into growing thicker. This protects the underlying aluminum from its environment, and can even accept dyes. However, the color possibilities for anodizing are not as abundant as in powder coating.

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In the given exponential fuction,

The base of the given exponential function is e

Answer:

Charging a phone is the exact opposite of discharging a battery's energy. By supplying current (the manipulated variable), a charger transfers lithium ions from the positive electrode to the negative electrode, thus restoring energy

Explanation:

The properties of waves are: wavelength, time period.

Sound wave is considered a mechanical wave because it requires medium to travel.

A mechanical wave is one whose energy cannot be transmitted via a vacuum. To transfer their energy from one place to another, mechanical waves need a medium.

A mechanical wave is something like a sound wave. A vacuum can not be traversed by sound waves.

Units of time and space can be used to measure the fundamental characteristics of waves. The length between wave crests, or wavelength (L), and the time it takes a wave to pass a fixed point, or period (T), are two characteristics that can be measured directly.

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Answer:

The value of the resistance is 3.99 kΩ

Explanation:

The value of the resistance, given that a heart pacemaker fires 89 times a minute, and each time a 36.0-nf capacitor is charged to 0.632 of its full voltage, is 3.99 kΩ.

How to determine the value of the resistance?

We know that a pacemaker fires 89 times per minute, charging a 36.0-nf capacitor each time, and the capacitor is charged to 0.632 of its full voltage.

The formula for determining the time constant is: τ = RC and the formula for determining the voltage of a capacitor as it charges is: Vc = Vmax(1 - e^(-t/τ)) Using the following information, we can compute the value of the time constant:

τ = RCτ = (0.632Vmax * C) / IV max = 9 V The value of the time constant is τ = RC = (0.632Vmax * C) / I = (0.632 * 9 * 10^-3) / I = 5.67 * 10^-3 / I To find the value of the resistance, R, we'll use the frequency of the pacemaker (f = 89/60 Hz), which is the number of times it fires per second.

RC = 1/fRC = (5.67 × 10^-3)/IR = RCfR = [(5.67 × 10^-3)/I](89/60)R = 3.99 kΩ

Therefore, the value of the resistance, given that a heart pacemaker fires 89 times a minute, and each time a 36.0-nf capacitor is charged to 0.632 of its full voltage, is 3.99 kΩ.

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To calculate the total mass of interstellar matter contained within a volume equal in size to planet Earth, we first need to determine the volume of Earth.

The average radius of Earth is approximately 6,371 kilometers, or 6.371 × 10^6 meters. The volume of a sphere can be calculated using the formula:

V = (4/3)πr³

Substituting the radius, we have: V = (4/3)π(6.371 × 10^6)³

Calculating this value gives us: V ≈ 1.083 × 10^21 cubic meters

Given that the average density of interstellar gas within the Local Bubble is roughly 10^3 hydrogen atoms/m³, we can now calculate the total mass. The mass of a hydrogen atom is 1.7 × 10^-27 kg.

First, we need to convert the density from hydrogen atoms/m³ to kg/m³:

Density ≈ 1.7 × 10^-24 kg/m³

To find the total mass, we multiply the density by the volume:

Mass = Density × Volume

Mass ≈ (1.7 × 10^-24 kg/m³) × (1.083 × 10^21 m³)

Mass ≈ 1.84 × 10^-3 kg

Therefore, the total mass of interstellar matter contained within a Bubble volume equal in size to planet Earth is approximately 1.84 × 10^-3 kilograms, expressed using two significant figures.

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Answer:

10 N south

Explanation:

It cancels out the north allowing the object to keep going west :)

i think this might be wrong so like don't trust me-

The net force on an object is zero that is pulled with forces of 80 newtons to the right and 80 newtons to the left.

Net force is equal to sum of all the force acting on a body.

The formula for net force if n force are acting on it:

                       \(F_{net}=F_{1}+ F_{2}+F_{3}.....F_{n}\)

In this case the two forces are equal but opposite in direction.

Putting the values in the formula

\(F_{net} = 80+(-80)\) (since forces are equal but opposite)

\(F_{net}= 0\)

So the net force acting on the object is zero because the forces are equal and opposite.

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The net force on an object that is pulled with forces of 80 newtons to the right and 80 newtons to the left is: 0 newtons

To solve this problem the formula of net force and the procedure that we have to use is:

Fr = ∑F

Where:

Information about the problem:

Applying the resultant force formula we get:

Fr = ∑F

Fr = F1 + F2

Fr = 80 newtons - 80 newtons

Fr= 0 newtons

We can say that the resultant force is the algebraic sum of all the forces acting on a body.

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Since the cosine function is equal to 1 when its argument is equal to an even multiple of π/2, and -1 when its argument is equal to an odd multiple of π/2, we can see that the wave function has antinodes at both ends of the machine .

The boundary conditions for a machine that is unclamped at both ends are that the displacement (y) of the machine at both ends is equal to zero. Mathematically, this can be written as:

y(0, t) = 0 and y(L, t) = 0

Substituting these boundary conditions into the given formula for the wave function, we get:

y(0, t) = Am cos(2πfmt)cos(0) = 0

y(L, t) = Am cos(2πfmt)cos(mπL/L) = 0

Since the cosine function is equal to zero when its argument is equal to an odd multiple of π/2, we can set the argument of the second cosine function equal to (2n - 1)π/2, where n is an integer. This gives us:

mπL/L = (2n - 1)π/2

Solving for m, we get:

m = (2n - 1)(2/L)

Therefore, the possible values of m are odd multiples of (2/L), i.e., m = 1/L, 3/L, 5/L, and so on.

Substituting these values of m back into the wave function, we get:

y(x,t) = Am cos(2πfmt)cos(mπx/L) = Am cos(2πfmt)cos((2n - 1)πx/2L)

Since the cosine function is equal to 1 when its argument is equal to an even multiple of π/2, and -1 when its argument is equal to an odd multiple of π/2, we can see that the wave function has antinodes at both ends of the machine (i.e., at x = 0 and x = L) when n is even, and nodes at both ends when n is odd.

Therefore, we have shown that the wave function for a machine that is unclamped at both ends has antinodes at both ends.

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Answer:

1 / f = 1 / i + 1 / o             1 / f = (o + i) / i o

f = i o / (o + i)

f = -26.5 * 8.25 / (8.25 - 26.8)

f = -221 / -.308 = 11.8 cm

To calculate the expected voltage across the capacitor and resistor, we need to use the peak-to-peak voltage of 4V and the frequency of 1000 Hz. The peak-to-peak voltage represents the difference between the maximum and minimum voltage levels in a waveform.

First, convert the peak-to-peak voltage to RMS voltage by dividing by the square root of 2:
Vrms = Vpp / √2 = 4V / √2 ≈ 2.83V
Next, we need to know the capacitance of the capacitor (C) and the resistance of the resistor (R) to determine the impedance of each component at 1000 Hz. Since these values are not provided, we will represent them as C and R.
Calculate the capacitive reactance (Xc) using the formula: Xc = 1 / (2π * f * C)
Calculate the impedance (Z) of the RC circuit using the formula: Z = √(R^2 + Xc^2)
Finally, use Ohm's Law to find the voltage across the capacitor (Vc) and resistor (Vr): Vc = Vrms * (Xc / Z)
Vr = Vrms * (R / Z)
In summary, to find the expected voltage across the capacitor and resistor, you need to convert the given peak-to-peak voltage to RMS voltage, calculate the capacitive reactance and impedance, and apply Ohm's Law. Since the values of C and R are not provided, the final answer is represented in terms of these variables.

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The cycle time of the entire line is 30.00528 minutes per part.

To calculate the cycle time of the entire line, we need to consider the processing times, failures, and repairs of both the milling machine and the turning machine.

For the milling machine:

Mean processing time (t0) = 15 mins

Standard deviation of processing time (sigma0) = 3 mins

Mean time to failure (MTTF) = 750 mins

Mean time to repair (MTTR) = 200 mins

For the turning machine:

Mean processing time (t0) = 15 mins

Standard deviation of processing time (sigma0) = 3 mins

Mean time to failure (MTTF) = 110 mins

Mean time to repair (MTTR) = 38 mins

We also know that the arrival rate to the milling machine is 1.2 parts/hr, with a coefficient of variation (CV) of 1.

To calculate the cycle time, we can use the following formula:

Cycle time = Processing time + Failure time + Repair time

Processing time:

The processing time is the sum of the mean processing times of the milling machine and the turning machine:

Processing time = t0 (milling machine) + t0 (turning machine) = 15 mins + 15 mins = 30 mins

Failure time:

The failure time is the inverse of the MTTF, considering the arrival rate:

Failure time = 1 / (MTTF * Arrival rate) = 1 / (750 mins * (1.2 parts/60 mins)) = 0.00111 parts/min

Repair time:

The repair time is the inverse of the MTTR, considering the coefficient of variation (CV):

Repair time = 1 / (MTTR * CV) = 1 / (200 mins * 1.2) = 0.00417 parts/min

Cycle time:

Cycle time = Processing time + Failure time + Repair time = 30 mins + 0.00111 parts/min + 0.00417 parts/min

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The production function will have constant returns to scale if 2αβ = 1

Constant returns to scale (CRS) implies that if all inputs increase by a factor of λ, the output increases by λ as well. The requirement for constant returns to scale (CRS) in a Cobb-Douglas production function with a new input factor is given by the sum of exponents on all variables equal to 1.

In this case, Y = AKαLβMγ.

Thus, we have that α + β + γ = 1 for constant returns to scale in K, L, and M, because the sum of the exponents is 1.

If the sum of the exponents is less than 1, it indicates decreasing returns to scale. If the sum of the exponents is greater than 1, it indicates increasing returns to scale. If we take γ = 0, we obtain the production function used in class, which is Y = AKαLβ, thus α + β = 1 for constant returns to scale in K and L.

When γ = 0, the answer we get is consistent with what we learned in class. Now, we consider the constant elasticity of substitution (CES) technology, where Y = [aKα + bLα]β. The production function will have constant returns to scale (CRS) in K and L if the sum of the exponents of K and L is equal to 1.

Therefore, αβ + αβ = 1, implying 2αβ = 1.

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Tennsion 1= horizontal = 484.94 N

Tension 2 = slanted string = 560 N

Explanation

Step 1

Free body diagram

Newton's first law says that if the net force on an object is zero, like in this case the mass is in rest,then that object will have zero acceleration

so

Step 1

set the equations:

a) for x-axis

b) for y -axis

Step 2

Solve the equations

a) solve for T2in equation (2)

b) replace the T2 value in equation (1) to find T1

therefore

Tennsion 1= horizontal = 484.94 N

Tension 2 = slanted string = 560 N

I hope this helps you

(a) a thin layer of vacuum is provided between the two walls of flask, to minimise the heat loss by conduction , because for conduction medium (molecules) is required , but now medium is absent .

.(b) the two walls are silvered to minimise the heat loss by radiation , because a shiny surface is a bad absorber and bad emitter of radiation i.e. good reflector of heat , so prevents the heat exchange between content of flask and surrounding .

(c) the lid of flask is provided with a tight cork stopper to minimise the heat loss by convection , so that convection currents cannot go out .

(d) a plastic (or metal) case is provided with a flask , to protect the flask from physical damage

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