Will only name Brainliest if its the correct answer!

Will Only Name Brainliest If Its The Correct Answer!

Answers

Answer 1

Answer:

2

Step-by-step explanation:

\( \frac{( {( {x}^{3} {x}^{4} )}^{2}) }{ {( {x}^{5} {x}^{3} )}^{z} } = {x}^{ - 2} \\ \\ \frac{( {( {x}^{3 + 4} )}^{2}) }{ {( {x}^{5 + 3} )}^{z} } = {x}^{ - 2} \\ \\ \frac{ {(( {x}^{7} ) }^{2}) }{ {( {x}^{8} )}^{z} } = {x}^{ - 2} \\ \\ \frac{ {x}^{7 \times 2} }{ {x}^{8 \times z} } = {x}^{ - 2} \\ \\ \frac{ {x}^{14} }{ {x}^{8z} } = {x}^{ - 2} \\ \\ {x}^{14 - 8z} = {x}^{ - 2} \\ \\ 14 - 8z = - 2 \\ \\ 14 + 2 = 8z \\ \\ 16 = 8z \\ \\ z = \frac{16}{8} \\ \\ z = 2\)

Answer 2

Answer:

sorry late. from next time it will be in time

Will Only Name Brainliest If Its The Correct Answer!

Related Questions

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.y = ex, y = 0, x = −2, x = 2;about the x-axisV =Sketch the region.

Answers

The required volume of the solid which was obtained by rotating the region bounded by the curve about a line is equal to  ( π/2 ) (  e⁻⁴  + e⁴).

Graph is attached.

Volume of the solid rotating the region bounded by the curves about a line with y = eˣ with x = −2, x = 2 about x-axis.

=π \(\int_{-2}^{2}\) [( eˣ - 0)² ] dx

= π \(\int_{-2}^{2}\) e⁽²ˣ⁾ dx

= π (e²ˣ) / ( 2 \(|_{-2}^{2}\)

= ( π/2 )[  e⁻⁴  - e⁴  ]

= ( π/2 ) (  e⁻⁴  +  e⁴ )

Graph is attached.

Therefore, the volume of the solid of the rotating region bounded by curves about line is equal to  ( π/2 ) (  e⁻⁴  +  e⁴ ).

Graph is attached.

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Find the volume V of the solid obtained by rotating the region bounded by the given curves about the

1. y=logb(2x-6) and b>1 what would the domain be in set builder notation?
2. what would be the y-intercept of this graph: f(n)=a^n + b where a is not equal to 1 and a > 0

Answers

The domain of the function y = log_b(2x – 6), where b > 1, is {x | x > 3}.
The y-intercept of the function f(n) = a^n + b, where a is not equal to 1 and a > 0, is the point (0, b).

The domain of the logarithmic function y = log_b(2x – 6), where b > 1, refers to the set of all valid input values for x. In this case, we need to ensure that the argument of the logarithm, 2x – 6, is greater than zero.

This is because the logarithm function is only defined for positive values.
To determine the domain, we solve the inequality 2x – 6 > 0:
2x – 6 > 0
2x > 6
X > 3

Therefore, the domain is expressed in set-builder notation as {x | x > 3}, meaning all values of x greater than 3.

The y-intercept of the function f(n) = a^n + b, where a is not equal to 1 and a > 0, is the point where the function intersects the y-axis, or when n = 0.

To find the y-intercept, we substitute n = 0 into the function:
F(0) = a^0 + b = 1 + b = b

Therefore, the y-intercept of the graph is (0, b), indicating that the y-coordinate is equal to the constant term b.


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Which statement is modeled by the expression? 100p Responses The coach received 100 tokens for the amusement park rides. If there are p players on the team, each player will receive 100p tokens. The coach received 100 tokens for the amusement park rides. If there are , p, players on the team, each player will receive , 100 over p, , tokens. After the league had supplied each player with a uniform, there were 100 uniforms left over. If there are p players in the league, 100p is the number of uniforms the league had originally. After the league had supplied each player with a uniform, there were 100 uniforms left over. If there are , p, players in the league, , 100 over p, is the number of uniforms the league had originally. One hundred more players signed up for soccer than the league had planned for. The league had p uniforms in stock. The number of uniforms the league needs to buy to make up the difference is 100p. One hundred more players signed up for soccer than the league had planned for. The league had p uniforms in stock. The number of uniforms the league needs to buy to make up the difference is 100 over p ., Each player in the league was given 100 tickets to sell. If there are p players in the league, the total number of tickets to sell is 100p Each player in the league was given 100 tickets to sell. If there are , p, players in the league, the total number of tickets to sell is , 100 over p

Answers

The statement modeled by the expression "100p" is: "If there are p players on the team, each player will receive 100p tokens."
The statement modeled by the expression
"100p" is: "If there are p players on the team, each player will receive 100p tokens." Have a good day

Determine the smallest integer that makes -3x + 7 - 5x < 15 true.

State the smallest possible value for x in the solution set below as a number only.

Answers

Answer:

-1

Step-by-step explanation:

write it in the following manner:

-3x + 7  - 5x = 15

-8x + 7 = 15

-8x = 8

x = -1

Thus, the number has to be smaller than -1.

The smallest integer that makes the given inequality true is 0.

What is Linear Inequalities?

Linear inequalities are defined as those expressions which are connected by inequality signs like >, <, ≤, ≥ and ≠ and the value of the exponent of the variable is 1.

Given inequality,

-3x + 7 - 5x < 15

We have to find the value of x.

(-3x - 5x) + 7 < 15

-8x < 8

Dividing whole sides by -1, the inequality sign changes.

x > -1

Smallest possible value is 0.

Hence the smallest posible value is 0.

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17, 24, 31, 38, ... common diffrence Arithmetic Sequences

Answers

Ans: 10+7n

Step-by-step explanation: there you go

17, 24, 31, 38, ... common diffrence Arithmetic Sequences

Answer:

d=7; equation=17+(n-1)7

Step-by-step explanation:

I dont know what your question is but it goes up by 7

If there are 4 people, and they are sharing $3000.how much will each person get?

Answers

\(\boxed{\sf 750~per/person}\boxed\)

\(3,000 / 4(people) = 750\\)

Whats the answer and how do i show work

Whats the answer and how do i show work

Answers

The measure of <1 is 147 degree.

Given:

m∠2 = 12x - 15

m∠7 = 3x + 21

Since angles 2 and 7 are alternate Exterior angles, they are congruent.

So, 12x - 15 = 3x + 21

12x - 3x = 21 + 15

9x = 36

x = 4

So, <2 = 12x - 15= 48 - 15 = 33

Now, <1 + <2 = 180 (Linear Pair)

<1 + 33 = 180

<1 = 147 degree

Thus, the measure of <1 is 147 degree.

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How much heat is released when 12. 0 grams of helium gas condense at 2. 17 K? The latent heat of vaporization of helium is 21 J/g. â€""250 J â€""26 J 26 J 250 J.

Answers

The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J

The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.

However, since we are required to determine heat released when the helium gas condenses.

The heat of condensation per gram is; -21 J/g.

Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.

Approximately, -250J.

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Answer:

its a

Step-by-step explanation:

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HELP ME PLEASE! IM IN SEARCH OF ANSWERS AND I DONT GET ANY UNDER MY POST SO IF YOU COULD, PLEASE ANSWER

Answers

Answer:

3 a) 8x +8 in

3 b) 24 in

3 c) 4x +4 in

3 d) 16x + 16 in

Step-by-step explanation:

3 b) You have to put 2 in place of x and calculate the perimeter:

8•2 +8

16 +8

24 in

In a survey of 2,200 people who owned a certain type of​ car, 880 said they would buy that type of car again. What percent of the people surveyed were satisfied with the​ car?
*blank*% of the people surveyed were satisfied with the car.

Answers

Answer:

40%

Step-by-step explanation:

Given parameters:

Number of people surveyed  = 2200

Number of people who said they would buy the car again  = 880

Unknown:

The percentage of people satisfied with the car  = ?

Solution:

The percentage of people satisfied with the car purchase can be determined using the expression below:

Percentage of people satisfied  = \(\frac{Number of people who said they would buy the car again}{Number of people surveyed} x 100\)

Percentage of people satisfied  = \(\frac{880}{2200}\)  x 100  = 40%

R-1.3 Algorithm A uses 10n log n operations, while algorithm B uses n2 operations. Determine the value n0 such that A is better than B for n ≥ n0.
R-1.4 Repeat the previous problem assuming B uses n √n operations.
I only need R-1.4!!

Answers

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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R-1.3 Algorithm A uses 10n log n operations, while algorithm B uses n2 operations. Determine the value

What is the highest number of degrees that an angle can have?
90
270
180
360

Answers

Answer:

360  s

Step-by-step explanati:

Answer:

360

Step-by-step explanation:

Hope it helps!~ (Sorry if you get it wrong or I got it wrong- ~The Confuzzeled homan

Answer this question plz thanks

Answer this question plz thanks

Answers

Answer:

Option A

Step-by-step explanation:

The area outside of the semicircle is the difference of the areas of the rectangle and the semicircle.

Area of rectangle:

A₁ = w(w + 5) = w² + 5w

Area of the semicircle:

A₂ = 1/2*πd²/4 = 1/8*πw²

The area we are looking for is:

A = A₁ - A₂A = w² + 5w - 1/8πw²

Correct choice is A

HELP!! I need to find the code to pass.

HELP!! I need to find the code to pass.

Answers

The side TU of the right triangle is 156.15 metres and the area of the triangle is  6168.07 metres squared.

The side GH of the right triangle is 182.33 metres and the area of the triangle is  8934.27 metres².

How to find the side and area of a right triangle?

A right triangle is a triangle that has one of its angles as 90 degrees. The sum of angles in a triangle is 180 degrees.

The missing side of the right triangle can be found using Pythagoras's theorem.

Therefore,

a² + b² = c²

where

a and b are the legsc is the hypotenuse side

The area of the right triangle can be found using the formula as follows:

area of a triangle = 1 / 2 bh

where

b = baseh = height

Hence,

1.

TU² = 175² - 79²

TU² = 30625 - 6241

TU² = 24384

TU = √24384

TU = 156.153770368

TU = 156.15 metres

Area = 1 / 2 × 156.15 × 79

area = 6168.07392952

area = 6168.07 metres squared

2.

GH² = 207² - 98²

GH² = 42849 - 9604

GH = √33245

GH = 182.33211456

GH = 182.33 metres

Area of the triangle  = 1 / 2 × 98 × 182.33

Area of the triangle  = 8934.27361345

Area of the triangle  = 8934.27 metres²

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Vladimir is looking to retire in 10 years. He has a plan to put $25,000 into an investment today that earns interest at a fixed amount per year. What would be a reasonable domain and range for a function modeling the total amount of the investment, including interest?
25 Points for the correct answer

Answers

The domain and range for a function modeling the total amount of the investment, including interest are as follows;

Domain, X = {0<= years <= 10}Range, Y (total amount) = {$25,000<= Y <= 25,000( 1 + 10R)}

The starting principal amount, P is $25,000.

Let the interest rate per year, be represented as, R (%)

Time of investment, T = 10 years

In essence, after 10 years, the total amount Vladimir has is;

Total amount = 25,000( 1 + xR).

In essence, the domain (No. of years ) is;

Domain, X = {0<= years <= 10}

Range, Y (total amount) = {$25,000<= Y <= 25,000( 1 + xR)}

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torresn06 where are you i need your help....


567*875

Answers

Answer:

The answer is 496125.

Step-by-step explanation:

Simply multiply the two numbers together to get 567*875 = 496125.

Hope this helped!

Answer:496,125

Step-by-step explanation:

if the fraction simplified is 5/8 then what is the fraction out of 100?

Answers

Explanation

Step 1

convert the fraction in decimal number

\(\frac{5}{6}=5\text{ divided by 6 =0.8333}\)

Step 2

Multiply the result by 100

\(0.83333\cdot1000\rightarrow83.333\)

so, the fractions equals 83.33 out of 100

laura graphed the function below y = 1 / 2(One over two)x + 4

if the range of the function is restricted to 2 ≤ y ≤ 6, what is the domain?

laura graphed the function below y = 1 / 2(One over two)x + 4if the range of the function is restricted

Answers

Step-by-step explanation:

y = 0.5x + 4

When y = 2, x = -4. (shown in graph)

When y = 6, x = 4. (shown in graph)

Hence the domain would be -4 <= x <= 4.

What's the volume of this container (QUICK)

What's the volume of this container (QUICK)

Answers

Answer:

1468 in^3

Step-by-step explanation:

Multiply all of the larger box dimensions

10 * 10 * 15 = 1500  in^3

subtract the smaller box cut out corner

2 * 4 * 4 =  32

1500 - 32 = 1468 in^3

I need help plsssssss ;-;

1) Factorize. 2a² - 8

2)Among the sets, P = {3,4,5,6} , Q = {0,1,2,3} , R = {5,6,7,8,9}
i) write a pair of disjoint sets
ii)name a pair of equivalent sets

3) Out of the students in the class, 3/7 are girls. If there are 24 boys in the class, find the total number of students in the class.​

Answers

Answer:

2(a\( 2(a^2-4)\)

a root of the equation 3x-8=13

Answers

Answer:

x= 7

Step-by-step explanation:

3x= 13+8

3x= 21

x= 21/3

x= 7

matt joins a gym the cost includes a one time fee of 200 plus a monthly fee of 20

Answers

The total cost paid by Matt if he joins for 6 months is found as 320.

How to form linear equation with one variable?The equation for a linear equation in one variable is written as ax+b = 0, whereby there and b were also two integers, as well as x is a variable. This equation has had only one solution. For instance, the linear equation 2x+3=8 only has one variable. As a result, this equation has a single solution, x = 5/2.

For the stated query:

The joining cost of gym = 200

The month cost = 20.

Let the number of month be 'x'.

Let the total cost be 'c'.

Then , linear equation forms be.

c = 200 + 20x

For 6 months, put x = 6.

c = 200 + 20*6

c = 200 + 120

c = 320

Thus, the total cost paid by Matt if he joins for 6 months is found as 320.

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The complete question is-

Matt joins a gym the cost includes a one time fee of 200 plus a monthly fee of 20. Find the total cost paid by Matt if he joins for 6 months.

if f represents the number of lots of fliptop pens to produce and t represents the number of lots of tiptop pens to produce, the linear programming model for this problem is:

Answers

The linear programming model for this problem is Max 1000F + 1000T

Given that,

If the quantity of flip top pens to be produced is f and the quantity of tiptop pens to be produced is t, then

Number of lots of Flip top pens to produce = F

Number of lots of Tip top pens to produce = T

Therefore, The linear programming formulation is given by:

Max 1000F + 1000T

s.t.

Plastic: 3F + 4T <= 39

Ink Assembly:  5F + 4T <= 45

Molding time: 5F + 2T <= 37

F, P >= 0

Hence, the linear programming model for this problem is Max 1000F + 1000P

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Transcribed image text: Transform the given differential equation into an equivalent system of first-order differential equations. x4)-5x"-3x 53 sin (3t) Let xl X, X2-x', X3-x, , , and X4-X( ). Complete the system below 2 4

Answers

The equivalent system of first-order differential equations is:

x1' = x2x2' = x3x3' = x4 - 5x2 - 3x1 + 53sin(3t)x4' = -5x2 - 3x1 + 159cos(3t)

To transform the given differential equation into an equivalent system of first-order differential equations, we can introduce new variables. Let's define:

x1 = x

x2 = x'

x3 = x''

x4 = x'''

Now, we can rewrite the original equation in terms of these new variables:

x4 - 5x'' - 3x' + 53sin(3t) = 0

Replacing the derivatives with the new variables, we have:

x4 = x4

x3 = x'''

x2 = x'

x1 = x

Now, we have a system of first-order differential equations:

x1' = x2

x2' = x3

x3' = x4 - 5x2 - 3x1 + 53sin(3t)

x4' = ?

We need to find an expression for x4' by differentiating one of the equations. Let's differentiate the equation x3' = x4 - 5x2 - 3x1 + 53sin(3t) with respect to t:

x4' = x3'' = (x4 - 5x2 - 3x1 + 53sin(3t))'

Differentiating each term, we get:

x4' = x4' - 5x2' - 3x1' + 159cos(3t)

Simplifying, we have:

x4' = -5x2 - 3x1 + 159cos(3t)

Therefore, the equivalent system of first-order differential equations is:

x1' = x2

x2' = x3

x3' = x4 - 5x2 - 3x1 + 53sin(3t)

x4' = -5x2 - 3x1 + 159cos(3t)

Note: The given differential equation is of the fourth order, so the resulting system has four first-order equations to represent it.

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In def x is a point on ef and y is a point on df so that xy ||de if xf =10 yf=5 and ef = 13 what is dy

Answers

DF^2 = 170 * 169^2 / (135^2 + 200 - 26EX) = 106.7027

DY^2 = 170 * 169^2 / (135^2 + 50 -

In the given figure, we have a triangle DEF, where EF is a transversal intersecting DE and DF at points X and Y, respectively, such that XY || DE.

    D

   / \

  /   \

 /     \

E-------F

Given that XF = 10, YF = 5, and EF = 13, we need to find DY.

We can start by using the property of similar triangles. Since XY || DE, we have the following similarity ratios:

EF / ED = EY / EJ  (where J is the intersection of XY and DF)

EF / DF = EJ / EY

Substituting the given values, we get:

13 / ED = EY / EJ

13 / DF = EJ / (13 - EY)

Multiplying the above two equations, we get:

13 / ED * 13 / DF = EY / EJ * EJ / (13 - EY)

169 / (ED * DF) = EY / (13 - EY)

Substituting the values of XF = 10 and YF = 5, we get:

169 / (ED * DF) = 5 / 8

ED / DF = 135 / 169

Using the Pythagorean theorem on triangles DEX and DFY, we get:

ED^2 = EX^2 + DX^2

DF^2 = FY^2 + DY^2

Since EX + DX = EF = 13, we have DX = 13 - EX. Substituting this in the first equation and simplifying, we get:

ED^2 = EX^2 + (13 - EX)^2

ED^2 = 2EX^2 - 26EX + 170

Similarly, substituting FY = 13 - EY in the second equation and simplifying, we get:

DF^2 = FY^2 + DY^2

DF^2 = 170 - 26EY + EY^2 + DY^2

Now, using the fact that ED/DF = 135/169, we can substitute ED^2 = (135/169)^2 * DF^2 in the above equation for ED^2, and simplify to get:

(135/169)^2 * DF^2 = 2EX^2 - 26EX + 170

DF^2 = 170 * 169^2 / (135^2 + 2EX^2 - 26EX)

DF^2 = 170 * 169^2 / (135^2 + 2(10^2) - 26EX)   (Substituting XF = 10)

Similarly, we can substitute EY = 5 in the above equation for DF^2 and simplify to get:

FY^2 + DY^2 = 170 * 169^2 / (135^2 + 2(5^2) - 26EY)   (Substituting YF = 5)

DY^2 = 170 * 169^2 / (135^2 + 2(5^2) - 26EY) - FY^2

Substituting the given values, we get:

DF^2 = 170 * 169^2 / (135^2 + 200 - 26EX) = 106.7027

DY^2 = 170 * 169^2 / (135^2 + 50 -

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Una playera de la misma marca cuesta con iva incluido $614.48, ¿cual será su precio sin iva ?

Answers

Answer: $600 cerados

Step-by-step explanation:

chiii y que marca es esa lol


LADDER PROBLEM
A fireman stood on the middle rung of a ladder directing water into a burning building.
As the smoke lessened, he stepped up three rungs and continued his work from that
point. A sudden flare-up forced him to go down five rungs. Later he climbed up seven
rungs to the top of the ladder and entered the building. How many rungs does the
ladder have?

Answers

The ladder has 10 rungs

Let x represent the number of rungs of the ladder

At the start of the question, the fireman is standing at the middle rung of the ladder. This would be represented with 0.5x

Based on the steps taken, the next equation can be formed

A plus sign signifies that the fireman climbed up and a negative sign signifies that the fireman went down the ladder

x = 0.5x + 3 - 5 + 7

Combine similar terms

x - 0.5x =  3 - 5 + 7

0.5x = 5

Divide both sides by 0.5

x = 10

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Recall that the cigarette industry requires that models in cigarette ads must appear to be at least 25 years old. Also recall that a sample of 50 people is randomly selected at a shopping mall. Each person in the sample is shown a "typical cigarette ad" and is asked to estimate the age of the model in the ad. The p -value for testing H0 versus Ha can be calculated to be 0.0038.
Determine whether H0 would be rejected at each of ? = .10, ? = .05, ? = .01, and ? = .001. (Round your answer to 4 decimal places.)
p-value Reject H0 at ? =

Answers

The p-value for testing H0 (null hypothesis) versus Ha (alternative hypothesis) is 0.0038. We need to determine whether H0 would be rejected at different significance levels: α = 0.10, α = 0.05, α = 0.01, and α = 0.001.

To make the decision, we compare the p-value with the chosen significance level. If the p-value is less than or equal to the significance level, we reject H0. Otherwise, we fail to reject H0.

At α = 0.10: Since the p-value (0.0038) is less than 0.10, we reject H0.

At α = 0.05: Since the p-value (0.0038) is less than 0.05, we reject H0.

At α = 0.01: Since the p-value (0.0038) is greater than 0.01, we fail to reject H0.

At α = 0.001: Since the p-value (0.0038) is greater than 0.001, we fail to reject H0.

In summary:

H0 would be rejected at α = 0.10 and α = 0.05.

H0 would not be rejected at α = 0.01 and α = 0.001.

Please note that the decision to reject or fail to reject the null hypothesis depends on the chosen significance level, and different levels of significance can lead to different conclusions.

Learn more about hypothesis testing here: brainly.com/question/17099835

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Helppppppp please thanks :)

Helppppppp please thanks :)

Answers

Answer:

Sorry its a little blurry.

Helppppppp please thanks :)

Functions! Help with number 3 please!!!

Functions! Help with number 3 please!!!

Answers

Answer: 20

Step-by-step explanation:

Assuming g(x) = -4x + 1,

( -4 (-4) + 1) - (-4 + 1)

= (16 + 1) - (-3)
= 17 + 3

= 20

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