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Use the Pythagorean Theorem to find the value of x. Round answers to the nearest tenth.

Answer:

Attached

Step-by-step explanation:

x+8≥9

x ≥ 9-8

x ≥ 1

picture one is two dimension and picture 2 is number line

Answer: Random condition

10% condition

Step-by-step explanation:

The conditions for inference that have been satisfied will be:

• Random condition: This has been satisfied since a random sample of 18 adults were taken from 1500 adults.

• 10% condition: Since 25% of those who responded said they were in favor of the change, then the 10% condition is satisfied.

we have

y-intercept is 8 -----> that means (0,8)

x-intercept is -10 ---> that means (-10,0)

step 1

Find out the slope

m=(0-8)/(-10-0)

m=-8/-10

m=8/10

simplify

m=0.8

step 2

Find out the equation in slope-intercept form

y=mx+b

we have

m=0.8

b=8

therefore

Answer:

i guess its 80

Step-by-step explanation:

time x thanks man

Answer: 6

Step-by-step explanation:

Step 1: Set up equation:

90=40.62+8.23p

^ the 'p' represents pounds.

Step 2: Subtract 40.62 from both sides

49.38 = 8.23p

Step 3: Divide both sides by 8.23 (We do this to get the variable "p" by itself)

6=p

Trust Milky. Milky Smart

Answer:

A-2

B-1

C-3

D-4

Step-by-step explanation:

Got it right on Edmentum

Answer:

A. 2

B. 1

C. 3

D. 4

Step-by-step explanation:

A.

A = {2, 4, 6}

Complement of A = {1, 3, 5}

Answer: 2

B.

A = {2, 4, 6}

B = {5, 6}

A U B = {2, 4, 5, 6}

Answer: 1

C.

B = {5, 6}

Answer: 3

D.

A ∩ B = {2, 4, 6} ∩ {5, 6} = {6}

Answer: 4

The time the mechanic is away from the shop is 2 hours.

To find the time the mechanic is away from the shop, we need to know either the distance of the round trip or the speed of the mechanic on one of the legs of the trip.

For example, if we know that the distance of the round trip is 30 miles, we can use the formula:

time = distance / speed

where speed is the average speed for the round trip, which is given as 15 miles per hour.

So, the time the mechanic is away from the shop would be:

time = 30 miles / 15 miles per hour = 2 hours

But without knowing the distance of the round trip or the speed of the mechanic on one of the legs of the trip, we cannot calculate the time the mechanic is away from the shop.

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Answer:

QR

Step-by-step explanation:

The question is just trying to see if you can read the order of the lines.

PQ is the first 2 letters of PQR so XY has to be the first 2 letters of XYZ

Answer

YZ is the second and third letters of xyz.

QR are the 2nd and 3rd letters of PQR

13:13

2 cubes=8

3-1=2

2 squared=4

4+1=5

5+8=13

Object B will be at a distance of 180 m from the bottom of the well when object A hits the bottom.

The formula for distance covered by a freely falling object is given by :

\(\[s = \frac{1}{2}gt^2\]\)

Where s is the distance covered, g is the acceleration due to gravity and t is time of fall.

So, the distance covered by object A when it hits the bottom of the well can be calculated as:

s = (1/2)gt²

= (1/2)×10×1²

= 5m

Now, let us calculate the time it takes for object B to hit the bottom of the well.

Since both objects are dropped from the same location, the initial velocity of both will be zero.

The time taken for object B to hit the bottom can be calculated as follows:

180 = (1/2)×10×t²

⇒ t = 6 seconds

Now, we can use the same formula as before to calculate the distance covered by object B by the time object A hits the bottom:

s = (1/2)gt²

= (1/2)×10×6²

= 180 m

Therefore, object B will be at a distance of 180 m from the bottom of the well when object A hits the bottom.

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The correct result of the expression is -21, not 13 as Dakota calculated. No, Dakota's work is not correct.

Let's go through the steps to evaluate the expression correctly:

Step 1:

8(18 ÷ 6) - (52 - 3) + 4

= 8(3) - (49) + 4

Step 2:

= 24 - 49 + 4

Step 3:

= -25 + 4

Step 4:

= -21

Therefore, the correct result of the expression is -21, not 13 as Dakota calculated.

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The mean of y, E(y) = 5. Answer: \boxed{5}.

The mean of y, E(y)We know that the mean of y, E(y) is given by:

E(y)=\int_{-\infty}^{\infty} y f(y)dy

Here, the pdf is given by:f(y) = ky³(1-y)², 0 ≤ y ≤ 1, 0, elsewhere

We know that for a pdf, it must be integrated from negative infinity to positive infinity and equated to 1. That is:

\int_{-\infty}^{\infty} f(y)dy = 1

\int_{0}^{1} ky³(1-y)²dy = 1

Hence, \frac{k}{60} = 1

k = 60

So, f(y) can be written as:f(y) = 60y³(1-y)², 0 ≤ y ≤ 1

The mean of y, E(y) is given by:

E(y)=\int_{-\infty}^{\infty} y f(y)dy

E(y)=\int_{0}^{1} y (60y³(1-y)²) dy

E(y)=60 \int_{0}^{1} y^4(1-y)² dy

Using integration by substitution, let u = 1-y

Therefore, du/dy = -1

The limits of integration will change.

When y = 0, u = 1When y = 1, u = 0

E(y)=60 \int_{0}^{1} (1-u)u² du

E(y)=60 \int_{0}^{1} u² - u³ du

E(y)=60 \bigg[\frac{u³}{3} - \frac{u⁴}{4}\bigg]_{0}^{1}

E(y)=60 \bigg[\frac{1}{3} - \frac{1}{4}\bigg]

E(y)=60 \bigg[\frac{1}{12}\bigg]

E(y)=5

Therefore, the mean of y, E(y) = 5. Answer: \boxed{5}.

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Answer:

Step-by-step explanation:

The expanded expression equivalent to \(log_4(\frac{x}{3x-5})\) is \(log_4(x) - log_4(3x - 5)\) by using the quotient rule of logarithms.

The quotient rule of logarithms is a rule used to simplify logarithmic expressions involving division. It states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and denominator. Mathematically, the quotient rule can be expressed as follows: logₐ(b / c) = logₐ(b) - logₐ(c)

In this rule, "logₐ" represents the logarithm with the base "a", and "b" and "c" are positive numbers. To apply the quotient rule, you first calculate the logarithm of the numerator and denominator separately and then subtract the logarithms. This rule is particularly useful when dealing with complex logarithmic expressions involving fractions or divisions.

To write an expanded expression equivalent to \(log_4(\frac{x}{3x-5})\), using the quotient rule of logarithms, we have;\($$\begin{aligned}\log_{4}\left(\frac{x}{3x - 5}\right) &= \log_{4}(x) - \log_{4}(3x - 5)\\&=\boxed{\log_{4}(x)-\log_{4}(3x-5)}\end{aligned}\)

To apply the quotient rule of logarithms, we use the formula; \(\[\log_{a}(\frac{x}{y}) = \log_{a}(x) - \log_{a}(y)\]\) where a, x and y are positive real numbers, and a ≠ 1.
We substitute the values of the variables with the given logarithmic expression to get; \(\[\log_{4}(\frac{x}{3x - 5}) = \log_{4}(x) - \log_{4}(3x - 5)\]\). So the expanded expression equivalent to \(log_4(\frac{x}{3x-5})\) is \(log_4(x) - log_4(3x - 5)\).

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This is the polar equation for the curve represented by the Cartesian equation xy = 1.

To find the polar equation for the curve represented by the Cartesian equation xy = 1, we can substitute the Cartesian coordinates with their equivalent polar coordinates.

In polar coordinates, x = r * cos(θ) and y = r * sin(θ).

Substituting these into the equation xy = 1:

(r * cos(θ)) * (r * sin(θ)) = 1

Expanding and simplifying:

r² * cos(θ) * sin(θ) = 1

Since cos(θ) * sin(θ) is equal to (1/2) * sin(2θ), we can rewrite the equation as:

(r²/2) * sin(2θ) = 1

Dividing both sides by (r²/2), we get:

sin(2θ) = 2/r²

This is the polar equation for the curve represented by the Cartesian equation xy = 1.

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The length of the microorganism that measure 5μm is equivalent to 0.005 mm

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

To solve this problem the we have to convert the units with the given information.

1mm is equal to 1000 μm

5μm * (1 mm/1000μm) = (5*1) / 1000 = 5/1000 = 0.005 mm = 5x10^-3 mm

The length of the microorganism that measure 5μm is equivalent to 0.005 mm

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\(f(x) = 5 \cdot 3^x\\\\\\f(-2) = 5\cdot 3^{-2}\\\\~~~~~~~~~=5\cdot \dfrac 1{3^2}\\\\~~~~~~~~~=\dfrac 59\\\\\text{Hence the answer is D.}\)

Answer:

B. {(-3, 4), (-8,0), (3, -8), (-3, -4)}

Step-by-step explanation:

B. is not a function because the x's repeat in this one.

If the x's repeat then it is not a function.

{(-3, 4), (-8,0), (3, -8), (-3, -4)}

The -3 repeats so it is not a function.

Y can repeat, but x cannot.

Hope this helps ya!!

Answer:

7

Step-by-step explanation:

Answer: lol pretty sure its 7

Step-by-step explanation: i divided 35 and 5

Answer:

how is this a question......

To calculate the mathematical value of 20, you would use the  : 20 x 1 = 20. This means that 20 multiplied by 1 is equal to 20. Therefore, the value of 20 in ASL is equal to 20.

ASL stands for American Sign Language. It is the visual language used by the deaf and hard of hearing communities to communicate. In ASL, the sign for the number 20 is done by holding up both hands with the palms facing out and fingers spread apart. The hands are then moved together in a circular motion with the fingers crossed at the end. This sign is also used to represent the mathematical concept of multiplication. To express the value of 20 in ASL, you would sign the number 20 by making the above mentioned sign, and then sign the word "equals". To calculate the mathematical value of 20, you would use the formula: 20 x 1 = 20. This means that 20 multiplied by 1 is equal to 20. Therefore, the value of 20 in ASL is equal to 20.

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Answer:7

Step-by-step explanation:

Answer: 7

Step-by-step explanation:

7

a) Two-way radio A covers approximately 79 square miles.

b) Two-way radio B covers approximately 903 square kilometers.

c) Two-way radio B covers a larger area than two-way radio A.

d) The radius of radio B is approximately 1.77 times larger than the radius of radio A.

Part A: To find the area covered by two-way radio A, we need to calculate the area of a circle with radius 5 miles. Using the formula for the area of a circle A = πr², where r is the radius, we get:

A = 3.14 x 5²

A = 3.14 x 25

A = 78.5 square miles

Part B: To find the area covered by two-way radio B, we need to calculate the area of a circle with radius 11.27 kilometers. Using the same formula, but converting the radius to kilometers first, we get:

A = 3.14 x (11.27 x 1.61)²

A = 3.14 x 286.96

A = 902.6 square kilometers

Part C: To compare the coverage areas of the two-way radios, we need to convert the area covered by radio A to kilometers as well. Using the conversion factor of 1 mile = 1.61 kilometers, we can convert the area covered by radio A as follows:

78.5 square miles x (1.61 kilometers/mile)² = 203.5 square kilometers

Part D: The scale factor relationship between the radio coverages can be found by dividing the radius of radio B by the radius of radio A:

11.27 kilometers / (5 miles x 1.61 kilometers/mile) = 1.77

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Answer:

Step-by-step explanation:

(3 + 1)/(-2 - 4) = 4/-6 = -2/3

y + 1 = -2/3(x -4)

y + 1 = -2/3x + 8/3

y + 3/3 = -2/3x + 8/3

y = -2/3x + 5/3

2x + 3y - 5 = 0 is the standard form

The required equation of the line that passes through (4, -1) and (-2, 3) is 2x+3y-5 = 0

An equation is a mathematical statement that shows that two mathematical expressions are equal.

Given that, A line is passing through points (4, -1) and (-2, 3)

We know that, the equation of a line passing through two points is given by, (y-y₁) = (y₂-y₁)/(x₂-x₁)(x-x₁)

y+1 = (3+1)/(-2-4)(x-4)

y+1 = -2/3(x-4)

3y+3 = -2x+8

2x+3y-5 = 0

Hence, The required equation of the line that passes through (4, -1) and (-2, 3) is 2x+3y-5 = 0

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The position vector r describes the path of an object moving in space.

r(t) = 3ti + tj + 1/4 * t ²* k t = 2

(a) The velocity vector, speed, and acceleration vector of the object.

v(t) = 3i + j + (1/2)tk

s(t) = √(10 + (1/4)t²)

a(t) = (1/2)k

(b) The velocity vector and acceleration vector of the object at the given value of t.

v(2) = 3i + j + k

a(2) =(1/2)k

(a) To find the velocity vector, speed, and acceleration vector of the object, we need to differentiate the position vector with respect to time.

Given:

r(t) = 3ti + tj + (1/4)t²k

Taking the derivative with respect to t, we get:

v(t) = dr(t)/dt = d(3ti + tj + (1/4)t²k)/dt

v(t) = 3i + j + (1/2)tk

The velocity vector is v(t) = 3i + j + (1/2)tk.

To find the speed, we calculate the magnitude of the velocity vector:

s(t) = ||v(t)|| = ||3i + j + (1/2)tk||

= √(3²+ 1² + (1/2)²t²)

= √(9 + 1 + (1/4)t²)

= √(10 + (1/4)t²)

The speed of the object is s(t) = √(10 + (1/4)t²).

To find the acceleration vector, we differentiate the velocity vector with respect to time:

a(t) = dv(t)/dt = d(3i + j + (1/2)tk)/dt = 0i + 0j + (1/2)k

The acceleration vector is a(t) = (1/2)k.

(b) To evaluate the velocity vector and acceleration vector at t = 2, we substitute t = 2 into the expressions obtained in part (a):

v(2) = 3i + j + (1/2)(2)k = 3i + j + k

a(2) = (1/2)k

Therefore, v(2) = 3i + j + k and a(2) = (1/2)k.

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The number 3.91 x 10⁻²  in the standard form is 392.

We have given an expression  3.91 x 10⁻²

Now look at the power of 10 ,you move the point to the right of many places as the (positive) value of the exponent of 10, which, in this case is 2.

On moving , we get

3.92→to places to the right:

39.2

392.0=392

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Answer:

need graph

Step-by-step explanation:

Answer:

x=186.68

y=140

z=233.34

Step-by-step explanation:

easy method to solve since you have the answers to pick from

first triangle. we have two sides 175 and 105 and we know that 175 have to be the largest number, its the hypotenuse. which means

y=140,

cannot be 233 or 186 because both greater than 175

now next triangle. x-y-z, we already know "y" and "z" needs to be the largest number so it has to be

z= 233.34 and finally

x=186. 67

The slope of the tangent line at the point x = a of the function f(x) is f'(a).

We are given the function:

Computing the first derivative:

The slope of the tangent line at (1, 1), that is, where x = 1 is:

The tangent line and the normal line are perpendicular to each other. If their respective slopes are m1 and m2, then:

We have calculated m1 = -1, calculate m2:

Now we know the slope of the normal line. We need to find its equation. Use the point-slope formula:

y - k = m(x - h)

Where m is the known slope and (h, k) is a point of the line. We are given the point (1, 1), thus:

y - 1 = 1(x - 1) = x - 1

Adding 1:

y = x

Answer: D. x