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A scientist observes a fault where the hanging wall has moved upward relative to the footwall. Which type of fault is the scientist observing?
normal
reverse
strike-slip
horizontal
I AM BEING TIMED
Answers
Explanation:
the answer is reverse fault
Answer:
Reverse fault
Explanation:
I play cheer
Related Questions
What is the independent variable on this graph?
Oonly temperature (*C)
Oboth flow time (s) and temperature (C)
only flow time (s)
Answers
REASON: Temperature is on the “x” axis meaning it is independent. The x axis is always independent while the y axis is always dependent.
During a football workout two linemen are pushing on the coach and the sled. The combined mass of the sled and the coach is 300 kg the coefficient of friction of between the sled and the grass is. 800. The sled accelerates at a rate of. 580 m/s/s. Determine the force applied to the sled by the lineman
Answers
A football workout involves two linemen who are pushing on the coach and the sled. The sled and the coach's combined mass is 300 kg, while the coefficient of friction between the sled and the grass is .800. The sled accelerates at a rate of .580 m/s/s. We need to determine the force applied to the sled by the linemen.
The total force acting on the sled is:Force = Mass × AccelerationF = 300 kg × .580 m/s/s = 174 NSince the sled and the grass's coefficient of friction are known, we can determine the force applied to the sled by the linemen using the following equation:
Frictional Force = Coefficient of Friction × Normal Force
The normal force is equal to the weight of the sled and the coach. Thus,Normal Force = Mass × GravityN = 300 kg × 9.81 m/s/s = 2943 NFrictional Force = .800 × 2943 N = 2354.4 NThe force applied to the sled by the linemen is the difference between the total force acting on the sled and the frictional force.
Force Applied by Linemen = Total Force − Frictional ForceF = 174 N − 2354.4 N = −2180.4 NThe linemen are exerting a force of −2180.4 N on the sled in the opposite direction to the sled's movement. This is because the frictional force is greater than the total force acting on the sled.
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an at-filled, parallel-plate capacitor has a capacitance of 1.32 pf. the separation of the plates is doubled and wax 1s inserted between them. the new capacitance is 2.57 pf. find the dielectric constant of the wax.
Answers
The dielectric constant of the wax is 4.
The energy stored in a capacitor is proportional to the square of the charge divided by the capacitance but doubling the plate spacing halves the capacitance. Capacitance is directly proportional to the electrostatic force field between the plates. This magnetic field gets stronger the closer the plates are to each other. Therefore, the capacitance increases as the distance between the plates decrease.
Therefore, we can conclude that doubling the area and distance between the plates of a parallel plate capacitor does not change the capacitance. A capacitor consists of two conductive plates separated by an insulator and is used to store an electrical charge. When you apply a voltage to a capacitor, one plate will be negatively charged and the other plate will be positively charged.
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Light travels (fastest, slowest) in media with a lower index
of refraction value.
Answers
Fastest
Light travels fastest in media which are least optically dense. The index of refraction value provides a relative measure of the optical density of a material. The higher the index of refraction value, the more optically dense a material is and the slower that light will travel in that material.
LaCie kicks a football from the ground level at a velocity of 13.9 m/s and at angle of 25 degrees to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35 degrees? Complete all equations without rounding and then round to the nearest tenth at the end
Answers
The ball will travel more distance when projected or kicked at an angle of 35 degrees.
What is the range of projectile?
The range of the projectile or the horizontal distance traveled by the ball is calculated by applying the following kinematic equation as shown below.
R = ( u² sin (2θ ) ) / g
where;
u is the initial velocity of the ballg is the acceleration due to gravityThe horizontal distance traveled by the ball when projected at 35 degrees is calculated as;
R = ( 13.9² x sin ( 2 x 35 ) ) / ( 9.8 )
R = 18.53 m
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A car with a mass of 1400 kg is being driven along the motorway at 30 m/s. Calculate the kinetic energy of the car.
Answers
Answer:
630,000 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\\)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 1400 \times {30}^{2} \\ = 700 \times 900 \\ = 630000\)
We have the final answer as
630,000 JHope this helps you
You find yourself in a place that is unimaginably hot and dense. A rapidly changing gravitational field randomly warps space and time. Gripped by these huge fluctuations, you notice that there is but a single, unified force governing the universe. Where are you
Answers
You find yourself in a place that is unimaginably hot and dense. A rapidly changing gravitational field randomly warps space and time. Gripped by these huge fluctuations, you notice that there is but a single, unified force governing the universe, you are in the early universe before the Planck time.
What is Planck time?The Planck time is approximately 10^-44 seconds. The smallest time interval, or "zeptosecond," that has so far been measured is 10^-21 seconds. A photon traveling at the speed of light would need one Planck time to traverse a distance of one Planck length.
What is Planck length?Planck units are a set of measuring units used only in particle physics and physical cosmology. They are defined in terms of four universal physical constants in such a way that when expressed in terms of these units, these physical constants have the numerical value 1. These units are a system of natural units because its definition is based on characteristics of nature, more especially the characteristics of free space, rather than a selection of prototype object, as was the case with Max Planck's original 1899 proposal. They are pertinent to the study of unifying theories like quantum gravity.
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When the spring on a toy gun is compressed by a distance x, it will shoot a rubber ball straight up to a height of h. Neglecting air resistance, how high will the gun shoot the same rubber ball of the spring is compressed by an amount 3x? assume x << h.
Answers
The rubber ball will reach a height that is 27 times higher if the spring is compressed by 3x compared to when it is compressed by x.
Assuming that the spring follows Hooke's law and that the only force acting on the rubber ball is the force of the compressed spring, we can use the principle of conservation of energy to find the height the rubber ball will reach when the spring is compressed by 3x.When the spring is compressed by x, it stores potential energy given by:PE = (1/2)kx^2where k is the spring constant.When the spring is released, this potential energy is converted into kinetic energy:KE = (1/2)mv^2where m is the mass of the rubber ball and v is its velocity.At the highest point of its trajectory, the rubber ball has zero kinetic energy, so its potential energy must be equal to the potential energy stored in the compressed spring:PE = (1/2)k(3x)^2 = (9/2)kx^2The potential energy at this point will also be equal to the gravitational potential energy at its highest point:PE = mghwhere g is the acceleration due to gravity.Equating the two expressions for potential energy, we get:(9/2)kx^2 = mghSolving for h, we get:h = (9/2)(k/m)x^2gTherefore, if the spring is compressed by 3x, the rubber ball will reach a height of:h' = (9/2)(k/m)(3x)^2g = 27hSo the rubber ball will reach a height that is 27 times higher if the spring is compressed by 3x compared to when it is compressed by x.For more such question on rubber ball
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30 12
w
Find the total
equivalent
resistance for the
circuit.
40 12
w
9.0V
50 Ω
2012 10 12
Reg = [?] 12
Answers
Answer:
6
.40 recharge
1.0v
45.0v
A skateboarder traveling at 7.0 meters per second rolls to a stop at the top of a ramp in 3.0
seconds. What is the skateboarder's acceleration?
Answers
The acceleration of the skateboarder is calculated out to bbe -2.33 m/s^2, when travelled at 7 meters per second.
What is acceleration and how it calculated out to be -2.33 m/s^2?As we have studied earlier also acceleration is the measure of change in velocity per unit time.Here is given the initial velocity 7 m/s , it is coming to a stop at the top of a ramp . And the time is given 3 seconds.Using the equation a = final velocity - initial velocity / time , we get the acceleration to be -2.33 m/s^2.The skateboarder's acceleration when travelled at 7 meters per second rolls to a stop at the top of a ramp in 3 seconds is calculated out to be -2.33 m/s^2.To know more about acceleration visit:
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The work done on an object is equal to the force times the distance moved in the direction of the force. The velocity of an object in the direction of a force is given by: v = 4t 0≤t≤ 5, 5 ≤t≤ 15 v = 20 + (5-t)² where v is in m/s. With step size h=0. 25, determine the work done if a constant force of 200 N is applied for all t a) using Simpson's 1/3 rule (composite formula) b) using the MATLAB function trapz
Answers
A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.
B) Using the MATLAB function trapz, the work done is approximately 7750 J.
Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.
A) Force (F) = 200 N (constant for all t)
Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)
Step size (h) = 0.25
To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.
Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.
Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].
For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²
Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).
Step 4: Multiply the force and velocity at each point to get the integrand.
For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]
Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].
The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]
Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).
Step 6: Multiply the result by the step size h to get the work done.
Work done: 1250 J
B) % Define the time intervals and step size
t = 0:0.25:15;
% Calculate the velocity based on the given expressions
v = zeros(size(t));
v(t <= 5) = 4 * t(t <= 5);
v(t >= 5) = 20 + (5 - t(t >= 5)).^2;
% Define the force value
F = 200;
% Calculate the work done using MATLAB's trapz function
\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;
% Display the result
disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);
The final answer for the work done using MATLAB's trapz function with the given force and velocity is:
Work done using MATLAB's trapz function: 7750 J
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if the observation screen is a distance of 5m from the slits, how far apart are the zero order maximum and the third order maximum?
Answers
The distance between the zero order maximum and the third order maximum is 6.6 m.
The distance between the zero order maximum and the third order maximum on an observation screen can be calculated using the formula:d = (m * λ) / a,
where , m is the order of the maximum, λ is the wavelength of light used, and a is the separation between the two slits.
The zero order maximum is the center maximum on the screen, and the third order maximum is the third maximum on either side of the center. To find the distance between them, we need to know the wavelength of light and the separation between the slits.If we assume that the light used has a wavelength of 550 nm (a common value for green light), and the separation between the slits is 0.25 mm, the distance between the zero order and the third order maximum can be calculated as follows:d = (3 * 550 * 10^-9) / (0.25 * 10^-3) = 6.6 m
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A 4-wheel truck with a total mass of 4000 kg having a velocity of 30 m/s tries to stop in 2 seconds. How much force is being exerted to each wheel? Solve the problem and show all calculations/equations.
Answers
The amount of force being exerted to each wheel when the 4-wheel truck with a total mass of 4000 kg tries to stop is 15,000 N.
First, we'll find the acceleration (a) using the formula:
vf = vi + (a * t)
Rearranging for acceleration, we get:
a = (vf - vi) / t
Substituting the values:
a = (0 - 30) / 2 = -15 m/s²
Now, we'll find the total force (F) using the formula:
F = m * a
Substituting the values:
F = 4000 * -15 = -60,000 N (the negative sign indicates the force is acting in the opposite direction of the initial motion)
Finally, we'll find the force exerted on each wheel by dividing the total force by the number of wheels:
Force per wheel = F / 4 = -60,000 / 4 = -15,000 N
The negative sign indicates that the force is in the opposite direction of the initial velocity (i.e. the force is acting to slow the wheel down). So, each wheel is exerting a force of 15,000 N to stop the truck in 2 seconds.
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How much work is done on a cat that is pushed 50 meters with 3 N of force?
Answers
Answer:
150
Explanation:
work done = constant force x distance moved in the direction of force
W = F x S
(UNITS: J = N x m)
50 x 3 = 150
How does the observed pitch of the buzzer change as it moves
observer?
pitch of the buzzer increased (higher tone) as it moves towards the observer
The pitch of the buzzer decreased (lower tone) as it moves towards the observer
The pitch of the buzzer stayed the same no matter where it was in relationship
to the observer
Answers
The answer is
Pitch of the buzzer increased (higher tone) as it moves towards the observer
The correct option that explains the change in the observed pitch of the buzzer as it moves towards the observer is;
A; pitch of the buzzer increased (higher tone) as it moves towards the observer
This is based on the concept of doppler effect which is defined as the change in frequency/pitch of a sound that is heard by an observer due to the fact that the sound source and the observer have different velocities with respect to the medium through the sound travels.Now, according to doppler effect, when the source of the sound moves towards the observer, the frequency will increase due to the fact that the time between successive sound waves is shortened. Thus, this means that the pitch will be higher. However, when the sound source moves away from the observer, the frequency would decrease due to the fact that the time between successive sound waves or the crest is now longer. Thus, the pitch will decrease.In conclusion, the pitch of the buzzer will increase as it moves towards the observer.
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What is potential energy? Give at least three examples, and explain why they have potential energy.
Answers
Answer:
Energy stored in an object due to its position is Potential Energy. · Energy that a moving object has due to its motion is Kinetic Energy.
Explanation:
Answer:
To summarize, potential energy is the energy that is stored in an object due to its position relative to some zero position.
Holding a bow and arrow before shooting, The amount of energy stored before you race on track, And a roller coaster going to it's highest point staying there waiting to come down.
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the third law of thermodynamics deals with
A. the conservation of energy
B.the direction of night
C.energy dissipation
D.absolute zero
Answers
Answer:D
Explanation:
Because it is not possible to reach a value of absolute zero as not only would it infringe the Second Law of Thermodynamics but also require infinite number of observations which is impossible
If the pressure of a gas is increased, then the volume will decrease because the particles of the gas will be forced more closely together.
The independent variable is
.
The dependent variable is
.
Answers
independent variable:
increasing the pressure of gas
dependent variable:
decrease in volume
Then the independent variable is the pressure of the gas while the dependent variable is the volume of the gas as it depends on the variation in the pressure of the gas.
What is an ideal gas?It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one,
A gas's volume will decrease as its pressure rises because the gas's particles will be pressed closer together.
As the volume of the gas depends on the fluctuation in the gas's pressure, the independent variable in this situation is the gas's pressure.
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Jane spent 3 hours exploring a mountain with a dirt bike First, she rode 72 miles uphill After she reached the peak she rode for 21 miles along the summit While going uphill, she went 5 mph slower than when she was the summit What was her rate along the summit?
Answers
Jane's rate along the summit was 25 mph.
Let's assume that Jane's rate along the summit is represented by the variable "x" in miles per hour. We know that she rode 72 miles uphill at a rate that was 5 mph slower than her rate along the summit. Therefore, her rate uphill would be (x - 5) mph.
To find her average rate for the entire journey, we can calculate the total time taken for each segment and divide it by the total distance covered.
Time taken to ride uphill = Distance / Rate
Time taken to ride uphill = 72 miles / (x - 5) mph
Time taken to ride along the summit = Distance / Rate
Time taken to ride along the summit = 21 miles / x mph
Since the total time taken for the entire journey is 3 hours, we can write the equation:
Time taken to ride uphill + Time taken to ride along the summit = Total time
72 / (x - 5) + 21 / x = 3
By solving this equation, we find that x = 25 mph. Therefore, Jane's rate along the summit was 25 mph.
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Why are some environmental problems only solved through joint efforts on an international scale?
Answers
Answer:
International Environmental Problems require international Cooperation to resolve them Factors Responsible for the Emergence of the Environment as a Global Issue 1. The Multiplication and Deepening of Environmental Problems.
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an air craft heads north at 320km/hr relative to the wind. The wind velocity is 80km/hr from the north. Find the velocity of the air craft relative to the ground
Answers
Answer:
iyuksouijz
Explanation:
ok,kcipxuoa
A 1,160 kg satellite orbits earth with a tangential speed of 7,446 m/s. if the satellite experiences a centripetal force of 8,955 n, what is the height of the satellite above the surface of earth? recall that earth’s radius is 6.38 × 106 m and earth’s mass is 5.97 × 1024 kg. 3.71 × 1028 m 8.02 × 105 m 7.20 × 105 m 9.67 × 1028 m
Answers
The satellite is 8.02 × 10⁵ m above Earth's surface.
Let H be the height above the surface of the Earth; since we know that the satellite is rotating around the Earth due to the gravitational pull of the planet, we may assert
Procedure to solve:
F = mv²/R+H
H = mv²/F - R
H = (1160 × 7446²/8955 - 6.38 × 10⁶)
M = 8.02 × 10⁵ m
About centripetal force:
The force applied to an item that is in velocity of curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.
The centripetal force formula is given as the product of mass (in kg) and tangential velocity (in meters per second) squared, divided by the radius (in meters) that implies that on doubling the tangential velocity, the centripetal force will be quadrupled. Mathematically it is written as:
F = mv²/r
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Answer:
8.02x 10^5 m
Explanation:
quiz
Which statement describe newtons first law?
Answers
Newton's first law, also known as the law of inertia, states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.
It implies that any object, either stationary or in motion, would remain as it is, unless an external force acts on it. When an external force is applied, it results in a change in motion in terms of direction, speed, or both. This is a statement that describes Newton's first law of motion.Basically, Newton's First Law of Motion states that a body at rest remains at rest and a body in motion maintains uniform motion in a straight line, unless acted upon by an external force.
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The mass of the beam is 3480kg
Calculate the weight of the beam. Remember that a mass of 1 kg has a
weight of 10 N.
Answers
Answer:
34800N
Explanation:
weight = mass × gravitational field strength
w=mg
w= 3480×10. (Gravitational field strength is constant at the value of 10)
w=34800N
three resistors in parallel have an equivalent resistance of 5.0 ω . two of the resistors have resistances of 20 ω and 40 ω .
Answers
The resistance of the third resistor is 8.0 Ω
Let R be the resistance of the third resistor in parallel. Using the formula for the equivalent resistance of resistors in parallel:
1/Req = 1/R1 + 1/R2 + 1/R3
Where Req is the equivalent resistance and R1, R2, and R3 are the resistances of the three resistors, we can write:
1/5.0 = 1/20 + 1/40 + 1/R
Simplifying this equation, we get:
1/R = 1/5.0 - 1/20 - 1/40
1/R = 0.2 - 0.05 - 0.025
1/R = 0.125
R = 1/0.125
R = 8.0 Ω
Therefore, the resistance of the third resistor is 8.0 Ω
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a 5-kg concrete block is lowered with a downward acceleration of 2.8 m/s2 by means of a rope. the force of the block on the rope is:
Answers
The force of the block on the rope can be calculated using Newton's second law of motion, which states that force is equal to mass times acceleration (F = m*a).
In this case, the mass of the concrete block is 5 kg and the downward acceleration is 2.8 m/s2.
To find the force, we can plug in these values into the equation:
F = m*a
F = 5 kg * 2.8 m/s2
F = 14 N
Therefore, the force of the block on the rope is 14 N.
It is important to note that this force is acting in the downward direction, as indicated by the downward acceleration.
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A book of mass 0.4 kg is pushed to the left across a table with a force of 2.4 N. Kinetic friction provides a force of magnitude 0.8 N.
What is the normal force acting on the book? N
Answers
If a book of mass 0.4 kg is pushed to the left across a table with a force of 2.4 N. Kinetic friction provides a force of magnitude 0.8 N, then the normal force acting on the book would be 3.92 Newtons.
What is friction?Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.
As given in the problem If a book of mass 0.4 kg is pushed to the left across a table with a force of 2.4 N. Kinetic friction provides a force of magnitude 0.8 N,
The normal force = m × g
= 0.4 × 9.8
= 3.92 Newtons
Thus, the normal force acting on the book would be 3.92 Newtons.
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what could be the size of the free block just before it was partitioned by x
Answers
The size of the free block just before it was partitioned by x is 2M+5M=7M. If x is a large block, the size of the free block will be smaller than if x is a small block.
An operating system has a "free space list" that keeps track of the available blocks. When a file is generated, the operating system looks through the list of available free space for the needed space to save a file. The file system releases the specified space when a file is deleted and adds it to the "free space list." Free space is crucial because when a file system fills up, file access efficiency decreases. UFS file systems function well as long as there is sufficient free space. Only root has access to the reserved free space when a file system is full, consuming up all of the available user space.
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Jenna took an open bowl of leftover mashed potatoes from the refrigerator and noticed a difference in smell. She determined that chemical changes occurred since the potatoes were first placed there.
Which observations most likely led to Jenna’s conclusion?
a change of odor
a decrease in temperature
a change in moisture content
a decrease in mass
Answers
Answer:
A change of odor
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if we observe a star's spectrum and find that the peak power occurs at the border between red and infrared light, what is the approximate surface temperature of the star?
Answers
The approximate surface temperature of the star when the peak power occurs at the border between red and infrared light is about 4143 Kelvin.
To find the approximate surface temperature of a star when the peak power occurs at the border between red and infrared light, you can use Wien's Law. Wien's Law relates the peak wavelength of emitted light to the surface temperature of a black body (in this case, the star). The formula for Wien's Law is:
λ_max = b / T
where λ_max is the peak wavelength, b is Wien's constant (approximately 2.9 x 10^(-3) mK), and T is the surface temperature in Kelvin.
The border between red and infrared light is around 700 nm (7 x 10^(-7) m). Plugging this value into Wien's Law:
7 x 10⁻⁷ m = (2.9 x 10⁻³ mK) / T
To find T, we'll rearrange the formula and solve for the surface temperature:
T = (2.9 x 10⁻³ mK) / (7 x 10⁻⁷ m)
T ≈ 4143 K
So, the approximate surface temperature of the star when the peak power occurs at the border between red and infrared light is about 4143 Kelvin.
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