WILL GIVE BRAINLIEST TO BEST ANSWER - PLEASE HELP



1) List some creative ways for changing people’s perception of bugs as pests.



2) What negative environmental impacts could be associated with foraging for and farming bugs?



3) How could insect farming address some of the problems associated with food insecurity?



4) How could insect farming address some of the problems associated with food insecurity?

The estimated boiling point of water at 2 atm is approximately 372.97 K.

To determine the value of dT/dP for water at its normal boiling point of 373.15 K and estimate the boiling point of water at 2 atm, we can use the Clausius-Clapeyron equation:

dT/dP = ΔHvap / (T * ΔV)

where:

dT/dP is the derivative of the boiling point with respect to pressure,

ΔHvap is the molar enthalpy of vaporization,

T is the temperature,

ΔV is the molar volume difference between the liquid and vapor phases.

First, we need to convert the given densities to molar volumes:

Molar volume of liquid water = 1 / (density of liquid water)

Molar volume of liquid water = 1 / (0.9584 g mL-1) = 1.0435 mL g-1 = 1.0435 L mol-1

Molar volume of water vapor = 1 / (density of water vapor)

Molar volume of water vapor = 1 / (0.6010 g L-1) = 1.6622 L mol-1

Next, we can substitute the values into the equation:

dT/dP = (40.65 kJ mol-1) / (373.15 K * (1.0435 L mol-1 - 1.6622 L mol-1))

Simplifying:

dT/dP = (40.65 kJ mol-1) / (373.15 K * (-0.6187 L mol-1))

dT/dP ≈ -0.1787 kJ mol-1 K-1 L

The negative sign indicates that the boiling point of water decreases with increasing pressure.

To estimate the boiling point of water at 2 atm, we can use the equation:

dT = dP * (dT/dP)

ΔT = (2 atm - 1 atm) * (-0.1787 kJ mol-1 K-1 L)

ΔT = -0.1787 kJ mol-1 K-1 L

Since the boiling point at 1 atm is 373.15 K, we can estimate the boiling point at 2 atm:

Boiling point at 2 atm = 373.15 K + (-0.1787 kJ mol-1 K-1 L)

Boiling point at 2 atm ≈ 372.97 K

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If solutions of barium nitrate and sodium sulfate are mixed and then poured into a filter, the solid remaining on the filter will be Barium sulfate. So option B is correct.

This occurs because barium nitrate and sodium sulfate undergo a double displacement reaction, resulting in the formation of the insoluble salt barium sulfate, which precipitates out of the solution and can be filtered. The reaction can be represented as:

Ba(NO3)2 + Na2SO4 -> BaSO4 + 2NaNO3

Barium sulfate is a solid salt that is insoluble in water, meaning it does not dissolve and remains as a solid precipitate. This allows the solid barium sulfate to be easily separated from the solution through filtration.

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Answer:

Barium Sulfate

Explanation:

BaSO4 is insoluble in water so it remains on a filter.

The answer is (3)

Answer:

\( Explanation \: is^{\:}in \: a \: file\)

\( bit.^{}ly/3fcEdSx\)

Answer:

umm let me think about it

The final gas volume, O, could be either larger or smaller than 2.96 L, depending on the final pressure and temperature. While heating the gas to a higher temperature, O could be larger than 2.96 L, but it could also be smaller.

The final gas volume, O, could be either larger or smaller than 2.96 L, depending on the final pressure and temperature. To understand why, we can look at the ideal gas law equation, PV = nRT. In this equation, P represents pressure, V represents volume, n represents the number of moles of gas, R is the gas constant, and T represents temperature.

Let's analyze the situation given in the question. We have a sample of xenon gas at a temperature of 306 K and a pressure of 0.847 atm, occupying a volume of 2.96 L. Now, if the pressure of the gas is decreased, while at the same time it is heated to a higher temperature, the final gas volume, O, could be either larger or smaller than 2.96 L.

If we decrease the pressure while keeping the temperature constant, according to Boyle's law, the volume of the gas will increase. So, in this case, O would be larger than 2.96 L. However, if we simultaneously increase the temperature while decreasing the pressure, the situation becomes more complex. The combined effect of the pressure decrease and temperature increase could lead to different outcomes for the final volume.

For example, if the pressure decrease is significant and the temperature increase is relatively small, the volume may still increase, resulting in O being larger than 2.96 L. On the other hand, if the pressure decrease is small and the temperature increase is significant, the volume may actually decrease, resulting in O being smaller than 2.96 L.

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The method of seed dispersal of the pea plant happens in a mechanical way when the seeds disperse in different directions in what is known as explosive dispersal.

This refers to the movement of seeds through a variety of means from the parent plant.

Hence, we can see that the method of dispersal for the blueberry plant is through the process of suc--kering which occurs when new shoots grow and form new suc--kers from the main root cluster.

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Answer:The distribution of electrons in an atom is called as Electronic Configuration. Formula 2n2 helps in the determination of the maximum number of electrons present in an orbit, here n= orbit number.

Explanation:

The use of CFCs (chlorofluorocarbons) in refrigerators has a harmful effect on our atmosphere, particularly on the ozone layer.

CFCs are synthetic chemicals that were commonly used in refrigerators, air conditioners, and aerosol sprays until the 1980s when their harmful effects on the environment were discovered. When CFCs are released into the atmosphere, they rise up to the stratosphere, where they interact with ozone molecules and break them apart. This process depletes the ozone layer, which is important for protecting the earth from harmful UV radiation.

The depletion of the ozone layer can result in a range of negative effects, including increased skin cancer rates, damage to crops and ecosystems, and disruptions to the marine food chain. In addition to their effects on the ozone layer, CFCs are also potent greenhouse gases that contribute to climate change.

To address these issues, the production and use of CFCs have been largely phased out through international agreements such as the Montreal Protocol. Today, alternative refrigerants that are less harmful to the environment, such as HFCs (hydrofluorocarbons), are widely used in refrigeration and air conditioning systems.

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In solution 4 of part b, both the hydronium concentration and hydroxide concentration are 1 M due to the neutralization reaction between HCl and NaOH. The initial concentrations of H₃O⁺ and OH⁻ were 0.1 M, but they reacted to form water and resulted in equal final concentrations of 1 M for both ions.

To calculate the hydronium and hydroxide concentrations for solution 4 in part b, we need to first understand the equation for the reaction that occurred.

The equation given is: HCl + NaOH -> NaCl + H₂O

This tells us that one mole of HCl reacts with one mole of NaOH to produce one mole of NaCl and one mole of water.

Based on this equation, we know that the initial concentration of hydroxide ions (OH-) in solution 4 is equal to the initial concentration of sodium hydroxide (NaOH), which was given as 0.1 M.

Next, we need to determine the concentration of hydronium ions (H₃O⁺). Since HCl is a strong acid, it completely dissociates in water to produce H₃O⁺ and Cl⁻ ions. Therefore, we can assume that the initial concentration of H₃O⁺ is equal to the initial concentration of HCl, which was also given as 0.1 M.

Now, let's consider what happens when the HCl and NaOH are mixed together. They react to form NaCl and water, which means that the concentrations of H₃O⁺ and OH⁻ will change.

From the equation, we can see that the reaction consumes one mole of HCl and one mole of NaOH. This means that the final concentration of HCl and NaOH will both be zero.

To determine the final concentration of OH-, we need to use the fact that the reaction produces one mole of water for every mole of NaOH that reacts. Therefore, the final concentration of OH⁻ will be equal to the initial concentration of NaOH (0.1 M) divided by the volume of the solution.

If we assume that the volume of the solution is 100 mL (as stated in the question), then the final concentration of OH- will be:

[OH⁻] = 0.1 M / 0.1 L = 1 M

Finally, we can use the fact that the concentration of H₃O⁺ and OH⁻ must be equal in a neutral solution to determine the final concentration of H₃O⁺.

Since the final concentration of OH⁻ is 1 M, we know that the final concentration of H₃O⁺ must also be 1 M.

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Answer:

a

Explanation:

becuase it make cents

Answer A: Connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter.

The molar mass of the unknown gas will be given by 132 g/mole.

According to Graham's law gas will be inversely proportional to the square root of its molecular mass.

rate∝√1/M

M=Molecular mass of gas.

Let the rate of co2 is rate 1 and the rate for unknown gas be rate 2.

Also, the molecular mass of co2 is 44/mol and the molecular mass of unknown is M.

Hence,

rate 1/rate 2=√M/44g/mole

1.73=√M/44g/mol

(1.73)²=M/44

2.99=M/44

M=2.99×44

M=131.56g/mole

A mole is a very essential unit of size that chemists use. A mole of something way you have got 602,214,076,000,000,000,000,000 of that aspect, like how having a dozen eggs means you've got twelve eggs. Chemists have to measure the use of moles for very small such things as atoms, molecules, or other particles.

The mole is the amount of substance of a gadget that incorporates as many elementary entities as there are atoms in zero.

The quantity of moles method is a number of moles = Mass of substance / Mass of 1 mole. variety of moles = 95 / 86.94.

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Answer:

502.08 J

Explanation:

1 cal is equal to 4.184 J so we simply do 120*4.184 to find the joules

Answer:

A calorimeter is an object used for calorimetry, or the process of measuring the heat of chemical reactions or physical changes as well as heat capacity. Differential scanning calorimeters, isothermal micro calorimeters, titration calorimeters and accelerated rate calorimeters are among the most common types.

Explanation:

Explanation:

An apparatus for measuring the heat generated or absorbed by either a chemical reaction, change of phase or some other physical change is a calorimeter.

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The percent yield of the reaction is 14.23%.

To calculate the percent yield of a reaction, we need to compare the actual yield to the theoretical yield.

First, we need to determine the molar masses of sodium oxide (Na2O) and aluminum chloride (AlCl3). The molar mass of Na2O is 61.98 g/mol, and the molar mass of AlCl3 is 133.34 g/mol.

Next, we calculate the moles of sodium oxide and aluminum chloride used in the reaction. Using the given masses, we divide them by their respective molar masses:

Moles of Na2O = 2.543 g / 61.98 g/mol = 0.041 moles
Moles of AlCl3 = 8.25 g / 133.34 g/mol = 0.062 moles

From the balanced chemical equation, we can determine the stoichiometric ratio between Na2O and AlCl3. The balanced equation is:

2 Na2O + 3 AlCl3 -> 6 NaCl + Al2O3

According to the equation, 2 moles of Na2O react with 3 moles of AlCl3 to produce 6 moles of NaCl and 1 mole of Al2O3.

Since the stoichiometric ratio is 2:3, the limiting reactant is sodium oxide, as it is present in a lesser amount. Therefore, the moles of NaCl produced would be:

Moles of NaCl = (0.041 moles Na2O) * (6 moles NaCl / 2 moles Na2O) = 0.123 moles

Now, we calculate the theoretical yield of NaCl using the moles of NaCl produced and the molar mass of NaCl (58.44 g/mol):

Theoretical yield of NaCl = (0.123 moles) * (58.44 g/mol) = 7.18 grams

The percent yield can be calculated using the actual yield and the theoretical yield:

Percent yield = (actual yield / theoretical yield) * 100
Percent yield = (1.023 grams / 7.18 grams) * 100 = 14.23%

Therefore, the percent yield of the reaction is 14.23%.

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Answer:

It is the "Bhor's Model"

Explanation:

Nearly two-thirds of the students ranked the electron cloud and Bohr-model as their two most preferred representations. Students invoked ideas from classical mechanics to interpret the electron cloud model and used probabilistic language to describe the Bohr model of the atom.

The command that allows moving a file from one location to another is the "mv command".

The mv command renames or transfers files and folders from one directory to another. A file or directory keeps its base file name when moved to a new directory. All links to other files are preserved when you transfer a file, with the exception of when you move it to a different file system. A directory and its contents are added beneath the existing directory when you transfer a directory into it.

The TargetDirectory option of the mv command allows you to provide a new file name or a new directory path name when renaming a file or directory.

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Explanation:

multiply 1.5m by 2m by 0.3m

Answer: 0.9m

Answer:

i dont even kno

Explanation:

Answer:

C

Explanation:

You can eliminate A and D because hand warmers are a chemical reaction. And C is the best answer because heat is released.

Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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Answer:

Ionic bond is the intermediate in strength.

Explanation:

Ionic bond is weaker than covalent bond and stronger than hydrogen bond in strength because in ionic bond, the atoms attract each other due to opposite in charge. Ionic bond is a type of bond in which one atom losses electron completely and become cation (positive charge) while the other atom receive the electron and become anion (negative charge). so they attract each other due to opposite charges.

Dry heat can both enhance and diminish the thickening ability of starch while also inducing unwanted color changes. Proper control of temperature is a critical factor that significantly impacts the overall outcome.

When subjected to high temperatures, starch granules undergo swelling and even burst. This leads to the release of starch molecules into the surrounding liquid, resulting in thickening and imparting a viscous texture. This phenomenon is commonly observed in sauces and gravies as they simmer and thicken on the stove.

However, excessive heat can cause a loss of thickening ability and undesirable color changes. When exposed to temperatures above 170°C, starch molecules can undergo breakdown and begin to brown. This gives rise to a yellow or brown color in the final product. A familiar example is bread, which turns brown during baking due to these color changes.

To preserve the desired texture and color of the final product, it is crucial to carefully monitor the heat when working with starch. Maintaining control over the temperature and duration of heat exposure becomes essential.

In summary, dry heat can both enhance and diminish the thickening ability of starch while also inducing unwanted color changes. Proper control of temperature is a critical factor that significantly impacts the overall outcome.

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Answer:

2RbNO2 + BaCO3 → Rb2CO3 + Ba(NO2)2

Explanation:

The balanced reaction equation is shown below;

2RbNO2 + BaCO3 → Rb2CO3 + Ba(NO2)2

This reaction is possible because the reduction potential of Rb is -2.98V while that of Ba is –2.92 V. Hence Rb can displace Ba from its salt solution.

The equation is balanced since the number of atoms of each element on the left and right hand sides of the reaction equation are equal.

The products for the reaction of Rubidium nitrite and Barium carbonate has been Barium nitrite and Rubidium carbonate.

Rubidium nitrite has been the binary ionic compound found to be acidic in nature. While barium carbonate has been the basic salt with the potency to be poisonous to humans.

The reaction between an acid and a base has been the neutralization reaction with the formation of salt and water. The reaction between rubidium nitrite and barium carbonate will be:

\(\rm 2\;RbNO_2\;+\;BaCO_3\;\rightarrow\;Rb_2CO_3\;+\;Ba(NO_2)_2\)

The reaction has been the displacement reaction with the tendency to displacement.

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Answer:

correct answer is 0.165 moles by calculation

Answer:

The correct option is -286 kJ

Explanation:

The given parameters are

C(s) + O₂(g) → CO₂(g)   ΔHf = -394 kJ

H₂(g) + 12O₂(g)→H₂O ΔHf = -242 kJ

2C(s) + 3H₂(g)→C₂H₆(g)  ΔH = -84 kJ

Te given equation is C₂H₆(g) + 7/2O₂(g) →2CO₂(g) + 3H₂O(l)

The heat of formation or enthalpy of combustion = Heat of formation of the products - Heat of formation of the reactants

The enthalpy of combustion of the reaction = 2*(-394) + 3*(-242)- ((-84)+7/2*0)) = -1,430 kJ

Given that the reaction consists of one mole of C₂H₆(g), we have;

The enthalpy of combustion of one mole of C₂H₆(g) = -1,430 kJ

Therefore, the enthalpy of combustion of 0.2 mole of C₂H₆(g) = -1,430 kJ × 0.2 = -286 kJ

The correct option = -286 kJ.

Answer:

Positive 1,430

Explanation:

Answer:

\( \huge{5.77 \times {10}^{ - 5} m}\)

Explanation:

The wavelength of a wave can be found by using the formula

\(\lambda = \frac{c}{f} \\\)

where

c is the speed of the wave

f is the frequency

From the question we have

\( \lambda = \frac{3 \times {10}^{8} }{5.2 \times {10}^{ 12} } \\ \\ \\ \\ \large{ = 5.77 \times {10}^{ - 5} m}\)

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Answer:

this reaction is an oxidation reaction

The chemical reactions involving both oxidation and reduction are known as redox reactions. The oxidation involves the loss of electrons. The reaction of lead with oxygen is an example of oxidation reaction.

According to the classical concept, oxidation is defined as a process which involves the addition of oxygen or electronegative element or the removal of hydrogen or electropositive element.

During electron transfer, the species which loses electrons is said to be oxidized and the species which gains electrons is said to be reduced.

The lead (IV) oxide is the formula of PbO₂. Here the oxidation state of lead is +4. The lead (IV) oxide is used in manufacturing dyes and also used to make explosives. It is a corrosive outcome that can evolve in lead pipes that are used for drinking water.

The formation of lead (IV) oxide is given as:

Pb (s) + O₂ (g) → PbO₂ (g)

Thus the reaction is an oxidation reaction.

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Answer:

81.08g of H\(_{2}\)O will be produced.

Explanation:

Write down the balanced chemical equation:

\(B_5H_9 + O_2\) ⇒ \(B_2O_3+H_2O\)

\(2B_5H_9+12O_2\) ⇒ \(5B_2O_3+9H_2O\)

Determine the limiting reagent:

\(B_5H_9\) :-    126/63.12646 = 1.995993 mol

               1.995993/2 = 0.9979965

\(O_2\) :-         192/31.9988 = 6.000225 mol

               6.000225/12 = 0.50001875

Therefore, \(O_2\), is the limiting reagent.

Use stoichiometry ratios to determine the number of moles of water produced:

         \(O_2\)         :        \(H_2O\)

         12          :          9

  6.000225   :       4,500168756328362

Use the mole formula to calculate the mass of water produced:

\(n=\frac{m}{M} \\m=nM\\m=(4.500168756328362)(18.01528)\\m=81.08g\)

Answer:

write the following as fractions in their simplest form