wich equation shows 5 is a factor of 45

I am the number 4052. It is rather confusing and i cannot promise that it is correct. Hope it helps : )

Answer:

J. 1

Step-by-step explanation:

Plug the x values into the equation:

f(-1)=3-(-1)^2

f(2)=3-(2)^2

Solve each one, then add.

3-(-1)^2=

=3-1=2

3-(2)^2=

=3-4=-1

Combine the answers together.

2-1=1

The answer is J. 1.

Hope this helps!

Please mark as brainliest if correct!

Estimation Possible year, 2005, when first-class postage was 37 cents, between 2001 and 2006.

First-Class mail is sent when a stamp is applied to an envelope and deposited in a mailbox. First-Class Mail is thus equivalent to "ordinary" mail. The ever-popular First-Class Mail is just one; the postal rate of the several services or "classes" that the Estimation Possible year, 2005, when first-class postage was 37 cents, between 2001 and 2006.

A fee will be assessed by a government postal service for the shipping and delivery of letters.

Assuming the value is supplied,

a) POSTAGE RATES L1=x

L2=y

y= -0.004x2+0.859x+27.53

y=28.381

b) Integers from -10 to 17 are the domain. Range: whole number between 18 and 42

c) From 2001 to 2006, first class postage cost 37 cents.

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Answer:

C= 150.8 I hope this helped! Also I used Google because I didn't know.

Step-by-step explanation:

Answer:

5) 75.36ft

6) 150.72mm

Step-by-step explanation:

Bc, you need to multiply 24 * 3.14 and you'll get 75.36.

The total number of people who have the disease is 115.

The total number of people in the sample population is

Total = 175

The negative predictive value is

NPV= (TN / (TN + FN)) = (25 / (25 + 55) = 25 / 80 = 0.3125

The positive predictive value

PPV = (TP / (TP + FP)) = (60 / (60 + 35) = 60 / 95 = 0.6316

The sensitivity of the test

Sensitivity = (TP / (TP + FN)) = (60 / (60 + 55) = 60 / 115 = 0.5217

The total number of people who have the disease

= 60+55 = 115

The number of False Positives (FP)

= 35

The number of True Positives (TP)

= 60

The total number of people that tested negative

= 80

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Answer:

C is a function, D is not.

Step-by-step explanation:

The equation arccos(cos(5π/6)) = 5π/6 is true.

The arccosine function (arccos) is the inverse of the cosine function. It returns the angle whose cosine is a given value. In this equation, we are calculating arccos(cos(5π/6)).

The cosine of an angle is a periodic function with a period of 2π. That means if we add or subtract any multiple of 2π to an angle, the cosine value remains the same. In this case, 5π/6 is within the range of the principal branch of arccosine (between 0 and π), so we don't need to consider any additional multiples of 2π.

When we evaluate cos(5π/6), we get -√3/2. Now, the arccosine of -√3/2 is 5π/6. This is because the cosine of 5π/6 is -√3/2, and the arccosine function "undoes" the cosine function, giving us back the original angle.

Therefore, arccos(cos(5π/6)) is indeed equal to 5π/6, making the equation true.

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Answer:

16/22, 24/33, and 40/55

or

72.7272...% = Percentage form

0.7272... = Decimal form

Hope this helps :)

Pls brainliest...

Answer:

24

Step-by-step explanation:

Tanner has 6 points so T = 6

Zach has four times as many so Z = 4T

4 * T

= 4 * 6

which is 24.

Answer:

24 = (9 * 6) - (15 + 15)

Step-by-step explanation:

Equation = (9 * 6) - (15 + 15)

Follow PEMDAS which in this case multiply 9 x 6

= 54 - (15+15)

Now you need to add the numbers that are in the parenthesis

= 54 - 30

= 24

Hope this helps!

Answer:

120

Step-by-step explanation:

Answer:

Step-by-step explanation:

0.69

Answer:

Complete question "Variable overhead is applied based on standard direct labor-hours allowed.   Required: Compute the labor and variable overhead price and efficiency variances.

a. Direct labor

Direct labor price variance = (actual rate - standard rate)*actual hrs  

(655,200-37700*x) = 23400  

x = (655200+23400)/37700  

x = 18

Efficiency variance = (Actual hrs - standard hrs allowed)*standard rate  

= (37,700 - 36500)*18

= 21600 U

I. Price variance = 23,400 F  

II. Efficiency variance = 21,600 U

b.  Variable overhead

Price variance = (Actual rate - standard rate)*actual hrs  

= (157120 - 37700*4.2)

= 1220 F    

Efficiency variance = (Actual hrs - standard hrs allowed)*standard rate  

= (37700-36500)*4.2

= 5040 U

I. Price variance = 1,220 F

II. Efficiency variance = 5,040 U

Answer: 30 cm

Step-by-step explanation:

The volume of the composite solid is 17000 cm³. To find h, we must first subtract the volume of the half cylinder from the composite volume.

From the figure, AE = MK, and so the radius of the half cylinder is 10cm. The volume of the half cylinder is thus \(\frac{1}{2}\) the volume of a cylinder. The volume of a cylinder is πr²h. So a half cylinder is 1/2 πr²h. This gives us a volume of  \(\frac{1}{2} (\frac{22}{7})(10 cm)^2(28 cm) = 4400 cm^3\).

Thus, the volume of the right prism is 17000cm³ - 4400cm³ = 12600cm³. Consider the cross-section ABKJ. If we multiply this by AE, we'll have the volume of the right prism.

The ABKJ is a trapezoid so it's area is \(\frac{1}{2}(AJ + BK) \cdot AB\). Thus the volume of the right prism is \(\frac{1}{2}(AJ + BK) \cdot AB \cdot AE\). This gives us \(\frac{1}{2}(28 + 14) \cdot h \cdot 20 = 12600\), and thus h = 30 cm.

Answer:

1) h(max) = 64 ft

2) t = 1 s  

3) t(in air)  = 3 s

4) just after 3 s

Step-by-step explanation:

The height f the ball is:

h(t) = -16*t² + 32*t  + 48

Maximum height is when V(y) = 0

D(h)/dt  = V(y)  = -16*2*t + 32

V(y) = 0       -32*t +  32  = 0

2) t = 1 s     time to reach maximum height

Plugging this value  in equation   h(t) = -16*t² + 32*t  + 48

h(max) = -16*(1)² + 32*(1) + 48

1) h(max) =  16 + 48 = 64 ft  

3)  In equation   h(t) = -16*t² + 32*t  + 48

when h(t) = 0 we find time of the ball in air

16*t² - 32*t  - 48  = 0    a second degree equation solving for x

x₁,₂  =  32 ± √( (32)² + 4*48*16)  / 32

x₁,₂  =  (32 ±  64 )/32

we dismiss negative x ( negative time)

x₂  = 32 + 64 /32

x₂  = 3 s

4) the ball hit the ground just at 3 scond after its thrown

The ball is 3 s in the air ( touch the ground just in that moment)

Given:

Initial population = 4 millions

Growth rate = 7% = 0.07

Present population = 16 millions

To find:

The time it will take for this invasive population to grow from 4 million cane toads to 16 million cane toads.

Solution:

The exponential growth model is

\(P=P_0(1+r)^t\)

where, P is present population, \(P_0\) is iniital population, r is growth rate and t is time in years.

Substitute P=16, \(P_0=4\) and r=0.07, we get

\(16=4(1+0.07)^t\)

Divide both sides by 4.

\(4=(1.07)^t\)

Taking log on both sides.

\(\log 4=\log (1.07)^t\)

\(\log 4=t\log (1.07)\)    \([\because \log x^n=n\log x]\)

\(\dfrac{\log 4}{\log (1.07)}=t\)

\(t=20.4895367\)

Approx the value to the next integer.

\(t\approx 21\)

Therefore, the required number of years is 21.

Answer:

x - 9

Step-by-step explanation:

Answer:

bguiyhvulcvougtjglctvtgulvugtfvufygbgl

Step-by-step explanation:

Answer:

4/3

Step-by-step explanation:

If you count, because the coordinates are smaller, you will know that the y-coordinate moves up 4 spaces, and the x-coordinate moves to the right 3 spaces.

Answer:

3.75 or 3 3/4

Step-by-step explanation:

(3/4) times 5 equals 3.75

Hence, the equation has no solution. The correct option is option C.

It is True to state that Arcs AB, BC, CD, DE, EF, FA in the circumscribed hexagon are all equal. See the explanation below.

In geometry, a hexagon is a six-sided polygon. A regular hexagon is one in which the lengths of all the sides and the measurements of all the angles are identical. The sides of a regular hexagon are therefore equivalent.

Allow point P to be the hexagon's and circle's center.

The dimension of arc AB is the same as the measure of central angle APB, which are both 360/6 = 60 degrees. This also applies to the other arc measurements. The whole 360-degree circle is divided into six equal parts, each measuring 60 degrees.

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Full Question:

Although the question seems incomplete you may have been referring to this:


A circle P is circumscribed about a regular hexagon ABCDEF

Arcs AB, BC, CD, DE, EF, FA are all equal

Select one:

a. False

b. True

Answer:

two

Step-by-step explanation:

solutions are where lines cross

the solutions for this system are (2,0) and (-6,8)

Answer:

2 solutions

Step-by-step explanation:

The solutions are the point(s) of intersection.

By inspection of the graph we can see that line (blue) intersects the parabola (red) at 2 points.

Therefore, the system of equations has 2 solutions.

The answer using positive exponents only is 16x^(24)y^(16).

To simplify the expression (2x^(6)y^(4))^(4), we need to use the properties of exponents. Specifically, we need to use the property that states (a^(m))^n = a^(m*n). This means that when we raise a power to another power, we multiply the exponents.

Using this property, we can simplify the expression as follows:

(2x^(6)y^(4))^(4) = 2^(4) * x^(6*4) * y^(4*4) = 16 * x^(24) * y^(16)

So, the simplified expression is 16x^(24)y^(16).

Therefore, the answer using positive exponents only is 16x^(24)y^(16).

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Answer:

0.05

Step-by-step explanation:

Answer:

it cost 5 cents every ounce

Step-by-step explanation:

0.60 = 12

0.05 = 1

Answer: D

Desmos said so

The relation R defined on X={1,2,⋯,20} as xRy if x≡y+1 (mod5) is not reflexive, not symmetric, and not transitive. These counter-examples demonstrate the violation of each property: reflexivity, symmetry, and transitivity, respectively.

To show that R is not reflexive, we need to find an element x in X such that x is not related to itself under R. For example, let's take x=1. In this case, 1R1 means 1≡1+1 (mod5), which is not true. Therefore, R is not reflexive.

To demonstrate that R is not symmetric, we need to find elements x and y such that xRy but yRx does not hold. Let's consider x=2 and y=1. We have \(2R_1\) because 2≡1+1 (mod5), but \(1R_2\) is not true since 1 is not congruent to 2+1 (mod5). Hence, R is not symmetric.

Lastly, to prove that R is not transitive, we need to find elements x, y, and z such that if xRy and yRz hold, xRz does not hold. Let's choose x=1, y=2, and z=3. We have \(1R_2\) because 1≡2+1 (mod5) and \(2R_3\) since 2≡3+1 (mod5). However, \(1R_3\) is not true because 1 is not congruent to 3+1 (mod5). Thus, R is not transitive.

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Answer:

x=2

Step-by-step explanation:

use the cover up method

Answer:

It is D. 21

Step-by-step explanation: