Answer:
the point of contact Thè path different is zero but
one of inter ferying ray is reflected so the effective path difference become / 2 and in this condition minimum intensity is created at center so the center of Newton ring is darkHow do humans get energy from
living things?
Answer:
The flow of energy through living organisms begins with photoshypothesis. This process stores energy from sunlight in the chemical bonds of glucose. By breaking the chemical bond in glucose, cells release the stored energy and make the ATP they need.
Explanation:
Or humans get energy from other things in the biosphere.
An object of mass 3 kg is accelerated at 4 m/s2. What force is acting on the object?
Answer:
12 N
Explanation:
Given,
Mass ( m ) = 3 kg
Acceleration ( a ) = 4 m/s^2
To find : Force ( F ) = ?
Formula : -
F = ma
F
= 3 x 4
= 12 N
Therefore, the force acting on the object is 12 N.
Answer: 12 N
Explanation:
If a body losses 20gram of electron. How much electron did the body lose
The body lost approximately 1.2047 x 10^20 electrons.
The charge of an electron is -1.602 x 10^-19 coulombs, which means that a loss of 20 grams of electrons is equivalent to a loss of (20/0.000911) moles of electrons, since the molar mass of electrons is 0.000911 grams/mole.
One mole of electrons contains 6.022 x 10^23 electrons (Avogadro's number), so the body lost (20/0.000911) x 6.022 x 10^23 electrons, which simplifies to approximately 1.2047 x 10^20 electrons. Therefore, the body lost approximately 1.2047 x 10^20 electrons.
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(Newton's Law of Cooling): The mathematical formulation of Newton's empirical law of cooling/warming of an object is given by the linear first-order differential equation
dt
dT
=k(T−T
s
), where k is a constant of proportionality, T(t) is the temperature of the object at any time t≥0, and T
s
is the surrounding environmental temeperature, that is, the temperature of the medium around the object. (i). Assuming that T
s
is constant, find the temeperature of the object as a function of time if T(0)=T
0
. (ii). Then what is the temepretauer of the object after 5 minutes?
Newton's Law of Cooling is described by the first-order linear differential equation dt/dT = k(T - Ts), where T(t) is the temperature of the object at time t, Ts is the surrounding environmental temperature, and k is the constant of proportionality.
The temperature of an object, governed by Newton's Law of Cooling
(i) To find the temperature of the object as a function of time, we first solve the differential equation dt/dT = k(T - Ts). This is a separable differential equation, and the solution can be obtained by rearranging and integrating:
dt/dT = k(T - Ts)
dt = k(T - Ts) dT
∫ dt = ∫ k(T - Ts) dT
t = k * ∫ (T - Ts) dT
t = k * (T^2/2 - Ts*T) + C
Now, we apply the initial condition T(0) = T0. At t=0, the temperature of the object is T0:
T(0) = T0
k * (\(T0^2\)/2 - Ts*T0) + C = T0
C = T0 - k * (\(T0^2\)/2 - Ts*T0)
C = T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2
C = T0 - k * (\(T0^2\) - 2 * Ts * T0) / 2
So, the equation becomes:
t = k * (\(T^2\)/2 - Ts*T) + (T0 - k * (\(T0^2\)- 2 * Ts * T0) / 2)
(ii) Now, we can find the temperature of the object after 5 minutes (t = 5 minutes). We'll use the initial condition T(0) = T0 and the formula obtained in part (i):
t = 5 minutes = 5/60 hours = 1/12 hours
T(t) = Ts + (T0 - Ts) * exp(-kt)
T(1/12) = Ts + (T0 - Ts) * exp(-k * (1/12))
This equation gives us the temperature of the object after 5 minutes, considering the given initial temperature T0 and the surrounding environmental temperature Ts.
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The Tesla Model S Electric vehicle can go from 0 to 60 mi/hr (26.8 m/s) in only 1.9 seconds! How far does it move from rest until it reaches 60 mi/hr? Round your answer to the nearest whole meter.
Answer:
The Tesla moves approx. 25 meters from rest before reaching 60 mi/hr
Explanation:
Given:
Initial velocity = 0 m/s
Final velocity = 26.8 m/s
Time = 1.9 seconds
Acceleration = change in velocity/time
\(a = \frac{26.8}{1.9}\)
The equation to find displacement (Δx) with given starting and final velocity, time, and acceleration is:
\(x = x_{0} + v_{0}t + \frac{1}{2} at^{2}\)
Starting position and initial velocity both equal 0, so
\(x = \frac{1}{2} at^{2}\)
\(x=\frac{1}{2} (\frac{26.8}{1.9})(1.9)^{2}\)
x = 25.46m
Rounded to the nearest whole number, x = 25m
Lightning McQueen is traveling at 34.5 m/sec. If he drives for 300 seconds, how many meters would
he cover?
Answer:
10,350 m
Explanation:
Distance = speed x time
Distance = 34.5 m/s x 300 s = 10,350 m
Answer:
If lightning McQueen travels at 34.5 m/s 300 secs
= 34.5*300
= 10,350 meters
Therefore we can see that lightning McQueen would travel 10,350 meter or 10.35 KM in 300secs or 5 mins if he has a stable speed of 34.5m/s
3 simple machines you find in a pinball machine
lever (The things that flick the ball around)
Inclined plane (The hill the ball rolls down)
Wedge (The bumps that stop the ball from rolling certain places)
find the slope of the graph of the equation at the given point. (if an answer is undefined, enter undefined.) xy − 9y2 = 4, (20, 2)
The slope of the graph of the equation at the point (20, 2) is 1/8.
To find the slope of the graph of the equation at the given point (20, 2), we need to find the derivative of the equation with respect to x and evaluate it at x = 20. Let's differentiate the equation implicitly:
xy - 9y^2 = 4
To differentiate implicitly, we treat y as a function of x and apply the chain rule. Differentiating both sides of the equation with respect to x:
1 * y + x * dy/dx - 9 * 2y * dy/dx = 0
Simplifying this equation:
y + x * dy/dx - 18y * dy/dx = 0
Grouping the terms with dy/dx:
dy/dx * (x - 18y) = -y
Now, let's solve for dy/dx by dividing both sides by (x - 18y):
dy/dx = -y / (x - 18y)
Substituting the given point (20, 2) into the equation:
dy/dx = -2 / (20 - 18(2))
= -2 / (20 - 36)
= -2 / (-16)
= 1/8
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A student uses the right-hand rule as shown. an illustration with a right hand with fingers curled and thumb pointed up. what is the direction of the magnetic field in front of the wire closest to the student? up right down left
The direction of the magnetic field in front of the wire closest to the student is on the left. The direction is found by the right-hand rule.
What is the right-hand rule?The right-hand rule is a popular mnemonic for remembering how axes in three-dimensional space are oriented.
The fact that the three axes of three-dimensional space have two different orientations gives birth to the majority of the many left-hand and right-hand rules.
Using the right-hand rule, we can recall this diagram. Your thumb points in the direction of the magnetic force pushing on the moving charge
If you point your pointer finger in the direction of the positive charge and then your middle finger in the direction of the magnetic field.
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Answer:
left
Explanation:
edge 2022
You throw a dodge ball with a mass of 2.1 kg. The ball leaves your hand with a speed of 25 m/s. Identify the energy (PE or KE) and calculate it.
Given,
The mass of the object, m=2.1 kg
The speed of the object, v=25 m/s
Kinetic energy is the energy that an object possesses due to its motion. And potential energy is the energy that an object possesses due to its position.
The gravitational potential energy depends on the height of the object. As the change in the height of the object is not mentioned in the question, let us assume that there is no change in the potential energy.
The velocity of the object, however, changes. Thus the energy possessed by the object is the kinetic energy.
And the kinetic is given by
\(E_K=\frac{1}{2}mv^2\)On substituting the known values,
\(\begin{gathered} E_K=\frac{1}{2}\times2.1\times25^2 \\ =656.25\text{ J} \end{gathered}\)Thus the kinetic energy of the ball is 656.25 J
A child in a swing makes 5 complete back and forth vibrations in 13.5 seconds. Determine the vibrational period of the child, along with the corresponding unit.
Answer:
2.7 sec / vibrat.
Explanation:
Frequency = 5 cycles / 13.5 sec
Period = 1/ frequency = 13.5 sec / 5 cycle
The required vibrational period of the child's swing is 2.7 seconds. The unit for the period is seconds (s).
What is vibration?Vibration is a repetitive motion that occurs around an equilibrium point. When an object vibrates, it oscillates back and forth, up and down, or side to side in a periodic manner. The motion is typically caused by a disturbance or a force applied to the object.
Here,
The vibrational period of a pendulum or swing is the time it takes for one complete back-and-forth vibration. We can find the period (T) of the child's swing using the given information,
Number of vibrations = 5
Time for 5 vibrations = 13.5 seconds
The period (T) of one vibration is equal to the time for 5 vibrations divided by the number of vibrations
T = (Time for 5 vibrations) / (Number of vibrations)
T = 13.5 s / 5
T = 2.7 s
Therefore, the vibrational period of the child's swing is 2.7 seconds. The unit for the period in seconds (s).
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the force of gravity of an object is 734 n. what would be the value of fg if the object was brought to a planet with 3 times the radius of earth?
The value of fg would be 244.7 N if the object was brought to a planet with 3 times the radius of the earth.
What is gravity?
All matter is attracted to one another by gravity, which is also known as a gravitational force in mechanics. It is by far the weakest known force in nature and has little bearing on how ordinary matter behaves within.
The structure and growth of stars, galaxies, and the entire cosmos are all under its influence, as are the orbits of some things. The weight of the Earth operates on all objects on Earth, giving them a weight or gravitational pull that is proportionate to their mass.
The acceleration that gravity gives a falling item is how it is measured. The acceleration of gravity is roughly 9.8 metres (32 feet) per second at the surface of the Earth. Her body is falling at a faster rate the longer it is in free fall.
Her body is falling free at a rate of around 9.8 metres per second. A free-falling object on the moon accelerates at a rate of about 1.6 metres per second.
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a wire having mass per unit length of 0.460 g/cm carries a 2.12 a current horizontally to the south. what are the direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward? magnitude
The direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward is clock wise direction and 0.245T.
What is a magnetic field?The magnetic field is the area that is affected by magnetism and is located around a magnet. The magnetic field is a valuable tool for explaining the distribution of the magnetic force within and around a magnetic object in nature.
The mass per unit length of the wire = 0.460 g/cm = 0.046 kg/m
Current in the wire, A = 2.12 A (due south)
To find,
The minimal magnetic field's magnitude as well as its direction.
F = ILB = mg
B = mg/IL
B = 0.046 × 9.8 /2
B = 0.225T
B = 0.245T.
The right hand rule specifies the magnetic field's direction, which is clockwise around the wire.
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a. How far does a 100-newton force have to move to do 1,000 joules
of work?
b. An electric hoist does 500 joules of work lifting a crate 2 meters. How
much force does the hoist use?
c. An athlete does one push-up. In the process, she moves half of her body
weight, 250 newtons, a distance of 20 centimeters. This distance is the
distance her center of gravity moves when she fully extends her arms. How
much work did she do after one push-up?
d. You decide to push on a brick wall with all your might for 5 minutes. You
push so hard that you begin to sweat. However, the wall does not move. If
you end up pushing with a force of 500 newtons, how much work did you
do?
Work done by a force is given as the product of force and the distance moved by the force.
What is work done?Work done is the product of force and the distance moved by the the force.
Work done = Force × distanceThus, distance required by the 100 N force is given as:
Distance = work done/forceDistance = 1000/100 = 10 m
Distance to be moved is 10 m.
Force applied = work done/ distance
Force applied by the hoist = 500/2
Force applied by the hoist = 250 N
Distance moved in one push-up = 25 cm = 0.25 m
Work done by the athlete after one push-up = 250 × 0.25 m
Work done by the athlete = 62.5 J
Distance moved by the force = 0 m
Work done = 500 × 0 = 0 N
Therefore, for work to be done, force has to move a distance.
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what is relavite velocity?
Answer:
The relative velocity {\displaystyle {\vec {v}}_{B\mid A}} is the velocity of an object or observer B in the rest frame of another object or observer A.
Answer:
The relative velocity is defined as the velocity of an object with respect to another observer. It is the time rate of change of relative position of one object with respect to another object.
an object is located at a distance of 101 cm from a concave mirror of focal length 23.9 cm. another concave mirror of focal length 5.21 cm is located 23.9 cm in front of the first concave mirror. the reflecting sides of the two mirrors face each other. assume the second mirror is partially silvered so that the light rays from the object go through it, reflect from the first mirror, and then reflect from the second mirror. a) what is the location of the final image formed by the two mirrors? give your answer in terms of the distance from the second mirror.
The final image formed by the two mirrors is located at a distance of 18.7 cm from the second mirror.
When light rays from an object pass through a concave mirror, they converge to a point known as the focal point. The distance between the focal point and the center of the mirror is known as the focal length of the mirror.
In this problem, we have two concave mirrors facing each other, with the second mirror partially silvered so that some of the light passes through it. The light rays from the object pass through the partially silvered mirror and converge to a point in front of the first mirror.
This point acts as the object for the first mirror, which reflects the rays back toward the second mirror. The second mirror then reflects the rays towards a final point, which is the location of the image formed by the two mirrors.
Using the mirror formula, we can calculate the distance of the first image from the first mirror:
1/f = 1/do + 1/di
where f is the focal length of the first mirror, do is the distance of the object from the first mirror, and di is the distance of the first image from the first mirror.
Substituting the given values, we get:
1/23.9 = 1/101 + 1/di
Solving for di, we get:
di = 19.1 cm
This first image acts as the object for the second mirror. Again using the mirror formula, we can calculate the distance of the final image from the second mirror:
1/f' = 1/do' + 1/di'
where f' is the focal length of the second mirror, do' is the distance of the first image from the second mirror, and di' is the distance of the final image from the second mirror.
Substituting the given values, we get:
1/5.21 = 1/19.1 + 1/di'
Solving for di', we get:
di' = 18.7 cm
Therefore, the final image formed by the two mirrors is located at a distance of 18.7 cm from the second mirror.
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Can carrying an object be said to be doing work on that object?
Answer:
Only if that object is being moved while carried
Explanation:
Work = Force • distance travelled
While holding an object would need force equal to that objects mass multiplied by 9.8, if it hasn't moved, then no work is done.
if you were to carry the object and have it travel some distance, then work would be done on that object.
what is the condition for the first dark fringe through a single slit of width w?
The condition for the first dark fringe through a single slit of width w is when the path difference between the rays passing through the top and bottom edges of the slit is half a wavelength, which causes destructive interference and results in a dark band on the screen.
This can be expressed mathematically as sin θ = λ/w, where θ is the angle between the direction of the incoming light and the direction of the diffracted light, λ is the wavelength of the light, and w is the width of the slit.
The condition for the first dark fringe in a single-slit diffraction pattern occurs when the path difference between adjacent rays is equal to half the wavelength (λ/2). This can be represented by the equation:
sin(θ) = λ/(2w)
where θ is the angle of the first dark fringe, λ is the wavelength of the light, and w is the width of the slit.
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Use the drop-down menus to complete the
sentences below.
Cocoa mix is the
DONE
Water is the
DONE
The picture shows a great deal of Cocoa mix on
the surface. Suppose that no more cocoa can be
dissolved. The solution has reached
Answer:
Solute
Solvent
Saturation
Explanation:
A great deal of cocoa mix on the surface. Cocoa is the solute. Water is the solvent. The solution has reached the saturation.
What is the saturation?The saturation is the state at which the solute dissolves no more.
The liquid is more in quantity is the solvent which is water here. The cocoa is added next, which is the solute generally less in quantity than solvent.
The addition of cocoa is continued till it stops dissolving. This state is reached at saturation.
Therefore, Cocoa is the solute. Water is the solvent. The solution has reached the saturation.
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When a space shuttle was launched, the astronauts on board experienced an acceleration of 29.0 m/s2. If one of the astronauts had a mass of 60.0 kg, what net force in Newton’s did the astronaut experience?
Mass is 50 kg and height is 10 m. pls someone help i wanna go home
Answer:
me dont know either
Explanation:
but search it up maybe that will work
A medium-sized apple provides about 95.0 Calories of energy.
(a) Convert 95.0 Cal to joules.
(b) Suppose that amount of energy is transformed into kinetic energy of a 2.03 kg object initially at rest. Calculate the final speed of the object (in m/s).
(c) If that same amount of energy is added to 3.79 kg (about 1 gal) of water at 21.7°C, what is the water's final temperature (in °C)? The specific heat of water is
c = 4186
J
(kg · °C)
.
A. 95 Cal is equivalent to 397480 J
B. The final speed of the object is 625.78 m/s
C. The final temperature of the water is 46.8 °C
A. Converting 95 Cal to Joules
1 Cal = 4184 J
Therefore,
95 Cal = 95 × 4184
95 Cal = 397480 JThus, 95 Cal is equivalent to 397480 J
B. Determination of the speed of the object
Kinetic energy (KE) = 397480 J
Mass (m) = 2.03 Kg
Velocity (v) =?KE = ½mv²
397480 = ½ × 2.03 × v²
397480 = 1.015 × v²
Divide both side by 1.015
v² = 397480 / 1.015
Take the square root of both side
v = √(397480 / 1.015)
v = 625.78 m/sTherefore, the speed of the object is 625.78 m/s
C. Determination of the final temperature of the water
Mass of water (M) = 3.79 kg
Initial temperature of water (T₁) = 21.7 °C
Specific heat capacity of water (C) = 4186 J/KgºC
Heat (Q) = 397480 J
Final temperature (T₂) =?Q = MC(T₂ – T₁)
397480 = 3.79 × 4186 (T₂ – 21.7)
397480 = 15864.94 (T₂ – 21.7)
Clear the bracket
397480 = 15864.94T₂ – 344269.198
Collect like terms
397480 + 344269.198 = 15864.94T₂
741749.198 = 15864.94T₂
Divide both side by 15864.94
T₂ = 741749.198 / 15864.94
T₂ = 46.8 °CTherefore, the final temperature of the water is 46.8 °C
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Can a resultant forces' direction be north or south, or is it only East and West?
Bowling ball rolls up a ramp 0.75 m high without slipping to storage. it has an initial velocity of its center of mass of 4.2 m/s. (a) what is its velocity at the top of the ramp? (b) if the ramp is 1 m high does it make it to the top?
(a) Using conservation of energy, the velocity of the ball at the top of the ramp is 3.9 m/s.
(b) When the height of the ramp is 1 m, the ball does not make it to the top of the ramp
Given,
Height of the ramp, h = 0.75 m
Initial velocity of the center of mass, u = 4.2 m/s
(a) What is its velocity at the top of the ramp?
The bowling ball rolls up a ramp of height 0.75 m without slipping to storage, and it has an initial velocity of its center of mass of 4.2 m/s. It is asked to determine the velocity of the ball at the top of the ramp.
Let the velocity of the ball at the top of the ramp be v.
By the law of conservation of energy, the potential energy of the ball at the bottom of the ramp is equal to the kinetic energy of the ball at the top of the ramp.
PE at the bottom of the ramp = KE at the top of the ramp
mgh = (1/2)mu² + (1/2)Iω²
where
m = mass of the ball
g = acceleration due to gravity
I = moment of inertia of the ball
ω = angular velocity of the ball
Assuming the ball is a solid sphere,
I = (2/5)mr²
where r is the radius of the sphere
At the bottom of the ramp,
PE = mgh
At the top of the ramp,
KE = (1/2)mu² + (1/2)(2/5)mu²
Substituting the given values,
PE = mgh = 0.75mg
KE = (1/2)mu² + (1/2)(2/5)mu²
= (1/2)(7/5)mu²
= (7/10)mu²
At the top of the ramp,
PE = KE
0.75mg = (7/10)mu²
v = u * √(7/10)
= 4.2 * √(7/10)
≈ 3.9 m/s
Therefore, the velocity of the ball at the top of the ramp is approximately 3.9 m/s.
(b) If the ramp is 1 m high does it make it to the top?
When the height of the ramp is 1 m,
PE = mgh = 1mg
At the top of the ramp,
KE = (1/2)mu² + (1/2)(2/5)mu²
= (1/2)(7/5)mu²
= (7/10)mu²
At the top of the ramp,
PE = KE
1mg = (7/10)mu²
u² = (10/7)gh
v = u * √(7/10)
= √(10gh/7)
≈ 3.96 √h m/s
Therefore, when the height of the ramp is 1 m, the ball does not make it to the top of the ramp.
Using the law of conservation of energy, the velocity of the ball at the top of the ramp is found to be approximately 3.9 m/s. When the height of the ramp is increased to 1 m, the ball does not make it to the top of the ramp.
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Remy wonders if the height of the mountain has anything to do with the eventual size of the tsunami wave. How should Remy test this? A. Cause avalanches on several different mountains and see how large each resulting tsunami is. B. Build different-sized model mountains at the edge of a pool, pour sand down the side of each mountain, and see how large each resulting wave is. C. Pour different amounts of sand down the side of a model mountain into a pool and see how large each resulting wave is. D. Build a model town at the edge of a pool and see how large waves must be to cause damage to the buildings.
Answer:
The answer is B
Explanation:
I got this from study island
Lowest energy?________(^_^)
Answer:
Ground state
Ground state should be the lowest energy
As your textbook notes, the paradox of stratification is that inequality is the result of.
Answer: abundance
Explanation: Paradox Inequality is the result of abundance. intended or unintended consequences of social processes and relationships. prevents social equality, and that this inequality ultimately leads to social conflict.
As your textbook notes, the paradox of stratification is that inequality is the result of the Universal Basic Income.
What is universal basic income ?A sociopolitical idea known as universal basic income proposes that every member of a particular population receive a transfer payment on a regular basis without having to prove their ability to pay.
A legally mandated and equally distributed cash award is provided by the government to all people of a given nation under the sociopolitical financial transfer policy concept known as universal basic income (UBI). Local, regional, or national implementation of a basic income are all possible.
The phenomena of birthweight-specific mortality curves crossing when stratified on other exposures, most notably cigarette smoking, is known as the "birth weight conundrum." The dilemma has received a lot of attention in the literature, and a lot of explanations and fixes have been proposed.
Thus, As your textbook notes, the paradox of stratification is that inequality is the result of the Universal Basic Income.
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Mass (kg)
2
4
6
8
12
15
Weight
(N)
20
35
55
70
105
135
What is the independent variable in this experiment
Mass.
Because mass doesn't depend on weight but weight depends on mass.
Which element most likely interacts with water the same way lithium interacts with water?
Answer:
Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)
Explanation:
An archer shoots an arrow in the air, horizontally. However, after moving some
distance, the arrow falls to the ground. Name and define the initial force that sets
the arrow in motion. Explain why the arrow ultimately falls down.
Answer:
The name of the force is elastic (spring) force
Explanation:
The elastic force which is the restoration force of an elastic (spring like) object that tries to return to its initial non-stretched state built up by the pulling of the bow by the archer (using the muscles) pushes on the arrow which the archer releases the same time he leaves the bow string, and the arrow flies in the direction already pointed by the archer
The arrow ultimately falls down due to gravity forces that acts on all objects within the Earths gravitational field. However due to the speed of constant horizontal speed of the arrow and increasing downward speed of the due to the gravity force, the falling of the arrow looks disappointing.