Answer:
People think they ruin landscapes.
Explanation:
This is a common opinion and will be accepted as a point in any essay.
1. True or False. Heat transfer is the movement of energy from an object of higher temperature to an object of lower temperature.
Соо
O False
O True
10
O
Answer:
false
Explanation:
hopes its right
Answer:
True
Explanation:
6CO2 + 6H20 + (energy)
Answer:6CO2 + 6H20 + (energy) → C6H12O6 + 6O2 Carbon dioxide + water + energy from light produces glucose and oxygen
Explanation:
the impulse experienced by a car is 4000 kg•m/s. What is the change in it's momentum?
The car's momentum change is 4000 kg/m/s because momentum change equals impulse.
Elaborating:Impulse can be summed up as follows: In this case, the car experienced an impulse of 4000 kg/s. Impulse = force x time.
The following formula can be used to determine the car's change in momentum using this information: The car's momentum change is 4000 kg/m/s because momentum change equals impulse.
How does momentum relate to impulse?The change in an object's momentum caused by a force acting on it for a certain amount of time is equal to impulse. An object's momentum change is measured by its impulse, which is defined as the sum of the object's acting force and time. Calculating impulse can be done by: Force x time is the impulse.
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1. A 15.0 kg box is hung from the ceiling by one rope. What is the tension on the rope? 2. A 1510 kg car is experiencing a 2650 N friction force from the road. What force must be applied to the car in
1. The tension on a rope suspending a 15.0 kg box from the ceiling is 147 N, acting in the opposite direction to counterbalance the weight of the box.
2. To overcome the friction force from the road and maintain a constant velocity, an applied force of 2650 N must be exerted on the car.
1. To determine the tension on the rope when a 15.0 kg box is suspended from the ceiling, we analyze the forces at play. When the box is stationary, the net force acting on it is zero.
Let's consider the tension in the rope as T. The weight of the box can be calculated using the equation W = mg, where m represents the mass of the box, and g is the acceleration due to gravity.
Weight of the box = 15.0 kg * 9.8 m/s² = 147 N
Since the box is in equilibrium, the tension in the rope must balance the weight of the box. Therefore:
T - 147 N = 0
Solving for T:
T = 147 N
2. When a 1510 kg car experiences a 2650 N friction force from the road, we need to find the force that must be applied to the car to overcome this friction and maintain constant velocity.
The force of friction is given by the equation \(F_f_r_i_c_t_i_o_n\) = μ * N, where μ is the coefficient of friction and N is the normal force. In this case, we assume the friction force is the maximum static friction force, which is μ * N.
Since the car is experiencing a friction force of 2650 N, we have:
\(F_f_r_i_c_t_i_o_n\) = 2650 N
The normal force (N) is equal to the weight of the car (mg), where g is the acceleration due to gravity.
Weight of the car = 1510 kg * 9.8 m/s² = 14818 N
Since the car is at constant velocity, the applied force must balance the friction force:
Applied force - 2650 N = 0
Solving for the applied force:
Applied force = 2650 N
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What is the least dense planet in our solar system?.
Answer:
Jupiter is the largest planet in the solar system, but it's Saturn—the solar system's second largest planet—that takes the prize for least dense. It's less dense than water, which has led many people to postulate that it would float.
If you can make it from one end of a football field to the other (100 meters) with an acceleration of 2.2m/s, what would be your top speed if you started from rest?
Answer:
v = 20.57 m/s
Explanation:
Given that,
Acceleration, a = 2.2 m/s²
Initial speed of the person, u = 0 (at rest)
Distance, s = 100 m
We need to find the top speed. It can be calculated using third equation of motion.
\(v^2-u^2=2as\)
v is final speed
\(v=\sqrt{2as} \\\\v=\sqrt{2\times 2.2\times 100} \\\\v=20.57\ m/s\)
So, the top speed of the person is 20.57 m/s.
what is the region of concentrated magnetism at the end of a magnet?
The region of concentrated magnetism at the end of a magnet is called a magnetic pole.
Magnets have two ends, called poles, which are labeled north (N) and south (S). The magnetic field lines of a magnet flow from the north pole to the south pole, creating a magnetic field that can attract or repel other magnets or magnetic materials.
At the ends of the magnet, the magnetic field lines are concentrated and the magnetic force is strongest, creating the magnetic poles. Unlike electric charges, magnetic poles always come in pairs, meaning that every north pole of a magnet is always paired with a south pole. The strength of a magnet's magnetic field depends on the size and strength of its poles.
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Which option is an example of a chemical reaction that occurs at a very slow rate?
Answer:D
Explanation:
:)
1. You released a pendulum of mass 1kg from a height of 0.05m
b. If the pendulum loses 18% of the initial energy by the time it reaches the bottom, how fast is it going when it reaches the bottom?
c. If the pendulum loses another 7% of its remaining energy by the time it reaches the other side, how high up does it go?
d. After a few minutes the pendulum is no longer swinging at all, explain why this happens in terms of energy?
a. The speed of the pendulum when it reaches the bottom is 0.9 m/s.
b. The height reached by the pendulum is 0.038 m.
c. When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
Kinetic energy of the pendulum when it reaches bottomK.E = 100%P.E - 18%P.E
where;
P.E is potential; energyK.E(bottom) = 0.82P.E
K.E(bottom) = 0.82(mgh)
K.E(bottom) = 0.82(1 x 9.8 x 0.05) = 0.402 J
Speed of the pendulumK.E = ¹/₂mv²
2K.E = mv²
v² = (2K.E)/m
v² = (2 x 0.402)/1
v² = 0.804
v = √0.804
v = 0.9 m/s
Final potential energyP.E = 100%K.E - 7%K.E
P.E = 93%K.E
P.E = 0.93(0.402 J)
P.E = 0.374 J
Height reached by the pendulumP.E = mgh
h = P.E/mg
h = (0.374)/(1 x 9.8)
h = 0.038 m
when the pendulum stopsWhen the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
Thus, the speed of the pendulum when it reaches the bottom is 0.9 m/s.
The height reached by the pendulum is 0.038 m.
When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
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What is the length of the y-component of the vector plotted below?
Answer:
A.1
Explanation:
on the vector plot you should count up and if you count up you´ll get one
The length of the y-component of the vector plotted in the given question would be 1. Thus, the correct option is A.
What is a vector plot?A vector field can be defined as an assignment of a vector to each point in the subset of space. For instance, a vector field in the plane can be easily visualized as a collection of arrows with a given magnitude and direction of a particle, each line or arrow attached to a point in the plane of space.
Vector plots are used to create vector lines between any two points or from one point in space to the specified angle direction and with the selected magnitude and direction of the quantity or quality.
In the given graph, the Y-component is the vertical line or vertical component. The value of the y-component of the vector plotted is 1.
Therefore, the correct option is A.
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The Moon orbits Earth at an average distance of 384,000 km and completes one sidereal orbit (with respect to the stars) in about 27.3 days. Based on these two numbers, what is its average orbital speed? Express your answer in km/s.
The given average distance of the Moon from the Earth is 384,000 km and the sidereal period of the moon is 27.3 days. We need to find the average orbital speed of the moon.So, we can use the formula to calculate the average orbital speed of the Moon as follows:
Average orbital speed (V) = distance/time.
To get the distance covered by the moon in one orbit, we will multiply the distance of the Moon from the Earth by the circumference of the orbit:
Distance = 2 × π × r = 2 × π × 384000 = 2.41 × 10^6 km.
Therefore, the average orbital speed of the Moon is given by the formula:V = Distance / Time periodV = 2.41 × 10^6 km / 27.3 days.
We need to convert the time period from days to seconds:1 day = 24 hours1 hour = 60 minutes1 minute = 60 seconds1 day = 24 × 60 × 60 seconds1 day = 86400 seconds.
Therefore, the time period is:27.3 days = 27.3 × 86400 seconds27.3 days = 2.36 × 10^6 seconds.
Substituting this value in the formula we get:V = 2.41 × 10^6 km / 2.36 × 10^6 secondsV = 1.02 km/s.
Therefore, the average orbital speed of the moon is 1.02 km/s.
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A square with an area of 196 ft is reduced by a factor
of 1/4 . how long are the new sides of the square?
the new sides of the reduced square are 3.5 feet long each. In order to find the new sides of a square with an area of 196 square feet that is reduced by a factor of 1/4, we have to follow some steps
The details of these steps are as follow:
1. Determine the original side length of the square: Since the area of a square is found by multiplying the length of one side by itself (side × side), you need to find the square root of the original area, which is 196. The square root of 196 is 14, so the original side length is 14 feet.
2. Reduce the original side length by a factor of 1/4: Multiply the original side length (14 feet) by the reduction factor (1/4).
14 × (1/4) = 14/4 = 3.5
So, the new sides of the reduced square are 3.5 feet long each.
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A force of 5 N accelerates an object. The object's mass is 50 g. What is the acceleration of the object? (Formula: F=ma) 0. 01 m/s2 0. 1 m/s2 10 m/s2 100 m/s2.
Answer:
it's 100m/s2
Explanation:
a=f/m
or,a=5/50/1000. (mass si unit is kg and 1kg=1000g
or,a=5/0.005
or,a=100m/s2
If force = mass x acceleration, then if an object has a mass of 10 grams
and the acceleration of 20 m/s, what is the force on the object?
Answer:
10g to kg=0.01
20×0.01=0.2
Force of 0.2N
The human eye is capable of seeing objects in our environment mainly because
they bend light.
they absorb light
they emit light
they reflect light
Answer: absorb
Explanation: ligh goes in ur eyes
Two layers of fluid are contained between parallel plates, each of 0. 8 m2 area. The fluid viscosities are η1 = 0. 12 N. S. M-2 and η2 = 0. 18 N. S. M-2. The thickness of each layer of fluid is L1 = 0. 62 mm and L2 = 0. 56 mm. What is the fluid relative velocity at the interface between the two plates, if the upper plate has a speed of 1. 3 m. S-1 at the interface?
According to the given statement , the fluid relative velocity at the interface between the two plates is approximately 0.684 m/s.
To find the fluid relative velocity at the interface between the two plates, we can use the concept of shear rate and the formula for the velocity gradient.
First, let's calculate the shear rate (γ) using the formula:
γ = Δv / Δx
Where:
- Δv is the velocity difference between the two plates, which is given as 1.3 m/s (since the upper plate has a speed of 1.3 m/s at the interface).
- Δx is the distance between the two plates, which is the sum of the thicknesses of the two fluid layers:
Δx = L1 + L2.
Given that L1 = 0.62 mm and L2 = 0.56 mm, we need to convert these values to meters:
L1 = 0.62 mm = 0.62 × 10⁻³ m
L2 = 0.56 mm = 0.56 × 10⁻³ m
Now we can calculate Δx:
Δx = L1 + L2
Substituting the values, we get:
Δx = 0.62 × 10⁻³ m + 0.56 × 10⁻³ m
= 1.18 × 10⁻³ m
Now we can calculate the shear rate:
γ = Δv / Δx
= 1.3 m/s / 1.18 × 10⁻³ m
Performing the division, we find:
γ ≈ 1101.7 s^-1
The shear rate (γ) represents the velocity gradient between the two fluid layers. To find the fluid relative velocity at the interface, we need to multiply the shear rate by the thickness of the first layer (L1).
Relative Velocity = γ * L1
Substituting the values, we get:
Relative Velocity = 1101.7 s⁻¹ * 0.62 × 10⁻³ m
Performing the multiplication, we find:
Relative Velocity ≈ 0.684 m/s
Therefore, the fluid relative velocity at the interface between the two plates is approximately 0.684 m/s.
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Two objects are moving downward at a speed of 3 cm/s. Object A has a mass of 2kg and Object B has a mass of 1kg. You want both objects to move to the left at a speed of 3cm/s.
In what direction or (directions) should you exert the forces that will make the desired change?
An automobile travels on a straight road for 40 km at 20 km/h. It then continues in the same direction for another 55 km at 75 km/h. (a) What is the average velocity (km/h) of the car during this 95 km trip? (Assume that it moves in the positive-x direction.) (b) What is its average speed in m/s?
(a) The average velocity of the car during the 95 km trip is 33.16 km/h.
(b) The average speed of the car during the 95 km trip is 9.21 m/s.
(a) The average velocity of the car during the 95 km trip is 33.16 km/h.
To calculate the average velocity, we need to consider both the distance traveled and the time taken. The car travels a total distance of 95 km and takes a total time of 2 hours and 10 minutes (40 km at 20 km/h = 2 hours and 55 km at 75 km/h = 50 minutes). Dividing the total distance by the total time gives us an average velocity of 33.16 km/h.
(b) The average speed of the car during the 95 km trip is 9.21 m/s.
To convert km/h to m/s, we divide the speed in km/h by 3.6. Thus, the average speed of the car, calculated by dividing 33.16 km/h by 3.6, is 9.21 m/s.
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1. The speed limit on a particular freeway is 28.0 m/s (about 101 km/hour). A car
that is merging onto the freeway is capable of accelerating at 2.25 m/s2. If the car
is currently traveling forward at 13.0 m/s, what is the shortest amount of time it
could take the vehicle to reach the speed limit? How far would the car travel in
this time?
Answer:
the speed limit 6 seconds and the car will travel in 90m
Question 20
When energy is added to a wave, how can the wave change? Select all that apply
А
The frequency can increase.
The wavelengin can inc
С
The frequency can decrease.
D
The amplitude can decrease.
E
The wavelength can decrease.
F
The amplitude can increase.
Answer:
I would say A, I hope this helped ; >
I am the only non-metal in Group 14. Who am I?
Answer:
it's either carbon or silicone
What happens to the pattern on the screen when the slits are brought closer to each other? Write your observations in the box below.
When the distance between the two slits on the screen is reduced, the interference fringes become wider apart. The pattern is less intense, with the bright fringes becoming less bright and the dark fringes becoming less dark.
When the distance between the two slits on the screen is reduced, the interference fringes become wider apart. The pattern is less intense, with the bright fringes becoming less bright and the dark fringes becoming less dark. As the distance between the two slits increases, the opposite occurs.
The fringes become closer together, with bright fringes becoming brighter and dark fringes becoming darker. This phenomenon is due to the constructive and destructive interference of light waves.
When the light waves from the two slits arrive at the screen, they interfere with one another, either constructively or destructively depending on the phase of the wave.
If the peaks and troughs of the two waves align perfectly, they will constructively interfere and create a bright fringe. If the peaks of one wave align with the troughs of another wave, they will destructively interfere and create a dark fringe.
The spacing between the fringes, known as the fringe spacing, is determined by the wavelength of the light and the distance between the slits. When the distance between the slits is reduced, the fringe spacing increases, resulting in fringes that are further apart from each other.
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compare the above electric field to the electric field of a large parallel plate capacitor with the same voltage and distance between the plates. which one is larger? is this expected? explain.
The electric field due to a point charge will always be greater than that of a parallel plate capacitor.
The electric field due to a point charge is given by the formula E=kq/r². Compare the above electric field to the electric field of a large parallel plate capacitor with the same voltage and distance between the plates.
According to Coulomb's law, the electric field due to a point charge varies inversely with the square of the distance from the charge. The magnitude of the electric field between the plates of a capacitor is uniform and is given by E=V/d (where V is the voltage across the plates and d is the distance between them).
Thus, the electric field between the plates of a capacitor is given by E=V/d. Comparing both electric fields, we get that `E\(_{point}\) = E\(_{plates}\).
It's expected because the electric field between the plates of a capacitor is uniform, and its magnitude depends on the distance between the plates and the voltage applied.
The electric field due to a point charge, on the other hand, varies inversely with the square of the distance between the charge and the point where we want to measure the field. Therefore, the electric field due to a point charge will always be greater than that of a parallel plate capacitor.
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Supposet that f(x,y)= The temperature of a sheet of metal (in°C)at the position (z,y) (in cm) Suppose that VJ (2,3)=(5,12) Suppose that an ant is crawling on the pan. At t=5s, the position of the ant is (2,3) cm, and the velocity of the ant is (3, 4) cm/s. For each of the following questions, show how you get your answer.
(a) At t= 5s, at what (instantaneous) rate is the ant warming up (assume the ant always has the same temperature as the metal it is standing on). Your a answer chould be in
(b) At t = 58, at what (instantaneous) rate is the ant warming up per cm it travels? Your answer should be in C
(c) If the position of the ant is (2,3) cm, in which direction should the ant move to maximize the instantaneous rate it warms up? Give your answer as a unit vector.
(d) If the posiiton of the ant is (2,3) cm and it is travelling in the direction given by (c), at what instantaneous rate is it warming up per cm it travles? Give your answer in cm C
(e) If the posiiton of the ant is (2,3) cm and it is travelling in the direction given by (c) with a speed of 4 at what instantaneous rate is it warming up with respect to time? Give your answer in
Explanation:
the answers are calculated in above pictures
A tap supplies water at 26°c while another supplies at 82°c. If a man wishes to bath with water at 40°c, what is the ratio of the mass of hot water to that of cold water
Where a tap supplies water at 26°c while another supply at 82°c. If a man wishes to bath with water at 40°c, then the ratio of the mass of hot water to that of cold water is: 1/3.
What is the rationale for the above response?The ratio of the mass of hot water to that of Cold water is determined as follows:
M₁C (82 40) = M₂C (40-26)
Where M₁C is the Mass of Tap 1; and
M₂C is the Mass of Tap 2.
Thus,
M₁C (82 40) = M₂C (40-26)
M₁/M₂ = 14/42
= 1/3
Thus, it is right to state that the ratio of the mass of hot water to that of cold water is: 1/3.
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the motion of the book as you lift it from the table and place it on the shelf
Answer:
what are you trying to do for this question
Explanation:
If you were going to redo the aluminum lifeboat experiment, what two to three factors do you think you could change to be able to hold more people (pennies)? Explain in complete sentences, using good grammar.
Remember you still have to use pennies and aluminum foil, but you can bring in other material or change the foil in some way. HELP ME
Yes, the aluminum foil is impure and includes a variety of materials that have an impact on the percentage yield when added to the final product's overall weight.
Aluminum foil is used in a variety of settings, both domestic and commercial. It can be used to wrap food, bake cookies and cakes, and store food.
Additionally, many preserve delicate foods like meat and vegetables in aluminum foil.
Research has shown that aluminum foil is not a pure material since some of its particles can leach into food and cause major health issues.
Iron, zinc, gallium, and silicon microparticles are present in this foil. In addition, when heated, the coloring and paint on it have negative effects.
Additionally, it increases the overall weight of the finished product, which also has an impact on the yield percentage.
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A delivery truck with 2.0m -high aluminum sides is driving west at 50km/hr in a region where the earth's magnetic field is B= (5.0 x 10^-5 T, north)
a. What is the potential difference between the top and the bottom of the truck's side panels? E= ____ V
The possible potential difference between the truck's top and bottom side panels is 1.39 x 10^-4 V.
The potential difference between two points in an electric circuit is given by the product of the magnetic field, the cross-sectional area of the conductor, and the component of velocity perpendicular to the magnetic field.
The potential difference between the top and bottom of the truck's side panels can be calculated using the following formula:
V = Blv
Where:
V = potential difference (V)
B = magnetic field (T)
l = length of conductor (m)
v = velocity of conductor perpendicular to the magnetic field (m/s)
Given that the magnetic field is B = (5.0 x 10^-5 T, north) and the truck is moving west at 50 km/hr = 13.89 m/s, the potential difference between the top and bottom of the truck's side panels can be calculated as:
V = Blv = (5.0 x 10^-5 T) * (2.0 m) * (13.89 m/s) = 1.39 x 10^-4 V
It is important to note that the magnetic field is pointing north and the truck is moving west, so the velocity of the truck is perpendicular to the magnetic field, which means that the potential difference is not zero. Also, it is important to note that the velocity of the truck is given in km/hr and needs to be converted to m/s before using it in the equation.
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A crane moves a 250 kg scoreboard from the ground to the height of 100 m. What is the work done on the scoreboard?
Answer:
You will have to do the last PE - the initial PE
Explanation:
How did Kepler's first law change the original heliocentric model proposed by Copernicus? placed the Earth near the center of the Sun's orbit suggested epicycles to explain retrograde motion improved the accuracy by making orbits elliptical concluded that the planets were in circular orbits around the Sun
Kepler's first law revolutionized the original heliocentric model proposed by Copernicus by introducing the concept of elliptical orbits instead of circular ones.
Kepler's first law, also known as the law of ellipses, significantly transformed the heliocentric model proposed by Copernicus. Copernicus initially placed the Sun near the center of the Earth's orbit, with the planets moving in circular orbits around it. However, Kepler's observations and mathematical analysis of planetary motion led him to conclude that the planets do not move in perfect circles but instead follow elliptical paths around the Sun. This discovery was a fundamental departure from Copernicus' circular orbits.
By determining that planetary orbits are elliptical, Kepler eliminated the need for the complex system of epicycles that were previously proposed by astronomers, including Copernicus himself, to explain the phenomenon of retrograde motion. Retrograde motion is the apparent backward motion of a planet in the sky as observed from Earth. Kepler's discovery provided a simpler and more accurate explanation for this phenomenon without the need for additional layers of complexity.
In summary, Kepler's first law transformed the original heliocentric model by replacing the assumption of circular orbits with the concept of elliptical orbits. This change improved the accuracy of the model and eliminated the necessity for epicycles, leading to a more elegant and comprehensive understanding of planetary motion within the solar system.
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