Answer:
B
Explanation:
Test
A 150 kg car hits a wall with 45 N of force, what was its acceleration?
Answer:
a = 0.3 m/s²
Explanation:
Given: 45 N, 150 kg
To find: a
Formula: \(a = \frac{F}{m}\)
Solution: To find a, divide the force by the weight
A = F ÷ m
= 45 ÷ 150
= 0.3 m/s²
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
Which of the following objects is composed mostly of wood?
A. Sweater
B. Tile
C. Pencil
D. Brick
❄ Hi there.
a pencil is composed mostly of wood.
Let's check if the other choices are right.
A. Sweaters are not made of wood
B. Tiles are not made of wood
C. Pencils are made of wood
D. Bricks are not made of wood
∴ the right choice is C.
❄
Help fast
Who is often referred to as the "father of modern physics?"
Rutherford
Edison
Newton
Dalton
Answer:
C. Newton
Explanation:
hope this helped:)
What is the final step in the fourth stage of technological design, after a product has been improved abs approved
Answer:
Evaluate the solution.
Explanation:
A technological design is designed as the design and study of a solution that can be provided from the solution by identifying the root cause or problem and trying to solve by various means.
A good technological design requires the minimum effort and resources while meeting the requirement of the problem.
The steps involved in the technological design are :
1. search and identify the problem or need.
2. design a solution
3. Implement a solution.
4. Evaluate the solution.
Therefore, the final step or the fourth step in the process of a technological design is " evaluating or communicating the final design solution".
Let V be an F-vector space.
a) Show that if SV then (S) = S.
b) Let W. W₂ V. Show that (W₁U W ₂ ) = W₁ + W₂.
a) If S is a subspace of vector space V, then the span of S, (S), is equal to S itself.
To show that if S⊆V, then (S) = S, we need to prove two inclusions:(i) (S) ⊆ S:
By definition, (S) is the smallest subspace of V that contains S. Since S⊆(S), it follows that every element in S is also in (S). Therefore, S is a subset of (S).(ii) S ⊆ (S):
Let's consider S as a subspace of V. Since S is already a subspace, it satisfies all the properties of a vector space, including closure under scalar multiplication and addition. Therefore, S is a subset of itself.
Combining both inclusions, we conclude that (S) = S.
b)The span of the union of subspaces W₁ and W₂, (W₁ ∪ W₂), is equal to the sum of W₁ and W₂, denoted by W₁ + W₂.
To show that (W₁ ∪ W₂) = W₁ + W₂, we need to prove two inclusions:
(i) (W₁ ∪ W₂) ⊆ W₁ + W₂:
Let's take an element x from (W₁ ∪ W₂). This means that x is an element of either W₁ or W₂ (or both). If x∈W₁, then x is in the subspace W₁, and therefore, it is also in the sum W₁ + W₂. Similarly, if x∈W₂, then x is in the subspace W₂, and hence it is also in the sum W₁ + W₂. Therefore, any element x from (W₁ ∪ W₂) is also in W₁ + W₂, which implies (W₁ ∪ W₂) ⊆ W₁ + W₂.
(ii) W₁ + W₂ ⊆ (W₁ ∪ W₂):
Let's take an element y from W₁ + W₂. By definition, this means that y can be expressed as the sum of an element in W₁ and an element in W₂. Therefore, y is either an element of W₁ or an element of W₂ (or both), and hence y is in the union (W₁ ∪ W₂). Therefore, any element y from W₁ + W₂ is also in (W₁ ∪ W₂), which implies W₁ + W₂ ⊆ (W₁ ∪ W₂).Combining both inclusions, we conclude that (W₁ ∪ W₂) = W₁ + W₂.
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Which nucleus completes the following equation?
Answer:
its b
Explanation:
A 10 kg ball is rolled to the top of a hill 37 m high using 4000 J of work. How much energy was lost due to heat?
Answer:
370.3J
Explanation:
A 10 kg ball is rolled to the top of a hill 37 m high using 4000 J of work. How much energy was lost due to heat?
Step one:
given data
mass m= 10kg
height of the hill= 37m
work done= 4000J
Step two:
The quantity of energy loss due to heat is the same as the difference in the potential energy possed by the mass and the work done
PE= mgh
PE=10*9.81*37
PE= 3629.7J
Hence the energy loss is
= 4000-3629.7
=370.3J
Cindy runs 2 kilometers every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minute for the next 350 meters, and 3 minutes for the rest.
Cindy’s average speed for the entire run is
meters per minute. One kilometer is the same as 1,000 meters.
Answer:
200 m / min
Explanation:
Total distance = 2000 m
Total time = 2+4+1+3 = 10 minutes
Average speed = 2000 m / 10 min = 200 m/min
What is the density of a wooden cube that has a mass of 59.3g and an edge length of 4.30cm ?
The density of the wooden cube is approximately 0.746 g/cm³.
What is density ?Density is a physical property that describes how much mass a substance has per unit volume. It is typically measured in grammes per cubic centimetre (g/cm3) or kilogrammes per cubic metre (kg/m3).
The formula for density is:
Density = Mass / Volume
The density (ρ) of an object is defined as its mass per unit volume, and can be calculated using the formula:
ρ = m / V
where ρ is the density in units of mass/volume (e.g. g/cm^3), m is the mass of the object, and V is its volume.
In this case, we are given the mass of a wooden cube (m = 59.3 g) and the edge length of the cube (l = 4.30 cm). To calculate the volume of the cube (V), we can use the formula for the volume of a cube:
V = l³
Substituting the given values, we get:
V = (4.30 cm)³ = 79.51 cm³
Now we can calculate the density:
ρ = m / V = 59.3 g / 79.51 cm^3 ≈ 0.746 g/cm^3
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If a student was spinning a key on a string around her head, the key would fly off in a straight line in one direction if she released the
string. What Law does this is example demonstrate?
A Newton's fourth law of motion
B. Newton's first law of motion
C. Newton's third law of motion
D. Newton's second law of motion
Answer:
B
Explanation:
the external force was applied
Can someone help me solve this?
Answer:
so the answer is number one which is A
Describe what it means to view something from a frame of reference. Give an example to illustrate your explanation. (4 points)
Jeff is building a toy car out of wood for a race. The car will be able to go faster if he makes it smaller, but Jeff also wants the car to be big enough to hold his toy figurines. This problem shows that A. toy cars cannot be made to go fast. B. a design can be perfect if it looks good. C. toy cars are never fun to play with. D. a design cannot have everything at once.
B Answer:
Explanation:
bc I just did it and got it wrong
what is the speed of a wave with a frequency of 2 Hertz and a wavelength of 87 m?
0.023 m/s
43.5 m/s
89 m/s
174 m/s
Answer:
The answer to your problem is, D. 174 m/s
Explanation:
Formula:
wave speed = frequency * wavelength
Speed of wave = 2Hz × 87m ( Look at question for the numbers )
Speed of wave = 174m/s
Simple math..
Thus the answer to your problem is, 174m/s
the wire in the drawing carries a current of 14 A. Suppose that a second long, straight wire is placed right next to this wire. The current in the second wire is 30 A. Use Ampere's law to find the magnitude of the magnetic field at a distance of r
The magnitude of the magnetic field at a distance r is given by 8 × 10^-6 T·m divided by r.
Ampere's law states that the line integral of the magnetic field around a closed loop is equal to the product of the current enclosed by the loop and the permeability of free space.
In this case, we have two parallel wires carrying currents of 14 A and 30 A. Let's consider a closed loop around the first wire. The current enclosed by this loop is 14 A. Applying Ampere's law, we have:
∮B⋅dl = μ₀ × 14 A
The left-hand side of the equation represents the line integral of the magnetic field around the loop. The right-hand side represents the product of the current and the permeability of free space, μ₀.
Since the wires are parallel and right next to each other, the magnetic field due to the first wire will be in the opposite direction to the magnetic field due to the second wire. Therefore, the net magnetic field at a distance r from the wire will be the difference between the magnetic fields due to the two wires.
Using the Biot-Savart law, we can find the magnetic field due to each wire at a distance r. The magnetic field due to a long, straight wire is given by:
B = (μ₀ × I) / (2π × r)
Plugging in the values, we get:
B1 = (μ₀ × 14 A) / (2π × r)
B2 = (μ₀ × 30 A) / (2π × r)
The net magnetic field Bnet at a distance r from the wire is the difference between B2 and B1:
Bnet = B2 - B1
Simplifying the equation, we have:
Bnet = [(μ₀ × 30 A) - (μ₀ × 14 A)] / (2π × r)
Bnet = (μ₀ × 16 A) / (2π × r)
Finally, we can substitute the value of the permeability of free space, μ₀, which is approximately 4π × 10^-7 T·m/A, to find the magnitude of the magnetic field Bnet at a distance r:
Bnet = (4π × 10^-7 T·m/A × 16 A) / (2π × r)
Bnet = (8 × 10^-6 T·m) / r
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A particle in uniform circular motion requires a net force acting in what direction? A. Towards the center of the circle. B. In the direction of velocity. C. Opposite the direction of the velocity. D. Away from the center of the circle. E. Upward. F. Downward
A particle in uniform circular motion requires a net force acting towards the center of the circle. So option A is correct.
The net force acting on a particle moving in a circular path is always directed towards the center of the circle. The motion of a particle in a circular path is characterized by the direction of its velocity and acceleration at each instant in time. These two vectors are always perpendicular to each other.The magnitude of the net force required to keep a particle in uniform circular motion depends on the mass of the particle and its velocity, as well as the radius of the circular path it is following. This force is referred to as the centripetal force and is always directed towards the center of the circle.The centripetal force is provided by some other object, such as a string or a gravitational field, which acts to pull the particle towards the center of the circle. Without this force, the particle would continue to move in a straight line tangent to the circle, rather than in a circular path.Therefore option A is correct.
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E-mail is usually a poor choice for the distribution of sensitive electronic files because
A paper copies seem more official than e-mail
B. not all computers can read e-mails correctly
C. it is easy to send e-mail to the wrong person
D. e-mail is saved on the server that transfers it
Answer:
it's D
Explanation:
its on edge
Question 56 Marks: 1 The concentration resulting from a continuous emission of a pollutant is directly proportional to wind speed.Choose one answer. a. True b. False
True. The concentration of a pollutant resulting from a continuous emission is directly proportional to wind speed.
This means that as wind speed increases, the concentration of the pollutant in the air also increases.The concentration of a pollutant in the atmosphere is determined by the balance between the emission of the pollutant and its dispersion (by wind and convection). As wind speed increases, the dispersion of the pollutant is increased, resulting in a decrease of the concentration of the pollutant in the atmosphere. Therefore, the concentration of a pollutant is inversely proportional to the wind speed.Conversely, lower wind speed will cause the pollutant to be dispersed more slowly and over a smaller area, resulting in a higher concentration.
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In the school cafeteria, a trouble-making child blows a 12.0 g spitball through a 25.0 cm straw. The force (F) in Newtons, of his breath as a function of the distance along the straw (x) in meters, can be modeled as a linearly decreasing function for the first half of the straw, followed by a constant force through the rest of the straw. The force decreases by half along the first half of the straw. Assume there is negligible friction and the straw is held horizontally.
(a) Sketch a plot of the force of his breath as a function of position along the straw, labeling the force at x = 0 as F0.
(b) If the spitball begins from rest and leaves the straw with a speed of 16 m/s, how much work is done on the spitball?
(c) What is the maximum force F0, that acts on the spitball?
Answer:
A.) Find the attached file
B.) 1.536 J
C.) 123N
Explanation:
Given that the force (F) in Newtons, of his breath as a function of the distance along the straw (x) in meters, can be modeled as a linearly decreasing function for the first half of the straw,
Half of the straw = 12.5 cm
Let Force F = dependent variable
And distance x = independent variable
A.) Find the attached file for the graph.
Sinnce the force decreases by half along the first half of the straw. Assume there is negligible friction and the straw is held horizontally
B.) Given that the mass M = 12g = 12/1000 = 0.012kg
And Velocity V = 16m/s
The workdone = the kinetic energy of the split ball
WD = 1/2mv^2
Substitutes m and V into the formula
WD = 1/2 × 0.012 × 16^2
WD = 1.536 Joule
C.) The maximum force acts on the spit ball will be at maximum kinetic energy.
Since work done = force × distance
Where distance = 12.5 cm
F × S = 1/2mv^2
Substitutes all the parameters
F × 0.0125 = 1.536
Make F the subject of formula
F = 1.536/0.0125
F = 122.88 N
The maximum force F0, that acts on the spitball is therefore equal to 123 N approximately.
We have that for the Question "(a) Sketch a plot of the force of his breath as a function of position along the straw, labeling the force at x = 0 as F0.
(b) If the spitball begins from rest and leaves the straw with a speed of 16 m/s, how much work is done on the spitball?
(c) What is the maximum force F0, that acts on the spitball?"
It can be said that
a) The sketch is attachedb) The workdone = \(1.536J\)c) Maximum force = \(6.4N\)From the question we are told
mass of spitball = 12g through a 25.0 cm straw
Generally the equation for workdone is mathematically given as
\(= \frac{1}{2}mv^2 - 0\\\\= \frac{1}{2} * 12*10^{-3} * 16^2\\\\= 1.536J\)
Maximum force
\(w = \frac{1}{2}*\frac{x_0}{2}*\frac{F_0}{2} + x_0*\frac{F_0}{2}\\\\w = \frac{5}{8}x_0F_0\)
Therefore,
\(F_0 = \frac{8w}{5x_0}\\\\F_0 = \frac{8*1.536}{5*25*10^[-2]}\\\\F_0 = 6.4N\)
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Suppose that the mirror is moved so that the tree is between the focus point F and the mirror. What happens to the image of the tree?
1. the image moves behind the curved mirror.
2.The image stays the same.
3.The image appears taller and on the same side of the mirror.
4. The image appears shorter and on the same side of the mirror.
When the mirror is moved so that the tree is between the focus point F and the mirror, the image appears shorter and on the same side of the mirror.This happens because of the phenomenon known as Reflection of Light. The mirror reflects light in such a way that it appears as if the light is coming from behind the mirror.
As a result, a virtual image is formed behind the mirror. This virtual image is similar in size and shape to the object being reflected.The characteristics of the image produced by a mirror depends on the location of the object relative to the mirror. There are two types of mirrors that we use to reflect light: Concave and Convex. In the case of a concave mirror, the image produced can either be real or virtual. When an object is placed between the focus point and the mirror, a virtual and erect image is produced. This image is smaller than the actual object and appears behind the mirror. The image is virtual because the light rays do not converge at the location of the image. In the case of a convex mirror, the image produced is always virtual, erect, and smaller than the actual object. As the object moves closer to the mirror, the image gets smaller. If the object is moved to a position where it is between the focus point and the mirror, the image produced will appear shorter and on the same side of the mirror.For such more question on Concave
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You walk in a straight line for 95 m at an angle of 162° above the positive x axis. What are the x and y components of your displacement?
Answer:
Explanation:
{ r, θ ) = [ r cosθ i , r sinθ j ]
( 95m , 162°) = [ 95 cos 162 i, 95 sin 162 j]
( 95m , 162°) = [ 95 * -0.951 i, 95 * 0.309 j]
( 95m , 162°) = -90.342 i, 29.355 j =
[ -90.34 m i , 29.36 m j ]
Therefore, the displacement of x and u components are
x displacement = -90.35 m and y displacement = 29.36 m
round appropriately
100 kg ball is initially traveling at 10 m/s. If the ball experiences a constant external force that increases the ba
velocity to 15 m/s, what is the net impulse that acted on the ball?
the net impulse that acted on the ball =500 N.s if 100 kg ball is initially traveling at 10 m/s. If the ball experiences a constant external force that increases the ba velocity to 15 m/s .
What is an example for force?The normal force acts in a direction normal to the surface interaction between objects. Friction is a force that opposes motion on surfaces. Other examples of non-fundamental forces include the elastic force, tension, and frame-dependent forces .
What does it mean to force someone?to make someone do something that they do not want to do, for example by using or threatening to use violence. force someone to do something: He claims that police officers forced him to sign a confession.
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How use of SI units in daily life is important .
Answer:
SI units are the physical units of measurement. SI units include kilogram, meter, second, ampere, kelvin, candela, and mole etcetera.
SI units are very important for daily life while measuring daily life commodities, such as:
Use of kilograms and grams while buying or selling sugar or other food items.Use of kilometers and meters while covering distances.Use of meters or inch by carpenters while estimating the lengths for furniture.Use of hours, seconds and minutes to measure time duration.Use of ampere and volt to measure current and voltage respectively by electricians.Without SI units, it would be difficult to meausre the amount of object required or any other measurement object.
Many measuring instruments have to be calibrated. What does this mean? Give an example.
Answer:
Explanation:
because we have to get a measuremt.
What are the 12 planets in order from the Sun?
Answer:
We were told that there are 9 planets if "Pluto" is included as a planet.
Matilda visits every monday just stays until noon - period
mercury, venus, earth, mars, jupiter, saturn, uranus, neptune, pluto
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune are the planet order from the Sun.
Who is the solar system's father?With the a biography, illustrations, and his dedication from "Of the Revolutions of the Heavenly Bodies," Nicolaus Copernicus is recognized to as the "Father of the Solar System."
In our solar system, are there eight or twelve planets?Eight planets, 146 moons, a number of comets, asteroids and other space rocks, ice, and numerous dwarf planets, namely Pluto, make up our solar system. The Sun is the single star in the system.
Who made the first planet discovery?Previous to the likes of Copernicus, Kepler, and Galileo, no one was really sure what those immense bright lights in the sky even were, and everyone believed that the planets (that they were conscious of) revolved around Earth.
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In operant conditioning, many complex behaviors are learned through shaping.
T or F
Hurricanes are powered by heat energy in the atmosphere and the ocean. Typically, one hurricane uses an amount of heat roughly equal to Z thousand atomic bombs. If the excess heat built up in Earth's atmosphere since 1850 went into producing hurricanes, about how many more hurricanes might we expect in the world every year?
Answer:
In an year about 6 major hurricanes and 3 minor storms occurs.
Explanation:
Hurricanes are increasing in number and frequency to the increasing impact of global warming. As current research states that climate change in the tropics results in an increased storm frequency. The presence of extra heat in the air or the oceans form the stoma that leads to the production of such energy. According to o the 200-2007 data shows in the huge increase in the storm frequency and this suggests the impact of climate warming.HELP PLSSSSSSSSSS ASAP :)))))
Answer:
Explanation:
Pooh Shiesty, that's my dawg
But Pooh, you know I'm really shiesty
You told all them O.T. ni ggas that you really slide
Tell the truth about your gang, they really dyin'
I got my own fire, don't need security in the club
All that woofin' on the net , I thought you was a thug
They ain't got nowhere to go, I sh0t up everywhere they was
Yeah, you know who took that - from you
Come get it back in blood
Come get it back in blood
if 9 joules of energy are expended pushing on one coulomb of charge round a circuit, what is the emf across the circuit?
\(\\ \sf\Rrightarrow V=\dfrac{W}{Q}\)
\(\\ \sf\Rrightarrow V=\dfrac{9}{1}\)
\(\\ \sf\Rrightarrow V=9V\)
When the outer envelope of a red giant is ejected, the remaining core of a low mass star is called a?
When the outer envelope of a red giant is ejected, the remaining core of a low mass star is called a white dwarf.
A white dwarf is a dense, hot object that no longer undergoes nuclear fusion. It is mainly composed of carbon and oxygen, and is supported by electron degeneracy pressure. The core of the white dwarf gradually cools down over billions of years, eventually becoming a cold, dark object known as a black dwarf. Therefore, When the outer envelope of a red giant is ejected, the remaining core of a low mass star is called a white dwarf.
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When the outer envelope of a red giant is ejected, the remaining core of a low mass star is initially called a planetary nebula, and eventually, it becomes a white dwarf.
When a low mass star nears the end of its life, it goes through a phase called the red giant phase. During this phase, the star's core begins to contract while its outer envelope expands, causing the star to increase in size and become less dense. Eventually, the outer envelope of the red giant becomes unstable and starts to drift away from the core. This process is known as a stellar wind or mass loss.
As the outer envelope is ejected, it forms a glowing cloud of gas and dust surrounding the central core. This cloud is called a planetary nebula. Despite its name, a planetary nebula has nothing to do with planets. The term was coined by early astronomers who observed these objects and thought they resembled planetary disks.
The remaining core of the low mass star, which is left behind after the ejection of the outer envelope, undergoes further transformation. It becomes a white dwarf, which is a hot, dense object composed mainly of carbon and oxygen. A white dwarf is the final evolutionary stage of a low mass star, where it no longer undergoes nuclear fusion and gradually cools down over billions of years.
In summary, when the outer envelope of a red giant is ejected, the remaining core of a low mass star is initially called a planetary nebula, and eventually, it becomes a white dwarf.
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