Why is climate changing?

Answers

Answer 1

Answer:

because the seasons are changing?

Answer 2

Answer:

Climate is changing because we have seasons.

Explanation:


Related Questions

What term is used to describe how things behave and is usually expressed in mathematical terms

Answers

Answer:

a 'Law'

Explanation:

Newton's laws of motion

Charles' Law      etc

The term "law"  is used to describe how things behave and is usually expressed in mathematical terms.

What are scientific laws?

Scientific laws or laws of science are propositions that describe or forecast a variety of natural occurrences and are based on repeated tests or observations.

All branches of natural science use the word "law" in a variety of contexts (approximate, accurate, broad, or narrow) (physics, chemistry, astronomy, geoscience, biology). All laws are directly or indirectly dependent on empirical facts, and they are developed from data and can be further developed through mathematics.

It is generally accepted that they are discovered rather than invented and implicitly represent causal links that are fundamental to reality even though they do not expressly declare them.

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What happens to the gravitation force between two objects that are 15 m apart, when one of them moves 3 m closer? (1 point).

Answers

Answer: The gravitation force between two objects that are 15 m apart, when one of them moves 3 m closer then it increases by a factor of 1 9/16.

Reason:

Mathematically it can be represented as, F = Gm1m2/r2 Where, F is the Gravitational force between two objects measured in Newton (N). G is the Universal Gravitational Constant with a value of 6.674 × 10-11 Nm2kg-2.

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Are the number of atoms before and after a chemical reaction the same? Why?

Answers

Answer:

They rearrange themselves and join together differently to make new substances called products. The number of atoms of each type is the same before and after a reaction. This means that the total mass of the products is the same as the total mass of the starting substances. In other words, mass is conserved.

On which object will Earth's gravity act with the greatest magnitude? *
An apple
A cereal bowl
A watermelon
A TV remote

Answers

Answer: The watermelon

Explanation: The watermelon has a larger mass than the rest of the three.

A drone has been designed that can do monitoring and surveillance at considerable heights due to its light weight of 0.800 kg. For this purpose, they are doing a test to determine its maximum height and they make it start in a vertical direction, using its thrusters it manages to achieve a thrust of 35.0 N during the first 6.00 s. until the battery runs out. What was the maximum height that the drone reached?

Answers

Answer:

2660 m

Explanation:

Sum of the forces in the first 6.00 s:

∑F = ma

F − mg = ma

35.0 N − (0.800 kg) (10 m/s²) = (0.800 kg) a

a = 33.75 m/s²

The height it reaches during this time is:

Δy = v₀ t + ½ at²

Δy = (0 m/s) (6.00 s) + ½ (33.75 m/s²) (6.00 s)²

Δy = 607.5 m

The velocity it reaches is:

v = at + v₀

v = (33.75 m/s²) (6.00 s) + 0 m/s

v = 202.5 m/s

After the battery runs out, the drone is in free fall.  At the highest point, the velocity is 0.  The height at this point is:

v² = v₀² + 2aΔy

(0 m/s)² = (202.5 m/s)² + 2 (-10 m/s²) (h − 607.5)

h ≈ 2660 m

What happens if we nuke a city?

Answers

The shadow would subsequently drop the temperature in the city, forcing warmer air to rush in and violently destroy countless buildings. There would also be “black rain,” which would be the radioactive ash and dust that would liquify and pour down on the city and we would all die.

Answer:

Those who survived the bomb may become deaf or blind, as well as suffer catastrophic burns and injuries. Even people who were not seriously injured could become trapped within a structure or unable to navigate through the wreckage.

Explanation:

A uniform rod with mass 6M and length 2L is rotating freely around an axis.
(1)
(2)
A) What is the angular velocity at position 1?
B) What is the velocity of the center of mass at position 2, given the angle theta relative to position 1?

Answers

(1) The angular velocity at position 1 of a uniform rod rotating freely around an axis can be determined.

(2) The velocity of the center of mass at position 2.

(1) To determine the angular velocity at position 1, we need to consider the conservation of angular momentum. Since the rod is rotating freely, there are no external torques acting on it.

The initial angular momentum is zero, and at position 1, the angular momentum is given by L = Iω, where I is the moment of inertia of the rod and ω is the angular velocity. By substituting the values of mass and length of the rod into the formula for moment of inertia, we can solve for ω.

(2) To calculate the velocity of the center of mass at position 2, relative to position 1 and at an angle theta, we can use the concept of angular velocity and linear velocity. The linear velocity of the center of mass is given by v = ωr, where ω is the angular velocity and r is the distance between the center of mass and the axis of rotation. By considering the given angle theta and the length of the rod, we can determine the distance r.

Substituting the value of ω calculated in part (1) into the formula, we can find the velocity of the center of mass at position 2, relative to position 1 and at angle theta.

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The amount of energy in the universe:
A)is decreasing slowly.
B)is rapidly decreasing.
C)is increasing quickly.
D) remains constant.

Answers

Answer: D

Explanation:

The total energy in the universe is constant. It cant be created or destroyed

Answer:

A

Explanation:

energy decays overtime

400.0 g of a metal absorbs 10000. j of heat energy and its temperature rises from 20.0 ºc to 103.0 ºc. what is the specific heat of the metal?

Answers

The correct answer is the specific heat of the metal in question is 0.301 J/g·ºC.

The specific heat of a substance is the amount of heat required to raise the temperature of one gram of the substance by one degree Celsius. To find the specific heat of the metal in this scenario, we need to use the formula:



q = mcΔT



where q is the amount of heat absorbed, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.


In this case, we know that the metal absorbed 10000 J of heat energy, had a mass of 400.0 g, and its temperature rose from 20.0 ºC to 103.0 ºC. Therefore, we can plug these values into the formula:



10000 J = (400.0 g) x c x (103.0 ºC - 20.0 ºC)



Simplifying this equation, we get:


10000 J = 33200 g·ºC x c



Dividing both sides by 33200 g·ºC, we get:



c = 0.301 J/g·ºC



Therefore, the specific heat of the metal in question is 0.301 J/g·ºC.



In simpler terms, this means that the metal requires 0.301 J of energy to raise the temperature of one gram of the metal by one degree Celsius.

The specific heat value is an important property of a substance, as it can help us determine how much energy is needed to heat or cool the substance, and how it will behave in different conditions.

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The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and round answer to the nearest whole number.)

Answers

53....................................

Explanation:

when a liquid is flowing through a pipe, frictional forces between the liquid and the wall of the pipe convert kinetic energy into thermal energy. what effect does this have on the pressure of the liquid within the pipe

Answers

Frictional forces between a liquid and the walls of a pipe can convert kinetic energy into thermal energy, leading to a drop in pressure within the pipe due to the decrease in force being applied to the walls.

Frictional forces between the liquid and the walls of a pipe can lead to the conversion of kinetic energy into thermal energy. This can have an effect on the pressure of the liquid within the pipe. Specifically, when the liquid loses kinetic energy due to friction, the pressure within the pipe drops. This drop in pressure can be attributed to the fact that as the liquid loses kinetic energy, its molecules move more slowly, thus decreasing the amount of force that is being applied to the walls of the pipe. As a result, the pressure within the pipe decreases.

In summary, frictional forces between a liquid and the walls of a pipe can convert kinetic energy into thermal energy, leading to a drop in pressure within the pipe due to the decrease in force being applied to the walls.


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A hockey puck slides to a stop on ice. The coefficient of friction between the puck and

the ice is 0.026. What is the puck’s acceleration?

Answers

Answer:

Explanation:

The puck slides on the ice . Coefficient of sliding friction μ = .026

Limiting frictional force = μ R

R is reaction force of the surface .

R = mg

Friction force = μ mg

deceleration = μ mg / m

= μ g

= .026 x 9.8 = .2548

= 0.26 m /s².

The complex position of a particle undergoing a 2D motion measured in meters is given by the-fellowing complex number z. z=x+iy=
t+i
t−i

Where t is time. A. Find the complex velocity Z

=
dt
dZ

as a funtion of t and then calcualte the magnitude of the complex velocity at t=2s. B. Find the complex acceleration Z
′′
=
dt
2

d
2
Z

as a function of t and then calcualte the magnitude of complex acceleration at t=2 s.

Answers

At t = 2s, the magnitude of the complex velocity can be calculated as:

\(|Z'| = |i|= 1\) , and at t = 2s, the magnitude of the complex acceleration is:

\(|Z''| = |0| = 0\).

A. To find the complex velocity Z', we differentiate the complex position z with respect to time t.

\(z = t + i(t - i)\)

Taking the derivative with respect to t:

\(dz/dt = 1 + i(1 - i)\)

Simplifying, we get:

\(Z' = 1 + i - 1 = i\)

At t = 2s, the magnitude of the complex velocity can be calculated as:

\(|Z'| = |i| = 1\)

B. To find the complex acceleration Z'', we differentiate the complex velocity Z' with respect to time t.

\(Z' = i\)

Taking the derivative with respect to t:

\(dZ'/dt = 0\)

The complex acceleration Z'' is zero, regardless of the value of t.

Therefore, at t = 2s, the magnitude of the complex acceleration is:

\(|Z''| = |0| = 0\\\).

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"A crew member of a spaceship measures the length of the ship to be 200 mm. However, an observer on a nearby space station measures the ship's length to be 120 mm. What is the speed of the spaceship relative to the space station?Express your answer with the appropriate units."

Answers

Speed of spaceship = 240,000 km/s.

This is a problem involving the relativistic length contraction, where the length of an object moving at a relativistic speed appears shorter to an observer who is at rest relative to the object.

The equation for the length contraction is given by:

L = L0 / γ

where L0 is the proper length of the object (i.e., the length measured in the object's rest frame), L is the length measured by an observer in a different frame, and γ is the Lorentz factor, which depends on the relative velocity between the two frames.

In this problem, the proper length of the spaceship is L0 = 200 mm and the length measured by the observer on the space station is L = 120 mm. Therefore, we have:

L = L0 / γ

γ = L0 / L

Substituting the given values, we get:

γ = 200 mm / 120 mm = 5/3

The Lorentz factor γ is related to the relative velocity v between the spaceship and the space station by:

γ = 1 / sqrt(1 - (v/c)^2)

where c is the speed of light.

Solving for v/c, we get:

v/c = sqrt(1 - 1/γ^2) = sqrt(1 - 9/25) = 4/5

Therefore, the speed of the spaceship relative to the space station is:

v = c x (4/5) = 0.8c

where c is the speed of light and the unit of the speed is m/s.

So, the speed of the spaceship relative to the space station is 0.8 times the speed of light, or approximately 240,000 km/s.

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Question 1
A bus travels 5 km east. Then it travels 3 km west by the same path and stops.
What is the bus's displacement?
O 10 km
O2 km
O3km
O 8 km

Answers

2 km, you simply subtract 5 from 3 and find the distance between the 2 travels.

How are mircowaves similar to radio waves

Answers

Microwaves is similar to radio waves such that they are both an electromagnetic wave of lower wavelength and high frequency.

What is a Wave?

This is referred to a disturbance which carries energy without movement of the particles.

Microwaves and radio waves both have a low wavelength and high frequency which makes them similar to each other.

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When an electron in a one-dimensional box makes a transition from the n = 1 energy level to the n = 2 level, it absorbs a photon of wavelength 426 nm. What is the wavelength of that photon when the electron undergoes a transition (a) from the n = 2 to the n = 3 energy level and (b) frorm the n = 1 to the n-3 energy level? (c) What is the width L of the box? [Ans: (a) 256 nm, (b) 160 nm, (c) 0.622 nm]

Answers

The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

Let's assume the wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h² / (8× m × L²)) ×(9 - 4)

ΔE = (h²/ (8 × m × L²)) × 5

The energy difference is proportional to the frequency of the emitted photon:

ΔE = h × c / λ

where c is the speed of light.

We can equate the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

Plugging in the given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L² = 0.00047765 m²

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

Following the same steps,

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Simplifying and solving for λ:

λ = (m × L² × c) / h

Plugging in the given values:

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.

Given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

The wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h²/ (8 × m × L²)) × 5

The frequency of the photon that was released directly correlates with the energy difference:

ΔE = h × c / λ

,c is the speed of light.

Evaluating the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Solving for λ:

λ = (m × L² × c) / h

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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B2-RT15: RIFLE SHOTS-TIME TO HIT GROUND The rifles in the figures are being fired horizontally (straight outward, off platforms). The bullets fired from the rifles are all identical, but the rifles propel the bullets at different speeds. The speed of each bullet and the height of each platform are given. All of the bullets miss the targets and hit the ground. 500 m/s 800 m/s 800 m/s 1200 m/s 40 m 40 m 30 m 20 m Rank the time it takes the bullets to hit the ground. OR All All the same zero determine Cannot 4 Least Greatest Explain your reasoning.

Answers

THE ANSWER BELOW THE PICTURES.

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B2-RT15: RIFLE SHOTS-TIME TO HIT GROUND The rifles in the figures are being fired horizontally (straight
B2-RT15: RIFLE SHOTS-TIME TO HIT GROUND The rifles in the figures are being fired horizontally (straight

A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water at an initial temperature of 20C. After a short time, the temperature of both the metal and water become equal at 25C. The specific heat of water is 4.18 J/gC in this temperature range. What is the specific heat capacity of the metal?

Record your answer with two significant figures.
5.98
J/gC

Answers

Answer:

0.64 J/g°C

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat

m = mass (g)

c = specific heat capacity

∆T = change in temperature (°C)

In this case:

Q (water) = - Q (metal)

mc∆T (water) = - mc∆T (metal)

According to the information in this question,

For water; m = 100g, c = 4.18J/g°C, ∆T = (25°C - 20°C)

For metal; m = 50g, c =?, ∆T = (25°C - 90°C)

mc∆T (water) = - mc∆T (metal)

100 × 4.18 × (25°C - 20°C) = - {50 × c × (25°C - 90°C)}

100 × 4.18 × 5 = - {50 × c × -65}

2090 = -{-3250c}

2090 = 3250c

c = 2090/3250

c = 0.643

c = 0.64J/g°C

Answer:

0.64

Explanation:

Because I got the question right :)

in 7 seconds, a projectile goes from 0 to 181m/s. What is the acceleration l? (round to the nearest whole number)

Answers

Answer:

84.83 ft/s^2 or 85 ft/s^2

Explanation:

A = Δ v Δ t

Acceleration is the rate of change of an objects speed; in other words, it's how fast velocity changes. According to Newton's second law, acceleration is directly proportional to the summation of all forces that act on an object and inversely proportional to its mass. It's all common sense - if several different forces are pushing an object, you need to work out what they add up to (they may be working in different directions), and then divide the resulting net force by your object's mass.

This acceleration definition says that acceleration and force are, in fact, the same thing. When the force changes, acceleration changes too, but the magnitude of its change depends on the mass of an object. This is not true in a situation when the mass also changes, e.g., in rocket thrust, where burnt propellants exit from the rocket's nozzle.

In the 17th century, Sir Isaac Newton, one of the most influential scientists of all time, published his famous book Principia. In it, he formulated the law of universal gravitation which states that any two objects with mass will attract each other with a force exponentially dependent on distance between these objects (specifically, it is inversely proportional to the distance squared). The heavier the objects are, the greater is gravitational force. It explains, for example, why planets orbit around the very dense Sun.

In Principia, Newton also includes three laws of motion which are central to understanding the physics of our world. The acceleration calculator is based on three various acceleration equations, where the third is derived from Newton's work:

a = (v_f - v_i) / Δt,

a = 2 * (Δd - v_i * Δt) / Δt²,

a = F / m,

where:

a is the acceleration,

v_i and v_f are respectively the initial and final velocities,

Δt is the acceleration time,

Δd is the distance traveled during acceleration,

F is the net force acting on an object that accelerates,

m is the mass of this object.

If you already know how to calculate acceleration let's focus on the units of acceleration. You can derive them from the equations we listed above. All you need to know is that speed is expressed in feet per second (imperial/US system) or in meters per second (SI system) and time in seconds. Therefore, if you divide speed by time (as we do in the first acceleration formula), you'll get acceleration unit ft/s² or m/s² depending on which system you use.

Alternatively, you can use the third equation. In this case, you need to divide force (poundals in US and newtons in SI) by mass (pounds in US and kilograms in SI) obtaining pdl/lb or N/kg. They both represent the same thing, as poundal is pdl = lb * ft/s² and the newton is N = kg * m/s². When you substitute it and reduce the units, you'll get (lb * ft/s²) / lb = ft/s² or (kg * m/s²) / kg = m/s².

There is also a third option that is, in fact, widely used. You can express acceleration by standard acceleration, due to gravity near the surface of the Earth which is defined as g = 31.17405 ft/s² = 9.80665 m/s². For example, if you say that an elevator is moving upwards with the acceleration of 0.2g, it means that it accelerates with about 6.2 ft/s² or 2 m/s² (i.e., 0.2*g).

Calculate the potential energy, kinetic energy, mechanical energy, velocity, and height of the 45 kg object at various locations as shown on the diagram below.

Calculate the potential energy, kinetic energy, mechanical energy, velocity, and height of the 45 kg

Answers

The potential energy at each point:

PE₁ = 1764 J

PE₂ = 1323 J

PE₃ = 0 J

PE₄ = 441 Jh

The kinetic energy at each point:

KE at point 1 = 0KE at point 2 = 1764 - 1323 JKE at point 2 = 441 JKE at point 3 = 1764 JKE₄ = 1219.7 J

To find the mechanical energy at each point:

ME₁ = 1764 JME₂ = 1764 JME₃ = 1764 JME₄ = 1764 J

The height at point 4, h = 1.23 m

What are the potential energy, kinetic energy, and mechanical energy of the object at each point?

To calculate the potential energy, kinetic energy, and mechanical energy of the object at each point, we will need to use the following formulas:

Potential energy (PE) = mgh, where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height above a reference point.

Kinetic energy (KE) = 0.5mv^2, where m is the mass of the object and v is its velocity.

Mechanical energy (ME) = PE + KE

Given:

Mass of the object (m) = 45 kg

Point 1: h = 4 m

Point 2: h = 3 m

Point 3: h = 0 m

Point 4: v = 5.2 m/s

To find the potential energy at each point:

PE₁ = mgh1 = 45 kg x 9.8 m/s^2 x 4 m

PE₁ = 1764 J

PE₂ = mgh2 = 45 kg x 9.8 m/s^2 x 3 m

PE₂ = 1323 J

PE₃ = mgh3 = 45 kg x 9.8 m/s^2 x 0 m

PE₃ = 0 J

PE₄ = mgh4 = 45 kg x 9.8 m/s^2 x h

PE₄ = 441 Jh

KE at point 1 = 0

KE at point 2 = 1764 - 1323 J

KE at point 2 = 441 J

KE at point 3 = 1764 J

To find the kinetic energy at point 4:

KE₄ = 0.5mv^2 = 0.5 x 45 kg x (5.2 m/s)^2

KE₄ = 1219.7 J

To find the mechanical energy at each point:

ME₁ = PE₁ + KE

ME₁ = 1764 J + 0 J = 1764 J

Since the mechanical energy is conserved (ignoring friction and air resistance), we can set ME₁ = ME₂ = ME₃ = ME₄

Solving for h:

ME₁ = ME₄

1764 J = 441 Jh + 1219.7 J

h = (1764 J - 1219.7 J) / (441 J)

h = 1.23 m

Therefore, at point 4, the object has a velocity of 5.2 m/s and a height of 1.23 m.

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calculate the centripetal force on the end of a 66.0 m (radius) wind turbine blade that is rotating at 0.47 rev/s. assume the mass is 3.4 kg.

Answers

Centripetal force on the end of a 66.0 m (radius) wind turbine blade that is rotating is calculated as = 1.23 *10^-4 N.

What is Centripetal force?

Centripetal force is the force acting on the object in curvilinear motion directed towards axis of rotation or the center of curvature and the unit of centripetal force is newton. It is directed perpendicular to the direction of the displacement of the object.

Given, radius= 66m mass is 3.4 kg

Given 0.47 rev/s

Angular velocity = 0.47 * 2π / 60

= 0.049 m/s

Centripetal force = mass * velocity²/radius

= 3.4 *  0.049² /66

Centripetal force= 1.23 *10^-4 N

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Both copper and ilver are good conductor of electricity but only copper i ued for making electric wire and not ilver why?

Answers

Both copper and silver are good conductor of electricity but only copper is used for making electrics wire and not silver because silver is expensive material when compared to copper.

Despite the fact that silver is an excellent heat conductor, it is not used in the production of electrical wire because of its high cost. Silver is a valuable metal that is used to make jewelry, high-value coins, and electroplating. Because of this, silver is not used to make electric wires. When it is exposed to air, silver quickly oxidizes and becomes tarnished.

Copper is nearly always utilized because of its low cost and the fact that it is an adequate conductor for the majority of uses. In comparison to copper, silver has a resistivity that is just marginally lower; yet, due to its higher density, the two elements are almost comparable in terms of their ratio of resistivity to mass.

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Total distance between Karachi and Hyderabad is 120 km , if a car speed is 40 km/h, In how many hours it can travel back to Hyderabad

Answers

it takes 6 hours to travel back to Hyderabad

120/40= 3
Answer: 3

Proof:
Total distance between Karachi and Hyderabad is 120 km , if a car speed is 40 km/h, In how many hours

a child walks 200 m east, pauses, and then continues 400 m east. whats the total dispaclement?

Answers

Using the same scale that was used to draw A and B, measure the length of the resultant, R, to determine its magnitude. The overall change in location in this case is 200 m east plus 400 m east, which equals 600 m east.

Displacement is characterized by the final position minus the starting position.

The displacement is only the difference between the locations of the two marks and is unrelated to the route used to get there. The total length of the path between the two markings, however, is the distance travelled.

Displacement and distance, however, are two distinct ideas. The total distance travelled is larger than the displacement between those two points if an object changes direction while travelling.

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A dropped rock takes 5.2 sec to fall from a cliff. How tall is the cliff? (use kinematics,
assume no air resistance)

Answers

Answer:

below

Explanation:

d  = 1/2 a t^2

  = 1/2 (9.81)(5.2)^2 = 132.6 m =~ 133 m

When the string on a violin vibrates, waves move in both directions along the string, interfering with each other. Sometimes these wave
interact to make nodes and antinodes. What are these kinds of waves called? (1 point)

A.) Superposition waves
B.) Frequency waves
C.) Electromagnet waves
D.) Standing Waves

Answers

When the string on a violin vibrates, waves move in both directions along the string, interfering with each other. These waves are standing waves (Option D).

What are Standing Waves?

The Standing Waves are waves generated due to the vibrational frequency that produces reflected waves capable of interfering with the incident waves.

Standing Waves generates a pattern of waves that form a standing still, it is for that reason of the name.

The nodes and antinodes of the standing waves are found elsewhere in the medium where waves form.

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Answer:

Standing waves

Explanation:

HELP PLZ HELP !!!!!!!!!!!

HELP PLZ HELP !!!!!!!!!!!

Answers

Neon (10)
Sodium (11)
Silicon (14)
Iron (26)
Uranium (92)

Answer:

From least to greatest: Neon, Sodium, Silicon, Iron, Uranium

Explanation:

Here are all the atomic numbers for each one:

Iron = 26

Sodium = 11

Uranium = 92

Neon = 10

Silicon = 14

Hope this helps! :D

Study the velocity vs. time graph shown.


What is the displacement of the object from 2 seconds
to 6 seconds?


4 m
8 m
16 m
24 m

Study the velocity vs. time graph shown.What is the displacement of the object from 2 secondsto 6 seconds?4

Answers

8m is the answer :D your welcome

36. The achievement of lifting a rocket off the ground and into space can be explained by
Newton's first law, ,
b. Newton's second law,
c.Newton's third law,
d.the law of conservation of momentum,

36. The achievement of lifting a rocket off the ground and into space can be explained byNewton's first

Answers

ANSWER: C. Newton’s third law
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