Why is accelration negative when velocity is positive.​

Answers

Answer 1

Answer:

An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion (in this case, a negative acceleration).

Explanation:


Related Questions

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time?

Free-fall Acceleration is -10 m/s^2

Answers

Answer:

Explanation:

s = s₀ + v₀t + ½at²

s = 0 + 0(15) + ½(6)(15²)

s = 675 m

Not sure what the free fall acceleration is needed for, but if the object is dropped from a high enough point, it will travel in 15 seconds

s = ½10(15²) = 2250 m  if air resistance is ignored

The strength of the force of friction depends on which two factors?

Answers

Answer:

coefficient of friction (μ) and normal force (N)

Answer: How hard the surfaces push together and the types of surfaces involved

Explanation:

If an object is placed at a distance of 12 cm from a convex lens of focal length 16 cm then calculate the image distance from the lens?

Answers

Answer:

-48cm

Explanation:

For a convex lens f is +ve and V is +ve

Using the formula 1/f=1/v+1/u

u=12cm and f=16cm

1/16-1/12=1/v

1/v=-1/48

v=-48cm

Simple machines make work easier. You must left a move this load of Saul for your parents. It is heavy you’re using to simple machines when you use this wheel barrow wight simple machine included in the wheelbarrow makes it easier to move the song from one place to another.

Answers

The use of the wheel barrow in this case makes it a simple machine

What is the simple machine?

A wheelbarrow is an illustration of a straightforward device that can simplify labour by lowering the force needed to move a large load. The wheel and axle and the lever are two basic machines that are used.

The wheelbarrow's wheel is made of an axle and wheel. The friction between the wheel and the ground is decreased by the wheel's rotation around the axle. It can also be seen as one of the classes of the lever.

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How are both electromagnetic and mechanical waves used when people communicate with each other?

Answers

Unlike mechanical waves, which require matter, electromagnetic waves can travel through empty space, as well as through liquids, solids, and gases. There are many similarities between light waves and mechanical waves. They can both be measured by their amplitude, wavelength, and frequency.

Please help! I'm really desperate.

Could anyone at least give some sketch ideas or advice?

I'm not sure how to set it out..

Please help! I'm really desperate.Could anyone at least give some sketch ideas or advice?I'm not sure

Answers

Answer:

make a pineapple schematic

Explanation:

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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If you throw a ball into the air, Earth exerts a force on the ball. The ball in the air exerts no force on Earth. True or false?

Answers

Answer:

False.

Explanation:

If you throw a ball into the air, Earth exerts a force on the ball. Also, the ball in the air exerts a force on Earth.

This ultimately implies that, there is a force pair between the earth and the ball.

find charge and charge density on the surface of a conducting sphere of radius 15.2cm where potential at 215 v

Answers

this is the correct answer

find charge and charge density on the surface of a conducting sphere of radius 15.2cm where potential

Six identical elements are connected in a battery whose internal resistance is 6Ω. Resistors R₁=14Ω and R₂ are connected to the battery, the total resistance of the external circuit is R=7Ω and the current flowing in it is 4 A. Determine the resistance of the second resistor and the internal EDS of the elements .

Six identical elements are connected in a battery whose internal resistance is 6. Resistors R=14 and

Answers

Answer:

Using Ohm's Law, we can calculate the voltage of the battery as V = IR = (4 A)(7 Ω) = 28 V.

The total resistance of the circuit is R = R₁ + R₂ + r, where r is the internal resistance of each element.

We know that R₁ = 14 Ω and R = 7 Ω, so we can solve for R₂:

R₂ = R - R₁ = 7 Ω - 14 Ω = -7 Ω

This is a negative resistance, which doesn't make sense physically. However, it indicates that there is an error in the problem or the calculations.

To find the internal EDS of the elements, we can use the equation:

V = ε - Ir

where V is the voltage of the battery, ε is the internal EDS of each element, I is the current flowing in the circuit, and r is the internal resistance of each element.

We know that V = 28 V, I = 4 A, and r = 6 Ω, so we can solve for ε:

ε = V + Ir = 28 V + (4 A)(6 Ω) = 52 V

Therefore, the internal EDS of each element is 52 V.

What force causes oppositely charged particles to attract each other?
A. Magnetic force B. Compression
C. Electrical Force D. Gravity

Answers

Answer:

The electromagnetic force.

Answer:

It is electrical force

Explanation:

i got it wrong on A P E X  with magnetic hope this helps!

2. A pair of narrow, parallel slits sep by 0.25 mm is illuminated by 546 nm green light. The interference pattern is observed on a screen situated at 1.3 m away from the slits. Calculate the distance from the central maximum to the

Answers

Answer:

for the first interference m = 1   y = 2,839 10-3 m

for the second interference m = 2   y = 5,678 10-3 m

Explanation:

The double slit interference phenomenon, for constructive interference is described by the expression

                d sin θ = m λ

where d is the separation between the slits, λ the wavelength and m an integer that corresponds to the interference we see.

In these experiments in general the observation screen is L >> d, let's use trigonometry to find the angles

           tan θ = y / L

with the angle it is small,

          tan θ = sin θ / cos θ = sin θ

   

we substitute

         sin θ = y / L

         d y / L = m λ

the distance between the central maximum and an interference line is

        y = m λ L / d

let's reduce the magnitudes to the SI system

     λ = 546 nm = 546 10⁻⁹ m

     d = 0.25 mm = 0.25 10⁻³ m

let's substitute the values

      y = m 546 10⁻⁹ 1.3 / 0.25 10⁻³

      y =  m 2,839 10⁻³

the explicit value for a line depends on the value of the integer m, for example

for the first interference m = 1

the distance from the central maximum to the first line is y = 2,839 10-3 m

for the second interference m = 2

the distance from the central maximum to the second line is y = 5,678 10-3 m

According to the Law of Effect, in which scenario is the behavior likely to be repeated as a result of the reward?

a
An employee is promised a bonus when he leaves his job for each quarter during which he has the most sales.

b
An employee is promised a bonus at the end of the year if he has the most sales for the first quarter.

c
An employee receives a bonus at the end of the quarter for having the most sales for
week one in the quarter.

d
An employee receives a bonus at the end of the week for having the most sales that week.

Answers

Answer:

D. An employee receives a bonus at the end of the week for having the most sales that week.

Explanation:

Took the test

A 4260-kg roller coaster train full of riders approaches the level loading dock at a speed of 19.0 m/s. It is abruptly decelerated to a speed of 3.2 m/s. Determine the work done on the roller
coaster.
KE+PE+Wext=KE+ PE

Answers

Answer:

below

Explanation:

The change in Kinetic Energy is equal to the work done

  KE = 1/2 mv^2

      Change in KE =   1/2 m (19^2 - 3.2^2) = 747.1 kjoules

Use Eq. (9.20) to calculate the moment of inertia of a uniform, solid disk with mass M and radius R for an axis per- pendicular to the plane of the disk and passing through its center

Answers

Circular disc's moment of inertia around axis passing through mass and parallel to disc Icm=MR22

Explain about the moment of inertia?

The phrase "moment of inertia" in physics refers to the precise calculation of a body's inertia with respect to rotation, or the resistance a body exhibits when a torque is applied to alter its rate of rotation around an axis (turning force).

It is a broad (additive) property: the moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. Because it resists rotational motion, the moment of inertia is referred to as such and not as a moment of force.

Moment of inertia is the propensity of an object to continue rotating at a constant speed or in a condition of rest. More torque is needed to shift this state the higher the moment of inertia.

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10. Liquids are poured into a container and separate. They form a green layer on
the bottom, a blue layer in the middle, and a red layer on the top. What's true about
the density of the liquids?
A. The red liquid is the least dense.
B. The green liquid is the least dense.
C. The blue liquid is the least dense.
D. They all have the same density.

Answers

Option A is true: the red liquid is the least dense.

What happens when different liquids are poured into a container?

When different liquids are poured into a container, they will typically separate based on their densities. Liquids with higher densities will sink to the bottom, while liquids with lower densities will float on top.

In the scenario described in the question, we are told that the liquids have separated into three distinct layers: green on the bottom, blue in the middle, and red on top. Based on this layering, we can infer that the red liquid must be the least dense, since it is floating on top of the other two liquids.

Similarly, we can infer that the blue liquid is denser than the red liquid, but less dense than the green liquid, since it is sandwiched between them. And we can infer that the green liquid is the most dense, since it is at the bottom.

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A baseball pitcher throws a fastball at a speed of 44 m/s. The acceleration occurs as the pitcher holds the ball in his hand and moves it through an almost straight-line distance of 3.5 m. Calculate the acceleration, assuming it is uniform. Compare this acceleration to the acceleration due to gravity.

Answers

v = s/t

44 m/s = 3.5 m/t

t = 3.5 m : 44 m/s

t = 0.08 s

a = v/t

a = 44 m/s/0.08 s

a = 550 m/s²

a : g = 550 m/s² : 10 m/s²

a : g = 55 : 1

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Can someone explain how to do the algebra for this question? I know everything else, I just don’t know how to rearrange the question to solve for v.

Can someone explain how to do the algebra for this question? I know everything else, I just dont know

Answers

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

A piston-cylinder device initially contains 50 L of liquid water at 40°C and 200 kPa. Heat is transferred to the water at constant pressure until the entire liquid is vaporized. (a) What is the mass of the water? (b) What is the final temperature? (c) Determine the total enthalpy change. (d) Show the process on a T-v diagram with respect to saturation lines.

Answers

(a) The mass of water is approximately 49.65 kg. (b) The final temperature of the water vapor will be 120°C. (c) The total enthalpy change is approximately 277,956 kJ. (d) Diagram shown below.

(a) To determine the mass of the water, we need to know its density at the given conditions. The density of water changes with temperature and pressure. At 40°C and 200 kPa, the density of water is approximately 993 kg/m³.

Since we have 50 L of water, we need to convert it to cubic meters:

50 L = 0.05 m³

Now we can calculate the mass of water:

Mass = Density * Volume

Mass = 993 kg/m³ * 0.05 m³

Mass ≈ 49.65 kg

Therefore, the mass of water is approximately 49.65 kg.

(b) To find the final temperature, we need to consider the phase change from liquid to vapor. At constant pressure, the temperature will remain constant until all the liquid water has vaporized. This temperature is called the saturation temperature.

We can determine the saturation temperature at 200 kPa using a steam table or other relevant data sources. Let's assume that the saturation temperature is 120°C.

Therefore, the final temperature of the water vapor will be 120°C.

(c) To calculate the total enthalpy change, we need to consider the energy required to heat the water from its initial temperature to the saturation temperature, as well as the energy required for the phase change from liquid to vapor.

The enthalpy change during heating can be calculated using the formula:

ΔH1 = Mass * Specific Heat Capacity * ΔT1

Where:

Mass = 49.65 kg (from part a)

Specific Heat Capacity = specific heat capacity of water at constant pressure = 4.18 kJ/(kg·°C)

ΔT1 = final temperature - initial temperature = 120°C - 40°C = 80°C

ΔH1 = 49.65 kg * 4.18 kJ/(kg·°C) * 80°C

ΔH1 ≈ 165,938 kJ

The enthalpy change during phase change can be calculated using the formula:

ΔH2 = Mass * Latent Heat of Vaporization

Where:

Mass = 49.65 kg (from part a)

Latent Heat of Vaporization = energy required to vaporize 1 kg of water = 2257 kJ/kg

ΔH2 = 49.65 kg * 2257 kJ/kg

ΔH2 ≈ 112,018 kJ

The total enthalpy change is the sum of ΔH1 and ΔH2:

Total Enthalpy Change = ΔH1 + ΔH2

Total Enthalpy Change ≈ 165,938 kJ + 112,018 kJ

Total Enthalpy Change ≈ 277,956 kJ

Therefore, the total enthalpy change is approximately 277,956 kJ.

(d) The process can be shown on a T-v (temperature-volume) diagram with respect to saturation lines. In this case, the process starts at the initial temperature and pressure (40°C, 200 kPa), and moves along the constant pressure line until reaching the saturation temperature (120°C). Then, the process follows the saturation line until the entire liquid is vaporized.

Here is a simplified representation of the process on a T-v diagram:

           |

Saturation |                       |

 Line   |                             |

           |                             |

           |                             |

           |                             |

           |                             |

           |                             |

           |                             |

 Initial |-----------------------------| Final

           |                             |

           |                             |

           |                             |

           |                             |

           |                             |

           |                            

This diagram is a rough representation and does not accurately reflect specific volume values or scale. It simply illustrates the general process from initial conditions to the final state along the constant pressure and saturation lines.

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Here's a quick story if a boy walks to the woods at night and slender man comes along what is most likely to happen put your answers in the comments.

Answers

Answer:

the boy would go missing

Answer: Slender man converts the boy to christianity

Silver is more costly than iron because it is 1. Heavier 2. Scarcer 3. Whiter 4. Harder 5 ...

Answers

Answer:

scarcer

Explanation:

Silver is more costly than iron because it is scarcer as it is found only in some areas of the country... it's a rare element hence it is scarcer and more expensive..

The position-time equation for a certain train is
2.9m + (8.8m/s)t + (2.4m/s2)+2

What is it’s acceleration?

Answers

Answer:

\(a=4.8m/s^2\)

Explanation:

Hello,

In this case, since the acceleration in terms of position is defined as its second derivative:

\(a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)\)

The purpose here is derive x(t) twice as follows:

\(a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2\)

Thus, the acceleration turns out 4.8 meters per squared seconds.

Best regards.

How do I solve this problem

How do I solve this problem

Answers

Answer:

it is light

Explanation:

the arrow that says light is on the glass it must be near from tungsten

Skydiver jumps out of a plane she falls down word and very fast P. When she Open Sarah parachute she slows down. What force pulls the skydiver to the ground?

Answers

There are two forces acting on a parachute with a parachutist: the force of gravity and the air resistance. The force pulling the skydiver to the ground would be Wright force

creation
Design a device to minimize impact from a collision.
Design a device to convert one form of energy to another.

In 2-3 paragraphs explain your design, the materials that would be used to construct it, its function, and the relative efficiency of your design compared to something that already exists and performs a similar function

Answers

Designing a device to minimize impact from a collision:

The device I would design to minimize impact from a collision would be a shock absorber made from a combination of rubber and metal. The device would be installed between the two colliding objects, and its function would be to absorb and dissipate the energy of the collision, thereby reducing the impact forces on the objects.
CONSTRUCTION:

The shock absorber would consist of a metal cylinder with a rubber insert that would compress upon impact. The metal cylinder would be made from a strong and durable material such as steel, while the rubber insert would be made from a high-density rubber material with excellent shock-absorbing properties.

Compared to existing shock-absorbing devices such as airbags and crumple zones, this design would be more efficient in reducing the impact forces on the colliding objects. Unlike airbags and crumple zones, which are designed to absorb the impact forces by deforming, the shock absorber would absorb the impact energy through compression and dissipation of the energy as heat.

Designing a device to convert one form of energy to another:The device I would design to convert one form of energy to another would be a piezoelectric generator. The function of this device would be to convert mechanical energy into electrical energy through the use of piezoelectric materials.The piezoelectric generator would consist of a piezoelectric material such as quartz or lead zirconate titanate (PZT) sandwiched between two metal plates. When mechanical stress is applied to the piezoelectric material, it generates an electrical voltage across the metal plates.

Compared to existing devices such as generators and batteries, the piezoelectric generator would be more efficient in converting mechanical energy into electrical energy. This is because the piezoelectric effect is a direct conversion of mechanical energy into electrical energy, without the need for any intermediate steps such as the conversion of mechanical energy into rotational energy in a generator. Additionally, the piezoelectric generator would be smaller and more lightweight than traditional generators, making it ideal for use in portable electronic devices.

A marshmallow is fired from ground level with an initial speed of 41.5 m/s at an
angle of 33.5° above the horizontal. (a) Determine the maximum height reached
by the marshmallow. (b) Determine the horizontal range that the marshmallow
travels during its flight.

Answers

Look at picture first I couldn’t fit it all in but after you get the time get all the x values that you have and sub into s=ut+1/at^2

S=? t=2.34 a=0 u=41.5cos(33.5)
s= (41.5cos(33.5))(2.34)+1/2(0)
s=80.98 meters
this is the horizontal range
A marshmallow is fired from ground level with an initial speed of 41.5 m/s at anangle of 33.5 above the

The skin temperature of a person is 34o C and his body surface area is about 1.8 m2 . He is standing bare skin in a room where the air temperature is 24o C and the walls are 17o C. He is metabolizing food at a rate of 155 W, the emissivity of his skin is 0.97 and there is a 5mm thick dead layer (immobile) air next to his skin acting as an insulation. a./ at what rate his body is losing heat by conduction

Answers

Answer:

the rate at which his body is losing heat by conduction is 93.6 J/s

Explanation:

Given that;

surface area A = 1.8 m²

Skin temperature of the person Tp = 32°C = ( 34 + 273.15 ) = 307.15 K

Temperature of Air \(T_{air}\) = 24°C = ( 24 + 273.15 ) = 297.15 K

Temperature of wall \(T_{wall}\) = 17°C = ( 17 + 273.15 ) = 290.15 K

Length ( thick dead layer = 5 mm = 0.005 m

Skin emissivity = 0.97

Rate of metabolism = 155 W

rate his body is losing heat by conduction = ?

first we determine the difference in temperature between the skin and air

so

ΔT = 307.15 K - 297.15 K = 10 K

we know that; coefficient of thermal heat conductivity of air k = 0.026 W/mK

so

rate of heat loss by conduction Q/ΔT will be;

Q/ΔT = (KA/L)ΔT

so we substitute

= ( 0.026 × 1.8/ 0.005 )10

= 9.36 × 10

= 93.6 J/s

Therefore, the rate at which his body is losing heat by conduction is 93.6 J/s

R₁ = 7 Ω
R₂ = 10 Ω
R₃ = 9 Ω
R₄ = 8 Ω
Find the resistance (in ohms) between points A and B.
Round to the nearest hundredth.

Please show all work!!!!!!

R = 7 R = 10 R = 9 R = 8 Find the resistance (in ohms) between points A and B.Round to the nearest hundredth.Please

Answers

Answer:

Explanation:

Let R5 be the resistance between R3 and R4

R3 and R4 are in series

R5=R3+R4 = 9+8=17

R1, R2 and R5 are in parallel

Resistance R between A and B is :

1/R= 1/R1+1/R2+1/R5=1/7+1/10+1/17=170+119+70/1190=359/1190

1/R=359/1190

R=1190/359=3.314 Ω

Rounding to nearest hundredth we get 3.31Ω

Fred the fisherman has been told that, because
of refraction, a fish in water will
appear
nearer the water's surface than it really is.
to be
He draws a diagram to try to work this out.
I think it will look lower, not higher.' he says.
Explain what Fred has done wrong.

Answers

Due to light refraction, any fish in the water can see a fisherman on the bank a little more clearly than one might anticipate. When the light hits the water's surface, it “bends” down by around 13 degrees, leaving the image. Thus option A is correct.

What refraction affect the fisherman?

When it reaches the surface, light emanating from the fish refracts (changes direction). When viewed from above the water, a fish appears to be closer to the surface than it actually is.

Therefore, Fred the fisherman has been told that, because of refraction, a fish in water will appear.

Learn more about fisherman here:

https://brainly.com/question/10776600

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What would cause the AMA of a machine to decrease?How could you increase the AMA of a machine?

Answers

The AMA is the quotient between the input and output forces and is given by:

\(AMA=\frac{F_o}{F_I}\)

Where:

\(\begin{gathered} F_o=\text{ output force} \\ F_I=\text{ input force} \end{gathered}\)

Therefore, the AMA is decreased if the input force is increased. If in a machine the friction force increases due to low maintenance then the required input force would increase and therefore, the AMA would decrease.

In a first-class lever we have the following:

We can calculate the ratio between input and output forces by adding the torque around the fulcrum:

\(F_oR_o-F_iR_i=0\)

Adding the product of the input force and input distance:

\(F_oR_o=F_iR_i\)

Now, we divide both sides by the input force:

\(\frac{F_oR_o}{F_i}=R_i\)

Now, we divide both sides by the output distance:

\(\frac{F_o}{F_i}=\frac{R_i}{R_o}\)

Therefore, the AMA is:

\(AMA=\frac{R_i}{R_o}\)

Therefore, if in the lever we increase the input distance or decrease the output distance we would increase the AMA.

What would cause the AMA of a machine to decrease?How could you increase the AMA of a machine?
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