Answer:
The answer is C!
Explanation:
Answer:
C- the modern atomic theory contains over 200 years of research.
Explanation:
A 100-g toy car is propelled by a compressed spring that starts it moving. The car follows the curved track in the figure above. What is the final speed of the toy car if its initial speed is 2.22
m/s and it coasts up the frictionless slope, gaining 0.21
m in altitude?
The toy car's top speed is roughly 2.01 m/s.
Why does the toy car move on the floor after the key has been wound?When the key is wound, the potential energy of the spring is transformed into kinetic energy, which causes the toy vehicle to move on the floor. The law of conservation of energy is the reason why the toy vehicle moves on the floor once the key is wound.
K1 = (1/2) * m * v1²
where m is the mass of the toy car, v1 is its initial speed, and K1 is its initial kinetic energy.
U = m * g * h
where g is the acceleration due to gravity and h is the height gained by the toy car.
K2 = m * g * h
where K2 is the final kinetic energy of the toy car.
Equating the initial and final energies of the system, we have:
(1/2) * m * v1² = m * g * h
Simplifying and solving for v2, the final velocity of the toy car, we get:
v2 = √(2 * g * h + v1²)
Substituting the given values, we get:
v2 = √(2 * 9.81 m/s² * 0.21 m + (2.22 m/s)²)
v2 = √(4.0443)
v2 = 2.01 m/s (approx)
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The pendulum on a grandfather
clock is 0.993 m long, and swings
to a maximum 4.57° angle. At that
point, how high is it above the
lowest point in its swing?
(Unit = m)
Watch your sig figs!
Answer:
Explanation:
the answer is 35.6
lowest point in its swing is 12.478 cm/s.
briefly:-Any pendulum, when positioned vertically, swings equally in both directions.
Assume that the swing's angle on either side is.
So, 2θ = 4.57°
Or, θ = 2.285°
Let v represent the pendulum's lowest point's linear speed.
The highest point of the pendulum is really h = l * (1 - cos ) vertical height above the lowest point of the swing when it reaches its maximum position.
h is therefore equal to (0.993 m) * (1 - cos 2.285°) (0.993 m) * (1 - 0.9992) = 0.0007944 m.
If m is the pendulum's mass, we can express the following using the rule of conservation of energy:
The highest point's potential energy is transformed into kinetic energy at the lowest location via height.
Therefore, m* g* h= (1 / 2)* m* (v2)
Or, v = √(2gh) (2gh)
v = ( 2 * 9.8 * 0.0007944) m/sec
v = 0.12478 m/sec
The correct answer is 12.478 cm/s.
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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.
two electrons are separated by 1.10m, What is the magnitude of the electric force each electron exerts on the other?
Answer:
4.56×10¯⁷¹ N
Explanation:
From the question given above, the following data were obtained:
Distance apart (r) = 1.10 m
Force (F) =?
NOTE:
Gravitational constant (G) = 6.67×10¯¹¹ Nm² /Kg²
Mass of electron = 9.1×10¯³¹ Kg
Mass of the two elections = M₁ = M₂ = 9.1×10¯³¹ Kg
Thus, we can obtain the force of attraction between the two elections as illustrated below:
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × (9.1×10¯³¹)² / (1.1)²
F = 4.56×10¯⁷¹ N
Thus, the force of attraction between the two elections is 4.56×10¯⁷¹ N
please look at the screenshot and tell me which line goes with the question 1,2,3, or 4
The diagram below that shows a free-body diagram is the third option m
How to explain the informationA free-body diagram shows all the forces acting on a single object. In this case, the object is m3. The forces acting on m3 are:
The force F1 exerted by m1. This force is directed to the left. The force F2 exerted by m2. This force is directed to the right.
The force F3 exerted by m3. This force is directed to the left.
The net force on m3 is zero, since the forces F1 and F2 are equal and opposite. This means that m3 is in equilibrium.
Diagram (a) shows the forces F1 and F2, but it does not show the force F3. This is incorrect, since F3 is also acting on m3. In conclusion,the correct option is C.
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25. The length of a bow is L. When it vibrates in the fundamental mode with a length of 2 L, the frequency is f. Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is,
(i) 3fo
(iv) √3f
(ii) 6fo
(v) √6fo
(iii) f/3
Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is 6fo. option(ii)
When a bow vibrates in its fundamental mode with a length of 2L, the frequency is denoted as f. Now, let's consider the scenario where half of the given length (L) is pulled to a length of 2L.
In the fundamental mode of vibration, the frequency is inversely proportional to the length of the vibrating object. Therefore, if the length of the bow is halved to L, the frequency would double to 2f.
When this new length of L is pulled to a length of 2L, we need to determine the frequency obtained in the fundamental mode.
Since the frequency is inversely proportional to the length, we can use the inverse relationship to find the new frequency.
If the original frequency was 2f at length 2L, when the length is reduced to L, the new frequency would be (2f)/(2L) = f/L.
Now, if this length of L is stretched to 2L again, the new frequency in the fundamental mode would be (f/L) * (2L) = 2f. option(ii)
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how often the earth magnetism change
1. In order to generate a current from a magnet, which of the following would generate a current?
a. Spinning a magnet near a wire
b. Placing the north end of a magnet near a wire
c. Place the south end of a magnet near a wire
2. In order for a circuit to function, which of the following must be true?
a. The circuit cannot have more than 3 bulbs attached
b. The circuit must have an switch placed in the circuit in the open position
c. The circuit must make a complete loop and must have all parts connected to that loop
Spinning a magnet near a wire would generate a current.
The circuit must make a complete loop and must have all parts connected to that loop.
What is the spinning magnet?When a magnet approaches a conductor, such as a wire, the magnetic field changes, causing the wire to conduct electricity. Electromagnetic induction is a process that underlies the operation of electric motors and generators.
Electromagnetic induction and is the basis for how generators and electric motors work and it explains the fact that current is generated by a spinning a magnet near a wire.
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22 Humans see different colors of
the visible light spectrum because
A. the wavelength of light is
reflected by what it is hitting and
directed back into the eye.
B. the wavelength of light is
refracted by what it is hitting and
directed back into the eye.
C. the wavelength of light is
diffracted by what it is hitting
and directed back into the eye.
D. the wavelength of light is
absorbed by what it is hitting and
directed back into the eye.
Answer:
A. the wavelength of light is reflected by what it is hitting and directed back into the eye.
Explanation:
A displacement vector with a magnitude of 20. meters could have perpendicular components with magnitudes of A. 10. m and 10. m B. 12 m and 8.0 m 12 m and 16 m D. 16 m and 8.0 m
Answer:10.m and 10. M
Explanation:
A displacement vector with a magnitude of 20. m could have perpendicular components with magnitudes of C. 12 m and 16 m.
A displacement vector with a magnitude of 20. meters can be decomposed in 2 perpendicular components.
They would form a right triangle, in which the displacement vector would be the hypotenuse (a) and the components would be the legs (b, c).
Given the magnitude of the legs, we can calculate the magnitude of the hypotenuse using the Pythagorean theorem.
\(c = \sqrt{a^{2} + b^{2} }\)
Let's use this formula to calculate the displacement vector for each pair of legs.
A. 10. m and 10. m\(c = \sqrt{a^{2} + b^{2} } = \sqrt{(10.m)^{2} + (10.m)^{2} }= 14.1m\)
B. 12 m and 8.0 m\(c = \sqrt{a^{2} + b^{2} } = \sqrt{(12m)^{2} + (8.0m)^{2} }= 14.4m\)
C. 12 m and 16 m\(c = \sqrt{a^{2} + b^{2} } = \sqrt{(12m)^{2} + (16m)^{2} }= 20m\)
D. 16 m and 8.0 m\(c = \sqrt{a^{2} + b^{2} } = \sqrt{(16m)^{2} + (8.0m)^{2} }= 17.9m\)
A displacement vector with a magnitude of 20. m could have perpendicular components with magnitudes of C. 12 m and 16 m.
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A stone of mass 1kg is thrown at 10m/s upwards making an angle of 37°with the horizontal from a building that is 20m high. Using the law of conservation of energy calculate the speed wjen the stone hits the ground.
Answer:
31.68 m/s
Explanation:
The law of conservation of energy states that energy is not lost or gained it is just converted, in this example, since it is not given any resistance from the wind, you'd have two variables Speed on the Y-axis and on the X-axis, since both of them would result in the same decrease and increase with against gravity, it doesn't matter the value of both.
As the stone continues to go upwards it will continue to lose speed due to de-acceleration from the gravity acting on it, similarly, it will continue to gain Potential energy, instead of kinetic energy, when it reaches its highest point the speed on Y will be "0" and the free fall will start, since the up and down movement will be equal in time the and acceleration would be equal -9.81 m/s and 9.81 m/s because the only acceleration you have is gravity, you only need to calculate how much speed will gain a rock accelerating at 9.81 m/s falling 20 m:
\(H=\frac{1}{2}g*t^{2} \\\frac{20}{1/2*9.81} =t^{2} \\\\t^{2} =4.08\\t=\sqrt{4.08} \\t=2.21\)
Now we just add the time accelerating:
\(Vf=Vo+at\\Vf=10 m/s+ 2.21*9.81\\Vf=10 m/s+21.68\\Vf=31.68 m/s\)
How does the ecotourism industry act as an ecosystem service that benefits tourists, the people that live in the area, and the people that work in the industry?
It promotes enjoyable experiences for both guests and hosts; It lessens the negative effects of tourism on the environment; It increases local residents' access to work and financial prospects; It promotes conservation by offering financial advantages in its direction.
What is ecotourism?The World Tourism Organization defines ecotourism as all forms of nature-based travel in which visitors' primary interests are in observing and appreciating the environment as well as the local cultures that are still practiced in natural settings.
Here are a few instances of ecotourism:
Visit places where there is nature (think of the flora, animals, and resources)discovering the heritage of the local culture.Ecologically sound wilderness excursions.volunteering or watching nature.trips devoted to environmental preservation efforts, like beach clean-ups.Learn more about ecotourism here:
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what probe has studied phobos; what were the names of the first two rovers explored mars; most asteroids are found between _____.; asteroids which are affected by jupiter's gravity are called _____.; explain why the moon, which is the earth’s natural satellite, has a spherical shape.; phobos (moon); deimos (moon); phobos and deimos
Phobos 1 was an uncrewed Soviet space probe of the Phobos Program launched from the Baikonur launch facility on 7 July 1988. Its intended mission was to explore Mars and its moon Phobos and Deimos.
Mars Pathfinder was the first-ever robotic rover to the surface of the red planet Mars. The Opportunity was the second of the two rovers launched in 2003. There are lots of asteroids in our solar system. Most of them are located in the main asteroid belt- a region between the orbits of Mars and Jupiter. The Trojan asteroids are affected by Jupiter's gravity.
The lowest gravitational potential energy of a system of particles is achieved when they form a sphere as opposed to a disk. This is why many smaller objects like asteroids and even Mars's two moons are shaped like lumpy boulders and so is our moon also spherical in shape.
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Please help! I'm really desperate.
Could anyone at least give some sketch ideas or advice?
I'm not sure how to set it out..
Answer:
make a pineapple schematic
Explanation:
A car drives around a racetrack for 30 seconds. What do you need to know to
calculate the instantaneous speed of the car at a given point?
A. The total displacement of the car
B. The time needed to drive 1 lap
C. The slope of the car's position-time graph
D. The average speed of the car
Answer: the slope of the cars position-time graph
Explanation:
Just took the test
A fast train has a speed of 181 km/hr. Because its wheels have a limited grip to the railway, the train must not accelerate at more than 0.058g (where g = 9.81 m/s2) while turning, or it will derail. What is the smallest radius of curvature for the track that the train can tolerate? If there is a curve of radius 1.100 km, what speed must the train mantain to keep the acceleration at the limit?
a. The the smallest radius of curvature for the track that the train can tolerate is 4.44 km
b. The speed must the train mantain to keep the acceleration at the limit is 25 m/s
a. What is the smallest radius of curvature for the track that the train can tolerate?Using the equation for centripetal acceleration, we find the radius of the circle the train can tolerate.
So, centripetal acceleration a = v²/r where
v = speed of train and r = radius of curvature of track.What is the radius of curvature of the track?Making r subject of the formula, we have
r = v²/a
Given that the train has a speed of 181 km/hr and its acceleration must not exceed 0.058g, we have that
v = 181 km/hr = 181 × 1000 m/3600 s = 50.28 m/s and a = 0.058g = 0.058 × 9.81 m/s² = 0.569 m/s²So, substituting the values of the variables into the equation for r,we have
r ≥ v²/a
r ≥ (50.28 m/s)²/0.569 m/s²
r ≥ 2528.0784 m²/s²/0.569 m/s²
r ≥ 4443.02 m
r ≥ 4.44 km
So, the the smallest radius of curvature for the track that the train can tolerate is 4.44 km
b. If there is a curve of radius 1.100 km, what speed must the train mantain to keep the acceleration at the limit?Using the equation for centripetal acceleration, we find the radius of the circle the train can tolerate.
So, centripetal acceleration a = v²/r where
v = speed of train and r = radius of curvature of track.What is the speed of the train?Making v subject of the formula, we have
v = √ar
Given that there is a curve of radius 1.100 km and its acceleration must not exceed 0.058g, we have that
r = 1.100 km = 1100 m and a = 0.058g = 0.058 × 9.81 m/s² = 0.569 m/s²So, substituting the values of the variables into the equation for r,we have
v = √ar
v = √(0.569 m/s² × 1100 m)
v = √(625.9 m²/s²)
v = 25.02 m/s
v ≅ 25 m/s
So, the speed must the train mantain to keep the acceleration at the limit is 25 m/s
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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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What happens to the molecules of a substance when it changes phase?
When it comes to phase shifts or phase change the greater the intermolecular interactions are the closer the molecules are to one another.
What is phase change?A phase change occurs when matter transitions from one state to another (solid, liquid, gas, plasma). When enough energy is provided to the system (or when a significant quantity is removed), as well as when the pressure on the system is adjusted, these changes occur.Any two phases of matter can undergo phase transitions.All phase shifts are accompanied by an energy shift.Isothermal phase shifts occur in all cases.Temperature changes can cause substances to change phase often. Most substances are solid at low temperatures; as the temperature rises, they become liquid; and at even higher temperatures, they become gaseous.To Know more about Phase change here
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6.
least 2 m. If the same car is moving with the speed 80K/h,what is the minimum stopping distance?
A car moving with a speed of 40 km/h can be stopped by applying the brakes after at-
The minimum stopping distance of the car is determined as 8 m.
What is the minimum stopping distance?The minimum stopping distance of the car is calculated as follows;
d = (u²)/(2a)
where;
d is the minimum stopping distanceu is the initial velocitya is the acceleration of the carwhen the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s
2 = (11.11²)/(2a)
a = (11.11²)/(2 x 2)
a = 30.86 m/s²
when the speed becomes 80 km/h, the minimum stopping distance is calculated as;
u = 80 km/h = 22.22 m/s
d = (22.22² )/ (2 x 30.86)
d = 8 m
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What is attachment?
a
bond between one person and another
b
physical closeness
c
regulation of emotions
d
seeing the world only through one's own eyes
Answer:
It depends I think it could be both a Bond between one person and another. And physical closeness
Explanation:
I would go with a though
Answer:
a, bond between one person and another
Explanation:
took the quiz
A cricketer lowers his hand while catching balls. Why?
Answer:
While catching a ball, a cricket player lowers his hands, because by doing so, he increases the time of catch. That is, the person increases the time to bring about a given change in momentum, and hence rate of change of momentum decreases. Thus, a small force is exerted by ball on the hands.
Explanation:
:)
Answer:
it is your answer....... if it is helpful plzz like and comment
Please help! Its due date is in 10 minutes!!
Answer:
the circle on left shows the needle to the right (north pole). the circle on the right shows the needle to the right again.
Explanation:
the needle always goes to north
A 550-g squirrel with a surface area of 945 cm2 falls from a 4.0-m tree to the ground. Estimate its terminal velocity. (Use the drag coefficient for a horizontal skydiver. Assume that the squirrel can be approximated as a rectanglar prism with cross-sectional area of width 11.6 cm and length 23.2 cm. Note, the squirrel may not reach terminal velocity by the time it hits the ground. Give the squirrel's terminal velocity, not it's velocity as it hits the ground.)
m/s
What will be the velocity of a 55.0-kg person hitting the ground, assuming no drag contribution in such a short distance?
m/s
The velocity of a 55.0-kg person hitting the ground, is mathematically given as
vt=39.5983m/s
What will be the velocity of a 55.0-kg person hitting the ground, assuming no drag contribution in such a short distance?Generally, the equation for is mathematically given as
mass of squirrel,
\(m=550 \mathrm{~g}\\\\Surface area, $A=945 \mathrm{~cm}^{2}=88 \times 10^{-3}$\\\\Height, $h-4 \mathrm{~m}$\\\)
Terminal velocity is given by:
\($v_{i}=\sqrt{\frac{2 m g}{\rho A C}}$\)
where \rho is the density of fluid that is falling and it is given by
\($\rho=\frac{m}{V}$\)
since, volume =area * height
\(^{\rho=} \frac{0.55 \mathrm{Kg}}{0.0945 \mathrm{~m}^{2} \times 4.0 \mathrm{~m}}\\\\$\rho=0.1455 \mathrm{Kg} / \mathrm{m}^{3}$\)
A is the surface area of squirrels.
C is the drag coefficient.
The surface area facing the fluid is given by:
\(A_{f}=\frac{0.0945 \mathrm{~m}^{2}}{2} \\\\\\ A_{f}=0.04725 \mathrm{~m}^{2}\)
so, terminal velocity is :
\($v_{t}=\sqrt{\frac{2 \times 0.55 \mathrm{Kg} \times 9.8 \mathrm{~m} / \mathrm{s}^{2}}{0.1455 \mathrm{Kg} / \mathrm{m}^{3} \times 0.04725 \mathrm{~m}^{2} \times 1}}$\)
Vt=39.5983
In conclusion, the terminal velocity of the squirrel is 39.5983m/s
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Blue light with a wavelength of 4.57 E-7 m is used in Young's experiment with the slits separated by a distance of 2.42 E-4Y
m. The screen is located at a distance from the slits of 4.5 m. Calculate the distance on the screen between the central
bright fringe and the first bright fringe. Show all work for full credit.
The distance between the central bright fringe and the first bright fringe on the screen is approximately 8.52E-3 meters.
In Young's double-slit experiment, the distance between the central bright fringe (m = 0) and the first bright fringe (m = 1) can be calculated using the following formula:
y = (m * λ * L) / d
where:
y is the distance between the fringes on the screen,
m is the order of the fringe (0 for the central bright fringe, 1 for the first bright fringe),
λ is the wavelength of the light,
L is the distance from the slits to the screen, and
d is the distance between the slits.
Given the values:
λ = 4.57E-7 m (blue light wavelength)
d = 2.42E-4 m (distance between the slits)
L = 4.5 m (distance from the slits to the screen)
For the central bright fringe (m = 0), the distance (y) is:
y = (0 * 4.57E-7 m * 4.5 m) / 2.42E-4 m
y = 0
Therefore, the central bright fringe coincides with the point where the two beams of light overlap.
For the first bright fringe (m = 1), the distance (y) is:
y = (1 * 4.57E-7 m * 4.5 m) / 2.42E-4 m
y ≈ 8.52E-3 m
This calculation demonstrates how the interference pattern in Young's experiment is formed, with bright and dark fringes being produced based on the constructive and destructive interference of the light waves from the two slits. The distance between these fringes depends on the wavelength of light, the separation of the slits, and the distance between the slits and the screen.
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I will give brainliest to whoever is first
Answer:
first
Explanation:
also wat u need help with
What is MOST likely to be TRUE about asynchronous communication?
It is rarely used in businesses in today's society.
It offers many opportunities to ask clarifying questions in real time.
It is helpful when employees work across multiple time zones.
It only works when all employees work in the same time zone.
The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.
Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.
Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.
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Which of these examples best illustrates Newton’s second law of motion
A a 100 lb boy has twice as much inertia as a 200 lb on boy.
B a truck need a more powerful engine then a small car.
C A hockey puck slides easily across the ice.
D A satellite stays in orbit for a long time.
Answer:
C )A hockey puck slides easily across the ice.
If is the current density and is a vector element of area then the integral over an area represents:Group of answer choicesthe resistivity of the areathe average current density at the position of the areathe resistance of the areathe electric flux through the areathe current through the area
Answer:
The average current density at the position of the area.
Explanation:
Current density is the vector whose magnitude is electric current in the cross sectional area. Current density is vector quantity which is measured in amperes. The average current density is dependent on the electric current flow. It has perpendicular direction of flow and scalar magnitude.
waves disturb a medium by causing the particles to_____.
Answer:
Oscillate
Explanation:
wave oscillates the particles of the medium around their equilibrium point.
consider the combination of two capacitor c1 and c2 with c2>c1,when connected in parallel,the equivalent capacitance is 8 times the equivalent capacitance of the same connected in series. calculate the ratio of capacitor c2/c1?
Explanation:
Current flowing through the circuit, I = 2A Applying Kirchoff’s Ist law at junction P, I = I1 + I2 I2 = I – I1 …(1) Applying Kirchoff’s Ind law at junction PQSP 5 I1 + 10 Ig – 15 I2 = 0 5 I1 + 10 Ig -15(I – I1) = 0 20 I1 + 10 Ig = 15 I 20 I1 + 10 Ig = 15 x 2 ÷ by 10 21 I1 + Ig = 3 … (2) Applying Kirchoff’s II law at junction QRSQ 10(I1 – Ig ) – 20(I – I1 – Ig ) – 10 Ig = 0 10 I1 – 10g – 20(I – I1 – Ig ) – 10 Ig = 0 10 I1 – 10 – 20 I + 20 I1 -20Ig – 10 Ig = 0 30 I1 – 40 Ig = 20 I ÷ by 10 ⇒ 3 I1 – 4 Ig = 20 I 3 I1 – 4 Ig = 2 I 3 I1 – 4 Ig = 2 x 2
hope this helps :)