Why does chlorophyll b appear yellow-green?

Copper class II connectors are designed to withstand a pull test of 890 newtons or 200 pounds of force. This test is performed to ensure that the connector can securely hold the wires or cables that it is intended to connect.

The pull test is conducted by applying a force perpendicular to the plane of the connector until it reaches the specified limit of 890 newtons. The connector should not break or come loose from the wires during the test. This test is important for ensuring the reliability and safety of electrical connections in various applications, including residential and industrial settings.
Copper Class II connectors are designed to be durable and reliable. They must withstand a pull test of 890 Newtons, which is equivalent to approximately 200 pounds-force (lbf). This requirement ensures the connectors maintain strong connections and provide consistent electrical conductivity, even under stress or tension.

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Answer:

B. Large atoms tend to have a low ionization energy and a low electron affinity.

Explanation:

Atomic radii can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).

Generally, atoms with relatively large atomic radii tend to have a low ionization energy and a low electron affinity. Ionization energy can be defined as the minimum energy required to remove or detach an electron from a neutral atom in a gaseous state. Electron affinity can be defined as the ability of an atom of a chemical element to accept or accommodate an electron.

The amount of heat absorbed when 182.7 g of Fe3O4 decomposes into Fe and O2 is 885.6 kJ.

The given chemical equation shows that the decomposition of 1 mole of Fe3O4 releases 1120.5 kJ of heat energy. To find the amount of heat absorbed when 182.7 g of Fe3O4 decomposes, we first need to determine the number of moles of Fe3O4 present.

The molar mass of Fe3O4 is:

(3 x atomic mass of Fe) + (4 x atomic mass of O) = (3 x 55.85 g/mol) + (4 x 16.00 g/mol) = 231.53 g/mol

The number of moles of Fe3O4 is:

182.7 g / 231.53 g/mol = 0.7894 mol

Now, we can use stoichiometry to calculate the amount of heat absorbed:

0.7894 mol Fe3O4 x (1120.5 kJ / 1 mol Fe3O4) = 885.6 kJ

Decomposition is a type of chemical reaction in which a single compound breaks down into two or more simpler substances. This reaction can occur through various processes, such as heating, exposure to light, or addition of a catalyst.

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Answer:

(D)=1.16g

Explanation:

Answer:

D) 1.16 g

I'm not sure about answer ..

Arachnids lack antennae. The main differences between insects and arachnids are in their body structure and legs.

Both insects and arachnids are multi-legged creatures that tend to elicit fear, and while they have a lot in common, including that fear response, there are some distinct differences between the two.

The main differences between insects and arachnids are in their body structure and legs.

Arachnids have eight legs, whereas insects only have six. Arachnids have simple eyes, whereas insects have compound eyes. Arachnids lack antennae while insects do.

Therefore, Arachnids lack antennae. The main differences between insects and arachnids are in their body structure and legs.

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Answer: A.

Explanation:

Brownian motion is the random motion of a particle as a result of collisions with surrounding gaseous molecules. Diffusiophoresis is the movement of a group of particles induced by a concentration gradient. This movement always flows from areas of high concentration to areas of low concentration.

Example:  The movement of pollen grains on still water. Motion of dust motes in a room (though largely influenced by air currents).

Answer:

12.5

1.95x10^-10

1.5

0.5

in that order

Explanation:

1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper. The balanced chemical equation for the reaction of copper with silver nitrate (use cu2) is as follows: Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

To determine how many grams of silver can be produced from 1.40 g of silver nitrate and excess copper, we first need to calculate the limiting reactant.

The stoichiometry of the reaction is such that 2 moles of silver nitrate react with 1 mole of copper to produce 2 moles of silver. The molar mass of silver nitrate is 169.87 g/mol while that of copper is 63.55 g/mol,

therefore, the number of moles of silver nitrate present in 1.40 g can be calculated as follows:Number of moles of silver nitrate = mass/molar mass= 1.40/169.87= 0.008240 molSimilarly, the number of moles of copper required to react with this quantity of silver nitrate is 0.004120 mol (half of the number of moles of silver nitrate).

Since there is an excess of copper, it will not limit the reaction and hence the limiting reactant is silver nitrate.To calculate the mass of silver produced, we use the molar mass of silver, which is 107.87 g/mol.Mass of silver produced = number of moles of silver x molar mass= 0.01648 x 107.87= 1.78 g

Therefore, 1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper.

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Some common protic solvents used in SN1 reactions include water, alcohols, and carboxylic acids.

In organic chemistry, SN1 reactions are a type of substitution reaction that occurs in a protic solvent.

A protic solvent is a solvent that has a hydrogen atom bonded to an electronegative atom, such as oxygen or nitrogen. This allows the solvent to form hydrogen bonds with the reactants and stabilize the transition state of the reaction.

These solvents are able to stabilize the carbocation intermediate that is formed during the reaction, which helps to increase the reaction rate.

It is important to note that the choice of solvent can have a significant impact on the rate and outcome of the reaction. For example, a polar protic solvent like water will favor the SN1 reaction, while a polar aprotic solvent like acetone will favor the SN2 reaction.

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The elements in group IA are called alkali metals. The elements in group IIA are called alkaline earth metals. The elements in group VIIA are called the halogens and the elements in group VIIA are called the noble gases or inert gases.

Because, like all other group 1A elements, it has eight valence electrons. Like all other Group 1A elements, it has only one valence electron. The reason why hydrogen can be classified in both Group 1 and Group 17 is that hydrogen can easily form cations, making some of its properties similar to alkali metals.

Although it can be placed in Group 1 of the periodic table, its properties differ from those of halogens because hydrogen is a non-metal and forms H2, which is the true property of halogens, being placed above the group of the periodic table. is also similar. The ns1 electrons are arranged like alkali metals. However, it differs significantly from alkali metals in that it is less likely to form cations H+ than other alkali metals.

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Answer:

See below.  

Explanation:

1. Newton's first law

(a) Problem 1

What is the net force required to keep a 500 kg object moving with a constant velocity of 10 m·s?

Answer: None.

Explanation: An object in motion stays in motion unless a net force acts on it.

The object will keep moving at 10 m/s.

(b) Problem 2

A force of 20 N acts on a 10 kg object from the left. A force of 30 N acts on it from the right. What is the net force required to keep the object moving with a constant velocity of 10 m/s?

Answer: 20 N

Explanation:  

The net force is

30 N - 20 N = 10 N

You must apply another 10 N from the left. The net force is then:  

30 N - 30 N = 0

If there is no net force, the object will keep moving at 10 m/s.

2. Newton's second law

(a) Problem 1

What is the net force needed to accelerate an object at a constant 5 m·s⁻²?

Answer: 5 N

Explanation:

F = ma = 1 kg × 5 m·s⁻² = 5 kg·m·s⁻² = 5 N

(a) Problem 2

A net force of 2 N acts on a 1 kg object.  What is the magnitude and direction of the acceleration?

Answer: 2 m·s⁻²

Explanation:

F = ma

2 N = 1 kg × a

a = (2 N)/(1 kg) = (2 kg·m·s⁻²\1 kg) = 2 m·s⁻²

The direction of the acceleration is the same as that of the applied force.

2. Newton's third law

(a) Problem 1

A person with a mass of 58 kg is standing near you. Diagram and calculate the opposing forces.

Answer: 570 N up and down

Explanation:

See Fig. 1.  The person's mass exerts a downward force on the floor.

F = mg, where g is the acceleration due to Earth's gravity

F = 58 kg × 9.8 m·s⁻² = 570 kg·m·s⁻² = 570 N

The floor exerts an upward force of 570 N.

(a) Problem 2

A teacher (mass 65 kg) pushes a cart (mass = 12 kg) of equipment (mass = 7 kg). Her foot applies a force of 150 N backward on the floor against a frictional force of 24 N. Diagram the opposing forces and calculate the net force available to move the cart.

Answer: 126 N

Explanation:

See Fig. 2 below. The teacher's mass exerts a downward force W on the floor, which exerts an equal reaction force R upward. The cart and equipment also exert a downward force on the floor, which exerts the same force upward. We can ignore these forces because they do not contribute to forward motion.

The teacher's foot exerts a backward force of 150 N on the floor, which exerts an equal force forward. However, a frictional force of 24 N opposes the forward force.

The net external force is the force of the floor minus the opposing frictional force. Thus,

F = 150 N − 24 N = 126 N

Amino acids are amphoteric, meaning that they can act as both acids and bases.

The building blocks of proteins are amino acids, which are the chemical compounds that come together to make proteins. These biomolecules are essential for human growth and development and are engaged in a number of biological and chemical processes in the body. In nature, there are around 300 amino acids.

Amino acids are amphoteric, meaning that they can act as both acids and bases. They have both an acidic carboxyl group (-COOH) and a basic amino group (-NH₂) in their structure. In a low pH environment, the amino acid will donate a proton from the amino group, becoming positively charged. In a high pH environment, the carboxyl group will lose a proton, becoming negatively charged. At a certain pH, called the isoelectric point, the amino acid will have no net charge because the acidic and basic groups will be equally protonated and deprotonated.

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Answer:  Thus mass of products is 177.2 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical reaction is:

\(AgNO_3+NaCl\rightarrow NaNO_3+AgCl\)

mass of silver nitrate \((AgNO_3)\) = 124.31 g

mass of sodium chloride \((NaCl)\) = 52.89 g

mass of reactants = mass of silver nitrate \((AgNO_3)\) +

mass of sodium chloride  \((NaCl)\) = 124.31 g + 52.89 g = 177.2 g

Thus mass of products = mass of reactants = 177.2 g

The potential temperature is 15°C.

Given,The temperature of some air is minus 20 degrees C at 95 kPa of pressure.

Reference pressure at sea level = 101.3 kPa

The potential temperature (θ) is the temperature a parcel of dry air would have if it were adiabatically brought to a standard reference pressure, typically 1000 millibars (100 kPa).

Potential temperature is directly proportional to the absolute temperature and inversely proportional to the pressure in a system.

In order to find the potential temperature of the given air, we can use the formula below:

θ = T × (P0 / P)^(R/cp)

where,θ = potential temperature (in Kelvin)

T = temperature (in Kelvin)

P0 = reference pressure (in Pa)

P = actual pressure (in Pa)

R = gas constant for dry air (287 J/(kg·K))

cp = specific heat of dry air at constant pressure (1004 J/(kg·K))

Converting the given temperature in Celsius to Kelvin:

T = -20°C + 273.15K= 253.15K

The formula can be written as:

θ = T × (P0 / P)^(R/cp)θ

= 253.15 × (101300/95000)^(287/1004)θ

= 288.5 K

Converting the potential temperature from Kelvin to Celsius:

θ = 288.5 K - 273.15

= 15.35°C (to the nearest degree)'

= 15°C (rounded off to the nearest degree).

Therefore, the potential temperature is 15°C.

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Answer:

The reaction shifts to the left.

Explanation:

Equilibrium constant (K) = 46.3

Reaction Quotient (Q) = 525

The relationship between Q and K with their implications are given as;

K = Q (No net reaction)

K > Q (Reaction shifts to the right)

K < Q (Reaction shifts to the left)

Since in this question, Q (525) > K (46.3)

The reaction shifts to the left.

Alkenes are hydrocarbons that contain a double carbon bond, whereas alkanes are hydrocarbons that only have single carbon-carbon bonds.

The reason why alkenes are more reactive than alkanes is that the double bond has a very high electron density in comprarison to the single bond of the alkanes. This double bond is made up of one very strong σ bond and a weak π bond.

So generally alkenes react breaking the π bond.

Answer:

A uniform temperature distribution is a MACROscopic property where the temperature is measured to be the same throughout the volume measured. An ideal gas with a uniform temperature distribution would have a Bellman distribution of kinetic energy of microscopic particles.

Explanation:

I am walter white

The name of an aqueous solution of HBr (hydrobromic acid) is simply HBr(aq).

An aqueous solution refers to a solution in which water is the solvent, and in this case, HBr is the solute. Hydrobromic acid, which has the formula HBr, is a strong acid that can dissolve in water to form H+ and Br- ions. When HBr is dissolved in water, the resulting solution is acidic due to the presence of these ions. It is important to note that the acidity of the solution will depend on the concentration of HBr in the solution. Therefore, the pH of an aqueous solution of HBr will vary based on the concentration of the solution.

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Answer: group 1A (or IA)

Explanation:

The D-Aldo triose is a type of sugar molecule that belongs to the family of trioses, which are three-carbon sugars. There are two possible stereoisomers of Aldo triose: D-Aldo triose and L-Aldo triose. D-Aldo triose has all three hydroxyl groups (-OH) on the same side of the carbon chain, while L-Aldo triose has them on alternating sides.

To check all D-Aldo triose, we need to consider the stereochemistry of each possible Aldo triose molecule. There are two D-Aldo triose isomers: D-glyceraldehyde and D-erythrose. D-glyceraldehyde has a -CHO group (aldehyde group) at one end of the carbon chain and a -CH2OH group (hydroxymethyl group) at the other end. The remaining carbon has a -OH group attached. This gives D-glyceraldehyde the chemical formula C3H6O3. D-erythrose has two -OH groups and one -CHO group, with the -CHO group at one end of the carbon chain and the two -OH groups at the other end. This gives D-erythrose the chemical formula C4H8O4. Therefore, to check all D-aldotriose, we need to examine the chemical structures of D-glyceraldehyde and D-erythrose and verify that they meet the criteria for being D-aldotriose isomers. Once we have confirmed their stereochemistry, we can conclude that these are the only two D-Aldo triose isomers that exist.

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Answer:

5232.5J

Explanation:

Data obtained from the question. This includes the following:

Mass (M) = 250g

Initial temperature (T1) = 30°C

Final temperature (T2) = 25°C

Change in temperature (ΔT) = T1 – T2 = 30°C – 25°C = 5°C

Specific heat capacity (C) = 4.186J/g°C

Heat (Q) =.?

The heat released can be obtained as follow:

Q = MCΔT

Q = 250 x 4.186 x 5

Q = 5232.5J

Therefore, the heat released is 5232.5J

The amount of heat released when the bottle (250g) of water is cooled  is 5232.5J .

Given data:-

Mass (M) = 250g

Initial temperature (T1) = 30°C

Final temperature (T2) = 25°C

Change in temperature (ΔT) = T1 – T2 = 30°C – 25°C = 5°C

Specific heat capacity (C) = 4.186J/g°C

Heat (Q) =.?

The heat released can be obtained as follow:

\(Q = MC\delta T\\\\Q = 250\times 4.186 \times 5\\\\Q = 5232.5J\)  

 Therefore, the heat released is 5232.5J.

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B. Einsteinium

Transuranium elements are the elements after the number 92 in the periodic table.

Answer:

Definite shape: S

Definite volume: S L

Takes shape of container: L G

Particles slide past one another: L

Particles vibrate in place: S

Particles move randomly and fast: G

Explanation:

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The mass of the precipitate, BaSO₄ obtained from the given reaction is 18.64 grams

Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.3

Mole of Na₂SO₄ = 0.09 mole

Mole = Molarity x Volume

Mole of BaCl₂ = 0.4 × 0.2

Mole of BaCl₂ = 0.08 mole

Balanced equation

Na₂SO₄(aq) + BaCl₂(aq) —> BaSO₄(s) + 2NaCl(aq)

From the balanced equation above,

1 mole of BaCl₂ reacted with 1 mole of Na₂SO₄.

Therefore,

0.08 mole of BaCl₂ will also react with 0.08 mole of Na₂SO₄.

From the above illustration, we can see that only 0.08 mole of Na₂SO₄ out of 0.09 mole given is neede to react completely with 0.08 mole of BaCl₂.

Therefore, BaCl₂ is the limiting reactant

Balanced equation

Na₂SO₄(aq) + BaCl₂(aq) —> BaSO₄(s) + 2NaCl(aq)

From the balanced equation above,

1 mole of BaCl₂ reacted to produce 1 mole of BaSO₄.

Therefore,

0.08 mole of BaCl₂ will also react to produce 0.08 mole of BaSO₄.

The mass of BaSO₄ can be obtained as follow

Mass = mole × molar mass

Mass of BaSO₄ = 0.08 × 233

Mass of BaSO₄ = 18.64 g

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Answer: 1.215 × 10^4  i think

Explanation:

Answer:

Structurally, plant and animal cells are very similar because they are both Eukaryotic cells. They both contain membrane-bound organelles such as the nucleus, mitochondria, endoplasmic reticulum, golgi apparatus, Iysosomes and peroxisomes. Plant cells can be larger than animal cells.

Explanation:

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