Why does a siren have a lower pitch as it moves away? ( I need a answer quick !)
A) The amplitude of the sound wave is increased
B) The period of the sound wave is decreased
C) The crests of the sound are farther apart
D) The troughs of the sound wave are spaced closer together

According to Newton's third law of motion, the reaction force exerted by the air on the balloon is equal in magnitude but opposite in direction to the action force exerted by the balloon on the air.

Given that the magnitude of the action force (F_balloon) is -3 N, the magnitude of the reaction force (F_air) will also be 3 N. The negative sign indicates that the forces are in opposite directions, but when considering magnitudes, we ignore the negative sign.

Therefore, the magnitude of the reaction force of the air pushing on the balloon is 3 N.

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Arches, Quintuplet, and GC are not names given to extinct asteroids, galactic dust balls, or supermassive black holes. Instead, they are examples of names given to live massive star clusters. The correct option is D

Astronomers have identified these star clusters in various regions of our galaxy. The Arches cluster is located near the center of the Milky Way, while the Quintuplet cluster is found in the same vicinity.

These clusters are comprised of young, massive stars that emit intense radiation and are surrounded by dense clouds of gas and dust.

GC stands for "globular cluster," and it refers to a densely packed spherical collection of stars found in the galactic halo.

These star clusters are fascinating subjects of study for astronomers, as they provide insights into the formation and evolution of stars in our galaxy.

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Answer: 1.2 x 10^7kg

Explanation:

Volume of tank = length x width x height

Volume = 51 x 20 x 11

Volume = 11220 m^3

Density = Mass/Volume

Density = 1030 kg/m^3

Volume = 11220 m^3

Mass = m

1030 = m/11220

m = 1030 x 11220

m = 11,556,600 kg or 1.2 x 10^7kg

Answer:

c. aluminum foil

Explanation:

Reflection is defined as the returning of light or sound wave from a surface at certain angles. For example: our image in the mirror.

To reflect light, we required a surface with one side completely polished, smooth and pure form so that it reflects maximum light rather than absorbing the light. Aluminum foil will reflect the most light from the given options. Aluminum foil has the purity and surface smoothness that makes it able to reflect maximum light. Any change in the smoothness of the aluminum foil, the reflectivity of light will decrease.

Other option a clear window, a green plastic bottle and a red lunch box will absorb more light rather than refect it.

Hence, the correct option is "c. aluminum foil ".

a) The power factor of the circuit is 0.75.

b) A capacitive load of approximately 136.42 kVARs is needed to improve the power factor to 0.95 lagging.

a) To decide the power factor (PF) of the circuit, we can utilize the data given by the ammeter (current) and the voltmeter (voltage). The power factor is the cosine of the stage point between the current and voltage waveforms.

The recipe to work out power factor is PF = P/(|V| * |I|), where P is the dynamic power in watts, |V| is the greatness of voltage in volts, and |I| is the extent of current in amperes. Utilizing the given qualities: P = 1350 W, |V| = 120 V, and |I| = 15 A, we can compute the power factor as follows: PF = 1350/(120 * 15) = 0.75.

b) To further develop the power element to 0.95 slacking, we want to acquaint a capacitive burden with make up for the slacking receptive power in the circuit.

The receptive power is given by the recipe Q = P * tan(θ), where Q is the responsive power, P is the dynamic power, and θ is the stage point. Since the power factor is slacking (under 1), the stage point θ is positive.

The recipe for the necessary responsive ability to accomplish the ideal power factor is Q = P * (tan(θ1) - tan(θ2)), where θ1 is the underlying stage point and θ2 is the ideal stage point. Given P = 1350 W and θ1 = acos(PF1) = acos(0.75), we can ascertain Q utilizing the equation.

Then, Q = 1350 * (tan(acos(0.75)) - tan(acos(0.95))) ≈ 136.42 VAr. Since the necessary receptive power is positive, we want a capacitive burden to give - 136.42 VAr (kvars) to further develop the power element to 0.95 slacking.

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Answer:

t = S / V = 3.8E8 / 3E8 = 1.3 sec

It takes over 1 second for a radio signal to travel between the earth and the moon.

Answer:

differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.

Explanation:

This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.

Answer:

3.3×10⁻⁹ kg/s

Explanation:

There are two forces on the particle: weight force pulling down and drag force pushing up.  At terminal velocity, the speed is constant, so the acceleration is zero.

∑F = ma

bv − mg = 0

b = mg / v

b = (10⁻¹³ kg) (9.8 m/s²) / (3×10⁻⁴ m/s)

b = 3.3×10⁻⁹ kg/s

a) 4.9 m

b) 38.3 m/s

c) 33.4 m

The three equations are,

v = u + at

v² = u² + 2as

s = ut + ½at²

According to the question,

Let hold the y-axis in the direction of gravity.

Initial velocity 0 = 0 /,

Initial height ℎ0 = 0 , and finish height ℎ = 75.0

gravitational acceleration = 9.8 /²

a) Determine the distance traveled during the first second.

By third equation of motion

\(S_{0} = v_{0} t +\frac{1}{2} gt^{2}\)  where \(v_{0}\) =0

then \(S_{0} = \frac{gt^{2}}{2} = \frac{9.8*1^{2} }{2} = 4.9 m\)

b) Determine the final velocity at which the object hits the ground

let – velocity of object, when it falling to the ground

– moment falling to the ground, and obtain from condition:

ℎ = ℎ() = 75.0

\(v_{f} = v_{0} +gt = gt\)

\(h (t_{f} ) = \frac{gt^{2} }{2} = 75.0 m\\t_{f} =\sqrt{\frac{2h_{f} }{g} } \\v_{f}= gt = g \sqrt{\frac{2h_{f} }{g} } =\sqrt{2hg_{f} }= =\sqrt{2*9.8*75.0} = 38.3 m/s\)

c) Determine the distance traveled during the last second of motion before hitting the ground.

From the above equation we get,

\(\sqrt{2*75*9.8*1} - \frac{9.8*1^{2} }{2} = 38.3 -4.9 = 33.4 m\)

Therefore,

a) 4.9 m is the distance traveled during the first second.

b) 38.3 m/s is the final velocity at which the object hits the ground

c) 33.4 is the distance traveled during the last second of motion before hitting the ground.

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Answer:

Rachels car moves and ashleys stops

Explanation:

When Ashley's moving car collides with Rachel's bumper car which is at rest then some of the momentum of Ashley's car is transferred to Rachel's car causing it to move.

Conservation of momentum states that the momentum of a system is constant if there is the absence of external forces on the system. The momentum of an object can be conserved and is a vector quantity.

Momentum can be defined as the multiplication of the mass of a particle and its velocity. The law of conservation of momentum is confirmed by experiment and can be deduced mathematically on the presumption that space is uniform.

Conservation of linear momentum is derived from Newton’s second law of motion states that the total momentum remains the same in an isolated system.

The total momentum of  Ashley's car and Rachel's car remains conserved. After the collision, the momentum transferred from  Ashley's car and Rachel's car which makes it move.

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Answer: Different types of fuels have varying compositions and release different amounts of pollutants when burned. Here are some common types of fuels and the pollutants associated with them:

Fossil Fuels:

a. Coal: When burned, coal releases pollutants such as carbon dioxide (CO2), sulfur dioxide (SO2), nitrogen oxides (NOx), and particulate matter (PM).

b. Petroleum (Oil): Burning petroleum-based fuels like gasoline and diesel produces CO2, SO2, NOx, volatile organic compounds (VOCs), and PM.

Natural Gas:

Natural gas, which primarily consists of methane (CH4), is considered a cleaner-burning fuel compared to coal and oil. It releases lower amounts of CO2, SO2, NOx, VOCs, and PM.

Biofuels:

Biofuels are derived from renewable sources such as plants and agricultural waste. Their environmental impact depends on the specific type of biofuel. For example:

a. Ethanol: Produced from crops like corn or sugarcane, burning ethanol emits CO2 but generally releases fewer pollutants than fossil fuels.

b. Biodiesel: Made from vegetable oils or animal fats, biodiesel produces lower levels of CO2, SO2, and PM compared to petroleum-based diesel.

Renewable Energy Sources:

Renewable energy sources like solar, wind, and hydropower do not produce pollutants during electricity generation. However, the manufacturing, installation, and maintenance of renewable energy infrastructure can have environmental impacts.

It's important to note that the environmental impact of a fuel also depends on factors such as combustion technology, fuel efficiency, and emission control measures. Additionally, advancements in clean technologies and the use of emission controls can help mitigate the environmental impact of burning fuels.

When a block with a mass of 3.8 kg is compressed against a spring with a spring constant of 17555 N/m, and placed on an inclined plane with an angle of 18 degrees, it will slide up the plane a certain distance.

The compressed spring stores potential energy, which is converted into kinetic energy as the block slides up the inclined plane. The work done against gravity during this upward motion can be calculated using the formula:

Work = Force × Distance × cos(θ)

In this case, the force is the component of the gravitational force acting parallel to the plane, which is given by m × g × sin(θ). By equating the work done against gravity to the potential energy stored in the spring, the distance the block will slide up the plane can be determined. The specific calculation involves manipulating the equations and substituting the given values, resulting in the final distance traveled by the block.

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Kepler used data to derive laws of planetary motion that confirmed Copernicus's heliocentric theory, but that showed the orbits were elliptical is the build upon the foundation established by copernicus. Option A is a correct option.

Kepler built upon the foundation established by Copernicus by using data to derive laws of planetary motion that confirmed Copernicus's heliocentric theory, but that showed the orbits were elliptical.

In other words, Kepler's work refined the model of Copernicus's heliocentric theory by describing planetary motion as elliptical instead of circular.

Kepler's contribution to astronomy was significant as it allowed for more accurate predictions of planetary motion, including the speed and distance of each planet's orbit.

Kepler's work was the first to include a precise understanding of the movement of the planets, and it laid the groundwork for future developments in astronomy.

In conclusion, Kepler built upon the foundation established by Copernicus by using data to refine the model of the heliocentric theory and derive laws of planetary motion.

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Question:-

how did kepler build upon the foundation established by copernicus?

A. kepler used data to derive laws of planetary motion that confirmed copernicus's heliocentric theory, but that showed the orbits were elliptical.

B. kepler observed the heavens and proved that planetary motion was circular around the sun. kepler discovered the three laws of thermodynamics.

C. kepler used magic to prove that the earth moved in a manner based on geometric figures, trying to bring harmony of the human soul into alignment with the universe.

D. kepler demonstrated that the motion of the planets is steady and unchanging.

The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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The correct answer is: object A must have a higher average internal kinetic energy than object B to have a higher absolute temperature.

To understand which of the given options would make object A have a higher absolute temperature than object B, we first need to understand what temperature is and how it is related to the properties of an object.

Temperature is a measure of the average internal kinetic energy of the particles in an object. The greater the average internal kinetic energy, the higher the temperature. So, to have a higher temperature than object B, object A must have a higher average internal kinetic energy.

Now let's consider the given options:

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Answer:

some of the energy is transformed to thermal energy

Answer:

some of the energy transforms to thermal energy

Explanation:

Answer:

v = -5 m/s

Explanation:

It is given that,

The initial velocity of the ball, u = 25 m/s

We need to find its velocity after 2 seconds in the air.

Let v is the velocity of the ball after 2 seconds. Using equation of motion to find it.

v = u + at

Here, a = -g

v = u -gt

Putting all the values,

v = 25 - (10)(3)

= 25-30

= -5 m/s

So, the velocity of the ball after 3 seconds is 5 m/s and it is in downward direction.

The radius of the axon must increase by a factor of 121 to increase the speed of the pulse by a factor of 11.

To find the factor by which the radius of the axon must increase to increase the speed of the pulse by a factor of 11, we will use the formula you provided:
λ ≈ √(rhom * r) / 2 * rhoa
Since the speed of the pulse is proportional to λ, we can set up a ratio:
λ₁ / λ₂ = Speed₁ / Speed₂
Given that Speed₂ = 11 * Speed₁, we can substitute and solve for the radius:
(√(rhom * r₁) / (2 * rhoa)) / (√(rhom * r₂) / (2 * rhoa)) = 1 / 11
Simplify and solve for r₂:
√(r₁ / r₂) = 1 / 11
Square both sides:
r₁ / r₂ = 1 / 121
Since we want the factor by which the radius must increase, we will solve for r₂ / r₁:
r₂ / r₁ = 121
So, the radius of the axon must increase by a factor of 121 to increase the speed of the pulse by a factor of 11.

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Answer:

the final velocity of the car after 6 seconds of acceleration is 30 m/s.

Explanation:

The final velocity of the car can be found using the kinematic equation:

v = u + at

where u is the initial velocity (which is zero since the car starts from rest), a is the acceleration (which is 5 m/s^2), t is the time elapsed (which is 6 seconds).

Substituting the given values, we get:

v = 0 + 5 x 6

Answer:

Tornadoes

A tornado is a violently rotating column of air that is in contact with both the surface of the Earth and a cumulonimbus cloud or, in rare cases, the base of a cumulus cloudExplanation:

Answer:

The frequency of the wave is 5 Hz (Hertz), which means it oscillates or cycles 5 times in one second.

Explanation:

The frequency of a wave is the number of times the wave oscillates or cycles in a given period of time. The period of a wave is the time it takes for the wave to complete one cycle.

The period of the wave is given as 0.2 seconds. To calculate the frequency, we can use the formula:

Frequency (f) = 1 / period (T)

So in this case:

f = 1 / 0.2 seconds

The frequency of the wave is 5 Hz (Hertz), which means it oscillates or cycles 5 times in one second.

Formula for frequency:

\(f=\dfrac{1}{T}\)

frequency(measured in Hertz) = 1 / period(measured in seconds)

__________________________________________________________

Given:

\(T=0.2s\)

\(f=?\)

__________________________________________________________

Finding frequency:

\(f=\dfrac{1}{T}\)

\(f=\dfrac{1}{0.2}\)

__________________________________________________________

Answer:

\(\fbox{f = 5 Hertz}\)

The angular speed of the planet is 1.33 x 10^-7 rad/s. The angle through which the planet will revolve in one Earth year is 0.055 degrees. The distance between the planet and its star is 1.5 x 10^11 km.

the angular acceleration of the disk is 0.0966 rad/s. The time it takes to stop is 5866 seconds.

(a) To find the angular speed of a planet, one can use the formula:

w = v/rwhere, w = angular speed of the planet v = linear speed of the planet r = distance of the planet from the center of its stara.

In this question, the linear speed of the planet is 20 km/s, and the planet revolves around its star every 1.5 years.

Therefore, the distance traveled by the planet in one revolution is given by:

d = vt where, d = distance traveled in one revolution t = time taken for one revolution v = linear speed of the planet

Therefore, d = 20 km/s x 1.5 x 365 days/year x 24 hours/day x 3600 s/hour d = \(9.46 \times 10^{11}\) km

The distance between the planet and its star is unknown, and we need to find it to calculate the angular speed of the planet.

However, we know that the distance traveled by the planet in one revolution is equal to the circumference of the orbit.

Therefore, we can write,2πr = d where, r = distance between the planet and its star\(2$\pi$r = 9.46 \times 10^{11}\) km r = \(1.5 \times 10^{11}\)km

Substituting the values of v and r in the formula for the angular speed, we get, w = v/r w = \((20 \times 10^3 m/s)/(1.5 \times 10^{11} m)w = 1.33 \times 10^{-7}\) rad/s

Therefore, the angular speed of the planet is \(1.33 \times 10^{-7 }\)rad/s.

(b) In one Earth year, the planet will complete only a fraction of its orbit.

We need to find the angle through which the planet will revolve in one Earth year.

This angle is given by:θ = (360 degrees/revolution) x (time for one revolution)/(time for one Earth year)θ = (360 degrees)/(1.5 x 365 days/year)θ = 0.055 degrees

Therefore, the angle through which the planet will revolve in one Earth year is 0.055 degrees.

(c) The distance between the planet and its star is \(1.5 \times 10^{11}\) km.

(a) The initial angular velocity of the disk is zero, and the final angular velocity is also zero.

The disk turns through 12 revolutions before coming to a stop. We need to find the angular acceleration of the disk and the time it takes to stop.

b. The angular displacement of the disk is given by:

θ = (2π) x (number of revolutions)θ = (2π) x (12)θ = 75.4 degrees

The final angular velocity of the disk is zero, and the initial angular velocity is given by:w0 = (2π x 5400)/60w0 = 566.37 rad/s

The final time is unknown, and we need to find it to calculate the angular acceleration.

However, we know that the final angular velocity is zero, and we can use the following formula to calculate the final time: w = w0 + at where, w = final angular velocityw0 = initial angular velocity a = angular acceleration t = time

Substituting the values of w, w0 and θ, we get:0 = 566.37 + a x tt = -566.37/a

We can use the formula, s = ut + (1/2)at 2 where, s = angular displacement u = initial angular velocity t = time a = angular acceleration

Substituting the values of s, u, t, and θ, we get:75.4 = (566.37 x -566.37/a) + (1/2) a (-566.37/a)2

Simplifying the equation, we get:

a = 0.0966 rad/s2

Therefore, the angular acceleration of the disk is 0.0966 rad/s2.

The time taken for the disk to stop is given by :t = -566.37/a = -566.37/0.0966 = 5866 seconds

Therefore, the time it takes to stop is 5866 seconds.

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The exact length of the curve is 105.98.

First, we will use the formula to find the arc length of the curve which is given as:
`L = int_a^b sqrt[1 + (dy/dx)^2]dx`
Here, `a = 0` and `b = 2`. Therefore, we can write:
`L = int_0^2 sqrt[1 + (dy/dx)^2]dx`
We will now find `dy/dx` by differentiating `x` and `y` with respect to `t`.
`x = et − 4t`
Therefore, `dx/dt = e^t - 4`.
`y = 8et⁄2`
Therefore, `dy/dt = 4e^t`.
We can now write `dy/dx` as `dy/dt * dt/dx`. This gives us:
`dy/dx = dy/dt * dx/dt^-1 = 4e^t / (e^t - 4)`
We can now substitute this value into the formula for `L` to obtain:
`L = int_0^2 sqrt[1 + (4e^t / (e^t - 4))^2]dx`
After integrating and simplifying, we get:
`L = (1/2) [5e^2 - 2 ln(2e^2 - 4) - 5]`
Evaluating this expression, we get `L = 105.98` (approx).

Therefore, the exact length of the curve is 105.98.

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Answer:

Telescope, Probware, etc,..

Answer: probeware

Explanation:

the answer is probeware

if you mean by the options,

A. a ruler

B. a thermometer

C. a beaker

D. probeware

Answer:

208.33 W

Explanation:

Using,

P = W/t.......................... Equation 1

P = Average power output, W = total work, t = total time.

From the question,

Given: W = 6000000 J, t = 8 hours = (8×60×60) = 28800 s

Substitute these values into equation 1

P = 6000000/28800

P = 208.33 W.

Hence the average power output is 208.33 W

The properties of light is option a wavelength.

It is the distance between the points of two consecutive waves. It is usually denoted by the Greek letter lambda (λ), and it is equal to the speed (v) of a wave train in a medium divided by its frequency (f): λ = v/f.

So based on the above information, the a option is correct.

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The combined mass of the package and the sled is 96.75 kg (A).