Why does a feather drift back and forth as it falls ?

(I’m confused I think it has something to do with terminal velocity though in my mind)

Answers

Answer 1

Answer:

you are very most correct

Explanation:

it does have something to do with terminal velocity and because the weight is so light of it any tiny gust of wind can push it back and forth and because wind is never stable thats why it moves side to side


Related Questions

Energy is not
1. a scalar.
2.operationally defined.
3.measured in joules.
4.created or destroyed.

Answers

Explanation:

think4

pleas! mark me s brainliest please please

I think 4 is correct

A characteristic of a substance?

Answers

A substance could have physical characteristics and chemical ones too, which are unique to the certain substance.

Color, odor, and how hard the substance, are all examples of physical characteristics of a substance.

Toxicity, flammability, and acidity, are all examples of chemical characteristics of a substance.

The characteristic properties of a substance are always the same whether the sample being observed is large or small. Examples of characteristic properties include freezing/melting point, boiling/condensing point, density, viscosity, and solubility.

An antique coin is a mixture of silver and copper. The coin has a mass of 1.155 10-2 kg and in water weighs 0.1011 N. Determine the mass of silver in the coin. Use 1.05 104 kg/m3 as the density of silver, 8.89 103 kg/m3 as the density of copper, and 1000 kg/m3 as the density of water.

Answers

The mass of silver in the coin is approximately 4.66 × 10⁻³ kg or 4.66 g. Hence, this is the answer.

An antique coin is a mixture of silver and copper.

The coin has a mass of 1.155 × 10⁻² kg and in water weighs 0.1011 N.

We need to determine the mass of silver in the coin.

The density of silver, the density of copper, and the density of water are

1.05 × 10⁴ kg/m³, 8.89 × 10³ kg/m³, and 1000 kg/m³, respectively.

The mass of the coin in air is given as: 1.155 × 10⁻² kg

The weight of the coin in water is given as: 0.1011 N

Let's determine the volume of the coin in terms of its weight in water.

The volume of water displaced is equal to the volume of the coin.

The density of water = 1000 kg/m³

Weight of coin in air - Weight of coin in water = Weight of water displaced (Archimedes principle)

So, we have

Weight of coin in air = 1.155 × 10⁻² kg

Weight of water displaced = 0.1011 N/9.8 m/s² = 0.0103 kg

Weight of coin in water = 0.1011 N/9.8 m/s² = 0.0103 kg

Thus, the volume of the coin is:

V = (Weight of water displaced) / (Density of water)

V = 0.0103 / 1000

V = 1.03 × 10⁻⁵ m³

Now, let's determine the mass of silver in the coin.

Let the mass of silver in the coin be m1 and the mass of copper in the coin be m2.

The total mass of the coin is:

m = m1 + m2

The total volume of the coin is:

V = V1 + V2

where V1 and V2 are the volumes of silver and copper in the coin, respectively.

V1 = (m1 / ρ1) and

V2 = (m2 / ρ2)

where ρ1 and ρ2 are the densities of silver and copper, respectively.

Substituting values, we have:

m = m1 + m2 ...(i)

V = [(m1 / ρ1) + (m2 / ρ2)] ...(ii)

We have

V = 1.03 × 10⁻⁵ m³

ρ = (m1 / V1) + (m2 / V2)

Substituting values, we get

1.05 × 10⁴ = [(m1 / V1) + (m2 / V2)] ...(iii)

We can solve equations (i), (ii), and (iii) simultaneously to get the mass of silver in the coin.

Let's solve equations (i) and (ii) simultaneously.

m = m1 + m2 ⇒ m2 = m - m1

Substituting the value of m2 in equation (ii), we get

V = [(m1 / ρ1) + ((m - m1) / ρ2)] ⇒ (m1 / ρ1) + ((m - m1) / ρ2)

V = V1 + V2⇒ (m1 / ρ1) + ((m - m1) / ρ2)

V  = (m1 / ρ1) + [(m - m1) / ρ2]⇒ (m - m1) / ρ2

V = (m1 / ρ1)⇒ m1 = [(ρ2 / ρ1 + ρ2) × m]

Substituting values, we get:

m1 = [(8.89 × 10³ / (1.05 × 10⁴ + 8.89 × 10³)) × 1.155 × 10⁻²]

m1 ≈ 4.66 × 10⁻³ kg

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Which of the following countries is most likely to consume the greatest portion of the world's
energy?
A. Japan
B. Mexico
C. Peru
D. Iran

Answers

If I am not mistaken it is Japan

The dimensional formula for specific latent heat is​

Answers

Answer:

The dimensional formula for specific latent heat is L²/T²

Explanation:

The unit of specific latent heat is J/kg

The wheel and axle is helpful because it reduces the effort needed to move a load.
What is the "price" you have to pay for this help?

Answers

The "price" that you have to pay for this help is by covering more distance

when using it.

Wheel and axle is a type of lever which has three properties present and

they include

LoadFulcrumEffort

It helps to reduce the force needed to do work and makes it easier thereby

saving strength and resources. Work done is the product of force and

distance traveled.

Since force is reduced in this type of lever then more distance has to be

covered for work to be done efficiently.

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What factors affect an objects kinetic energy?

Answers

Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

A 535 kg roller coaster car began at rest at the top of a 93.0 m hill. now it is at the top of the first loop-de-loop. an illustration of a roller coaster track with the first hill labeled 93.0 m high and it goes down to a vertical loop with the car at the top. the loop is labeled as 62.0 m high. this roller coaster’s track is nearly frictionless, so resistance can be ignored. using g = 9.8 m/s2, what best describes the roller coaster car when it is at the top of the loop-de-loop? the car has only potential energy, so it is moving at 0 m/s. the car has both potential and kinetic energy, and it is moving at 24.6 m/s. the car has both potential and kinetic energy, and it is moving at 34.9 m/s. the car’s potential energy has all been converted to kinetic energy, so it moves at 42.7 m/s.

Answers

Using g = 9.8 m/s2, the statement that best describes the roller coaster car when it is at the top of the loop-de-loop is that The car has both potential and kinetic energy, and it is moving at 24.6 m/s. The correct answer is B) The car has both potential and kinetic energy, and it is moving at 24.6 m/s.

Potential energy is the energy that is stored in any object or system as a result of its position or component arrangement. The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles inside a system or an item.

The energy an individual or an object has as a result of motion in this case, the motion of the falling apple is known as kinetic energy. Potential energy, which exists in a bike that is parked on top of a hill, is converted to kinetic energy when you start riding it downhill. These two energies are both expressed as joules.

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Answer: B (The car has both potential and kinetic energy, and it is moving at 24.6 m/s.)

Explanation:

Asky wave is incident on the ionosphere at an angle of 60°. The electron density of this ionosphere layer is N = 24.536 × 10¹¹ electrons/m³
a. For the point of reflection, determine the refractive index of the ionospheric layer. (3 Marks)
b. Identify the critical frequency for the communication link. (2 Marks)
c. Determine the maximum usable frequency (2 Marks)
d. Give reasons why the transmissions would fail the following frequencies if the frequencies were 10 MHz and 30 MHz respectively. (4 Marks)
e. The lonosphere bends high frequency radio waves towards Earth. Discuss this bending phenomenon.

Answers

We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)

(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.

The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.

Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).

(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).

(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.

(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.

(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.

As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.

This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.

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A cyclist is moving toward a wall while holding a tuning fork rated at 474 Hz. Assume the speed of sound is 343 m/s. If the cyclist detects a beat frequency of 29.0 Hz (between the waves coming directly from the tuning fork and the echo Up = m/s waves coming from the wall), calculate the speed v, of the bicycle.

Answers

To solve this problem, we can use the Doppler effect equation for sound waves:

f' = (v + vr) / (v + vs) * f

Where:

f' is the observed frequency,

v is the speed of sound,

vr is the velocity of the receiver (cyclist),

vs is the velocity of the source (wall),

f is the actual frequency of the tuning fork,

and the beat frequency is the difference between the observed frequency and the actual frequency.

Given:

Actual frequency of the tuning fork (f) = 474 Hz

Speed of sound (v) = 343 m/s

Beat frequency = 29.0 Hz

We are looking for the velocity of the receiver (cyclist), vr.

Using the information provided, we can rearrange the Doppler effect equation to solve for vr:

vr = [(f' / f) - 1] * (v + vs)

Substituting the known values:

vr = [(f' / f) - 1] * (v + vs)

vr = [(474 Hz + 29.0 Hz) / 474 Hz - 1] * (343 m/s + 0 m/s)

vr = (503 Hz / 474 Hz - 1) * 343 m/s

vr = (1.06197 - 1) * 343 m/s

vr = 0.06197 * 343 m/s

vr = 21.3 m/s

Therefore, the velocity of the cyclist (vr) is approximately 21.3 m/s.

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Determine the work done to raise a mass of 8.0 kg through a height of 2.5 m on this planet.

Answers

Answer:

196 J

Explanation:

Formula

Work done(W) = Mass (m) x gravity (g) x height (h)

Here, we are given :

m = 8.0 kgg = 9.8 m/s² (on Earth)h = 2.5 m

Solving

W = 8 × 9.8 x 2.5W = 20 × 9.8W = 196 J

The mean lifetime of an electronically excited molecule is 1. 0 x 10-8 s. If the emission of the radiation occurs at 610 nm, what are the uncertainties in frequency {av) and wavelength {al)?

Answers

The uncertainty in frequency (∆v) is approximately 3.28 x 10^14 Hz, and the uncertainty in wavelength (∆λ) is approximately 4.92 x 10^-11 m.

To calculate the uncertainties in frequency (∆v) and wavelength (∆λ), we can use the uncertainty principle. The uncertainty principle states that the product of the uncertainties in position and momentum (Δx Δp) is on the order of Planck's constant (h).

In this case, we are given the mean lifetime of the molecule (Δt) as 1.0 x 10^-8 s. The uncertainty in energy (∆E) can be calculated using the relationship ΔE ∆t ≈ h, where h is Planck's constant.

Using the formula ΔE = hv, where v is the frequency, and c = λv, where c is the speed of light, we can derive the following relationships:

ΔE ≈ hv = hc/λ

From this, we can solve for the uncertainties in frequency (∆v) and wavelength (∆λ) as follows:

Δv = (∆E / h) = (hc / λh) = c / λ

Δλ = (∆λ / λ) = (∆v / v) = (∆v / c / λ) = ∆v / c

Given that the emission occurs at a wavelength of 610 nm (6.10 x 10^-7 m), we can substitute the values to calculate the uncertainties:

Δv = c / λ = (3.00 x 10^8 m/s) / (6.10 x 10^-7 m) ≈ 4.92 x 10^14 Hz

Δλ = ∆v / c ≈ (4.92 x 10^14 Hz) / (3.00 x 10^8 m/s) ≈ 1.64 x 10^-11 m

Therefore, the uncertainties in frequency (∆v) and wavelength (∆λ) are approximately 3.28 x 10^14 Hz and 4.92 x 10^-11 m, respectively.

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assuming that the resolution of an electron microscope is equal to the de broglie wavelength of the electrons used, to what speed must the electrons be accelerated to obtain a resolution of 0.19 nm ?

Answers

The electrons must be accelerated to a speed of approximately 2.07 million meters per second to obtain a resolution of 0.19 nm.

The de Broglie wavelength of a particle is given by:

λ = h / (mv)

Where h is the Planck constant, m is the mass of the particle, and v is its velocity. To obtain a resolution of 0.19 nm, the de Broglie wavelength must be equal to or less than 0.19 nm.

Rearranging the equation above and solving for v, we get:

v = h / (mλ)

Given the mass of an electron (m = 9.10938356 x 10^-31 kg), and the Planck constant (h = 6.62607015 x 10^-34 Js), we can calculate the required velocity for a de Broglie wavelength of 0.19 nm (λ = 0.19 x 10^-9 m):

v = (6.62607015 x 10^-34) / (9.10938356 x 10^-31 x 0.19 x 10^-9)

v ≈ 2.07 x 10^6 m/s

So, the electrons must be accelerated to a speed of approximately 2.07 million meters per second to obtain a resolution of 0.19 nm.

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at what speed does the wreckage move if one car was driving north and one east?

Answers

The speed of the wreckage resulting from a collision between a car driving north and another car driving east depends on the velocities of the two cars and the angle of the collision.

To determine the speed of the wreckage resulting from the collision, we need information about the velocities of the two cars and the angle at which they collided. The magnitude and direction of the resultant velocity of the wreckage will depend on these factors.

If the two cars were moving at equal speeds in their respective directions, the resultant velocity of the wreckage would be the vector sum of the velocities of the two cars. This can be calculated using vector addition. However, without specific values for the velocities and angle of collision, a specific speed cannot be determined.

In collisions involving objects moving in different directions, the resultant velocity can vary significantly based on the angles and speeds involved. Therefore, to determine the speed of the wreckage resulting from a collision between a car driving north and another car driving east, more information about the velocities and angle of collision is needed.

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If atmospheric conditions changed in such a way that the ambient air temperature and relative humidity decreased while at the same time the barometric pressure increased, what effect would these changes have on air density

Answers

If atmospheric conditions changed in such a way that the ambient air temperature and relative humidity decreased while at the same time the barometric pressure increased, the main effect on air density would be an increase.

Air density is directly affected by temperature, humidity, and barometric pressure. When the temperature and humidity decrease, the air molecules become closer together, resulting in an increase in air density. Additionally, when barometric pressure increases, the weight of the air above a given point increases, causing the air density to increase as well.

Therefore, in this scenario, the decrease in temperature and humidity along with the increase in barometric pressure would lead to an overall increase in air density.

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.
A .63 kg ball is moving at 4.3m/s. What is the momentum of the ball?

Answers

Answer:

Given Mas (m) =63kg

velocity (v) =4.3m/s

momentum (p) =?

p=mv

63kgx4.3m/s

270.9kg.m/s

the momentum =270.9kg.m /s

If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.

What is momentum?

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.

Momentum = mass of the object × velocity of the object

As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of  4.3 meters/seconds,

The momentum of the ball = 0.63× 4.3

                                             

                                             =2.709 kilogram meters/second

Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.

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A vehicle travels for 20 minutes at a speed of 60 km/h. It then travels for 10 minutes at 90 km/h. At
the end of 30 minutes, it covers a distance of Select... v km.

Answers

Answer:

120km

Explanation:

it will covered 120km

A cosmic ray electron moves at 7.50 × 106 m/s perpendicular to the Earth’s
magnetic field at an altitude where field strength is 1.00 × 10−5 T. What is the radius
of the circular path the electron follows?

Answers

Answer:

4.27m

Explanation:

force on moving charge= qvBsin$

centripetal force=mv^2/r

since the forces are equal

mv^2/r=qvBsin$

r= (mv^2)/(qvBsin$) = mv/qBsin$

r-radius

m-mass of an electron

q-charge on electron

v-velocity of the electron

B-field strength

$ - angle

r= ((9.1093837 ×10^-31)kg × 7.50 × 10^6 m/s)/(1.6×10^-19C×10^-5T×sin90) = 4.27m

The property of matter that resists changes in motion is called...
a) inertia
b) gravity
c) weight
d) friction

Answers

Answer:

inertia

Explanation:

i hade the same question

Answer: inertia

Explanation:

You push against a wall and the wall pushes back on you.
O Newton's 1st Law of Motion
O Newton's 2nd Law of Motion
Newton's 3rd Law of Motion

You push against a wall and the wall pushes back on you.O Newton's 1st Law of MotionO Newton's 2nd Law

Answers

Answer:

Its the third law of motion.

Explanation:

Newton's third law of motion states that every action has equal and opposite reaction.

When a metal car is struck by lightning, the resulting electric field inside the car is?.

Answers

When a metal car is struck by lightning, the resulting electric field inside the car is zero.

What is Electric field ?

The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge.

The roof and walls of the car provide a path of less resistance than the interior of the car, which is why a person inside a car does not get struck by lightning.

When lightning is present, it is safer to sit under a car than to stand under a tree. Inside the car, there is no electric field.

The metal cage that encloses the occupants of cars protects them from lightning.

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The diagram below shows a sled moving along a smooth, frictionless track.
Section 1
Section 2
Section 4
Section 3
In which sections of the track will the sled experience an unbalanced force?
A Sections 1 and 3
B Sections 2 and 3
C Sections 2 and 4
D Sections 3 and 4

Answers

Answer:

C. 2 and 4

Explanation:

my teacher went over it and the answer was that

The sections of the track in which the sled would experience an unbalanced force are: C. Sections 2 and 4.

The two types of force.

In Science, there are two (2) main types of force that acts on an object and these include:

Balanced forceUnbalanced force

What is an unbalanced force?

An unbalanced force refers to a type of force that occurs when two (2) or more forces acting on an object are unequal in magnitude, and as such, it typically results in a change of motion.

In this scenario, the sections of the track in which the sled would experience an unbalanced force are sections 2 and 4 respectively.

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a ball on the end of a string is whirled around in a horizontal circle of radius 0.300 m. the plane of the circle is 1.00 m above the ground. the string breaks and the ball lands 1.90 m (horizontally) away from the point on the ground directly beneath the ball's location when the string breaks. find the radial acceleration of the ball during its circular motion.

Answers

The radial acceleration of the ball during its circular motion is approximately 59.4 m/s^2.

Centripetal acceleration, a = v^2 / r, where v is the speed of the ball and r is the radius of the circle.

The time it takes for the ball to reach the ground,

y = 1/2 g t^2

where y is the initial height of the ball (1.00 m), g is the acceleration due to gravity (9.81 m/s^2), and t is the time it takes for the ball to reach the ground.

t = sqrt(2y/g)

= sqrt(2 x 1.00 / 9.81)

≈ 0.45 s

Velocity, v = x/t

= 1.90 / 0.45

≈ 4.22 m/s

The radial acceleration of the ball during its circular motion can now be found using the equation,

a = v^2 / r

a = v^2 / r = (4.22)^2 / 0.300 ≈ 59.4 m/s^2

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Count The Significant Digits In Each Of These Measurements:: Measurement Number of significant digits -9.0x10-1 kJ/mol 9.6 x 10^-1 mL 0.006600 J 91900 kg

Answers

All the non zero digits are significant and 9*10^-1 has 3 significant figures. Leading zeros and succeeding zeros are not significant.

Rules to find significant digits. 0.175 has 3 significant figures, 1930000 has 3 significant figures, 0.045 has 2 significant figures. Zeros after decimals are significant, provided they must have a significant figure(s) on the left side of them. Example-5.730 has 4 significant figures.

40.038 has 5 significant figures. All constants or exponential nos. and trigonometric angles are not significant. Example- 50° has no significant figure. Speed of light-3*10^8 m/s have no significant figures. 14*10^7 have 2 significant figures.

Zeros between two significant figures are significant. Example-40.0 have 3 significant figures. All amounts like 4 apples ,7 children have infinite no.of significant figures.

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Can someone please explain these or help answer them? ​

Can someone please explain these or help answer them?

Answers

Answer:

41.57.

Explanation:

Sometimes if you type in google "area of a regular hexagon, it will give you a calculator you can use to solve your math questions.

Answer:41.57

Hope this help

The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and round answer to the nearest whole number.)

Answers

53....................................

Explanation:

What is the mechanical advantage ????

What is the mechanical advantage ????

Answers

Answer:

the advantage gained by the use of a mechanism in transmitting force specifically : the ratio of the force that performs the useful work of a machine to the force that is applied to the machine.

Explanation:

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. The device trades off input forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever.

The volume per second of a fluid flowing through a horizontal pipe of length l is given by kpa/n where k is constant, p is the excess pressure (force per unit area) a is the radius of the pipe and U is the frictional quantity of dimension MLT-1 by dimensions find the number x

Answers

According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

The equation given is:

Volume per second = k * (p * a) / n

Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹


To find the number x, we need to determine the dimensions of each term in the equation.

1. Dimension of Volume per second:


  - Volume has the dimension L³ (length cubed)
  - Time has the dimension T (time)
  - Therefore, Volume per second has the dimension L³  / T

2. Dimension of k:


  - The equation states that k is a constant. Constants are dimensionless.

3. Dimension of p * a:


  - Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
  - Radius has the dimension L (length)
  - Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L²  * T² )

4. Dimension of n:


  - Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)

Now, we can equate the dimensions:

L³  / T = k * (M / (L²  * T² )) * MLT⁻¹


Simplifying the dimensions:

L³  / T = k * M / (L²  * T² ) * MLT⁻¹


L³  / T = k * M / L²  * M / T²  * L^-1 * T⁻¹


L³  / T = k * M²  / L²  * T⁻¹


To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:

L³ / T = k * M² / L² * T⁻¹


Comparing the dimensions on both sides, we can conclude:

L³ / T = k * M² / L²* T⁻¹

The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).

Therefore, the number x is 2.

The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

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average method and it reports the tollowing unit data tor the rorming department. Units completed in the torming department are transferred to the painting department. Production cost information for the forming department follows. . Calculate the equivalent units of production for both direct materials and conversion for the Forming department. o. Calculate the costs per equivalent unit of production for both direct materials and conversion for the Forming department c. Using the weighted average method, assign costs to the forming department's output-specifically, its units transferred to painting and its endina work in brocess inventorv. Calculate the costs per equivalent unit of production for both direct materials and conversion for the For Jsing the weighted average method, assign costs to the forming department's output-specifically, its 4 d its ending work in process inventory. Complete this question by entering your answers in the tabs below. Calculate the equivalent units of production for both direct materials and conversion for the forming department. a. Calculate the equivalent units of production for both direct materials and conversion for the Forming departm b. Calculate the costs per equivalent unit of production for both direct materials and conversion for the Forming c. Using the weighted average method, assign costs to the forming department's output-specifically, its units tra and its ending work in process inventory. Complete this question by entering your answers in the tabs below. Calculate the costs per equivalent unit of production for both direct materials and conversion for the forming department Required information Using the weighted average method, assign costs to the forming department's output-specifically, its units trar painting and its ending work in process inventory.

Answers

Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.

Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500

Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000

a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units

Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units

b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production

Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit

Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit

c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production

Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700

Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300

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As the block slides down the incline, the sum of its gravitational potential energy with respect to the horizontal and kinetic energyA. DecreasesB. IncreasesD. Stays the same

Answers

Answer:

D. Stays the same

Explanation:

When a block slides down the incline, the potential energy will drecrease because it depends on the height and the kinetic energy will increase because it depens on the speed. However by the conservation of energy, the sum of these energies will be constant.

It means that the answer is

D. Stays the same

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