Why do the leaves outside change colors?

When 6.8776g of aluminium reacts with an excess of oxygen, 6.8776g of aluminium oxide are produced.

What is the name of aluminum oxide?

Al2O3 is an inorganic chemical reagent with the chemical name aluminum oxide. Other names for it include alumina, alundum, al-alumina, and aloxide.

If there are 4 moles of Al that equals 107.926156 grams of 4Al

If there are 2 moles of Al2O3 that equals 203.9226g

If  107.9261 grams of 4Al equals 203.9226 grams of 2Al2O3 then, 3.64g of Al equals x

107.9261 / 3.64 = 203.9226 / x

(107.9261) x = (203.9226) 3.64

107.9261 x = 742.2782

dividing both LHS and RHS by 107.9261,

107.9261/107.9261x = 742.2782/107.9261

                             x = 6.8776g

Hence, 6.8776g of aluminium oxide are produced.

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ANSWER: From experience and observation, the pathogen that responds more faster to treatments are PARASITES.

This is because, our body are already used to parasite, as they feed and mostly live inside our body. Parasites becomes harmful to our body, when it is allowed to be much in the body, thereby weakening the immune system of the body. Intake of vaccination reduces the number of parasites in the body, which gives the immune system the chance of recovering and protecting the body.

Parasite does not replicate more faster like viruses and other pathogens. These makes it more easier for treatment to work more faster. They are also easily killed by taking the proper treatment, and the rate of their replications are very slow when compared to the rate of their death when vaccinated.

Some example disease caused by parasites are:

1) Giardiasis

2) Trichomoniasis

3) Malaria

4) Toxoplasmosis

5) Intestinal worms

6) Pubic lice

All this disease above responds very fast to medical treatment, unless when they is complications, which are mostly when the parasite has been allowed to cause more harm and replicate much in the body, without any treatment. This is why doctors advice patients that lives at the tropical regions to periodically vaccinate themselves on parasitic infections.

Answer:

24.9 L Ar

General Formulas and Concepts:

Atomic Structure

Aqueous Solutions

Stoichiometry

Explanation:

Step 1: Define

[Given] 40.0 g Ar

[Solve] L Ar

Step 2: Identify Conversions

[PT] Molar Mass of Ar - 39.95 g/mol

[STP] 22.4 L = 1 mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

24.9235 L Ar ≈ 24.9 L Ar

The M electrode in the left half-cell will be oxidized since the left half-cell has a higher concentration and will act as the anode. As a result, the M electrode in the right half-cell will be lowered, and the right half-cell will act as the cathode. As a result, the right half-cell's M electrode will be positive.

The given half-cell reactions are:

Left half-cell: M₂(SO4)₃ + 6 e⁻ → 2M

Right half-cell: M₂(SO4)₃ + 6 e⁻ → 2M

Since both half-cell reactions are the same, the cell potential will be zero at equilibrium. Therefore, the voltmeter will show zero voltage.

However, if we assume that the reactions are not at equilibrium, we can use the Nernst equation to calculate the potential difference between the two electrodes:

Ecell = E°cell - (RT/nF)ln(Q)

where:

E°cell = standard cell potential

R = gas constant = 8.314 J/(mol K)

T = temperature in kelvin = 35.0 + 273 = 308 K

n = number of electrons transferred in the reaction = 6

F = Faraday's constant = 96,485 C/mol

Q = reaction quotient = [M]left / [M]right

The standard cell potential for the given reactions is not provided, but since both half-cell reactions are the same, the standard cell potential will be zero.

Plugging in the values, we get:

Ecell = - (RT/nF)ln(Q)

Ecell = - (8.314 J/(mol K) x 308 K / (6 x 96,485 C/mol)) ln(4.50 M / 2.25 mM)

Ecell = - (0.0257 V) ln(2000)

Ecell = 0.103 V

The M electrode in the left half-cell will be oxidized since the left half-cell has a higher concentration and will act as the anode. As a result, the M electrode in the right half-cell will be lowered, and the right half-cell will act as the cathode. As a result, the right half-cell's M electrode will be positive.

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Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Answer

C and D

Explanation

A is NOT correct, Solids have the strongest intramolecular forces.

B is NOT correct, Gases have more kinetic energy than liquids.

C is correct, Solids have the lowest kinetic energy.

D is correct, The particles in a gas do not have any particular arrangement and there are very, very weak forces between them. So, the particles in a gas can easily move around and fill the shape of the container they are in, meaning they have no fixed shape.

Answer:

Advantages of Renewable Energy Resources

Explanation:Because renewable energies are not burned like fossil fuels, they do not release pollutants into the atmosphere and provide a cleaner, healthier environment. Sources of renewable energy are found everywhere in the world and cannot be depleted.

Answer:

hex-1-ene with a hydroboration-oxidation reaction

Explanation:

In this case, we can start with the structure of 1-hexanol. In this alcohol, the "OH" is on the first carbon. Thus, the alkene that this alcohol can produce must have a double bond between carbons 1 and 2, that is, hex-1-ene.

Now, it is important to know which of the reactions we can use, hydroboration-oxidation, or oxymercuration-reduction. To decide which reaction to using, we must look again at the alcohol we want to produce. In this alcohol, the "OH" is attached to a primary carbon. Therefore, the addition of the "OH" must be made on the least substituted carbon, that is, carbon number 1.

Because of this, an anti-Markovnikov reaction (a reaction in which the "OH" is added on the less substituted carbon) must be used. The reaction, which serves us then is: hydroboration-oxidation since this reaction is anti-markovnikov.

See figure 1

I hope it helps!

Answer:

Its a physical change so its reversible

Explanation:

hope it helps

Answer:

It is a reversible esterification reaction.

Explanation:

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Answer:

( essay ) a time when i got lost somewhere

To determine the tomato's velocity when it hits the ground, we need more information. Specifically, we need the height from which the tomato was dropped and the tomato mass.

Without these details, it is impossible to calculate velocity accurately. The velocity of an object when it hits the ground depends on factors such as the height of the fall, the mass of the object, and any forces acting on it during the fall (such as air resistance).

If you can provide the necessary information, I can help you calculate the velocity of the tomato when it hits the ground.

Answer: The final pressure is 0.81 kPa

Explanation:

The combined gas equation is,

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

where,

\(P_1\) = initial pressure of gas = 0.58 kPa

\(P_2\) = final pressure of gas = ?

\(V_1\) = initial volume of gas = v

\(V_2\) = final volume of gas = \(v-\frac{40}{100}\times v=0.6v\)

\(T_1\) = initial temperature of gas = \(25^0C=(25+273)K=298K\)

\(T_2\) = final temperature of gas = \(-22^0C=(-22+273)K=251K\)

Now put all the given values in the above equation, we get:

\(\frac{0.58\times v}{298}=\frac{P_2\times 0.6v}{251}\)

\(P_2=0.81kPa\)

The final pressure is 0.81 kPa

Answer:

Maybe A

Explanation:

The pH of the aqueous solution is 8 means solution is basic.

pH of any solution will be calculated by using the below equation:

pH = -log[H⁺]

Given that concentration of H⁺ ions = 1.0×10⁻⁸ M

On putting this value in the above equation, we get

pH = -log( 1.0×10⁻⁸ )

pH = -(0-8) = 8

Means the given aqueous soution is basic in nature.

Hence pH is 8 means solution is basic.

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Answer:

• Atom B

• Atom R

• Atom A

• Atom P

Explanation:

To calculate the overall charge of each atom, it is necessary to do a subtraction between the number of protons and the number of electrons:

So, the order of the atoms from most positive to least positive is:

• Atom B

• Atom R

• Atom A

• Atom P

Answer:

Depends on others to function

Explanation:

The answer to the equation ΔH = [(40 mol CO₂ × -394 kJ/mol) + 42 mol H₂O × -242 kJ/mol)] - [(2 mol C₂₀H₄₂ × -2230 kJ/mol)] is -11,822 kJ/mol.

The negative sign in the value of ΔH indicates that the reaction is exothermic, meaning that it releases heat to the surroundings.

This equation is related to the process of combustion as it calculates the enthalpy change for the combustion of a given substance. The enthalpy change for the combustion of a substance is the heat released when one mole of the substance is burned completely in oxygen.

By calculating the enthalpy change using this equation, we can determine the heat of combustion for a given substance, which is useful in fields such as energy production and fuel efficiency.

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The enthalpy change for the given reaction is -22,004 kJ. This means that the reaction releases 22,004 kJ of heat energy for every mole of C₂₀H₄₂ that reacts.

Heat energy is a form of energy that is transferred from one body to another as a result of a temperature difference between them. It is a form of kinetic energy associated with the random motion of atoms and molecules in a substance.

Kinetic energy is a form of energy that an object possesses due to its motion. The amount of kinetic energy an object has depends on its mass and velocity. Kinetic energy is a scalar quantity, which means it only has a magnitude and not a direction.

To solve the equation, we need to calculate the total enthalpy change (ΔH) for the reaction:

C₂₀H₄₂ + 40 O₂ → 40 CO₂ + 42 H₂O

We can use the given equation to calculate ΔH as follows:

ΔH = [(40 mol CO₂ × -394 kJ/mol) + 42 mol H₂O × -242 kJ/mol)] - [(2 mol C₂₀H₄₂ × -2230 kJ/mol)]

ΔH = [-15,760 kJ + (-10,164 kJ)] - [-4,460 kJ]

ΔH = -26,464 kJ + 4,460 kJ

ΔH = -22,004 kJ

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Answer:

56.96 grams

Explanation:

To find the mass of 1.78 moles of O2, we need to use the molar mass of O2, which is the mass of one mole of O2.

The chemical formula for O2 is O-O or simply O2. The molar mass of O2 is the sum of the atomic masses of two oxygen atoms, which can be found on the periodic table.

The atomic mass of oxygen (O) is approximately 16.00 g/mol. So the molar mass of O2 is:

Molar mass of O2 = 2 x atomic mass of O

= 2 x 16.00 g/mol

= 32.00 g/mol

Therefore, the mass of 1.78 moles of O2 is:

Mass = number of moles × molar mass

= 1.78 mol × 32.00 g/mol

= 56.96 g

So the mass of 1.78 moles of O2 is 56.96 grams.

1. For the pair of half-reactions:

Pt2+(aq) + 2e- → Pt(s)    ... (1)

Sn2+(aq) + 2e- → Sn(s)    ... (2)

To obtain the balanced equation for the overall cell reaction, we need to multiply the half-reactions by appropriate coefficients to ensure that the number of electrons transferred is equal. In this case, we can multiply equation (1) by 2 and equation (2) by 1:

2(Pt2+(aq) + 2e-) → 2(Pt(s))

Sn2+(aq) + 2e- → Sn(s)

Combining the equations, we have:

2Pt2+(aq) + Sn2+(aq) → 2Pt(s) + Sn(s)

The cell notation for this reaction is:

Pt2+(aq) | Pt(s) || Sn2+(aq) | Sn(s)

To calculate the standard cell potential (E°), we need to know the standard reduction potentials for Pt2+/Pt(s) and Sn2+/Sn(s) half-reactions. Referring to standard reduction potential tables, we find:

E°(Pt2+/Pt(s)) = +1.20 V

E°(Sn2+/Sn(s)) = -0.14 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = 0.00 V - (-0.14 V) = +0.14 V

Therefore, the standard cell potential for this reaction is +0.14 V.

2. For the pair of half-reactions:

Co2+(aq) + 2e- → Co(s)    ... (3)

Cr3+(aq) + 3e- → Cr(s)    ... (4)

To balance the number of electrons transferred, equation (4) can be multiplied by 2:

2(Co2+(aq) + 2e-) → 2(Co(s))

Cr3+(aq) + 3e- → Cr(s)

Combining the equations, we have:

2Co2+(aq) + Cr3+(aq) → 2Co(s) + Cr(s)

The cell notation for this reaction is:

Co2+(aq) | Co(s) || Cr3+(aq) | Cr(s)

To calculate the standard cell potential (E°), we refer to the standard reduction potentials:

E°(Co2+/Co(s)) = -0.28 V

E°(Cr3+/Cr(s)) = -0.74 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = -0.74 V - (-0.28 V) = -0.46 V

Therefore, the standard cell potential for this reaction is -0.46 V.

3. For the pair of half-reactions:

Hg2+(aq) + 2e- → Hg (l)    ... (5)

Cr2+(aq) + 2e- → Cr(s)    ... (6)

The equation for the overall cell reaction can be obtained by multiplying equation (6) by 2:

2(Hg2+(aq) + 2e-) → 2(Hg (l))

Cr2+(aq) + 2e- → Cr(s)

Combining the equations, we have:

2Hg2+(aq) + Cr2+(aq) → 2Hg (l) + Cr(s)

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Answer: extra-high high tides, and very low, low tides

Explanation: When the sun, moon, and Earth are in alignment (at the time of the new or full moon), the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides—both commonly called spring tides.

The ΔH of the reaction for the formation of graphite from diamond is equal to -1.9 KJ/mol.

The heat of formation can be described as the amount of heat absorbed or evolved when 1 mole of a substance is formed from its constituent elements, each substance being in its normal physical state.

We have to rearrange the provided equations in a way in which all molecules of O₂ and CO₂ can be eliminated:

2C (diamond) + 2O₂ (g) → 2CO₂ (g)     ΔH₁= 2 × (-395.4 KJ)

2 CO₂ (g) → 2 CO(g) + O₂(g)            ΔH₂ = 566.0 KJ

CO₂(g) → C (graphite) + O₂(g)          ΔH₃= - 1 × (-393.5 KJ)

2CO (g) → C (graphite) + CO₂(g)      ΔH₄= -172.5 KJ

When we eliminate the molecules that appear both in reactants and products, the total chemical reaction is the following:

2C (diamond) → 2C (graphite)

ΔH (total) = ΔH₁ + ΔH₂ + ΔH₃ + ΔH₄

ΔH (total) = 2 × (-395.4 KJ) + 566.0 KJ + (-1 × (-393.5 KJ)) - 172.5 KJ

ΔH (total) = 347.2 KJ

This is for 2 mol of C (diamond) which is converted into 2 mol of C (graphite). To find ΔH for the reaction of 1 mol C (diamond) to 1 mol (graphite) we have to divide it into 2:

ΔH = - 3.8/2 = -1.9 KJ/mol

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• that the mass fraction of Na2CO3 = 2%

meaning 2 grams of Na2Co3 was dissolved in 98g of water .

∴ total mass of solution = 100g

• Density = 1.019g/mL.

• Molar mass Na2CO3=105,9888 g/mol

Density = mass /volume

∴Volume = mass/density = 100g /1.019g/mL.

= 90.66mL.

n = mass Na2CO3/MolMass Na2Co3

= 2 g /105.9888g/mol

∴moles of Na2CO3 =0.019moles Na2CO3

Molarity =( n/v) * 1000

= (0.019mol/(90.66/1000) L

= (0.019/90.66)*1000 ( multiply by 1000: 90.66/1000=0.09066)

=0.21M

The rate of the given reaction is 0.00197 M/s.

The balanced chemical equation of the reaction is:

CO (g) + NO₂ (g) → CO₂ (g) + NO (g)

From the equation, 1 mole of CO produces 1 mole of CO₂, and hence the number of moles of CO2 produced is equal to the number of moles of CO consumed.

The concentration of CO₂ produced = 0.123 M.

Therefore, the concentration of CO consumed is also 0.123 M.

The rate of reaction is given by the formula:

where Δ[C] is the change in concentration and Δt is the change in time.

Over 62.3 seconds, the concentration of CO decreases from 0 M to 0.123 M.

Δ[C] = 0.123 M - 0 M

Δ[C]  = 0.123 M

Δt = 62.3 s

Substituting the values in the formula, we get:

rate of the reaction = Δ[C]/Δt

rate of the reaction = 0.123 M/62.3 s

rate of the reaction = 0.00197 M/s

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The factors that will cause an increase in the gas's solubility are:

1) The volume of the gas above the solution decreases when solution is added with a syringe.

This will increase the pressure of the gas above the solution, causing more gas molecules to dissolve into the solvent.

2) The temperature of the flask is raised.

An increase in temperature will cause the gas molecules to move faster and collide more frequently with the solvent molecules, increasing the solubility of the gas.

3) A reaction occurs between the gas solute and the solvent.

If the gas solute reacts with the solvent to form a new compound, the solubility of the gas will increase as the reaction will remove gas molecules from the gas phase and into the solution.

The other two factors (using a syringe to add a gas other than the solute and increasing the volume of the gas above the solution by removing solution with a syringe) will not cause an increase in the gas's solubility. Adding a gas other than the solute will not affect the solubility of the original gas solute, and increasing the volume of the gas above the solution will decrease the pressure of the gas, causing less gas molecules to dissolve into the solvent.

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Answer:

The segment of this graph that shows a decreasing velocity is the EF segment. AB and DE segments show that whatever was moving, in these segments was stopped. The segment BC shows an increase in velocity - the metres travelled were always more as the time went by.

Explanation:

Answer:

Explanation:

60 27 cobalt isotope decays with a half life of 5.27 years to produce 60 28 nickel. The fraction of a sample of 60/27 cobalt isotope that will remain after 15 yrs is 0.125.

The number of half lives for a sample is calculated as

n=t/t(1/2)

Where, t=15yrs

t(1/2)=5.27 yrs

Therefore, number of half lives for 60 27 cobalt is

n=15 yrs/5.27 yrs=2.8463≈3

Let us assume that we will start with 100g of 60 27 cobalt. Then amount of cobalt remains at each decay is

At first decay, 100/2=50 g

At second decay, 50g/2 = 25g

At third decay, 25g/2=12.5 g

The fraction of sample remain after 15 yrs is

fraction = 12.5/100 = 0.125

Therefore, the fraction of a sample remain after 15 yrs is 0.125.

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The value of Kc for the given reaction is 0.0579 (rounded to four decimal places).

The formula for the equilibrium constant, Kc, of a reaction is given by the ratio of the product of the concentrations of the products raised to their respective stoichiometric coefficients to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

The stoichiometric coefficients are the coefficients in the balanced chemical equation.

To determine the value of Kc for the reaction given by the following chemical equation:N2(g) + 3 H2(g) ⇌ 2 NH3(g)

we first need to write the expression for Kc.

The expression for Kc is given by the following formula:Kc = [NH3]² / [N2][H2]³.

We are given the equilibrium concentrations as follows:[N2]eq = 2.66 M[H2]eq = 0.64 M[NH3]eq = 3.34 M

We can substitute these values into the expression for Kc and obtain the following:Kc = (3.34)² / (2.66)(0.64)³ = 0.0579 (rounded to four decimal places).

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1. SO2 is a reducing agent, O2 is an oxidizing agent. Therefore we have a reduction-oxidation reaction.

2. Al2(SO4)3 is an acid and Ca(OH)2 is a base, therefore we have a neutralization reaction.

3. CH2 is fuel and O2 is an oxidizing agent, here we have a combustion reaction.

4. AgNO3 is an oxidizing agent, Mg is a reducing agent. Therefore we have a reduction-oxidation reaction.

5. Ba(NO3)2 is a salt or we can classify it as a base and H3PO4 is an acid, so it will be a neutralization reaction.

6.