Why do sound waves travel through solids, liquids and gases?

X2 Y2 ---> X2Y2 rate = k[X2]

A reaction and its experimentally determined rate law are represented above. A chemist proposes two different possible mechanisms for the reaction, which are given below.

Mechanism 1 Mechanism 2 X2 ---> 2X (slow) X2 ---> 2X (slow) X + Y2 ---> XY2 (fast) X + Y2 --->

XY + Y (fast)

X + XY2 ---> X2Y2 (fast) X + XY

---> X2Y (fast) X2Y + Y ---> X2Y2 (fast)

Based on the information above, The statement that true is

Both mechanism 1 and 2 are consistent with the rate law.

The reaction rate is defined as the change in the concentration of a reactant or product per unit time. The unit for reaction rate is M/s (Molars per second).

As we know, chemical reactions take place from the direction of the reactants to the product. This means, during a chemical reaction, the reactants are used (consumed) along with the formation of a number of products. Thus, the reaction rate can be studied in terms of reducing the concentration of the reactants and increasing the concentration of the products.

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At Location C, nightfall is experienced by the Northern Hemisphere. At Location C, the Northern Hemisphere is inclined away from the Sun.

The Northern Hemisphere tilts away from the Sun at its greatest angle around December 21. We experience the least amount of daylight at this time of year, which is known as the northern winter solstice.

The Earth's axis is tilted most closely towards the sun twice a year during what are known as the solstices. The longest day occurs in the hemisphere that is slanted most towards our star, whereas the longest night occurs in the hemisphere that is tilted away from the sun.

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Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).

Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.

In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.

Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

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An outline is a line drawn around an element, enclosing the element content, padding, and border spaces.

A form or figure's outline is defined by a line or combination of lines. The lines restrict the shape, isolating it inside the composition or the area. The shapes are created by the outlines.

The phrase "outline" in art refers to the lines, real or apparent, that define or confine a figure (or shape) within the field of vision, with the total number of these lines defining the contour of the figure.

An item is depicted by lines of contour without shade in an outline sketch or drawing, leaving out internal detail. A variety of markers are used to transform an object's seeming edge into a useful reference on paper.

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Answer:

the wave is reflected. it starts heading towards the other direction

Explanation:

Answer:

1.04 L.

Explanation:

What is given?

Temperature 1 (T1) = 240 K.

Pressure 1 (P1) = 670 mmHg.

Volume 1 (V1) = 1.28 L.

Temperature 2 (T2) = 198 K.

Pressure 2 (P2) = 680 mmHg.

What do we need? Volume 2 (V2).

Step-by-step solution:

To solve this problem, we have to use the combined gas law. The combined gas law expresses the relationship between the pressure, volume, and absolute temperature of a fixed amount of gas. For a combined gas law problem, only the amount of gas is held constant. The formula of combined gas law is:

We need to find the volume 2 (V2), so let's solve for this unknown value and let's replace the given data that we have:

The final volume for this case would be 1.04 L, the volume is being reduced.

The Number of moles present is 0.5mol.

What is ideal gas law?

The general gas equation, also known as the ideal gas law, is the equation of state for a fictitious ideal gas. The equation for the ideal gas's relationship to pressure P, volume V, temperature T, and number of moles n is known as the ideal gas law.

Use P V = n R T 

R = 0.08206 L -atm /mol -K when the pressure is in atmosphere atm, the volume is in litres L, and the temperature is in Kelvin K.

One atm is equal to 760.0 mm Hg, so depending on how the pressure changes, there will either be a division or multiplication.

Divide the value in mmHg by 760.0 mmHg/atm to convert it to atm.

P= 912mmHg /760mmHg/atm=1.2atm

to convert °C to kelvin,

  K=°C +273= 20+273=293K

R=0.08206

Add these values to given equation,

n=PV/RT

 = 1.2×10÷0.08206×293

 = 12÷24.02

 =0.5mol

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Answer:

It is used by the organism itself for respiration.

This is kind of a pretty easy question:

- In order to get the number of atoms/entities of Neon, you will have to turn that 1009g of Neon into moles

-And then you have to use the moles and calculate it using Avogadro's Number which is 6.02 x 10^23

number of moles = mass/molar mass of element/compound

n = 1009g/20.18g/mol

n = 50 mol

Number of atoms/entities = 50 x  (6.02 x 10^23)

Number of atoms in 1009g of neon is 3.01 x 10^25 (scientific notation because its a really long number)

Answer:Helium

Explanation:

Helium can hold two electrons on the outer shell. as for the inner part it mostly looks like helium.

The concentration, in m/v %, of a solution prepared by dissolving 65.4 g NaCl in a total volume of 3.7 l of solution is 1.76 %.

The data given as follows:

mass of the NaCl = 65.4 g

volume of the solution = 3.7 L = 3700

concentration in m/v % is means that : mass by volume percentage and is given as :

concentration in m/v % =(mass of solute / volume of the solution ) × 100 %

                                      = ( 65.4 / 3700 ) × 100 %

                                      = 1.76 %

Thus, The concentration, in m/v %, of a solution prepared by dissolving 65.4 g NaCl in a total volume of 3.7 l of solution is 1.76 %.

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Explanation:

0 10 grams that that should be the answer

The three (3) examples from the sword fighting scene that showed Inigo and the masked man's similarities are:

Inigo Montoya was one of the fictional character in the novel titled "The Princess Bride" and written by William Goldman's in 1973. Inigo hails from the village called Arabella and he was raised by his father Domingo Montoya, who was a master craftsman that makes sword.

In The Princess Bride, Inigo had a swordfight with a man in black (masked man) and they have the following things in common:

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The specific heat capacity is  the quantity of heat (J) absorbed per unit the mass (kg) of the material. when you try to heat up the substance that has a high specific heat , it will takes the more energy to rise the temperature .

The specific heat capacity is  the quantity of heat (J) that absorbed the per unit mass (kg) of the material.  when its temperature will increases 1 K or the 1 °C, and the unit of the specific heat capacity is   J/(kg K) or the J/(kg °C).

ween we try to heat up the substance that has the high specific heat capacity then it will takes the more energy to rise the temperature .

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Part C the answer is Δ[S8]/Δt = 0.0026 M/s

Parte D the answer is v = 0.0026 M/s

The formula for the limiting reagent is Fe, and the maximum amount of iron(II) oxide that can be produced is 0.135 moles.

To determine the limiting reagent and the maximum amount of iron(II) oxide that can be produced, we need to compare the moles of each reactant and their stoichiometric ratios in the balanced equation.

The balanced equation for the reaction is:

4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)

From the balanced equation, we can see that the stoichiometric ratio between iron and oxygen is 4:3. This means that 4 moles of iron react with 3 moles of oxygen to produce 2 moles of iron(II) oxide.

Moles of iron(II) oxide = min (0.270 moles of Fe, (0.579 moles of O₂) × (2 moles of Fe₂O₃ / 3 moles of O₂))

To determine the limiting reagent, we compare the moles of iron and oxygen and choose the reactant that produces the lesser moles of iron(II) oxide. In this case, we have:

Moles of iron(II) oxide produced from 0.270 moles of Fe = 0.270 moles × (2 moles of Fe₂O₃ / 4 moles of Fe) = 0.135 moles

Moles of iron(II) oxide produced from 0.579 moles of O₂ = 0.579 moles × (2 moles of Fe₂O₃ / 3 moles of O₂) = 0.386 moles

Since 0.135 moles of iron(II) oxide is less than 0.386 moles, the limiting reagent is iron.

Therefore, the formula for the limiting reagent is Fe, and the maximum amount of iron(II) oxide that can be produced is 0.135 moles.

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Explanation:

its its originality as an atom has to be pure

A different element is formed because the radioactive element has lost its originality as a pure atom when a radioactive element emits alpha radiation.

Some elements of unstable atomic nuclei undergo radioactive decay to form stable nuclei because of the presence of excess nuclear charge inside them are known as radioactive elements.

The stability of nuclei of an element can be estimated by neutron to proton ratio. The atomic number up to Z= 20 is stable nuclei and contains an equal number of protons and neutrons. As the atomic number starts to increase, the repulsion forces between protons increase.

Thus, the neutron-to-proton ratios of stable nuclei increase with increasing atomic numbers. If elements with the atomic number, Z > 83 and n/p > 1.5 and they will be most unstable and radioactive.

For example, Pu-240 emits an alpha particle and gets converted into U-236 which is completely different from the original nuclei.

²⁴⁰Pu₉₄  →   ⁴He₂  +   ²³⁶U₉₂

Therefore, the radioactive element lost its identity after disintegration.

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Answer:

the structure of atom which discovered by Thomson the describe on how the sub-atomic particles are arranged in an atom

The correct equation representing the radioactive decay of 226Ra is (2)   226Ra → 222Rn + 4He.

This equation correctly represents the radioactive decay process of 226Ra (Radium-226) into 222Rn (Radon-222) and 4He (Helium-4).

In radioactive decay, unstable isotopes undergo a spontaneous process to transform into more stable forms by emitting particles or radiation. In the case of 226Ra, it decays by a process called alpha decay. Alpha decay involves the emission of an alpha particle, which consists of two protons and two neutrons (equivalent to a helium nucleus).

The equation (2) shows that 226Ra undergoes alpha decay, resulting in the formation of 222Rn and the release of an alpha particle (4He). The atomic number and mass number must be conserved in the decay process. Therefore, 226 (atomic number 88) on the left side of the equation decays to 222 (atomic number 86) on the right side, while the mass number also decreases by 4 units.

It's important to note that equation (1) represents an incorrect notation, as it suggests that 226Ra undergoes a transformation to 226Ra89, which is not possible as it implies an increase in atomic number. Equation (3) does not accurately represent the decay of 226Ra. Equation (4) is incorrect as it represents the formation of an isotope that doesn't exist.

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IUPAC name -Ascorbic Acid (Vitamin C)-(5R)-[(1S)-1,2-Dihydroxyethyl]-3,4-dihydroxyfuran-2(5H)-one, Fruit sugar or D-fructose are other names for fructose-fructose. D-glucose, or glucose.

Early in the 1930s, vitamin C—then known as "hexuronic acid"—was extracted from fruits, vegetables, and the adrenal cortex. After being proved to treat scurvy in guinea pigs, it was renamed ascorbic acid to reflect its anti-scorbutic qualities.

Description. Ascorbic acid, a naturally occurring organic substance with antioxidant qualities, is offered by TCC. C6H8O6 is its chemical formula. It is a crystalline white substance that mixes easily with water to form moderately acidic solutions.

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Answer:

ITS SPOOKY MONTH (skid and pump phrase)

Explanation:

Answer:

The 1-kg ball accelerates twice as much as the 2-kg ball.

Explanation:

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Answer:

Listed below

Explanation:

COMPOUND

1. It is a pure substance.

2. It can not be separated by a physical method.

3. Element loses their properties in a compound.

4. Its composition is fixed throughout its mass.

5. It has a fixed melting point.

6.In nature they are homogeneous.

MIXTURE

1. It is an impure substance.

2. It can be separated by a physical method.

3. Substances forming mixture retain their properties.

4. It has no fixed composition.

5. It has no sharp melting point.

6. They can be homogeneous as well as heterogeneous in nature.

Answer:

Some of the energy released in respiration is used to make larger molecules from smaller ones, to enable muscles to contract and to keep temperature steady. Some of the energy released in respiration in plants is used to make amino acids and proteins. c Food provides the amino acids needed to make body proteins.

Explanation:

Answer:

89.3 %

Explanation:

M(CH4) = 12+ 4*1 = 16 g/mol

M(O2) = 2*16 = 32 g/mol

M(CO2) = 12 + 2*16 = 44 g/mol

8.50 g * 1 mol/16 g = 0.5313 mol CH4

15.9 g * 1 mol/32 g = 0.4969 mol O2

9.77 g * 1 mol/44 g = 0.2220 mol CO2

1)                                  CH4        + 2O2 -----> CO2 + 2H2O

from reaction             1 mol          2 mol

given                       0.5313 mol   (0.4969 mol)

1 mol CH4              --- 2 mol O2

0.5313 mol  CH4  --- x mol O2

x= 2*0.5313 = 1.0626 mol O2

We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.

2)                               CH4        + 2O2 -----> CO2 + 2H2O

from reaction                             2 mol        1 mol

given                                      0.4969 mol   x mol

x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield

3)

Practical yield CO2 = 0.2220 mol

Theoretical yield CO2 = 0.2485 mol

% yield = (0.2220/0.2485)*100% = 89.3 %

Answer:

a) Na2S

b) AlF3

c) O2

d) C6H12O6

Explanation:

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Your experiment would not work because Taq polymerase needs a tiny bit of DNA to add bases to. Due to the lack of an enzyme that could add new nucleotide bases, your process would not succeed.

The primers are absolutely necessary for a PCR reaction to work. The RNA primers must anneal before the heat-resistant DNA polymerases may start replicating DNA. The DNA polymerase cannot work without the primers, and as a result, no product will be produced.

DNA polymerase requires a primer on which it may add the first nucleotide since it can only add a nucleotide onto an already-existing 3'-OH group. This prerequisite allows the researcher to identify a particular area of the template sequence that they want to amplify.

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For the number of grams of 35S in a sample and the amount remaining after a specific time, we use the decay law equation. First, we calculate the initial number of radioactive atoms (N₀) by dividing the decay rate by the decay constant. Then, we convert N₀ to grams by multiplying it by the molar mass of 35S.

To solve the problem, we'll use the decay law for radioactive decay:

\(\[N(t) = N_0 \cdot e^{-\lambda t}\]\),

where N(t) is the number of radioactive atoms at time t, N₀ is the initial number of radioactive atoms, λ is the decay constant, and e is the base of the natural logarithm.

(a) To find the number of grams of 35S in a sample with a decay rate of \(3.70 \times 10^2 s^{(-1)\), we need to determine N₀.

First, we need to find the decay constant (λ) using the half-life (t₁/₂):

t₁/₂ = 0.693 / λ.

Rearranging the equation, we have:

λ = 0.693 / t₁/₂.

Given that the half-life (t₁/₂) of 35S is 87.1 days, we can calculate the decay constant:

λ = 0.693 / 87.1.

Now we can find N₀ using the decay rate (decay/s) and the decay constant:

decay rate (decay/s) = N₀ * λ.

Solving for N₀:

N₀ = decay rate (decay/s) / λ.

Plugging in the values:

\(\[N₀ = \frac{{3.70 \times 10^2 \, \text{{s}}^{-1}}}{{\frac{{0.693}}{{87.1}}}}\]\).

Calculating this, we find the initial number of radioactive atoms (N₀).

To find the mass of 35S, we need to convert the number of radioactive atoms (N₀) to grams. The molar mass of 35S is approximately 35 g/mol.

Mass (g) = N₀ * molar mass (g/mol).

(b) To determine the number of 35S remaining after 365 days, we'll use the decay law:

N(t) = N₀ * e^(-λt).

Substituting the known values:

\(\[N(365 \, \text{days}) = N_0 \cdot e^{-\lambda \cdot 365}\]\).

Calculate the value of N(365 days) using the previously determined N₀ and λ.

To find the mass of 35S remaining, multiply N(365 days) by the molar mass of 35S.

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