Why are there number in the middles I’m so confused

Why Are There Number In The Middles Im So Confused

Answers

Answer 1

Step-by-step explanation:

The numbers between the squares are the possible answers.

For example, 2/3 ÷ 3/4 is either 1/2 or 8/9.

2/3 ÷ 3/4

2/3 × 4/3

8/9

The answer is 8/9, so you'll move up to the next square.


Related Questions


\(2 |3 \sqrt{2} - 2 \sqrt{3} | + |3 \sqrt{8} - 8 \sqrt{3} | + 2 \sqrt{12} \)
.......................​

Answers

Answer:

hope it helps

Step-by-step explanation:

[tex]2 |3 \sqrt{2} - 2 \sqrt{3} | + |3 \sqrt{8} - 8 \sqrt{3} | + 2 \sqrt{12} [/tex].......................

Answer:

SEE THE IMAGE FOR SOLUTION..

[tex]2 |3 \sqrt{2} - 2 \sqrt{3} | + |3 \sqrt{8} - 8 \sqrt{3} | + 2 \sqrt{12} [/tex].......................

Lynne is rolling a six-sided number cube repeatedly. Her goal is to roll an even number 23 times. How many times should Lynne expect to have to roll the number cube to result in an even number 23 times? Enter your answer in the box to correctly complete the statement

Answers

Using the binomial distribution, it is found that she should expect to roll the number cube 46 times.

What is the binomial probability distribution?

It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.

The expected number of trials until q successes is:

\(E_s(X) = \frac{q}{p}\)

In this problem:

She wants 23 successes, hence q = 23.Of the six numbers on the cube, three are even, hence the probability of a success on a trial is of p = 3/6 = 0.5.

Then:

\(E_s(X) = \frac{23}{0.5} = 46\)

She should expect to roll the number cube 46 times.

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Answer:

answer is 46.

Step-by-step explanation:

ALGEBRA 1 CP

Write the number in decreasing order.

ALGEBRA 1 CPWrite the number in decreasing order.

Answers

Answer: 9/2, 2.63, -2.47, -5sqrt(3), -18

Step-by-step explanation:

Do the following using the given information: Utility function u(x1+x2) = .5ln(x1) + .25ln(x₂) .251 Marshallian demand X1 = - and x₂ = P₂ . Find the indirect utility function . Find the minimum expenditure function . Find the Hicksian demand function wwww

Answers

Hicksian demand functions are:x1** = 2P₁x₂ ; x₂** = P₂²

Utility function: u(x1+x2) = .5ln(x1) + .25ln(x₂) .The Marshallian demand functions are: x1* = - and x₂* = P₂.

The indirect utility function is found by substituting Marshallian demand functions into the utility function and solving for v(P₁, P₂, Y).u(x1*,x2*) = v(P₁,P₂,Y) ⇒ u(-, P₂) = v(P₁,P₂,Y) ⇒ .5ln(-) + .25ln(P₂) = v(P₁,P₂,Y) ⇒ v(P₁,P₂,Y) = - ∞ (as ln(-) is not defined)

Thus the indirect utility function is undefined.

Minimum expenditure function can be derived from the Marshallian demand function and prices of goods:

Exp = P₁x1* + P₂x2* = P₁(-) + P₂P₂ = -P₁ + P₂²

Minimum expenditure function is thus:

Exp = P₁(-) + P₂²

Hicksian demand functions can be derived from the utility function and prices of goods:

H1(x1, P1, P2, U) = x1*H2(x2, P1, P2, U) = x2*

Hicksian demand functions are:

x1** = 2P₁x₂

x₂** = P₂²

If there are no restrictions on the amount of money the consumer can spend, the Hicksian demand functions for x1 and x2 coincide with Marshallian demand functions.

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which of the following give chart elements a realistic, three-dimensional look?A. axisB. chart areaC. legendD. plot area

Answers

The option that gives chart elements a realistic, three-dimensional look is D. Plot Area.

The option that gives chart elements a realistic, three-dimensional look is the plot area. The plot area is the portion of the chart that displays the data points and is typically the main focus of the chart. Adding shading and depth to the plot area, can give the chart a more lifelike appearance and make the data more visually engaging. Additionally, three-dimensional charts can also be created by using specialized charting software that allows for the creation of 3D visualizations. These types of charts can be useful for highlighting patterns and trends in the data, especially when dealing with large datasets.
In a chart, the plot area is the space where the actual data points, bars, lines, or pie slices are displayed. By applying three-dimensional effects to the plot area, you can make the chart elements appear more realistic and visually appealing. This can enhance the viewer's understanding of the data being represented and make the chart more engaging.
In summary, to give chart elements a realistic, three-dimensional look, you should focus on the plot area (Option D). The axis (Option A), chart area (Option B), and legend (Option C) do not directly contribute to creating a three-dimensional appearance for the chart elements.

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A scientist is interested in whether stretching before running 5 kilometers will improve a runner’s time. The scientist decides that an experimental study is the best method to use to answer the question. One group of runners will run a 5-kilometer race without stretching, and a second group of runners will follow a specific stretching routine before running the race. The finishing times will be recorded, along with the group type for each runner.The distribution of times for the group that followed a specific stretching routine before the race is shown. Why is it reasonable to model this distribution with a normal distribution?

A scientist is interested in whether stretching before running 5 kilometers will improve a runners time.

Answers

First, to understand the reason to use a normal distribuition, let's analyse some of it's properties.

The normal distribution is given by the following formula:

\(f(x)\text{ = }\frac{1}{\sigma\sqrt[]{2\pi}}\text{exp\lbrack}\frac{-1}{2}(\frac{x-\mu}{\sigma})^2\text{ \rbrack}\)

The normal distribuition is centered at the mean(given by 'mu' in the equation above) and its growth is controlled by its standard deviation(given by the 'sigma').

It is shaped like a bell(centered, with a gaussian decay, symetric). The data given by the question, have all of those properties. Is centered at the middle with a exponential decay in both 'directions'. Since the data agrees with the gaussian distribution properties, it makes sense to model this distribuition as a normal distribuition.

Please help me please help me please help me

Please help me please help me please help me

Answers

Step-by-step explanation:

solution file attached

Please help me please help me please help me

NEED ASAP!!!
Expand the following using the distributive property.

6(-3w + 1/3)

A) -18w + 2
B) 18w + 2
C) 18w – 2
D) -18w – 2

Answers

Answer:

A

Step-by-step explanation:

6(-3w+1/3)

-18w+2

Answer:

A

Step-by-step explanation:

6(-3w +1/3)

to distribute you multiply everything inside the parentheses by 6

so

6(-3w) + 6(1/3)

-18w + 6/3

-18w +2

fill in the boxes to complete the differences

Answers

Answer:

Ok but

Step-by-step explanation:

give question too

Determine the equation of the line that passes through the (8,-27) and is parallel to the line y = - 3x - 1

Answers

Answer:

The equation parallel to the given equation, and passing through the given point is

y = -3x - 3

Explanation:

Given the line:

y = -3x - 1 ................................................(1)

The slope of this equation is -3

A line parallel to this line has the same slope as this, but a different y-intercept.

Let the parallel line be

y = -3x + b ..............................................(2)

To find the unknown b, we use the given point (8, -27), i.e x = 8, y = -27 into equation (2) and solve for b

-27 = -3(8) + b

-27 = -24 + b

b = -27 + 24

= -3

Substitute the value of b into (2), we have

y = -3x - 3

The scores of 12th-grade students on the national assessment of educational progress year 2000 mathematics test have a distribution that is approximately normal with mean of 300 and standard deviation of 35. a.choose one 12th-grader at random. what is the probability that his or her score is higher than 300

Answers

The probability of randomly selecting a 12th-grader with a score higher than 300 on the 2000 mathematics test is approximately 0.5.

Given that the scores of 12th-grade students on the 2000 mathematics test follow an approximately normal distribution with a mean of 300 and a standard deviation of 35, we can use the properties of the normal distribution to calculate the probability.

To find the probability that a randomly chosen student has a score higher than 300, we need to determine the area under the normal distribution curve to the right of the value 300. This represents the probability of a score being higher than 300.

Using statistical tables or a calculator with a cumulative distribution function for the normal distribution, we can find that the area to the right of 300 is approximately 0.5. This means that there is a 50% probability of selecting a student with a score higher than 300.

The normal distribution is symmetrical around its mean, so the probabilities of being below and above the mean are equal. Since the mean is 300, which is the cutoff point, the probability of a randomly selected student having a score higher than 300 is 0.5 or 50%.

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after euclid high school's last basketball game, it was determined that 1/4 of the team's points were scored by alexa and 2/7 were scored by brittany. chelsea scored 15 points. none of the other 7 team members scored more than 2 points. what was the total number of points scored by the other 7 team members?

Answers

The total number of points scored by the other 7 team members in Euclid high school's last basketball game is 11.

What is defined as the term two variable equation?If an equation is written in the form ax + by + c=0, where a, b, and c are real integers as well as the coefficients of x and y, i.e., a and b, respectively, really aren't equal to zero, then it is said to be a linear function in two variables.

For the given question.

Let 't' be the total points scored.

Alexa = 1/4 t.

Brittany = 2/7 t

Chelsea = 15

Let 'x' be the points scored by remaining 7 team.

Thus, the two variable equation becomes.

1/4 t +  2/7 t + 15 + x = t   .....eq 1

Where, x ≤ 14 ( for 7 terams)

Simplifying eq 1.

15 + x = 13/ 28 t

28x + 28 = 13 t

Now, t must be divisible by 28.

Let t = 28 u, u ≥ 0 and divisible by 28.

Thus,

x + 15 = 13u.

Then, u = 2( t = 56) has been the only candidates for which x = 11.

Thus, the total number of points scored by the other 7 team members is 11.

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In the given figure ABCD, prove that
angleBCD= angleBAD+ angle ABC+angle ADC.
[Hint: Join A and C then extended AC to the point E]​

In the given figure ABCD, prove thatangleBCD= angleBAD+ angle ABC+angle ADC.[Hint: Join A and C then

Answers

We have proved that Angle BCD is equal to angle BAD plus angle ABC plus angle ADC, as required.

To prove that angle BCD is equal to angle BAD plus angle ABC plus angle ADC, we can use the following steps:

Step 1: Join points A and C with a line segment. Let's label the point where AC intersects with line segment BD as point E.

Step 2: Since line segment AC is drawn, we can consider triangle ABC and triangle ADC separately.

Step 3: In triangle ABC, we have angle B + angle ABC + angle BCA = 180 degrees (due to the sum of angles in a triangle).

Step 4: In triangle ADC, we have angle D + angle ADC + angle CDA = 180 degrees.

Step 5: From steps 3 and 4, we can deduce that angle B + angle ABC + angle BCA + angle D + angle ADC + angle CDA = 360 degrees (by adding the equations from steps 3 and 4).

Step 6: Consider quadrilateral ABED. The sum of angles in a quadrilateral is 360 degrees.

Step 7: In quadrilateral ABED, we have angle BAD + angle ABC + angle BCD + angle CDA = 360 degrees.

Step 8: Comparing steps 5 and 7, we can conclude that angle B + angle BCD + angle D = angle BAD + angle ABC + angle ADC.

Step 9: Rearranging step 8, we get angle BCD = angle BAD + angle ABC + angle ADC.

Therefore, we have proved that angle BCD is equal to angle BAD plus angle ABC plus angle ADC, as required.

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Given: Quadrilateral \(\displaystyle\sf ABCD\)

To prove: \(\displaystyle\sf \angle BCD = \angle BAD + \angle ABC + \angle ADC\)

Proof:

1. Draw segment \(\displaystyle\sf AC\) and extend it to point \(\displaystyle\sf E\).

2. Consider triangle \(\displaystyle\sf ACD\) and triangle \(\displaystyle\sf BCE\).

3. In triangle \(\displaystyle\sf ACD\):

- \(\displaystyle\sf \angle ACD = \angle BAD + \angle ADC\) (Angles of a triangle add up to \(\displaystyle\sf 180^\circ\)).

4. In triangle \(\displaystyle\sf BCE\):

- \(\displaystyle\sf \angle BCE = \angle BAD + \angle ABC\) (Angles of a triangle add up to \(\displaystyle\sf 180^\circ\)).

5. Since \(\displaystyle\sf \angle BCE\) and \(\displaystyle\sf \angle BCD\) are corresponding angles formed by transversal \(\displaystyle\sf BE\):

- \(\displaystyle\sf \angle BCE = \angle BCD\).

6. Combining the equations from steps 3 and 4:

- \(\displaystyle\sf \angle BCD = \angle ACD = \angle BAD + \angle ADC\). - \(\displaystyle\sf \angle BCD = \angle BCE = \angle BAD + \angle ABC + \angle ADC\).

Therefore, we have proven that in quadrilateral \(\displaystyle\sf ABCD\), \(\displaystyle\sf \angle BCD = \angle BAD + \angle ABC + \angle ADC\).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

using the function below what is f(-2)​

using the function below what is f(-2)

Answers

The numeric value of x at x = -2 is given as follows:

f(-2) = 9.

How to obtain the numeric value of a function or of an expression?

To obtain the numeric value of a function or of an expression, we substitute each instance of any variable or unknown on the function by the value at which we want to find the numeric value of the function or of the expression.

In this problem, we have a piece-wise function, which is a function with different definitions based on the input of the function.

x = -2 is less than 1, hence the definition at x = -2 is given as follows:

f(x) = -4x + 1.

The numeric value is then given as follows:

f(-2) = -4(-2) + 1

f(-2) = 9.

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The force exerted by an electric charge at the origin on a charged particle at a point (x,y,z) with position vector r = (x,y,z) is F(r) =Kr/||r||^3. Where k is a constant. Find the work done as the particle moves along a straight line from (2, 0, 0) to (2,3,5)

Answers

To find the work done, we need to integrate the force F(r) along the path that the particle moves. Since the path is a straight line, we can parametrize it as r(t) = (2, 0, 0) + t((2,3,5)-(2,0,0)) = (2+2t, 3t, 5t),

where 0 <= t <= 1.

Then, the force F(r(t)) is given by F(t) = K(2+2t, 3t, 5t)/[(2+2t)^2 + (3t)^2 + (5t)^2]^(3/2).

The work done by the force as the particle moves from (2,0,0) to (2,3,5) is given by the line integral:

W = ∫ F(r(t)) · dr(t) from t=0 to t=1

where dr(t) is the differential of r(t) with respect to t.

Now, we need to evaluate the dot product F(r(t)) · dr(t).

Note that dr(t) = (2,3,5) dt, since the path is a straight line.

Therefore: F(r(t)) · dr(t) = K(2+2t, 3t, 5t)/[(2+2t)^2 + (3t)^2 + (5t)^2]^(3/2) · (2,3,5) dt

= K(2+2t)(2) + 3t(3) + 5t(5) / [(2+2t)^2 + (3t)^2 + (5t)^2]^(3/2) dt

= K(4+4t + 9t + 25t) / [(2+2t)^2 + (3t)^2 + (5t)^2]^(3/2) dt

= 38Kt / [(2+2t)^2 + (3t)^2 + (5t)^2]^(3/2) dt

Thus, the work done is:

W = ∫ F(r(t)) · dr(t) from t=0 to t=1

= ∫0^1 38Kt / [(2+2t)^2 + (3t)^2 + (5t)^2]^(3/2) dt

This integral is difficult to solve exactly, so we can use numerical methods or software to obtain an approximation.

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gursoy is selling christmas trees. she purchases trees for $10 and sells for $25 each. the number of trees she can sell is normally distributed with a mean of 100 and standard deviation of 30. how many trees should gursoy purchase?

Answers

Gursoy's purchase level should be 0.3.

According to the given data, we have the following:

Mean demand, μ = 100

Standard deviation, σ = 30

Purchase price = $10

Selling price = $25

Hence, Cost of under-ordering, Cu = $25 - $10 =$15

Cost of over-ordering, Co = $10 + $25 =$35

Therefore, the calculation of optimal purchase level is calculated as follows:

purchase level = Cu / (Cu + Co)

purchase level = $15 / ($15 + $35)

purchase level = $15 / $50

purchase level = 0.3

The purchase level would be 0.3.

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Let x be a random variable that represents white blood cell count per cubic milliliter of whole blood. Assume that x has a distribution that is approximately normal, with mean μ = 7500 and estimated standard deviation σ = 1750. A test result of x < 3500 is an indication of leukopenia. This indicates bone marrow depression that may be the result of a viral infection. (a) What is the probability that, on a single test, x is less than 3500? (b) Suppose a doctor uses the average x(sample mean) for two tests taken about a week apart. What can we say about the probability distribution of x(sample mean)? What is the probability distribution of x(sample mean) < 3500? (c) Repeat part (b) for n = 3 tests taken a week apart. (d) Compare your answers to parts (a), (b), and (c). How did the probabilities change as n increased? The probabilities increased as n increased. If a person had x ( sample mean)< 3500 based on three tests, what conclusion would draw as a doctor or nurse?

Answers

The sample size increases, the probability of obtaining a sample mean less than 3500 decreases. The mean of the sample mean distribution is equal to the population mean, which is 7500.

a) The probability that, on a single test, x is less than 3500 can be calculated using the standard normal distribution. We need to standardize the value using the z-score formula: z = (x - μ) / σ. Substituting the given values, we get z = (3500 - 7500) / 1750 ≈ -2.286.

Using a standard normal distribution table or a calculator, we can find the probability associated with a z-score of -2.286. The probability is approximately 0.0116, or 1.16%. Therefore, there is a 1.16% chance that a single test result will be less than 3500, indicating leukopenia.

(b) When the doctor uses the average x (sample mean) for two tests taken about a week apart, the probability distribution of x (sample mean) follows a normal distribution. The mean of the sample mean distribution is equal to the population mean, which is 7500. The standard deviation of the sample mean distribution is equal to the population standard deviation divided by the square root of the sample size. In this case, the sample size is 2.

The probability distribution of x (sample mean) < 3500 can be calculated by standardizing the value using the z-score formula and then finding the corresponding probability from the standard normal distribution table or a calculator. With two tests, the probability distribution will be narrower compared to a single test. The exact probability depends on the specific value of the sample mean and the standard deviation of the sample mean distribution.

(c) When considering three tests taken a week apart, the process is similar to part (b). The mean of the sample mean distribution remains the same at 7500, but the standard deviation of the sample mean distribution is now divided by the square root of 3, since the sample size is 3. As the sample size increases, the standard deviation of the sample mean distribution decreases, resulting in a narrower distribution.

The probability distribution of x (sample mean) < 3500 can be calculated using the z-score formula and finding the corresponding probability from the standard normal distribution table or a calculator. With three tests, the probability distribution will be even narrower compared to two tests.

In summary, as the sample size increases, the probability of obtaining a sample mean less than 3500 decreases. With more tests, we can have greater confidence in the accuracy of the sample mean and draw stronger conclusions about the individual's condition. If a person had a sample mean less than 3500 based on three tests, it would indicate a higher level of certainty about the presence of leukopenia, potentially leading to further investigation or treatment options.

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help me plz 10 points

help me plz 10 points

Answers

Answer:

580 cm

Step-by-step explanation:

To find the surface area you just need to find the area of every side of the box and add them together.

SO- the equation for this would be

SA (Surface Area) = 2(20 x 10) + 2(20 x 3) + 2(10 x 3)

SA = 2(200) + 2(60) + 2(30)

SA = 400 + 120 + 60

SA = 520 + 60

SA = 580

Write the function below in the form y = f(u) and u = g(x), then find dy/dx as a function of x. y = cos (sin x) What are the functions f(u) and g(x)? f(u) = g(x) =

Answers

The function of f(u) = cos(u)` and `g(x) = sin x`.

We are to write the function `y = cos(sin x)` below in the form `y = f(u)` and `u = g(x)`.

Then, we need to find `dy/dx` as a function of `x`.

Function `y = cos(sin x)` can be written as: `y = f(u)`, where `u = sin x` and `f(u) = cos(u)`.

Thus, `f(u) = cos(sin x)` and `u = sin x`.

Hence, `f(u) = cos(u)` and `g(x) = sin x`.

Now, we can apply the chain rule of differentiation to find `dy/dx` as a function of `x`.

The chain rule states that if `y = f(u)` and `u = g(x)`, then `dy/dx = dy/du * du/dx`.

Here, `f(u) = cos(u)` and `g(x) = sin x`. Thus, `dy/du = -sin(u)` and `du/dx = cos x`.

Therefore, `dy/dx = dy/du * du/dx = -sin(u) * cos x = -sin(sin x) * cos x`.

Thus, `dy/dx = -sin(sin x) * cos x`.

Hence, the functions `f(u)` and `g(x)` are: `f(u) = cos(u)` and `g(x) = sin x`.

Therefore, we have `y = cos(sin x)` in the form `y = f(u)` and `u = g(x)`.

Finally, `dy/dx` as a function of `x` is `-sin(sin x) * cos x`.

Thus, `f(u) = cos(u)` and `g(x) = sin x`.

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what is 1.4×0.2×1.8=can you pls show how you slove it

Answers

In order to calculate the value of the expression 1.4 * 0.2 * 1.8, first let's calculate the product of the first two numbers.

To multiply 1.4 by 0.2, we can first multiply 1.4 by 2 and then divide the result by 10:

\(\begin{gathered} 1.4\cdot2=2.8 \\ 2.8\colon10=0.28 \end{gathered}\)

Now we can calculate the product of 0.28 and 1.8.

To do so, we can multiply 0.28 by 18 and then divide the result by 10:

\(\begin{gathered} 0.28\cdot18=5.04 \\ 5.04\colon10=0.504 \end{gathered}\)

So the final result of the expression is 0.504.

plzzzzz helpppppp!!! ( Write an equation of the line in slope-intercept form)

plzzzzz helpppppp!!! ( Write an equation of the line in slope-intercept form)

Answers

Answer:

3. y = 2x - 2

4. y = \(\frac{4}{3}x-1\)

Step-by-step explanation:

3. Slope = 2

Y-intercept = -2

4. Slope = \(\frac{4}{3}\)

Y-intercept = -1

Answer:

3). y = 2x - 2

4). y = (4/3)x - 1

Step-by-step explanation:

3).

First find the slope

(y2 - y1) / (x2 - x1)  or rise/run

(0 - (-2)) / (1 - 0) = 2

2 is your slope

Now use the equation below for using coordinates for finding slope intercept form.

y - y1 = m(x - x1)

y1 = y number of given coordinate

x1 = x number of given coordinate

m = slope

y - 0 = 2(x - 1)

Distribute

y - 0 = 2x + (-2)

Get y by itself by adding 0 to both sides.

y - 0 = 2x + (-2)

  +0           +0

y = 2x - 2

4).

Repeat the same process for 4 as done in 3

Find the slope

(y2 - y1) / (x2 - x1)  or rise/run

(3 - (-1)) / (3 - 0) = 4/3

4/3 is your slope

Now use the equation below for using coordinates for finding slope intercept form.

y - y1 = m(x - x1)

y1 = y number of given coordinate

x1 = x number of given coordinate

m = slope

y - 3 = (4/3)(x - 3)

Distribute

y - 3 = (4/3)x + (-4)

Get y by itself by adding 3 to both sides.

y - 3 = (4/3)x + (-4)

  +3                  +3

y = (4/3)x - 1

Q: Marci wants to prove that the diagonals of
a rectangle are congruent. Which of these
procedures would be best for Marci to use
to write a correct proof?

a) She should use the fact that the
diagonals of a square are perpendicular
and then use the triangle-angle-sum
theorem.

b) She should use the fact that the
opposite sides of a parallelogram are
congruent and then use the
Pythagorean theorem.

c) She should use the fact that the
opposite angles of a parallelogram are
congruent and then use triangle
similarity relationships.

d) She should use the fact that the
diagonals of a parallelogram bisect the
angles of the parallelogram and then
use triangle congruence relationships.

Answers

Answer: Option B

She should use the fact that the

opposite sides of a parallelogram are

congruent and then use the

Pythagorean theorem.

We cannot use the diagonals of square property because this is a rectangle, opposite angles will also not work, and we cannot use the diagonal property because thats what we have to prove.

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find :- a) 7.9 ÷ 1000
b ) 26.3 ÷ 1000
c) 38.53 ÷ 1000

all of the questions are separated, explain with the steps, according to class 7 , ch - 2 Fractions and Decimals......​

Answers

Answer:

The solution is given below.

Step-by-step explanation:

Given that

a) 7.9 ÷ 1000

b ) 26.3 ÷ 1000

c) 38.53 ÷ 1000

We need to find out their answers

So,

for a)

= 7.9 ÷ 1000

= 0.0079

b)

= 26.3 ÷ 1000

= 0.0263

c)

= 38.53 ÷ 1000

= 0.03853

Basically we divided the number and it comes in decimal form

Helen is typing a report and is using two different sizes of fonts, as shown below. What is the ratio of the height of a letter typed using font I to the height of a letter typed using font II?
2/9
1/3
3
9
WILL RECIEVE BRAINLIST

Answers

Tff coo I FTC con got a CFC fav. Tvtttttv gggt

Answer: 2/9

Step-by-step explanation:

Solve for r. r - 76 = 9​

Answers

Answer:

r=85

Step-by-step explanation:

r-76=9

add 76 to both sides

r=85

hope this is helpful

Answer: 85

Step-by-step explanation:

Since we're finding the placeholder of r and we're already subtracting, we need to add! What we need to do is add 76 + 9 which equals 85!

Hope this helps you! Good luck with your future work!

How does line EF relate to line AC?

How does line EF relate to line AC?

Answers

Answer:

they both have the same angles

Step-by-step explanation:

Convert 2 ½ to mass in grams

Answers

The value of 2 1/2 kilograms to mass in grams is 2500 grams

How to determine the value

To determine the value of the mass in grams, we need to know the conversion factor is;

1 gram = 1000 kilograms

1 ounce=  28.3495 grams.

1 ounce =  0.028 kilogram

From the information given, we have that;

2 1/2 kilogram kilogram is;

2. 5 kg

If 1000grams = 1 kilogram

Then x grams = 2.5 kilograms

Cross multiply the values, we have;

x = 2.5(1000)

Multiply the values, we have;

x = 25000 grams

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Complete question:

Convert 2 ½ kilograms to mass in grams

3/4-3/10
In simplest form and they are fractions

Answers

Answer:

Let's establish that the LCM between the two is 20, so now we need to multiply our numerators by the same numbers used to multiply the denominators.

3(5)/20 - 3(2)/20 = (15-6)/20 = 9/20

What is the y value of the solution to the system of equations 3x 5y 17x 4y − 13?.

Answers

So, the y-value of the solution to the system of equations 3x + 5y = 17 and 4x + 4y = -13 is not possible to find, because the system is inconsistent and has no solution.

To find the y-value of the solution to the system of equations 3x + 5y = 17 and 4x + 4y = -13, we can use one of the methods for solving systems of equations, such as substitution, elimination, or graphing. In this case, we will use elimination method.

The first step of elimination method is to eliminate one of the variables by adding or subtracting the equations. In this case, we will multiply the first equation by 4 and the second equation by -3 and add them:

4(3x + 5y) = 4(17)

12x + 20y = 68

-3(4x + 4y) = -3(-13)

-12x - 12y = 39

then we can add these two equations:

12x + 20y = 68

-12x - 12y = 39

0 = 29

This is an impossible equation, which means that the system has no solution.

Therefore, the y value of the solution to the system of equations 3x + 5y = 17 and 4x + 4y = -13 is not possible to find, because the system is inconsistent and has no solution.

To learn more about Y-intercept

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Two coins are tossed and a number cube (dice) is rolled. How many outcomes are
possible?
A. 24
B. 18
C. 12
D. 10

Answers

Answer:

C

Step-by-step explanation:

I tried my best, The coin has 2 outcomes and the dice has 6 so 6 times 2 is 12

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