The markup on retail is 47%. The correct option is c.
he markup on retail price is calculated to determine the percentage increase from the wholesale price to the retail price. In this case, the wholesale price is $17 and the retail price is $25. By subtracting the wholesale price from the retail price ($25 - $17),
we find that the markup is $8. Dividing this markup by the wholesale price ($8 / $17) gives us a ratio. Multiplying this ratio by 100 converts it to a percentage, which is approximately 47.06%.
This means that the retail price is approximately 47% higher than the wholesale price. Option c, 47%, correctly represents the calculated markup on the retail price.
Therefore, the markup on retail is 47%, so the answer is (c).
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Select two trigonometric functions that are equivalent to the ratio x/y.
I NEED THE ANSWER ASAP
Answer:
A,B,D, and E?
Step-by-step explanation:
Rebecca carries a balance on her credit card each month. Today is the first day of the new. 28-day billing cycle. The current balance is x and the APR is 24%.
Rebecca is buying a friend an expensive gift that costs $1,400 that she plans to put on her credit card. This will be her only purchase this month. Sed she will be
making this purchase on the last day of the month. Part A if her finance charge will be $51 write and solve an equation to determine her current balance on her credit card show your work. Part B How much in finance charges can she save by making the purchase on the last day of the billing cycle
Part A: Rebecca's credit card balance can be calculated using the equation x = (51 - 1) 0.02 if her finance charge is $51.
Part B: By making the purchase on the final day of the billing cycle rather than the first day, Rebecca will be able to avoid paying $27 in finance charges.
How do equations work?
A mathematical statement proving the equality of values between two or more mathematical expressions is called an equation.
Equation symbols (=) are used to represent equations.
A finance charge is what?
The interest and other fees levied on credit cards are included in a finance charge.
Typically, the finance charge is based on a stated APR (annual percentage rate).
The month's billing cycle lasts for 28 days.
Balance at current starting = x.
APR = 24%, or annual percentage rate.
The monthly percentage rate (MPR) equals 2% (24% divided by 12).
The final day's purchase cost $1,400.
$51 is the total finance fee for the month.
($1,400 x 2% x 1/28) = $1 finance fee for the last-minute purchase.
$50 ($51 - $1) serves as the initial balance's finance charge.
The starting balance at this time is x = $2,500 ($50 x 2%).
Current Beginning Balance Equation: x = 51 - 1 0.02
($1,400 x 2%) Equals $28 in total loan charges for the last-minute purchase.
Finance charge savings from buying on the last day equals $27 ($28 - $1).
By buying the $1,400 gift for her friend on the last day of the billing cycle rather than the first, Rebecca can avoid paying $27 in finance charges.
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bolivian coffee sells for $4.59 per pound, and colombian coffee sells for $5.95 per pound. how many pounds of each coffee should be mixed to produce 4000 pounds of mixture that will sell for $5.10 per pound?: * a) bolivian: 2500 pounds; columbian: 1500 pounds b) bolivian: 2000 pounds; columbian: 2000 pounds c) bolivian: 2250 pounds; columbian: 1750 pounds d) bolivian: 1500 pounds; columbian: 2500 pounds e) bolivian: 1000 pounds; columbian: 3000 pounds
The required pounds of Bolivian coffee and Colombian coffee are 2500 and 1500 respectively.
How we use the linear equation of two variable to solve this problem?
A equation is supposed to be linear equation in two factors in the event that it is written as ax + by + c=0, where a, b and c are genuine numbers and the coefficients of x and y, i.e an and b separately, are not equivalent to nothing. For instance, 10x+4y = 3 and - x+5y = 2 are direct conditions in two factors.
According to question:Let x be the pound of Bolivian coffee and y is that of Colombian coffee.
Bolivian coffee sells for $4.59 per pound, and Colombian coffee sells for $5.95 per pound and whole mixture sells for $5.10.
So, 4.59x + 5.95y = 5.10(4000)
4.59x + 5.95y = 20400--------------------(1)
and x + y = 4000-----------------------------(2)
On solving above two equation, we get
x = 2500 pounds and y = 1500 pounds
Thus, required pounds of two coffees are 2500 and 1500.
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You are given the coordinates of a triangle and
coordinates for only one of the vertices of its image
under a translation, Explain how to translate the entire
trangle
Answer:
Find translation Using the coordinates of the given image with corresponding vertices coordinate of the object. After getting the translation,find the coordinates of the two other vertices of the image from formula IMAGE=OBJECT + TRANSLATION
Answer:
Translations move every point on a figure the same distance and direction. You can use the one vertex and its image to find the rule that maps the triangle to its image. This rule can then be used to find the images of the other vertices of the triangle. Plot the vertices and connect them to form the image of the triangle.
Step-by-step explanation:
How do I find the triangular formula of a pentagon
It is not possible to find the triangular formula of a pentagon because a pentagon is a polygon with five sides and does not have a triangular formula.
We have,
A triangular formula is used to calculate the area of a triangle, which is a polygon with three sides.
The formula for the area of a triangle is given by:
Area = 1/2 x base x height
where the base and height are two of the sides of the triangle.
If you want to calculate the area of a pentagon, you can use the formula for the area of a regular pentagon, which is given by:
Area = (5/4) x s² x tan(π/5)
where s is the length of one of the sides of the Pentagon.
Thus,
It is not possible to find the triangular formula of a pentagon because a pentagon is a polygon with five sides and does not have a triangular formula.
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John read the first 114 pages of a novel, which was 3 pages less than 1/3 of the novel.
Answer:
114 plus 3 = 117 (one-third of the novel)
117 x 3 = p = 351 (entire novel)
If the lengths of the sides of triangle abc are 4, 5, and 7 feet, what is the perimeter in feet of similar triangle def whose shortest side is 12 feet?
Given,
ΔABC and ΔDEF are similar triangles.
AB = 6 feet, BC = 4 feet, AC = 7 feet
Let the shortest side of ΔDEF be EF = 12 feet.
Let DE = x and DF = y
Since, ΔABC and ΔDEF are similar,
\(\frac{BC}{EF}\) = \(\frac{AB}{DE} = \frac{AC}{DF}\)
⇒ \(\frac{4}{12} = \frac{6}{x} =\frac{5}{y}\)
On Solving,
x = 18 feet and y = 15 feet
We know,
Perimeter of a triangle = sum of all three sides
Hence, perimeter of ΔDEF = DE + EF + DF = 18 + 15 + 12 = 45 feet.
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write the rational number as a decimal, and state whether the decimal is repeating or terminating. question content area bottom part 1 choose the equivalent decimal. a. 0. b. 0. c.0. 16 overbar d. 0.
a. The decimal is terminating and the rational number is 0.
b. The decimal is terminating and the rational number is 0.
c. The decimal is repeating and the rational number is 0.161616...
d. The decimal is terminating and the rational number is 0.
To write a rational number as a decimal, you need to divide the numerator by the denominator. Let's go through each option to determine which decimal is repeating or terminating.
a. 0: This decimal is terminating because there are no numbers after the decimal point. The rational number is 0.
b. 0: This decimal is also terminating because there are no numbers after the decimal point. The rational number is 0.
c. 0.16 overbar: This decimal has a line over the 16, indicating that it is repeating. The rational number is 0.161616...
d. 0: This decimal is terminating because there are no numbers after the decimal point. The rational number is 0.
So, to summarize:
a. The decimal is terminating and the rational number is 0.
b. The decimal is terminating and the rational number is 0.
c. The decimal is repeating and the rational number is 0.161616...
d. The decimal is terminating and the rational number is 0.
.
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Y²+ 6y+5 Factorize And Explain
Answer:
(y+1)(y+5)
Step-by-step explanation:
For each linear equation write the slope of a line parallel to the given line. 3x - 2y = 8
We first need to convert 3x - 2y = 8 into y = mx + b form.
To do this, we first subtract 3x from
both sides and we have -2y = -3x + 8.
Now divide both sides by -2 and we have y = 3/2x - 4.
Now, we want the slope parallel to this given line.
Since the m or the coefficient of the x term
represents slope, we know this line has a slope of 3/2.
Now, it's important to understand that parallel lines have the same slope.
So the slope of the line parallel to this line will also be 3/2.
2. find f(1), f(2), f(3), f(4), and f(5) if f(n) is defined re- cursively by f(0) = 3 and for n = 0, 1, 2, … a) f(n + 1) = −2f(n). b) f(n + 1) = 3f(n) + 7. c) f(n + 1) = f(n)2 − 2f(n) − 2. d) f(n + 1) = 3f(n)∕3.
Here are the values of f(1), f(2), f(3), f(4), and f(5) for each recursive definition:
a) \(\[f(1) = -6, \quad f(2) = 12, \quad f(3) = -24, \quad f(4) = 48, \quad f(5) = -96\]\)
b) \(\[f(1) = 16, \quad f(2) = 55, \quad f(3) = 172, \quad f(4) = 523, \quad f(5) = 1576\]\)
c) \(\[f(1) = 1, \quad f(2) = -3, \quad f(3) = 11, \quad f(4) = 107, \quad f(5) = 11365\]\)
d) \(\[f(1) = 3, \quad f(2) = 3, \quad f(3) = 3, \quad f(4) = 3, \quad f(5) = 3\]\)
a) Recursive definition: \(\(f(n + 1) = -2f(n)\)\)
To find \(\(f(1)\)\), we use the initial condition \(\(f(0) = 3\)\) and apply the recursive definition:
\(\[f(1) = -2f(0) = -2 \cdot 3 = -6\]\)
To find \(\(f(2)\)\):
\(\[f(2) = -2f(1) = -2 \cdot (-6) = 12\]\)
Similarly, we can continue applying the recursive definition to find \(\(f(3)\), \(f(4)\), and \(f(5)\)\):
\(\[f(3) = -2f(2) = -2 \cdot 12 = -24\]\)
\(\[f(4) = -2f(3) = -2 \cdot (-24) = 48\]\)
\(\[f(5) = -2f(4) = -2 \cdot 48 = -96\]\)
b) Recursive definition: \(\(f(n + 1) = 3f(n) + 7\)\)
Using the initial condition \(\(f(0) = 3\):\)
\(\[f(1) = 3f(0) + 7 = 3 \cdot 3 + 7 = 16\]\)
To find \(\(f(2)\)\):
\(\[f(2) = 3f(1) + 7 = 3 \cdot 16 + 7 = 55\]\)
Continuing in the same manner:
\(\[f(3) = 3f(2) + 7 = 3 \cdot 55 + 7 = 172\]\)
\(\[f(4) = 3f(3) + 7 = 3 \cdot 172 + 7 = 523\]\)
\(\[f(5) = 3f(4) + 7 = 3 \cdot 523 + 7 = 1576\]\)
c) Recursive definition: \(\(f(n + 1) = f(n)^2 - 2f(n) - 2\)\)
Using the initial condition \(\(f(0) = 3\)\)
\(\[f(1) = f(0)^2 - 2f(0) - 2 = 3^2 - 2 \cdot 3 - 2 = 1\]\)
To find \(\(f(2)\):\)
\(\[f(2) = f(1)^2 - 2f(1) - 2 = 1^2 - 2 \cdot 1 - 2 = -3\]\)
Continuing in the same manner:
\(\[f(3) = f(2)^2 - 2f(2) - 2 = (-3)^2 - 2 \cdot (-3) - 2 = 11\]\)
\(\[f(4) = f(3)^2 - 2f(3) - 2 = 11^2 - 2 \cdot 11 - 2 = 107\]\)
\(\[f(5) = f(4)^2 - 2f(4) - 2 = 107^2 - 2 \cdot 107 - 2 = 11365\]\)
d) Recursive definition: \(\(f(n + 1) = \frac{{3f(n)}}{3}\)\)
Using the initial condition \(\(f(0) = 3\):\)
\(\[f(1) = \frac{{3f(0)}}{3} = \frac{{3 \cdot 3}}{3} = 3\]\)
Since the recursive definition is \(\(f(n + 1) = \frac{{3f(n)}}{3}\)\), the value of \(\(f(n)\)\) remains constant as 3 for all values of \(\(n\)\). Hence, \(\(f(2)\), \(f(3)\), \(f(4)\),\) \(\(f(5)\),\) the value will be 3.
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Determine the domain and range of the function f(x) = â€""|x| 2. The domain of the function is. The range of the function is.
The domain of the function f(x) = |x|² is the set of all real numbers (-∞ < x < ∞)
The range of the function f(x) = |x|² is the set of all real numbers greater than or equal to zero ( f(x) ≥ 0)
The given function is:
f(x) = |x|²
This can also be expressed as:
f(x) = x²
This is because the square operator cancels the effect of the absolute value
The function f(x) = x² is valid for all real values of x. Therefore, the domain of the function f(x) is -∞ < x < ∞
The range of the function f(x) is all positive real numbers. This is because the square of all numbers gives a positive number.
Range = f(x) ≥ 0
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Answer:
1. all the real numbers
2. all numbers less than or equal to 2.
Step-by-step explanation:
A music store marks up the instruments it sells by 30%.
1. If the store brought a guitar for $45, what will be the amount of the mark up?
Answer: They will mark it up 13.5$ to 58.5$
Step-by-step explanation:
45 x .3 = 13.5
45 + 13.5 = 58.5
Answer:
The mark up will be 13.5
Step-by-step explanation:
Find the discount and the selling price, when:
(ii) the printed price =₹12750, discount= 25/3%
Answer:
12,741.66666
Step-by-step explanation:
12750 - 25/3%
= 12,741.66666
according to survey data, what percentage of recruiters review the social profile of a candidate for a job? group of answer choices approximately 30% approximately 90% approximately 60%
According to survey data, approximately 90% of recruiters review the social profile of a candidate for a job.
This means that the majority of recruiters, about 90%, look at the social media accounts of potential candidates.
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Which equation of a line is parallel to y=4/5x-1?
a. y=4/5x+2
b. y= -5/4x-1
c. y= -4/5x+3
d. y=5/4x-6
Answer:
a
Step-by-step explanation:
you need to have same kx for lines to be parallel.
y=kx+l
l is where the line is going through ordinate and it doesn't matter, but the kx has to be the same
Patrick is using layers of colored sand in an art project. He divides 2 ·· 3 lb of
blue sand into 3 equal parts in order to make 3 layers.
a. What is the weight of the sand in each layer of blue sand? Show your work.
b. Check your answer to problem 3a. Show your work
The calculated weight of the blue sand matches the total weight of the blue sand, confirming that our answer in problem 3a is correct. Each layer of blue sand weighs approximately 0.7667 lb.
a. To find the weight of the sand in each layer, we divide the total weight of the blue sand (2.3 lb) by the number of layers (3):
Weight of each layer = Total weight of blue sand / Number of layers
Weight of each layer = 2.3 lb / 3
Weight of each layer ≈ 0.7667 lb (rounded to four decimal places)
Therefore, the weight of the sand in each layer of blue sand is approximately 0.7667 lb.
b. To check our answer from problem 3a, we can multiply the weight of each layer (0.7667 lb) by the number of layers (3) and see if it equals the total weight of the blue sand (2.3 lb):
Weight of each layer × Number of layers = Total weight of blue sand
0.7667 lb × 3 = 2.3 lb
2.3 lb ≈ 2.3 lb
The calculated weight of the blue sand matches the total weight of the blue sand, confirming that our answer in problem 3a is correct. Each layer of blue sand weighs approximately 0.7667 lb.
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1
Select the correct answer from each drop-down menu.
Consider triangle ABC shown on the graph.
-8 -6 -4 -2
8
6-
4
2-
O
-2-
-4-
-6
-8
A
2B 4
27
C
-6
8
Side lengths and angle measures will be preserved when AABC is
Side lengths are not preserved when AABC is
First box (dilated by a scale factor of 1/2- reflected across the y-axis - stretched vertically by a scale factor of 2)
Second box ( dilated by a scale factor of 1 - rotated 90° clockwise about the origin - dilated by a scale factor of 3)
A dilation of a triangle is a transformation that changes the size of the triangle but preserves its shape. It involves multiplying the coordinates of each vertex by a scale factor, which is a non-negative number. The scale factor determines how much the triangle is enlarged or reduced.
Hence a scale factor different of 1 changes the side lengths of the figure, representing a compression if the scale factor has an absolute value less than 1 and a stretch if the scale factor has an absolute value greater than 1.
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Step-by-step explanation:
A university professor does not believe that there is really a difference between the GPA of male and female scholarship athletes, so he looks into how the sample was collected. His investigation shows that the study was given to all of the athletes on the basketball teams exclusively. Based on this information, should the university administration trust the results from this study?
a. Yes, because the results were significant
b. Yes, because a large enough sample was taken
c. No, because not every scholarship athlete part of the study
d. No, because the study was not taken from a random sample of scholarship athletes
Answer: d. No, because the study was not taken from a random sample of scholarship athletes.
Step-by-step explanation:
Since the study only focuses on basketball players, the sample may not be representative of all scholarship athletes in the university. This can cause bias in the results and make it difficult to generalize the findings to the larger population of scholarship athletes. Therefore, the university administration should not fully trust the results of this study.
Find the midpoint of CD.
An23
Step-by-step explanation:
Answer:
The midpoint is (1 ,-7/2).
Step-by-step explanation:
I just followed the equation listed, hope this helps!
Take the first 4 digits of your student number as the first number and the last 3 digits as the second number. Write the matlab code to find the greatest common divisor of these numbers using the Euclidean algorithm.
The required Matlab code to find the greatest common divisor of a number using the Euclidean algorithm is shown.
To find the greatest common divisor (GCD) of two numbers using the Euclidean algorithm in MATLAB, you can use the following code:
% Replace '12345678' with your actual student number
studentNumber = '12345678';
% Extract the first 4 digits as the first number
firstNumber = str2double(studentNumber(1:4));
% Extract the last 3 digits as the second number
secondNumber = str2double(studentNumber(end-2:end));
% Find the GCD using the Euclidean algorithm
gcdValue = gcd(firstNumber, secondNumber);
% Display the result
disp(['The GCD of ' num2str(firstNumber) ' and ' num2str(secondNumber) ' is ' num2str(gcdValue) '.']);
Make sure to replace '12345678' with your actual student number. The code extracts the first 4 digits as the first number and the last 3 digits as the second number using string indexing. Then, the gcd function in MATLAB is used to calculate the GCD of the two numbers. Finally, the result is displayed using the disp function.
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A triangle has side lengths of 13, 9, and 5. Is this a right triangle?
Answer:
no
Step-by-step explanation:
a^2+b^2 = c^2
Lance bought 15 sets of 3 tennis balls. Some of the tennis balls, t, were lost during each of the 4 matches he played. Now, the are 37 tennis balls left. Which equation represents this situation?
The sum of two numbers is 50 and twice the sum of money the number is 100.Make a pair of equations and solve them to find the numbers.
Answer:
Step-by-step explanation:
Let us represent
First number = x
Second number = y
The sum of two numbers is 50
Hence:
x × y = 50
xy = 50..... Equation 1
x = 50/y
Twice the sum of money the number is 100.
2(x + y) = 100
2x + 2y = 100...... Equation 2
We substitute 50/y for x in Equation 2
2(50/y) + 2y = 100
100/y + 2y = 100
Multiply through by y
100/y × y + 2y × y = 100 × y
100 + 2y² = 100y
Hence:
2y² - 100y + 100
is -x - 3 the same thing as x+3
please help I forgot
Answer: no it ain't
Step-by-step explanation:
let's substitute
-1-3 = -4
1+3 = 4
so like yea
musicians need to be able to discern frequencies which are quite near each other. assume that the average musician can differentiate between frequencies that vary by only 0.6%. this corresponds to about 1/10 of the frequency difference between neighboring notes in the middle of the piano keyboard.
Musicians need to have the ability to discern frequencies that are very close to each other in order to accurately distinguish between different notes and tones in music.
In this context, it is assumed that the average musician can differentiate between frequencies that vary by only 0.6%. This means that they can perceive a difference of 0.6% in frequency between two sounds. To put this into perspective, let's consider the piano keyboard. The frequency difference between neighboring notes in the middle of the piano keyboard is divided into 12 equal parts, corresponding to the 12 semitones in an octave. Therefore, if we divide the frequency difference between neighboring notes by 12, we get the frequency difference between each semitone. Given that musicians can discern frequencies that vary by 0.6%, which is approximately 1/10 of the frequency difference between neighboring notes, we can conclude that they have a highly developed sense of pitch and can detect even the smallest variations in frequency.
In conclusion, musicians possess the ability to discern frequencies that are very close to each other, allowing them to accurately differentiate between different notes and tones in music.
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how many significant figures should be retained in the result of the following calculation:
12.00000 x 0.9893 + 13.00335 x 0.0107
To find the average value of the function f(x, y) = 8x + 5y over the given triangle, we need to calculate the double integral of f(x, y) over the region and then divide it by the area of the triangle.
The vertices of the triangle are (0, 0), (2, 0), and (0, 7). We can set up the integral as follows:
∬R f(x, y) dA = ∫₀² ∫₀ᵧ (8x + 5y) dy dx
Integrating with respect to y first, the inner integral becomes:
∫₀ᵧ (8x + 5y) dy = 8xy + (5y²/2) |₀ᵧ = 8xᵧ + (5ᵧ²/2)
Now integrating with respect to x, the outer integral becomes:
∫₀² (8xᵧ + (5ᵧ²/2)) dx = (4x²ᵧ + (5ᵧ²x)/2) |₀² = (8ᵧ + 10ᵧ² + 20ᵧ)
To find the area of the triangle, we can use the formula for the area of a triangle: A = (1/2) * base * height.
The base of the triangle is 2 and the height is 7.
A = (1/2) * 2 * 7 = 7
Finally, to find the average value, we divide the double integral by the area of the triangle:
Average value = (8ᵧ + 10ᵧ² + 20ᵧ) / 7
Simplifying this expression gives:
Average value = (8 + 10ᵧ + 20ᵧ) / 7 = (8 + 10(7) + 20(7)) / 7 = 142/7 = 20 2/7
Therefore, the correct answer is not listed among the options provided.
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Solve the equation
using square roots.
Round your solutions to
the nearest hundredth.
x² + 11 = 24
Answer:
3.606
Step-by-step explanation:
ur solving for x
:)
Help solve this math problem
Check the picture below.
so let's do this one a bit oddly kinda.
we know AB is a diameter, that means the arc made by AB is simply 180°, so the arcs AE + ED + DB = 180°.
By the inscribed angle theorem, as you see there, the arcDB is simply 2ɑ and by the same theorem ED is 88°, so the arc AE is just 180° - ED - DB, let's keep in mind that AE is the "far arc" whilst DB is the "near arc", and we know the external angle they make is 18°.
\(18~~ = ~~\cfrac{(\stackrel{ far~arc }{180-88-2\alpha})~~ - ~~\stackrel{ near~arc }{2\alpha}}{2} \implies 36=(180-88-2\alpha)-2\alpha \\\\\\ 36=92-4\alpha\implies 36+4\alpha=92\implies 4\alpha=56\implies \alpha=\cfrac{56}{4}\implies \boxed{\alpha=14}\)
the function , where is value and is time in years, can be used to find the value of a large copy machine during the first years of use. what is the value of the copier after years and months?
The value of the copier after 3 years and 6 months can be found by substituting t = 3.5 into the function and solving for V. The salvage value of the copier can be found by substituting t = 5 into the function and solving for V.
After 3 years and 6 months of use, the copier is worth $5,800. This can be found by substituting t = 3.5 into the function V(t)-3600t+20000: V(3.5) = 3600(3.5) - 20000 + 20000 = $5,800.
The salvage value of the copier after 5 years of use is $4,000. This can be found by substituting t = 5 into the function V(t)-3600t+20000: V(5) = 3600(5) - 20000 + 20000 = $4,000. This is the value of the copier when it is sold or replaced after 5 years of use.
The domain of the function is all real numbers because time and value can take on any real value. However, since the function is only defined for the first 5 years of use, t must be between 0 and 5.
The graph of the function is a downward-sloping line with an intercept of $20,000 on the y-axis and a slope of -3600. This means that the value of the copier decreases by $3,600 each year. At t = 0, the copier is worth $20,000, and after 5 years, it is worth $4,000. The graph is a straight line because the function is linear.
Complete Question:
The function V(t)-3600t+20000, where V is value and t is time in years, can be used to find the value of a large copy machine during the first 5 years of use. a. What is the value of the copier after 3 years and 6 months? After 3 years and 6 months, the copier is worth $ b. What is the salvage value of the copier if it is replaced after 5 years? After 5 years, the salvage value of the copier is ts c. State the domain of this function. d. Sketch the graph of this function. 20000 18000 16000 14000 12000 10000 8000 6000+ 4000 2000 4 .
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