Who was martin Luther king and how is he celebrite

Answer:

\(CH_4 + 2O_2 --> CO_2 + 2H_2O\)

Explanation:

The chemical formula for methane is \(CH_4\)

The chemical formula for oxygen is \(O_2\)

The chemical formula for carbon dioxide is \(CO_2\)

The chemical formula for water is \(H_2O\)

Methane burns in oxygen to give carbon dioxide and water:

\(CH_4 + O_2 --> CO_2 + H_2O\)

The balanced equation that will ensure an equal number of each atom on the left and right-hand sides of the equation would be:

\(CH_4 + 2O_2 --> CO_2 + 2H_2O\)

The valence states provided are general representations and may vary depending on specific conditions and coordination environments.

a. Uvarovite: The mineral formula for uvarovite is Ca3Cr2(SiO4)3. In this formula, the valence state of calcium (Ca) is +2, the valence state of chromium (Cr) is +3, and the valence state of silicon (Si) is +4. Oxygen (O) is usually assigned a valence state of -2.

b. Azurite: The mineral formula for azurite is Cu3(CO3)2(OH)2. In this formula, the valence state of copper (Cu) is +2, carbonate (CO3) has a valence state of -2, and hydroxide (OH) has a valence state of -1.

c. Cuprite: The mineral formula for cuprite is Cu2O. In this formula, the valence state of copper (Cu) is +1, and oxygen (O) is usually assigned a valence state of -2.

d. Gypsum: The mineral formula for gypsum is CaSO4·2H2O. In this formula, the valence state of calcium (Ca) is +2, sulfur (S) has a valence state of +6, and oxygen (O) is usually assigned a valence state of -2. The water molecules (H2O) do not have a net charge.

e. Galena: The mineral formula for galena is PbS. In this formula, the valence state of lead (Pb) is +2, and sulfur (S) has a valence state of -2.

It's important to note that the valence states provided are general representations and may vary depending on specific conditions and coordination environments.

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The structure of the alkene formed in this reaction is  \(CH_{3}CH=CHCOCH_{3}\) .

The structure of the alkene formed in the reaction when \(CH_{3}CH_{2}I\) reacts with triphenyl phosphine, followed by n-butyl lithium, followed by acetone is as follows:

Step 1: \(CH_{3}CH_{2}I\)  reacts with triphenyl phosphine ( \(PPh_{3}\) ) to form a phosphonium ylide through a substitution reaction.
\(CH_{3}CH_{2}I\)  + \(PPh_{3}\) → (\(CH_{3}CH_{2}\)) \(PPh_{3}\) + I-

Step 2: The phosphonium ylide reacts with n-butyl lithium (n-BuLi), which acts as a strong base, to form a carbanion.
(\(CH_{3}CH_{2}\)) \(PPh_{3}\) + I- + n-BuLi → [(\(CH_{2}=CH\)) \(PPh_{3}\) ]+ LiI

Step 3: The carbanion then reacts with acetone through a Wittig reaction, forming an alkene as the product.
[(CH2=CH) \(PPh_{3}\) ]+ LiI +\(CH_{3}COCH_{3}\) → \(CH_{3}CH=CHCOCH_{3}\) + ( \(PPh_{3}\) )LiI

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At standard pressure, which substance becomes less soluble in water as temperature increases from 10.°C to 80.°C is : d. NH4Cl

Solubility of substance increases with temperature, as higher temperatures allow more particles to dissolve in solvent. However, there are some exceptions, where solubility decreases with increasing temperature.

In this case, we are looking for substance that becomes less soluble in water as temperature increases from 10°C to 80°C at standard pressure.

The correct answer is d. NH4Cl.

At standard pressure, solubility of NH4Cl decreases with increasing temperature due to its endothermic dissolution process. As temperature increases, heat absorbed by the solution also increases, which makes dissolution process less favorable. Therefore, solubility of NH4Cl decreases with increasing temperature.

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The density of a liquid is 1.09 g/ml. what is the mass of a 27.3 ml sample of this liquid in units of g is 2.507 g

we  know that,  ρ = \(\frac{M}{V}\)

Here,

         ρ   = density of the substance

          M = mass of the substance

          V = Volume of the substance

given , density ρ = 1.09 g/ml

            volume V =27.3 ml

Then, the mass of the liquid can be given by,

               M = ρ × V

               M = 1.09  g/ml  × 27.3 ml

               M = 2.507 g

Thus ,the mass of the liquid in g is 2.507 g

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Answer: Confidence, strength, potential

Explanation:

\( \huge \boxed{ \fcolorbox{black}{pink}{Answer}}\)

20 Distinguishing Personality Traits of High-Performing Athletes

1. Self Confidence. “Self-Confidence” isn't just a phrase for cheesy motivational posters. ...

2. Strong Sense of Motivation. It takes more than a shiny medal or hefty check to motivate the world's best athletes. ...

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4. Natural Goal Setter. ...

5. Self-Discipline. ...

6. Optimism. ...

7. Sense of Belonging. ...

8. Natural Leader.

Answer:skin cream

Explanation:

the independent variable is the variable that is always changed or manipulated. in this case the skin cream is the independent variable.

Answer:

A. 1s²2s²

B. 1s²

C. 1s²

D. 1s²2s²2p⁶

Explanation:

The valency electron is the outer electron of an element. The valency electron resides in the outermost region of the shell.

Using the general configuration for the first 20 elements 2 8 8 2 the valency electrons can be identified.

A. 1s²2s²2p⁶3s² . The valency electron here are 2p⁶ and 3s² . Removing the valency electron we have 1s²2s²

B. 1s² 2s² 2p⁶. After removing the valency electron the configuration will be 1s².

C.1s²2s². After removing the valency electron the configuration will be 1s²

D.1s²2s²2p⁶3s¹. Removing the valency electron the electron configuration will be 1s²2s²2p⁶

The rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

To determine the rate of change of the concentration of sodium oxalate (Na₂C₂O4), we can use the rate equation:

Rate = (Δ[Na₂C₂O4]) / (Δt)

where Δ[Na₂C₂O4] represents the change in concentration of Na₂C₂O4 and Δt represents the change in time.

In this case, the initial concentration of Na₂C₂O4 is 1.34 M, and after 19.3 seconds, the concentration is 0.276 M.

Substituting the values into the rate equation, we have:

Rate = (0.276 M - 1.34 M) / (19.3 s - 0 s)

Rate = (-1.064 M) / (19.3 s)

Rate = -0.0551 M/s

Therefore, the rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

The negative sign indicates that the concentration of Na₂C₂O4 is decreasing over time, as the reactant is being consumed in the reaction.

It's important to note that the rate of a reaction is influenced by various factors, such as the reaction mechanism, temperature, and presence of catalysts. The rate can be determined experimentally by measuring the change in concentration of a reactant or product over a specific time interval.

The given information allows us to calculate the rate of change for the specific reaction involving Na₂C₂O4. However, without additional information about the reaction, it is not possible to determine the exact nature or stoichiometry of the reaction, as well as any other reactants or products involved.

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Tone-mending coatings grounded on poly( urea- formaldehyde) microcapsules are an innovative technology that allows for the form of damage on the coating ace.

These microcapsules contain a  mending agent,  generally a liquid polymer, which is released upon the circumstance of a crack or in the coating.

The ending agent fills the damaged area, undergoes in situ polymerization, and forms a new polymer network that restores the coating's integrity.  

Poly( urea- formaldehyde) microcapsules are chosen for their excellent mechanical parcels,  similar high durability, and good adhesion to colorful substrates. The capsules are generally in the micrometer range,  furnishing sufficient storehouse capacity for the mending agent.

The capsules are designed to rupture upon mechanical stress, releasing the ending agent into the damaged area.   This technology finds operations in colorful diligence, including automotive, aerospace, and construction.

Tone-mending coatings can retract the lifetime of defensive coatings, reduce conservation costs, and ameliorate the overall continuity of hells exposed to harsh surroundings. They can be applied to a wide range of accouterments including essence, plastics, and fixes, offering a  protean result for ace protection.  

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a. Since 38 is greater than 20, the approximation is valid.

b. Since 24 is greater than 20, the approximation is valid.

c. Since 20 is equal to 20, the approximation is borderline and may or may not be valid.

The 5% rule states that an equilibrium concentration can be approximated by its initial concentration if the initial concentration is at least 20 times greater than the equilibrium concentration. Mathematically, this can be expressed as:

initial concentration / equilibrium concentration ≥ 20

(a) For cyanic acid (HCNO), the equilibrium expression is:

HCNO ⇌ H⁺ + CNO⁻

The Ka expression is:

Ka = [H⁺][CNO⁻] / [HCNO]

Using the given pKa value, we can calculate the Ka value:

pKa = -logKa

\(Ka = 10^{-pKa} = 4.02 x 10^{-4}\)

Let x be the equilibrium concentration of [H⁺] and [CNO⁻]. Then, at equilibrium, [HCNO] = 0.45 - x. Plugging these into the Ka expression, we get:

4.02 x 10⁻⁴ = x² / (0.45 - x)

Solving for x, we get x = 0.012 M.

Now, we can check if the 5% rule applies:

initial concentration / equilibrium concentration = 0.45 / 0.012 ≈ 38

Since 38 is greater than 20, the approximation is valid.

(b) For hydrazoic acid (HN₃), the equilibrium expression is:

HN₃ ⇌ H⁺ + N₃⁻

The Ka expression is:

Ka = [H⁺][N₃⁻] / [HN₃]

Using the given pKa value, we can calculate the Ka value:

pKa = -logKa

\(Ka = 10^{-pKa} = 2.51 x 10^{-5}\)

Let x be the equilibrium concentration of [H⁺+] and [N₃⁻]. Then, at equilibrium, [HN₃] = 0.0077 - x. Plugging these into the Ka expression, we get:

2.51 x 10⁻⁵ = x² / (0.0077 - x)

Solving for x, we get x = 3.22 x 10⁻⁴ M.

Now, we can check if the 5% rule applies:

initial concentration / equilibrium concentration = 0.0077 / 3.22 x 10⁻⁴ ≈ 24

Since 24 is greater than 20, the approximation is valid.

(c) For arsenic acid (H₃AsO₄), the equilibrium expression is:

H₃AsO₄ + H₂O ⇌ H₃O + H₂AsO₄⁻

The Ka expression is:

Ka = [H₃O⁺][H₂AsO₄⁻] / [H₃AsO₄]

Using the given pKa value, we can calculate the Ka value:

pKa = -logKa

\(Ka = 10^{-pKa} = 6.98 x 10^{-3}\)

Let x be the equilibrium concentration of [H₃O⁺] and [H₂AsO₄⁻]. Then, at equilibrium, [H₃AsO₄] = 1.5 - x. Plugging these into the Ka expression, we get:

6.98 x 10⁻³ = x² / (1.5 - x)

Solving for x, we get x = 0.074 M.

Now, we can check if the 5% rule applies:

initial concentration / equilibrium concentration = 1.5 / 0.074 ≈ 20

Since 20 is equal to 20, the approximation is borderline and may or may not be valid. Therefore, we need to use a more accurate method to calculate the equilibrium concentration.

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Answer: The ultraviolet or UV portion

Explanation:

The term comes from the fact that this type of radiation is slightly beyond the violet region of visible wavelengths

Answer:

basic laboratory research, perform process and product development

Explanation:

good luck <3

I apologize, but you have not provided any specific information regarding the reaction, so I am unable to answer your question. Please provide more details or context so I can assist you better. electrochemical reaction. Based on the terms you provided, I will explain the process of electrolysis of water as an example.

Electrolysis of water, Equation of the reaction: 2H2O l → 2H2 g + O2 g Two half-reactions with voltages Oxidation anode half-reaction: 2H2O(l) → O2(g) + 4H+(aq) + 4e- ; E° = -1.23 V Reduction cathode half-reaction: 4H+(aq) + 4e- → 2H2(g)  E° = 0 Economics and environment concerns Electrolysis of water is an energy-intensive process, which means it can be expensive to perform on a large scale. Using renewable energy sources such as solar or wind power can help reduce the economic and environmental impact. Additionally, the production of hydrogen through electrolysis can be a clean and sustainable alternative to fossil fuels if the electricity used is derived from renewable sources.

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The number of moles of \(3.2\times10^{22\) SO2 molecules is approximately 0.053 moles.

To determine the number of moles, we need to use Avogadro's number, which states that one mole of any substance contains \(6.022\times10^{23\) particles (atoms, molecules, ions, etc.).

By dividing the given number of molecules by Avogadro's number, we can calculate the corresponding number of moles.

For the first question, dividing \(3.2\times10^{22\) SO2 molecules by Avogadro's number yields approximately 0.053 moles.

For the second question, dividing \(1.4\times 10^{23\) CO2 molecules by Avogadro's number will provide the number of moles of CO2.

To convert between the number of moles and mass, we need to know the molar mass of the substance. The molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol).

By multiplying the number of moles by the molar mass, we can find the mass of the substance.

For the third question, knowing that C6H12O6 is glucose, we can determine the molar mass of glucose and multiply it by 5.5 moles to find the number of moles of carbon.

For the fourth question, knowing the molar mass of C6H12O6, we can convert the given mass of 4.5 g to moles of C6H12O6 and then determine the number of moles of carbon.

Avogadro's number and molar mass are fundamental concepts in chemistry.

Avogadro's number allows us to relate the number of particles (atoms, molecules, etc.) to the number of moles, enabling us to convert between the microscopic and macroscopic scales.

Molar mass, on the other hand, provides a measure of the mass of one mole of a substance and is used to convert between moles and grams.

These concepts are essential in stoichiometry, where chemical equations and reactions are balanced based on the moles of reactants and products.

Understanding moles, molecules, and mass relationships is crucial for various calculations and analyses in chemistry.

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Answer:

13.57 approximately 14

Neutral atoms of all isotopes of a given element have the same number of protons and neutrons.

All the isotopes of the same element consists of the same number of protons, which defines the element.

Depending on the neutron count, different isotopes can exist . This is  because electrons are negatively charged and they can counterbalance the positive charge of protons. Also, they are present in equal numbers in neutral atoms of the same element.

Mass number is formed from the addition of protons and neutrons, which varies between isotopes. An isotope's mass can differ between different isotopes since it depends on its mass number and the masses of the particles that it is formed from.

However, the masses of various isotopes of the same element are extremely close. Hence, this can be challenging to distinguish without the help of specialized tools.

Thus, option (a) is correct.

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Answer: In atomic theory and quantum mechanics, an atomic orbital is a mathematical function describing the location and wave-like behavior of an electron in an atom. This function can be used to calculate the probability of finding any electron of an atom in any specific region around the atom's nucleus

Explanation:

Answer: green house effect

Answer:

The middle hydrogen is bonded to 2

elements.

Each hydrogen must be bonded to one element which is oxygen

Answer:

A, C, and D

Explanation:

the conjugate base for ch2=ch2 is:

CH2=CH−

To draw the conjugate base for the acid CH2=CH2, follow these steps:

1. Identify the acid: CH2=CH2 is ethylene, which is a weak acid.

2. Remove a hydrogen: To form the conjugate base, we need to remove a hydrogen atom from ethylene. This leaves us with CH2=CH-.

3. Add a lone pair: Since we removed a hydrogen, the conjugate base now has an additional lone pair of electrons. The carbon atom that lost the hydrogen now has a lone pair.

4. Add charges: The removal of a hydrogen results in a negative charge on the conjugate base. So, the carbon atom with the lone pair will have a negative charge.

Therefore, The conjugate base for the acid CH2=CH2 is CH2=CH- with a lone pair on the negatively charged carbon atom.

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it is tecnically magnesium,

Answer:

barium is the answer

Answer:

The melting and boiling points of molecular compounds are generally quite low compared to those of ionic compounds. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound (Figure 6.2. 1) .

Explanation:

hopefully this helps :)

if not then here. (Most of the time, the melting points of ionic compounds are very high compared to the melting points of molecular compounds.)

Answer: A. Molecular compounds tend to have lower melting points

Explanation:

Answer:

4400, and 0

Explanation:

since they traveled 2200 in one direction, to return home they must travel that distance again, so they travel 4400

displacement is the distance from the start point, so since they are back home at the end of the trip, they did not get displaced at all

if you have any questions, leave them in the comments and i will try to answer them, if this helped, pls give brainliest

Answer:

My answer to the question is 4400 and 0

The position in extremity from most to least is water, ethanol, ethyl acetic acid derivation, CH3)2CO, 2-butanone, diethyl ether, hexane, and benzene.

From these solvents, ethanol will be totally miscible in water because of its more modest carbon fasten and it's capacity to frame hydrogen bonds.

Water is a polar dissolvable; other polar solvents incorporate CH3)2CO, acetonitrile, dimethylformamide (DMF), dimethylsulfoxide (DMSO), isopropanol, and methanol.

One way you could really work out a dissolvable's extremity is by utilizing its dielectric consistency, which is utilized to quantify how well the dissolvable can part of the way drop the field strength of the electric field of a molecule added to it. The higher the worth of a dissolvable's dielectric consistent, the more polar it will be.

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Best describe table sugar is considered a pure substance is Sugar has the same chemical composition throughout

Table sugar is pure sucrose derived from sugar beet or sugar cane and sucrose is the disaccharide consisting of glucose and fructose and it is produced by green plant in the process of photosynthesis and since the chemical composition of sugar is definite and does not vary hence it is pure substance and table sugar refer to standard while white sugar that you see in your cooking baking or cup of tea at home and the scientific name foe table sugar is sucrose

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Answer:

1192.54 J

Explanation:

Applying,

Q = cm(t₂-t₁)................ Equation 1

Where Q = Amount of heat lost, c = specific heat capacity of the iron, m = mass of the iron, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: m = 83 g = 0.083 kg, t₁ = 297 K, t₂ = 329 K

Constant: c = 449 J/kg.K

Substitute these values into equation 1

Q = 449(0.083)(329-297)

Q = 449(0.083)(32)

Q = 1192.54 J