who knows the answer​

Let:

From that equation:

If two lines are perpendicular, then:

Given an arbitraty point:

Using the point slope equation:

The area of the Trapezium given in the question is 28ft²

The area of a trapezium is calculated using the relation :

Using the parameters given for our compuation:

height, h = 4

b1 = 9

b2 = 5

Inputting the parameters into our formula :

Area = 4/2(5 + 9)

Area = 2(14)

Area = 28ft²

Therefore, the area of the Trapezium is 28ft²

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Answer:

y=5x-1/3

Step-by-step explanation:

form is y=mx+b

m is slope

b is y-intercept

The equivalent algebraic expression of \(sin(cos^{-1}(x/4))\) that involves x only is \(\sqrt{1 - (x/4)^{2}}\)

An algebraic expression is a mathematical phrase that includes numbers, variables, and operations. It can contain constants, coefficients, and one or more variables.

The expression \(sin(cos^{-1}(x/4))\) can be interpreted as follows: the value inside the brackets of the \(cos^{-1}\) function represents the cosine of an angle (let's call it theta) whose value lies between 0 and π/2 radians. This angle can be found using the inverse cosine function. Then, the sin of this angle is taken.
Now, let's try to express this in terms of x only. Since x/4 is the value of cosine of the angle theta, we can write:
\(cos(\theta) = x/4\)
Using basic trigonometric identities, we can express sin(theta) in terms of x as follows:
\(sin^{2}(\theta) = 1 - cos^{2}(\theta)\\ sin^2(\theta) = 1 - (x/4)^{2}\\ sin(\theta) = \sqrt{1 - (x/4)^{2}}\)
Therefore, the equivalent algebraic expression that involves x only is:
\(\sqrt{1 - (x/4)^{2}}\)

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a) X'Y' + X'Y + XY simplifies to X' + Y.

b) A'BC' + ABC' + BC'D simplifies to BC'.

Complement of the functions:

a) Complement is W' + X' + YZ.

b) Complement is (A' + B + C)(A'B' + C' + A'B).

a) To prove X'Y' + X'Y + XY = X' + Y, we can use Boolean algebra identities:

X'Y' + X'Y + XY

= Y'(X' + X) + XY(Distributive Law)

= Y' + XY(X + X' = 1)

= X' + Y(Commutative Law)

Therefore, X'Y' + X'Y + XY simplifies to X' + Y.

b) To prove A'BC' + ABC' + BC'D = BC', we can simplify the expression using Boolean algebra:

A'BC' + ABC' + BC'D

= BC'(A' + A) + BC'D   (Distributive Law)

= BC' + BC'D(A + A' = 1)

= BC'(BC' + BC'D = BC' + BC'(1) = BC')

Hence, A'BC' + ABC' + BC'D simplifies to BC'.

Complement of the given functions:

a) The complement of WX(Y'Z + YZ') + W'X'(Y' + Z)(Y + Z') is W' + X' + YZ.

b) The complement of (A + B' + C')(A'B' + C)(A + B'C') is (A' + B + C)(A'B' + C' + A'B).

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Answer:

cl has a better deal

Step-by-step explanation:

ch=38+4m=50

cl=20+6m=50

ch=4*3 months =12+38=50

cl=6*5 months=30+20=50

The scale factor of the model to the real garden can be obtained by dividing any two corresponding lengths (or distances) in the model and the actual garden. Here, we will divide the length of the path in the garden and the length of the path in the model.The path in the garden is 16 ft long while the path in the model is 4 ft long.

Scale factor = (length of path in model)/(length of path in garden)

                    =4/16

                    =1/4

Therefore, the scale factor of the model to the real garden is 1/4. This means that each distance in the model is 1/4 of the corresponding distance in the actual garden.

We know that a model is a smaller representation of an object or a place.

Models can be used to simulate things that are too large, too small, too expensive, or too dangerous to study directly. The scale factor of a model is the ratio of the length or size of an object in the model to the length or size of the corresponding object in the real world.

A scale factor is usually expressed as a fraction or a ratio. It shows how much the model has been reduced or enlarged from the actual size. For example, if the scale factor of a model is 1/10, this means that every dimension in the model is one-tenth of the size of the corresponding dimension in the real object or place. In other words, the model is ten times smaller than the real object or place.In the given question, we are asked to find the scale factor of a model garden to the real garden. To do this, we need to find the ratio of any two corresponding lengths in the model and the actual garden.

Here, we are given the length of the path in the garden and the length of the path in the model. By dividing these lengths, we get the scale factor of the model to the real garden. We get 1/4 as the scale factor.

The scale factor of the model to the real garden is 1/4. This means that each distance in the model is one-fourth of the corresponding distance in the actual garden. Scale factors are important in model making, architecture, engineering, and many other fields. They help us to create accurate and proportional models of complex objects and structures.

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Answer:

6 hours

Step-by-step explanation:

Answer:

6 Hours

Step-by-step explanation:

First you want to know how many hours it will take to get to 440 miles

Then figure it out in fractions which would be 4/4

then half it to make it easier so 220 = 2/4 then the equation asks on how to get 3/4 well whats the even number between the 2 fractions

and the answers to the miles are

440 miles = 8 hours

220 miles = 4 hours

so then 330 miles = 6 hours

so 6 hours is the answer

Answer:

slope = 7

Y intercept =  2

Step-by-step explanation:

Answer: Airline P since the median is lower and the SDR is lower

Step-by-step explanation:

The bond's current yield with face value for time period of 11 years is equal to 4.316%.

Time period of mature bond = 11 years.

Face value of bond = $1,000

Yield to maturity of 8.6321%

Pays an 8.6321% annual interest rate on its face value

The current yield of a bond is calculated by dividing the annual coupon payment by the current market price of the bond.

Since the bond pays coupons semiannually, the coupon payment is half of the annual interest payment.

To calculate the annual interest payment, multiply the face value by the annual interest rate.

Annual interest payment

= $1,000 × 8.6321%

= ( $1,000 × 8.6321 ) / 100

= $86.321

Since the bond pays coupons semiannually, the semiannual coupon payment is half of the annual interest payment.

Semiannual coupon payment

= $86.321 ÷ 2

= $43.16

Now, to calculate the bond's current yield, divide the semiannual coupon payment by the market price of the bond.

The bond is selling for $1,000,

Current yield

= Semiannual coupon payment / Market price

= $43.16 / $1,000

≈ 0.04316 or 4.316%

Therefore, the bond's current yield is approximately 4.316%.

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Certainly!

This text is discussing two linear functions, g and h, which have different slopes. A linear function is a function that can be graphed as a straight line. The value of both functions at a specific point (x = a) is the same (b).

The question being asked is what happens at the point (a, b) when both functions are graphed on the same coordinate plane.

Pls Mark brainliest

For the weight of bags 402 grams filled with chocolate chips the required null hypothesis and alternative hypothesis  equal to  H0: μ = 402 and Ha: μ ≠ 402.

Weight of the bag filled with chocolate chips made by machine works = 402 grams

The null hypothesis for the bag filled with machine work representing the statement has no effect.

And it represents that the mean weight of the bag filled with chocolate chips is 402grams.

Null hypothesis for the given scenario is equal to ,

H0: μ = 436

The alternative hypotheses for the above scenario of the bag isn't filled with chocolate chips with weight 402grams.

They are either under filled or that is less than 402grams or overfilled that is above 402grams.

Alternative hypothesis for the given scenario is equal to,

Ha: μ ≠ 402

Statistics is the study of surveys and research of the given numerically data.

Two different kinds of hypotheses we have,

A null hypothesis is one that holds true for the given scenario.

And an alternate hypothesis is another.

The null hypothesis is a default condition to represents nothing is happening.

Possibility of  no relationship between two given measured groups.

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Answer:

increasing spread epidemics your outlook

The function f(x) = cos(4πx) evaluated at the endpoints of the interval [2, 1] is f(2) = cos(8π) and f(1) = cos(4π). Rolle's Theorem does not apply to f on this interval (DNE).

Evaluating the function f(x) = cos(4πx) at the endpoints of the interval [2, 1], we have f(2) = cos(4π*2) = cos(8π) and f(1) = cos(4π*1) = cos(4π).

To determine if Rolle's Theorem applies to f on this interval, we need to check if the function satisfies the conditions of Rolle's Theorem, which are:

1. f(x) is continuous on the closed interval [2, 1].

2. f(x) is differentiable on the open interval (2, 1).

3. f(2) = f(1).

In this case, the function f(x) = cos(4πx) is continuous and differentiable on the interval (2, 1). However, f(2) = cos(8π) does not equal f(1) = cos(4π).

Since the third condition of Rolle's Theorem is not satisfied, Rolle's Theorem does not apply to f on the interval [2, 1]. Therefore, we cannot find a value c in (2, 1) such that f'(c) = 0. The answer is "DNE" (Does Not Exist).

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Answer:

113.1

Step-by-step explanation:

Like and give 5 star rating

Answer:

Los factores de 48 son 1, 2, 3, 4, 6, 8, 12, 16, 24 y 48.

Answer:

2850 kilograms

Step-by-step explanation:

step 1)

change the percent to a decimal

by moving the decimal over to spots to the left

95.0% to 0.95

step 2

Multiply tge decimal with the amount you were given

0.95 × 3000 = 2850

If you want to double check, do this

2850 ÷ 3000 = 0.95

Answer:

Hope this is correct and helpful

HAVE A GOOD DAY!

\( \text{Given : 2x - y = 4 and x + 2y = 7}\)

\( \text{Solution : according to the question here we are provided with} \\ \text{two equations separately. So, let's name them as eq(1) and eq(2).} \\ \text{ The rest is followed as we continue to get to our goal} \\ \\ \sf {1}^{st} \: equation : \\ \quad\dashrightarrow \frak{2x - y = 4} \\ \\ \quad \dashrightarrow \frak{ \red{x = \frac{y + 4}{2} }} \qquad \sf ...eq(1) \\ \rm{ now \: \: as \:per \: our \: plan \: we \: need \: to \: get \: eq(2) } \\ \\ \sf{ {2}^{nd} \:equation} : \\ \quad\dashrightarrow \frak{ x + 2y = 7} \\ \\ \quad\dashrightarrow \frak{ \red{y = \frac{7 - x}{2}}} \qquad \sf ...eq(2) \\ \\ \text{Now, finding x and y} \\ \\ \underline{ \frak{Finding \: x}}\\ \\ \quad \hookrightarrow \frak{x = \frac{y + 4}{2}} \\ \\ \quad \hookrightarrow \frak{2x = \frac{7 - x}{2} + 4} \\ \\ \quad \hookrightarrow \frak{2x = \frac{7 - x + 8}{2}} \\ \\ \quad \hookrightarrow \frak{2x = \frac{1 - x}{2}} \\ \\\quad \hookrightarrow \frak{4x = 1 - x} \\ \\ \quad \hookrightarrow \frak{5x = 1} \\ \\\quad \star \qquad \underline{ \boxed{ \green{ \frak{x = \frac{1}{5}}}}} \\ \\ \underline{ \frak{Finding \: y}} \\ \\ \quad \hookrightarrow \frak{y = \frac{7 - x}{2}} \\ \\ \hookrightarrow \frak{2y = 7 - \frac{1}{5} } \\ \\ \hookrightarrow \frak{2y = \frac{35 - 1}{5} } \\ \\ \hookrightarrow \frak{2y = \frac{34}{5}} \\ \\ \hookrightarrow \frak{y = \frac{34}{5} \times \frac{1}{2}} \\ \\ \hookrightarrow \frak{y = \frac{17}{5} } \\ \\ \star \qquad \underline{ \boxed{ \frak{ \green{y = 3 \frac{2}{5} }}}}\)

We need to find the inverse of the function gof (x). First we need to find the composite function gof (x) which is given by:

\(g(f(x)) = g(3x - 6)\)

= \((1/3)(3x - 6) + 1\)

= x - 1 + 1

= x

Thus,

gof (x) = x.

Now we need to find the inverse of the function gof (x) to obtain

\((gof)^-1 (x).\)

We have gof (x) = x

which implies\((gof)^-1 (x)\)

= gof (x)^-1

= x^-1

= 1/x,

x ≠ 0

Therefore,

\((gof)^-1 (x) = 1/x\)

which is option (3) (x+1) since 1/x can be written as 1/(x+1-1), where (x+1-1) is the denominator of 1/x.

Hence, the correct option is (3).

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To find (g(f))^-1 (x), substitute the expression for f(x) into g(x) and simplify. The composition of g(f) is x and its inverse is also x. Therefore, (g(f))^-1 (x) equals x.

To find (g(f))^-1 (x), we need to first find the composition of g(f) and then find its inverse. Start by substituting the expression for f(x) into g(x): g(f(x)) = g(3x-6) = \frac{1}{3}(3x-6) + 1 = x - 1 + 1 = x. So, g(f(x)) = x. Now, to find the inverse of g(f), we switch the x and y variables and solve for y: y = x. Therefore, (g(f))^-1 (x) = x.

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If bc is a 2×8 matrix, then the number of columns of b must be the same as the number of rows of c. Let r be the number of rows of b.

So we have b × c = (r × n) × (n × 8) = r × 8, where n is the number of columns of b (and also the number of rows of c). Since the product of b and c is a 2×8 matrix, we know that r × 8 = 2×8 = 16. Therefore, we have:r = 16/8 = 2

So b must have 2 rows if bc is a 2×8 matrix. To clarify, the product of two matrices, A and B, is defined only if the number of columns of A equals the number of rows of B. The resulting matrix will have the same number of rows as A and the same number of columns as B.

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Based on the cost of the gliders and the amount to be financed, a down payment of 25% would be enough.

The gliders would cost $12,000 but the Rices do not want to take out more than a loan of $9,000.

A downpayment of 25% on the amount would be:

= 25% x 12,000

= $3,000

= Cost of gliders - Down payment

= 12,000 - 3,000

= $9,000

A down payment of 25% would therefore be enough to finance no more than $9,000.

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m = 17/4

Hopefully, I correctly answered your question! If I did, I would really appreciate Brainliest. You can give Brainliest by clicking the crown (it only works if there’s two people who answered.) I would also appreciate if you rated my answer 5 stars, and clicked the heart!

Answer:

Anything.

Step-by-step explanation:

The reason why I say " anything " is because the fraction, \(\frac{1}{1}\) is bascially representing the number 1, nothing else so you can put whatever you want, tens, hundreds, thousands, millions, and so on.

So whatever number you want to put it will always equal, \(\frac{1}{1}\), But just remember to always put the number that you choose on top or the numerator such as the following:

\(\frac{4}{1}\).

Thus, you answer is, anything.

Answer:

The inequality that represents p are p \(\geq\) 125 or p \(\leq\) 85.

Step-by-step explanation:

We are given that in order to be invited to tutoring or extension activities, a student's performance must be at least 20 points higher or lower than an average score. The average score is 105.

Let p = the scores for students who are eligible for tutoring or extension activities.

The first condition states that a student's performance must be at least 20 points higher than an average score, that means;

p \(\geq\) (105 + 20)

p \(\geq\) 125

Similarly, the second condition states that a student's performance must be at least 20 points lower than an average score, that means;

p \(\leq\) (105 - 20)

p \(\leq\) 85

So, the inequality that represents p are p \(\geq\) 125 or p \(\leq\) 85.

Answer:

D.  p ≤ 85 or p ≥ 125

You only have to meet 1 requirement, which A & B have 2.  

Due to the wording, at least 20 points, I would take that as meaning 105-20=85 is allowed or 105+20=125 is allowed.  

C, does not allow you to use 85,125.

2) \(m\angle A+m\angle B+m\angle C+m\angle D=360^{\circ}\)

3) Substitution property

4) Combine like terms

Answer:

A

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

(h, k) are the coordinates of the vertex and a is a multiplier

Given

f(x) = - 2x² - 12x - 16

To complete the square the coefficient of the x² term must be 1

Factor out - 2 from - 2x² - 12x

f(x) = - 2(x² + 6x) - 16

add/ subtract ( half the coefficient of the x- term )² to x² + 6x

f(x) = - 2(x² + 2(3)x + 9 - 9 ) - 16

     = - 2(x + 3)² + 18 - 16

     = - 2(x + 3)² + 2 ; y = 2

Answer:

lol ok

Step-by-step explanation:

Answer:

ok Y?

Step-by-step explanation: