While excavating the tomb of Tutankhamen (d. 1325 BC), archeologists found a sling made of linen. The sling could hold a stone in a pouch, which could then be whirled in a horizontal circle. The stone could then be thrown for hunting or used in battle. Imagine the sling held a 0.10-kg stone; and it was whirled at a radius of 1.5 m with an angular speed of 2.0 rev/s. What was the angular momentum of the stone under these circumstances

Acceleration depends on force applied and the mass involved. The smaller object will accelerate more. The correct answer is B

Force can simply be defined as a pull or push. It is the product of mass and acceleration. It is a vector quantity and it is measured in Newton.

If a constant force acts on two objects of different masses, the two object will not have the same acceleration because according to Newton's second law, F = ma

a = F/m

That is, acceleration is inversely proportional to the mass of the body. The bigger the mass, the smaller the acceleration and vice versa.

Therefore, the object that will accelerate more will be the smaller object.

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A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the planet's surface, the scale indicates a force of 10,000 Newtons. The surface area of the scale is 0.125 square meters.

To calculate the surface area of the scale, we can use the formula:

P = F/A

where P is the pressure, F is the force, and A is the surface area.

Given that the atmospheric pressure on the surface of Physica is 80,000 Pascals and the scale indicates a force of 10,000 Newtons, we can plug in these values into the equation:

80,000 Pa = 10,000 N / A

To solve for A, we can rearrange the equation:

A = 10,000 N / 80,000 Pa

A = 0.125 m²

In summary, based on the given information, the surface area of the scale on the surface of planet Physica is calculated to be 0.125 square meters.

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The third law of Newton's theory of motion states that there is a contrary response to every action. Anytime forceone body puts pressure on another, the second body puts equal and opposing pressure on the first.

It is quite acceptable to refer to a force of this level as a push and a pull. Force is not a property that an object 'has in it' or that it 'contains. One thing is subject to a force from another. There is no distinction between living and non-living things in the concept of a force.

Simply put, force is the push / pull motion. Both touch and non-forces are different types of force. Forces like nuclear effect, the force of gravity, frictional force, magnetism force, electric force, and spring force are a few examples.

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Given:

Mass, m = 0.68 kg

Initial temperature, T1 = 20°C

Final temperature, T2 = 45°C

Let's find the amount of heat needed.

Apply the Specific Heat Capacity formula:

Where:

m is the mass = 0.68 kg

c is the specific heat of water = 4.187 J/kg °C−1

T1 = 20°C

T2 = 45°C

Plug in the values and solve for Q:

Where:

1 kJ = 0.239 kCal

Since the answer is to be in kCal, we have:

Therefore, the amount if heat added is 17.01 kCal.

ANSWER:

17.01 kCal

\(E = \frac{K Q q }{ \sqrt[\frac{3}{2} ]{ R^{2} + x^{2} } }\)The magnitude of electic field at a distance 'a'  from the center of the ring is

\(E = \frac{K Q q }{ 2\sqrt{2} a^{2} }\)  where  K =  \(\frac{1 }{4 \pi }\)∈

a = radius of ring  

Q = uniform charge distribution over ring

q =  another point charge located at a distance a from centre of ring

We know that the electric field at distance x from the center of ring of radius R is given by

\(E = \frac{K Q q }{ \sqrt[\frac{3}{2} ]{ R^{2} + x^{2} } }\)

according tho the question the radius of ring is equal to distance of q from centre of the ring

substituting  R= a , x = a

we get

\(E = \frac{K Q q }{ \sqrt[\frac{3}{2} ]{ a^{2} + a^{2} } }\)

\(E = \frac{K Q q }{ \sqrt[\frac{3}{2} ]{ 2 a^{2} } } }\)

\(E = \frac{K Q q }{ 2\sqrt{2} a^{2} }\)

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Answer:

he tripped ballanced forces ballanced forces

Answer:

Mass of block = 6kg

wright = 6 × g = 60 N using g = 10 m/s^2 .

compression= 0.20m

spring constant =( weight / compression) =( 60/0.20) = 300 N/m .

Work done in compressing 0.20 m =( 1/2 × 300 × 0.20 × 0.20)= 6 joule.

Additional compression = 0.10 m

total compression = 0.20+ 0.10= 0.30 m.

Total work done = ( 1/2 × 300 × 0.30× 0.30) = 13.5 joule.

Hence work done in compressing from 0.20 m to 0.30 m will be = ( 13.5 - 6) = 7.5 joule.

Note :- work done in compressing a spring having spring constant K N/m by x m is equal to 1/2× (K) × X^ 2 .

One full weather station reports  wave passing a spot every second is equivalent to a frequency of 1 Hz. The frequency is 48=12=0.5 Hz if 4 waves pass a spot in 8 seconds.

The number of cycles that make up a time unit is the frequency. The frequency of a wave with a 30-second period is therefore 1 30 = 0.033 cycles per second, or 0.033 Hertz (Hz).

A wave's speed and wavelength vary as it crosses a border and enters a new medium, but its frequency doesn't.

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Given :

Density of the water, \(\rho = 1000\ kg/m^3\).

Depth of lake, d = 5 m.

To Find :

The pressure at the bottom of the lake due to the depth of water.

Solution :

We know, hydrostatic pressure is given by :

\(P = \rho gd\) ( Here,  g is acceleration due to gravity, g = 10 m/s².

Putting all values in above equation, we get :

\(P = 1000\ kg/m^3 \times 10 \ m/s^2 \times 5\ m\\\\P = 5\times 10^4 \ Pascal\)

Hence, this is the required solution.

Answer:

The net acceleration of the SUV is 0.429 meters per square second due west.

Explanation:

Statement is incomplete. Description is presented below:

A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration? If yes, then what are the magnitude and direction of the car's acceleration?

According to Newton's Laws of Motion, the SUV will accelerate if and only if net acceleration is different of zero. Let suppose as positive the direction of driving force (\(F\)), measured in newtons:

\(\Sigma F = F - R -f = F_{net}\) (1)

Where:

\(R\) - Resistance force, measured in newtons.

\(f\) - Wind force, measured in newtons.

\(F_{net}\) - SUV net force, measured in newtons.

If we know that \(F = 2500\,N\), \(R = 500\,N\) and \(f = 500\,N\), then net force experimented by the SUV is:

\(F_{net} = 2500\,N-500\,N-500\,N\)

\(F_{net} = 1500\,N\)

The car has acceleration.

By definition of force for systems with constant mass, we calculate the acceleration of the vehicle below:

\(a_{net} = \frac{F_{net}}{m}\) (2)

Where \(m\) is the mass of the SUV, measured in kilograms.

If we know that \(F_{net} = 1500\,N\) and \(m = 3500\,kg\), then the net acceleration of the car is:

\(a_{net} = \frac{1500\,N}{3500\,kg}\)

\(a_{net} = 0.429\,\frac{m}{s^{2}}\)

The net acceleration of the SUV is 0.429 meters per square second due west.

Answer:

d

Explanation:

By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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When a car collides with another object, the total momentum of the system before and after the collision must be conserved. Momentum, on the other hand, is a product of mass and velocity. To find the velocity of a car after a collision, we must first consider the initial momentum of the system before the collision and compare it to the final momentum after the collision.

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Answer:

a) W=2.425kJ

b) \(\Delta E=2.425kJ\)

c) \(T_f=20.06^{o}C\)

d) Q=-2.425kJ

Explanation:

a)

First of all, we need to do a drawing of what the system looks like, this will help us visualize the problem better and take the best possible approach. (see attached picture)

The problem states that this will be an ideal system. This is, there will be no friction loss and all the work done by the object is transferred to the water. Therefore, we need to calculate the work done by the object when falling those 10m. Work done is calculated by using the following formula:

\(W=Fd\)

Where:

W=work done [J]

F= force applied [N]

d= distance [m]

In this case since it will be a vertical movement, the force is calculated like this:

F=mg

and the distance will be the height

d=h

so the formula gets the following shape:

\(W=mgh\)

so now e can substitute:

\(W=(25kg)(9.7 m/s^{2})(10m)\)

which yields:

W=2.425kJ

b) Since all the work is tansferred to the water, then the increase in internal energy will be the same as the work done by the object, so:

\(\Delta E=2.425kJ\)

c) In order to find the final temperature of the water after all the energy has been transferred we can make use of the following formula:

\(\Delta Q=mC_{p}(T_{f}-T_{0})\)

Where:

Q= heat transferred

m=mass

\(C_{p}\)=specific heat

\(T_{f}\)= Final temperature.

\(T_{0}\)= initial temperature.

So we can solve the forula for the final temperature so we get:

\(T_{f}=\frac{\Delta Q}{mC_{p}}+T_{0}\)

So now we can substitute the data we know:

\(T_{f}=\frac{2 425J}{(10000g)(4.1813\frac{J}{g-C})}+20^{o}C\)

Which yields:

\(T_{f}=20.06^{o}C\)

d)

For part d, we know that the amount of heat to be removed for the water to reach its original temperature is the same amount of energy you inputed with the difference that since the energy is being removed this means that it will be negative.

\(\Delta Q=-2.425kJ\)

The correct statement is Molecular collisions transfer thermal energy between the system and its surroundings. Thus, option D is correct.

The energy moves between a system of reacting substances and the surroundings by the collision of molecules. The transfer of heat or thermal energy between the system and its surroundings by the process of Conduction. Conduction is the process of transmitting the heat to the neighboring atoms or collisions by the process of collisions.

The conduction takes place more steadily in solids and liquids where the molecules are closer together. When the molecules are collided with the nearby molecules, the potential energy is converted into kinetic energy and hence the heat energy is transferred between the system and its surroundings.

Hence, Molecular collisions transfer thermal energy between the system and its surroundings. Thus, the correct option is D.

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Answer:

false....

Explanation:

brainliest

The magnitude of object's acceleration is 3.26m/s².

The mass of the body is 4.10 lg.

The two forces that are acting on the object are F₁ = -6i + 7.9j newton and F₂ = 6.8i + 5.3j Newton.

We know that the force acting on an object is,

F = Ma

Where,

F is the force acting,

M is the mass of the object and,

a is the acceleration of the object.

As we can see, two forces are acting on the body,

We can simplify the forces in x direction and y direction,

The forces are  F₁ = -6i + 7.9j N and F₂ = 6.8i + 5.3j N.

So, the total force in x-direction,

Fₓ = (-6+6.8)i

Fₓ = 0.8i

Fᵧ = (7.9+5.3)j

Fᵧ = 13.2j

So, the net force Fₙ on the object is Fₙ = (0.8i + 13.2j) N

Now, putting value of force and mass in the formula,

F = Ma

0.8i + 13.2j = 4.1a

a = 0.19i + 3.21j m/s².

The magnitude of acceleration is,

|a| = √[(0.19)²+(3.21)²]

|a| = 0.361 +10.3

|a| = 3.26m/s².

So, the magnitude of acceleration is 3.26m/s².

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Answer:

a. lower surface area, less resistence

b. more surface area, the load is split so no single tire overstrained

c. more surface area, more resistance against the sand. human steps sink down in the sand.

d. rapid change in air pressure on eardrums lead to somewhat-painful tension

e. air would always find its way in so no pressure difference can be achieved

(would indeed appreciate the brainliest if you appreciate the work)

Answer: EASY BROOOOOOOOOOOOOOOOOOOOOOOOO

Take a look inside your heart

Is there any room for me?

I would have to hold my breath

'Til you get down on one knee

Because you only want to hold me

When I'm looking good enough

Did you ever fault me?

Would you ever picture us?

Every time I pull my hair out

Was only out of fear

That'd you find me ugly

And one day you'll disappear

Because what's the point of crying?

It was never even love

Did you ever want me?

Was I ever good enough?

The scenario presented is an example of negative punishment.

Negative punishment involves the removal of a desirable stimulus or the addition of an aversive stimulus in response to a behavior, with the goal of decreasing the likelihood of that behavior occurring again in the future.

In this case, the desirable stimulus that was removed is the son's ability to engage in leisure activities like playing hockey, and the aversive stimulus that was added is the scolding from the parent. By experiencing this consequence, the son may be less likely to forget his chores in the future in order to avoid the negative outcome.

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The diagram that shows the greatest magnitude net torque with a zero net force is the diagram in second option.

option B is the correct answer.

The net torque is the sum of the individual torques. The torque itself is obtained from the product of applied force and the perpendicular distance of the force.

In rotational equilibrium, there is no net torque on the object. There may be individual torques, but they add up to zero and cancel each other out.

Mathematically, the formula for torque is given as;

τ = Fr

where;

The torque applied to an object increases with increase in the perpendicular distance.

To obtain a zero net force, sum of all the opposite forces applied to an object must be equal to zero.

The forces must be equal in magnitude but opposite in direction, and the diagram that meets this specification is the last graph.

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Answer:

403 kg is the diffrence

Recall that average velocity is given by

\(v_{\rm ave}=\dfrac{\Delta x}{\Delta t}\)

Under constant acceleration, we also have

\(v_{\rm ave}=\dfrac{v_i+v_f}2\)

Then

\(\dfrac{\Delta x}{\Delta t}=\dfrac{v_i+v_f}2\)

\(\implies\dfrac{110\,\mathrm m}{\Delta t}=\dfrac{22\frac{\rm m}{\rm s}+3.0\frac{\rm m}{\rm s}}2\)

\(\implies\boxed{\Delta t=8.8\,\mathrm s}\)

Answer: 0.52N

Explanation:

Formula

F=ke

Givens

e= 4.0cm>>>0.04m

k=13N/m

Plug givens into formula

F= (13N/m)(0.04m)

F=0.52N

The force on the ball at the moment the spring is released will be F =0.52N

When a spring is stretched or compressed , it displaces from equilibrium position . As a result , a restoring force will act ( which act opposite to the direction of force applied on the string ) and tends to retract the spring back to its original position . The force is called spring force

Given

x = 4cm  = 0.04 m

spring constant is(k) =  13 N/m

F( spring force on the ball ) = ?

F = -k x

F  = -(13)(.04)

F ( spring force) = - 0.52N

The force on the ball at the moment the spring is released will be F =0.52N

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The acceleration of the dragster is 2.01 * 10^5 m/s^2

The term acceleration refers to the change in velocity with time. Hence the formula for acceleration is given as;

a = v - u/t

a = acceleration

v = final velocity

u = initial velocity

t = time taken

Now;

v = 100 miles or 160934 meters

u = 0 miles or 0 meters

t = 0.8 seconds

a =  160934 - 0/ 0.8

a = 2.01 * 10^5 m/s^2

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The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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