Which way did the light ray bend in relation to the normal line?

Conductivity is the property of matter in which a substance can transfer heat or electricity.

Matter : Anything which occupies space and has mass is called matter.

Chemical classifications

Physical classifications

Answer:

Decibel (dB) is the unit of sound.

Answer:

Decibels ( dB)

Explanation:

When measuring sound intensity in units, it is referred to as decibels

The units of the constant of proportionality between pressure and volume in alphabetical order are

1. Celsius (°C)

2. Fahrenheit (°F)

3. Kelvin (K)

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

We will start by completing the Boyle's Law stated

Boyle's Law states the volume and pressure of a gas are inversely proportional, provided that the temperature remains constant.

This means temperature is the constant of proportionality.

Now, we will name the three units of the constant of proportionality, that is, temperature. The units are

1. Degree Celsius (°C)

2. Degree Fahrenheit (°F)

3. Kelvin (K)

2. In the ideal gas equation (PV/nT=R), R represents the ideal gas constant.

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

Hence,

The units of the constant of proportionality between pressure and volume in alphabetical order are

1. Celsius (°C)

2. Fahrenheit (°F)

3. Kelvin (K)

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

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Answer:

Cost = $ 7.62

Explanation:

First we find the energy consumed by the LED bulb during one year, for six hours a day runtime:

E = Pt

where,

E = Energy Consumed = ?

P = Power = (12 W)(1 KW/ 1000 W) = 0.012 KW

t = time of use = (1 year)(365 days/ 1 year)(6 h/ 1 day) = 2190 h

Therefore,

E = (0.012 KW)(2190 h)

E = 26.28 KWh

Now, we find the cost of running LED:

Cost = (E)(Unit Price)

Cost = (26.28 KWh)($ 0.29/ KWh)

Cost = $ 7.62

Answer:

12 m/s

Explanation:

From the question,

Applying the law of conservation of momentum,

total momentum before collision = Total momentum after collision

mu+Mu' = mv+Mv'........................... Equation 1

Where m = mass of the bullet, u = initial velocity of the bullet, M = combined mass of the gun and the puck, u' = initial velocity of the gun and the puck, v = final velocity of the bullet, v' = final velocity of the gun and the puck

make v the subeject of the equation

v = [(mu+Mu')-Mv']/m................. Equation 2

Given: m = 5.00 g = 0.005  kg, M = 120 g = 0.12 kg, u = u' = 0 m/s (at rest), v' = 0.5 m/s

Substitute these values into equation 2

v = [0-(0.12×0.5)]/0.005

v = -0.06/0.005

v = -12 m/s

The negative sign  can be ignored since we are looking for the speed, which has only magnitude.

Hence the speed of the bullet is 12 m/s

Answer:

you would use a measuring tape and compare your answers

On Earth, air typically prevents engine exhaust gases from leaving the engine. Thus, the thrust is lessened. However, to the lack of atmosphere in space, the exhaust gases may leave the engine considerably.

Rocket engines use combustion to operate, just like engines on Earth. Since oxygen is required for all types of combustion, liquid oxygen or another oxidizer is carried by rockets into space. Thus, unlike an automobile engine, they are not dependent on the ambient air.

The Space Station also uses water, which is composed of hydrogen and oxygen atoms bound together, to sustain its oxygen supply. Astronauts and cosmonauts can separate oxygen from hydrogen by electrolyzing water, a procedure that includes passing electricity through water.

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Answer:

The ceramic tile will stand the force of 5 N.

Explanation:

Step 1: Calculate the area (A) of the ceramic tile

We will use the formula for the area of a square.

A = 50 cm × 50 cm = 2500 cm²

Step 2: Convert "A" to in²

We will use the conversion factor 1 in² = 6.45 cm².

2500 cm² × 1 in²/6.45 cm² = 3.9 × 10² in²

Step 3: Calculate the pressure (P) exerted by a force (F) of 5 N

We will use the following expression.

P = F/A

P = 5 N / 3.9 × 10² in² = 0.013 N/in²

Since the pressure exerted would be less than the maximum pressure resisted (40 N/in²), the ceramic tile will stand the force of 5 N.

The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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The displacement of an object is defined as a change in the position of the object. If the final position is x_f and the initial position is x_i, the displacement is given by:

Since the driver is spotted at the milepost 124 and then at the milepost 181, then the final position is 181 miles, and the initial position is 124 miles.

Substitute those values into the equation to find the displacement:

Then, the change in position was 57 miles towards the North.

Therefore, during that time interval, the bank robber's displacement was 57 miles towards the North. Then, the answer is: 57.

Given data

*The given speed of sound is v = 335 m/s

*The given distance is d = 43705 m

The formula for the time taken to hear the sound is given as

Substitute the values in the above expression as

Answer:

a) y = 127.6 m, b) 11.9s,  c)  v = 103.6  m / s, θ’= 326.7º

Explanation:

This is a missile throwing exercise

let's start by breaking down the initial velocity

         sin 30 = \(\frac{v_{oy} }{v_o}\)

         cos 30 = v₀ₓ / v₀

         v_{oy} = v₀ go sin 30

         v₀ₓ = v₀ cos 30

         v_{oy} = 100 sin 30 = 50 m / s

         v₀ₓ = 100 cos 30 = 86.6 m / s

a) the maximum height is requested.

At this point the vertical velocity is zero (v_y = 0)

         v_y² = \(v_{oy}^2\) - 2 g y

         0 = v_{oy}^2 - 2g y

         y = \(\frac{v_{oy}^2 }{2g}\)

         y = 50² / (2  9.8)

         y = 127.6 m

b) Flight time

this is the time it takes to reach the ground, the reference system for this movement is taken on the ground this is a height of y = 0 m and the body is at an initial height of i = 100m

         y = y₀ + v₀ t - ½ g t²

       0 = 100 + 50 t - ½ 9.8 t²

we solve the quadratic equation

        4.9 t² - 50 t - 100 = 0

         t = \(\frac{50 \pm \sqrt{50^2 + 4 \ 4.9 \ 100} }{2 \ 4.9}\)

         t = \(\frac{50 \ \pm \ 66.8}{9.8}\)

         t₁ = 11.9 s

         t₂ = -8.4 s

flight time is 11.9s

c) The time 1 s before hitting the ground is

        t1 = 11.9 -1

        t1 = 10.9 s

let's find the vertical speed

       v_y =\(v_{oy}\) - g t

       v_y = 50 - 9.8 10.9

       v_y = -56.8 m / s

the negative sign indicates that the direction of the velocity is downward.

On the x-axis there is no acceleration therefore the speed is constant.

Let's use the Pythagorean theorem

        v = \(\sqrt{v_x^2+v_y^2}\)

        v = \(\sqrt { 86.6^2 + 56.8^2}\)

        v = 103.6  m / s

let's use trigonometry

        tan θ = \(\frac{v_y}{v_x}\)

        θ = tan⁻¹  \frac{v_y}{v_x}

        θ = tan⁻¹  (-56.8 / 86.60)

        θ = -33.3º

the negative sign indicates that it is measured clockwise from the x-axis

for a counterclockwise measurement

          θ’= 360 - θ

          θ' = 360 - 33.3

          θ’= 326.7º

In order to determine which orientation results in a larger depolarization factor for the similar dielectric ellipsoids placed in an electric field, we need to consider the shape and alignment of the ellipsoids with respect to the electric field.

The depolarization factor measures the reduction in the electric polarization of a material due to its shape and alignment in an electric field. It is influenced by the geometry of the material and how it interacts with the electric field.

Qualitatively, if the ellipsoids are aligned in such a way that their major axes are parallel to the electric field lines, the depolarization factor would be smaller. This is because the electric field would act along the long axis of the ellipsoid, resulting in less distortion of the polarized charges inside the material. The polarization would be more effectively aligned with the electric field, minimizing the depolarization effect.

On the other hand, if the ellipsoids are oriented such that their major axes are perpendicular or at an angle to the electric field lines, the depolarization factor would be larger. In this case, the electric field would act in a direction that is not aligned with the major axis of the ellipsoid, causing more distortion and misalignment of the polarized charges inside the material. This results in a larger depolarization effect.

Without a specific diagram or more information about the orientations shown in Figure P5.5, it is difficult to determine the exact orientation with the larger depolarization factor. However, based on the general understanding of the relationship between alignment and the depolarization effect, the orientation where the major axes of the ellipsoids are perpendicular or at an angle to the electric field lines is likely to result in a larger depolarization factor.

The net force on q₂ will be  1.07 x 10⁻² N, pointing to the left.

To find the net force on particle q₂, we need to calculate the force due to q₁  and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:

F = k × (q₁ × q₂) / r²

where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

The force due to q₁ on q₂ can be calculated as:

F₁ = k × (q₁ × q₂) / r₁²

where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).

Similarly, the force due to q₃ on q₂ can be calculated as:

F₂ = k × (q₃ × q₂) / r₃²

where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).

The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.

To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:

Fnet = F₁ - F₃

Substituting the values we get:

Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²

Plugging in the values we get:

Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]

Fnet = 1.07 x 10⁻² N

Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.

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Answer:

So for an object moving in a circle, there must be an inward force acting upon it in order to cause its inward acceleration. This is sometimes referred to as the centripetal force requirement. The word centripetal (not to be confused with the F-word centrifugal) means center seeking.

Explanation:

hope this helps

According to the statement, on latitude (l) and mean temperatures in February, the least squares linear regression model calculated for these data was:

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Answer:

1,840,000 J

Explanation:

The energy required for a particular change in state is given by the specific latent heat. Specific latent heat is the amount of energy required to change the state of 1 ... of ice into 1 kg of water at its melting point of 0°C. The same amount of energy ... stored or released as the temperature of a system changes can be calculated.

According to the graph below, the statements about these cars must be true are :

options B and C are correct

Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

There are some similarities  between velocity and speed and they include:  

Velocity (v) is known as a vector quantity that measures displacement (or change in position, Δs) over the change in time.

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The graph is attached below:

Answer:

The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

Explanation:

We can find the drift speed by using the following equation:

\( v = \frac{I}{nqA} \)

Where:

I: is the current = 4.50 A

n: is the number of electrons

q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C

A: is the cross-sectional area = 2.20x10⁻⁶ m²

We need to find the number of electrons:

\( n = \frac{6.022\cdot 10^{23} atoms}{1 mol}*\frac{1 mol}{26.982 g}*\frac{2.70 g}{1 cm^{3}}*\frac{(100 cm)^{3}}{1 m^{3}} = 6.03 \cdot 10^{28} atom/m^{3} \)                  

Now, we can find the drift speed:

\(v = \frac{I}{nqA} = \frac{4.50 A}{6.03 \cdot 10^{28} atom/m^{3}*1.6 \cdot 10^{-19} C*2.20 \cdot 10^{-6} m^{2}} = 2.12 \cdot 10^{-4} m/s\)              

Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.

I hope it helps you!      

The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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Answer:

V = 4/3 π R^3 = 4/3 π 3.8^3 = 230 cm^3

M = ρ V = 8.89 g/cm^3 * 230 cm^3 = 2045 g

ΔQ = C M ΔT = .093 cal /g deg C * 2045 g * 240 deg C

ΔQ = 45,640 cal

Answer:

B Electrons are negatively charged while protons are positively charged

Answer:

which on a is the question

Answer:

Relative to solids and liquids, the air is a poor conductor of sound. Any elastic substance, solid-liquid gas plasma, can transmit sound. Inelastic substances (putty) cannot transmit sound. The speed of sound is generally greater in solids than in liquids and greater in liquids than in gases.

Explanation:

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\(b. \: outer \: space\)

Sound waves need to travel through a medium such as a solid, liquid, or gas.

Answer:

C

Explanation:

Option C is correct since it is the effect of Newton’s third law.

Considering the Coulomb's Law, the force between the two ballons is 9.216×10⁻⁸ N.

Charged bodies experience a force of attraction or repulsion on approach.

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that two balloons have a negative charge of 1.6×10⁻¹⁰ C and the balloons are 0.05 m apart.

Replacing in the Coulomb's Law, you get:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{(-1.6x10^{-10} C)x(-1.6x10^{-10} C)}{(0.05 m)^{2} }\)

Solving:

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } \frac{2.56x10^{-20} C^{2} }{(0.05 m)^{2} }\)

\(F=9x10^{9} \frac{Nm^{2} }{C^{2} } 1.024x10^{-17}\frac{ C^{2} }{m^{2} }\)

F= 9.216×10⁻⁸ N

Finally, the force between the two ballons is 9.216×10⁻⁸ N.

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