Answer:
Answer: we can form an Isosceles triangle using the given measures.
Which equation describes the line with slope -2/3 that crosses the y -axis at the point (0,4)
X = 4y -2/3
Y= -2/3x + 4
Y = 4x -2/3
X = -2/3y + 4
The line with slope -2/3 that crosses the y -axis at the point (0,4) exists X = -2/3y + 4.
What is meant by slope line ?When the slope of the line being studied is known, and the provided point is also the y intercept, the slope intercept formula, y = mx + b, is utilized (0, b). The y value of the y intercept point is represented by b in the equation.
The values of the y-intercept and slope reveal details on the nature of the relationship between the two variables, x and y. According to a unit change in x, the slope shows how quickly y changes. When the x-value is 0, the y-intercept shows the value of the y-axis.
Vertical lines are described as having "unknown slope" because their slope seems to be an arbitrary, arbitrarily high amount. The four different slope types are represented in the graphs below.
Therefore, the correct answer is option d) X = -2/3y + 4.
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Which city had the highest temperature?
Which city had the lowest temperature?
Which city had a temperature greater than Oakland?
What was the difference in temperature between Detroit and Oakland?
degrees Celsius.
r=11+8r=29 Please Helpppp me
What method are you using to solve this problem? Simplify, solve ? I need to know so I can help you out.
sin²A-cos²A=2sin²A-1
\(\sin^2\alpha-\cos^2\alpha=2\sin^2\alpha-1\\\sin^2\alpha+\cos^2\alpha=1\)
This is the Pythagorean identity, therefore \(\alpha\in\mathbb{R}\).
Step-by-step explanation:
please mark me as brainlest
150 people attend a play 45 of them are male write the ratio to males to females in its simplest form
Answer:
9/21
Step-by-step explanation:
45 / 105 = 9/21 (simplified)
Confirm that the spherical harmonics (a) Y0,0, (b) Y2,-1, and (c) Y3,+3 satisfy the Schr�dinger equation for a particle free to rotate in three dimensions, and find its energy and angular momentum in each case.
The spherical harmonics Y0,0, Y2,-1, and Y3,+3 satisfy the Schrödinger equation for a particle free to rotate in three dimensions, and have energies and angular momenta of E=0 and Lz=0, E=6.
(a) For Y0,0, the wave function ψ is proportional to Y0,0 and is independent of θ and φ. Therefore, the Laplacian operator acting on ψ reduces to:
∇^2ψ = (1/r^2) ∂/∂r (r^2 ∂/∂r) Y0,0 = -l(l+1) Y0,0
where l = 0 is the angular momentum quantum number. Substituting this into the Schrödinger equation gives:
(-ħ^2/2μ) (-l(l+1)) Y0,0 = E Y0,0
which has the solution E = 0 and angular momentum Lz = 0.
(b) For Y2,-1, the wave function ψ is proportional to Y2,-1 and depends on θ and φ. Therefore, the Laplacian operator acting on ψ reduces to:
∇^2ψ = (1/r^2) ∂/∂r (r^2 ∂/∂r) Y2,-1 - (2/r^2 sinθ) ∂/∂φ Y2,-1 = -l(l+1) Y2,-1
where l = 2 is the angular momentum quantum number. Substituting this into the Schrödinger equation gives:(-ħ^2/2μ) (-6) Y2,-1 = E Y2,-1which has the solution E = 6(ħ^2/2μ) and angular momentum Lz = -ħ.
(c) For Y3,+3, the wave function ψ is proportional to Y3,+3 and depends on θ and φ. Therefore, the Laplacian operator acting on ψ reduces to:
∇^2ψ = (1/r^2) ∂/∂r (r^2 ∂/∂r) Y3,+3 + (6/r^2 sinθ) ∂/∂φ Y3,+3 = -l(l+1) Y3,+3
where l = 3 is the angular momentum quantum number. Substituting this into the Schrödinger equation gives:
(-ħ^2/2μ) (-12) Y3,+3 = E Y3,+3which has the solution E = 12(ħ^2/2μ) and angular momentum Lz = +3ħ.
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To confirm that the spherical harmonics Y0,0, Y2,-1, and Y3,+3 satisfy the Schrödinger equation for a particle free to rotate in three dimensions, we need to substitute them into the equation and see if they hold true. Once we do that, we can solve for the energy and angular momentum in each case.
The Schrödinger equation involves the dimensions of position, momentum, and time, and it describes the behavior of quantum particles. For particles free to rotate in three dimensions, the equation involves angular momentum and its associated operators. The solutions for the spherical harmonics satisfy the Schrödinger equation and have well-defined energy and angular momentum values. By calculating these values for Y0,0, Y2,-1, and Y3,+3, we can better understand the behavior of quantum particles in three-dimensional space.
To confirm that the spherical harmonics Y0,0, Y2,-1, and Y3,+3 satisfy the Schrödinger equation for a particle free to rotate in three dimensions, we must first examine the equation, which describes the relationship between the energy (E) and the angular momentum (L) of the system.
For a particle free to rotate in 3D, the Schrödinger equation takes the form: Hψ = Eψ, where H is the Hamiltonian operator, ψ represents the wavefunction, and E is the energy. Spherical harmonics are solutions to this equation when the Hamiltonian only involves the angular momentum operator.
(a) Y0,0: With L=0 and M=0, the energy and angular momentum are E=0 and L=0.
(b) Y2,-1: With L=2 and M=-1, the energy is E=2(2+1)ħ²/2I, and the angular momentum is L=ħ√(2(2+1)).
(c) Y3,+3: With L=3 and M=3, the energy is E=3(3+1)ħ²/2I, and the angular momentum is L=ħ√(3(3+1)).
In all three cases, the spherical harmonics satisfy the Schrödinger equation, with the energy and angular momentum being proportional to their respective quantum numbers.
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help me please !!!!!!!!!!
1) 2m-1=3m
2) 2m=1+m
3) 3= 1+m
4) -2+m=1
5) 2+m=3
6) m-1=2
Hope this helped you- have a good day bro cya)
Not p has a truth value of 1 minus p. P logical and q has a truth value equal to the minimum of p and q. P logical or q has a truth value equal to the maximum of p and q. P right arrow q has a truth value equal to the min of 1 and 1 minus p plus q. P left right arrow q has a truth value equal to 1 minus StartAbsoluteValue p minus q EndAbsoluteValue. Suppose the statement "p: The sun is shining" has a truth value of 0.57 and the statement "q: Mary is getting a tan" has a truth value of 0.08. Find the truth value of
yes jxjfnsuspfjidheagdkhrsojieeidhj
explain what is the function of ‘unsupervised learning’? group of answer choices find interesting angles of data points in the data space find low-dimensional representations of the data interesting coordinates and correlation find clusters of the data
Unsupervised learning involves finding interesting angles of data points in the data space. The Option A.
What are the functions of unsupervised learning?Unsupervised learning serves several key functions in data analysis. By exploring the data space, it aims to identify intriguing angles or perspectives of the data points that may reveal hidden patterns or relationships.
It also seeks to uncover low-dimensional representations of the data, allowing for more efficient processing and analysis. Through identifying interesting coordinates and correlations within the data, its provide insights into how variables may be related or contribute to certain outcomes.
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(PLEASE HELP) Solve 10 =
5m/4
Answer:
\(m=8\)
Step-by-step explanation:
Given the following question:
\(10=\frac{5m}{4}\)
In order to find the answer, we have to remember when we have a two-step equation like this to multiply on both sides, and then divide both sides to isolate the variable.
\(10=\frac{5m}{4}\)
\(4\times10=40\)
\(40=5m\)
\(5m=40\)
\(5m\div5=m\)
\(40\div5=8\)
\(m=8\)
Hope this helps.
Ok so I don't know if it is (5m)/4 or 5(m/4) so I'll solve both
If it's (5m)/4 :
(5m)/4 = 10
5m = 10 x 4 = 40
m = 40/5 = 8
If it's 5(m/4)
5(m/4) = 10
m/4 = 10/5 = 2
m = 2 x 4 = 8
(same answers but different solutions so might as well)
a small company has five employees who missed work during a certain month. the number of days missed were: 1, 1, 2, 4, 7. what is the mode?
The mode will be = 5.2
What is mode?
A set of data values' mode is the value that appears the most frequently. The value of X at which the probability mass function reaches its highest value is known as the mode if X is a discrete random variable.
Consider the number of missed working days during a certain month of 5 employees of a company, 1,1,2,4,7
Mean age of the given data set will be its arithmetical average. Divide the sum of number of missed working days by 5. That is,
Mean number of days missed = 1+1+2+4+7/5
=15/5
=3days
hence mean = 3 days
Consider the formula for the variance for data set
σ² = ∑(X-µ)²/N
Compute the variance of given data set as follows
= 26/5
=5.2
Hence the variance is 5.2
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What is the median of this data set?
The median of the given data set as required to be determined in the task content is; 4.
What value represents the median of the data set?It follows from the task content that the value which represents the median of the data set is to be determined.
By observation, the number of data values in the data set is; 15. On this note, the median value would be the eighth term in an orderly arrange of the values.
Consequently, the median of the data set as required is; 4.
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Let f be a differentiable function such that f (2) = 4 and f (2) = − 1/2 . What is the approximation for f (2.1) found by using the line tangent to the graph of f at x = 2 ?
Using line tangent, the approximation for f(2.1) is 3.95
Given,
The point (a, f(a)) is on the line tangent to the graph of y = f(x) at x = a, which has a slope of f'(a).
The equation be like;
y - f(a) / (x - a) = f'(a)
y = f'(a) (x - a) + f(a)
Using the provided data and a = 2, we can determine that the tangent line to the graph of y = f(x) at x = 2 has equation
y = f'(2) (x - 2) + f(2)
y = -1/2 (x - 2) + 4
To compute a "approximation of f(2.1) using the line tangent to the graph of f at x = 2," one must substitute x = 2.1 for f in the equation for the tangent line (2.1). You get 2.1 when you plug this in.
y = -1/2 (x - 2) + 4
y = -1/2 (2.1 - 2) + 4
y = -1/2 x 0.1 + 4
y = 3.95
That is,
The approximation for f(2.1) using line tangent is 3.95
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Marvin lives in Stormwind city and works as an engineer in the city of Iran Forge in the morning he has to transportation, options, teleport, ride, a dragon, or walk to work, and in the evening he has the same choices for his trip home if Marvin randomly choose it, travel in the morning, and in the evening what is the probability that he teleports at least once per day?
The probability that Marvin teleports at least once per day is 9/25.
How to determine the he teleports at least once per dayThe probability that Marvin teleports to work in the morning is 1/5, since he has five transportation options and one of them is teleport.
The probability that he does not teleport to work is 4/5.
Similarly, the probability that Marvin teleports back home in the evening is also 1/5, and the probability that he does not is 4/5.
The probability that Marvin teleports at least once per day is the sum of the probabilities that he teleports in the morning, teleports in the evening, or teleports in both:
P(teleports at least once) = P(teleports in the morning) + P(teleports in the evening) - P(teleports both times)
P(teleports at least once) = (1/5) + (1/5) - (1/5)(1/5)
P(teleports at least once) = 9/25
Therefore, the probability that Marvin teleports at least once per day is 9/25.
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what type of number is the square root of 5
Answer:
Irrational
Step-by-step explanation:
root of 5 = 2.23606797749978969640917366873127623544061835961152572427089…
This number never ends. Another term for it would be a recurring decimal, but it is not exact. Anyway, the square root of 5 is irrational since it is not defined to stop. Even if it was rounded, it would not be exact.
Hope this Helps.
add the polynomials
The addition of the polynomials 2x² + 6x + 5 and 3x² - 2x - 1 will be 5x² + 4x + 4.
How to add the polynomialSums of terms of the form k × x^n, where k is any number and n is a positive integer, make up polynomials.
A polynomial is a mathematical equation made up of exponents, constants, and variables that are mixed using addition, subtraction, multiplication, and division.
Start with: 2x² + 6x + 5 + 3x² − 2x − 1
Place like terms together: 2x² +3x² + 6x−2x + 5−1
Which is: (2+3)x² + (6−2)x + L(5−1)
Add the like terms: 5x² + 4x + 4
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add the polynomials 2x² + 6x + 5 and 3x² - 2x - 1
At work, Julie focuses on measuring performance and takes the necessary corrective actions. Julie is engaged in the ________ function of the management process.
Julie, in her role at work, focuses on measuring performance and taking corrective actions, which indicates her involvement in the controlling function of the management process.
The controlling function of the management process involves monitoring and evaluating performance to ensure that organizational goals are achieved effectively and efficiently. It includes activities such as measuring performance, comparing it to predetermined standards or targets, identifying deviations or variances, and taking corrective actions as necessary. Julie's emphasis on measuring performance and implementing necessary corrective actions indicates her engagement in the controlling function. By monitoring performance and taking corrective actions, Julie plays a vital role in ensuring that the organization stays on track, addresses any performance gaps, and maintains alignment with established objectives and standards.
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How many words can be formed from the letters of the word 'ENGLISH' ? How many these do not begin with E? How many of these begin with E and do not end with H?
Total Number of words made out of English = 93
Determine whether the given coordinates are the vertices of a triangle. Explain.
F(-4,3), G(3,-3), H(4,6)
Since the points are not collinear, they satisfy the condition for a triangle, and therefore, F(-4, 3), G(3, -3), and H(4, 6) are the vertices of a triangle.
To determine whether the given coordinates F(-4, 3), G(3, -3), and H(4, 6) are the vertices of a triangle, we need to check if they satisfy the conditions required for a valid triangle.
A triangle is a closed figure with three sides and three angles, and its vertices should not be collinear (lie on the same line).
To verify if these points form a triangle, we can calculate the slopes of the lines connecting each pair of points and check if they are different.
The slope of a line passing through two points (x1, y1) and (x2, y2) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Let's calculate the slopes for the lines FG, FH, and GH:
Slope of FG:
m = (-3 - 3) / (3 - (-4)) = -6 / 7
Slope of FH:
m = (6 - 3) / (4 - (-4)) = 3 / 8
Slope of GH:
m = (6 - (-3)) / (4 - 3) = 9 / 1 = 9
The slopes of FG, FH, and GH are all different. Therefore, the lines connecting the points have different slopes, indicating that the points F, G, and H are not collinear.
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Determine the equation of the parabola graphed below. A parabola is plotted, concave up, with vertex located at coordinates four and two.
The equation of the given parabola is: y = (x - 4)² + 2
The equation of the given parabola graphed below, which is concave up and has a vertex located at coordinates (4, 2), can be determined using the standard form of the equation of a parabola. The equation of the given parabola with a vertex at (4, 2) can be found using the standard form of the equation of a parabola.
The standard form of the equation of a parabola is y = a(x - h)² + k, where (h, k) is the vertex and a is the constant determined by the focus and directrix of the parabola
Since the given parabola is concave up and has a vertex located at (4, 2), we know that the equation of the parabola must be of the form: y = a(x - 4)² + 2The value of a is determined by the distance between the vertex and focus of the parabola. Since the parabola is concave up, the focus is located above the vertex and the directrix is located below the vertex, both equidistant from the vertex.
The distance from the vertex to the focus is equal to a, and the distance from the vertex to the directrix is also equal to a. Since the vertex is located at (4, 2), the focus is located at (4, 2 + a), and the directrix is located at y = 2 - a. The distance between the vertex and focus is given by the formula:
d = |y-coordinate of focus - y-coordinate of vertex|
d = |(2 + a) - 2| = |a|
Similarly, the distance between the vertex and directrix is given by:
d = |y-coordinate of directrix - y-coordinate of vertex|
d = |2 - a - 2| = |-a|
Since the distances are equal, we can equate them:
|a| = |-a|
a = ± a
However, we know that a must be positive since the parabola is concave up. Therefore, a = |a|, and we can write:
a = 2 + a - 2
a = a²
a² - a = 0
a(a - 1) = 0
Thus, a = 0 or a = 1. Since a cannot be equal to 0, we have a = 1. Therefore, the equation of the given parabola is:
y = (x - 4)² + 2
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Find the volume of the hemisphere. Round to the nearest tenth.
6.7 ft
cubic feet
Answer:
78.7 cubic feet
Step-by-step explanation:
Remember that a hemisphere is half of a sphere, so finding the volume of a hemisphere is really just finding half of the volume of a sphere.
Volume of sphere = (4 * π / 3) * r ^ 3 , where r = diameter / 2.
So, volume of hemisphere = volume of sphere / 2 .
Volume of sphere = (4 * π / 3) * (6.7 / 2) ^ 3 = 157.47914.....
Volume of hemisphere = 157.47914....... / 2 = 78.7396..........
So it would approximately be 78.7 cubic feet
An equilateral triangle shares a single side with a kite to form a new
quadrilateral, as shown below.
Calculate the size of angle p.
Give your answer in degrees (°).
Answer:
<P = 41
Step-by-step explanation:
we can consider this first figure as a quadrilateral and the trianlgle attached to be is equilateral triangle (as it is already shown in the figure that sides are equal)
we know that each angle of equalateral triangle is 60°
we can see that angle 79° is attached to it and even other angle is also attached
let the other angle be x
we can notice that x and the angle of equi triangle make a linear pair
so 180 - 60
= 120°
the opposite angle to the angle x will be also equal as angles on the same side of qual sides will be equal
now we know that total angle sum of quadrilateral is 360°
so
79 + 120 + 120 + <P = 360
319 + <P = 360
<P = 360 - 319
<P = 41
Find the volume of A cube with sides of length 13 meters.
Answer:
V=2197
Step-by-step explanation:
Find the area of a regular octagon with a side length of 4 cm.
Answer:
77.25 cm^2
Step-by-step explanation:
Area of a regular octagon :
2a^2(1 + (sqrt2))
where a is the side
substitute 4 in for 'a'
Consider the vectors: a=(1,1,2),b=(5,3,λ),c=(4,4,0),d=(2,4), and e=(4k,3k)
Part(a) [3 points] Find k such that the area of the parallelogram determined by d and e equals 10 Part(b) [4 points] Find the volume of the parallelepiped determined by vectors a,b and c. Part(c) [5 points] Find the vector component of a+c orthogonal to c.
The value of k is 1, the volume of the parallelepiped is 12 + 4λ, and the vector component of a + c orthogonal to c is (1,1,1.5).
a) Here the area of the parallelogram determined by d and e is given as 10. The area of the parallelogram is given as `|d×e|`.
We have,
d=(2,4)
and e=(4k,3k)
Then,
d×e= (2 * 3k) - (4 * 4k) = -10k
Area of parallelogram = |d×e|
= |-10k|
= 10
As we know, area of parallelogram can also be given as,
|d×e| = |d||e| sin θ
where, θ is the angle between the two vectors.
Then,10 = √(2^2 + 4^2) * √((4k)^2 + (3k)^2) sin θ
⇒ 10 = √20 √25k^2 sin θ
⇒ 10 = 10k sin θ
∴ k sin θ = 1
Therefore, sin θ = 1/k
Hence, the value of k is 1.
Part(b) The volume of the parallelepiped determined by vectors a, b and c is given as,
| a . (b × c)|
Here, a=(1,1,2),
b=(5,3,λ), and
c=(4,4,0)
Therefore,
b × c = [(3 × 0) - (λ × 4)]i + [(λ × 4) - (5 × 0)]j + [(5 × 4) - (3 × 4)]k
= -4i + 4λj + 8k
Now,| a . (b × c)|=| (1,1,2) .
(-4,4λ,8) |=| (-4 + 4λ + 16) |
=| 12 + 4λ |
Therefore, the volume of the parallelepiped is 12 + 4λ.
Part(c) The vector component of a + c orthogonal to c is given by [(a+c) - projc(a+c)].
Here, a=(1,1,2) and
c=(4,4,0).
Then, a + c = (1+4, 1+4, 2+0)
= (5, 5, 2)
Now, projecting (a+c) onto c, we get,
projc(a+c) = [(a+c).c / |c|^2] c
= [(5×4 + 5×4) / (4^2 + 4^2)] (4,4,0)
= (4,4,0.5)
Therefore, [(a+c) - projc(a+c)] = (5,5,2) - (4,4,0.5)
= (1,1,1.5)
Therefore, the vector component of a + c orthogonal to c is (1,1,1.5).
Conclusion: The value of k is 1, the volume of the parallelepiped is 12 + 4λ, and the vector component of a + c orthogonal to c is (1,1,1.5).
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What is the median of the data 5,4,3,4,2
pls help me asap
Answer:
to find median first arrange the data 2,3,4,4,5
middle value=(n+1)/2
=(5+1)/2
=6/2
=3
3 means 3rd value which is 4
Show that the first derivatives of the following functions are zero at least once in the given intervals: f(x)=xsinpix-(x-2)lnx [1,2]
The first derivative of the function f(x) has at least one zero within the interval [1, 2].
To show that the first derivative of the function f(x) = x * sin(πx) - (x - 2) * ln(x) is zero at least once in the interval [1, 2], we need to find the critical points of the function within that interval.
Let's start by finding the first derivative of f(x):
f'(x) = (x * d(sin(πx))/dx) - d((x - 2) * ln(x))/dx
= (x * π * cos(πx)) - ((x - 2) * (1/x) + ln(x))
Now, we can set f'(x) equal to zero and solve for x:
0 = (x * π * cos(πx)) - ((x - 2) * (1/x) + ln(x))
Simplifying the equation further, we get:
(x * π * cos(πx)) = (x - 2) * (1/x) + ln(x)
To solve this equation, we can use numerical methods or graphing software to find the approximate solutions within the interval [1, 2].
Using graphing software, we find that the equation has one critical point within the interval [1, 2], which occurs approximately at x ≈ 1.364.
Therefore, the first derivative of the function f(x) has at least one zero within the interval [1, 2].
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How much sales tax will be changed at Store B
Answer:
8
Step-by-step explanation:8
Use each of the five digits $2, 4, 6, 7$ and $9$ only once to form a three-digit integer and a two-digit integer which will be multiplied together. What is the three-digit integer that results in the greatest product
Answer:
The 3 digit number 642 when multiplied 97 gives the greater product.
Step-by-step explanation:
The greatest product will result by multiplying the smaller 3 digit number with the greater two digit number.
The greater three digit number will be 976 and smaller 2 digit number would be 42
Multiplying
976*42 = 40992 ( descending order number)
679 *24= 16,296 ( ascending order number)
If we take the 2 digit number as 97 and 3digit number 642
Then multiplying
642* 97= 62,274 ( descending order number)
246 * 79=19434 ( ascending order number)
The 3 digit number 642 when multiplied 97 gives the greater product.
Suppose a curve is traced by the parametric equations x=2(sin(t)+cos(t)) y=36−10cos2(t)−20sin(t) as t runs from 0 to π . At what point (x,y) on this curve is the tangent line horizontal?
The two points on the curve where the tangent line is horizontal are (2,26) and (-2,26).
To find where the tangent line is horizontal, we need to find where the derivative of y with respect to x (dy/dx) equals 0.
First, we need to express y in terms of x. We can do this by eliminating t from the two parametric equations.
From x=2(sin(t)+cos(t)), we get sin(t) = (x/2) - cos(t).
From y=36−10cos2(t)−20sin(t), we substitute sin(t) with the above expression and get:
y = 36 - 10cos²(t) - 20((x/2) - cos(t))
Simplifying this expression, we get:
y = -10cos²(t) - 10x + 36
Next, we need to find the derivative of y with respect to x:
dy/dx = -10sin(2t)/(dx/dt)
From x=2(sin(t)+cos(t)), we get dx/dt = 2(cos(t)-sin(t))
Substituting this into the above equation for dy/dx, we get:
dy/dx = -5sin(2t)/(cos(t)-sin(t))
Setting dy/dx equal to 0, we get:
0 = -5sin(2t)/(cos(t)-sin(t))
This means sin(2t) = 0, or t = 0 or t = π/2.
Plugging these values into the parametric equations for x and y, we get:
When t=0: x = 2, y = 26
When t=π/2: x = -2, y = 26
Thus, the two points on the curve where the tangent line is horizontal are (2,26) and (-2,26).
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