Answer: Convention
Explanation: Convention is pretty well known for being a process that transmits heat from one place to another place with the movements of heated particles. I got this answer from my notebook during my chemistry class.
Hope this answer helps!
A ball thrown vertically upward returns to the thrower 25s later determine the speed with which it was thrown
25/2=12.5s
12.5*9.8=122.5 m/s
A 2 m long wire carrying 2 A of current pointing to the right is placed in a magnetic field of 4 T directed away from you. Which direction does the force on the wire point?
A. Down
B. Up
C. Left
D. Right
Explanation:
To determine the direction of the force on the wire, we can use the right-hand rule for the cross product of two vectors. The force on the wire is given by:F = I * L x Bwhere I is the current, L is the length of the wire, and B is the magnetic field.
If we point our right-hand thumb in the direction of the current (to the right), and our fingers in the direction of the magnetic field (away from us), then our palm will point in the direction of the force.
So, using the right-hand rule, we can see that the force on the wire will be directed downward. Therefore, the correct answer is A. Down.help me please!!!!!!!!!!!!!!!!
In a skate park, you are trying to determine how to get the most speed at the bottom of the ramp. If the ramp is 4.5 m high, and you start at the top of the ramp with an initial velocity of 1.5m/s, how fast will you be rolling at the bottom of the ramp, given there is no friction. Use conservation of energy to solve.
Answer:
If you have an initial velocity of 1.5m/s and the ramp height is 4.5, and an extreme fart is initiated at the bottom of the ramp exerting an didditional upward force, and the smell of the fart causes you to begin flailing, and everyone running from you causes an additional wind force, then you would be rolling at a speed of 3 m/s given there is no friction. :)
The primary coil of a transformer has 200 turns and the secondary coil has 800 turns. The power supplied to the primary coil is 400 watts. What is the power generated in the secondary coil if it is terminated by a 20-ohm resistor? The primary coil of a transformer has 200 turns and the secondary coil has 800 turns. The power supplied to the primary coil is 400 watts. What is the power generated in the secondary coil if it is terminated by a 20-ohm resistor? 20W 200W 400W 800W 8000W 16000W 32000W\
Answer:
400 W
Explanation:
Ignoring the efficiency rating for the transformer we have to assume 100% .. Also, the power input to primary is equal to the power output in secondary.
This means that power input = 400 W = power output
The law of conservation of mass states that ___________
A.) matter cannot be created or destroyed
B.)mass can be created if a chemical reaction occurs
C.) atoms conserve mass when they fuse to form molecules
The law of conservation of mass states that matter cannot be created or destroyed.
The law of conservation of mass states that the mass of the reactant must be equal to the mass of the product.
In 18th century law of conservation of mass was given by Levoisier.
It states that mass is neither created nor destroyed.
Example -
when wood burns the mass of the suit ,ashes and gases equal to the original mass of the charcoal. after heating the ice it will convert into water. Mass of the ice does not change after undergoes a physical. Change.
The law of conservation of mass states that matter cannot be created or destroyed.
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A projectile is fired straight up with an initial velocity of 40.0 m/s . Approximately how high will the projectile ?
Answer:
it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters
Explanation:
hope it helped
:)
A car of mass 2000kg accelerates from 0 to 30ms-¹ in 5.5seconds.
Calculate the mean resultant force on the car during that time.
(Hint: use suvat equations before Newtons second law)
Using the Suvat equations, a car of mass 2000 kg accelerates from 0 to 30 m/s in 5.5 seconds, so the mean resultant force on the car during the 0–30 m/s acceleration period is 10,900 N.
What is the resultant force?Using the following suvat equation,
v = u + at
( v = final velocity (30 m/s), u= initial velocity (0 m/s), a= acceleration (not known), and t = time taken (5.5 s). )
a = (v - u) / t
a = (30 m/s - 0 m/s) / 5.5 s
a = 5.45 m/s²
applying Newton's second law of motion,
Force = Mass x Acceleration
Force = 2000 kg x 5.45 m/s²
Force = 10,900 N
Hence, the mean resultant force on the car during the 0–30 m/s acceleration period is 10,900 N.
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Equipotential Surfaces: A region of space contains a uniform electric field directed in the positive x direction as shown. Among the following the correct statements about the electric potential is: Select one: VYYc b. V₁ V₂ Ve d. We can't judge
The true statement about the electric potential for the equipotential surface is \(V_A = V_B = V_C\)
What is equipotential surface?A surface with an equipotential potential is one where all points on the surface have the same electric potential. .
That is an equipotential surface is that surface at every point of which, the electric potential is the same.
The formula for the potential across every point on the surface is given as;
V = F/Q x R
V = ER
where;
E is the electric field across the surfaceR is the distance or position of the chargeSince the surface is equipotential with uniform electric across the surface, the electric potential at any point across the surface will be the same.
So \(V_A = V_B = V_C\)
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Define angle of deviation ?
Angle of deviation can be defined as the angle between the incident ray and the emergent ray when light passes through a prism.
What are related terms to Angle of deviation?When speaking of Angle of deviations, the incident ray is the ray of light that hitss the prism, while the emergent ray is the ray of light that emerges from the prism.
The angle of deviation is noted to be always greater than zero, and it can be used to calculate the refractive index of the prism.
The angle of deviation can be calculated using δ = i + r - A
δ is the angle of deviation
i is the angle of incidence
r is the angle of refraction
A is the angle of the prism
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PLEASE HELP NO LINKS NEED HELP FAST
Use the scenario to answer the question.
An astronomer discovers a new galaxy using a telescope. The astronomer wants to investigate how the galaxy is moving relative to the Milky Way galaxy.
In one or two sentences, make a hypothesis about the movement of the galaxy and explain at least one way to test the hypothesis.
Answer:
The galaxies outside of our own are moving away from us, and the ones that are farthest away are moving the fastest. This means that no matter what galaxy you happen to be in, all the other galaxies are moving away from you
Explanation:
The hypothesis about the movement of the galaxy is that galaxies are moving far from each other continuously.
What is the milky way galaxy?The milky way galaxy is a galaxy that contains over a hundred billion stars and it also includes our solar system. Its name describes its appearance when viewed from the earth. All the individual stars in the whole sky are a portion of the Milky Way Galaxy, the term "Milky Way" is because of the band of light.
The astronomer has discovered a new galaxy which means our universe is continuously expanding. This is because the universe encloses everything that exists.
Galaxies are moving in space and since the universe space is continuously expanding so the galaxies continuously move from each other. The farther the galaxy is from the milky way which is an observable part, the faster will be moving the galaxy and the closer the galaxy is to the milky way, the slower will be movement of the galaxy.
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Two blocks can collide in a one-dimensional collision. The block on the left hass a mass of 0.30 kg and is initially moving to the right at 2.4 m/s toward a second block of mass 0.80 kg that is initially at rest. When the blocks collide, a cocked spring releases 1.2 J of energy into the system. (For velocities, use to mean to the right, - to mean to the left).A) What is the velocity of the first block after the collision?
B) What is the velocity of the second block after the collision?
Answer:
a) 3.632 m/s
b) 0.462 m/s
Explanation:
Using the law of conservation of momentum:
\(m_{1} u_{1} + m_{2} u_{2}= m_{1} V_{1} + m_{2} V_{2}\)..........(1)
\(m_{1} = 0.30 kg\\u_{1} = 2.4 m/s\\m_{2} = 0.80 kg\\u_{2} = 0 m/s\)
Substituting the above values into equation (1) and make V2 the subject of the formula:
\(0.3(2.4) + 0.80(0)= 0.3 V_{1} + 0.8 V_{2}\\\)
\(V_{2} = \frac{0.72 - 0.3 V_{1}}{0.8}\)..................(2)
Using the law of conservation of kinetic energy:
\(0.5m_{1} u_{1} ^{2} + 1.2 = 0.5m_{1} V_{1} ^{2} + 0.5m_{2} V_{2} ^{2}\\0.5(0.3) (2.4) ^{2} + 1.2 = 0.5(0.3) V_{1} ^{2} + 0.5(0.8)V_{2} ^{2}\\\)
\(2.064 = 0.15 V_{1} ^{2} + 0.4V_{2} ^{2}\).......(3)
Substitute equation (2) into equation (3)
\(2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.72 - 0.3V_{1} }{0.8}) ^{2}\\2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.5184 - 0.432V_{1} + 0.09V_{1} ^{2} }{0.64}) \\1.32096 = 0.096 V_{1} ^{2} + 0.20736 - 0.1728V_{1} + 0.036V_{1} ^{2} \\0.132 V_{1} ^{2} - 0.1728V_{1} - 1.1136 = 0\\V_{1} = 3.632 m/s\)
Substituting \(V_{1}\) into equation(2)
\(V_{2} = \frac{0.72 - 0.3 *3.632}{0.8}\\V_{2} = \frac{0.72 - 0.3 *(3.632)}{0.8}\\V_{2} = 0.462 m/s\)
A 60-W light bulb radiates electromagnetic waves uniformly in all directions. At a distance of 1.0 mm from the bulb, the light intensity is Io, the average energy density of the waves is u0, and the rms electric and magnetic field values are Eo and Bo, respectively.
Required:
a. What is the light intensity?
b. What is the average energy density of the waves?
c. What is the rms magnetic field value?
Answer:
The appropriate solution is:
(a) \(\frac{1}{4}(I_o)\)
(b) \(\frac{1}{4} (u_o)\)
(c) \(\frac{1}{2}B_o\)
Explanation:
According to the question, the value is:
Power of bulb,
= 60 W
Distance,
= 1.0 mm
Now,
(a)
⇒ \(\frac{I}{I_o} =\frac{r_o_2}{r_2}\)
On applying cross-multiplication, we get
⇒ \(I=I_o\times \frac{1_2}{2^2}\)
⇒ \(=I_o\times \frac{1}{4}\)
⇒ \(=\frac{1}{4} (I_o)\)
(b)
As we know,
⇒ \(\frac{u}{u_o} =\frac{I}{I_o}\)
By putting the values, we get
⇒ \(u=\frac{1}{4}(u_o)\)
(c)
⇒ \(\frac{B^2}{B_o^2} =\frac{u}{u_o}\)
\(=\frac{I}{I_o}\)
⇒ \(B=B_o\times \sqrt{\frac{1}{4} }\)
⇒ \(=\frac{1}{2}(B_o)\)
Which situation does NOT show kinetic energy? *
PLS ANSWER ASAPPPP
Answer options:
A. a hockey puck sliding on the ice
B. a baseball in a catcher's glove
C. a lady walking slowly across the street
D. a man running around a track
"Kinetic" energy is the energy of motion.
The ball in the glove is not moving. It's just laying there. (B)
So it has no kinetic energy.
All the other choices describe something moving, so they all have some.
If a boy lifts a mass of 6kg to a height of 10m and travels horizontally with a constant velocity of 4.2m/s, calculate the work done? Explain your answer.
Answer:
W = 641.52 J
Explanation:
The work done here will be the sum of potential energy and the kinetic energy of the boy. Here potential energy accounts for vertical motion part while the kinetic energy accounts for the horizontal motion part:
\(Work\ Done = Kinetic\ Energy + Potential\ Energy\\\\W = K.E +P.E\\\\W = \frac{1}{2}mv^2+mgh\\\\\)
where,
W = Work Done = ?
m = mass = 6 kg
v = speed = 4.2 m/s
g = acceleration dueto gravity = 9.81 m/s²
h = height = 10 m
Therefore,
\(W = \frac{1}{2}(6\ kg)(4.2\ m/s)^2+(6\ kg)(9.81\ m/s^2)(10\ m)\)
W = 52.92 J + 588.6 J
W = 641.52 J
a concave mirror has a focal length of 12cm the object is [laced at 24cm. What type, orientation,location and magnification does the image have?
To obtain the type, orientation, location and magnification of the image, we shall first obtain the location (i.e distance) of the image from the mirror. Details below:
The location i.e distance of the image can be obtained as follow:
Focal length (f) = 12 cmObject distance (u) = 24 cmImage distance (v) =?1/f = 1/v + 1/u
Rearrange
1/v = 1/f - 1/u
v = (f × u) / (u - f)
v = (12 × 24) / (24 - 12)
v = 288 / 12
v = 24 cm
Thus, the the location of the image is 24 cm
Since the location of the image is positive (i.e 24 cm). Thus,
The type of image is realThe orientation of the image is invertedNow, we shall obtain the magnification of the image. Details below:
Object distance (u) = 24 cmImage distance (v) = 24 cmMagnification (m) = ?Magnification = image distance (v) / object distance (u)
Magnification = 24 / 24
Magnification = 1
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Part A
Choose the correct free body diagram for the case when the ball is at its lowest point
The correct free body diagram for the case when the ball is at its lowest point is tension pointing upwards and weight of the object pointing downwards.
What is the tension in the string at the lowest point in circular path?
The tension in the string at the lowest point in a circular path is equal to weight added to centripetal force required.
Mathematically, the formula for the tension in the string is given as;
T = W + ma
where;
W is the weight on the stringm is the mass of the objecta is the acceleration of the objectAt the lowest point the acceleration of the object is zero, a = 0. The new equation becomes the following;
T = W
The free body diagram of the tension and the weight of the object is given as;
↑ T
Ф
↓ W
Thus, the correct free body diagram consist of the tension force pointing upwards and the weight of the object pointing downwards.
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While operating around buildings, the remote PIC should be aware of the creation of wind gusts that
answer choices
— change rapidly in direction and speed causing turbulence.
— enhance stability and imagery.
— increase performance of the aircraft.
The remote PIC should be aware of the wind gust because of a) the rapid change in direction and speed which causes turbulence.
The wind gust is a sudden short-term increase in wind speed. According to US weather observation practice, a gust is reported when the maximum wind speed reaches at least 16 knots and the difference between the maximum wind speed and the light wind speed reaches at least 9 knots. Wind forces can disrupt a building's load path or pierce the building's skin. Doors and windows can burst in really high winds. In other cases, nearby debris can be caught in the wind and flung into the building's envelope.
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A falling object satisfies the initial value problem dv dt = 9.8 − v 5 , v(0) = 0 where v is the velocity in meters per second. (a) Find the time that must elapse for the object to reach 95% of its limiting velocity. (Round your answer to two decimal places.) s (b) How far does the object fall in the time found in part (a)? (Round your answer to two decimal places.) m Additional Materials
Answer:
a. t \(\simeq\) 14.98 sec
b. x = 501.27 m
Explanation:
From the given information:
\(\dfrac{dv}{dt}=9.8-(\dfrac{v}{5 })\) and \(v(0)=0\)
\(\dfrac{dv}{dt}=\dfrac{49-v}{5 }\)
\(\dfrac{dv}{49-v}=\dfrac{dt}{5 }\)
Taking Integral of both sides
\(- ln(49-v) = \dfrac{t}{5} + C\)
at t=0 we have v=0
This implies that
\(- ln(49-0) = \dfrac{0}{5} + C\)
\(C= - ln(49)\)
Thus:
\(\dfrac{t}{5} - In (49) = - In (49 -v) \\ \\ In(49) - \dfrac{t}{5} = In (49-v)\)
\(49-v = e^{(-\frac{t}{5} +ln(49))}\\ \\ v = 49 - 49e^{(-\dfrac{t}{5})}\)
The limiting velocity when the time is infinite is :
95% of 49 = 46.55
∴
\(0.05= e^{(-\dfrac{t}{5})}\)
\(\dfrac{t}{5}= In(\dfrac{1}{0.05})\)
\(\dfrac{t}{5}=2.9957\)
t = 5 × 2.9957
t \(\simeq\) 14.98 sec
b.) \(v = 49 - 49e^{(-\dfrac{t}{5})}\)
\(v = \dfrac{dx}{dt}=49 - 49e^{(-\dfrac{t}{5})}\)
\(dx=(49 - 49e^{(-\frac{t}{5})}) \ dt\)
Taking integral of both sides.
\(x = 49t + 245 e^{(\frac{-t}{5})} +C\)
at time t = 0 , distance x traveled = 0
∴
C= - 245
Therefore
\(x = 49t + 245 e^{(\frac{-t}{5})} -245\)
replacing the value of t = 14.98
\(x = 49(14.98) + 245 e^{(\frac{-14.98}{5})} -245\)
x = 501.27 m
Make a poem about waves with 12 Lines and 3 Stanzas.
In a ocean full of storms
A new wave was born
Deep into that darkness flooding
Suddenly, I heard some pummeling
By the grave I saw the winds
And the sun just shined
Answer:
a friendly face that comes with waves,
the waves of all the memorial days,
and with these days we smile with pride,
as for the waves we used to ride,
given up the day has passed,
how it went away like an hour glass,
as if we knew the world was right,
just like the waves, oh so bright,
the time has come the days have passed,
the waves ashore the waves alast,
as if the friendly face was right,
the waves that rode, oh goodnight.
Calculate the frequency if the number of revolutions is 300 and the paired poles are 50.
15 kHz
150 kHz
1500 kHz
150 Hz
Answer: A
Explanation: We know that f=p*n
f=50*300=15000 Hz = 15kHz.
Have a great day! <3
If the number of revolutions is 300 and the paired poles are 50 , then the frequency would be 15 kHz, therefore the correct answer is option A.
What is the frequency ?It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.
The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,
F = 1 / T
As given in the problem, we have to calculate frequency if the number of revolutions is 300 and the paired poles are 50.
F = 300 × 50
= 1500 kHz
Thus, If the number of revolutions is 300 and the paired poles are 50, then the frequency would be 15 kHz, therefore the correct answer is option A.
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which of these are lost when the body repairs?
oxygen and calcium
calcium and sodium
sodium and potassium
potassium and oxygen
c. Sodium and potassium
What is called perspiration?Perspiration, water given off by the intact skin, either as vapor by simple evaporation from the epidermis or as sweat, a form of cooling in which liquid actively secreted from sweat glands evaporates from the body surface.
When our body is sweating sodium and potassium is lost from the body along with water.
In order to maintain the integrity of the cells in the body ,Sodium and potassium are very important.
Sweat is also known as perspiration.
So,
By maintaining the proper cell functioning and cell vitality optimum level of sodium and potassium should be maintained in the body.
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A cart is pulled by a rope making an angle of 45° to the horizontal. If 100 newtons of force are applied to the rope, the magnitude of the horizontal component force is approximately
Answer:
the answer is 100sin45°
Explanation:
F=100N
0=45°
component to the horizontal so we say 90°-45°=45°
magnitude of component =100sin45°
A hypothesis always starts with.....
Question 1 options:
If
then
conclusion
because
Answer:
because
Explanation:
starts with question then explored through the mind.
Galileo
o did not believe friction existed
o believed that friction stopped objects in motion
o believed that friction kept objects in motion
О
assumed that in a frictionless environment objects would never move
Answer:
object would move but it could be difficult to slow down or stop.
1. Two charges are separated by a distance of 1 cm. One charge has a value of 7 micro Coulombs. The other charge has a value of 10 micro Coulombs. What is the force between them, in pounds. Make sure to include the sign of the force which will be positive if the charges repel each other and negative if they attract each other.
2. 12 gauge copper wire is normally used in house wiring. When aluminum wire is used one needs to use a smaller gauge size to obtain the same resistance, 40 ft of 12 gauge copper wire was calculated. What would the resistance be if 10 gauge aluminum wire were used?
3. A 12 V automobile battery can supply 51 amps for one hour and cost $194. What is the cost of this electricity in cents per kWh?
4. Most of the body's resistance is in its skin. When wet, salts go into ion form, and the resistance is lowered. Thus, the resistance of the skin can go from 100,000 ohms when dry to 300 ohms when wet. What is the current that would be carried through the body, in milliAmperes, if you touched a 240 V power line while dry? Currents over 10 mA are almost always deadly.
1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.
2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.
3. The cost of electricity from the automobile battery is 38.6 cents per kWh.
4. The current that would be carried through the body is 0.8 mA if dry.
1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.
2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.
Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.
3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.
Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.
4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.
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wire (mass = 50 g, length = 40 cm) is suspended horizontally by two vertical wires which
conduct a current I = 8.0 A, as shown in the figure. The magnetic field in the region is into the
paper and has a magnitude of 60 mT. What is the tension in either wire?
The magnetic field in the region is into the paper and has a magnitude of 60 mT and the tension in either wire is 0.096 N.
To find the tension in either wire, we can apply the equation for the force experienced by a current-carrying wire in a magnetic field.
The force experienced by a current-carrying wire in a magnetic field is given by the equation F = B * I * L * sin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.
In this case, the wire is suspended horizontally by two vertical wires, and the magnetic field is into the paper. Since the wire is horizontal, the angle between the wire and the magnetic field is 90 degrees, so sin(θ) = 1.
The force experienced by the wire due to the magnetic field is F = B * I * L.
Given:
Current (I) = 8.0 A
Magnetic field (B) = 60 mT = 60 * 10^(-3) T
Length of the wire (L) = 40 cm = 40 * 10^(-2) m
Substituting the given values into the equation, we get:
F = (60 * 10^(-3) T) * (8.0 A) * (40 * 10^(-2) m)
Simplifying the expression, we find:
F = 0.192 N
Since the wire is suspended by two vertical wires, the tension in each wire will be half of the total force. Therefore, the tension in either wire is 0.192 N / 2 = 0.096 N.
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When I mix 200g of water at 10°C with 300g of water at 55°C, what is the final temperature of the mixture?
Answer:
4th of August is the
Explanation:
5th and then I can help out by getting
What would the separation between two identical objects, one carrying 4 C of positive charge and the other 4 C of negative charge, have to be if the electrical force on each was precisely 8 N
Answer:
7.46×10⁻⁶ m
Explanation:
Applying,
F = kqq'/r²............ Equation 1
make r the subject of the equation
r = √(F/kqq').......... Equation 2
From the question,
Given: F = 8 N, q' = q= 4 C
Constant: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 2
r = √[8/(4×4×8.98×10⁹)]
r = √(55.7×10⁻¹²)
r = 7.46×10⁻⁶ m
Which statement about electric charges is correct? (1 point)
*two objects with negative charges will attract each other
*an object with a negative charge and an object with a positive charge will attract each other
*an object with a positive charge and an object with a negative charge will repel each other
*two objects with positive charges will attract each other
Answer:The correct statement about electric charges is:
"An object with a negative charge and an object with a positive charge will attract each other."
Explanation:
*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.
What is charge ?Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.
Hence option B is correct.
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