which type of electromagnetic radiation travels the fastest
all electromagnetic radiation travels at the same speed
visible light
radio waves
x-rays

Answers

Answer 1

Answer:

visible waves

Explanation:

because visible waves are the brightest

Answer 2

Answer:

The answer to this question is: visible light

Explanation:

This is the answer because:Photons travel in harmonic waves at the fastest speed possible in the universe: 186,282 miles per second (299,792,458 meters per second) in a vacuum, also known as the speed of light.


Related Questions

The equilibrium constant, Kc, for the reaction below is 0.10 at 25oC. Find the equilibrium concentration of chlorine gas, Cl2(g), if the equilibrium concentrations of ICl(g) and I2(g) are known to be 0.50 M and 0.40 M respectively.

2 ICl(g) → Cl2(g) + I2(g)

Answers

Answer:

The equilibrium concentration of chlorine gas, Cl₂(g), is 0.0625 M

Explanation:

Chemical equilibrium is established when there are two opposite reactions that take place simultaneously at the same speed, so that no changes are observed as time passes, despite the fact that the substances present continue to react with each other.

The mathematical expression that represents Chemical Equilibrium is known as the Law of Mass Action and is stated as: The ratio of the product of high concentrations to the stoichiometric coefficients in the reaction of products and reactants remains constant at equilibrium. For any reaction:

aA + bB ⇄ cC + dD

the equilibrium constant Kc is calculated as:

\(Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b}}\)

In this case, you have:

2 ICl(g) → Cl₂(g) + I₂(g)

So, the equilibrium constant Kc is:

\(Kc=\frac{[Cl_{2} ]*[I_{2} ]}{[ICl]^{2} }\)

Being:

Kc= 0.10[Cl₂]= ?[ICl]= 0.50 M[I₂]= 0.40 M

Replacing:

\(0.1=\frac{[Cl_{2} ]*0.40 M}{(0.50 M)^{2} }\)

Solving:

\(0.1=\frac{[Cl_{2} ]*0.40 M}{0.25 M^{2} }\)

0.1= 1.6 \(\frac{1}{M}\)* [Cl₂]

[Cl₂]= 0.1 ÷ 1.6 \(\frac{1}{M}\)

[Cl₂]= 0.0625 M

The equilibrium concentration of chlorine gas, Cl₂(g), is 0.0625 M

The equilibrium concentration of chlorine gas, if the equilibrium concentrations of ICl(g) and I₂(g) are known to be 0.50 M and 0.40 M respectively is 0.0625M.

How we calculate the equilibrium constant?

Equilibrium constant for any reaction will be define as the ratio of the concentration of products to the concentration of reactants with raise to their respective coefficients.

Given chemical reaction is:

2ICl(g) → Cl₂(g) + I₂(g)

Equilibrium constant for this reaction will be calculated as:

Kc = [Cl₂][I₂] / [ICl]², where

Kc = equilibrium constant = 0.10

[I₂] = concentration of iodine gas = 0.40 M

[ICl]² = concentration of ICl = 0.50 M = (0.50M)² = 0.25M²

[Cl₂] = concentration of chlorine gas = to find?

On putting all these values on the above equation and calculate for the value of [Cl₂] as follow:
[Cl₂] = Kc × [ICl]² / [I₂]

[Cl₂] = (0.10)(0.25) / (0.40)

[Cl₂] = 0.0625M

Hence, equilibrium concentration of chlorine gas is 0.0625M.

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Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus chloride.

2P +3Cl2 2PCl3

How much chlorine reacted with the phosphorus?

15.5 g
17.7 g
35.4 g
66.4 g

Answers

Answer: 35.4 g

2 moles of phosphorous chloride are produced by = 3 moles of  

Thus 0.37 moles of phosphorous chloride are produced by= of  

Mass of  

Thus 35.4 g of chlorine reacted with the phosphorus

Answer 35.4g
That’s the answer

Indicate which species can behave as a Lewis acid, but cannot behave as a Bronsted acid. AlF3 H2O C2H4 BrOH NH4 1

Answers

A Lewis acid is a compound or ion that can accept a pair of electrons to form a new covalent bond. \(AlF_3\) is the only species that can behave as a Lewis acid but not as a Bronsted acid.

On the other hand, a Bronsted acid is a species that donates a proton (H+) to a base. Among the given species, \(AlF_3\) can behave as a Lewis acid but cannot behave as a Bronsted acid. This is because \(AlF_3\) has an incomplete octet and can accept a pair of electrons to form a new bond. However, it does not have any hydrogen atom to donate a proton to a base, which is a requirement for a species to behave as a Bronsted acid. \(H_2O\), \(C_2H_4\), BrOH, and \(NH_4\) can act as both Lewis and Bronsted acids as they have both electron-pair accepting and proton-donating capabilities.

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A magnesium atom that loses two electrons becomes a...

Answers

Answer:

Positive ion with a smaller radius

Explanation:

Castle learning

A magnesium atom that loses two electrons becomes a magnesium ion. Negative charge characterizes electrons. As a result, magnesium will become a positively charged ion after losing two electrons.

What is an electron ?

The elementary electric charge of the electron is a negative one, making it a subatomic particle. Due to their lack of components or substructure, electrons, which are members of the lepton particle family's first generation, are typically regarded to be elementary particles.

The terms electric and ion are combined to form the word electron. In turn, electron is derived from the suffix -on, which is currently used to describe other subatomic particles, such as a proton or neutron.

Magnesium is an element with two valence electrons. Magnesium may readily lose or ionize these two electrons when it forms an ionic connection with a nonmetal.

Thus, magnesium will become a positively charged ion after losing two electrons.

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Which nitrogen base sequence is the partner of C-A-T-C-G-A?
C-A-T-C-G-A
G-T-A-G-C-T
T-G-C-T-A-G
G-C-A-T-G-T

Answers

Answer:

The answer should be B. G-T-A-G-C-T

A pairs with T and G pairs with C.

Answer:

It's B, GTAGCT.

Explanation:

How many joules
are
equal to 2.45 calories?

Answers

Answer:

10250.8

Explanation:

Formula

multiply the energy value by 4184

Give an example of when
carbon can displace a metal
from its compounds and when it cannot?

Answers

Answer:

If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.

Explanation:

Part A Write an equation for the formation of HCl(g) from its elements in their standard states. Express your answer as a chemical equation. Identify all of the phases in your answer.
Part B Write an equation for the formation of MgO(s) from its elements in their standard states. Express your answer as a chemical equation. Identify all of the phases in your answer.
Part C Write an equation for the formation of FeCl3(s) from its elements in their standard states. Express your answer as a chemical equation. Identify all of the phases in your answer.

Answers

The equation for the formation of HCl(g) from its elements in their standard states is: 2H₂(g) + Cl₂(g) → 2HCl(g).

To form HCl(g) from its elements in their standard states, we need to combine hydrogen gas (H₂) and chlorine gas (Cl₂). The balanced chemical equation for this reaction is:

2H₂(g) + Cl₂(g) → 2HCl(g)

1. Start with the reactants: hydrogen gas (H₂) and chlorine gas (Cl₂).

2. Since hydrogen is a diatomic molecule, we write 2H₂ to represent two molecules of H₂.

3. Balance the equation by adding coefficients: 2H₂ + Cl₂ → 2HCl. This ensures the same number of atoms on both sides of the equation.

4. The products are two molecules of hydrogen chloride gas (HCl(g)).

5. Finally, we indicate the physical state of each substance: 2H₂(g) + Cl₂(g) → 2HCl(g), where (g) represents gas phase.

6. The equation shows that two molecules of hydrogen gas react with one molecule of chlorine gas to produce two molecules of hydrogen chloride gas.

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Atmospheric pressure on the peak of Mt, Everest can be as low as 150.0 mmHg, which is why climbers need to bring oxygen tanks for the last part of the climb. If the climbers carry 10.00 L tanks with an internal gas pressure of 3.400 x 10⁴ mmHg, what will be the volume of the gas be when it is released from the tanks?

Answers

Answer:

The volume of the gas when it is released from the tanks will be equal to 10.00 L x (150.0 mmHg / 3.400 x 10⁴ mmHg) = 0.004412 L.

Explanation:

Which of the following salts form a basic aqueous solution at298 K? [Select all that apply]
NaF
FeCl3
CaCl2
LiOH
MgS
KClO3
NH4Cl
NaNO3
Al(NO3)3

Answers

The salts that form a basic aqueous solution at 298 K are NaF, LiOH, and MgS. The pH of a solution can be classified as acidic, basic, or neutral.

In chemistry, the ion Na+ would stand for a solution of table salt, also known as sodium chloride (NaCl), in water (aq). The prefix aqua gives rise to the adjective aqueous, which may be defined as relating to, being like, or being dissolved in water.
In chemistry, water is considered to be a ubiquitous solvent since it is both a good solvent and one that is naturally plentiful.

Acids have a pH of less than 7, bases have a pH greater than 7, and a pH of 7 is considered neutral.

Therefore, aqueous solutions with a pH less than 7 are acidic, while those with a pH greater than 7 are basic.

An acidic aqueous solution has an excess of hydrogen ions (H+), while a basic aqueous solution has an excess of hydroxide ions (OH).

At 298 K, the salts that form a basic aqueous solution are NaF, LiOH, and MgS.

The reaction of NaF is: F(aq) + H2O(l)  HF(aq) + OH(aq). LiOH reacts to produce:

LiOH(s) → Li⁺(aq) + OH⁻(aq)

MgS reacts to produce:

MgS(s) + H₂O(l) → Mg(OH)₂(aq) + H₂S(aq)

Therefore, the correct answer is:NaF, LiOH and MgS

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Please answer all questions on sheet

Please answer all questions on sheet

Answers

Answer:

Yes you always only see one side of the moon

The moon flag always points towards earth

It take 1 month for the moon to orbit the earth

It takes 29.5 days for the flag to rotate once in a full circle

1. You can compare osmolarities of two solutions. Solution A=1Osm Glucose Solution B=2.5Osm Glucose Solution C=1OsmNaCl Answers: i) A is to B (hyperosmotic, isosmotic, hypoosmotic) ii) B is to A (hyperosmotic, isosmotic, hypoosmotic) iii) A is to C (hyperosmotic, isosmotic, hypoosmotic) iv) C is to A (hyperosmotic, isosmotic, hypoosmotic) 2. Body fluid osmolarity is 300mOsm. How will the following values change when you drink water? Would they increase, decrease, or not change?

Answers

i) A is to B: hypoosmotic (Solution A has a lower osmolarity compared to Solution B). ii) B is to A: hyperosmotic (Solution B has a higher osmolarity compared to Solution A)

iii) A is to C: isosmotic (Solution A and Solution C have the same osmolarity)

iv) C is to A: isosmotic (Solution C and Solution A have the same osmolarity)

When you drink water, the osmolarity of body fluids will decrease. This is because water is a hypotonic solution compared to body fluids.

Hypotonic refers to a solution that has a lower solute concentration compared to another solution or a reference solution. In a hypotonic solution, there is a higher concentration of water molecules relative to solute particles.

By drinking water, you are diluting the solute concentration in the body, leading to a decrease in osmolarity. Therefore, the values related to osmolarity, such as the concentration of solutes in the body fluids, would decrease.

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5. A stream consisting of two organic chemicals: (1) benzene
(C6H6) and (2) toluene (C7Hg), enters a separation column. The
total mass flow rate of the stream is 10,000 lbm/hr. The mass
percent of benzene in the stream is 40%. Determine the follow-
ing for the stream:
a. The mass flow rate of benzene
REb. The mass flow rate of toluene
c. The molar flow rate of toluene
d. The total molar flow rate of the stream
e. The mole fraction of benzene

Answers

10,000 lbm/hr is the mass flow rate of the stream as a whole. Benzene (C6H6) and toluene are two organic substances that enter a separation column (C7H8).

The correct option is d.

What exactly does benzene mean?

In order to make polystyrene, benzene, a colorless liquid with a distinct odor, is primarily used. It is incredibly toxic, a known carcinogen, and leukemia has been related to exposure to it.

Benzene is a typical chemical used in industry.

Exactly what is gasoline?

internal combustion engines are fuelled by a derived mixture of highly combustible liquid hydrocarbons. The vast bulk of gasoline is used in automobile engines. infrastructure for blending as well as refining petroleum products.

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Select the correct answer.

How does substituting a hydrogen atom with a halogen in a hydrocarbon affect the resulting compound?

A.
All the single bonds in the original molecule change to double bonds.
B.
The boiling point of the new compound increases.
C.
The bonds between the carbon atoms in the molecule become weaker.
D.
The resulting compound is called a saturated hydrocarbon.
E.
The substitution allows each carbon atom to accept more than four valence electrons.

Answers

Answer:

E. The substitution allows each carbon atom to accept more than four valence electrons.

Explanation:

Halogens (except for fluorine) have seven valence electrons, which gives them the flexibility to participate in more than four covalent bonds. Hydrogen only has one valence electron, so it tends to form only four covalent bonds. In a substitution reaction, each halogen provides the carbon atom with additional electrons, allowing it to accept more than the usual four.

Answer:

C. The bonds between the carbon atoms in the molecule become weaker.

Explanation:

Explain why pentane has a higher boiling point than butane

Answers

Answer: Larger molecules have stronger London forces.

Explanation:

Pentane therefore has a stronger force than butane.

Why is the Earth's hydrosphere (oceans) made up of mostly hydrogen
and oxygen? *

Answers

Answer:

Because ocean water contains salt, there is also sodium and chlorine in the oceans.

Explanation:

FILL IN THE BLANKS:
_____ARE THE
STARTING SUBSTANCES
OF A CHEMICAL
REACTION, WHILE
________ARE THE
SUBSTANCES PRODUCED
FROM A REACTION.

Answers

Reactants are the starting substances of a chemical reaction, while products are the substances produced from a reaction.

What are Reactant?

In a chemical reaction, the starting substances are called reactants, and the substances produced from the reaction are called products. Reactants are the substances that are transformed or changed during the reaction, while products are the substances that are formed as a result of the chemical reaction.

For example, in the chemical reaction where hydrogen gas reacts with oxygen gas to form water, the reactants are hydrogen and oxygen, and the product is water.

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what is mass of nitrogen

Answers

Nitrogen has an atomic mass of approximately 14.0067 atomic mass units (u) and a molar mass of approximately 14.0067 grams per mole (g/mol).

Understanding the Mass of Nitrogen

Nitrogen is a chemical element with the symbol N and atomic number 7. It is a colorless, odorless, and tasteless gas that makes up about 78% of the Earth's atmosphere. The mass of nitrogen depends on the quantity of nitrogen being measured. The atomic mass of nitrogen is approximately 14.0067 atomic mass units (u), which is the average mass of one nitrogen atom. The molar mass of nitrogen, which is the mass of one mole of nitrogen atoms, is approximately 14.0067 grams per mole (g/mol). One mole of nitrogen contains

Avogadro's number of nitrogen atoms, which is approximately 6.022 x 10^23. If you have a specific quantity of nitrogen, you can calculate its mass by multiplying the quantity by the molar mass of nitrogen. For example, if you have 2 moles of nitrogen, the mass of nitrogen would be 2 x 14.0067 g/mol, which is approximately 28.0134 grams. Understanding the mass of nitrogen is important in various scientific fields, including chemistry, physics, and biology, as well as in industrial applications such as fertilizer production and food packaging.

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When there are 0.0814 moles of hockey pucks how many hockey pucks are there?

Answers

Answer:

4.9 x 10²²hockey pucks

Explanation:

Given parameters:

Number of moles of hockey  = 0.0814moles

Unknown:

Number of pucks there = ?

Solution:

A mole of a substance is made up of Avogadro's number of particles.

Therefore;

       1 mole of hockey pucks will contain 6.02 x 10²³ hockey pucks

       0.0814 mole of hockey pucks will contain :

                              0.0814 x 6.02 x 10²³ = 4.9 x 10²²hockey pucks

What is the wavelength of electromagnetic radiation which has a frequency of 4.464 x 10^14 s-1

a. 1.338 x 10^23 m
b. 1.489 x 10^-6 m
c. 6.716 x 10^-7 nm
d. 671.6 nm

Answers

Answer:

d. 671.6 nm

Explanation:

It is possible to solve the wavelength of a radiation from its frequency -or vice versa- using:

λ = c / f

Where λ is wavelength,

c is speed of light, a constant (2.998x10⁸m/s)

And f is frequency: 4.464x10¹⁴s⁻¹

Replacing:

λ = 2.998x10⁸m/s / 4.464x10¹⁴s⁻¹

λ = 6.716x10⁻⁷m

As 1m = 1x10⁹nm:

6.716x10⁻⁷m * (1x10⁹nm / 1m) = 671.6nm

Right answer is:

d. 671.6 nm

A particle of mass 0.350 kg is attached to the 100-cm mark of a meterstick of mass 0.150 kg. The meterstick rotates on the surface of a frictionless, horizontal table with an angular speed of 2.00 rad/s.

Answers

To determine the rotational kinetic energy of the system, we need to consider the contributions from both the particle and the meterstick. Therefore, the total rotational kinetic energy of the system is 0.450 J.

The rotational kinetic energy of the particle is given by the formula: K_particle = (1/2) * I_particle * ω², where I_particle is the moment of inertia of the particle and ω is the angular speed.

The moment of inertia of a point particle is given by I_particle = m_particle * r², where m_particle is the mass of the particle and r is the distance from the rotation axis.

Given that the mass of the particle is 0.350 kg and it is located at the 100-cm mark, which is 1 meter from the rotation axis, we can calculate the moment of inertia of the particle as I_particle = 0.350 kg * (1 m)² = 0.350 kg·m².

Substituting the values into the formula, we have: K_particle = (1/2) * 0.350 kg·m² * (2.00 rad/s)² = 0.350 J.

The rotational kinetic energy of the meterstick can be calculated in a similar way. The moment of inertia of the meterstick can be approximated as I_meterstick = (1/3) * m_meterstick * L², where m_meterstick is the mass of the meterstick and L is its length.

Given that the mass of the meterstick is 0.150 kg and its length is 1 meter, we can calculate the moment of inertia of the meterstick as I_meterstick = (1/3) * 0.150 kg * (1 m)² = 0.050 kg·m².

Substituting the values into the formula, we have: K_meterstick = (1/2) * 0.050 kg·m² * (2.00 rad/s)² = 0.100 J.

Therefore, the total rotational kinetic energy of the system is K_total = K_particle + K_meterstick = 0.350 J + 0.100 J = 0.450 J.

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Identify what type of reaction is this
2AgCl + H2 → 2Ag + 2HCI

Answers

Answer:

single displacement

Explanation:

What is the half-life of a compound if 42% of a given sample of the compound decomposes in 60 min? Assume first-order kinetics

Answers

The half-life of a compound if 42% of a given sample of the compound decomposes in 60 min is 45.1 min (rounded to one decimal place).

In a first-order reaction, the rate of decomposition is directly proportional to the concentration of the reactant.

That is, the reaction rate (R) is proportional to the concentration (C) raised to the power of :

1.Rate of reaction = - dC/dt = kC

Where k is the rate constant and t is the time taken.

Therefore, the integrated form of the equation for first-order kinetics is:

ln [C]t - ln [C]0 = - kt

Where [C]t and [C]0 are the concentrations at time t and at time zero respectively, k is the rate constant, and t is the time taken for the reaction to proceed.

The half-life of a reaction is the time taken for half of the reactant to be consumed,

i.e., when [C]t = [C]0 / 2.

Substituting these values into the integrated equation, we have:

ln ([C]0 / 2) - ln [C]0 = - kt12 ln 1/2 = - kt1/2 = (ln 2) / k

Now we can use the half-life equation to find k: 60 min

= t1/2

= (ln 2) / kk

= 0.0116 min-1

Now that we know the rate constant, we can use the integrated equation to find the half-life of the reaction for 42% decomposition.

Using 0.42[C]0 and solving for t, we get:

t = 45.1 min

Therefore, the half-life of the reaction for 42% decomposition is 45.1 min.

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In part A you will prepare a dilution solution of 0.1M NaOH using a 500mL graduated cylinder and pump dispenser. The solution is then mixed and stored in the amber bottle found in your drawer. Be sure the cap is in good condition. Calculate the volume of 6.0M NaOH needed to make 450 mL of about 2.4 M NaOH. Do not include units in answer.

Answers

The volume of 6.0M NaOH needed to make 450 mL of about 2.4 M NaOH if a dilution solution of 0.1M NaOH using a 500mL graduated cylinder and pump dispenser is 180 ml.

To calculate the volume of 6.0M NaOH needed to make 450 mL of about 2.4 M NaOH, we know that:

The initial concentration of NaOH (C₁) = 6.0 MThe final concentration of NaOH (C₂) = 2.4 MThe final volume of the solution (V₂) = 450 mL

We are required to find the volume of NaOH required to make the given solution.

To solve this, we will use the dilution formula;

C₁V₁ = C₂V₂

Where; C₁ is the initial concentration of the solution, V₁ is the initial volume of the solution, C₂ is the final concentration of the solution and V₂ is the final volume of the solution.

Substituting the given values,

6.0 M × V₁ = 2.4 M × 450 mL

V₁ = (2.4 M × 450 mL)/6.0 M

= 180 mL

Therefore, the volume of 6.0 M NaOH required to make 450 mL of 2.4 M NaOH is 180 mL.

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What is the mass of 5.119 102 molecules of copper sulfate
(CuSO4)?

Answers

Answer:

Mass = 135.66 ×10⁻²¹ g

Explanation:

Given data:

Number of molecules of CuSO₄= 5.119×10²

Mass of CuSO₄= ?

Solution:

The given problem will solve by using Avogadro number.

1 mole contain 6.022×10²³ molecules

5.119×10² molecules ×1 mol / 6.022×10²³ molecules

0.85×10⁻²¹ mol

Mass in grams:

Mass = number of moles × molar mass

Mass = 0.85×10⁻²¹ mol × 159.6 g/mol

Mass = 135.66 ×10⁻²¹ g

8250 J of heat is applied to a piece of aluminum, causing a 40. 0 °C increase in its temperature. The specific heat of aluminum is 0. 9025 J/g ·°C. What is the mass of the aluminum?

Answers

We can use the formula for calculating heat:

Q = m × c × ΔT

where Q is the amount of heat transferred, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.

Plugging in the given values, we get:

8250 J = m × 0.9025 J/g ·°C × 40.0 °C

Simplifying, we get:

8250 J = m × 36.1 J/g

Solving for m, we get:

m = 8250 J ÷ 36.1 J/g

m ≈ 228.26 g

Therefore, the mass of the aluminum is approximately 228.26 g.

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Molybdenum can form a wide series of halide compounds, including four different fluoride compounds. The percent by mass of molybdenum in the four compounds is 63. 0%, 56. 0%, 50. 0%, and 46. 0%. Determine the formula and name for each of the four different molybdenum fluorides.

Answers

1. Formula of compound => MoF₃
Name of compound => Molybdenum trifluoride
2. Formula of compound => MoF₄
Name of compound => Molybdenum tetrafluoride
3. Formula of compound => MoF₅
Name of compound => Molybdenum pentafluoride
4. Formula of compound => MoF₆
Name of compound => Molybdenum hexafluoride
1. Determination of the name and formula of the molybdenum fluoride having 63.0% of molybdenum.
Molybdenum (Mo) = 63.0%
Fluorine (F) = 100 – 63 = 37%
Formula =?
Mo = 63.0%
F = 37%
Divide by their molar mass
Mo = 63.0 / 96 = 0.656
F = 37 / 19 = 1.947
Divide by the smallest
Mo = 0.656 / 0.656 = 1
F = 1.947 / 0.656 = 3
Therefore,
Formula of compound => MoF₃
Name of compound => Molybdenum trifluoride
2. Determination of the name and formula of the molybdenum fluoride having 56.0% of molybdenum.
Molybdenum (Mo) = 56.0%,
Fluorine (F) = 100 – 56 = 44%
Formula =?
Mo = 56%
F = 44%
Divide by their molar mass
Mo = 56 / 96 = 0.583
F = 44 / 19 = 2.316
Divide by the smallest
Mo = 0.583 / 0.583 = 1
F = 2.316 / 0.583 = 4
Therefore,
Formula of compound => MoF₄
Name of compound => Molybdenum tetrafluoride
3. Determination of the name and formula of the molybdenum fluoride having 50.0% of molybdenum.
Molybdenum (Mo) = 50.0%,
Fluorine (F) = 100 – 50 = 50%
Formula =?
Mo = 50%
F = 50%
Divide by their molar mass
Mo = 50 / 96 = 0.520
F = 50 / 19 = 2.632
Divide by the smallest
Mo = 0.520 / 0.520 = 1
F = 2.632 / 0.520 = 5
Therefore,
Formula of compound => MoF₅
Name of compound => Molybdenum pentafluoride
4. Determination of the name and formula of the molybdenum fluoride having 46.0% of molybdenum.
Molybdenum (Mo) = 46.0%,
Fluorine (F) = 100 – 46 = 54%
Formula =?
Mo = 46%
F = 54%
Divide by their molar mass
Mo = 46 / 96 = 0.479
F = 54 / 19 = 2.842
Divide by the smallest
Mo = 0.479 / 0.479 = 1
F = 2.842 / 0.479 = 6
Therefore,
Formula of compound => MoF₆
Name of compound => Molybdenum hexafluoride

Arachidonic acid, which is found in meat, eggs, and some fish, is a polyunsaturated fat with 20 carbons and 4 double bonds, so it is described in shorthand notation as (20:4). Write its molecular formula.

Answers

Arachidonic acid is a polyunsaturated fat that has 20 carbons and 4 double bonds, and its shorthand notation is (20:4). In this notation, the first number (20) indicates the number of carbons, and the second number (4) represents the number of double bonds.

Therefore, to write the molecular formula of arachidonic acid, we need to know the chemical formula of a fatty acid with 20 carbons and 4 double bonds. To do that, we start with a fatty acid with 20 carbons, which is an unbranched chain with the formula C19H39COOH. Then, we need to introduce the double bonds into the chain, starting at the methyl (CH3) end of the chain.

The shorthand (20:4) indicates that there are four double bonds, so we need to replace four of the carbon-hydrogen (C-H) bonds with carbon-carbon double bonds (C=C). The double bonds are introduced at the following positions: the fifth, eighth, eleventh, and fourteenth carbon atoms. The resulting molecular formula for arachidonic acid is:C19H31COOHC=C-C=C-C=C-COOH. Therefore, the molecular formula of arachidonic acid is C20H32O2.

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Question 11
Which formula represents a hydrocarbon?


C₂H6
C₂H5OH
C₂H5Cl
C₂H6O

Answers

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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3. Use Eq. 7-8 to estimate the fractional saturation of hemoglobin when po, is (a) 20 torr, (b) 40 torr, and (c) 60 torr. YO2 = (pO2)^n / (p50)^n + (pO2)^n [7-8]

Answers

The fractional saturation of hemoglobin when po, is (a) 20 torr is 0.279, 40 torr is 0.545 and 60 torr is 0.747.

Y02 = (p02)n / (p50)n + (p02)n

From the given equation, we can estimate the fractional saturation of hemoglobin when PO2 is 20, 40 and 60 torr.

Y02 = (20)n / (p50)n + (20)n

= 0.279

Y02 = (40)n / (p50)n + (40)n

= 0.545

Y02 = (60)n / (p50)n + (60)n

= 0.747

The fractional saturation of hemoglobin for a PO2 of 20 torr is 0.279,

for a PO2 of 40 torr is 0.545,

and for a PO2 of 60 torr is 0.747.

In conclusion, we can say that the fractional saturation of hemoglobin is an important parameter for determining the oxygen-carrying capacity of blood. The above equation helps us to estimate the fractional saturation of hemoglobin when PO2 is given.

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