which type of electromagnetic radiation is most likely to cause skin cancer as a result of sun exposure over time?​

Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.

What  is linearly decreasing force?

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The hiker made it to a safe landing on the other side of the gap after travelling horizontally at 2.49 m.

The time taken for the hiker to fall from the given height is calculated as follows;

h = vt + ¹/₂gt²

where;

h = ¹/₂gt²

t = √(2h/g)

t = √[(2 x 0.6) / (9.8)]

t = 0.35 seconds

The horizontal velocity of the hiker during the period of acceleration is calculated as follows;

Vₓ = at

Vₓ = (5.92 m/s²) x (1.2 s)

Vₓ = 7.104 m/s

The horizontal distance travelled during the time period of 0.35 seconds;

X = Vₓt

X = 7.104 x 0.35

X = 2.49 m

Thus, the hiker made it to a safe landing on the other side of the gap which is 2.3 m wide and smaller to his horizontal displacement of 2.49 m.

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Answer:

85.77 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 41 m/s

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 41² – (2 × 9.8 × h)

0 = 1681 – 19.6h

Collect like terms

0 – 1681 = –19.6h

–1681 = –19.6h

Divide both side by –19.6

h = –1681 / –19.6

h = 85.77 m

Thus, the maximum height reached by the ball is 85.77 m

Explanation:

Sooooo, first,

Constant Speed means that the body isn't accelerating.

a= 0

Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.

The force that pulls the body downwards is given by,

F = mgsin40°

F= 18.898N

P -(F+Fr) = ma, but, a= 0

P = F + Fr

Fr = 26-18.898

= 7.102N

If the block must move down the incline, Q and Fr will act in the same direction.

Q + Fr = F

Q = 11.796N

The diagram best represents the steps in the formation of the sun is the clouds of gases condense > The clouds rotate at high speed > The clouds flatten into an elliptical disc > The planets are born. The correct option is D.

Planets are the large spherical shaped objects that rotate about the Sun in the elliptical orbits.

Planets are shaped from Planetary cloud. The dust storm and gases gathers under its own weight. The dense matter beginnings pivoting at high paces and accumulates more mass. The center structures, the star and rest of it ultimately levels into a curved plate from which planet is formed.

Thus, the correct sequence is D.

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Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

Answer:

gh

Explanation:

the initial momentum of the system of block m1 and block m2 is

Pi= m1v1 + m2v2

the final momentum of the combine blocks is

Pf= (m1+m2)V

according to the law of convervation of momentum

Pi = Pf

m1v1 + m2v2 = (m1+m2)V

1.3 × 1 + 5m2 = 1.3 × 2 + 2m2

m2= 1.3/3 kg

The magnitude of the velocity of S with respect to S' is 0.866 times the speed of light, and it is in the negative x-direction (i.e., opposite to the direction of motion of S').

Explanation:

The problem can be solved using the concept of relativity of simultaneity and the Lorentz transformation equations. Let's assume that the inertial system S is moving with a velocity v with respect to S', where the two events are simultaneous.

Let's first find out the time difference between the two events as observed in S. According to S, the two events occur at different times because they are separated by a distance of 900m. Let's call this time difference Δt.

Δt = 900m / c = 3 × 10^−6 S

where c is the speed of light.

Now, let's apply the Lorentz transformation equations to relate the time difference Δt in S to the time difference Δt' in S':

Δt' = γ(Δt - vΔx/c^2)

where Δx is the distance between the two events as measured in S, and γ is the Lorentz factor given by:

γ = 1 / sqrt(1 - v^2/c^2)

Since the two events are simultaneous in S', we have Δt' = 0. Also, Δx = 900m, and Δt = 3 × 10^−6 S.

Solving for v, we get:

v = Δx / (γΔt)

Substituting the values of Δx, Δt, and γ, we get:

v = 0.866c

Answer:

Energy storage plays an important role in this balancing act and helps to create a more flexible and reliable grid system. For example, when there is more supply than demand, such as during the night when low-cost power plants continue to operate, the excess electricity generation can be used to power storage devices.

Explanation:

I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)

It important for scientists to find better ways to store solar and wind energy because solar and wind energy have variable outputs.

Lately, the world have begun to gradually gravitate away from non renewable energy sources such as fossil fuels and research efforts have been concentrated on renewable energy sources such as solar and wind energy.

However, the energy output from these sources are variable. Therefore, it is necessary to device ways to store energy from these sources in order to improve overall energy supply.

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Answer:

29.4 kW

Explanation:

time t = 10 s, height h = 30 m, mass m = 1,000 kg

power output = work done/time

work done = increase in potential energy = mgh = 1,000 * 9.8 * 30 = 294,000 J = 294 kJ

power output = 294/10 = 29.4 kW

Answer:

1. The image is real

2. 5.85

3. h' = 3.05 mm

4. The image is upright

Explanation:

1. Start with the first lens and apply 1/f = 1/p + 1/q

1/5.01 = 1/13.7 + 1/q

q = 7.90 cm

Since that distance is behind the first lens, and the second lens is 62.5 cm behind the first lens, that distance is 62.5 - 7.90 = 54.6 cm in front of the second lens, and becomes the object for that lens, thus,

1/25.9 = 1/54.6 + 1/q

q = 49.3 cm behind the second lens

Using that information, since q is positive, the image is real

2. Also, using that information, you have the second answer, which is 49.3 cm

The height can be found from the two magnifications.

m = -q/p

m1 = -7.9/13.7 = -.577

m2 = -49.3/54.6 = -.903

Net m = (-.577)(-.903) = .521

Then, m = h'/h

.521 = h'/5.85

3. h' = 3.05 mm

4. For the fourth answer, since the overall magnification is positive, the final image is upright

Answer:

The frecuency is 1.2*10¹¹ Hz.

Explanation:

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time, that is, how many peaks or valleys are repeated in a unit of time. Its unit is s – 1 or hertz (Hz).

The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. It relates the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f * λ.

In this case:

Replacing:

300,000,000 m/s= f* 0.0025 m

Solving:

f= 300,000,000 m/s ÷0.0025 m

f= 1.2*10¹¹ \(\frac{1}{s}\) =  1.2*10¹¹ Hz

The frecuency is 1.2*10¹¹ Hz.

Answer:

18600j

Explanation:

It is given that,

Number of moles = 3

Temperature, T = 25°C = 25+273 = 298 K

The internal energy of N₂ gas is given by :

U=f\times nRTU=f×nRT

f is degrees of freedom. For diatomic gas, degree of freedom is equal to 5/2. So,

\begin{gathered}U=\dfrac{5}{2}\times 3\times 8.31\times 298\\\\U=18572.85\ J\end{gathered}

U=

2

5×3×8.31×298

U=18572.85 J

or

U = 18600 J

So, the internal energy of the gas is 18,600 J

The scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable.

Observation is the first step of the scientific method, which then requires to raise a question that will be answered by a testable hypothesis.

The scientific method is a series of well-established steps used to collect scientific empirical data/evidence, which allow to test a given hypothesis.

In conclusion, the scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable..

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Answer:

general steps of performing an autopsy:

1. The body is identified and the relevant information about the deceased is collected.

2. A visual examination of the body is performed to look for any abnormalities or signs of injury.

3. The external examination is followed by an internal examination. The body is opened up to examine the organs, including the brain, heart, lungs, liver, and kidneys, for any signs of disease or injury.

4. The organs are weighed, measured and dissected.

5. Tissue samples are taken and sent for laboratory analysis.

6. The cause of death is determined based on the autopsy findings, and a report is generated.

7. The body is then closed and prepared for release to the family for funeral arrangements.

It is important to note that the specific steps involved may vary depending on the type of autopsy being conducted and the circumstances surrounding the death.

Explanation:

A race car is traveling in a uniform circular motion around a race track, the radial acceleration of the car when the velocity is doubled and the radius of the circle is halved will increase by a factor of 8 (Option D)

To arrive at the above conclusion, we must recall that radial acceleration is defined by:

Ac = v²/r; where

Ac - is the magnitude of radial acceleration

v -  is the linear or tangential speed

r - is the radius of the circular path

A′c -  is the new magnitude of the radial acceleration.

Given that the linear velocity is duplicated and simultaneously the radius is split in two, then the new radial acceleration increases by a factor of 8, according to the following calculation:

A'c = (2v²)/(0.5r)

= 4v²/(0.5r)

= 8 · (v²/r)

= 8 · Ac

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Full Question:

A race car is traveling in a uniform circular motion around a race track what happens to the radial acceleration of the car if the velocity is doubled and the radius of the circle is halfed?

A. It remains the same.

B. It increases by a factor of 2.

C. It increases by a factor of 4.

D. It increases by a factor of 8.

E. It decreases by a factor of 2.

The magnitude of the net force causing the block’s acceleration is 8N.

We know that,

                         \(F_{x} = mg* cos\alpha\) (force along x - axis) and

                         \(F_{y} = mg* sin\alpha\) (force along y - axis)

The magnitude of net force is given by :

                         \(F_{net} = \sqrt{F_{x} ^{2} + F_{y} ^{2} }\)

                         \(F_{net} = \sqrt{(mg*cos\alpha )^{2} + (mg*sin\alpha )^{2} } \\F_{net} = \sqrt{(mg)^{2}[ (cos\alpha) ^{2}+(sin\alpha) ^{2} ] } \\F_{net} = mg\)

Given, weight = 8N and angle \(\alpha =\) 15°

We know that F (force) = ma = mg = weight

Putting these values in above equation we get ,

                          \(F_{net} = 8N\)

So the magnitude of the net force causing the block’s acceleration is 8N.  

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The above has to do with the study of the earth's lithospheric plates. See the attached image and the explanation below.

The movement of lithospheric plates is a geological process that occurs due to the motion of hot, molten material in the Earth's mantle. The lithosphere, which is the rigid outer layer of the Earth's surface, is divided into several large plates that move relative to each other.

These movements are caused by the convection of material in the mantle and the forces that arise at the boundaries between the plates.

There are three main types of plate boundaries: divergent, convergent, and transform. Divergent boundaries occur where plates move apart from each other, creating new oceanic crust. Convergent boundaries arise where plates collide, leading to subduction, volcanic activity, and the formation of mountains. Transform boundaries occur where plates slide past each other.

The movement of lithospheric plates gives rise to various geological phenomena, such as earthquakes, volcanic activity, and the formation of mountain ranges and ocean basins.

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The apparent weight of the 56.1 kg passenger at the top of the bump is 1552 N. The maximum speed that the car can be driven over the top of the bump without losing contact with the road is 25.0 m/s.

To calculate the apparent weight of the passenger, we need to first calculate the centripetal force acting on the car and passenger as they pass over the bump. The centripetal force can be calculated using the formula:

Fc = m\(v^2\) / r

where Fc is the centripetal force, m is the mass of the car and passenger, v is the speed of the car, and r is the radius of curvature of the bump.

Plugging in the values, we get:

Fc = (56.1 kg + m) x (18.3 m/s)^2 / 75.9 m

Next, we need to calculate the weight of the passenger when the car is not accelerating, which is given by:

W = mg

where W is the weight of the passenger, m is the mass of the passenger, and g is the acceleration due to gravity (9.81 m/s^2).

Plugging in the values, we get:

W = 56.1 kg x 9.81 m/s^2 = 550.2 N

Now, the apparent weight of the passenger as the car passes over the bump can be calculated as:

Apparent weight = W + Fc

Plugging in the values, we get: Apparent weight = 550.2 N + [(56.1 kg + m) x (18.3 \(m/s)^2\) / 75.9 m]

B) To calculate the maximum speed that the car can be driven over the bump without losing contact with the road, we need to calculate the minimum centripetal force required to keep the car on the road. This is given by the formula:

Fc(min) = mg + Ff

where Fc(min) is the minimum centripetal force required, m is the mass of the car and passenger, g is the acceleration due to gravity, and Ff is the force of friction acting on the car and passenger.

We can assume that the force of friction is equal to the coefficient of static friction (μ) times the normal force (N), which is equal to the weight of the car and passenger (m + 56.1 kg) times the acceleration due to gravity (9.81 m/s^2):

Ff = μN = μ(m + 56.1 kg)g

Now we can plug in the values and solve for the minimum centripetal force:

Fc(min) = mg + μ(m + 56.1 kg)g

The minimum centripetal force must be equal to the centripetal force acting on the car and passenger as they pass over the bump at the maximum speed. So we can set Fc = Fc(min) and solve for v:

Fc = \(mv^2\) / r = mg + μ(m + 56.1 kg)g

\(v^2\)= r(g + μ(g + \(v^2\)/r))

\(v^2\) = rg + μrg + μv^2

\((1 - μ)v^2\) = rg + μrg

\(v^2\)= (rg + μrg) / (1 - μ)

Now we can plug in the values and solve for v:

\(v^2\) = (75.9 m x 9.81 m/s^2 + 0.75 x 75.9 m x 9.81 m/\(s^2\)) / (1 - 0.75)

\(v^2\) = 623.90

v = 25.0 m/s (rounded to one decimal place)

Therefore, the maximum speed that the car can be driven over the top of the bump without losing contact with the road is 25.0 m/s.

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Answer:

Efficiency of the system = 100%

Explanation:

Given:

Input energy = 100 J

Potential energy load = 60 J

Find:

Efficiency of the system

Computation:

Efficiency of the system = [Potential energy load/Input energy]100

Efficiency of the system = [60/100]100

Efficiency of the system = 100%

Answer:

force needed for the bus to go round the corner is 50,000 N.

Explanation:

To find the force needed for the bus to go round the corner, we can use the formula for centripetal force:

F = (mv^2)/r

where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular path.

Plugging in the values given in the problem, we get:

F = (2500 kg)(5 m/s)^2 / 50 m

= 50,000 N

So the force needed for the bus to go round the corner is 50,000 N.

Answer:

visualizing

Explanation:

You are imagining yourself doing it, using the image in your head and the steps you read to figure out what to do first, next, last.

The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.

The work-energy theorem states that "the work done on an object is the change in its kinetic energy".

Hence;

Kinetic energy = work done

Note that: work-done is expressed as:

Work done = f × d

Where f is force applied and d is distance traveled.

Given that:

Force applied f = 5 newton

Distance d = 2 meters

Work done = ?

Plug these values into the above formula and solve for the workdone.

Work done = f × d

Work done = 5N × 2m

Work done = 10Nm

Work done = 10 Joules

Therefore, the kinetic energy is 10 Joules.

Option B) 10 J is the correct answer.

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The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:

U = k × (Q₁ × Q₂) / r

where:

U = potential energy in joules

k = Coulomb's constant (8.988 x 10⁹ N m²/C²)

Q₁ and Q₂ = charges in coulombs

r = distance between the charges in meters

In this case:

U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J

The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:

KE = 1/2 × m × v²

where:

KE = kinetic energy in joules

m = mass in kilograms

v = velocity in meters per second

Solve for the velocity of particle B using the conservation of energy equation:

KE = U

Substituting the expressions for KE and U gives:

1/2 × m × v² = 5.375 x 10⁻⁷ J

Solving for v gives:

v = √(2 × 5.375 x 10⁻⁷ J / m)

= 1.53 m/s

The kinetic energy of particle B is then:

KE = 1/2 × m × v²

= 1/2 × m × (1.53 m/s)²

= 4.32 J

Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

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Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions