Which test tube has the largest amount of precipitate? record the ratio of cuso4 to na2s used. what is the indicated by the maximum amount of particiapation

Answers

Answer 1

The third test tube has the largest amount of precipitate. The correct ratio for this reaction is 1:1.

What do you mean by test tube?

Test tubes intended for the general chemical work are usually made of glass, and for its relative resistance to heat. Tubes made from the expansion-resistant glasses, mostly borosilicate glass or fused quartz, can withstand high temperatures up to several hundred degrees Celsius.

Chemistry tubes are available in a multitude of the lengths and widths, typically from 10 to 20 mm wide and 50 to 200 mm long. The top often features a flared lip to aid pouring out contents.

A chemistry test tube typically has flat bottom, a round bottom, or a conical bottom. Some test tubes are made to accept a ground glass stopper or  screw cap. They are often provided with small ground glass or white glaze area near the top for labelling with a pencil.

Test tubes are widely used by the chemists to handle chemicals, especially for qualitative experiments and assays. Their spherical bottom and vertical sides reduce mass loss when pouring, make them easier to wash out, and allow convenient monitoring of contents. The long, narrow neck of the test tube slows down the spreading of gases to the environment.

Test tubes are convenient containers for heating the small amounts of liquids or solids with a Bunsen burner or alcohol burner. The tube is usually held by its neck with clamp or tongs. By tilting tube, the bottom can be heated to hundreds of degrees in the flame, while the neck remains relatively cool, possibly allowing vapors to condense on its walls. A boiling tube is large test tube intended specifically for boiling liquids.

In reaction:

CuSO4 + Na2S ⇒ CuS + Na2SO4

Third test tube had largest amount of precipitate.

In third test tube all Cu2+ ion converted into CuS precipitate.

Test Tube         Ratio

1                          5:1

2                          2:1

3                           1:1

4                           1:2

5                          1:5

so, the correct ratio is 1:1.

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Related Questions

student plans to isolate chlorophyll, mix it in a solution of carbon dioxide and water, and then shine light on the mixture. Do you predict glucose will be produced inside the mixture

Answers

Answer:

No

Explanation:

In order for glucose to be produced inside the mixture, photosynthesis has to take place. The photosynthetic process requires a series of steps within an organelle called the chloroplast. The chloroplast contains the chlorophyll and other enzymes that are necessary for photosynthesis.

Once the chlorophyll is isolated, it becomes separated from the enzymes necessary for the completion of photosynthesis, and the process is truncated. When light is shined on the mixture, the majority would instead be lost as heat while some cause the chlorophyll molecules to glow.

Explain the role of photosynthesis in the cycling of matter between the plant and the person?

Answers

The process of photosynthesis converts light energy into stored chemical energy by converting carbon dioxide plus water into sugars plus released oxygen.

What is photosynthesis ?

Utilizing a process called photosynthesis, plants and other living things may transform light energy into chemical energy that can then be released through cellular respiration to power their activities. Photosynthesis, from the Greek phs (light) and synthesis (putting together), derives from the fact that some of this chemical energy is stored in carbohydrate molecules, such as sugars and starches, which are created from carbon dioxide and water.

Photoautotrophic organisms, such as the majority of plants, algae, and cyanobacteria, carry out photosynthesis. The majority of the energy required for life on Earth is produced and maintained through photosynthesis, which is also primarily responsible for producing and maintaining the oxygen concentration of the Earth's atmosphere.

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Which of the following is considered a dilute solution? Choose all that apply.
Very sweet tea
Contact lens solution
Tide pods (laundry detergent)
Swimming pool water

Answers

Answer:

Very sweet tea

Explanation:

yeah... because sweet tea can cause tooth decay in our mouth thats why...(Please check the other answers also...Its all my point of view....thank you)

how many different products are formed from the dehydrohalogenation of 2-bromobutane?

Answers

Answer:

3  1-butene, Z-2-butene, and E-2-butene.

Explanation:

Since 2-butene exists as two stereoisomers, three products are possible from the reaction of potassium ethoxide with 2-bromobutane. The products are, of course, 1-butene, Z-2-butene, and E-2-butene.

How many moles of KC1 are in 1250 mL of 0.75 M KC1

Answers

The following formula can be used to determine how many moles of KC1 are present in 1250 mL of 0.75 M KC1: Molarity (M) is equal to the moles of solute per litre of solution.

In this instance, the volume of the solution is 1250 mL, and the molarity of KC1 is 0.75 M. The following formula can be used to determine how many moles of KC1 are present in 1250 mL of 0.75 M KC1: Molarity (M) times the number of litres in the solution equals 0.75 M times (1250 mL/1000 mL/L) or 0.9375 moles of KC1.

Consequently, 0.9375 moles of KC1 are present in 1250 mL of 0.75 M KC1. It is significant to remember that a solution's molarity is a measurement of the amount of a solute present in a given volume of the solution.

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Based on location in the periodic table, which element has chemical properties that are most similar to iodine
xenon (Xe)
calcium (Ca)
Selenium (Se)
fluorine (F)

Answers

Answer:fluorine

Explanation:

Based on location in the periodic table, fluorine (F) has chemical properties that are most similar to iodine.

In the periodic table, elements are classified in groups and periods. The elements in the same group are chemically similar and they have the same number of valence electrons. Elements in the same period have the same highest energy level.

Hence, when looking for an element that is most chemically similar to iodine, we have to consider the element that is in the same group with iodine.

Both fluorine are iodine are both in group 17 hence, fluorine is most chemically similar to iodine.

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Why is it energetically favorable rather than many oil to form one large oil droplet droplets (protein monomers) in an (protein complex) aqueous solution? A. Because there is less ordered water with overall: large ' oil droplets_ lower entropy B. Because large oil droplets have more positive standard change in free than do small water droplets, energy sO more favorable C. Because there is more ordered water with large oil droplets, so higher entropy overall: D. Because there is less ordered water with large oil droplets, higher entropy overall:

Answers

It is favorable rather than the many oil to form the one large oil droplet droplets in an aqueous solution , the correct option is A) because there is less ordered water with large oil droplets, so higher entropy overall.

The entropy is the measure of the randomness or the disorder in the solution. The entropy increases the randomness increases and when the entropy decreases the arrangement will be the more ordered.

Thus, Because of the less ordered water with large oil droplets, so higher entropy overall in the energetically favorable rather than the many oil to form the one large oil droplet droplets that is protein monomers in that is protein complex in an aqueous solution.

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What do we mean by c8 columns? None of the above The column contains eight carbons by lonic bonded The column contains eight carbons by covalent bond The column contains phenyl group by covalent bond

Answers

C8 columns refer to chromatography columns that contain a stationary phase consisting of hydrocarbon chains with eight carbon atoms. c8 columns means none of the given options. The correct answer is (d) None of the above.

C8 columns refer to chromatography columns that contain a stationary phase consisting of hydrocarbon chains with eight carbon atoms. These carbon chains are typically covalently bonded to a solid support material.

The C8 designation represents the length and composition of the hydrocarbon chains in the stationary phase.

These columns are commonly used in chromatography techniques, such as reversed-phase liquid chromatography, where nonpolar compounds are separated based on their interactions with the hydrophobic stationary phase.

The C8 stationary phase provides moderate retention for analytes with different polarities, allowing for effective separation.

The statement about ionic bonding or the presence of a phenyl group is not applicable to C8 columns.

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here are three isotopes of silicon: si-28, si-29, and si-30, with relative abundances of 92.23%, 4.67%, and 3.1%, respectively. determine the atomic mass of silicon.

Answers

The atomic mass of silicon is calculated to be 28.1087 amu if the three isotopes have relative abundances of 92.23%, 4.67%, and 3.1%, respectively.

The atomic mass of an element can be determined by first changing the percentage abundance of each isotope into decimal form, then multiplying this value by the atomic mass of that isotope. Then the resultant value of each isotope is added together to get the atomic mass of the element.

As the mass of the three isotopes of silicon is 28 amu, 29 amu, and 30 amu  with relative abundances of 92.23%, 4.67%, and 3.1%, respectively, we can calculate the atomic mass of silicon as follows;

si-28 = 92.23% = 92.23/100 = 0.9223

si-29 = 4.67% = 4.67/100 = 0.0467

si-30 = 3.1% = 3.1/100 = 0.031

Now multiplying these values by the atomic mass;

si-28 = 0.9223 × 28 = 25.8244

si-29 = 0.0467 × 29 = 1.3543

si-30 = 0.031 × 30 = 0.93

Now adding these values together;

atomic mass of silicon = 25.8244 + 1.3543 + 0.93

atomic mass of silicon = 28.1087 amu

Therefore; the atomic mass of silicon is calculated to be 28.1087 amu.

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Examine the chemical reaction.
C3H8+—>4H2O+3CO2
What coefficient of Oz should be added so the number
of atoms of oxygen is conserved on both sides of the
reaction equation?
i don’t know if this is chemistry

Answers

Answer:

5

Explanation:

how much water will you need to add to your working solution to get to a 100 ml total volume of a 0.03m nacl solution?

Answers

Answer:

The solution is made by adding 4.38 g NaCl to a 250-mL volumetric flask. About 100 mL of water are added and when all the NaCl dissolves water is added up ...

Using the molality of the salt from the last question. Calculate how much the freezing point of water will be lowered. The freezing-point despression constant for water is Kf=-1.86 degrees C/m. Remember the salt contributes twice as many per volume because salt breaks into Ana+ and Cl-.

Using the molality of the salt from the last question. Calculate how much the freezing point of water

Answers

Therefore, the freezing point of water will be lowered by 5.58 °C when 1.5 mol/kg of this salt is added to the water.

What is freezing point?

Freezing point is the temperature at which a liquid substance turns into a solid state at a given pressure. It is the temperature at which the solid and liquid states of the substance are in equilibrium. The freezing point is a physical property of a substance that depends on its chemical composition and pressure. The freezing point of pure water, for example, is 0 degrees Celsius (32 degrees Fahrenheit) at standard atmospheric pressure. However, the freezing point of a substance can be lowered or raised by adding solutes to the liquid or by increasing the pressure on the liquid.

Here,

Assuming the molality of the salt is 1.5 mol/kg, the freezing point depression can be calculated using the formula:

ΔTf = Kf x molality x i

where ΔTf is the freezing point depression, Kf is the freezing-point depression constant, molality is the molality of the solution, and i is the vent Hoff factor that takes into account the dissociation of the salt into ions. Since the salt breaks into two ions (Na+ and Cl-), i = 2.

Substituting the given values, we get:

ΔTf = -1.86 °C/m x 1.5 mol/kg x 2

ΔTf = -5.58 °C

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4. Which of the following are not able to
travel through empty space?
A. gamma rays
C. sound waves
B. ultraviolet waves
D. light waves

4. Which of the following are not able totravel through empty space?A. gamma raysC. sound wavesB. ultraviolet

Answers

Answer:

C.Sound waves.

Hope it helps you.
Answer: C. Sound Waves

Explanation: Sound waves need a medium to travel through because they are vibrations so they need to travel through a solid, liquid, or gas. While electromagnetic/light waves can travel through empty space, gamma rays and ultraviolet waves are Electromagnetic waves.

How many atoms are in 11.5 g of Hg?
A. 5.73 x 10^-2 atoms
B.3.45 atoms
C.3.45 x 10^22 atoms
D. 5.73 atoms

Answers

C 3.45 x 10^22 atoms
Is C. 345 x 10^22 atoms

find values of the intrinsic carrier concentration n. for silicon at -55°c, 0°c, 20°c, 75°c, and 125°c. at each temperature, what fraction of the atoms is ionized? recall that a s

Answers

The intrinsic carrier concentration and the fraction of ionized atoms of silicon at -55℃, 0℃, 20℃, 75℃, 125℃ is calculated below.

The intrinsic carrier concentration in intrinsic material is the number of electrons found in the conduction band or holes in the valence band. This quantity of carriers is determined by the material's band gap as well as its temperature.

Because the number of holes equals the number of electrons, the concentration of each is equal to some amount, ni, and this quantity is known as the intrinsic carrier concentration, and the pure semiconductor material is referred to as intrinsic material.

Given:

B = 5.4 x \(10^{31}\)

\(E_G\) = 1.12 ev for silicon

K = 8.62 x \(10^{-5}\)

Silicon crystal = 5 x \(10^{22}\) atoms/\(cm^3\)

To find:

Intrinsic carrier concentration, ni = ?

Fraction of ionized atom = ?

Formula:

\(ni^2 = BT^3 e^{\frac{-E_G}{KT}\)

Fraction of ionized atom = ni / 5 x \(10^{22}\)

Calculations:

(a) For -55℃:

T = -55 + 273 = 218K

ni = \(5.4 * 10^{31} * 218^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 218})}\)

ni = 2.7018 x \(10^6\) carriers/\(cm^3\)

Fraction of ionized atom = 2.7018 x \(10^6\) / 5 x \(10^{22}\)

Fraction of ionized atom = 5.403 x \(10^{-17}\) atoms/\(cm^3\)

(b) For 0℃:

T = 0 + 273 = 273K

ni = \(5.4 * 10^{31} * 273^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 273})}\)

ni = 1.53 x \(10^9\) carriers/\(cm^3\)

Fraction of ionized atom = 1.53 x \(10^9\) / 5 x \(10^{22}\)

Fraction of ionized atom = 3.07 x \(10^{-14}\) atoms/\(cm^3\)

(c) For 20℃:

T = 20 + 273 = 293K

ni = \(5.4 * 10^{31} * 293^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 293})}\)

ni = 8.65 x \(10^9\) carriers/\(cm^3\)

Fraction of ionized atom = 8.65 x \(10^9\) / 5 x \(10^{22}\)

Fraction of ionized atom = 1.73 x \(10^{-13}\) atoms/\(cm^3\)

(d) For 75℃:

T = 75 + 273 = 348K

ni = \(5.4 * 10^{31} * 348^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 348})}\)

ni = 3.724 x \(10^{11}\) carriers/\(cm^3\)

Fraction of ionized atom = 3.724 x \(10^{11}\) / 5 x \(10^{22}\)

Fraction of ionized atom = 7.449 x \(10^{-12}\) atoms/\(cm^3\)

(e) For 125℃:

T = 125 + 273 = 398K

ni = \(5.4 * 10^{31} * 398^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 398})}\)

ni = 4.75 x \(10^{12}\) carriers/\(cm^3\)

Fraction of ionized atom = 4.75 x \(10^{12}\) / 5 x \(10^{22}\)

Fraction of ionized atom = 9.51 x \(10^{-11}\) atoms/\(cm^3\)

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find values of the intrinsic carrier concentration n. for silicon at -55c, 0c, 20c, 75c, and 125c. at

One major goal of wastewater treatment is the decrease of reduced organic carbon and reduced nitrogen compounds from the sewage. Which procedure do all wastewater treatment facilities employ to achieve this

Answers

Wastewater treatment facilities employ a combination of physical, biological, and chemical processes, including primary, secondary, and tertiary treatment stages, to achieve the goal of decreasing reduced organic carbon and reduced nitrogen compounds from sewage. These processes work in tandem to ensure that the treated wastewater meets acceptable quality standards before it is released back into the environment or reused for various purposes.

Wastewater treatment facilities employ a multi-step process to achieve the goal of decreasing reduced organic carbon and reduced nitrogen compounds from sewage. This process typically consists of primary, secondary, and tertiary treatment stages.

The primary treatment stage involves physical processes such as screening and sedimentation to remove large debris, solids, and settleable materials from the wastewater. This step helps in reducing the organic carbon and nitrogen content to some extent.

Following primary treatment, the secondary treatment stage focuses on biological processes to further break down organic matter. This is typically achieved through the use of activated sludge systems or trickling filters. These systems provide an environment conducive to the growth of aerobic bacteria, which consume the organic carbon compounds, converting them into carbon dioxide and water. Additionally, some nitrogen compounds are converted into less harmful forms through nitrification and denitrification processes.

Finally, in the tertiary treatment stage, advanced techniques are employed to remove any remaining organic carbon and nitrogen compounds. This may include processes like chemical precipitation, filtration, and disinfection. Chemical precipitation involves the addition of chemicals to the wastewater to precipitate and remove any remaining organic and nitrogenous substances. Filtration further removes fine particles, while disinfection helps eliminate pathogens and harmful microorganisms.

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I NEED THE ANSWER ASAP IM ON A TIMER

I NEED THE ANSWER ASAP IM ON A TIMER

Answers

That’s tuff, lol stay in school.

The melting of a glacier is an example of the interactions among which of Earth's spheres? geosphere, troposphere, cryosphere atmosphere, geosphere, cryosphere atmosphere, asthenosphere, biosphere hydrosphere, asthenosphere, atmosphere

Answers

Answer:

The melting of a glacier is an example of interaction among;

Hydrosphere, asthenosphere, atmosphere

Explanation:

The melting of a glacier is an example of the interactions among the Earth's cryosphere and hydrosphere

The cryosphere is described as the portions on Earth where water appears in solid (frozen) form such as glaciers, frozen grounds, snow covered land, sea ice, ice sheets, river ice, ice caps, etc.

The hydrosphere is all the forms water on a planet including, ice, liquid water and water vapor, therefore, the cryosphere is a part of the hydrosphere

The geosphere comprises the Earth's interior, including the asthenosphere, which is fluid and hot and therefore spread heat through both conduction and convection to the hydrosphere that raises the ocean temperatures and lead to glacier melting

The green house effect in the atmosphere results in global warming that raises the average temperature of the Earth which in turn raises the temperature of the oceans and the troposphere, resulting in melting of a glacier

Therefore, the melting of a glacier is an example of interaction among the hydrosphere, asthenosphere, and, atmosphere

What is the mass of a liquid having a density of 1.40 g/mL and a volume of 3090 mL? It will have a mass of 4.326 grams.

All answers must have the correct unit! (g/mL) d= mass/volume, d= masa/volumen

Answers

It has a mass of 4.326 grams.
you already answered the question?

how many moles of chloride ions are there in a mixture of 2mol of barium chloride and 1 mol of pottassium chloride

Answers

In a mixture of 2 mol of barium chloride and 1 mol of potassium chloride, 5 moles of chloride ions are present.

Barium chloride

2BaCl₂ →  2 Ba⁺     +   4Cl⁻

2 moles   2 moles     4 moles

2 moles of barium chloride contain 4 moles of chloride ions.

Potassium chloride

KCl →   K⁺      +      Cl⁻

1 mole  1 mole     1 mole

1 mole of Potassium chloride contains 1 mole of chloride ions.

Thus, total mole chloride ions = 4+1

                                                  = 5.

In a mixture of 2 mol of barium chloride and 1 mol of potassium chloride, 5 moles of chloride ions are present.

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55 points plz help
which is not a way to separate the components of a mixture?
A filtering
B distilling
C evaporating
D Stirring

Answers

Answer: A FILTERING

Explanation:

WHEN YOU FILTER YOU SEPARATE (sorry for caps) btw can you check out my recent question plz

pls help me with chemistry
just some questions
pls

pls help me with chemistry just some questions pls

Answers

Answer:

incomplete question need more information

Three different rocks that each weigh 50 grams are put out in the sunlight. After two hours, they are all at the same temperature. Pick the true statement.

Answers

Answer:

All rocks have same thermal conductivity.

Explanation:

Rocks are heated with the sunlight exposure. Different types of rocks have different thermal conductivity. The heat energy of the rocks is measure in Joules. The size and thermal conductivity of the rocks is important property which determines their heating capacity.

3. Predict Based on the cooling curve data above, predict a freezing temperature range for a mixture containing 83% lead and 17% tin.​

3. Predict Based on the cooling curve data above, predict a freezing temperature range for a mixture

Answers

Based on the cooling curve data above freezing temperature range for a mixture containing 83% lead and 17% tin is solid lead - in other words, the lead starts to freeze at 250°C and tin having freeze at 183°C.

In what kind of a state would lead be at 250 degrees?

The temperature will eventually fall to a level where it crosses the line into the following area of the diagram. At that point, the mixture will begin to form some solid lead, meaning that the lead begins to freeze but not the tin. Around 250°C is the temperature at which that occurs.

From the cooling curve, one can infer the typical liquidus and solidus temperatures for each alloy. The tin lead temperature equilibrium Phase Diagram can then be used to determine the corresponding compositions of each alloy using this liquidus temperature.

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How many moles are in 28 grams of O2?

Answers

Answer:

0.88 mol O₂

Explanation:

Step 1: Find molar mass

Oxygen (O) - 16.00 g/mol

O₂ - 32.00 g/mol

Step 2: Use Dimensional Analysis

\(28 \hspace{3} g \hspace{3} O_2(\frac{1 \hspace{3} mol \hspace{3} O_2}{32.00 \hspace{3} g \hspace{3} O_2} )\) = 0.875 mol O₂

Step 3: Simplify

We have 2 sig figs.

0.875 mol O₂ ≈ 0.88 mol O₂

Which state of matter is characterized by molecules that are tightly packed together and hold their shape?

gas

solid

liquid

plasma​

Answers

Solids have tightly packed molecules

Answer: The answer is Solid

Explanation: :)

Pls big test What are openings in the ground that release energy from deep inside the planet? * 1clouds 2volcanoes 3sun 4hurricanes

Answers

Answer:

2. Volcanoes

Explanation:

The interior of some planets (e.g earth) contains some hot flowing fluids called lava which has a very high thermal energy. The lava as a means of escaping the confinement within the planet, burst out by creating an opening through the ground to the surface of the planet to release the energy (lava).

This process in which the energy is released to the surface of the planet is termed volcanic eruptions. Which occurs majorly in some susceptible regions of the earth.

The openings in the ground that release energy from deep inside the planet is thus called volcanoes.

what causes the change in pressure when a basketball is pumped up?
A) the temperature of the gas changes.
B) the volume of the gas changes.
C) the number of molecules changes.
D) the energy of the molecules changes.
the correct answer is C.

Answers

The increase in pressure when a basketball is pumped up is caused by the change in the number of molecules (optionC).

When air is pumped into a basketball, the air molecules are forced into a smaller space, which increases the number of molecules in that space. This increase in the number of molecules leads to an increase in the pressure of the gas within the ball.To better understand why this is the case, we can use the ideal gas law, which describes the behavior of gases under various conditions. The ideal gas law is expressed as PV = nRT, where P is pressure, V is volume, n is the number of molecules, R is the gas constant, and T is temperature.
When air is pumped into a basketball, the volume of the ball remains the same (assuming the ball is rigid and does not expand), and the temperature of the air inside the ball does not change significantly. Therefore, according to the ideal gas law, the only way the pressure can increase is if the number of molecules (n) increases.
This increase in pressure is what makes the ball bouncy and allows it to be used for games and activities. It is important to note that overinflating a basketball can lead to a rupture or bursting of the ball due to the excessive pressure created by the increased number of molecules.

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What happens when Sulphuric acid is added to into Barium Chloride solution?​

Answers

Answer:

please give me brainlist and follow

Explanation:

When dilute sulphuric acid is added to barium chloride solution, barium sulphate is formed as a precipitate and hydrogen chloride is formed in aqueous solution.

Part 2: Gathering More Evidence About Velocity 1. Use the Force and Motion Simulation to determine how to exert a force to cause an object's velocity to change in each of the five ways. 2. Use one of these options to describe the force in the table: • same direction as object's motion • opposite direction as object's motion • any direction Object's velocity change Direction of force 1. Start moving I 2. Speed up 3. Slow down​

Answers

Variation in object velocity force's direction, begin to move in any way, the same speed as the object's motion, opposing the direction of the object's motion, slow down.

A vector number called velocity is used to explain how quickly an object's position changes in relation to time. It details the direction and speed of the object's motion. Velocity is measured in metres per second (m/s), the SI unit. Calculating velocity involves dividing the object's displacement by the time needed to cover that distance. It is a key idea in physics and engineering since it is used to calculate acceleration, evaluate motion, and resolve kinematic and dynamical issues. Velocity is a crucial factor in many different applications, including navigation systems and vehicle speed.

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