Answer:
Energy
Explanation:
work is actually a transfer of energy. When work is done to an object , energy is transferred to that object.
The ability to do work is called energy.
What is work ?"Work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement."
What is energy ?"Energy is defined as the “ability to do work, which is the ability to exert a force causing displacement of an object.” energy is just the force that causes things to move. Energy is divided into two types: potential and kinetic."
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A metal ball began a free fall from the top of a building towards a sandy soil ground so that its velocity at the moment of striking the ground was 30 m/s, if the ball stopped after 0.01 s of penetrating the sand and the average resistance force of the sand again the motion of the ball was-3010 N, the mass of the ball is approximately equal to (Given that: The acceleration due to gravity is 10 m/s²)
The mass of the metal ball is approximately equal to 0.1 kg.
Freefall is a type of motion in which an object falls with gravitational acceleration without resistance from air, surface, or medium. In a freefall, the only force acting on an object is the force of gravity. In a freefall, the acceleration of an object is given by the formula: `g = 9.81 \(m/s^2`\)
The final velocity of a freefalling object can be calculated using the formula: `v = g*t `Where v is the final velocity, g is the gravitational acceleration, and t is the time taken to reach the final velocity. The force acting on an object is equal to the product of the mass of the object and the acceleration acting on the object. This is known as Newton's Second Law of Motion.
The formula for calculating force is: `F = ma`.Where F is the force acting on the object, m is the mass of the object, and a is the acceleration acting on the object.Given that the velocity of the metal ball at the moment of striking the ground was 30 m/s, and that it stopped after penetrating the sand for 0.01 s, we can calculate the mass of the metal ball using the formula for force.
We can assume that the force acting on the metal ball is equal to the average resistance force of the sand against the motion of the ball.
The formula for calculating force is: `F = ma`.
Rearranging the formula, we get: `m = F/a` .
Substituting the given values, we get: `
m = -3010/10`
Thus, the mass of the metal ball is approximately equal to 0.1 kg.
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A hypothetical planet has a radius 1.8 times that of Earth but has the same mass. What is the acceleration due to gravity near its surface?
The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
The formula for acceleration due to gravity is:
g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet
In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.
Therefore, g is proportional to 1/r².
So, using the ratio of radii given (1.8), we can write:
r = 1.8 x r Earth, where r Earth is the radius of Earth.
Substituting this value of r in the formula for acceleration due to gravity, we get:
g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²
We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².
Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:
gh = (1/3.24) x g Earth = 3.02 m/s²
Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².
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Group B[1] 12 State Huygens's Principle [2] b) In a Young's double slit experiment, the fringe width obtained is 0.6 cm. When light of wave length 4500 Aº is used if the distance between the screen and the slit is reduced in half, what should be the wavelength of light used to obtain fingers 0.0045 m wide? [3]
The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.
Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.
Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.
Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.
We can use the formula for fringe width in Young's double-slit experiment:
w = (λ * D) / d
Where:
w is the fringe width,
λ is the wavelength of light,
D is the distance between the screen and the double slits, and
d is the distance between the two slits.
Let's calculate the value of D/d using the given information:
D/d = w / λ
= 0.006 m / 4500 Å (1 m = 10^10 Å)
= 0.006 * 10^10 / 4500 m^-1
Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:
(D'/d) = (0.006/2) * 10^10 / 4500 m^-1
Now, we can rearrange the equation to solve for the new wavelength (λ'):
(λ' * D') / d = (D/d)
λ' = (D/d) * d / D
= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å
= 0.0045 m * 10^10 / 2 Å
= \(0.00225 * 10^{10\) Å
=\(2.25 * 10^7\)Å
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A circuit can only light up a lightbulb if there is a ______ path for electricity to travel from one end of the energy source to the other end.
Answer:
Continuous
Explanation:
A circuit can only light up a lightbulb if there is a continuous path for electricity to travel from one end of the energy source to the other end.
Answer:
continuios
Explanation:
define gravitational potential energy in your own words?
Answer:
The energy that an object has due to its location in a gravitational field is known as gravitational potential energy. When an object is close to the surface of the Earth, when the gravitational acceleration can be assumed to remain constant at roughly 9.8 m/s2, gravitational potential energy is most frequently used.
Explanation:
A parasitic plant with yellow, slender and branched stem is called.....
Explanation:
A parasitic plant with yellow, slender and branched stem is called Cuscuta (Amarbel).
hope this helps you.
If enough experimental data supports a hypothesis, then it:
A. Is accepted as true until proven false.
B. Becomes an Observational Law
C. Is proven 100% true.
D. Is falsified.
If enough experimental data supports a hypothesis, it is considered a well-supported scientific theory, but it is not considered to be 100% true or proven. Scientific theories are always open to further investigation and revision based on new evidence. Therefore, option C ("Is proven 100% true") is incorrect.
Option A ("Is accepted as true until proven false") is also incorrect because scientists do not accept a hypothesis as true until it has been rigorously tested and supported by a large body of evidence. Even then, scientists recognize that any scientific theory is subject to revision or falsification if new data or evidence emerges that contradicts it.
Option B ("Becomes an Observational Law") is also incorrect because scientific laws are typically descriptive, rather than explanatory. They describe what happens in a given set of circumstances, but they do not explain why it happens. Hypotheses and theories, on the other hand, attempt to explain why certain phenomena occur, and they are supported by experimental evidence.
Therefore, none of the options are completely accurate, but the most appropriate answer is that the hypothesis becomes a well-supported scientific theory.
Find the displacement and acceleration of the object in the graph.
The correct answer is as per graph displacement and acceleration is initially 0 m & 0 m/s^2, at middle 0 m & Infinity m/s^2 and finally 320 m & 5 m/s^2 respectively.
What is relation between velocity & acceleration with respect to displacement and time?
Velocity = Displacement / Time
Acceleration = Velocity / Time
Given data:
V1 = 40 m /s, t = 0 (Initial Velocity)
Displacement = 40 x 0 = 0 m,
Acceleration = 40 / 0 = 0 m/s^2
V2 = 0 m/s, t = 4 sec
Displacement = 0 x 4 = 0 m,
Acceleration = 0 / 4 = Infinity m/s^2
V3 = -40 m/s, t = 8 sec
Displacement = -40 x 8 = 320 m (in opposite direction)
Acceleration = -40 / 8 = 5 m/s^2
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You release a ball from rest at the top of a ramp. 6 s later it is moving at 4.0
m/s. What is the acceleration? (in meters per second squared) *
Your answer
\(a = \frac{vf - vi}{t} \)
here initial velocity vi=0 as ball release from rest
the final velocity is vf=4.0
time is t=6
so putting all these values in above equation
\(a = \frac{ 4.0- 0}{6} \)
\(a = 0.6667m \s {}^{2} \)
can you answer these 2 ?
Answer:
1. 38,500
2. 308,000
Explanation:
This would require a calculator. To find momentum, you multiply mass and velocity. You always want your mass to be measure in kilograms, but that is irrelevant in this question because they already are, it is just something to remember.
Name:.
Date:
Homework: Writing an Argument About
Australia's Skin Cancer Rate
G
4
You now have enough evidence to explain why Australia's skin cancer rate is so high. Review your
argument from Chapter 2 and think about how you will convince the AHA that both Claim 2 and
Claim 3 are accurate. You will use your completed Reasoning Tool from Activity 3 to revise and add to
your argument.
Question: Why is the skin cancer rate in Australia so high?
What does the slope represent? v^2/h = what variable?
Answer:
Slope measures the rate of change in the dependent variable as the independent variable changes.
Explanation:
What's Kinetic energy Give definition
Answer:
Kinetic energy is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work
03.03 LC)
The refraction of a sound wave occurs when the sound wave
stops at a boundary between media
bounces off the boundary between media
bends as it passes through the boundary between media
changes frequency after it passes through the boundary between media
The refraction of a sound wave occurs when the sound wave bends as it passes through the boundary between media. Refraction occurs when there is a difference in the speed of sound waves in two different media.
The bending of the sound wave occurs because the speed of sound changes as it passes from one medium to another. The amount of bending depends on the angle of incidence and the difference in speed between the two media. If the speed of sound is higher in the second medium than the first, then the wave bends away from the normal. If the speed of sound is lower in the second medium than the first, then the wave bends towards the normal. If the sound wave is incident perpendicular to the boundary, then there is no bending of the wave and no refraction occurs. Refraction of sound waves is an important phenomenon in our daily lives. It is the reason why we can hear sound around corners or why we can hear someone talking in another room even if the door is closed. The refraction of sound waves is also used in medical imaging, such as in ultrasound, where the sound waves are refracted as they pass through different tissues in the body.For more such questions on sound wave, click on:
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Say you have designed a machine that will allow you to become to first human to visit the center of the Earth. The journey straight down from your home to the center of the planet's core will take you 10 hours (at constant speed). Use this information and your own research to determine about how long it will take you to pass through the Earth's crust. Please show your calculations.
Assuming the Earth has a uniform density, we can estimate the thickness of the Earth's crust as the difference between the radius of the Earth and the radius of the Earth's core.
The radius of the Earth is approximately 6,371 kilometers, and the radius of the Earth's core is approximately 3,486 kilometers (source: USGS). Therefore, the thickness of the Earth's crust is:
thickness of Earth's crust = radius of Earth - radius of Earth's core
= 6,371 km - 3,486 km
= 2,885 km
To determine how long it will take to pass through the Earth's crust, we need to calculate the speed at which you are traveling. We know that the journey from the surface to the center of the Earth takes 10 hours at a constant speed, so we can calculate the speed as:
speed = distance / time
= radius of Earth / time taken to travel from surface to center
= 6,371 km / 10 hours
= 637.1 km/h
Now that we know the speed at which you are traveling, we can calculate how long it will take you to pass through the Earth's crust. The distance you need to travel through the crust is the thickness of the crust, which is 2,885 kilometers. Therefore, the time it will take you to pass through the Earth's crust is:
time = distance / speed
= 2,885 km / 637.1 km/h
= 4.53 hours
So, it will take you approximately 4.53 hours to pass through the Earth's crust on your journey to the center of the Earth, assuming a constant speed and uniform density of the Earth. However, it is important to note that this is a rough estimate, as the density of the Earth is not uniform, and there may be other factors that could affect the speed of your journey.
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A crane takes 2.0 minutes to lift a load to the top of a building. The change in gravitational potential energy of the load is 360kJ.
What is the useful power output of the crane?
A. 3.0kW
B. 180kW
C. 720kW
D. 43,200kW
Answer:
The answer is option A
Explanation:
why?
because to get the power, you need this equation. P= Work done/Time taken.
the unit of time are seconds, and the unit of work is kJ. So, the equation is=
360kJ/120s = 3kW
The useful power output of the crane is: A. 3.0 kW.
Given the following data:
Time = 2 minutesGravitational potential energy = 360 kJ = 360,000 J.To find the useful power output of the crane:
First of all, we would convert the time in minutes to seconds.
Conversion:
1 minutes = 60 seconds
2 minutes = 120 seconds.
360 kJ = 360,000 Joules.
Mathematically, the power output of a device is given by the formula;
\(Power = \frac{Energy}{Time} \\\\Power = \frac{360,000}{120}\)
Power output = 3000 Watts
In kilowatts, power output = 3.0 kW
Therefore, the useful power output of the crane is 3.0 kW.
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Convert 360 s to ms? Pls need help
Answer:
360000
Explanation:
Answer:
360000 milliseconds
Explanation:
I have this remembered dont worry homie i got chu
If 100. g of gold-198 decays to 6.25g in 25.3 days, what is the half-life of gold-198?
Given
\(\begin{gathered} N_0=100\text{ g} \\ t=25.3\text{ days} \\ N(t)=6.25\text{ g} \end{gathered}\)According to law of radioactive decay,
\(N(t)=N_0e^{-\lambda t}\)Rearranging equation in order to get rate constant,
\(\lambda=\frac{1}{t}\ln (\frac{N_0}{N(t)})\)Substituting all known values,
\(\begin{gathered} \lambda=\frac{1}{25.3\text{ days}}\ln (\frac{100\text{ g}}{6.25\text{ g}}) \\ =\frac{1}{25.3\text{ days}}\ln (16) \\ =0.109day^{-1} \end{gathered}\)The relation between the rate constant and the half life is given as,
\(\begin{gathered} \text{half life=}\frac{0.693}{\lambda} \\ =\frac{0.693}{0.109day^{-1}} \\ =6.357\text{ days} \end{gathered}\)Therefore, half life of the Gold -198 is about 6.375 days.
If mass is measured in kg and acceleration is measured in m/s^2, what units would force be measured in? This unit is also know as a newton (N).
Using Newtons second law
\(\\ \sf\longmapsto Force=Mass\times Acceleration\)
\(\\ \sf\longmapsto Force=kgm/s^2\)
\(\\ \sf\longmapsto Force=Newton(N)\)
SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?
The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
How to explain tje informationIsaac's force:
Magnitude: 255 N
Angle: 13 degrees North of East
x-component: 255*cos(13) = 245.1 N (Eastward)
y-component: 255*sin(13) = 58.1 N (Northward)
Newton's force:
Magnitude: 156 N
Angle: 34 degrees South of East
x-component: 156*cos(34) = 129.4 N (Westward)
y-component: 156*sin(34) = 86.5 N (Southward)
Now we can add the x- and y-components of the forces to find the net force:
Net force:
x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)
y-component: 58.1 N - 86.5 N = -28.4 N (Southward)
The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
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Part B
A roller coaster ride starts with the roller coaster car being pulled to the top of the first hill with pulley system. The car is
released from the top with an initial velocity close to zero, then accelerates downward. From that first hill, the roller coaster just
coasts; there is no driving force, other than gravity, to keep It going. Assuming no friction, what can you say about the height of
the other hills in the roller coaster ride?
The highest point of a roller coaster is almost always the first hill. In the majority of roller coasters, the hills get smaller as the train travels down the track.
To find the answer, we have to know more about the mechanical energy of a system.
How to find the answer?Since it influences the mechanical energy of the system, the first hill must be the highest.One of the fundamental tenets of physics is that, in the absence of friction, mechanical energy must be conserved. Mechanical energy is the product of kinetic energy and potential energy.When the vehicles ascend the first hill on the roller coaster, mechanical energy is provided to the system because the speed is zero at this point.Mechanical energy = U = mgh
Where m represents the car mass, g represents gravity, and h represents height
If the system is to continue moving, the other hills on the mountain must be lower than the first hill. When the vehicles are released, this energy is converted into kinetic and potential energy when it lowers and ascends, but the sum of these two cannot be larger than the starting energy.Finally, by applying the principle of energy conservation, we may determine that, the initial hill must be the highest.
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Can someone explain how to do the algebra for this question? I know everything else, I just don’t know how to rearrange the question to solve for v.
Answer:
Refer to the step-by-step Explanation.
Step-by-step Explanation:
Simplify the equation with given substitutions,
Given Equation:
\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)
Given Substitutions:
\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)
Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)
Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the left-hand side of the equation:
\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
Simplifying the third term.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)
"R²'s" cancel, we are left with:
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)
We have like terms, combine them.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)
Each term has an "m" in common, factor it out.
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)
Now we have the following equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the right-hand side of the equation:
\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)
\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)
Now we have the equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
\(\hrulefill\)
Now solving the equation for the variable "v":
\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
Dividing each side by "m," this will cancel the "m" variable on each side.
\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)
Subtract the term "gh" from either side of the equation.
\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)
Multiply each side of the equation by "10/7."
\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)
Now squaring both sides.
\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)
Thus, the simplified equation above matches the simplified equation that was given.
The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5 m. If the box has a mass of 1 kg, what is the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s?
The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.
Acceleration of the box
The acceleration of the box is calculated as follows;
vf² = vi² + 2as
a = (vf² - vi²)/2s
a = (11.5² - 13²) / (2 x 8.5)
a = -2.16 m/s²
Time of motion of the boxThe time taken for the box to travel is calculated as follows;
a = (vf - vi)/t
t = (vf - vi) / a
t = (11.5 - 13) / (-2.16)
t = 0.69 s
Average power supplied by the frictionP = Fv
P = (ma)(vf - vi)
P = (1 x -2.16) x (11.5 - 13)
P = 3.24 W
Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.
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In a showdown on the streets of Laredo, the good guy drops a 5.00-g silver bullet at a temperature of 20.0°C into a 100-cm' cup of water at 90.0°C. Simultaneously, the bad guy drops a 5.00-g copper bullet at the same initial temperature into an identical cup of water.
Which one ends the showdown with the coolest cup of water in the West? Neglect any energy transfer into or away from the container.
The silver would be coolest since it has the lowest heat capacity.
What is the heat capacity?Heat capacity, also known as thermal capacity, is the amount of heat energy required to raise the temperature of a substance by a certain amount. It is expressed as the amount of heat energy per unit temperature change, and is usually measured in joules per kelvin (J/K) or calories per degree Celsius (cal/°C).
Heat capacity is a key property of materials that provides important information about their thermal behavior and is critical for many areas of science and technology.
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If a sunspot has a temperature of 4,360 K and the sunspot can be considered a blackbody, what is the wavelength (in nm) of maximum intensity of the sunspot's radiation?
Given :-
A sunspot has a temperature of 4360 K .Sunspot can be considered as a black body .To find:-
The wavelenght of maximum intensity .Answer :-
Here we are given that the sunspots temperature is 4360K , and considering it as a black body we need to find out the wavelength of its maximum intensity.
So here we can use Wein's displacement Law according to which;
\(\qquad\: \underset{\rm\small Wein's \ displacement \ law }{\underbrace{\underline{\underline{ \green{ \quad\quad\lambda_{max}= b/T \quad\quad}}}}} \\\)
where ,
\(\lambda_{max}\) is maximum wavelength.\( b \) = Wein's displacement constant = 2.89 * 10-³ m K \( T\) is temperature in KelvinNow on substituting the respective values, we have;
\(\implies \lambda_{max}= \dfrac{2.89\times 10^{-3}m\ K}{4360K}\\\)
\(\implies \lambda_{max}= 0.0006628 \times 10^{-3}\ m\\\)
\(\implies \lambda_{max}=0.000663 \times 10^{-3}\ m\\\)
\(\implies\underline{\underline{\green{ \lambda_{max}= 663 \times 10^{-9} m = 663\ nm }}} \\\)
Hence the maximum wavelength is 663 nm .
and we are done!
Two glasses are filled with liquid to the same height . Glass W is filled with water and glass F is filled with fruit juice. Fruit juice has a higher density than water. Will the pressure in the glass of water be higher or smaller than the pressure in the glass of fruit juice.? Explain your answer
The weight at the foot of each glass will be the same because it is decided by the stature of the fluid column over it and the increasing speed due to gravity. Be that as it may, the weight applied by the fluid on the dividers of the holder will be diverse due to contrasts in thickness.
Since natural product juice incorporates a higher thickness than water, the mass of the same volume of natural product juice will be more noteworthy than that of water.
This implies that the constraint applied by the natural product juice on the dividers of the glass will be more prominent than the constraint applied by the water on the dividers of its glass, as the drive is straightforwardly corresponding to mass.
Subsequently, the weight of the glass of natural product juice will be higher than the weight of the glass of water.
In rundown, in spite of the fact that the weight at the foot of each glass will be the same, the weight applied by the fluid on the dividers of the holder will be diverse due to the contrasts in thickness, with the natural product juice applying a more noteworthy weight.
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An object of temperature 330 K is in a room at 296 K. Calculate how much heat is lost from the object in 13 minutes assuming an emissivity of 1 and a surface area of 1 m2. Take the heat loss units as J for Joules.
The heat loss from the object in 13 minutes is \(Q = -1.503684 * 10^{-3} Joules\)
How can Heat loss from an object be calculated?Heat loss can be calculated using this formula:
\(\frac{Q}{t} = oeA(T^{4} _{2} - T^{4} _{1})\\\)
It can be found that:
Q = heat loss in joules
t = time in seconds, 13 minutes = 780seconds
σ = (5.67 x 10⁻8J/s . m² . K⁴)
e = emissivity, 1
A = surface area of 1m²
T₂ = temperature of a room, 296 K
T₁ = temperature of an object, 330 K
Find \(Q\), where \(Q\) = \(\frac{Q}{t} = oeA(T^{4} _{2} - T^{4} _{1})\\\) = \(Q = oeA(T^{4} _{2} - T^{4} _{1}) t\\\)
\(Q = (5.67 x 10^{-8} J/s . m^{2} . K^{4} ) (1) (1) (296 K^{4} - 330 K^{4} ) (780)\\\)
\(Q = -0.001503684J\)
\(Q = -1.503684 * 10^{-3} Joules\)
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An electron moving along the x axis has a position given by x 16te$t m, where t is in seconds. How far is the electron from the origin when it momentarily stops
This question is incomplete, the complete question is;
An electron moving along the x axis has a position given by x = 16 t\(e^{-t}\) m, where t is in seconds. How far is the electron from the origin when it momentarily stops
Answer:
the electron is 5.88 m far from the origin when it momentarily stops
Explanation:
Given that;
the position of the electron is x = 16 t\(e^{-t}\) m
now, if the electron stopped after a time t, then its velocity is zero
so
V = dx/dt = 0
d/dt( 16 t\(e^{-t}\) m) = 0
16( -t\(e^{-t}\) + \(e^{-t}\) ) = 0
16(-t + 1) \(e^{-t}\) = 0
16(1 - t) \(e^{-t}\) = 0
1 - t = 0
t = 1 sec
so
x = 16 × 1 × \(e^{-1}\) m
x = 16 × 1 × 0.36787 m
x = 5.88 m
Therefore, the electron is 5.88 m far from the origin when it momentarily stops
Derive an expression of total energy Kinetic energy plus potential energy in rolling motion
The derivation of the total energy Kinetic energy plus potential energy in rolling motion is shown in the image attached.
What is the total energy Kinetic energy plus potential energy in rolling motion?In rolling motion, the total energy is the sum of the kinetic energy and the potential energy. Rolling motion is a combination of rotational and translational motion, and the energy of rolling can be expressed as follows:
Total energy = Kinetic energy + Potential energy
The derivation has been done and shown in the image attached here.
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If you pour liquid into a tall, narrow glass, you may hear sound with a steadily rising pitch. What is the source of the sound
Answer:
the vibration of the glass tube creating sound waves within itself. reason is the rising pitch is that the liquid rise shortens the length of the vibrating area within the tube.
Explanation: