Which sum is equivalent to 9c-12-15c-8-3c

Answer:

a)40.5m

b)139.5m

Step-by-step explanation:

Considering downward as 'positive' y-direction

\(x_i=0\\y_i=0\\v_i=8.8m/s\\a_x=0\\a_y=g\\\theta = 23\degree\\t=5s\)

First is to resolve initial velocity into x and y component:

\(v_x_i=v_icos\theta = 8.8 \times cos(23)= 8.1m/s\\v_y_i=v_isin\theta = 8.8 \times sin(23)= 3.4m/s\\\)

a) in order to find horizontal position of the ball:

\(x_f=x_i+v_x_it+\frac{1}{2} a_xt^2\)

\(x_f= 8.1\times5=40.5m\)

b) To find the height that the ball was thrown from(vertical position):

\(y_f=y_i+v_y_it+\frac{1}{2} a_yt^2\\y_f=(3.4\times 5)+(\frac{1}{2} \times9.8\times5^2)\\y_f=139.5m\)

Answer:

4.63 is the highest overall speed.

Answer:

D 4.63

Step-by-step explanation:

Step-by-step explanation:

Arc  PSR = 360° - 131° = 229°

Using outside angle theorem:

PQR =  (229 -131)° / 2 = 49°

The true statements about the functions A and B are

Given that

Function B: y = 3x + 4

A linear equation is represented as

y = mx + c

Where

Rate of change = m

y-intercept = c

Using the above definition, we have the following summary for function B

Rate of change = 3 and y-intercept = 4

For function A (the table), we have

Rate of change = (10 - 2)/(3 - 1)

Rate of change = 4

While the y-intercept is

y-intercept = 2 - 4

y-intercept = -2

So, we have

                                             Function A                Function B

Rate of change                         3                                4

y-intercept                                4                                -2

By comparing the features, we have the following true statements

C. The y-intercept of Function A is greater than the y-intercept of Function B.

E. The rate of change of Function A is less than the rate of change of Function B.

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Complete question

Function A and Function B are linear functions. Function A is represented by the table of values. Function B is represented by the equation.

Function A

x 1   3    4    7

y 2  10  14 26

Function B

y = 3x + 4

Which statements about the properties of Function A and Function B are true? Select each correct statement.

A. The y-intercept of Function A is equal to the y-intercept of Function B. B. The y-intercept of Function A is less than the y-intercept of Function B. C. The y-intercept of Function A is greater than the y-intercept of Function B.

D. The rate of change of Function A is equal to the rate of change of Function B.

E. The rate of change of Function A is less than the rate of change of Function B.

F. The rate of change of Function A is greater than the rate of change of Function B.

Given:

The units sold follows the equation

\(U = 10000-2000P\)

To find:

An equation for sales as a function of price.​

Solution:

Let S represents the sales function.

We know that, the money from sales is equal to the units sold times the price P of the unit.

\(S=U\times P\)

\(S=(10000-2000P)\times P\)

Using distributive property, we get

\(S=10000P-2000P^2\)

Therefore, the equation for sales as a function of price is \(S=10000P-2000P^2\).

In the given prisoner's dilemma game, players have two choices: cooperate (C) or defect (D). The payoffs for each combination of actions are represented by the variables g and ℓ, where g>0 and ℓ>0.

Now, let's consider a twist in the game. If a player chooses a different action in the second period compared to the first period, they incur a cost of ε. The players aim to maximize the sum of their payoffs over the two periods, with a discount factor of δ=1.

The question asks us to show that there is always a subgame perfect equilibrium where both players play (D,D) in both periods, given that g<1 and ℓ<1.

To prove this, we can analyze the incentives for each player and the possible outcomes in the game.

1. If both players choose (C,C) in the first period, they both receive a payoff of ℓ in the first period. However, in the second period, if one player switches to (D), they will receive a higher payoff of g, while the other player incurs a cost of ε. Therefore, it is not in the players' best interest to choose (C,C) in the first period.

2. If both players choose (D,D) in the first period, they both receive a payoff of g in the first period. In the second period, if they both stick to (D), they will receive another payoff of g. Since g>0, it is a better outcome for both players compared to (C,C). Furthermore, if one player switches to (C) in the second period, they will receive a lower payoff of ℓ, while the other player incurs a cost of ε. Hence, it is not in the players' best interest to choose (D,D) in the first period.

Based on this analysis, we can conclude that in the subgame perfect equilibrium, both players will choose (D,D) in both periods. This is because it is a dominant strategy for both players, ensuring the highest possible payoff for each player.

In summary, regardless of the values of g and ℓ (as long as they are both less than 1), there will always be a subgame perfect equilibrium where both players play (D,D) in both periods. This equilibrium is a result of analyzing the incentives and outcomes of the game.

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The area of the field is 376.99 square feet.

To find the area of the field that receives water from the irrigation sprinkler.

We can use the formula A = (1/2) * \(r^2\) * θ, where r is the distance covered by the sprinkler spray and θ is the angle it rotates through.

Given that the distance covered by the sprinkler spray is 40 feet (10) and it rotates through an angle of 135°, we can substitute these values into the formula to calculate the area:

r = 40 feet

θ = 135°

A = (1/2) * \((40)^2\) * 135°

Calculating this expression:

A = (1/2) * 1600 * 135°

A = (1/2) * 1600 * (135 * π/180)  [Converting degrees to radians using the conversion factor π/180]

A ≈ (1/2) * 1600 * (135 * 3.14159/180)  [Using an approximation of π as 3.14159]

A ≈ (1/2) * 1600 * (2.35619)

A ≈ 376.9911184 square feet

Therefore, the area of the field that receives water from the irrigation sprinkler is approximately 376.99 square feet when rounded to two decimal places.

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Answer:

información ℹ ‍♂️ ️ ℹ ‍♀️ ️ ℹ ‍♀️ ️ ℹ ‍♂️ ️ ℹ ‍♂️ ️ ℹ que no me lo esperaba en

Adding a variable may actually decrease the R2 if the variable is not strongly related to the dependent variable or if it is highly correlated with other explanatory variables already included in the model.

6. If two regressions use different sets of observations, then we cannot accurately compare the R2 values between the two models. R2 is a measure of how well the regression model fits the observed data, and if the data sets are different, then the R2 values cannot be compared.
7. Economic time series are outcomes of random variables, which means that they are subject to variability and uncertainty. This makes economic modeling challenging, as it requires identifying and accounting for the various factors that influence economic outcomes.
8. The key assumption for the general multiple regression model is that all factors in the unobserved error term be uncorrelated with the explanatory variables. This assumption is necessary to ensure that the regression coefficients are unbiased and accurately estimate the true relationship between the explanatory variables and the dependent variable.
9. An explanatory variable is called exogenous if it is uncorrelated with the error term. This means that the variation in the explanatory variable is not caused by any of the factors included in the error term, and therefore does not affect the accuracy of the regression coefficients.
10. R2 generally increases when an independent variable is added to a multiple regression model, as the model is better able to explain the variation in the dependent variable. However, in some cases, adding a variable may actually decrease the R2 if the variable is not strongly related to the dependent variable or if it is highly correlated with other explanatory variables already included in the model.

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6.Comparing the \(R_2\) values of two different regressions using different sets of observations is not meaningful or valid.

7.The economic time series are not necessarily outcomes of random variables.

8.The key assumption for the general multiple regression model is not that all factors in the unobserved error term be correlated with the explanatory variables.

9.An explanatory variable is called exogenous if it is not correlated with the error term.

10.\(R_2\) does not necessarily decrease when an independent variable is added to a multiple regression model.

What is regression?

Regression refers to a statistical modeling technique used to analyze the relationship between a dependent variable and one or more independent variables. It aims to find the best-fitting mathematical function that describes the relationship between the variables.

6.False. Comparing the \(R_2\) values of two different regressions using different sets of observations is not meaningful or valid.\(R_2\) is a measure of the proportion of the variation in the dependent variable that is explained by the independent variables in a particular regression model. Since the two regressions are based on different sets of observations, the R2 values will be specific to each regression and cannot be directly compared.

7.False. Economic time series are not necessarily outcomes of random variables. Economic time series data can be influenced by a combination of deterministic factors, such as economic policies, trends, and events, as well as random fluctuations. It depends on the specific context and the nature of the economic phenomenon being studied.

8.False. The key assumption for the general multiple regression model is not that all factors in the unobserved error term be correlated with the explanatory variables.The assumption is that the errors or residuals (the unobserved error term) are normally distributed with a mean of zero and constant variance, and they are independent of the explanatory variables.

9.False. An explanatory variable is called exogenous if it is not correlated with the error term. In other words, exogenous variables are independent of the error term in a regression model.

10.False. \(R_2\) does not necessarily decrease when an independent variable is added to a multiple regression model. \(R_2\)can increase, decrease, or remain the same when additional independent variables are included, depending on their relationship with the dependent variable and the existing independent variables in the model. \(R_2\) measures the goodness of fit of the regression model and represents the proportion of the total variation in the dependent variable that is explained by the independent variables.

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The race horse's speed is approximately 256 furlongs per fortnight.

To determine the race horse's speed in furlongs per fortnight, we need to convert both the distance and time units to their respective values.

1 furlong is equal to 180 yards, so the horse's speed in yards per second (7 yards/second) can be converted to furlongs per second:

Speed in furlongs per second = (7 yards/second) / (180 yards/furlong) = 7/180 furlongs/second

Next, we need to convert the time from seconds to fortnights. Since a fortnight is a time period of two weeks, and there are 7 days in a week, a fortnight consists of 14 days:

Time in seconds per fortnight = (14 days/fortnight) * (24 hours/day) * (60 minutes/hour) * (60 seconds/minute) = 1,209,600 seconds/fortnight

Finally, we can calculate the horse's speed in furlongs per fortnight by multiplying the speed in furlongs per second by the time in seconds per fortnight:

Speed in furlongs per fortnight = (7/180 furlongs/second) * (1,209,600 seconds/fortnight) = 46,080/180 furlongs/fortnight ≈ 256 furlongs/fortnight

The race horse's speed is approximately 256 furlongs per fortnight.

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Answer:

7 3/8 + (-4 1/2) ÷ (-5 2/3) = 8 23/136

Step-by-step explanation:

1) First I turned all the mix numbers into improper fractions:

7 3/8 ----> ( 7(8)+3/8) = 59/8, 4 1/2 ----> (4(2)+1/2) = 9/2, 5 2/3 ---->  (5(3)+2/3) = 17/3

So now it should look like this: 59/8 + (-9/2)÷(-17/3)

2) Now our goal is to divide both of the improper fractions (-9/2)÷(-17/3),

- We first apply our fraction rule:  -a/-b = a/b (when we have two negatives they cancel out each other and make a positive)

Our Case, From this:-9/2 ÷ -17/3 = To This: 9/2 ÷ 17/3

3) Now we can divide the fractions using this rule: a/b ÷ c/d = a times d / b times

Our Case, From This: 9/2 ÷ 17/3 To This: 9(3)/2(17) Which Gives Us: 27/34

(9 x 3 = 27, 2 x 17= 34)

So now it looks like this: 59/8 +27/34

4) Our look goal is to have the same denominator (which is the bottom part of the fraction)  which are 8 and 34

To find it we find the LCM or Least Common Multiple of 8 and 34

(The LCM of a, b is the smallest positive number that is divisible by both a and b) which in this case a and b are 8 and 34  

LCM is 136

5) We adjust our two fractions based on the LCM,

(Multiply each numerator ( top part of the fraction)  by the same amount of needed to multiply its corresponding denominator to turn it to the LCM 136.

From This: 59/8  and 27/34 To This: 1003/136 and 108/36 ( 59(17)/8 (17) = 1003/136, 27(4)/34(4) = 108/306

6) Finally we can add the numerator (1003 and 108) together: 1003+108= 1111 and now we are left with 1111/136

Then we turn our improper fraction back into a mix number: 1111/138= 8 23/136

Answer:

\(\frac{1111}{136} = 8 \frac{23}{136}\)

Step-by-step explanation:

We want to simplify:

\(7 \frac{3}{8} + \frac{ -4 \frac{1}{2} }{ -5 \frac{2}{3} }\)

First, convert all the fractions to improper fractions:

\(\frac{59}{8} + \frac{ - \frac{9}{2} }{ - \frac{17}{3} } \\\\= \frac{59}{8} + \frac{27}{34}\)

Find the LCM of the denominators:

\(\frac{(17 * 59) + (4 * 27)}{136} \\\\ = \frac{1003 + 108}{136}\\ \\= \frac{1111}{136} \\\\= 8 \frac{23}{136}\)

Answer: y=-0.4x+2

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

The LHS and RHS are exactly the same, so the equality is true.

The associate property of addition says that

\(\boxed{a+(b+c)=(a+b)+c}\)

In order to make the addition of fractions, the denominators should be same. So we can write three fractions as one.

\(\dfrac{1}{2} +\left(\dfrac{2}{3}+\dfrac{3}{4} \right )\)

\(\dfrac{1}{2} +\dfrac{2}{3}+\dfrac{3}{4}\)

\(\dfrac{1\cdot 6 }{2\cdot 6} +\dfrac{2 \cdot 4}{3 \cdot 4}+\dfrac{3 \cdot 3 }{4 \cdot 3}\)

\(\dfrac{ 6 }{12} +\dfrac{8}{12}+\dfrac{9 }{12}\)

\(\dfrac{ 23 }{12}\)

Answer:

You gotta give me (us) more to work with homie.

Step-by-step explanation:

If I have more of a picture with it I could possibly help but all there is a barely readable and legible nonsense equation. Sorry :(

In this distribution, the shape that describes the temperature data is left-skewed distribution.

left-skewed distribution serves as a type of more values on the right side (tail) of the distribution graph .

Therefore, From the graph, majority of the data is to the right of the graph which is a left-skewed distribution.

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Answer:

B) left-skewed

Step-by-step explanation:

It will take approximately 3.23 years for the wolf population to reach 1000.

Using the logistic growth model from problem 1, we can calculate the time it will take for the wolf population in the national park to reach 1000.

First, we need to find the carrying capacity (K) of the population. We can estimate it to be around 2000 based on the given data.

Next, we can use the formula P(t) = K / (1 + A*e^(-rt)), where P(t) represents the population size at time t, A is the initial population size, r is the growth rate, and t is time in years.

We know that A = 200, P(t) = 1000, and K = 2000. We can solve for r using the formula r = ln((P(t)/A)-1) / (-t). Plugging in the values, we get:

r = ln((1000/200)-1) / (-t)

r = ln(4) / (-t)

Solving for t, we get:

= -ln((1000/200)-1) / r

t = -ln(4) / r

Using the growth rate from problem 1, r = 0.68, we get:

t = -ln(4) / 0.68

t ≈ 3.23 years

Therefore, it will take approximately 3.23 years for the wolf population to reach 1000.

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Answer:

1, 3, 6, 10, 15, 21....

Step-by-step explanation:

What is the formula of the sequence

Since the difference in the second row matches up, the nth term of the sequence has the general form of a second degree polynomial.

So,

\(a_n=bn^2+cn+d\)

Putting \(n=1,2,3...\)

\(b+c+d=1....[i]\)

\(4b+2c+d=3......[ii]\)

\(9b+3c+d=6....[iii]\)

From equation [i]

\(d=1-b-c\)

Putting this into [ii] and [iii]

\(4b+2c+1-b-c=3\)

\(\implies3b+c=2....[iv]\)

\(9b+3c+1-b-c=6\)

\(\implies8b+2c=5\\\implies4b+c =\frac{5}{2}..........[v]\)

[v]-[iv]

\(\implies{b=\frac{5}{2}-2=\frac{1}{2}\)

Putting this into [iv]

\(\frac{3}{2}+c=2\\\implies c=\frac{1}{2}\)

Putting everything found so far into [i]

\(d=1-b-c=1-\frac{1}{2}-\frac{1}{2}=0\\\)

Hence

\(a_n=\frac{1}{2}n^2+\frac{1}{2}n\)

\(\implies a_n=\frac{1}{2}n(n+1)\)

and this matches with the general term of the triangular number sequence.

Answer:

She is 2 dollars in debt. Or $-2

Step-by-step explanation:

14 + 8= 22. She only had 20 dollars so the purchase she made left her with $-2

Answers:

Everything is rational but choice D

=======================================================

Explanation:

A rational number is anything in the form p/q where p and q are integers. The value of q cannot be zero.

So that's why -4/11 is rational. Here we have p = -4 and q = 11.

Any terminating decimal is rational. For choice A, we have 3.14 = 314/100

Choice C is also rational because \(\sqrt{\frac{4}{9}} = \frac{\sqrt{4}}{\sqrt{9}} = \frac{2}{3}\)

Choice E is rational since 6 = 6/1.

In short, choices A, B, C, and E are rational.

------------------

The only irrational answer is d) 2pi

pi is irrational because we cannot write it as a fraction of two integers. Any number in the form n*pi, where n is any integer, is also irrational.

Step-by-step explanation:

if this figure is rectangle then opposite side of rectangle are equal

perimeter= sum of all sides

156=5x-3+5x-3+4x+4x

156=18x-6

x=9

So length of side WX is 9. 4

WX= 36

Answer:

22

Step-by-step explanation:

The preimeter is adding all sides together. I took 154-55 twice sense we have four sides of a rectangle and two are lengths. after that i got 44. I then just remembered we had two sides left so divided that by 2 and got 22

Answer:

Her results changed because the power increased due to the fact that she reduced variability in her data as a result of using a sample that had lesser variability.

Step-by-step explanation:

She is trying to find if there is difference between people who consumed 1 versus 2 beverages.

Now initially she surveyed 40 people between ages 18 to 38 years and of huge weights and found out there was no difference. However, she decided to run the survey again on only women aged 18 to 22 years with normal body weight.

Since she used a lesser sample size and surveyed only women, it means there will be lesser variability in the result as the sample is smaller and streamlined to only women.

Thus, her result changed because the power increased due to the fact that she reduced variability in her data as a result of using a sample that had lesser variability.

Answer:

35

Step-by-step explanation:yes

Answer:

what's the question?

Step-by-step explanation:

Recall that any non-zero number raised to the power of 0 is equal to 1. Therefore, 8^0 = 1.

To rewrite the expression using only positive exponents, we can use the following rules of exponents:

a^(-n) = 1 / a^n

a^0 = 1

Using these rules, we can rewrite the expression as:

4^(-2) x 8^0 x 5^6

= (1/4^2) x 1 x 5^6

= 1/16 x 5^6

Therefore, the expression 4 to the power of negative 2 times 8 to the power of 0 times 5 to the power of 6, rewritten using only positive exponents, is 1/16 x 5^6.

Answer:

10 hours

Step-by-step explanation:

let x be the total number of hours

Amazing design total charge = 45x+250

super structures total charge = 60x+100

both companies charge the same amount when both equation equals

45x+250=60x+100

60x-45x=250-100

15x=150

x=10

therefore at 10 hours both companies will charge the same amount

Answer:

-½ + (root2 / 2) i + root½ i

Step-by-step explanation:

\( \frac{a}{b} - \frac{c}{d} = \frac{ad - cb}{bd} \)

I used this formula to do it but let me know if it's enough or you have to simplify it further

Answer:

45

Step-by-step explanation:

The value of the variables are y = -45/2, r = -9, x = 2/9 and x = 2

(1) y/3 + 6 = -3/2

Multiply through by 3

y + 18 = -9/2

Subtract 18 from both sides

y = -18 - 9/2

Take LCM

y = (-18 * 2 - 9)/2

Evaluate

y = -45/2

(2) -2r/3 - 3 = 3

Multiply through by 3

-2r - 9 = 9

Add 9 to both sides

-2r = 18

Divide by 2

r = -9

(3) 2/3 - 2x = x

Multiply through by 3

2 - 6x = 3x

Add 6x to both sides

2 = 9x

Divide by 9

x = 2/9

(4) 7x/2 + -5/2 = 9/2

Multiply through by 2

7x - 5 = 9

Add 5 to both sides

7x = 14

Divide by 7

x = 2

Hence, the value of the variables are y = -45/2, r = -9, x = 2/9 and x = 2

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