Which statement is true?
A
7.9 <6.964
B
7.9 > 6.964
с
7.9 = 6.964

The correct angle which is adjacent to ADB is,

⇒ ∠ ADC

Since, An angle is a combination of two rays with a same endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs and sometimes the arms of the angle.

We have to given that;

To find correct angle which is adjacent to ADB.

We know that;

Two angles are Adjacent when they have a common side and a common vertex and don't overlap are called Adjacent angle.

Hence, By definition of Adjacent angle, we get;

The correct angle which is adjacent to ADB is,

⇒ ∠ ADC

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The finite population correction factor is used in computing the standard error of the sample mean when the sample size is smaller than 5% of the population size.

The finite population correction factor is a adjustment made to the standard error of the sample mean when the sample is taken from a finite population, rather than an infinite population.

It accounts for the fact that sampling without replacement affects the variability of the sample mean.

When the sample size is relatively large compared to the population size (more than half), the effect of sampling without replacement becomes negligible, and the finite population correction factor is not necessary.

In this case, the standard error of the sample mean can be estimated using the formula for sampling with replacement.

On the other hand, when the sample size is small relative to the population size (less than 5%), the effect of sampling without replacement becomes more pronounced, and the finite population correction factor should be applied.

This correction adjusts the standard error to account for the finite population size and provides a more accurate estimate of the variability of the sample mean.

Therefore, the correct answer is option 2: the finite population correction factor is used when the sample size is smaller than 5% of the population size.

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Answer:

623

Step-by-step explanation:

Answer:

20 2/3

Step-by-step explanation:

Answer:

5/1

Step-by-step explanation:

Statistics on women in politics highlight that woman - who make up over 50 percent of the U.S. population - are substantially lag in high government positions.

In U.S. the population of Women are 50.8 percent. Approximately, 60 percent of women have their undergraduate degree, and 60 percent of women have their master's degree. They are very well educated. They earn almost 60 percent of law degrees.

But, when it comes to representation in high government positions, they substantially lag behind men. There are only 14.6 percent of executive officers, they hold only 24.2 percent of state legislative seats. They hold only 18.5 percent of congressional seats, and they are just 20 percent of U.S. senators.

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The definite integral is 2.5.

The given definite integral is ∫₆³ |x-4| dx. We can evaluate this integral by breaking it up into two separate integrals, depending on the sign of x-4. When x-4 ≥ 0, the absolute value of x-4 is simply x-4, and when x-4 < 0, the absolute value of x-4 is -(x-4). Thus, we have:

We can split the integral into two parts:

For x between 3 and 4:

I1 = ∫\(3^4\) (x-4)dx

= [\(x^2\)/2 - 4x]\(3^4\)

= [(16-12)-(9/2-12)]

= 2.5

For x between 4 and 6:

I2 = ∫\(4^6\) (4-x)dx

= [4x - \(x^2\)/2]\(4^6\)

= [(24-16)-(16-8)]

= 0

So the total integral is:

I = I1 + I2 = 2.5 + 0 = 2.5

Therefore, the definite integral is 2.5.

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The average speed during the interval between 1 second and 2 seconds is most nearly 8 m/s, which corresponds to option (E).

To determine the average speed during the interval between 1 second and 2 seconds, we need to find the displacement of the object during that time interval and divide it by the duration.

Looking at the graph, we can observe that the object's position increases from approximately 0 meters at 1 second to approximately 8 meters at 2 seconds.

Therefore, the displacement is 8 meters - 0 meters = 8 meters.

The duration of the time interval is 2 seconds - 1 second = 1 second.

To calculate the average speed, we divide the displacement by the duration:

Average speed = Displacement / Duration = 8 meters / 1 second = 8 m/s.

Therefore, the average speed during the interval between 1 second and 2 seconds is most nearly 8 m/s, which corresponds to option (E).

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The inequality represents all possible values for the clerk's sales, s, on Monday is 0.1s + 125 < 180.

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

A clerk earns $125 per day, plus a commission equal to 10% of her sales, s. The clerk earns less than $180 on Monday.

The total commission on her sales s = 10% x s

                                                           = 0.1s

The total money earn on monday = 0.1s + 125

The inequality represents all possible values for the clerk's sales, s, on Monday.

The clerk earns less than $180 on Monday.

0.1s + 125 < 180

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Answer:

1

Step-by-step explanation:

To solve this, first, take 22 minutes and divide it by 60 minutes, which is the number of minutes in an hour. Then, add two to the value, and multiply it by six square meters per hour, which is the rate that David can paint the wall. From there, you get 14.2 square meters which he painted in 2 hours and 22 minutes. Divide 14.2 square meters by the length of 11 meters to get 1.290 meters. Since they asked you to round to the nearest meter, you get 1 meter.

Answer:

21y^2+11.2

Step-by-step explanation:

4-3y(-7y)+7.2

combine like terms

-3y (-7y) = 21y^2

add 4 to 7.2

11.2

21y^2 + 11.2

Answer:

C

Step-by-step explanation:

it is stretched

Answer:

(ab-bc)²

Step-by-step explanation:

Answer:

(ab - bc)^2.

Step-by-step explanation:

ab(ab - bc) + bc(bc - ab)​

= ab(ab - bc) - bc(ab - bc)​

= (ab - bc)(ab - bc)

= (ab - bc)^2

Answer:

The answer is C There were no mosques on the African continent.  

Step-by-step explanation:

Answer:

27 / 4x^6y^8.

Step-by-step explanation:

= 4 * 3^3 x^6 y^12 / 16 x^12 y^20

= 4*27 / 16 x^6y^8

= 4*27/ x^6y^8

= 27 / 4x^6y^8

Step-by-step explanation:

let the number be x

\(1 \div 3 \: of \: x \\ x \div 3 = 1 \div 2 \: of \: x - 6 \\ x \div 3 = x \div 2 - 6 \\ multiply \: both \: sides \: by \: the \: lcm \: 6 \\ x \div 3 \times 6 = x \div 2 \times 6 - 6 \times 6 \\ x \times 2 = x \times 3 - 36 \\ 2x = 3x - 36 \\ 2x - 3x = - 36 \\ - x = - 36 \\ divide \: both \: sides \: by \: - 1 \\ - x \div - 1 = - 36 \div - 1 \\ x = 36\)

Answer:

d. 194481

Step-by-step explanation:

We solve this question using exponential growth rate formula

This is given as:

y = a(1 + r) ^t

Where y = Amount after time t

a = Initial amount = 160000

r = growth or increase rate = 5% = 0.05

t = time in years = 4

y = 160000(1 + 0.05)⁴

y = 160000(1.05)⁴

y = 194481

Therefore, the number of cows needed after 4 years to fulfill the requirement of the milk is 194481

Question 4: Laura applies for the position of ambulance medic. To give her a job simulation (behavioral interview) screening test, the interviewer...

This question involves providing a job simulation or behavioral interview, which allows the interviewer to observe how the candidate performs in a simulated work situation. This type of question assesses the candidate's skills, abilities, and behavior in a real or simulated work scenario, providing a more accurate evaluation of their capabilities for the job.

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Answer: Our answer set is( -1,-2 )

Step-by-step explanation:

y = x - 1

y = 3x + 1

We can use the combine method here.

==> - 1y + 1x = 1  (y = x - 1)

==>  -1y +3x = -1 (y = 3x + 1)

- 1y + 1x = 1  

 -1y +3x = -1

To single out any of the two variables, we need them to cancel out. Let us choose to cancel out y. We therefore multiply by negative 1 in the first re-arranged equation.

==> -1* (- 1y + 1x )= (1 ) * -1

Now we add the equations

==> 1y -1x = -1

==>-1y +3x = -1

______________

2x = -2

Divide.

==> x = -1

Now we insert x into any of the two original equations;

y = (-1) - 1

==> y = -2

Our answer set is( -1,-2 )

Answer: 4.2

Step-by-step explanation: First, you'd need to re-arrange the decimals so, you can get 4.65.........

Then, you round up to get about 4.7

Another way is to round up the decimals, so your new equation:

\(\frac{21}{5}\)

Then, you'd divide to get 4.2. This way is more of an estimate than the 1st way; the 1st way is an exact answer [rounded] I hope this helped.

Answer:

  4.64

Step-by-step explanation:

You want an estimate of the quotient 21.4/4.6.

Multiplication and division by 5 are simplified by the relation ...

  5 = 10/2

Here, the denominator is about 5, so the quotient is about ...

  21.4 × 2/10 = 42.8/10 = 4.28 ≈ 4.3 . . . . . a first estimate; known to be low

We notice that 4.6 is 0.4 less than 5, which is 0.8/10 = 0.08, or 8% less. That means the actual quotient will be on the order of 8% more than 4.3.

A closer estimate would be ...

  4.3 + 0.08 · 4.3 = 4.3 +0.344 ≈ 4.64

An estimate of the quotient is 4.64.

__

Additional comment

To compute our "error correction," we rounded 4.28 up to 4.3, about 2 parts in 400, making that number (4.3) be about 0.5% high. The estimate of 1/0.92 ≈ 1.08 turns out to be about 0.7% low. This means an even better estimate would add 0.2%, or about 0.009, to the estimate we have, making it about 4.653. These second-order corrections are also slightly off. The actual quotient rounds to 4.652.

Doubling a number is so easy that we elected to keep all of the digits of the numerator when we did the division by 5. This gave a more satisfying 4.3 instead of 4 as the first estimate.

The difference between groups and the sample size makes the results of a study statistically significant.

Statistical significance is a measure of the likelihood that the results of a study are not due to chance. In order for a result to be statistically significant, it must meet two criteria:

The difference between groups must be large enough to be unlikely to occur by chance. This is typically assessed using a statistical test such as a t-test or an ANOVA.

The result of the test is expressed as a p-value, which represents the probability of obtaining the observed results if there were no true difference between groups. A p-value of less than 0.05 (or 5%) is generally considered to be statistically significant.

The sample size must be large enough to reduce the possibility of sampling error. A larger sample size generally increases the power of a study, making it more likely to detect a true effect.

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Answer:

d = 1 + 3p  

Step-by-step explanation:

Leon already ran 1 miles on his own and he is expected to cover a distance d of 3 miles during each practice. The number of practices is expressed as p and the distance covered is expressed as d.

For every track practice he is expected to cover a distance of 3 miles. Recall he has already cover 1 mile on his own.

Therefore, the relationship between the practices p and the distance d can be expressed as follows.

number of track practice = p

distance covered = d

The distance covered  d in miles is 1 miles plus the number of track practice p multiply by 3

d = 1 + 3p  

When a = -0.1 and b = 4, the value of the monomial \(-3a^3b\) is 0.012.

To find the value of the monomial\(-3a^3b\) when a = -0.1 and b = 4, we substitute these values into the expression and perform the necessary calculations.

Plugging in the given values, we have:

\(-3(-0.1)^3(4)\)

First, we evaluate \((-0.1)^3\). Cubing -0.1 gives us -0.001.

Now, substituting the value, we have:

-3(-0.001)(4)

Multiplying -3 and -0.001 gives us 0.003.

Finally, multiplying 0.003 by 4, we get the value of the expression:

0.003(4) = 0.012

When a = -0.1 and b = 4, the value of the monomial \(-3a^3b\) is 0.012.

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Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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The radius of the cylinder that produces the minimum surface area is 3/2 centimeters.

To solve this problem, we need to use the formulas for the volume and surface area of the solid. Let's first denote the radius of the cylinder by r and its height by h. Since the total volume of the solid is 18 cubic centimeters, we have:

V = volume of cylinder + volume of two hemispheres
V = πr^2h + 2(2/3πr^3)
V = πr^2h + (4/3)πr^3
18 = πr^2h + (4/3)πr^3

To find the radius that produces the minimum surface area, we need to express the surface area in terms of r and then minimize it using calculus. The surface area of the solid consists of three parts: the top and bottom surfaces (which are the two hemispheres), and the lateral surface (which is the cylinder). The formulas for these are:

A_top = A_bottom = 2πr^2
A_lateral = 2πrh

The total surface area is therefore:

A = A_top + A_bottom + A_lateral
A = 4πr^2 + 2πrh

Now we can eliminate h from these equations by using the volume equation. Solving for h, we get:

h = (18 - (4/3)πr^3)/(πr^2)

Substituting this expression into the surface area equation, we get:

A = 4πr^2 + 2πr[(18 - (4/3)πr^3)/(πr^2)]
A = 4πr^2 + 2(18/r - (4/3)πr)

To find the minimum of this function, we take its derivative with respect to r, set it equal to zero, and solve for r:

dA/dr = 8πr - 8/3πr^2 = 0
r = 3/2

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The greatest number of shelves Melanie can fill is 15 shelves

Given :

Melanie has 45 horse statues and 60 elephant statues

She wants to put them on shelves so that the same number of each type of statue are on each shelf.

To find greatest number of shelves , we need to take GCF of 45  and 60

Lets find out GCF, greatest common factor

First write the factors for 45  and 60

45 --> 3,3,5

60 --> 2,3,2,5

Common factors are 3,5

GCF is 15

She needs 15 shelves to fill .

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