which statement is true about electron shielding of nuclear charge? which statement is true about electron shielding of nuclear charge? core electrons efficiently shield one another from nuclear charge. outermost electrons efficiently shield core electrons from nuclear charge. outermost electrons efficiently shield one another from nuclear charge. core electrons efficiently shield outermost electrons from nuclear charge.

Answer:

The process is given in the pic.

I have taken the average masses so u substitute the values and solve hope it will help :)❤

Answer:

900 windings

Explanation:

Applying,

Vs/Vp = Ns/Np............. Equation 1

Where Vs = Secondary voltage, Vp = primary voltage, Ns = Number of turns in the secondary circuit, Np = number of turns in the primary circuit

make Ns the subject of the equation

Ns = VsNp/Vp........... Equation 2

From the question,

Given: Vs = 240 V, Np = 300 windings, Vp  = 80 V

Substitute these values into equation 2

Ns = (240×300)/80

Ns = 900 windings

Any action intended to hurt, harm, or cause suffering to another living thing or group of beings is considered to be aggressive.

Specifically, acts that injure someone physically. action that harms psychological health, such as that which instills apprehension, concern, or anguish.When you hurt your brother, you also hurt him. One way to damage someone is to hurt them physically.

People who are distressed could also believe that they are unable to handle or cope with alterations brought on by everyday activities or medical conditions like cancer. It is unfavourable, unhealthy, and discouraging. Stressors events that trigger the stress reaction in our bodies. A stressor is anything that creates stress.

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Answer: D

Explanation: just completed this question on a p e x

Answer:

4km

Explanation:

Distance=speed x time

Knowing this we know the time and speed

so it is 8 x .5= D

And 8 x .5 =4

If you have any questions let me know

Answer:

Two tectonic plates move horizontally past one another along Earth’s surface, forming long fault lines.

Answer:

Plates move apart

Explanation:

At a transform boundary, plates move apart. At a divergent boundary, plates separate. Convection currents in the mantle contribute to tectonic plate movement.

(A) The wavelength of each of these waves when they are sent through sea water is 0.0126 m and 0.0076 m respectively.

(B) The wavelength of each of these waves when they are sent through freshwater is 0.012 m and 0.0074 m respectively.

(C) The time taken for the echo to return to the ship is 3.97 seconds.

The wavelength of the sound wave in sea water depends on the speed of sound in seawater and frequency of the wave.

The speed of sound in seawater, v = 1,510 m/s

λ = v/f

when the frequency, f = 120 kHz

λ = 1510 / 120,000

λ =  0.0126 m

when the frequency, f = 200 kHz

λ = 1510 / 200,000

λ =  0.0076 m

The speed of sound in freshwater, v = 1481 m/s

when the frequency, f = 120 kHz

λ = 1481 / 120,000

λ =  0.012 m

when the frequency, f = 200 kHz

λ = 1481 / 200,000

λ =  0.0074 m

The time taken for the echo to return is calculated as follows

v = 2d/t

t = 2d/v

t = (2 x 3,000 m) / (1510 m/s)

t = 3.97 s

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Answer:

false a curciut is just a loop of electricity goes in and negative comes out  when using a battery the negative goes in and the goes out making a battery have two sides to a uircute.

hope this helps!  

Explanation:

Answer:

Answer B is the correct answer: "Motion of one projectile as seen from the other is a straight line."

Explanation:

Let's write the equations of motion for each projectile, using that projectile \(a\) is launched with velocity \(a\) which has components associated with the angle of launching, given in x and y coordinates as: \(a_x\,\,and\,\,a_y\).

Similarly, assume that projectile b is launched with velocity \(b\) with components due to the launching angle = \(b_x\,\,and \,\,b_y\)

then the equations of motion for the two projectiles launched at the same time (t) from the same spot (position that we assume to be at the origin of coordinates to simplify formulas) are:

\(x_a=a_x\,t\\y_a= a_y\,t-\frac{1}{2} g\,t^2\\and\\x_b=b_x\,t\\y_b= b_y\,t-\frac{1}{2} g\,t^2\)

therefore, from the frame of reference of projectile "b", the x and y position of projectile "\(a\)" would be:

\(x_{a\,b}= x_a-x_b= a_x\,t-b_x\,t=(a_x-b_x)\,t\)  which is linear in "t"

\(y_{a\,\,b}=y_a-y_b= a_y\,t-\frac{1}{2} g\,t^2-\left[ b_y\,t-\frac{1}{2} g\,t^2\right]=(a_y-b_y)\,t\) which is also linear in t.

Therefore the motion of one projectile with reference to the other is a straight line (answer B)

Notice as well that this two projectiles cannot collide because they have been launched together, and supposedly at different speeds and angles. The only way that they can share the same x-coordinate and the same y-coordinate at the same time "t" is if their velocity components are equal, which is not what we are told.

\(x_a=x_b\\a_x\,t= b_x\,t\\and\\y_a= y_b\\a_y\,t-\frac{1}{2} g\,t^2= b_y\,t-\frac{1}{2} g\,t^2\\a_y\,t=b_y\,t\\a_y=b_y\)

The perpendicular force to the plane exerted on the sled is approximately 382.68 lb

we need to use trigonometry and the concept of resolving forces into components.

Let's draw a diagram of the sled and inclined plane:

    |\

    | \

    |  \

    |   \

    |    \

    |     \

    |      \

    |       \

    |θ      \

    |        \

    |         \

    |          \

    |           \

    -------------

          W

Where W is the weight of the sled and θ is the angle of the inclined plane with the horizontal.

We can resolve the weight of the sled into two components: one perpendicular to the plane and one parallel to the plane.

The perpendicular component is the force that we are looking for.

The perpendicular component of the weight is given by:

W_perp = W * cos(θ)

Substituting the values:

W_perp = 500 lb * cos(50°) = 382.68 lb (rounded to two decimal places)

Therefore, the perpendicular force to the plane exerted on the sled is approximately 382.68 lb.

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Answer:

Formula for constant-speed = Total distance / Total time taken

Explanation:

Answer:

distance

Explanation:

it is the distance traveled by light in one year

Answer:

The phases occur because the Sun lights different parts of the Moon as the Moon revolves around the Earth. That means the reason we see different phases of the Moon here on Earth is that we only see the parts of the Moon that are being lit up by the Sun.

Answer:

A

Explanation:

the current passed in car is fixed and responsible for electric devices in car moves in one direction only but there are some cars has alternating cars to make induced current in its coils allowing it to move without fuel(as exception)

Answer:

yarchij b club, kakegurui, devilman, Mr.love, yuri on ice, sk8, joker game, young black jack

Answer:

1 kg

Explanation:

.suebebdindnwb....

Answer:

S = 12757.5 m

Explanation:

A magnitude of the displacement can be obtained by visualizing the walking. The actual path from A to B Is 3 m then from B to D as 5 m and finally from D to E as 6 m. |S| =√92+52 = 10.29 m. The direction of Resultant displacement is South East.

Solving for the different variables we can use the following formulas:  

Given initial velocity, final velocity, and time calculate the displacement.

s = ½( v + u )t

Given displacement, time, and initial velocity calculate the final velocity.

v = 2s/t - u

Given displacement, time, and final velocity calculate the initial velocity.

u = 2s/t - v

Given initial velocity, final velocity, and time calculate the displacement.

t = 2s/ ( v + u )

Answer:

The correct answer is ii) It must revolve around a star

Explanation:

For a celestial body to be called a planet, it must meet at least three characteristics

* rotate around a star

* its mass must be sufficient to maintain hydrostatic equilibrium

* have control over its orbital that is to say to prevent that other body is in its same orbital

if we check the different proportions

i) False. Most of the planets are spheres deformed by their rotation on themselves and around the star

ii) True. It is in accordance with the minimum characteristics of the plants

iii) False .. the orbit of the planet can be elliptical and the speed changes at each point for this at a different distance from the star that is in a focus of the ellipse.

The correct answer is ii) It must revolve around a star

The time that the rocket must fall before its engine starts is determined by calculating the time it takes for the rocket to fall to an altitude that is 1 km below the airliner's altitude (11 km).

Explanation:Initially, the rocket is dropped from an altitude of 12 km above sea level. There is no initial velocity because the airliner is flying at a constant speed in a straight line.The acceleration due to gravity is 9.8 m/s² and is directed vertically downwards. Hence, the acceleration in the horizontal direction is zero and the acceleration in the vertical direction is given by a = 9.8 m/s².The velocity of the rocket after it has fallen for time t is given by:v = u + atwhereu is the initial velocity, which is zero, and a is the acceleration due to gravity, which is directed vertically downwards. Substituting the values,v = 0 + (9.8 m/s²)t = 9.8t

The displacement of the rocket after it has fallen for time t is given by:s = ut + 1/2 at²whereu is the initial velocity, which is zero, and a is the acceleration due to gravity, which is directed vertically downwards. Substituting the values,s = 0 + 1/2 (9.8 m/s²)t² = 4.9t²The rocket should be at least 1 km in front of the airliner when it climbs through the airliner's altitude, which is 12 km. Therefore, the rocket must fall to an altitude of 11 km before its engine starts. Substituting s = 11 km = 11000 m in the equation for displacement,11000 m = 4.9t²Rearranging to find t,t = sqrt(11000/4.9) = 48.9 sHence, the minimum time that the rocket must fall before its engine starts is 48.9 s.

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To determine the minimum fall time before the rocket's engine starts, we use kinematic equations for the falling and accelerating phases. The rocket takes approximately 15.6 seconds to fall to the airliner's altitude and another 28.7 seconds to reach it again after accelerating. Thus, the minimum fall time is approximately 44.3 seconds.

To determine the minimum time that the rocket must fall before its engine starts, we can break down the motion of the rocket into two phases: the falling phase and the accelerating phase. In the falling phase, the rocket experiences only gravity, and in the accelerating phase, the rocket experiences both gravity and thrust. We'll use kinematic equations to solve for the time it takes for the rocket to reach the airliner's altitude.

In the falling phase, the rocket falls for a time t1 until it reaches the airliner's altitude of 12.0 km. We can use the equation d = (1/2)gt2 to find the time it takes to fall that distance. Since the rocket starts from rest, the equation simplifies to 12.0 km = (1/2)(9.8 m/s2)t12. Solving for t1, we find that it takes approximately 15.6 seconds for the rocket to fall to the airliner's altitude.

In the accelerating phase, the rocket's acceleration can be represented as a vector quantity with magnitude 3.00g and an angle of 30.0° above the horizontal. We can use the equation d = v0t + (1/2)at2, where d represents the horizontal displacement of the rocket, v0 is the initial horizontal velocity of the rocket, a is the horizontal acceleration of the rocket, and t represents the time it takes for the rocket to reach the airliner's altitude again. We know that the rocket must be at least 1.00 km in front of the airliner, so d = 1.00 km = 1000 m. We also know that the initial horizontal velocity of the rocket is the same as the airliner's velocity, so v0 = 850 km/h = 236.11 m/s. Setting a = 3.00g cos(30.0°), we can solve for t. Plugging in the known values, we find that it takes approximately 28.7 seconds for the rocket to reach the airliner's altitude again.

Therefore, the minimum time that the rocket must fall before its engine starts is the sum of the falling phase time and the accelerating phase time, which is approximately t1 + t = 15.6 s + 28.7 s = 44.3 seconds.

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Ionisation: the loss or gain of an electron

It is dangerous because cells that have been ionised can either die, or can mutate incorrectly, which might cause cancer.

Answer:

0.018 cm

Explanation:

The increase in length can be calculated using the formula:

ΔL = α * L * ΔT

where ΔL is the increase in length, α is the linear expansivity of iron, L is the original length of the rod, and ΔT is the change in temperature.

Plugging in the values, we get:

ΔL = 1.2 x 10^-5 * 30 * 50

ΔL = 0.018 cm

So, the iron rod increases in length by 0.018 cm when heated through 50 Kelvin.

Answer:

3.6 kg*m^2/s

Explanation:

The angular momentum equals mvr, where m is the mass, v is the velocity, and r is the radius or rotational arm. Inputting these values, we can find the angular momentum.

Angular momentum = (1.5 kg)(3.0 m/s)(0.8 m) = 3.6 kg*m^2/s

I hope this helps! :)

Answer:

3.6 kg is the answer

Explanation:

becuase 8/3 = 3.6

Answer:

\(2000kg\)

Explanation:

Kinetic Energy Equation: \(KE = (mv^2)/2\)

KE: Kinetic energy of the object

m: Mass of the object

v: Velocity of the object

\(400000=(m*20^2)/2\)

\(800000=400m\)

\(m=2000kg\)

Explanation:

The third class lever cannot magnify our force because in third class lever the effort it between the load and the fulcrum. Also, in this type of lever no matter where the force is applied, it is always greater than the force of load. Hence, That type of lever cannot magnify our force.

Answer:

c. hope this helped

Explanation:

Answer: A. 25%

Explanation: Ap3x

The ratio of the potentials of these surfaces is 1.2,

Option choice C is correct.

The potential at any point on an equipotential surface is constant.

Since both spheres are equipotential surfaces, the potential at the center of sphere A is equal to the potential at any point on sphere A, and likewise for sphere B.
The potential at the center of sphere A due to the point charge is given by the formula

V = kq/r,

where k is the Coulomb constant,

q is the charge,

and r is the distance from the charge to the point.

In this case,

V = kq/RA.
The potential at the center of sphere B due to the point charge is given by the same formula,

but with r = RB.

So V = kq/RB.
Taking the ratio of these two potentials, we get:
VA/VB = (kq/RA)/(kq/RB)
VA/VB = (RB/RA)
VA/VB = 0.0012/0.0010
VA/VB = 1.2.

Option choice C is correct.

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