Which statement is false?
A. Every rational number is also an integer.
B. No rational number is irrational.
C. Every integer is also a rational number.
D. Every irrational number is also real.

Answer:

0%

Step-by-step explanation:

ITS A CUBE BRUH!!!!

Answer:

Using the distributive property. (Answer is n = 3).

Step-by-step explanation:

3(5n - 7) = 24

Solve it by multiplying the 3 and 5, and the 3 and 7, to make it:

15n - 21 = 24

Then, solve the rest of it.

15n -21 + 21 = 24 + 21

15n = 45

15n divided by 15 = 45 divided by 15

n = 3

Answer:

Below!

Step-by-step explanation:

The best way to solve this equation is to use distributive property to simplify the LHS. Once simplified, isolate the variable. Once isolated, divide both sides (If needed). Once divided, your result will be nice and clear. Please seek below for solution of the problem.

Hello !

Answer:

\(\boxed{\sf x = \frac{1}{ log(8) } }\)

Step-by-step explanation:

We want to find the value of x that verifies the following equation :

\(\sf 3xlog 2+log(8^x)=2\)

Let's remember :

\(\sf log( {x}^{a} ) = a \times log(x) \)

We can apply this property to our equation :

\(\sf 3x log(2 ) + x log(8) = 2\)

Let's factor the left side by x :

\(\sf x(3 log(2) + log(8) ) = 2\)

We can apply the previous property to put the 3 as an exponent in the log

\(\sf x(log( {2}^{3} ) + log(8) ) = 2 \\ x( log(8 ) + log(8) ) = 2 \\ 2x log(8) = 2\)

Let's divide both sides by 2 :

\(\sf x log(8) =1\)

Finally, let's divide both sides by log(8) :

\(\boxed{\sf x = \frac{1}{ log(8) } }\)

Have a nice day ;)

Hello, I Am BrotherEye

Answer: Here is an Example On How To Solve Your Problem.

Step-by-step explanation:

Explanation:

29

,

33

,

36

,

37

,

39

,

40

,

41

The minimum is the lowest number in the data set.

Since it is listed from smallest to largest, we know that the minimum is

29

.

The median is the middle number. Cancel out

3

numbers from each side and we are left with the median:

29

,

33

,

36

,

37

,

39

,

40

,

41

Therefore, the median is

37

.

The first quartile (Q1) is the median of the lower half of data which lies at 25% of the data.

Let's look at the lower half of numbers:

29

,

33

,

36

The number in the middle is

33

, so that is the first quartile.

The third quartile (Q3) is the median of the upper half of data which lies at 75% of the data.

Let's look at the upper half of numbers:

39

,

40

,

41

The number in the middle is

40

, so that is the third quartile.

The maximum is the highest number in the data set; it is

41

.

So here's the five-number summary:

Minimum: 29

First quartile: 33

Median: 37

Third quartile: 40

Maximum: 41

The angle that has a cosine of 3/5 is: ∠A

The three main trigonometric ratios are:

sin x = opposite/hypotenuse

cos x = adjacent/hypotenuse

tan x = opposite/adjacent

The given fraction is actually 3/5. This can also be written as 6/10. Thus:

From the given triangle, we can say that:

cos A = 6/10

Thus, it represents angle A.

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The value of the car loan payments today is $4810.27.

The monthly payment is $315.

The number of payments is 3 years * 12 months/year = 36 payments.

The annual interest rate is 5.64%.

To calculate the present value of the car loan payments, we can use the following formula:

present value = monthly payment * (1 - (1 + interest rate)**-number of payments) / interest rate

Plugging in the values for the monthly payment, number of payments, and interest rate, we get:

present value = 315 * (1 - (1 + 0.0564)**-36) / 0.0564 = 4810.27

Therefore, the value of the car loan payments today is $4810.27.

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The roots of the quadratic equation 0 = 2x² + 12x-14 is (C) x=-7 and x=1.

Any equation in algebra that can be written in the standard form where x stands for an unknown value and a, b, and c stand for known values is said to be a quadratic equation.

In general, it is assumed that a > 0; equations with a = 0 are regarded as degenerate since they become linear or even simpler.

So, the roots of 0 = 2x² + 12x-14 are:

2x² + 12x-14  = 0

2x² + 14x - 2x -14

2x(x + 7) - 2(x + 7)

(2x - 2) (x + 7)

Now, use the zero product property as follows:

2x - 2 = 0

2x = 2

x = 2/2

x = 1

And

x + 7 = 0

x = -7

Therefore, the roots of the quadratic equation 0 = 2x² + 12x-14 is (C) x = -7 and x = 1.

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Correct question:

What are the roots of the quadratic equation 0 = 2x² + 12x-14?

a. 1,6, -7

b. 2,12,-14

c. -7,1

d. -1,7

Answer:

False

Step-by-step explanation:

Answer:

Step-by-step explanation:

y = -3x / 4 + 9

Answer:

hi! this is (insert your name) what does this sybol/mathematical term mean?

√

Step-by-step explanation:

Answer:

Below

Step-by-step explanation:

Greetings Mrs.(name here)!

I got my recent test back and I was wondering why this question was incorrect.

For #4, I was sure that you had to find the square root and then multiply by pi, but apparently that's not what some people did and they got it correct.

How do I properly do this question?

-*name here*

If an equation defines a function over its implied domain, then the graph of the equation must pass the vertical line test.

The vertical line test is a criterion used to determine if a graph represents a function. It states that if a vertical line intersects the graph of the equation at more than one point, then the equation does not define a function. In other words, for every x-value in the domain, there can only be one corresponding y-value.

By applying the vertical line test, we can visually inspect the graph of the equation and determine if it represents a function. If no vertical line intersects the graph at more than one point, then the equation defines a function.

This test is based on the concept that a function relates each input value (x) to a unique output value (y). If there are multiple y-values corresponding to a single x-value, then there is ambiguity in the relationship, and the equation does not satisfy the criteria of a function.

Therefore, passing the vertical line test is an essential requirement for an equation to define a function over its implied domain. It ensures that each input value has a unique output value, providing a clear and unambiguous relationship between the variables.

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Using the binomial distribution, the mean number of balls you would expect him to catch is of 7.2.

It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

For this problem, the parameters are:

n = 8, p = 0.9.

Hence the mean is:

E(X) = np = 8 x 0.9 = 7.2.

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Answer:

25quarts of grape juice, 50 quarts of water

Step-by-step explanation:

Do the math

Answer:

You'd need 50 quarts of sparkling water and 25 quarts of grape juice

Step-by-step explanation:

You can make an equation with this.

\(75=4/6x+3/4x\)

When you solve for this, you'll get 100/3.

You can then substitute x for 100/3 and get the numbers.

Answer:

im not sure but here u go 85x+60

If one of the longer sides of the Isosceles triangle is 6.3 centimeters, the length of the base is 3.1 centimeters.

Let's solve the problem step by step:

1. Identify the given information:

  - The triangle is isosceles, meaning it has two equal sides.

  - The two equal sides, labeled "a," are longer than the base, labeled "b."

  - The perimeter of the triangle is 15.7 centimeters.

  - One of the longer sides is 6.3 centimeters.

2. Set up the equation based on the given information:

  Since the triangle is isosceles, the sum of the lengths of the two equal sides is twice the length of the base. Therefore, we can write the equation:

  2a + b = 15.7

3. Substitute the known value into the equation:

  One of the longer sides is given as 6.3 centimeters, so we can substitute it into the equation:

  2(6.3) + b = 15.7

4. Simplify and solve the equation:

  12.6 + b = 15.7

  Subtract 12.6 from both sides:

  b = 15.7 - 12.6

  b = 3.1

5. Interpret the result:

  The length of the base, labeled "b," is found to be 3.1 centimeters.

Therefore, if one of the longer sides of the isosceles triangle is 6.3 centimeters, the length of the base is 3.1 centimeters.

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Ai) 5575 Swedish kronor      500*11.15

Aii) 312.50 swiss frans      250*1.25

B) £345     407.10/1.18

Hope this helps, have a great day!!

aggreed very mean.....

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The volume of fuel the first car used is 5.25 litres

A ratio is a comparison of two similar quantities. Given any two similar quantities a and b, the ratio of a to b that is a:b is defined as a:b = a/b, where b≠0. Percentage means 'by the hundred' or 'divide by one hundred'. The percentage is also used to compare quantities, which means 'per 100.

91 litres of fuel is shared in ratio 6:7

the first car will have 6/13× 91 = 42 litres

This means the first car has 42 litres of fuel.

The first car used 12.5% out of 42 litres = 12.5/100 × 42 = 5.25litres.

Therefore the first car used 5.25 litres of fuel on the journey.

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To find the length of the graph of f(x)=ln(4sec(x)) for 0≤x≤π/3, we first need to compute the derivative of the function.

f(x) = ln(4sec(x))
f'(x) = (1/sec(x)) * (4sec(x)) * tan(x) = 4tan(x)
Next, we use the arc length formula:
L = ∫ [a,b] √[1 + (f'(x))^2] dx
Substituting in the values, we get:
L = ∫ [0,π/3] √[1 + (4tan(x))^2] dx
We can simplify this by using the identity 1 + tan^2(x) = sec^2(x):
L = ∫ [0,π/3] √[1 + (4tan(x))^2] dx
 = ∫ [0,π/3] √[1 + 16tan^2(x)] dx
 = ∫ [0,π/3] √[sec^2(x) + 16] dx
 = ∫ [0,π/3] √[(1 + 15cos^2(x))] dx
 = ∫ [0,π/3] √15cos^2(x) + 1 dx
Using the substitution u = cos(x), we get:
L = ∫ [0,1] √(15u^2 + 1) du
This can be solved using trigonometric substitution, but the details are beyond the scope of this answer. The final result is:
L = 4/3 * √(15) * sinh^(-1)(√15/4) - √15/2
Therefore, the length of the graph of f(x)=ln(4sec(x)) for 0≤x≤π/3 is approximately 3.195 units.

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The hypotheses for the test are H₀: σ₁² = σ₂² and H₁: σ₁² ≠ σ₂². This is a two-tailed test to assess if there is a difference in the standard deviations of sound levels between the areas designated as "casualty doors" and operating theaters. The claim being investigated is whether or not there is a difference in the standard deviations.

The hypotheses for the test are:

H₀: σ₁² = σ₂² (There is no difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

H₁: σ₁² ≠ σ₂² (There is a difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

This hypothesis test is a two-tailed test because the alternative hypothesis is not specifying a direction of difference.

To substantiate the claim that there is a difference in the standard deviations, we will conduct a two-sample F-test at a significance level of 0.10, comparing the variances of the two groups.

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Step-by-step explanation:

v = u + at

v-u = at

a = (v -u)/t

When t = 4, u=10, v=50

a = (50-10)/4

a= 40/4

a = 10

The value of the integral is \(&\frac{1}{4} \ln |x|+\frac{9}{8} \ln |x+2|+\frac{11}{8} \ln |x-2|+C\).

Here, we have,

Let us use the method of partial fractions to integrate the following integral:

\(\[\int\frac{2x^2-x-1}{x^3-4x}dx\]\)

Partial fraction decomposition is a method of rewriting a fraction so that it is easier to integrate.

To do so, we need to rewrite the denominator.

So, let us begin with that.

\(\[x^3-4x=x(x^2-4)=x(x+2)(x-2)\]\)

Thus, we can write the given fraction as follows:

\(\[\frac{2x^2-x-1}{x(x+2)(x-2)}\)

\(=\frac{A}{x}+\frac{B}{x+2}+\frac{C}{x-2}\]\)

Next, we multiply both sides of the equation by the common denominator, to get:

\(\[2x^2-x-1=A(x+2)(x-2)+Bx(x-2)+C(x)(x+2)\]\)

Let us now substitute values of x in the above equation so that we can determine the values of A, B, and C.

We can substitute x = 0, x = -2, and x = 2, as they make the other terms in the equation equal to zero as well.

Substituting This reduces to: \(\[-1=-4A\]\)

Thus, we can find A as follows: \(\[A=\frac{1}{4}\]\)

Substituting \(x = -2,\[2(-2)^2-(-2)-1\)

\(=A(-2+2)(-2-2)+B(-2)(-2-2)+C(-2)(-2+2)\]\)

This reduces to :\(\[9=8B\]\)

Thus, we can find B as follows:

\(\[B=\frac{9}{8}\]\)

Substituting \(x = 2,\[2(2)^2-(2)-1=A(2+2)(2-2)+B(2)(2-2)+C(2)(2+2)\]\)

This reduces to:\(\[11=8C\]\)

Thus, we can find C as follows:\(\[C=\frac{11}{8}\]\)

Thus, we can now integrate the given fraction by substituting the values of A, B, and C as we have found:

\(\int \frac{2 x^{2}-x-1}{x^{3}-4 x} d x\)

\(=\frac{1}{4} \int \frac{1}{x} d x+\frac{9}{8} \int \frac{1}{x+2} d x+\frac{11}{8} \int \frac{1}{x-2} d x \\ &\)

\(=\frac{1}{4} \ln |x|+\frac{9}{8} \ln |x+2|+\frac{11}{8} \ln |x-2|+C \end{aligned}\]\)

Therefore, the value of the integral is \(&\frac{1}{4} \ln |x|+\frac{9}{8} \ln |x+2|+\frac{11}{8} \ln |x-2|+C\).

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complete question:

Find the value of the integral:

\(\[\int\frac{2x^2-x-1}{x^3-4x}dx\]\)

Answer:

the length of one side is 120

Step-by-step explanation:

let the length = x

we need to form an equation to find the side...

since its 10 per metre

10x = 1200

x = 1200/10

x=120

hope it helped !