Which statement describes chemical properties?
A. Characteristics that can change without changing the substance
B. Characteristics that can change when the state of the substance
changes
C. Characteristics that describe the ability of a substance to form a
new substance
D. Characteristics that describe what chemical a substance is made
up of
QQ

Answer:

3

Explanation:

Answer:

Potassium

1s2 2s2 2p6 3s2 3p6 4s1

Explanation:

The atom having only one electron its outermost shell must belong to an element in group one of the periodic table.

Having noted that, we proceed to find out what element in group one that has the atom just described in the question.

That atom must belong to an element in the fourth period. The only group 1 element in the fourth period is potassium.

The electron configuration of potassium is;

1s2 2s2 2p6 3s2 3p6 4s1

Answer:

5867ml is the answer to 5.867L to ml

Answer: they are the same because they both convert and deal with thermal energy because it’s not created or destroyed

Explanation:

71 g of Na2SO4 is produced if 49 gram of H2SO4 reacts with 80 gram of NaOH

Given that;

Mass of Na2SO4 is 49 gram

Mass of NaOH is 80 gram

To find number of mol we have to find molar mass of each element ;

Molar mass of Na2SO4 = 98 g/mol

Molar mass of NaOH = 40 g/mol

So, Number of mol(n) of Na2SO4 = 49/98

     n(Na2SO4) = 0.5 mol of H2SO4

Number of mol(n) of NaOH = 80/40

n(NaOH) = 2 moles of NaOH

According to the balanced chemical reaction ; H2SO4 + 2 NaOH –––> Na2SO4 + 2 H2O one mol of H2SO4 react with 2 mol of NaOH to form 1 mol of Na2SO4, same as 0.5 mol of H2SO4 react with 1 mol of NaOH to form 0.5 mol Na2SO4

H2SO4 + 2 NaOH –––> Na2SO4 + 2 H2O

(1) .. .. .. .. (2) .. .. .. .. .. .. (1) .. .. Then,

(0.5) .. .. .. (1) .. .. .. .. .. .. (0.5)

H2SO4 is the limiting and NaOH is the excess reagent.

So,0.5 mol of Na2SO4 is formed .

Mass of Na2SO4 = mol of Na2SO4 × molar mass of Na2SO4

Mass of Na2SO4 = 0.5 × 142

Mass of Na2SO4 =  71 g of Na2SO4

So,  71 g of Na2SO4 will produced

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Answer:

The rocks contain iron that points in the direction the rocks move away from the ridge.

Answer:

Boron and argon have 3 and 8 valence electrons respectively.

Aluminum and calcium have 3 and 2 valence electrons respectively.

Explanation:

Please give the brainliest.

The 500 kcal meal consists of 150 kcal from protein, 250 kcal from carbohydrates, and 100 kcal from fat.

To calculate the grams of each macronutrient in the meal, we need to convert the percentage of each macronutrient to its respective calorie contribution.

For protein:

30% of 500 kcal = 0.30 * 500 = 150 kcal

Since protein provides 4 kcal per gram, the protein content can be calculated as:

150 kcal / 4 kcal/gram = 37.5 grams of protein.

For carbohydrates:

50% of 500 kcal = 0.50 * 500 = 250 kcal

Since carbohydrates also provide 4 kcal per gram, the carbohydrate content can be calculated as:

250 kcal / 4 kcal/gram = 62.5 grams of carbohydrates.

For fat:

20% of 500 kcal = 0.20 * 500 = 100 kcal

Since fat provides 9 kcal per gram, the fat content can be calculated as:

100 kcal / 9 kcal/gram ≈ 11.1 grams of fat.

In summary, the 500 kcal meal consists of approximately 37.5 grams of protein, 62.5 grams of carbohydrates, and 11.1 grams of fat.

To calculate the grams of each macronutrient, we need to convert the percentage into calories for each component. The 500 kcal meal is composed of 30% protein, 50% carbohydrates, and 20% fat.

For protein, we multiply the total calorie content (500 kcal) by the protein percentage (30%):

30% * 500 kcal = 0.30 * 500 kcal = 150 kcal

Since 1 gram of protein provides 4 calories, we divide the protein calorie content by 4:

150 kcal / 4 kcal/gram = 37.5 grams of protein.

For carbohydrates, we perform a similar calculation:

50% * 500 kcal = 0.50 * 500 kcal = 250 kcal

250 kcal / 4 kcal/gram = 62.5 grams of carbohydrates.

Finally, for fat:

20% * 500 kcal = 0.20 * 500 kcal = 100 kcal

100 kcal / 9 kcal/gram ≈ 11.1 grams of fat.

In summary, the 500 kcal meal contains approximately 37.5 grams of protein, 62.5 grams of carbohydrates, and 11.1 grams of fat.

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When 2 mole of Fe2O3 and 9 molecules of CO react, 6 moles of the each product are created.

The term "mole" refers to a common scientific measurement unit for atoms, molecules, and other very small particles.

The first one is supposed to produce a balanced chemical reaction in accordance with the situation supplied.

FeO3 + 3 CO 2 Fe + 3CO2 is the formula.

Because 2 moles of Fe2O3 reacted with 3 x2=6 moles of Co to produce Fe and CO2, CO was in excess and Fe2O3 was the limiting reagent.

Utilize the mole ratio to determine the moles of the each product.

That is the Fe2O3 mole ratio: Because Fe is a 1:2 element, the mole of Fe is 2x2=4 moles.

Because the mole ratio of Fe2CO3 to CO2 is 1:3, the moles of Co2 are 2 x 3 = 6 moles.

Therefore, 6 moles of the each product will be created when 2 moles or Fe2O3 react to 9 moles of CO.

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The electrochemistry underlying the electrical current in a neuron as it is stimulated involves sodium channels opening to allow sodium to enter the cell.
2. The most fundamental variable that can likely explain the evolution of bigger brains is the overall ecological complexity that the animal deals with.

During neuron stimulation, an action potential is generated. This process involves the depolarization of the neuron's membrane, which is achieved by the influx of positively charged ions, primarily sodium ions (Na+). When a neuron is stimulated, voltage-gated sodium channels in the cell membrane open, allowing sodium ions to rapidly enter the cell. This influx of positive charge depolarizes the membrane, creating an electrical current that propagates along the neuron.

Regarding the second question, the most fundamental variable that can likely explain the evolution of bigger brains is the overall ecological complexity that the animal deals with. Animals that inhabit complex and challenging environments often require enhanced cognitive abilities to navigate and respond to their surroundings effectively. The ecological complexity, such as varied food sources, social interactions, and environmental stimuli, can drive the evolutionary pressure for larger brain size and increased cognitive capacity. While factors like diet, sociality, and mating strategies may play a role, the overall ecological complexity is considered a crucial determinant of brain evolution.


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The cell notation for the given electrochemical cell can be represented as follows: Pt | Cr2 (aq) || H+ (aq) | Pt . In this notation, the left-hand side represents the anode compartment where Cr2 (aq) is oxidized to Cr3 (aq) at a platinum electrode.

The single vertical line represents the phase boundary between the two half-cells. The right-hand side represents the cathode compartment where H+ (aq) is reduced to H2(g) at a platinum electrode.

It is important to note that the cell notation also includes the standard conditions for concentration and pressure. In this case, the aqueous solutions have a concentration of 1 mol/l and the gases have a pressure of 1 bar. These conditions are usually mentioned to ensure the standardization and comparability of electrochemical cell measurements.

Furthermore, the cell notation also provides information on the direction of the electron flow, which is from the anode to the cathode. The pressure and concentration values can also affect the direction and magnitude of the cell potential and can impact the overall performance of the electrochemical cell.

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Rusting is the common name for the corrosion of iron or steel. The chemical name of rust is iron oxide, particularly iron (III) oxide.

Rust is the reddish-brown coating that often appears on certain types of metal. Rust forms when these metals are exposed to moisture and air. This combination causes a chemical reaction, producing the red substance.

The chemical name for rust is iron oxide, with the chemical formula Fe2O3. Iron or alloys that contain iron (such as steel) are metals that become rusty. When iron comes into contact with both water and oxygen in the air, a chemical reaction occurs over a period of time. This reaction forms a new compound that is iron oxide. Iron oxide is found in nature and is also abundant on Mars, giving it its reddish colour.

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Answer:

\(-3.06\) is the overall voltage produced

Explanation:

Potassium and Tin are connected in an electrochemical series.

In a series circuit, the resultant voltage is equal to the sum of voltage drops at all points in the circuit.

Here,

The voltage drop at potassium \(= -2.92\)

The voltage drop at Tin \(= -0.14\)

The net voltage

\(= -2.92 -0.14 \\= -3.06\)

The Ka for the acid HA is approximately 7.39×10⁻⁹. This value represents the acid dissociation constant, which is a measure of the strength of the acid. A lower Ka value indicates a weaker acid.

The Ka for an acid HA can be calculated using the given equilibrium concentrations of HA, H3O+, and A-. In this case, the equilibrium concentrations are [HA]=1.3 M, [H3O+]=9.8×10⁻⁵ M, and [A-]=9.8×10⁻⁵  M.

To determine the Ka, we will use the expression:
Ka = ([H₃O+] × [A-]) / [HA]

Now, we will substitute the given values into the equation:
Ka = (9.8×10⁻⁵  M × 9.8×10⁻⁵  M) / (1.3 M)
Ka = (9.604×10⁻⁹ M²) / (1.3 M)
Ka = 7.388×10⁻⁹

Therefore, the Ka for the acid HA is approximately 7.39×10⁻⁹. This value represents the acid dissociation constant, which is a measure of the strength of the acid. A lower Ka value indicates a weaker acid, while a higher Ka value indicates a stronger acid.

In this case, the Ka of 7.39×10⁻⁹ suggests that the acid HA is a weak acid, as it has a relatively low dissociation constant.

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Answer:

0.0307

Explanation:

Let us consider the ionization of this acid in water:HA(aq)+H2O(l)↽−−⇀H3O+(aq)+A−(aq)The equilibrium constant expression for this reaction is as follows: Ka=[H3O+][A−][HA]. given the concentrations of each of these species, so we simply plug them in (minus the units, as the equilibrium constant is unitless). Ka=(0.225)(0.225)1.65=0.0307

The nuclear fission of U-235 is a process of radioactive decay in which the heavy nucleus of Uranium-235 which absorbs a neutron first and then it ultimately converts into a an unstable nucleus of Uranium-236 which eventually bifurcates into the lighter elements and additional neutrons.

One of the fissile isotopes that undergo an important and crucial nuclear fission reactions is U-235 which in turn forms a chain reaction. A nuclear fission can be defined as a process of radioactive decay where a heavier nucleus splits further into the two or more lighter elements by absorbing a neutron and releasing its multiples along with great amount of energy.

Taking up the example of Uranium-235, when it's bombarded with small neutrons, the nucleus of U-235 absorbs one of them and turns to heavier U-236 which remains unstable for an infinitesimal time. This U-236, undergoes a phase where fission occurs and it releases three neutrons and produce Kr-92 and Ba-141 along with enormous amount of energy and gamma rays.

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Answer:

antimony

Explanation:

it has 51 protons, 4 more than silver and two less than xenon

If 162.35 g aluminum hydroxide are dissolved in 6750 mL of solution, the concentration of the solution is 0.308M

The concentration of a solution can be calculated using the following formula:

Molarity = no of moles ÷ volume (L)

However, the number of moles in 162.35g of Al(OH)3 must be calculated as follows:

Molar mass of Al(OH)3 = 78g/mol

no of moles = 162.35g ÷ 78mol

no of moles = 2.08mol

Molarity = 2.08mol ÷ 6.75L

Molarity = 0.308M

Therefore, if 162.35 g aluminum hydroxide are dissolved in 6750 mL of solution, the concentration of the solution is 0.308M.

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(a)

pH = 4.77

; (b)

[

H

3

O

+

]

=

1.00

×

10

-4

l

mol/dm

3

; (c)

[

A

-

]

=

0.16 mol⋅dm

-3

Explanation:

(a) pH of aspirin solution

Let's write the chemical equation as

m

m

m

m

m

m

m

m

l

HA

m

+

m

H

2

O

⇌

H

3

O

+

m

+

m

l

A

-

I/mol⋅dm

-3

:

m

m

0.05

m

m

m

m

m

m

m

m

l

0

m

m

m

m

m

l

l

0

C/mol⋅dm

-3

:

m

m

l

-

x

m

m

m

m

m

m

m

m

+

x

m

l

m

m

m

l

+

x

E/mol⋅dm

-3

:

m

0.05 -

l

x

m

m

m

m

m

m

m

l

x

m

m

x

m

m

m

x

K

a

=

[

H

3

O

+

]

[

A

-

]

[

HA

]

=

x

2

0.05 -

l

x

=

3.27

×

10

-4

Check for negligibility

0.05

3.27

×

10

-4

=

153

<

400

∴

x

is not less than 5 % of the initial concentration of

[

HA

]

.

We cannot ignore it in comparison with 0.05, so we must solve a quadratic.

Then

x

2

0.05

−

x

=

3.27

×

10

-4

x

2

=

3.27

×

10

-4

(

0.05

−

x

)

=

1.635

×

10

-5

−

3.27

×

10

-4

x

x

2

+

3.27

×

10

-4

x

−

1.635

×

10

-5

=

0

x

=

1.68

×

10

-5

[

H

3

O

+

]

=

x

l

mol/L

=

1.68

×

10

-5

l

mol/L

pH

=

-log

[

H

3

O

+

]

=

-log

(

1.68

×

10

-5

)

=

4.77

(b)

[

H

3

O

+

]

at pH 4

[

H

3

O

+

]

=

10

-pH

l

mol/L

=

1.00

×

10

-4

l

mol/L

(c) Concentration of

A

-

in the buffer

We can now use the Henderson-Hasselbalch equation to calculate the

[

A

-

]

.

pH

=

p

K

a

+

log

(

[

A

-

]

[

HA

]

)

4.00

=

−

log

(

3.27

×

10

-4

)

+

log

(

[

A

-

]

0.05

)

=

3.49

+

log

(

[

A

-

]

0.05

)

log

(

[

A

-

]

0.05

)

=

4.00 - 3.49

=

0.51

[

A

-

]

0.05

=

10

0.51

=

3.24

[

A

-

]

=

0.05

×

3.24

=

0.16

The concentration of

A

-

in the buffer is 0.16 mol/L.

hope this helps :)

The equilibrium constant of this reaction is 1.80×10-5

Given data,

pH of solution = 2.873

Number of moles of acetic acid (m) = 0.05 moles

Volume of water (V) =  500 mL = 0.5L

So, concentration (C) = m/V in lit = 0.05/0.5 = 0.1 M

Equilibrium constant ( K ) = \([CH_{3} COO-]\)×\([H+_{} ]\)/\([CH_{3} COOH]\)

Since, acetic acid is weak acid,

So, Equilibrium constant ( K ) = \([H+]^{2}\)/\([CH_{3} COOH]\)   ....(i)

As the pH = 2.873, the \([H+_{} ]\) is antilog of -2.873 or 1.34×10-3 M.

Putting the value of concentration of \(H+_{}\) and \(acetic_{} acid\) in equation (i).

Equilibrium constant ( K ) = 1.80×10-5

The acid which is partially dissociates into ions on dissolving in aqueous solution is called weak acid.

Example: \(acetic_{} acid\).

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The atomic number of rubidium is 37, it means that its electron configuration is as follows:

Rubidium is an alkali metal. Its ion is formed when it loses an electron. It means that the rubidium ion has 36 electrons instead of 37, and its configuration is as follows:

3H₂(g)+N₂(g)——> 2NH₃ (g) , here the volume of NH₃(g) measured at STP is produced when 2.15 L of H₂(g) reacts is approximately 1.58 L of NH₃ gas will be produced when 2.15 L of H₂ reacts at STP.

3H₂(g) + N₂(g) → 2NH₃ (g)

3 moles of H₂ reacts to produce 2 moles of NH3. Therefore, one need to first calculate the number of moles of H₂ in 2.15 L.

PV = nRT

P= is the pressure (STP has a pressure of 1 atm), V =is the volume in liters, n is the number of moles, R= is the ideal gas constant (0.0821 L·atm/mol·K), T =is the temperature in Kelvin (STP has a temperature of 273 K).

Here, 

n(H₂) = (P(H₂) × V(H₂)) / (R × T)

Assuming the pressure of H₂ is also 1 atm at STP, and substituting the values:

n(H₂) = (1 atm × 2.15 L) / (0.0821 L·atm/mol·K × 273 K) n(H₂) ≈ 0.0954 mol

According to the balanced equation, 3 moles of H₂ react to produce 2 moles of NH3. Therefore, one can determine the number of moles of NH₃ produced:

n(NH₃ ) = (2/3) × n(H₂) n(NH₃ )

≈ (2/3) × 0.0954 mol n(NH₃ )

≈ 0.0636 mol

V(NH₃ ) = (n(NH₃  × R × T) / P(STP)

Substituting the values:

V(NH₃ ) = (0.0636 mol × 0.0821 L·atm/mol·K × 273 K) / (1 atm) V(NH₃ )

≈ 1.58 L

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If 30 ml of a 0.80 m solution of k is mixed with 50 ml of a 0.45 m solution of clo−4, a precipitate will be observed in this solution.

The solution contains k (potassium) and clo−4 (chlorate) ions and we are to find out if a precipitate will form or not. The ksp for the following equilibrium is 0.004. kclo4(s)↽−−⇀k (aq) clo−4(aq)

We can obtain the molarity of k ions as follows: 0.80 M = (moles of K)/(0.030 L)Moles of K = 0.80 M × 0.030 L = 0.024 mol

We can obtain the molarity of clo−4 ions as follows: 0.45 M = (moles of clo−4)/(0.050 L)Moles of clo−4 = 0.45 M × 0.050 L = 0.0225 mol

The concentration of K and clo−4 ions are 0.8 M and 0.45 M respectively. Now, we need to calculate the reaction quotient Q of the solution to find out whether the precipitate will form or not. Q = [K+][clo−4] = 0.8 M × 0.45 M = 0.36

Since Q (0.36) > Ksp (0.004), the reaction quotient is greater than the solubility product constant. It indicates that the product is more than what it should be. The excess products will precipitate to form a solid. Hence, we can say that a precipitate will be observed in this solution.

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Eating fewer processed foods would promote the development of more-sustainable practices in the world food system.

This is the food which has undergone some degree of alteration during preparation such addition of preservatives etc.

Eating less of it will ensure that more sustainable practices in the world food system are promoted.

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false, the rusting of iron can be prevented by painting, oiling, greasing or varnishing its surface.

Answer:

Answer is: elements in the same group have similar chemical properties. Periodic law is the arrangement of the elements in order of increasing atomic number.

Based on the complete question, Thermolysin yields the maximum number of fragments with 9 fragments while endo peptidase yields the fewest 2 fragments

In biochemistry and biotechnology, thermolysin is frequently utilized for protein digestion and peptide synthesis. It is an important tool for researching protein structure and function because of its capacity to cleave proteins at precise places.

Thermolysin is also helpful in industrial settings including food processing and pharmaceutical manufacture due to its great temperature stability.

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The chemical in the catabolism of glucose that enters the mitochondria is pyruvat.

In the catabolism of glucose, the process begins with glycolysis, which takes place in the cytoplasm of the cell. During glycolysis, glucose is broken down into two molecules of pyruvate through a series of enzymatic reactions. Pyruvate is a three-carbon compound (C₃H₄O₃) and serves as an intermediate product in glucose metabolism.

After glycolysis, if oxygen is available, pyruvate enters the mitochondria, where further oxidation occurs through a process called aerobic respiration. In the mitochondria, pyruvate undergoes decarboxylation, producing acetyl CoA, which then enters the citric acid cycle (also known as the Krebs cycle). The citric acid cycle generates high-energy electrons, which are then used in the electron transport chain to produce ATP through oxidative phosphorylation.

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The concentration of CO (g) in the equilibrium mixture is 0.020 M. In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.

The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.

Given that the concentration of H2O (g) is [H2O] = 0.500 M at 1000°C, and  the reaction is:

C(s) + H2O(g) ⇄ CO(g) + H2(g) KC = 0.2 at 1000°C

We need to determine the concentration of CO in an equilibrium mixture (in mol/L)

if a reaction mixture initially contains only reactants.

We can solve this problem using the ICE table method as follows:

Let x be the change in concentration of H2O (g) and CO (g) when they reach equilibrium.

Then the equilibrium concentrations of CO (g) and H2 (g) are equal to x. Hence, the equilibrium concentration of H2O (g) is (0.500 - x) M. Substitute these values in the expression for Kc and solve for x.

Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]

= 0.2[CO (g)] = Kc [H2O (g)] [C (s)] / [H2 (g)]

= 0.2 × (0.500 - x) / x

We can simplify this expression by cross-multiplication to get:

5x = 0.1 - 0.2xx = 0.02 M

Substituting x = 0.02 M in the expression for [CO (g)], we get:

[CO (g)] = 0.2 × (0.500 - 0.02) / 0.02 = 5.8 M (approx.)

Therefore, the concentration of CO (g) in an equilibrium mixture (in mol/L) is 5.8 M.                                                                                               The problem requires us to find the equilibrium concentration of CO (g) in a mixture that initially contains only reactants.

To solve this problem, we need to use the expression for the equilibrium constant Kc, which is given by:

Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]

We can also use the ICE table method to solve this problem. In this method, we start with the initial concentration of the reactants and calculate the change in concentration of each species as they reach equilibrium.

We then use the equilibrium concentrations to calculate the value of Kc and solve for the unknowns. Here is how we can set up the ICE table for this problem: Reaction:

C(s) + H2O(g) ⇄ CO(g) + H2(g)

Initial: [C] = [H2]

= 0 M,

[H2O] = 0.500 M

Equilibrium: [C] = [H2] = x,

[H2O] = 0.500 - x,

[CO] = [H2] = x

Change: +x +x -x -x

Substituting the equilibrium concentrations into the expression for Kc, we get:

Kc = [CO] [H2] / [H2O] [C]

= x² / (0.500 - x)

= 0.2

Solving for x, we get: x = 0.020 M

Substituting this value of x into the expression for [CO], we get:

[CO] = x = 0.020 M

Therefore, the concentration of CO (g) in the equilibrium mixture is 0.020 M.

In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.

The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.

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Answer:

The answer is lemonade.

Weaker acids are those which tend to have a higher pH from 4 to at least 6 stronger acids have low pH from 2 and below that's from 2 to 0.

Hope this helps

Hope

There are approximately 0.01582 moles of acetic acid in the given solution with a concentration of 0.743 M.

To determine the number of moles of acetic acid in the solution, we can use the formula:

moles = concentration (molarity) × volume (in liters)

First, let's convert the volume from milliliters to liters. Since 1 liter is equal to 1000 milliliters, we have:

21.33 ml = 21.33/1000 = 0.02133 L

Next, we can substitute the values into the formula:

moles = 0.743 mol/L × 0.02133 L

Calculating this expression, we find:

moles = 0.01582 mol

Therefore, there are approximately 0.01582 moles of acetic acid in the given solution with a concentration of 0.743 M.

In summary, the number of moles of acetic acid in 21.33 ml of a solution with a concentration of 0.743 M is approximately 0.01582 mol.

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Answer:  The two elements on the periodic table that may be produced in sad reactions are Oxygen and Nitrogen.

Explanation:

Both of these elements are part of the air we breathe and are required for survival, but under certain conditions, they can lead to sad reactions. Oxygen is required for respiration, but when it reacts with other substances in the body, it can lead to the production of free radicals, which can damage cells and cause mood disorders. Nitrogen is also required by the body, but when it reacts with oxygen and other substances in the air, it can lead to the formation of air pollutants, such as smog and ozone, which can also contribute to sad reactions.