Which statement contains valid syntax for the RETAIN statement?
a. retain Year 2018;
b. retain Year*2018;
c. retain Year=2018;
d. retain Year{2018};

Its True the range before you enter data saves time because it confines the movement of the active cell to the selected range .

What is data
Data is information that has been collected and organized in a meaningful way. Data can be quantitative (numbers) or qualitative (descriptive and subjective information). Data can come from surveys, experiments, observations and other sources. Data is a valuable asset and is used to inform decisions, create insights, and uncover trends and patterns. Data can be structured (structured in a way that makes it easy to search, sort, and analyze) or unstructured (not organized in a conventional way). Data can be used to identify problems, generate and test hypotheses, and measure the success of different strategies. Data is a key component of any organization and is used to help inform decisions, gain insights, and improve operations.

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Answer:

Area of the piston = 1.143 * 10^-3 m^2

Explanation:

Here, we are tasked with calculating the area of the piston.

Mathematically, the area of the piston =

Piston force/ cylinder pressure

From the question,

Piston force = mg where m is the mass of the piston = 35 kg and g is the acceleration due to gravity = 9.8 m/s^2

Thus, piston force = 35 * 9.8 = 343 N

Now the pressure gauge reads 300 KPa and 1KPa = 300 * 10^3 Pa = 300000 Pa

Thus, the area of the piston = 343/300000 =

0.001143333333 m^2 which is simply 1.143 * 10^-3 m^2

After three hours of rainfall/runoff, the mass of mud accumulated in the detention pond can be calculated by considering the flow rate and concentration of particles in the inflow water.

The concentration of particles in the creek after mixing with the overflow from the pond can be determined based on the flow rates and concentrations of the pond outflow and the ambient creek water.

To calculate the mass of mud accumulated in the detention pond after three hours of rainfall/runoff, we need to consider the flow rate and concentration of particles in the inflow water. The inflow water has a flow rate of 5.00 m^3/min and a particle concentration of 4000 mg/L. Since the rain is steady, we can assume a constant inflow rate over the three-hour period. By multiplying the inflow flow rate by the particle concentration and the duration (in minutes) of three hours, we can calculate the mass of mud accumulated in the detention pond.

To determine the concentration of particles in the creek after mixing with the overflow from the pond, we need to consider the flow rates and concentrations of the pond outflow and the ambient creek water. The pond outflow has a concentration of 400 mg/L and is a fraction of the inflow water that overflows into the creek. By adding the product of the pond outflow concentration and flow rate to the product of the ambient creek water concentration and flow rate, divided by the sum of the two flow rates, we can calculate the concentration of particles in the creek after mixing.

These calculations provide insights into the amount of mud accumulated in the pond and the resulting concentration of particles in the creek, allowing for an assessment of the effectiveness of the detention pond in mitigating pollution from soil particles in the runoff.

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The code creates a variable with internal linkage named "y" and initializes it to 1.75, and prints its value to the console when the program is run.

The code provided creates a variable named "y" with internal linkage and assigns it the value of 1.75.

The "static" keyword used before the declaration of the variable signifies that the variable will have internal linkage, meaning it will only be accessible within the same file it is declared in.

The function "memory()" is defined but is not used or called within the code, so it has no effect on the program execution.

When the program is run, it will print the value of "y" to the console using the "cout" statement. The output of the program will be:

```

The value of y is 1.75

```

Overall, the code demonstrates how to create a variable with internal linkage and use it in a program.

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In the ungrounded electrical circuits or systems, the circuit is one that is not  or do not have the connection to the grounding electrode.

An ungrounded system is known to be defined as a system that is known to be one that do not have an intentional connection to ground, and it has an exception of possibly going through potential indication or other kinds of devices.

Note that The neutral of an ungrounded system is one that is seen to be under reasonably balanced load conditions and thus it is one that is usually near to ground potential.

Hence, In the ungrounded electrical circuits or systems, the circuit is one that is not  or do not have the connection to the grounding electrode.

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Answer:

Step One: Know What Your Rocket Needs to Do. ...

Step Two: Establish Mission Parameters. ...

Step Three: Call in Experts. ...

Step Four: Start Drawing. ...

Step Five: Whittle Down the Possibilities. ...

Step Six: Pick the Best Design.

Explanation:

Hope this helps and thx for tha fwee pts

Answer:

Resistance = 3 Ω

Explanation:

As we know that, By Ohm's Law

V = IR

where

V is the voltage in volt

I is the current in amps

R is the resistance in ohm

Now,

Given that,

V = 15 volts

I = 5 amps

So,

R = V/I

  = 15/5

 = 3 Ω

⇒R = 3 Ω

The rate of heat transfer to the engine is 0.53kW

To find the rate of heat transfer, we have to know the maximum enclosed volume.

The given data are;

Let's calculate the maximum enclosed volume (Vmax):

V(max) = V(d) * n = 4 L * 6 = 24 L = 0.024 m³

The compression/expansion ratio (r):

r = V(max) / V(min) = V(max) / (0.15 * V(max)) = 1 / 0.15 = 6.67

Find the air standard efficiency (η(air standard):

γ = 1.4 (specific heat ratio for air)

\(\eta (air standard) = {1- (\frac{1}{r})^\gamma ^- ^1 }\\ \eta (air standard) = 1 - \frac{1}{6.67} ^(^0^.^4^) = 0.53\)

Let's assume a mechanical efficiency of 90% (η(mech) = 0.9)

Let's calculate the indicated power (P(ind)):

η = η(air standard * η(mech) = 0.53 * 0.9 = 0.477

P(ind) = P / η = 90 HP / 0.477 = 188.68 HP

Convert the indicated power to Watts:

P(ind) Watts = P(ind) * 745.7 = 188.68 * 745.7 = 140698.7 Watts

Calculate the rate of heat transfer (Q(in)):

Q(in) = P(ind) / (2πN)

Q(in) = P(ind) Watts / (2π * N/60)

Q(in) = P(ind) Watts / (2π * 2500/60)

Q(in) = 140698.7 / (2π * 2500/60)

Q(in) = 537.43W = 0.53kW

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Answer:

The condition in which a problem exists

Explanation:

Context is the situation surrounding information, e.g. if you don't understand a word in a passge you can look for "context clues" where you use surrounding words to infer the meaning of the unknown one

Answer:

The correct answer is C. 22.80 VDC.

The equation for calculating the voltage across a capacitor in an RC circuit in its third time constant is given by Vc = 24 x (1 - e^(-3)), where Vc is the voltage across the capacitor and 24 is the supply voltage.

Plugging these values into the equation gives us a result of 22.80 VDC.

Answer:

V = 20.6 m/s

Explanation:

Given that the temperature of the neon molecules = 356 Kelvin

Pressure = 0.9 bar

The mass number of Neon = 21.

Using the formula below

1/2 m v^2 = (3kT)/2

Where

T = temperature = 356 k

K = Bolzmann constant

= 1.38 × 10^-23jk^-1

NA = 6.02214076×10²³ mol⁻¹

Where NA = Avogadro number

Substitute all the parameters Into the formula

1/2 × 21/NA × v^2 = (3 × k × 356)/2

1.744×10^-23V^2 = 7.3692 × 10^-21

Make V^2 the subject of formula

V^2 = (7.37×10^-21)/1.744×10^-23

V^2 = 422.55

V = sqrt( 422.55)

V = 20.55

Therefore, the average (root mean square) velocity (m/s) of Neon molecules at 356 Kelvins and 0.9 bars is 20.55 m/s

Answer:

Near

Explanation:

Please mark me brainliest

Answer:

Near.... bcoz it is an adverb...

Answer:

true

Explanation:

It is accurate what is said. The compressor, expansion valve, and orifice tube are further protected when an additional filter is installed.

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Answer:

82.62%

Explanation:

The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

\(z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean\ and\ \sigma=standard\ deviation.\\\\Given \ that\ \mu=12V, \sigma=0.11V.\\\\For\ x<12.15V:\\\\z=\frac{12.15-12}{0.11} =1.36\\\\For\ x>11.85V:\\\\z=\frac{11.85-12}{0.11} =-1.36\\\\\)

From the normal distribution table, P(11.85 < x < 12.15) = P(-1.36 < z < 1.36) = P(z < 1.36) - P(z < -1.36) = 0.9131-0.0869 = 0.8262 = 82.62%

The missing part of the question is highlighted in bold form as seen below.

In designing an ECG circuit, it is known that at the input site, the ECG signal is about 1 mV and the amplitude of interference is 100mV. We need enlarge the 1 mV ECG signal to 800mV and keep the interference in the output signal within 5% of the ECG signal. Determine the required differential gain, Gd, and CMRR in dB of this ECG amplifier.

Answer:

\(\mathbf{G_d =0.506 \ dB}\)

CMRR = 66.02 dB

Explanation:

From the given information above:

We can express the formula for calculating the differential gain as:

\(\mathbf{G_d = \dfrac{V_{out}}{(V_t)-(V\_)} }\)

where;

the O/P signal related with e interference is =  800 mV + 5%

\(V_{out} = 850 \ mV\)

In an ECG circuit system, at one end of i/p, there is a connection to 1 mV & the other end is connected to 800 mV of i/p.

∴

\(\mathbf{G_d = \dfrac{850 \ mV}{(800 mV)-(1 \ mV)} }\)

\(\mathbf{G_d = \dfrac{850 \ mV}{799 mV}}\)

\(\mathbf{G_d =1.063}\)

In dB;

\(\mathbf{G_d =0.506 \ dB}\)

To find the value for the CMRR, we  need to determine the Signal to Noise ratio (SNR) by using the formula;

SNR = 1 mV/ 100 mV

SNR = 0.01

SNR = (5%)⁻¹

\(SNR =\bigg ( \dfrac{5}{100} \bigg )^{-1}\)

SNR = 20

Finally, we can estimate the Common Mode Ratio (CMRR) can be as:

\(CMRR = \dfrac{20}{0.01}\)

\(CMRR =2000\)

Thus, expressing our answer in dB; we have:

\(CMRR = 20 \ log _{10} (2000)\)

CMRR = 66.02 dB

Answer:

a) 15.075  , b ) 12.9

Explanation:

pressure on cylindrical vessel = 1.7 MPa

Twisting moment due to pressure = To of  8( 10^6 ) N-m

outer diameter of vessel = 2.5 m

wall thickness of vessel = 50 mm

Steel wall uniaxial yield strength = 600 MPa

Calculate the factor of safety

a) assuming a max shear stress yield criterion

safety factor = 15.075

b) assuming a von Mises yield criterion

safety factor = 12.9

attached below is the detailed solution of the problem

The frequency of the AC supply is 0.036 Hz.

We know that an alternating current circuit is the kind of circuit in which we do have the resistor in addition to the to the capacitor or the inductor or both as the case may be.

Here we are told that; A 32x10^-6 F capacitor is connected to a 60V AC supply in series with a 56 ohm resistor. The current flowing in the circuit is 0.16 A.

We can tell that the impedance of the circuit can be obtained by the use of the formula;

V = IZ

V = voltage

I = current

Z = impedance

Z = V/I

Z = 60 V/0.16 A

Z = 375 ohms

Then we have;

Z = √R^2 - XC^2

375 = √(56)^2 - (1/2 * 3.142 * f *  32x10^-6)^ 2

140625 = 3136 - (1/2 * 3.142 * f *  32x10^-6)^ 2

140625 -  3136  =  (1/2 * 3.142 * f *  32x10^-6)^ 2

137489 = 1/2 * 10^-4 f

137489 * 2 * 10^-4 f = 1

f = 1/137489 * 2 * 10^-4

f = 0.036 Hz

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The speed of the ball when it hits the bottom of the lake is 18.75 ft/s.

Every procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.

We can use the kinematic equation for constant acceleration to solve this problem:

\(v_f = v_i + aXt\)

First, we can use the fact that the ball is dropped from rest to find its initial velocity:

\(v_i\) = 0 ft/s

We are given the speed of the ball when it hits the surface of the lake:

\(v_f_1\) = 16.5 ft/s

a = 10 - 0.8v

t = 3.3 s

a = 10 - 0.8v

\(v_i\) = 16.5 ft/s (the speed when it hits the surface)

\(v_f_2\)= 16.5 ft/s + (10 - 0.8v) x 3.3 s

\(v_f_2\) = 16.5 ft/s + 33 ft/s - 2.64v ft/s

\(v_f_2\) = 49.5 ft/s - 2.64v ft/s

0 = 49.5 ft/s - 2.64v ft/s

2.64v ft/s = 49.5 ft/s

v = 18.75 ft/s

Thus, the speed of the ball when it hits the bottom of the lake is 18.75 ft/s.

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The fence height, additional structures, and architectural design are generally categorized under covenants.

The primary private land-use control is known to be a form of a deed restrictions, that hinders what a person can do on the property as regards to the owner.

Note that in the case above, the fence height, additional structures, and architectural design are generally categorized under covenants.

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Automatization of tasks increases memory demands. (False)

Automation describes technological applications that require as little human input as possible. Business process automation (BPA), IT automation, and other personal applications like home automation are all included in this.

Simple automation automates basic, easy-to-complete tasks. At this level of automation, tasks are centralized and streamlined through the use of tools. For example, information is shared through a messaging system rather than existing in isolated silos. The terms "basic automation" refer to techniques like business process management (BPM) and robotic process automation (RPA).

Business processes are managed through process automation to ensure consistency and openness. Dedicated software and business apps are typically used to handle it. Process automation can boost productivity and effectiveness within your company. It can also provide fresh perspectives on business problems and offer solutions.

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For a kinematics link with a constant angular velocity of 1 rad/s, the coordinate of the link can be determined using the equation θ = ωt, where θ represents the angular displacement and t is the time.

The speed vector can be found by taking the derivative of the coordinate equation with respect to time. Similarly, the acceleration vector can be obtained by taking the derivative of the speed vector equation.

In this scenario, we have a kinematics link with a constant angular velocity of 1 rad/s. The coordinate of the link can be determined using the equation θ = ωt, where θ represents the angular displacement and t is the time. Since the angular velocity is constant, the coordinate of the link increases linearly with time. If we know the initial position of the link, we can calculate the coordinate at any given time.

To find the speed vector, we need to take the derivative of the coordinate equation with respect to time. Since the angular velocity is constant, the derivative of θ with respect to t is simply ω. Therefore, the speed vector of the link is constant and its magnitude is equal to the angular velocity, which in this case is 1 rad/s.

To determine the acceleration vector at a specific point, let's say point P, we need to take the derivative of the speed vector equation. Since the angular velocity is constant, the derivative of the speed vector is zero. Thus, the acceleration vector at point P is zero. This means that the link is moving at a constant speed and there is no change in its velocity at point P.

In summary, for a kinematics link with a constant angular velocity of 1 rad/s, the coordinate increases linearly with time according to θ = ωt. The speed vector is constant and equal to the angular velocity, while the acceleration vector is zero at any point on the link.

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Answer:

The fifth deviation is +1

Explanation:

Given

\(Deviations = -5, +2, +4,-2\)

Required

Determine the fifth deviation

Represent the fifth deviation with x.

As a theorem, the sum of deviations from mean is always 0.

So, we have:

\(-5 +2 +4-2+x = 0\)

\(-1+x = 0\)

Add 1 to both sides

\(1 -1+x = 0 +1\)

\(x = 0 +1\)

\(x= +\ 1\)

Hence, the fifth deviation is +1

Answer:A

Explanation:

Those who want to save money and will use the product for only a few years

Answer:

THE ANSWER is A - those who want to save money and will use the product for only a few years

Explanation: Got it right on edg 2021

Explanation:

Acoustic.

In general, soft, pliable, or porous materials (like cloths) serve as good acoustic insulators - absorbing most sound, whereas dense, hard, impenetrable materials (such as metals) reflect most.

Answer:

Acoustic

Explanation:

Trust me

Answer:

Explanation:

The first reported attempts to strengthen concrete flexural elements by externally bonded steel plates were attempted in France around 1964-65 and practical applications date back to 1966-67 in France and South Africa then followed by Japan and Russia.