Which statement below best explains why the James Webb Space Telescope was optimized for infrared viewing in order to study early galaxy formation in the universe?
The earliest galaxies were cooler than today’s galaxies, so rather than emitting light in visible wavelengths they emitted mostly infrared light.
It didn’t actually need to be optimized for infrared viewing; this choice was the result of a global vote by astronomers based on their own preferences.
The earliest galaxies were hotter than today’s galaxies, so rather than emitting light in visible wavelengths they emitted mostly infrared light.
The earliest galaxies are the most distant, and universal expansion has redshifted their spectra into infrared wavelengths.
The details of how a galaxy formed are encoded in the infrared portion of its spectrum.
Answers
The most distant galaxies are the ones that have had their spectra redshifted into infrared wavelengths by universal expansion best explain the James Webb Space telescope was optimized for infrared viewing to understand the universe's initial galaxy formation.
The three main justifications for JWST to use infrared observation are the capacity of infrared light to penetrate thick and icy clouds of dust and gas (relative to other wavelengths), a phenomena called "Redshift," and the link among wavelength and temperature.
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Related Questions
What average net force is required to accelerate a 375 kg motorcycle initially at rest to a speed of 25.5 m/s over a distance of 174 m?
Answers
Answer:
700.7N
Explanation:
m = 375
x = 174
v = 25.5
a = ?
\( {v}^{2} = 2ax\)
F = ma
We substitute a
F = m * (v^2 /(2x))
F = 375 * 25.5^2/(2*174)
F = 700.7 N
Average net force is required to accelerate a 375 kg motorcycle initially at rest to a speed of 25.5 m/s over a distance of 174 m is 700.7 N
What is force?The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given in the question motorcycle of mass, m = 375 kg covers a distance of x = 174 m have initial velocity zero and final velocity, v = 25.5 m/sec then the acceleration a,
\(v^{2} = 2ax\)
\(a= v^{2} / 2x\)
Force required to accelerate,
F = ma
substitute a
F = m * \((v^2 /(2x))\)
F = 375 * \(25.5^2/(2*174)\)
F = 700.7 N
So the average net force required to accelerate motorcycle, F = 700.7 N.
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something that orbiys other things in space
Answers
Answer: well we all orbit the sun all the planets do so the
SuN
Explanation: two words common sense
Is altitude abiotic or biotic or neither SCIENCE WORK NEEDED BY 11:59 HELP HELP HLEP
Answers
Answer:
abiotic
Explanation:
goggle:)))))))
Momentum conservation often assumes that the mass of an object remains
constant throughout a process or event. However, a change in momentum can
also occur when mass changes. Consider an automobile with a full tank of
gasoline traveling at a velocity of 88.0 km/h to the east. The mass of the car when
the fuel tank is full is 1292 kg. Suppose that the car travels along a highway that
extends eastward for 600 km. By the time the car has traveled this distance, its
mass is 1255 kg. What is the car's velocity at the end of the journey?
Answers
The law of conservation of momentum states that in an isolated system, the total momentum of two or more bodies acting on each other remains constant unless an external force acts on them. Therefore, it cannot create or destroy momentum.
What is the speed of the car at the end of the trip?Velocity is the percentage of time an object moves along a path, and Velocity is the speed and direction of an object's movement.If the car is moving at a constant speed, the car is also moving at a constant speed. The confusion between the two rates, which are actually measured in the same units, is:Velocity is a vector quantity, but velocity is a scalar quantity.This is just Newton's first law. An object at rest will remain stationary and an object in motion will continue to move in the same direction at a constant speed unless an unbalanced force acts on it. The car tends to keep moving at a constant speed and direction because the two forces are canceling (i.e. balanced).To know more about speed visit:
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When scientists use one of their five senses to gather information, they are
A.
drawing a conclusion.
B.
making an inference.
C.
predicting a relationship
D.
making an observation.
Answers
Answer:
making an observation
Explanation:
Write the differences between rest and motion
Answers
Answer:
Depends on position
Explanation:
Rest:
A body is said to be at rest, if it does not change its position with respect to its surroundings.
Motion:
A body is said to be in motion, if it changes its position with respect to its surroundings.
The state of rest and motion is relative
A parallel circuit has four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. How much current is supplied by the source?
Answers
A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.
The sum of the branch currents in a parallel circuit can be calculated by adding up the values of the individual branch currents. In this case, we have four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. Thus, the sum of the branch currents is:120 mA + 380 mA + 250 mA + 2.1 A= 2.85 ATherefore, the current supplied by the source in this parallel circuit is 2.85 A. This is because, in a parallel circuit, the current from the source is split between the different branches of the circuit. Each branch will have a different current, but the sum of all the branch currents will always equal the current supplied by the sourceFor such more question on parallel circuit
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A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed . The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time . a. What is the value of ? b. What is the y position of the cannonball at the time c. Find the initial speed of the projectile.
Answers
a) The value of t u = 140/t`b.
b) The y position of the cannonball at the time t is 55.5 mc.
c) The initial speed of the projectile is 52.4 m/s.
Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.
a. To find the value of t:Here, we have to use the formula of distance
i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`
Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is
(2H) = 2 × 55.5
= 111 m`2H/g
= 111/9.8`
= 11.32653 s
From equation (1),u×t = 140u = 140/t
Therefore, `u = 140/t`b.
b)To find the y position of the cannonball at the time t:
Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,
Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².
We have already calculated the time taken by the cannonball to hit the ground in the previous step.`
y = 140 - (1/2) × 9.8 × t²`
On substituting the value of t as `t = 11.32653`,
we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.
c) To find the initial speed of the projectile:
To calculate the initial speed of the projectile, we need to use the formula of range of projectile
.i.e.,R = u²sin2θ/g
Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)
u² = R × g/sin2θ
= 140 × 9.8/sin0°
= 2744m²/s²u
= \(\sqrt(2744m^2/s^2)\)
= 52.4 m/s
Hence, the initial speed of the projectile is 52.4 m/s.
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PLEASE ANSWERRRRR
a) A microwave oven that draws 0.8 kWh is used for one hour. At a cost of 7.5 cents per kWh, what is the cost of the microwave’s electrical energy consumption?
b) What is the cost for the microwave if it is used one day for 20 min?
(c) What is the cost of using the microwave for 20 min a day for a month of 30 days?
Answers
a) A microwave oven that draws 0.8 kWh is used for one hour. At a cost of 7.5 cents per kWh, then the cost of the microwave’s electrical energy consumption is 7.5 cents per kWh.
b) the cost for the microwave if it is used one day for 20 min is 1.98 cents.
(c) the cost of using the microwave for 20 min a day for a month of 30 days is 59.4 cents.
Given,
Energy consumption of microwave = 0.8 kWh
cost = 7.5 cents/kWh
20 min = 0.33hr
Energy consumption in 20 min = 0.8 kWh × 0.33 = 0.26 kWh.
cost for 20= 0.26 kWh × 7.5 cents/kWh = 1.98 cents
cost for 30 days,
1.98 cents × 30 days = 59.4 cents.
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How do you get c and d?
A positive charge of magnitude Q1 = 0.85 nC is located at the origin. A negative charge Q2 = −7.5 nC is located on the positive x-axis at = 15.5 cm from the origin. The point P is located at = 6.5 cm above the charge Q2.
a) Sketch the directions of Q1, Q2, and on the figure. Make sure to label your arrows.
b) Determine the magnitudes of E1 and E2 at point P.
c) Determine the x and y components of E1 at point P.
d) Determine the x and y components of E2 at point P.
e) Determine the magnitude and direction of the net electric field at point P due to the two charges.
Answers
Answer:
of the net electric field at point P due to the two charges.
Explanation:
An ice cube has a mass of 64 g and is initially at a temperature of 0°C . The ice cube is heated until 56.6 g has become water at 100°C and 7.4 g has become steam at 100°C. How much energy (in kJ) was transferred to the ice cube to accomplish the transformation?
Answers
Answer:
An ice cube has a mass of 64 g and is initially at a temperature of 0°C . The ice cube is heated until 56.6 g has become water at 100°C and 7.4 g has become steam at 100°C. How much energy (in kJ) was transferred to the ice cube to accomplish the transformation?
An object A is placed 12cm in front of a concave mirror M₁ of focal length 8cm and a plane mirror M₂ is placed 30cm in front of the concave mirror as shown in Figure 1 The object A is first reflected by M₁and then reflected by M₂ to get an image 1₂. What is the distance between 1₂ and the object A？
Answers
According to the question the distance between the object A and the image 1₂ is 6 cm.
What is distance?Distance is the measure of how far apart two objects, points, or locations are from one another. Distance can be measured in linear units such as feet, meters, or kilometers, or angular units such as degrees. The concept of distance is a fundamental concept in mathematics, physics, and other sciences. Distance is used to calculate the speed and velocity of objects, as well as the force of gravity between two objects.
The distance between the object A and the image 1₂ can be calculated using the mirror equation.
Mirror equation: 1/d₁ + 1/d₂ = 1/f
Where d₁ is the object distance, d₂ is the image distance, and f is the focal length of the mirror.
In this case, d₁ = 12 cm, d₂ = ? and f = 8 cm.
Substituting these values into the equation gives us:
1/12 + 1/d₂ = 1/8
Rearranging the equation gives us:
1/d₂ = 1/8 – 1/12
Plugging in the values gives us:
1/d₂ = 1/8 – 1/12 = 1/6
Solving for d₂ gives us:
d₂ = 6 cm
Therefore, the distance between the object A and the image 1₂ is 6 cm.
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You are going 30 m/s in a car of mass 1000 kg when you reach a red light and stop your car.
a. how much heat energy is released by the brakes of your car
Answers
Answer:
Explanation:
The kinetic energy will convert to heat energy (provided the car has friction brakes and not regenerative brakes as might be found on an electric or hybrid) Also assuming level road.
E = ½mv² = ½(1000)30² = 450,000 J
7. A car stops at a red light. The light turns green
and the car accelerates up to a constant speed. After
several minutes, the car slows down and stops at the
next red light. Which graph shows the car's motion?
Answers
Answer:
Graph C
Explanation:
This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.
pls helppp
A model rocket has a mass of 0.2 kg, with a motor that can provide a force of 100 N. A second model rocket is being built with the
same motor, but it is being designed to accelerate half as much as the first rocket. What kind of change can be made in the design to
achieve this objective? (1 point)
O The mass of the second rocket should be 0.1 kg.
The mass of the second rocket should be 0.01 kg.
The mass of the second rocket should be 0.4 kg.
O The mass of the second rocket should be 0.2 kg.
Answers
The mass of the second rocket should be 0.4 kg in order for the acceleration to be half of the first rocket's acceleration.
We know that,
F = m a
where,
F = Force
m = Mass
a = Acceleration
Given that,
\(F_{1}\) = 100 N
\(m_{1}\) = 0.2 kg
\(F_{1}\) = \(F_{2}\) = 100 N
\(a_{2}\) = \(a_{1}\) / 2
\(F_{1}\) = \(m_{1}\) * \(a_{1}\)
\(a_{1}\) = 100 / 0.2
\(a_{1}\) = 500 m / s²
\(a_{2}\) = 500 / 2
\(a_{2}\) = 250 m / s²
\(m_{2}\) = 100 / 250
\(m_{2}\) = 0.4 kg
According to Newton's second law of motion, acceleration of an object is the result of force acting on the object.
Therefore, The mass of the second rocket should be 0.4 kg
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System A consists of a mass m attached to a spring with a force constant k; system B has a mass 2m attached to a spring with a force constant k; system C has a mass 3m attached to a spring with a force constant 6k; and system D has a mass m attached to a spring with a force constant 4k.
Rank these systems in order of increasing period of oscillation. (Use only the symbols < and =, for example A < B = C.)
Answers
Solution :
We know that the time period of oscillation of a spring mass system is given by :
\($T = 2 \pi \sqrt{\frac{m}{k}}$\) , where m is mass and k is the spring constant
∴ \($T_A = 2 \pi \sqrt{\frac{m}{k}}$\) .........(i)
\($T_B = 2 \pi \sqrt{\frac{2m}{k}}$\) ..........(ii)
\($T_C = 2 \pi \sqrt{\frac{3m}{6k}} = 2 \pi \sqrt{\frac{m}{2k}}$\) ..........(iii)
\($T_D = 2 \pi \sqrt{\frac{m}{4k}}$\) ...............(iv)
Comparing the equations (i), (ii), (iii) and (iv)
We get
\($T_B > T_A > T_C > T_D$\)
So in increasing order of time period, we get
\($T_D < T_C < T_A < T_B$\)
Forces that cancel each other are called_ forces \
Answers
Answer:
balanced forces
I need help, please!
Answers
Answer:
can u send pictures again it's unclear.
All of the following steps are included in a self-modification program except __________. A. specifying target behavior B. designing a program C. focusing on one goal at a time D. gathering data about target behavior
(Psychology)
Answers
Answer:
C)focusing on one goal at a time
Explanation:
Self-modification programs could be regarded as a program that help individual in managing unwanted as well as dysfunctional behavioral responses whenever they are going through a problem and try to deal with it. For instance the dysfunctional behavioral response for someone with a panic attack is avoidance. Some of the the steps that are involved in in a self-modification program are;
✓ specifying target behavior ✓designing a program
✓ gathering data about target behavior
Answer:
c
Explanation:
on edge 2020
a block of aluminum occupies a volume of 0.15L and weighs .405kg. what is its density
Answers
Answer:
ρ=3000 kg/m
Explanation:
My work is in the attachment.
Density is just the mass of an object/substance divided by its volume. Technically you could just divide the kg by L and be done with it, but the standard units for volume are m³. So I converted it before calculating.
What is it called when the moon passes through the penumbra of Earth’s shadow?(1 point)
total lunar eclipse
total solar eclipse
partial lunar eclipse
partial solar eclipse
Answers
Answer: I'm not sure, but I think it would be a total lunar eclipse
When the moon passes through the penumbra of Earth’s shadow it is referred to as partial lunar eclipse. The correct option is C.
What is partial lunar eclipse?A partial lunar eclipse occurs when the moon is not completely immersed in the umbra of the earth's shadow.
During a partial solar eclipse, the Moon, Sun, and Earth do not align perfectly straight, and the Moon casts only the penumbra of its shadow on Earth. From our vantage point, it appears that the Moon has eaten the Sun.
A shadow's penumbra is the lighter outer edge. Partial solar eclipses are caused by the Moon's penumbra, while penumbral lunar eclipses are caused by the Earth's penumbra. The penumbra is a type of lighter shadow.
The Penumbra is a half-shadow region that occurs when an object only partially covers a light source.
Thus, the correct option is C.
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Louis Armstrong ride his bike 55km east time trial in 51 minutes what was his average velocity in KM/min?
Answers
Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.
How to determine average velocity?To calculate the average velocity, divide the total displacement by the total time taken. In this case, Louis Armstrong rode his bike 55 km to the east in a time trial lasting 51 minutes.
Average Velocity = Displacement / Time
Displacement = 55 km (since he rode 55 km to the east)
Time = 51 minutes
Average Velocity = 55 km / 51 min
To express the average velocity in km/min, convert the time from minutes to minutes.
1 hour = 60 minutes
Average Velocity = 55 km / 51 min × (1 hour / 60 min)
Average Velocity = 55 km / 51 min × (1/60) hour
Simplifying the expression:
Average Velocity = 1.078 km/min
Therefore, Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.
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The size of a proton is of the order of 10–15 m and the size of the visible universe is of the order of 1026 m. From this information you can conclude that:
A. The size of the universe is 41 orders of magnitude greater than that of the proton.
B. The size of the universe is 26 orders of magnitude greater than that of the proton.
C. The size of the proton is 11 orders of magnitude greater than that of the universe.
Answers
The size of the universe is 41 orders of magnitude greater than that of the proton i.e. option A is correct.
The size of a proton is approximately 1 femtometer (fm), which is equivalent to 1 x 10^-15 meters. This is a very small size, much smaller than the size of an atom. And the size of the universe is in the order of 10^26 m. Comparing the size of both.
The size of a proton is 10^-15 m and the size of the visible universe is 10^26 m, so the difference in size can be calculated by dividing the size of the universe by the size of the proton :
log((size of universe)/(size of proton))
log(10^26/10^-15) = log(10^41) = 41
Therefore, option A stating " the size of the universe is 41 orders of magnitude greater than that of the proton " is correct.
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assume the earths mass is 34.102 kg, and the radius is 56.867 x 10^3 miles, what would be the gravitational acceleration on such an planet in unit of m/s^2?
Answers
Answer:
The gravitational acceleration of that planet is \(2.718\times 10^{-25}\) meters per square second.
Explanation:
Under the assumption that Earth is a sphere and with an uniformly distributed density, the gravitational acceleration at the surface of the planet is given by the following expression:
\(g = G\cdot \frac{M}{r^{2}}\) (Eq. 1)
Where:
\(G\) - Gravitation constant, measured in newton-square meters per square kilogram.
\(r\) - Radius of the planet, measured in meters.
\(M\) - Mass of the planet, measured in kilograms.
If we know that \(M = 34.102\,kg\), \(r = 91.5\times 10^{6}\,m\) and \(G = 6.674\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}}\), then the acceleration on the planet is:
\(g = \left(6.672\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}} \right)\cdot \left[\frac{34.102\,kg}{(91.5\times 10^{6}\,m)^{2}} \right]\)
\(g = 2.718\times 10^{-25}\,\frac{m}{s^{2}}\)
The gravitational acceleration of that planet is \(2.718\times 10^{-25}\) meters per square second.
calculate the work done by the person who applies force of 5000N to lift a load up to a height of 2m
Answers
Answer:
W = 10000J
Explanation:
W = F • s
W = Work in J
F = Force in N
s = displacement in m
W = 5000N • 2m
W = 10000J
The self-referencing effect refers to ________.
Answers
What is the difference between classical mechanics and quantum mechanics?
Answers
Classical mechanics describes the motion of objects on a macroscopic scale, while quantum mechanics deals with the behavior of particles on a microscopic scale. Classical mechanics is deterministic, meaning that it predicts precise outcomes based on initial conditions, while quantum mechanics is probabilistic, providing probabilities of different outcomes. Classical mechanics follows the principle of causality, where every effect has a specific cause, whereas quantum mechanics introduces inherent uncertainty and wave-particle duality. Classical mechanics is well-suited for describing everyday objects, while quantum mechanics is necessary to explain the behavior of particles at the atomic and subatomic levels.
~~~Harsha~~~
classical mechanics is the branch of physics that deals with the motion of everyday objects like balls, cars, and planets.
quantum mechanics is a branch of physics that focuses on the behavior of very small particles, such as atoms and subatomic particles like electrons.
I didn't understand
Answers
Emory pushes the box with 20 Newtons of force. If the box is 4kg, how fast will the box accelerate?
Answers
20N=4kg.a
a=5 N/kg
Blank C3H6O2+ blank O2 ➡️blank CO2+blank H2O
Answers
The balanced equation for the given unbalanced chemical reaction is:
\(C_3H_6O_2 +\frac{7}{2} O_2 \longrightarrow 3CO_2 +3H_2O\)
What is the balanced chemical equation?A chemical equation can be defined as a representation of a chemical reaction in which symbols of the substances, participated reactants, formed products, and an arrow showing the direction of the reaction is involved.
A balanced equation in which the number of atoms of each element reactants and products is equal in the equation of a chemical equation.
The law of conservation of mass should be obeyed while balancing a chemical equation. The total mass present on the reactant side should be equal to the total mass on the product side in a balanced chemical equation.
The balanced chemical equation for a given reaction is:
\(C_3H_6O_2 +\frac{7}{2} O_2 \longrightarrow 3CO_2 +3H_2O\)
Therefore, missing coefficients O₂, CO₂ and H₂O are 7/2, 3 and 3 respectively.
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