which solute would provide the sharper end point in a titration with 0.10 m ? a question content area , 0.10 m 0.10 m aniline b question content area , 0.10 m 0.10 m sodium phenolate c question content area , 0.10 m ethanolamine 0.10 m aniline d question content area , 0.10 m aniline 0.10 m

Answer:

I need the constant k (the rate at which the amount decays)

Answer:

313

Explanation:

70÷14=5 which means

10000÷2÷2÷2÷2÷2=312.5gram

The amount of the substance that will remain after 70 days, given that you initially have 10000 grams of the substance is 312.5 grams

First, we must obtain the number of half lives that has elapsed after 70 days. This is shown below:

n = t / t½

n = 70 / 14

n = 5

Now, we shall determine the amount remaining after 70 days. Details below:

N = N₀ / 2ⁿ

N = 10000 / 2⁵

N = 10000 / 32

N = 312.5 grams

Thus the amount remaining after 70 days is 312.5 grams

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The total weight of dextrose is 250 grams.

The total weight of Aminosyn is 42.5 grams.

10 mL of KCI should be added.

5 mL of NaCl should be added.

The total volume of the solution with the original fluids and the addition of KCI and NaCl is 1315 mL.

To calculate the total weight of dextrose, we need to know the concentration of the 50% dextrose solution. Assuming the concentration refers to weight/volume (w/v), we can calculate the weight using the formula:

Weight of dextrose = (Concentration of dextrose * Volume of dextrose solution) / 100

Weight of dextrose = (50 * 500) / 100

Weight of dextrose = 250 g

Therefore, the total weight of dextrose is 250 grams.

To calculate the total weight of Aminosyn, we need to know the concentration of the 8.5% Aminosyn solution. Assuming the concentration refers to weight/volume (w/v), we can calculate the weight using the same formula as above:

Weight of Aminosyn = (Concentration of Aminosyn * Volume of Aminosyn solution) / 100

Weight of Aminosyn = (8.5 * 500) / 100

Weight of Aminosyn = 42.5 g

Therefore, the total weight of Aminosyn is 42.5 grams.

To calculate the volume of KCI to be added, we need to know the strength of the stock KCI solution. Assuming the stock KCI solution is 2 mEq/mL, we can calculate the volume of KCI using the formula:

Volume of KCI = (Amount of KCI needed) / (Strength of KCI solution)

Volume of KCI = 20 mEq / 2 mEq/mL

Volume of KCI = 10 mL

Therefore, 10 mL of KCI should be added.

To calculate the volume of NaCl to be added, we need to know the strength of the stock NaCl solution. Assuming the stock NaCl solution is 4.4 mEq/mL, we can calculate the volume of NaCl using the formula:

Volume of NaCl = (Amount of NaCl needed) / (Strength of NaCl solution)

Volume of NaCl = 22 mEq / 4.4 mEq/mL

Volume of NaCl = 5 mL

Therefore, 5 mL of NaCl should be added.

The total volume of the solution with the original fluids and the addition of KCI and NaCl can be calculated by adding the volumes of all the components:

Total volume = Volume of dextrose solution + Volume of Aminosyn solution + Volume of sterile water + Volume of KCI + Volume of NaCl

Total volume = 500 mL + 500 mL + 300 mL + 10 mL + 5 mL

Total volume = 1315 mL

Therefore, the total volume of the solution is 1315 mL.

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This would be 1.5 * C moles of sodium carbonate. To completely eliminate the calcium ions, you would need to add an equal number of moles of sodium carbonate.  

To completely eliminate hard water ions, you would need to add a specific amount of a solution that can react with these ions. The exact amount depends on the concentration of the hard water ions and the stoichiometry of the reaction.
Let's assume that the hard water ions are calcium ions (Ca2+) and the solution you are adding is sodium carbonate (Na2CO3), which can react with the calcium ions to form insoluble calcium carbonate (CaCO3).
First, determine the molar concentration of the hard water ions. If we assume the concentration is C mol/L, then the number of moles of calcium ions present in 1.5 L of the solution is 1.5 * C.
Next, find the stoichiometric ratio between the calcium ions and sodium carbonate. If the balanced equation is:
Ca2+ + Na2CO3 → CaCO3 + 2Na+,

we see that 1 mole of calcium ions reacts with 1 mole of sodium carbonate.
Therefore, to completely eliminate the calcium ions, you would need to add an equal number of moles of sodium carbonate. This would be 1.5 * C moles of sodium carbonate.
To convert moles to grams, multiply the number of moles by the molar mass of sodium carbonate. For example, if the molar mass of sodium carbonate is M g/mol, then the mass of sodium carbonate to add is (1.5 * C * M) grams.

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Jewelry is a potential safety issue because chemicals can be trapped under it, in contact with sensitive skin (option A).

Jewelry is collectively a personal ornamentation such as rings, necklaces, brooches and bracelets, made of precious metals and sometimes set with gemstones.

Jewellery is made of metals, sometimes heavy metals. Hence, the accumulation can be serious threat to the environment when used.

Chemicals can be trapped under jewelry such as rings, necklace, etc. This, when in contact with the skin, can cause serious damage to the body.

Therefore, option A is the correct choice.

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The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

a) Saloni needs to add water and shake the test tube afterwards test it with litmus paper and the litmus will turn red that will confirm that the gas is acidic.

b) \(\mathrm{C}+\mathrm{O}_{2} \rightarrow \mathrm{CO}_{2}\)

   \($\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{H}_{2} \mathrm{CO}_{3}$\)

A litmus test is a test which is conducted to check the presence of acid and base in a chemical solution . A litmus paper is used which is made from a particular species of lichens. A litmus will turn to blue color when exposed to a base and to red color when exposed to an acid.

In the Given question, Charcoal contains carbon, when it is burned it reacts with oxygen present in the atmosphere to form Carbon dioxide and later when this carbon dioxide reacts with water, it is converted into  carbonic acid gas. The acidic nature of the compound is proved later with the litmus test.

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Hello!!!

Answer: Therefore elements with high ionization energies have more positive electron affinity whereas alkali metals having the lowest ionization energy do not tend to add electrons.

Explanation:  So energy is to be supplied for the addition of electrons and shows positive electron affinity.

Hope This Helps You Out! So... The Answer Your Looking For Is "True"

The statement is true as  all elements with high ionization energy have more electrons and hence have   high electron affinity​.

It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.

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Answer: ON THE PRINCIPLE OF EXPANSION OF METAL ON HEATING

                           (THERMAL EXPANSION)

Explanation: WHEN THE THERMOMETER GET HEATED MERCURY RISES UP AND SHOW THE TEMPERATURE AND DOES THE SAME WHEN COOLED IT GOES DOWN

It is false that if a question is asking about an opinion, it can be answered with science.

A personal belief or assumed that is not tested or backed up by evidence is described as an opinion.

A hypothesis is typically a claim based on some form of observation or evidence. Hypotheses must be testable and, once tested, evidence-supported.

Any question that is based on opinion cannot be answered by scientific reasonings as it is not evidence based.

Thus, the given statement is false.

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The second peak is higher than the first peak.

Explanation:

For each run, there are two peaks of voltage because the magnet induces a voltage in the solenoid as it falls through it. The voltage induced by the magnet changes direction as it passes through the solenoid, creating two peaks. The two peaks point in opposite directions because the magnetic field changes direction as the magnet falls through the solenoid. The second peak is higher than the first peak because of the changing magnetic field.

A solenoid is an electrical component that is used to generate a magnetic field when an electric current is passed through it. When a magnet falls through a solenoid, it induces a voltage in the solenoid, which can be detected using a voltmeter or oscilloscope.

The voltage induced by the magnet changes direction as it passes through the solenoid, creating two peaks. The two peaks point in opposite directions because the magnetic field changes direction as the magnet falls through the solenoid. This is due to the fact that the magnet's north pole attracts the south pole of the solenoid, and vice versa.

As a result, the direction of the magnetic field in the solenoid changes as the magnet falls through it. The second peak is higher than the first peak because of the changing magnetic field. The strength of the magnetic field is directly proportional to the rate of change of the magnetic field. The rate of change of the magnetic field is greatest when the magnet is in the center of the solenoid, resulting in a larger induced voltage.

Therefore, the second peak is higher than the first peak.

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The volume of NaOH needed to reach a pH of 9.0 is 7.9 mL. Since 125 mL is closest to 7.9 mL option A is correct.

To determine the volume of 0.10 M NaOH needed to reach a pH of 9.0 when titrating a 100.0 mL solution of fully protonated 0.25 M lysine, we need to consider the pKa values of lysine and its corresponding protonation and deprotonation reactions.

Lysine is an amino acid with multiple ionizable groups. Its side chain has a pKa value of approximately 10.5, which corresponds to the protonation and deprotonation of the amino group (-NH₂) in lysine.

At a pH of 9.0, the amino group in lysine is mostly deprotonated, meaning it has lost its H⁺ ion. To achieve this, we can use the Henderson-Hasselbalch equation:

pH = pKa + log\(\frac{[A^{-}] }{[HA]}\)

Where [A-] is the concentration of the deprotonated form (in this case, lysine with the amino group deprotonated) and [HA] is the concentration of the protonated form (lysine with the amino group protonated).

In this case, we want to find the volume of NaOH needed to reach a pH of 9.0, which corresponds to the deprotonated form. Thus, we can rewrite the equation as:

9.0 = pKa + log\(\frac{[A^{-}] }{[HA]}\)

Rearranging the equation gives:

log\(\frac{[A^{-}] }{[HA]}\) = 9.0 - pKa

Now we substitute the pKa value for the amino group in lysine (approximately 10.5):

log\(\frac{[A^{-}] }{[HA]}\) = 9.0 - 10.5

log\(\frac{[A^{-}] }{[HA]}\) = -1.5

To simplify the calculation, we can rewrite this equation as an exponential expression:

\(\frac{[A^{-}] }{[HA]}\) = 10^(-1.5)

\(\frac{[A^{-}] }{[HA]}\)= 0.0316

Since we have a 0.25 M lysine solution, we can say that [HA] = 0.25 M.

0.0316 = [A⁻]/0.25

[A⁻] = 0.0079 M

This means that the concentration of the deprotonated form (lysine with the amino group deprotonated) is 0.0079 M.

Now we can calculate the moles of lysine with the amino group deprotonated:

moles of [A⁻]  = [A⁻]  × volume of lysine solution

moles of [A⁻]  = 0.0079 M × 100.0 mL

moles of [A⁻]  = 0.00079 moles

To neutralize this amount of [A⁻] , we need an equal number of moles of NaOH. Since NaOH is 0.10 M, we can calculate the volume of NaOH needed:

volume of NaOH = moles of [A⁻] / NaOH concentration

volume of NaOH = 0.00079 moles / 0.10 M

volume of NaOH = 7.9 mL

Therefore, the volume of NaOH needed to reach a pH of 9.0 is 7.9 mL.

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Answer:

Any unapposed interaction that will change the motion of an object.

Explanation:

My physics teacher had us write this down last week.

Answer:

56160grams

Explanation:

First, we need to convert the number of molecules of magnesium chloride (MgCl2) into moles by dividing by Avagadro's number (6.02 × 10^23 molecules)

n = nA ÷ 6.02 × 10^23

n = 14.07 × 10^26 ÷ 6.02 × 10^23

n = 14.07/6.02 × 10^(26-23)

n = 2.34 × 10^3 moles of MgCl2

The balanced reaction given in the question is as follows:

Mg + 2HCl → MgCl2 + H2

If 1 mole of Mg produced 1 mole of MgCl2

Then, 2.34 × 10^3 moles of Mg will also produce 2.34 × 10^3 moles of MgCl2.

Using mole = mass ÷ molar mass (MM)

Molar mass of Mg = 24g/mol

mass = mole × MM

mass = 2.34 × 10^3 × 24

mass = 56.16 × 10^3

mass = 56160grams.

Answer:  The concentration of hydroxide ions in the solution is 2.2 x 10^(-5) M.

Explanation:

To determine the concentration of hydroxide ions in the aqueous solution of methylamine, we can use the equation for the base dissociation reaction of methylamine in water:

CH3NH2 + H2O ⇌ CH3NH3+ + OH-

The equilibrium constant expression for this reaction is:

Kb = [CH3NH3+][OH-] / [CH3NH2]

Here, the concentration of methylamine ([CH3NH2]) is 0.050 M and the Kb value is 4.4 x 10^(-4), we can rearrange the equation and solve for [OH-]:

[OH-] = (Kb * [CH3NH2]) / [CH3NH3+][OH-]

= (4.4 x 10^(-4) * 0.050) / 1[OH-] = 2.2 x 10^(-5) M

Therefore, the concentration of hydroxide ions in the solution is 2.2 x 10^(-5) M.

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1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution. Details about molarity can be found below.

The number of moles of a solution can be calculated by multiplying the molarity of the solution by its volume. That is;

no of moles = molarity × volume

According to this question, a solution has a molarity of 8.20M and volume of 125 mL of solution.

no of moles = 8.20 × 0.125

no of moles = 1.025moles

Therefore, 1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution.

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Answer:

approximately 0.51 moles

Explanation:

gram of Nacl= numberof moles/RMM

relative molecular mass of NaCl=1×23+1×35.5=23+35.5=58.5

gram of NaCl =29.7/58.5=0.5076mole=approximately 0.51 mole

Answer:

 a supply of electric charges which are free to flow, some form of push to move the charges through the circuit and a pathway to carry the charges.

Explanation:

There's your answer have a good day

Answer: 77.47 g of \(Fe_2O_3\) will be produced from 100.0 g of Iron (III) hydroxide

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} Fe(OH)_3=\frac{100.0g}{106.9g/mol}=0.935moles\)

The balanced chemical equation is:

\(2Fe(OH)_3(s)\rightarrow Fe_2O_3(s)+3H_2O(g)\)  

According to stoichiometry :

2 moles of \(Fe(OH)_3\) produce = 1 mole of \(Fe_2O_3\)

Thus 0.935 moles of \(Fe(OH)_3\) will producee=\(\frac{1}{2}\times 0.935=0.468moles\)  of \(Fe_2O_3\)

Mass of \(Fe_2O_3=moles\times {\text {Molar mass}}=0.468moles\times 159.7g/mol=74.74g\)

Thus 77.47 g of \(Fe_2O_3\) will be produced from 100.0 g of Iron (III) hydroxide

Answer:

A.experiment

Explanation:

hope this helps

Answer:Rubidium and Strontium

Explanation:

The two fractions that would be best to pool together for application to a subsequent column would be fractions 4 and 5.

Fractions are a way of writing numbers as a ratio of two numbers. They are written in the form of a/b, where a is the numerator and b is the denominator. The numerator represents the number of parts of a whole, and the denominator represents the total number of parts into which the whole is divided. Fractions can represent parts of a whole number, parts of a set, or parts of a measurement.

The two fractions that would be best to pool together for application to a subsequent column would be fractions 4 and 5. This is because fraction 4 has the highest concentration of the desired protein, and fraction 5 has the second highest concentration. Pooling these two fractions together would maximize the amount of protein present in the pooled fraction and minimize any contaminants that may be present in the other fractions.

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The complete question is:

Based upon the quantitative data, what two fractions would be the best to pool together for application to a subsequent column (like an ion exchange or gel filtration column)?

Answer:B

Explanation:

A positively charged object attracts an uncharged object.

A positively charged object attracts an uncharged object statement is in correct in the table. Hence option B is correct.

Charge are defined as a subatomic particle's ability to experience force when exposed to an electric and magnetic field. The value that the atom reaches after removing or gaining electrons is known as charge. Only ions that comply with the octat rule are stable. Atoms or groups of atoms with an electric charge are referred to as ions. Cations are positive-charged ion particles. Anions are ion types that have a net negative charge.

A charged object will cause an opposing charge to be applied to an uncharged object when it is brought close to the charged one. These two things are drawn to one another because opposing charges attract one another. Other charged items are drawn to a charged object whereas uncharged objects are repelled by it.

Thus, a positively charged object attracts an uncharged object statement is in correct in the table. Hence option B is correct.

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Answer:

c. plastic is an insulator

Explanation:

a and b are metals which are conductors and d contains water which is also a conductor

The molality of concentrated aqueous HCl is 16.0 m and the mol fraction for the same solution is 0.0223.

[HCl]=12.0 M =12.0 mol HCl/1L solution

The density of solution = 1.19 g/ml

Thus, the mass of 1L of solution = Volume x density

=1000 ml x1.19 g/ml

=1190 g

Mass of HCl= Moles x Molar mass

=12.0 x36.5 g

=438 g

Thus, mass of water= mass of solution - mass of HCl

=1190- 438

=752 g

Molality is the ratio of number of moles to the weight of solvent in kg.

=12 mol x 1000 g/752 g x 1 kg

=16.0 m

Moles of water = mass/ molar mass

=752/18

=41.8 mol

Thus, the calculation of mole fraction is,

X_HCl=12.0/12.0+41.8

=0.223

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To calculate the density of the object, we need to know its volume. The volume can be calculated by multiplying its length, width, and height. Unfortunately, the diagram does not provide any measurements for the object's dimensions. Therefore, we cannot determine its density.

However, we do know the object's mass, which is 120 grams. Mass is the amount of matter in an object and is measured in grams. Density, on the other hand, is the amount of mass per unit of volume and is measured in grams per cubic centimeter (g/cm3).
In summary, we cannot answer the question about the density of the object without knowing its volume. But we do know that its mass is 120 grams, which is an important piece of information in calculating density.
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Answer:

3000 milligrams

Explanation:

to get milligrams you add 3 zero at the end

Answer:

The correct answer is - c. adding 10 mL bleach to 90 mL water.

Explanation:

To prepare a effective disinfecting solution to clean the countertops is a bleasce solution of 10% solution of bleach. The ten percent of the bleach solution means there are one volve of bleach and 9 volume of clean water in this solution.

So, preparing the 1/10 or ten percent solution is where adding 10 ml of bleach which is diluted to 90 ml clean water. This diluted solution can be use as disinfecting solution.