Which set of phrases best lists the characteristics of asexual reproduction?

one parent, offspring are not identical to the parent

one parent, offspring are identical to the parent

two parents, offspring are not identical to the parents

two parents, offspring are identical to the parents
I need this answer fast ASAP.

My answer is in the picture.

Stay safe always

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⁺˚*･༓☾✧.* ☽༓･*˚⁺‧

⏩ The scattering of a beam of light through a colloidal solution in its dispersed phase is known as \(\large\boxed{tyndall \ \ effect}\).

⁺˚*･༓☾✧.* ☽༓･*˚⁺‧

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Yes, \(Br^{-}\) and \(Cl^{-}\) ions both can be positively identified through  precipitation reaction or precipitimetry.

Through titration employing precipitation reaction or precipitimetry, these two ions can both be positively identified. When exposed to Cl- and Br- ions, AgNO3 transforms into silver halides. AgNO3 with Cl- ions precipitates white because AgCl is not particularly soluble in water, whereas AgNO3 with Br- ions precipitates cream.

A very light cream precipitate results from mixing cream and white ppt.

Both halides react as described below:

\(AgNO_{3}+ XCl\)\(= AgCl_{whiteppt.}\)

\(AgNO_{3}+ XBr\) \(= AgBr_{creamppt.}\)

Now, While AgBr does not dissolve in diluted ammonia, this AgCl precipitate does to create an Ag-diammonium ion combination. Two facts, including the fact that the ppt shade is now darker than the prior pale cream, demonstrate this. As a result of the addition of an ammonia solution, it becomes less concentrated, although some cream precipitates persist.

Second, concentrated ammonia dissolves the AgBr precipitate. AgBr precipitates dissolve when cream precipitate is filtered and concentrated ammonia is added. In solution Br- ions are confirmed by this.

\(Ag^{+}+NH_{3}\) ⇄ \((AgNH_{3} )_{2} ^{+}\)

The foregoing reaction switches in the right direction after the addition of diluted ammonia solution, and more and more Ag+ ions are complexed, producing the soluble form of Ag-diammonium complex.

Brown globules are produced when CHCl3 is added to the mixture and agitated.

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Answer:

37.85 liters

Explanation:

they need 10 gallons for a month (2.5*4)

after that, convert gallons to liters (conversion to liters= 3.785)

10*3.7585= 37.85

Answer:

Water and carbon. They are important for climate, and they are important for life.

Answer:

True

Explanation:

Atomic radius can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).

Hence, the atomic radius of phosphorus is smaller than the atomic radius of magnesium. Basically, the atomic radius of phosphorus is 98 pm while the atomic radius of magnesium is 145 pm.

The final temperature of the mixed water will be approximately 311.3°C.

To solve this problem, we can use the principle of heat transfer, which states that heat will flow from the hotter object to the colder object until they reach thermal equilibrium at the same temperature.

The amount of heat lost by the hot water will be equal to the amount of heat gained by the cold water. This can be expressed mathematically as:

Qlost = Qgain

where Q is the amount of heat, and subscripts h and c denote the hot and cold water, respectively.

The amount of heat gained or lost can be calculated using the formula:

Q = m * c * ΔT

where m is the mass of the water, c is the specific heat capacity of water (4.184 J/g°C), and ΔT is the change in temperature.

Let's first calculate the amount of heat lost by the hot water:

Qlost = m_h * c * (T_h - T_f)

where T_f is the final temperature of the mixed water.

Substituting the values given in the problem, we get:

Qlost = 75.0 g * 4.184 J/g°C * (73.7°C - T_f)

Next, let's calculate the amount of heat gained by the cold water:

Qgain = m_c * c * (T_f - T_c)

Substituting the values given in the problem, we get:

Qgain = 100.0 g * 4.184 J/g°C * (T_f - 24.5°C)

Since Qlost = Qgain, we can set the two equations equal to each other and solve for T_f:

75.0 g * 4.184 J/g°C * (73.7°C - T_f) = 100.0 g * 4.184 J/g°C * (T_f - 24.5°C)

Simplifying the equation, we get:

31155 J - 311.55 T_f = 4184 T_f - 102584 J

Combining like terms, we get:

429.55 T_f = 133739 J

Solving for T_f, we get:

T_f = 311.3°C

Therefore, the final temperature of the mixed water will be approximately 311.3°C.

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Answer:

The highlighted words in the explanation.

Explanation:

A clue comes by considering the noble gas elements, the rightmost column of the periodic table. These elements—helium, neon, argon, krypton, xenon, and radon—do not form compounds very easily, which suggests that they are especially stable as lone atoms. What else do the noble gas elements have in common?

Answer:

Sn (Tin)

Explanation:

Answer:

196J, but C. at 200 J comes close.

Explanation:

Potential energy due to gravity is given by:

PEgrav = mass • g • height

where g is the acceleration due to gravity.  We'll use 9.8 N/kg (on Earth).

PEgrav = mass • g • height

PEgrav = (2 kg) • (9.8 N/kg) • (10 m)

PEgrav = 196 N*m

1 N*m = 1 Joule

PEgrav = 196 J

C. at 200 J comes close.  The solution probably used a value of g equal to 10 N/kg)

Answer:

20 J

Explanation:

The molarity when .772 moles are dissolved in .500 Liters of water is 0.0015M. The molarity when .453 moles are dissolved in .450 Liters of water is 0.001M.

The term molarity is defined as the number of moles of solute dissolved in per litre of solution. The unit of molarity is mole, which is denoted by the symbol "M".

M = Number of moles of solute / litre in solution

1. Number of moles of solute = .772 moles

so, 0.772 / 500

= 0.0015 M

2. Number of moles of solute =  .453 moles

so, .453 / 450

= 0.001 M

Thus, The molarity when .772 moles are dissolved in .500 Liters of water is 0.0015M. The molarity when .453 moles are dissolved in .450 Liters of water is 0.001M.

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To determine the number of aluminum atoms recovered and weighed, we need to consider the stoichiometry of the reaction between aluminum fluoride (AlF3) and fluorine (F2). The balanced chemical equation for the reaction is:

2 AlF3 → 2 Al + 3 F2

From the equation, we can see that for every 2 moles of aluminum fluoride that decompose, we obtain 2 moles of aluminum metal. Additionally, 3 moles of fluorine gas are produced.

Given that the volume of fluorine gas produced is 3.40 L at STP (standard temperature and pressure), we can use the ideal gas law to determine the number of moles of fluorine gas:

PV = nRT

Where P is the pressure (STP = 1 atm), V is the volume (3.40 L), n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)), and T is the temperature in Kelvin (STP = 273.15 K).

Using the ideal gas law, we can calculate the number of moles of fluorine gas:

n = PV / RT = (1 atm) * (3.40 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

Once we have the number of moles of fluorine gas produced, we know that the molar ratio between aluminum and fluorine is 2:3. Therefore, the number of moles of aluminum metal recovered will be two-thirds of the moles of fluorine gas.

To find the number of aluminum atoms, we can multiply the number of moles of aluminum by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol.

Finally, to find the weight of the aluminum metal, we need to know the molar mass of aluminum and multiply it by the number of moles.

Given the necessary input values, we can perform the calculations to determine the number of aluminum atoms recovered and the weight of the aluminum metal.

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To determine the number of aluminum atoms recovered and weighed, we need to consider the stoichiometry of the reaction between aluminum fluoride (AlF3) and fluorine (F2). The balanced chemical equation for the reaction is:

2 AlF3 → 2 Al + 3 F2

From the equation, we can see that for every 2 moles of aluminum fluoride that decompose, we obtain 2 moles of aluminum metal. Additionally, 3 moles of fluorine gas are produced.

Given that the volume of fluorine gas produced is 3.40 L at STP (standard temperature and pressure), we can use the ideal gas law to determine the number of moles of fluorine gas:

PV = nRT

Where P is the pressure (STP = 1 atm), V is the volume (3.40 L), n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)), and T is the temperature in Kelvin (STP = 273.15 K).

Using the ideal gas law, we can calculate the number of moles of fluorine gas:

n = PV / RT = (1 atm) * (3.40 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

Once we have the number of moles of fluorine gas produced, we know that the molar ratio between aluminum and fluorine is 2:3. Therefore, the number of moles of aluminum metal recovered will be two-thirds of the moles of fluorine gas.

To find the number of aluminum atoms, we can multiply the number of moles of aluminum by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol.

Finally, to find the weight of the aluminum metal, we need to know the molar mass of aluminum and multiply it by the number of moles.

Given the necessary input values, we can perform the calculations to determine the number of aluminum atoms recovered and the weight of the aluminum metal.

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The correct answer is B. Ammonia, NH3, has the smallest bond angle. The bond angle is the angle between two bonds that share a common atom. In general, bond angles depend on the repulsion between the electrons in the bonds and lone pairs of electrons on the central atom.

For the bond angles of the given molecules, we need to consider the number of bonds and lone pairs of electrons on the central atom. The general formula for the bond angle is AXnEm, where A is the central atom, X is the bonded atom, n is the number of bonded atoms, and m is the number of lone pairs of electrons. In methane and CH4, we have carbon as the central atom with four bonded hydrogen atoms. Since carbon has no lone pairs of electrons, the bond angle is the maximum possible at 109.5 degrees. Next, carbon tetrachloride, CCl4, has carbon as the central atom with four bonded chlorine atoms. As with methane, carbon has no lone pairs of electrons, so the bond angle is again 109.5 degrees.

Water, H2O, has oxygen as the central atom with two bonded hydrogen atoms and two lone pairs of electrons. The lone pairs repel the bonded hydrogen atoms, causing the bond angle to be less than the maximum at about 104.5 degrees.

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Answer:

It uses fossils to help pinpoint the ages of rocks.

Explanation:

Radiocarbon  dating can not be used  to determine the age of rocks.

Carbon dating works well only for objects that are less than 50,000 years.  Most rocks are far older than that. Over time, carbon-14 decays gradually  into nitrogen. Hence, we can not really use radiocarbon dating to determine the absolute age of a rock sample since the carbon-14 in the fossils of ancient rock samples may have completely decayed.

Answer:

Compound

Explanation:

Compounds consists of atoms of two or more different elements that are chemically bonded together.

Answer:

H₂O₂

Explanation:

Hydrogen peroxide is a typical example of a compound molecule. A compound is made up of one or more atoms that are combined together in a definite grouping.

The properties of a compound is different from those of the elements that combines to from them.

The theoretical yield of the products would be 88.0 g of \(CO_2\) and 54.0 g of \(H_2O\).

The balanced equation for the reaction of 1 mol of ethane (\(C_2H_6\)) with \(O_2\) at -135°C is:

\(C_2H_6 (g) + 3 O_2 (g) = 2 CO_2 (g) + 3 H_2O (g)\)

According to the balanced equation, 1 mole of \(C_2H_6\) reacts with 3 moles of \(O_2\) to produce 2 moles of \(CO_2\) and 3 moles of \(H_2O\).

To find the theoretical yield of the product(s), we need to know the amount of ethane that is being reacted.

Assuming that we have 1 mole of ethane (\(C_2H_6\) ), we can calculate the theoretical yield of the products as follows:

The molar mass of \(CO_2\) is:

12.0 g/mol (C) + 2(16.0 g/mol) = 44.0 g/mol

The molar mass of \(H_2O\) is:

2(1.0 g/mol) + 16.0 g/mol = 18.0 g/mol

From the balanced equation, we know that 1 mole of \(C_2H_6\) produces 2 moles of \(CO_2\) and 3 moles of \(H_2O\). Therefore, the theoretical yield of \(CO_2\) would be:

moles of \(CO_2\) = 2 x moles of \(C_2H_6\)

If we assume that we have 1 mole of \(C_2H_6\), then the theoretical yield of \(CO_2\) would be:

moles of \(CO_2\) = 2 x 1 = 2 moles

mass of \(CO_2\) = moles of \(CO_2\) x molar mass of \(CO_2\) = 2 mol x 44.0 g/mol = 88.0 g

Similarly, the theoretical yield of \(H_2O\) would be:

moles of \(H_2O\)  = 3 x moles of \(C_2H_6\)

If we assume that we have 1 mole of \(C_2H_6\), then the theoretical yield of \(H_2O\) would be:

moles of \(H_2O\) = 3 x 1 = 3 moles

mass of \(H_2O\) = moles of \(H_2O\) x molar mass of \(H_2O\) = 3 mol x 18.0 g/mol = 54.0 g

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A homogeneous mixture is a mixture where the components are uniformly distributed throughout the mixture, resulting in a uniform composition and appearance. Here are 10 examples of homogeneous mixtures:

Saltwater: When salt is dissolved in water, the resulting mixture is homogeneous, with the salt molecules evenly distributed throughout the water.

Air: The air we breathe is a mixture of gases, including nitrogen, oxygen, and carbon dioxide. These gases are evenly distributed throughout the atmosphere, resulting in a homogeneous mixture.

Sugar solution: When sugar is dissolved in water, the resulting mixture is homogeneous, with the sugar molecules evenly distributed throughout the water.

Vinegar: Vinegar is a homogeneous mixture of acetic acid and water, with the two components evenly distributed throughout the solution.

Milk: Milk is a homogeneous mixture of water, fat, protein, and sugar, with these components evenly distributed throughout the liquid.

Brass: Brass is a homogeneous mixture of copper and zinc, with the two metals evenly distributed throughout the alloy.

Gasoline: Gasoline is a homogeneous mixture of hydrocarbons and other additives, with the components evenly distributed throughout the liquid.

Blood: Blood is a homogeneous mixture of plasma, red and white blood cells, and platelets, with these components evenly distributed throughout the liquid.

Alloy steel: Alloy steel is a homogeneous mixture of iron and other metals, such as nickel, chromium, or manganese, with the metals evenly distributed throughout the alloy.

Soft drinks: Soft drinks are homogeneous mixtures of water, sugar, and other additives, with the components evenly distributed throughout the liquid.

Overall, homogeneous mixtures are common in nature and in many industrial processes, and their uniformity allows for consistent properties and behaviors.

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A- the decay of U-238 to Th-234

right on edge 2021

Answer:

A) the decay of U-238 to Th-234

:)

Explanation:

Answer:

It’s B: Monomers are forming large polymers

Explanation:

Answer:

B. Monomers are forming large polymers.

Explanation:

The final temperature of the solution is 81.95 degree c.

What degree of temperature is too much for people?

People frequently cite a 2010 study that established the maximum limit of safety to be a moisture temperature of 35 C, or 95 F at 100% humidity or 115 F at 50% humidity. At this temperature, the human body can no longer cool itself by evaporating sweat from the skin.

Briefing:

The final temperature is:

To calculate the amount of heat released or absorbed, we use the equation:   We use the equation: to calculate the amount of heat released or absorbed.

(95g)(0.885J per gm degree c) = (180)(4.184  per gm degree c)

Since T2a1=T2copper,

We can describe them as x and find x by solving for x.

T2 = 81.95 degree c.

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The concentration of the Ca(OH)₂ stock solution is 0.00511 M.

The pH of an aqueous solution of Ca(OH)₂ can be calculated using the following equation,

pH = 14 - log([Ca(OH)₂])

where [Ca(OH)₂] is the concentration of Ca(OH)₂ in moles per liter (M).

Since the solution has a pH of 14.235, we can plug this value into the equation and solve for [Ca(OH)₂]:

14.235 = 14 - log([Ca(OH)₂])

log([Ca(OH)₂]) = 14 - 14.235 = -0.235

[Ca(OH)₂] = 10^(-0.235) = 0.00513 M

The Ca(OH)₂ stock solution was diluted to a final volume of 500.00 ml by adding 91.138 ml of the stock solution to a volumetric flask and filling up to the mark with water. Therefore, the number of moles of Ca(OH)₂ in the stock solution can be calculated as:

moles of Ca(OH)₂ = concentration × volume = [Ca(OH)₂] × (91.138/1000) = 0.000467 moles

The stock solution was diluted to a final volume of 500.00 ml, so the final concentration of the Ca(OH)₂ solution is:

final concentration = moles / volume = 0.000467 moles / 0.500 L = 0.000934 M

Therefore, the concentration of the Ca(OH)₂ stock solution is:

concentration = final concentration × (final volume / initial volume) = 0.000934 M × (500.00 ml / 91.138 ml) = 0.00511 M

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Answer:

09998908

Explanation:

The density of the fish tank of rob having 50 cm length, 25 cm height and a width of 20 cm and mass of 3000 g is 0.12 g/cm³ or 1.2 x 10⁻¹ g/cm³.

What is density?

Density of a substance is the mass of substance divided by its volume. It is denoted by a Greek symbol is ρ. It is given by,

                                               ρ = m

                                                      v

where,

ρ = density of substance

m = mass of substance

v = volume of substance

Given data :

Mass = 3000 g

length = 50 cm

width = 20 cm

height = 25 cm

volume = length x width x height

volume = (50 x 20 x 25) cm³ = 25000 cm³

Substituting values in the formula,

Density =  Mass  

                Volume

Density =   3000 g  

                25000 cm³

Density = 0.12 g/cm³ or 1.2 x 10⁻¹ g/cm³

Therefore, the density of the fish tank which rob had is 0.12 g/cm³ or 1.2 x 10⁻¹ g/cm³.

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Answer:

Neodymium is a naturally occurring element that was first discovered by Austrian chemist Carl Auer von Welsbach in 1885. It was discovered in the mineral cerite, which was found in a mine in the village of Bastnäs, Sweden. Neodymium can also be produced by nuclear reactors or particle accelerators by the process of neutron capture. This isotope of neodymium is highly radioactive and has a very short half-life, making it unsuitable for most practical applications.

The pH of a 0.15 M solution of Sodium hypochlorite (NaClO) at 25°C is 6.2

Sodium hypochlorite (NaClO) is a salt of hypochlorous acid (HClO), which is a weak acid with a dissociation equilibrium:

\(HClO $\rightleftharpoons$ H$^+$ + ClO$^-$\)

The dissociation constant (Ka) of this reaction can be expressed as:

\(K_{a} = \frac{[H^{+}][ClO^{-}]}{[HClO]}\)

Taking the negative logarithm of both sides of the equation, we obtain:

\(-pK_{a} = pH - \log{\frac{[ClO^{-}]}{[HClO]}}\)

where pKa is the negative logarithm of the dissociation constant, and [ClO-]/[HClO] is the ratio of the concentrations of the conjugate base and acid.

In the case of a solution of NaClO, the hypochlorite ion (ClO-) is the conjugate base of HClO, and its concentration can be calculated from the molarity of the solution as follows:

\([ClO^{-}] = [NaClO]\)

[HClO] can be calculated from the dissociation equilibrium and the concentration of H+:

\([HClO] = \frac{[H^{+}]}{K_{a}[ClO^{-}]}\)

At 25°C, the ion product constant of water (Kw) is \(1.0 \times 10^{-14\). Therefore, we can assume that \([H^{+}] = [OH^{-}] = 1.0 \times 10^{-7}\) in pure water at 25°C.

Substituting these values into the equation for [HClO], we get:

\([HClO] = \frac{1.0 \times 10^{-7}}{K_{a}[NaClO]}\)

Substituting the values for the pKa and [NaClO], we obtain:

\(-pK_{a} &= pH - \log{\frac{[NaClO]}{10^{-7}/K_{a}}}\)

\(7.50 &= pH - \log{\frac{[NaClO]}{10^{-7}/10^{-7.5}}}\)

\(7.50 &= pH - \log{\frac{[NaClO]}{10^{-0.5}}}\)

\(7.50 &= pH + 0.5 + \log{[NaClO]}\)

\(pH &= 7.50 - 0.5 - \log{[NaClO]}\)

\(pH &= 7.00 - \log{[NaClO]}\)

Substituting the value of [NaClO] = 0.15 M, we get:

pH = 7.00 - log(0.15)

pH = 7.00 - 0.823

pH = 6.18

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Answer:i dont know thats why imon her

Explanation: