which scientist helped develop the current model of the atom which states that electrons are located in regions known as orbitals of electron clouds?

The reaction between tin (II) oxalate and lithium chloride is that it forms tin (II) chloride and lithium oxalate, which are the products of the reaction. The balanced chemical equation for the reaction is  SnC₂O₄ + 2 LiCl → SnCl₂ + Li₂C₂O4.

Tin (II) oxalate reacts with lithium chloride to form a precipitate of tin (II) chloride and lithium oxalate. The reaction between tin (II) oxalate and lithium chloride is given below.

SnC₂O₄ + 2 LiCl → SnCl₂ + Li₂C₂O4

The balanced chemical equation for the reaction is as follows:

SnC₂O₄ + 2 LiCl → SnCl₂ + Li₂C₂O4 .

SnC₂O₄ is tin (II) oxalate, while LiCl is lithium chloride.

SnCl₂ is tin (II) chloride, while Li₂C₂O4 is lithium oxalate.The products of the reaction between tin (II) oxalate and lithium chloride are tin (II) chloride and lithium oxalate. Tin (II) chloride is a white crystalline powder that is soluble in water, whereas lithium oxalate is a white solid that is insoluble in water.The reaction between tin (II) oxalate and lithium chloride is a double displacement reaction, which is also known as a metathesis reaction. When a double displacement reaction takes place, two compounds exchange their cations and anions, resulting in the formation of two new compounds.

The reaction is a double displacement reaction or metathesis reaction where two compounds exchange their cations and anions to form two new compounds.

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Answer:

\(0.00365\ cm=3.65\times 10^{-3}\ cm\)

Explanation:

Aly's teacher said some bacteria can be as small as 0.00365 cm long.

In this problem, we need to write the length of the bacteria written in scientific notation. Any number can be written in the form of scientific notation as follows :

\(N=a\times 10^b\)

a is a real no and b is an integer

In the given number, there are two zeroes before 3. We need to shift the decimal after 3. It can be done as follows :

\(0.00365\ cm=3.65\times 10^{-3}\ cm\)

Hence, this is the required solution.

The portion of the titration curve of a strong base with a strong acid is the same as the region before the endpoint is reached for a weak base titrated with a strong acid. The correct answer is Option C.

Titration refers to the process of measuring the volume of one solution required to react with a given volume of another solution completely. The titration curve is a graph that shows the change in pH during a titration.

The pH changes quickly from acidic to basic as the volume of strong base added approaches the stoichiometric point. It can be observed that the pH of the strong base solution is high, but as it is titrated with an acid, its pH decreases. The graph gradually falls as the acid is added, finally reaching a sharp rise known as the equivalence point or endpoint. As a result, the correct option is c. the portion before the endpoint is reached.

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Therefore, the estimated energies of a proton in a 5.0 fm long box are approximately:

E1 = 1.808 x 10^-13 J

E2 = 7.234 x 10^-13 J

E3 = 1.631 x 10^-12 J

The allowed energies of a particle in a one-dimensional box are given by:

E = (n^2 * h^2) / (8 * m * L^2)

Where:

E is the energy of the particle

n is the quantum number (1, 2, 3, ...)

h is the Planck's constant (approximately 6.626 x 10^-34 J*s)

m is the mass of the particle (mass of a proton = 1.673 x 10^-27 kg)

L is the length of the box (5.0 fm = 5.0 x 10^-15 m)

For n = 1:

E1 = (1^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

For n = 2:

E2 = (2^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

For n = 3:

E3 = (3^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

Now we can calculate the values:

E1 ≈ 1.808 x 10^-13 J

E2 ≈ 7.234 x 10^-13 J

E3 ≈ 1.631 x 10^-12 J

Therefore, the estimated energies of a proton in a 5.0 fm long box are approximately:

E1 = 1.808 x 10^-13 J

E2 = 7.234 x 10^-13 J

E3 = 1.631 x 10^-12 J

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There are approximately 4.45 x 10^24 atoms of iron (Fe) in a sample of 7.38 mol Fe.

To calculate the number of atoms, we use Avogadro's number (6.022 x 10^23 atoms/mol) as a conversion factor. Multiply the given amount of moles by Avogadro's number to obtain the number of atoms:

7.38 mol Fe * (6.022 x 10^23 atoms/mol) = 4.45 x 10^24 atoms Fe.

In the sample of 7.38 mol of iron, there are approximately 4.45 x 10^24 atoms of iron. This calculation is based on the concept that one mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23 particles.

Therefore, when we multiply the given amount of moles (7.38 mol) by Avogadro's number, we can determine the number of atoms in the sample.

It is important to note that Avogadro's number represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance.

This constant allows us to relate the amount of substance in moles to the number of individual particles. In the case of iron (Fe), the sample of 7.38 mol contains approximately 4.45 x 10^24 atoms.

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^ tap to see the full pic

Explanation:

you make use of the formulas

amount(mol) = number of particles ÷ 6.02 × 10^23

and

mass(g) = amount(mol) × molar mass

Molecular mass/ empirical formula mass = n

Where n is a whole number.

For the above question, n = 2

The above formula is used to calculate the formula mass of a compound.

Where n, that is the answer, should be a whole number or very close to a whole number.

Molecular mass = 220.771 g/mol

Se molecular weight =78.96

Cl molecular weight = 35

The formula mass = 78.96+35.45 = 114.41

Thus, n = 220/114 = 2

Hence value of n=2  

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The mass of sodium Tetraoxosulphate formed when 0.5 mole of sodium hydroxide react with Tetraoxosulphate acid is 35.5 grams.

0.5 m of NaOH denotes the amount of the solvent that is dissolved in 0.5 mole (20.0 g) of NaOH. 0.5 moles of NaOH (20.0 g) are dissolved in 1000 millilitres of the solution, or 0.5 M of NaOH.

Tetraoxosulphate VI acid is produced commercially using the Contact process. The Contact procedure entails the following steps. In order to purge the sulphur (IV) oxide generated of contaminants and dust that can poison the catalyst, it is combined with extra air and sent through an electric chamber.

Strong acid known as tetraoxosulphate may be used to produce synthetic colours, extract metals, serve as the electrolyte in lead-acid storage batteries, and produce synthetic and natural fibres.

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Complete question:

Calculate the mass of sodium tetraoxosulphate (vi) formed when 0.5 mole of sodium hydroxide react with tetraoxosulphate (vi) acid. (Na=23, O=16, S=32, H=1

The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.

Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.

Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.

According to the given data;

Decomposition of carbon monoxide (CO);

Oxygen produced = 3.36 g

Carbon produced = 2.52 g

We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;

Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol

Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol

Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;

0.21 mol C / (0.21 mol O) = x

Simplifying the equation, we have;

x = 1

Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.

Decomposition of carbon dioxide (CO₂);

Oxygen produced = 9.92 g

Carbon produced = 3.72 g

Following the same calculations as before;

Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol

Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol

Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;

0.31 mol C / (0.62 mol O) = y

Simplifying the equation, we have;

y = 0.5

Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.

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--The given question is incomplete, the complete question is

"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--

Approximately 35.90 grams of ice must melt to lower the water temperature to 0.0°C.

To solve this problem, we need to calculate the amount of heat that needs to be transferred from the water to the ice in order to lower the water temperature to 0.0°C.

First, let's calculate the initial heat content of the water. The specific heat capacity of water is 4.186 J/(g·K), and the mass of the water can be calculated using its density (1 g/mL) and volume (7.30 × 10^2 mL):

Mass of water = density × volume = 1 g/mL × 7.30 × 10^2 mL = 7.30 × 10^2 g

The initial heat content of the water can be calculated using the formula:

Heat content = mass × specific heat capacity × temperature change

Heat content = 7.30 × 10^2 g × 4.186 J/(g·K) × (25.0°C - 0.0°C) = 7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C

Next, we need to calculate the amount of heat that needs to be transferred from the water to the ice to lower the water temperature to 0.0°C. This heat transfer occurs during the melting of the ice.

The amount of heat required to melt the ice can be calculated using the formula:

Heat = mass of ice melted × latent heat of fusion

Let's assume that x grams of ice melts. The mass of the ice can be calculated using its density (0.92 g/mL) and volume (same as the volume of water):

Mass of ice = density × volume = 0.92 g/mL × 7.30 × 10^2 mL = 6.716 × 10^2 g

Heat = x g × 333.7 J/g

Now, we need to ensure that the heat transferred from the water to the ice is enough to lower the water temperature to 0.0°C. The heat transferred from the water to the ice is equal to the heat transferred from the water when its temperature drops to 0.0°C:

Heat content of water = Heat transferred to ice

7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C = x g × 333.7 J/g

Now, we can solve for x:

x = (7.30 × 10^2 g × 4.186 J/(g·K) × 25.0°C) / (333.7 J/g)

x ≈ 35.90 g

Therefore, approximately 35.90 grams of ice must melt to lower the water temperature to 0.0°C.

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Based on the assertion and reasons given, it can be seen that the Assertion is true, but the reason is false.

Camphor and ammonium chloride are not separated because they are volatile substances. Hence assertion is true.

Camphor on heating sublimes, only when mixed with sodium chloride so the reason is false.

The bark and wood of the camphor tree were once used to make the chemical known as camphor.

Today, turpentine oil is typically used to make camphor. The fragrance of camphor is quite distinctive. It helps with symptoms like pain and itching by stimulating the nerves, it seems.

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Answer:

0.028%

Explanation:

From the question given above, the following data were obtained:

Accepted value = 4.6026 g

Measured value = 4.6013 g.

Percentage error =..?

Thus, we can obtain the percentage error in the student's reading as follow:

Percentage error = |measured value – accepted value|/accepted value × 100

Percentage error = |4.6013 – 4.6026| / 4.6026 × 100

Percentage error = 0.0013 / 4.6026 × 100

Percentage error = 0.13/4.6026

Percentage error = 0.028%

Therefore, the percentage error in the student's reading is 0.028%

Answer:

evaporation, condensation, precipitation, interception, infiltration, percolation, transpiration, runoff, and storage.

Use one of the picture below:

The half-life of a radioisotope if 25.0 grams of an original 200. -gram sample of the isotope remains unchanged after 11.46 days is 3.82 days.

The radioactive isotopes of an element are known as radioisotopes. They can also be described as atoms with an excessive amount of energy in their nucleus or unstable neutron-proton combinations.

A radioisotope's unstable nucleus can form either naturally or as a result of atomic manipulation. Radioisotope production can take place using a cyclotron or a nuclear reactor, depending on the situation. Molybdenum-99, which has a high neutron content, can be produced most efficiently in nuclear reactors, whereas fluorine-18, which has a high proton content, can be produced most efficiently in cyclotrons.

Uranium is the most well-known illustration of a naturally-occurring radioisotope. Uranium-238 makes up 99.9% of naturally occurring uranium; the remaining 0.7% is the less stable and more radioactive uranium-235, which has three fewer neutrons in its nucleus.

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The provided statement states that a radioisotope's half-life is 3.82 days if 25.0 milligrams of a 200.0-gram initial sample of something like the isotope remain intact after 11.46 days.

An unstable chemical element that releases radiation as it breaks down and becomes more stable. Both natural habitat and then a laboratory can manufacture radioisotopes. They are used in medical treatments and imaging examinations. also called a radionuclide.

Since we now know that first phase kinetics governs radioactive decay,

Therefore, the following is the equation for the rate rule for first order kinetics:

\(k=\frac{2.303}{t} \log \frac{a}{a-x}\)

where,

k = rate constant

t = time taken for decay process  = 11.46 days

a = initial amount of the reactant  = 200 g

After the decay process, the quantity remaining is equal to 25 g.

By plugging data into the equation above, we can get the rate constant.

\(k=\frac{2.303}{11.46} \log \frac{200}{25}=0.1814\)

We now need to determine a radioisotope's half life.

Formula used : \(t_{1 / 2}=\frac{0.693}{k}\)

We obtain the half life by entering the value of "k" into this calculation.

\(t_{1 / 2}=\frac{0.693}{0.1814}=3.820\)

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The complete question is-

What is the half-life of a radioisotope if 25.0 grams of an original 200.-gram sample of the isotope remains unchanged after 11.46 days?

(1) 2.87 d

(2) 11.46 d

(3) 3.82 d

(4) 34.38 d

Answer: Lebron

Explanation: James was here

Answer:

True

Explanation:

If you look closley at the nucleus, you don't count the neutrons just the prtons which then effect the electrons.

Good luck :)

The two main methods used to increase CO2 levels in beer after fermentation are natural carbonation and forced carbonation.

Natural carbonation involves adding a small amount of sugar to the beer before bottling or kegging. The residual yeast in the beer will consume the sugar, producing CO2 as a byproduct, which will dissolve into the beer, naturally carbonating it. This process can take anywhere from a few days to a few weeks, depending on the beer style and temperature.

Forced carbonation, on the other hand, involves using a CO2 tank to directly inject carbon dioxide into the beer. The beer is placed in a closed vessel and pressurized with CO2 until the desired level of carbonation is reached. This method is much quicker and more precise than natural carbonation, but it requires specialized equipment and can be more expensive.

Both methods have their advantages and disadvantages, and many breweries use a combination of both to achieve the desired level of carbonation for their beers. The level of carbonation can greatly affect the taste and mouthfeel of the beer, so it is an important consideration for brewers to get right.

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Answer:

See explanation below

Explanation:

Sodium will react with chlorine to form sodium chloride NaCl.

Na is a group I metal with 1 valance electron to become one Na+ ion to bond with one Cl- ion

Magnesium will also react with chlorine to form magnesium chloride MgCl2

Mg is a group II metal with 2 valence electrons become one Mg2+ ion to bond with two Cl- ions.

Both Na and Mg are metals while Cl is non-metals so the bond between metal and non-metal is ionic bond.

Hope this helps.

Ionic bonds are created when two oppositely charged ions are attracted to one another by electrostatic force. A chemical element is uniquely defined by its atoms, which are tiny pieces of substance.

An atom is made up of a core nucleus and one or more negatively charged electrons that orbit it. The positively charged, comparatively hefty protons and neutrons that make up the nucleus may be present. Any elementary particle of matter with at least one proton is referred to as an atom. Examples of atoms are neon (N) and hydrogen (H) (Ne). Chemistry's fundamental building component is an atom. It is the lowest fraction of substance into which electrically charged particles cannot be released. It is also the smallest piece of substance with chemical element-like characteristics.

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Answer: D

Explanation:

Water is comprised of 2 Hydrogen atoms and 1 Oxygen atom. This gives us a total of 8 valence electrons to form bonds with.

Because Hydrogen is in first row of elements it can only hold a total of two electrons. This means each Hydrogen holds 2 electrons.

But that means there are four more electrons. VSEPR theory is basically how electron repulsion causes atoms to arrange in different ways.

There will be four electrons left on the oxygen because they can not go anywhere else. This will cause the hydrogen molecules to move away from the lone electrons and cause a bent geometry rather than a straight-line geometry.

Answer:

5.5 × 10²² formula units Al₂O₃

General Formulas and Concepts:

Chemistry - Stoichiometry

Explanation:

Step 1: Define

9.3 g Al₂O₃

Step 2: Define conversions

Avogadro's Number

Molar Mass of Al - 26.98 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al₂O₃ - 2(26.98) + 3(16.00) = 101.96 g/mol

Step 3: Convert

\(9.3 \ g \ Al_2O_3(\frac{1 \ mol \ Al_2O_3}{101.96 \ g \ Al_2O_3} )(\frac{6.022 \cdot 10^{23} \ formula \ units \ Al_2O_3}{1 \ mol \ Al_2O_3} )\) = 5.4928 × 10²² formula units Al₂O₃

Step 4: Check

We are given 2 sig figs. Follow sig fig rules.

5.4928 × 10²² formula units Al₂O₃ ≈ 5.5 × 10²² formula units Al₂O₃

A. We are aware that the reaction's rate depends on the slowest, or rate-determining, step in the overall reaction mechanism. The first step of the reaction is the one that moves the most slowly in the example reaction mechanism. As a result, just one step (Step 1) would have an impact on the reaction's rate.

As a result, the rate law for the mechanism described is given by –

Step 1.  Cl2 2Cl  (slow)  ---------k1

Step 2.  Cl + C5H10HCl + C5H9  (fast) ---------k2

Step 2.  C5H9 + Cl C5H9Cl  (fast)  ---------k3

Step 1. is the slowest step. So, the reaction rate will depend upon on the rate of Step 1 only.

Hence, the rate law for the reaction is given by –

Rate = k1 [Cl2]

B. A species that is created and then consumed in situation is referred to as an intermediate of a reaction mechanism; hence, reaction intermediates never appear in the final rate law or in the actual reaction itself. The overall reaction in this reaction will show up, and likewise will be included in the rate law, as demonstrated above.

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Answer:

1. 0.125 mole

2. 42.5 g

3. 0.61 mole

Explanation:

1. Determination of the number of mole of NaOH.

Mass of NaOH = 5 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass /molar mass

Mole of NaOH = 5/40

Mole NaOH = 0.125 mole

2. Determination of the mass of NH₃.

Mole of NH₃ = 2.5 moles

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 2.5 × 17

Mass of NH₃ = 42.5 g

3. Determination of the number of mole of Ca(NO₃)₂.

Mass of Ca(NO₃)₂ = 100 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole of Ca(NO₃)₂ =?

Mole = mass /molar mass

Mole of Ca(NO₃)₂ = 100 / 164

Mole of Ca(NO₃)₂ = 0.61 mole

Choose a fact or concept from the lesson that you can apply in your life. Describe the fact or concept, and explain how you will apply it.

Answer: For Primavera integrated science

A fact is this, we all have a lot of issues in life, but we need to stay as positive as possible about it.

Explanation:

In life a lot of bad things will happen to us. These things can be very negative at time's and make life harder. We should attempt to remain as positive about the situation as possible. This will enable us to be in a better headspace about whatever has happened to us and give us more mental room to breath.

Two heads are better than one is the phrase which means that advice from a second person can be helpful. The concept of the issues and positivity can be taken.

Negativity is the pessimism that criticizes something around a person. Positivity is the optimistic attitude or the positive approach towards a person or something.

An individual faces a lot of challenges and issues in his life that can be dealt with a positive approach. A lot of bad things occurring in a person's life can negatively affect the person making their life harder.

Being positive in a bad situation will enable a person to remain calm to solve the problems and will give him more mental peace.

Therefore, "two heads are better than one."

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a sample of trifluoroacetic acid, c2hf3o2, contains 88.9 88.9 g of oxygen, the mass of the trifluoroacetic acid sample is: 316.484 grams

The mass in grams of one mole of a chemical is its molar mass. A mole is the measurement of the number of things, such as atoms, molecules, and ions, that are present in a material. It provides you with the amount of grams per mole of a substance, to put it another way. The molar mass of a material is a bulk attribute rather than a molecular one. The fundamental units of matter are called atoms, and by joining atoms together, molecules are created. Chemists use the term "mole" because atoms, molecules, and other particles are all very tiny and require a large amount to even weigh them.

As we know,

1 mole of C₂HF₃O₂ contains 2 moles of oxygen

molar mass of C₂HF₃O₂ = 114.0 gm

atomic mass of 2 Oxygen = 32 gm

(114 / 32) = 3.56

grams of C₂HF₃O₂ = 88.9 x 3.56 = 316.484 grams

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