The property of an ancient rock that allowed scientists to determine that Earth was at least 4.3 billion years old is the radioactive decay. It is because many rocks contain radioactive isotopes of elements such as carbon and uranium.
The process of decay is random, but the rate of decay for each element is constant over time, as it does not depend on external factors. As the radioactive isotopes decay, they release particles that cause their decay to occur at a regular rate.
By measuring the relative amounts of the parent and daughter isotopes in a rock, scientists can calculate the age of the rock and therefore, estimate the age of the Earth. It is done through the method called radiometric dating. The most common type of radiometric dating is called carbon dating, which is used to date rocks that are less than 50,000 years old. However, scientists use other types of radiometric dating methods to date rocks that are much older. Therefore, radioactive decay is one of the most reliable methods that allowed scientists to determine that Earth was at least 4.3 billion years old.
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Select the number that matches the power of ten. 105 = 10-3 =
The number that matches the power of ten is given below:
10⁵ = 100000
10⁻³ = 0.001
What are the values of the numbers given in powers of 10?The value of numbers expressed in the power of ten is that number multiplied or divided by the given power or exponent of 10.
Writing numbers in powers of 10 is described as writing in standard form.
For a number written in powers of 10, if the power of ten is positive, the number is multiplied by 10 the number of times found in the power of 10. However, if the power of ten is negative, the number is divided by 10 the number of times found in the power of 10.
For example:
10⁵ = 1 * 10 * 10 * 10 * 10 * 10 * 10 = 100000
10⁻³ = 1 ÷ 10 ÷10 ÷ 10 = 0.001
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What is a net ionic equation?
when is pressure evident in daily lives?
Explanation:
When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside
Answer:
The pressure of the liquid (blood) forces the liquid to move into the syringe when its plunger is withdrawn. When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.
For the sequential deprotonations of a polyprotic acid, the equilibrium constants will typically?
For the sequential deprotonations of a polyprotic acid, the equilibrium constants will typically decrease with each successive ionization.
For explaining above statement let's take an example of polyprotic acid like phosphoric acid.
In the phospheric acid \(H_{3} PO_{4}\), after deprotonation of one hydrogen results as \(H_{2} PO_{4}^{-}\) and equilibrium constant as \(K_{1}\) . \(H_{2} PO_{4}^{-}\) donate one hydrogen results as \(H_{} PO_{4}^{-2}\) and equilibrium constant as \(K_{2}\) . Similarly, \(H_{} PO_{4}^{-2}\) donate one hydrogen results as \(PO_{4}^{-3}\) and equilibrium constant as \(K_{3}\) . The removing of hygen ion from nuetral molecule is easier than removal of hydrogen ion from ionic species So, the value of \(K_{1}\) is greater than \(K_{2}\) and value of \(K_{2}\) is greater than \(K_{3}\).
So, the equilibrium constants of polyprotic acid will typically decrease with each successive ionization.
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Ca(OH)2 is an Arrhenius ______________ and increases the concentration of __________ when added to water
Fill in the words to complete each step in liquid spill cleanup. 1.Surround the area with _____, then cover the spill. 2. Scoop up the material and place in a _____.
the complete statement in liquid spill cleanup is 1- Surround the area with barriers, then cover the spill. 2- Scoop up the material and place it in a container.
steps for liquid spill cleanup are:
Identify and assess the type of liquid spilled.
Put on appropriate personal protective equipment (PPE)
Alert others in the area and evacuate if necessary.
Surround the area with barriers, such as caution tape or cones, to prevent anyone from entering the area.
Use absorbent materials, such as sand, clay, or kitty litter, to cover the spill and contain it.
Scoop up the material and place it in a container for proper disposal.
Clean the area with a neutralizing agent if necessary.
Dispose of the waste in accordance with local and federal regulations.
Check for any remaining traces of the spill and clean if necessary.
Document the incident and make sure it is properly reported if required by regulations.
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HELP! NEED ASAP
1. A mixture of 11.23 moles of A, 26.50 moles of B, and 45.83 moles of C is placed in a one-liter container at a certain temperature. The reaction is allowed to reach equilibrium. At equilibrium, the number of moles of B is 29.445. Calculate the equilibrium.
(A)- A(g) + B(g) C(g)
(B)- SHOW ALL YOUR STEPS IN THE CALCULATIONS.
The equilibrium constant of the reaction from the calculation that has been done is 0.154
What is the equilibrium constant?The concentrations (or partial pressures) of reactants and products in chemical equilibrium for a specific chemical reaction are related by the equilibrium constant (K), a mathematical equation. It quantifies the degree to which an equilibrium has been reached in a reaction.
We have the equation of the reaction as;
A(g) + B(g) ⇔C(g)
Thus;
Keq = 45.83/11.23 * 26.50
Keq = 0.154
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calculate the ph of the buffer obtained by adding 4.0g naoh (40 g/mol) to 1.00l of 0.3m ch3cooh (pka
To calculate the pH of the reaction buffer obtained by adding 4.0g NaOH to 1.00L of 0.3M CH3COOH (pKa=4.76), we use the Henderson-Hasselbalch equation.
First, we need to calculate the concentration of CH3COOH before the addition of NaOH. The number of moles of CH3COOH in 1.00L of 0.3M CH3COOH is:moles CH3COOH = Molarity x Volume= 0.3M x 1.00L= 0.3 molesWe can use the balanced chemical equation for the reaction between NaOH and CH3COOH to find the number of moles of CH3COOH and CH3COO- after the addition of NaOH:CH3COOH + NaOH → CH3COO- + H2ONumber of moles of NaOH = mass / molar mass= 4.0g / 40 g/mol= 0.1 molesNaOH is a strong base, so it reacts completely with CH3COOH to form CH3COO- and water:NaOH + CH3COOH → CH3COO- + H2ONumber of moles of CH3COOH remaining = initial moles of CH3COOH - moles of NaOH= 0.3 - 0.1= 0.2 molesNumber of moles of CH3COO- formed = moles of NaOH= 0.1 moles.
Now we can calculate the concentration of CH3COOH and CH3COO-:[CH3COOH] = moles / volume= 0.2 moles / 1.00L= 0.2M[CH3COO-] = moles / volume= 0.1 moles / 1.00L= 0.1MNext, we can use the Henderson-Hasselbalch equation to find the pH of the buffer:pH = pKa + log [A-] / [HA]pKa = 4.76[CH3COOH] = 0.2M[CH3COO-] = 0.1MpH = 4.76 + log (0.1 / 0.2)= 4.76 - 0.301= 4.459.
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A sample of gas occupies 2.5 liters of space. How many moles of gas are there if its pressure is 1.2 atm and temperature is 25 C.
Moles of gas = 0.123
Further explanationIn general, the gas equation can be written
\(\large {\boxed {\bold {PV = nRT}}}\)
where
P = pressure, atm , N/m²
V = volume, liter
n = number of moles
R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m2, v= m³)
T = temperature, Kelvin
Volume(V) =2.5 L
Pressure(P) = 1.2 atm
Temperature(T) = 25 + 273=298 K
\(\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 2.5}{0.082\times 298}\\\\n=0.123~moles\)
If an object weighs 2,354 N on Earth, what is the objects mass?
Answer:
4.0 kg
Explanation:
M = W/g = 39.2/9.8 = 4.0 kg
sorry if its wrong-
what is the density of a rock that has a volume of 56 ml and a mass of 170 g?
Answer: The density of the rock is 3.03
Explanation:
Density formula:
P = mass/volume
= 170/56
= 3.03
Note: cannot measure density, so there is no sign beside it.
a ballon is filled with 35000 mL of helium in the morning when the temperature is 20.0 c by noon the temp has risen 45.0 c what is the new volume of the balloon
The new volume of the balloon is approximately 40,417 mL.
How to solve this problemFirst we need to use the gas law equation:
PV = nRT
Where
P = pressure (constant for this problem since the balloon is not compressed or expanded)V = volumen = number of moles of gasR = gas constantT = temperatureAssuming the number of moles of helium in the balloon remains constant, we can set up the following equation:
P1V1/T1 = P2V2/T2
Where
P1 = pressure at morning (constant)V1 = initial volume = 35,000 mLT1 = initial temperature = 20.0°C + 273.15 = 293.15 KP2 = pressure at noon (constant)V2 = final volume (what we are trying to find)T2 = final temperature = 20.0°C + 45.0°C + 273.15 = 338.15 KSimplifying the equation:
V2 = V1 × T2 / T1
Plugging in the values:
V2 = 35,000 mL × 338.15 K / 293.15 K
V2 = 40,417 mL (rounded to the nearest mL)
Therefore, the new volume of the balloon is approximately 40,417 mL.
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As part of a lab experiment, Tasha drops a metal cube into a beaker of water, as shown in the figure below. heat transfer After energy in the form of heat transfers between the substances, what is the final temperature of the water? Group of answer choices The final temperature is 25 °C because there is more water than metal. The final temperature is 50 °C because the metal warms the water to the temperature of the metal. The final temperature is between 25 °C and 50 °C because most of the thermal energy is lost to the air around the substances. The final temperature is between 25 °C and 50 °C because energy is transferred from the metal to the water.
Answer:
Explanation:ddxc
an ionic compound that is neither an acid nor a base is classified as a(n) ___________.
An ionic compound that is neither an acid nor a base is classified as a salt. Salts are formed when an acid reacts with a base, resulting in the neutralization of their respective acidic and basic properties.
In this reaction, the acid donates a proton (H+) to the base, forming water, while the remaining ions from the acid and base combine to form the salt. Salts are composed of positively charged cations and negatively charged anions. The cation is derived from a base, while the anion is derived from an acid. However, the resulting salt does not exhibit the characteristic properties of either an acid or a base. It does not donate or accept protons in solution, making it neutral in nature. Salts have a wide range of applications, including as flavor enhancers, preservatives, and components in chemical reactions and industrial processes. They can also be found naturally in minerals and are essential for various biological processes in living organisms. In summary, an ionic compound that is neither an acid nor a base is classified as a salt. It is formed through the neutralization reaction between an acid and a base and does not exhibit acidic or basic properties in solution.
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What would happen if a small amount of base were added to a buffered solution?
OA. The pH would remain about the same.
OB. The pH would remain neutral.
OC. The pH would decrease.
OD. The pH would increase.
From the following items, which is closest in size to one mole of gas at STP? A) A car. B) An elephant. C) A microwave. D) A marble.
In the given query, none of the options presented are the same size as one mole of gas at STP. At STP, one mole of petrol has a volume of 22.4 L, which is larger than a marble but smaller than a car or an elephant.
At STP (standard temperature and pressure), the temperature is 273 K and the pressure is 1 atm. One mole of an ideal gas at STP occupies a volume of 22.4 L.
To determine which of the items is closest in size to one mole of gas at STP, we need to use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of gas.
A) A car is much larger than one mole of gas at STP, so it is not the correct option.
B) An elephant is also much larger than one mole of gas at STP, so it is not the correct choice.
C) A microwave is much smaller than one mole of gas at STP, so it is not the correct option.
D) A marble is much smaller than one mole of gas at STP, so it is not the correct choice.
Therefore, none of the options provided is closest in size to one mole of gas at STP. One mole of gas at STP occupies a volume of 22.4 L, which is much larger than a marble and much smaller than a car or an elephant.
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calculate the effective nuclear charge of s and cl using the simple formula zeff = z–s. do not use slater's rules.
The effective nuclear charge of sulfur is 14, and the effective nuclear charge of chlorine is 15.
Effective nuclear charge (Zeff) is a measure of the positive charge felt by the valence electrons. The effective nuclear charge (Zeff) of s and Cl is calculated using the simple formula zeff = z – s, where z is the atomic number and s is the screening constant. Screening constant (s) is the number of electrons between the nucleus and the valence electrons that shield the valence electrons from the full nuclear charge of the nucleus.
For sulfur (S), the atomic number is 16, and there are two electrons in the innermost shell and four electrons in the second shell. So, the number of valence electrons in sulfur is 6. The screening constant of S is 2. Effective nuclear charge of sulfur = z – s= 16 - 2= 14
For chlorine (Cl), the atomic number is 17, and there are two electrons in the innermost shell and eight electrons in the second shell and seven valence electrons. Therefore, the screening constant of Cl is 2. Effective nuclear charge of chlorine = z – s= 17 - 2= 15
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Which halogen has the highest boiling point.
a.) f2
b.) cl2
c.)br2
d.) i2
Answer:
D
Explanation:
Recall that boiling points increase with stronger intermolecular forces.
Because halogens are diatomic molecules, they are nonpolar and lack the ability to form hydrogen bonds. Therefore, the only IMF they possess are London dispersion forces.
Recall that London dispersion forces increase with increasing polarizability, which is higher in larger molecules due to the increased number of electrons.
The largest halogen is iodine (I₂). Therefore, it will have the strongest IMF and hence the highest boiling point.
plz help!
Why is it important that scientists use identical twins, rather than fraternal twins or siblings in studying how the environment affects gene expression?
A student is studying a sample of neon in a container with a moveable piston (this means the container can change in size). If the sample in the container is initially at a pressure of 757.2 torr when the container has a volume of 81.4 mL, what is the pressure of the gas when the piston is moved so that the volume of the container becomes 132.5 mL? Round your answer to the nearest 0.01 and include units!
(thank you so much in advance)!
Boyle's Law, which states that at constant temperature, a gas's pressure and volume are inversely related, can be used to address this issue.
Boyle's Law says that P1V1 = P2V2.
Where: P1 = The gas's initial pressure (in torr)
V1 is the container's initial volume (in millilitres).
P2 stands for the gas's post-volume change pressure (unknown).
V2 is the revised volume of the container (in millilitres).
Let's solve for P2 by entering the provided values into the equation:
P₁ = 757.2 torr
V2 = 132.5 mL V1 = 81.4 mL
P2 = ambiguous
P₁V₁ = P₂V₂
P2 equals 757.2 torr x 81.4 mL x 132.5 mL.
P2 times 132.5 mL = 61702.08 torr * mL
61702.08 torr = P₂ * 132.5
P2 = 132.5 mL / 61702.08 torr
P₂ ≈ 465.69 torr
as a result, the gas's pressure
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Calculate the number of moles of Bromine molecules in 2.49g of Br
Answer:
0.0311 moles
Explanation:
given in pic.
Have a good day!
Contractile vacuoles are organelles that maintain water balance by pumping excess water out of some single-celled pond organisms. In humans, the kidney is an organ chiefly involved in maintaining water balance. These facts best illustrate that.
These facts serve as the best examples of how the tissues, organs, and organ systems in all living things collaborate to maintain homeostasis because contractile vacuoles are organelles that regulate water balance
Homeostasis is the term used to describe the body's need to achieve and preserve a specific state of equilibrium. A physiologist by the name of Walter Cannon first used the term in 1926. The tendency of the body to keep internal conditions, like blood sugar and temperature, at essentially constant and stable levels is known as homeostasis.
Between cells and an entire organ, there is a biological organisational level called tissue. An assembly of comparable cells and their extracellular matrix from the same origin that work together to perform a particular function is referred to as a tissue.
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Categorize each of the following reactions according to its predicted change in standard entropy of reaction. N2(g) + 02(g)- 2NO(g) 2C(s) +O,(g) 2CO(g) N2(g) + 202(9)-N204(g) 2H2(g) + O2(g)-2H2O(g)
Reaction 1 has a predicted negative change in standard entropy of reaction.
Reaction 2 has a predicted positive change in standard entropy of reaction.
Reactions 3 and 4 have predicted negative changes in standard entropy of reaction.
To categorize each reaction according to its predicted change in standard entropy of reaction, we need to consider the number of moles of gas on the reactant and product side of each equation.
1. N2(g) + O2(g) → 2NO(g)
There are 3 moles of gas on the reactant side and 2 moles of gas on the product side, so there is a decrease in the number of moles of gas. This means that the predicted change in standard entropy of reaction is negative.
2. 2C(s) + O2(g) → 2CO(g)
There is 1 mole of gas on the reactant side and 2 moles of gas on the product side, so there is an increase in the number of moles of gas. This means that the predicted change in standard entropy of reaction is positive.
3. N2(g) + 2O2(g) → N2O4(g)
There are 3 moles of gas on the reactant side and 2 moles of gas on the product side, so there is a decrease in the number of moles of gas. This means that the predicted change in standard entropy of reaction is negative.
4. 2H2(g) + O2(g) → 2H2O(g)
There are 3 moles of gas on the reactant side and 2 moles of gas on the product side, so there is a decrease in the number of moles of gas. This means that the predicted change in standard entropy of reaction is negative.
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A 0.1 mm^3 sample of human blood has approximately 6000 red blood cells. An adult typically has 5.0 L of blood. How many red blood cells are in an adult?
There are approximately 300 trillion (300,000,000,000,000) red blood cells in an adult.
To calculate the number of red blood cells in an adult, we can use the ratio of the sample size to the adult's blood volume.
Given that the sample size is 0.1 mm^3 and contains approximately 6000 red blood cells, we can determine the number of red blood cells per mm^3 by dividing the number of cells by the sample size:
6000 cells / 0.1 mm^3 = 60,000 cells/mm^3
Next, we need to convert the adult's blood volume from liters to mm^3. Since 1 L is equal to 1,000,000 mm^3, the adult's blood volume is:
5.0 L * 1,000,000 mm^3/L = 5,000,000 mm^3
Finally, we can calculate the total number of red blood cells in an adult by multiplying the red blood cell concentration (60,000 cells/mm^3) by the adult's blood volume (5,000,000 mm^3):
60,000 cells/mm^3 * 5,000,000 mm^3 = 300,000,000,000,000 cells
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Iron (II) chloride
Covalent or ionic
Answer:
ionic
Explanation:
Iron(II) chloride, also known as ferrous chloride, is the chemical compound of formula FeCl2. It is a paramagnetic solid with a high melting point. The compound is white, but typical samples are often off-white
URGENT:
In order for an element to transform into a new element, which particles must be released to change the number of protons. number of protons.
In order for an element to transform into a new element, the particles which must be released is the protons.
What us Proton?This is referred to as subatomic particle which is present in the nucleus and is positively charged. The proton and the electron must be equal in a neutral atom.
The proton is also equal to the atomic number which is why it is the particle which can be added removed to change the element. It is because a change in atomic number will automatically mean a change in the element which therefore makes it the correct choice.
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In order for an element to transform into a new element, the particles which must be released to change the number of protons is: beta particles.
What is a beta particle?A beta particle can be defined as an isotope which typically undergoes radioactive decay through the emission of a radiation with a negative one (-1) charge. This ultimately implies that, an atom of neutron becomes a proton and an electron (₀e⁻¹), and an atom of proton also becomes a neutron and a positron (⁰⁻e₁⁺) during beta decay.
Based on scientific information and records from radioactivity, we can reasonably infer and logically deduce that an atom of proton becomes a neutron and a positron during a beta decay as shown by this chemical reaction:
³H₁ -----> ³He₂ + ⁰e₋₁ + ⁰v₀
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how many moles in 85 grams of calcium
Mole present in 85 grams of calcium is 2.12 moles
It is given that
given mass of calcium = 85 grams
molar mass of calcium = 40 grams
We have to find the moles
The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12, its symbol is “mol”
moles = given mass/molar mass
moles = 85 gram/40 gram
moles = 2.12
Hence, moles in 85 grams of calcium is 2.12 moles
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A solution of NaCl was prepared in the following manner: 0.0842 g of NaCl is massed out on an analytical balance. The solid is transferred to a 25.00 mL volumetric flask. Deionized water is added to the flask such that the bottom of the meniscus is at the line. A 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask using a volumetric pipet and diluted to volume. 6. Calculate the concentration of NaCl in the resulting solution in mg/L NaCl. (answer = 67.4 mg/L) 7. Calculate the concentration of NaCl in the resulting solution using propagation of error through the calculation. Use the manufacturer's tolerance values as the absolute error. The tolerances can be found in Chapter 2 of the Harris text. Assume a Class 1 balance and Class A glassware. Treat the tolerances as random error. (answer = 67.4+0.4 mg/L) 8. Identify 2 possible sources of random (indeterminate) error. Identify 2 possible sourses of systematic (determinate) error.
Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl
To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7. Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.
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PLEASE HELP
Suppose 200.0 g of ice absorb 1255.0 J of heat. What is the corresponding temperature change? Specific heat capacity of ice is 2.1 J/gC.
Considering the definition of calorimetry, if 200.0 g of ice absorb 1255.0 J of heat, the temperature change is 2.988°C.
Definition of calorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change). So, the amount of heat that a body receives or transmits is determined by the following expression:
Q = c×m×ΔT
Where:
Q is the heat exchanged by a body of mass m.c is a specific heat substance.ΔT is the temperature variation.Temperature change in this caseIn this case:
Q= 1255 Jc= 2.1 J/gCm= 200 gΔT= ?Replacing in the definition of calorimetry:
1255 J = 2.1 J/gC× 200 g× ΔT
Solving:
1255 J ÷(2.1 J/gC× 200 g)= ΔT
2.988 °C= ΔT
Finally, the temperature change is 2.988°C.
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I need help ASAP 10 points
Answer:
the sun beams down on the pool and heats it up top to bottom the deeper the colder