Answer:
ok
Explanation:
Which properties change the composition of a substance?
A. chemical properties
B. chemical and physical properties
C. physical properties
D. neither chemical nor physical properties
Answer:
chemical properties
Explanation:
chemical properties did change the composition of substance, so it cannot go back to original anymore, such as burning, rusting, etc.
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Why does Oxygen (O - 8) have a higher ionization energy than Tellurium (Te - 52)?
The balanced equation below shows the products that are formed when pentane (C5H12) is combusted.
C5H12 + 8O2 Right arrow. 5CO2 + 6H2O
What is the mole ratio of oxygen to pentane?
1:6
6:8
8:1
5:8
The mole ratio of oxygen to pentane in the balanced equation is 8:1.
In the given equation, the coefficient in front of pentane (C5H12) is 1, indicating that 1 mole of pentane is combusted. On the other hand, the coefficient in front of oxygen (O2) is 8, suggesting that 8 moles of oxygen are needed to react with 1 mole of pentane. Therefore, the mole ratio of oxygen to pentane is 8:1.
In simpler terms, for every 1 mole of pentane that undergoes combustion, you would need 8 moles of oxygen to fully react with it and form the products mentioned in the equation. This mole ratio of 8:1 indicates the stoichiometry of the reaction, allowing us to determine the relative amounts of reactants and products involved.
The mole ratio is an essential concept in stoichiometry, helping us understand the quantitative relationships between different substances in a chemical reaction. It allows us to calculate the amounts of reactants needed or products formed based on the balanced equation. In this case, the mole ratio of 8:1 tells us that a larger quantity of oxygen is required compared to pentane for complete combustion to occur.
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if 140cm3 of methane diffuse into air in 72 sec,how long will it take 210cm3 of sulphur dioxide to diffuse under the same condition ?
Answer:
time for sulphur dioxide to diffuse is 221.05 secs
The time for sulphur dioxide to diffuse is 108 sec.
Which gas diffuses twice quickly as SO2?Sulfur dioxide has a molecular weight of sixty-four and as a result, the square root is 8. since its inversely proportional, on the way to diffuse two times as fast, the rectangular root of the molecular weight should be 4, and subsequently the molecular weight might be 16. So the solution is methane (CH4).
Which gases diffuse the fastest?The charge of diffusion for a gas is inversely proportional to the rectangular root of its molecular mass (Graham's law). The gasoline with the lowest molecular weight will effuse the fastest. The lightest, and consequently fastest, fuel is helium.
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Can someone help me with this
What is meant by "the energy of an electron is quantized"?
The quantity of electron energy can be measured.
Each electron around an atom has a discrete amount of energy.
The quantity of electron energy changes as it moves around the nucleus.
all of the above
Answer:
d: All of the above. Have a nice day!
Answer:
The answer is: All of the above
Explanation:
no draw the molecule by placing atoms on the grid and connecting them with bonds. include all lone pairs of electrons and nonbonding electrons. do not include charges.
To draw a Lewis structure, you first need to determine the number of valence electrons each atom has. Then, you can place the atoms on the grid and connect them with bonds to form the skeletal structure of the molecule. Next, you can add lone pairs of electrons to each atom to satisfy the octet rule, which states that atoms tend to bond in such a way as to achieve a full valence shell of eight electrons.
For example, let's consider the Lewis structure of water (H2O). Oxygen has six valence electrons, while each hydrogen has one. Thus, the total number of valence electrons in the molecule is 6 + 2(1) = 8.
To draw the structure, we place the oxygen atom in the center of the grid and connect it to each hydrogen atom with a single bond. We then add two lone pairs of electrons to the oxygen atom, which completes its octet. Each hydrogen atom has two electrons, satisfying its duet.
The resulting Lewis structure for water is O-H, with two lone pairs of electrons on the oxygen atom.
Overall, drawing Lewis structures is an essential skill in chemistry as it provides a visual representation of the molecule and helps predict its properties and behavior.
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Which of the following compounds in the main group is an alkaline earth metal?Question options:A) SiliconB) XenonC) SodiumD) Calcium
Explanation:
The alkaline earth metals are six chemical elements. They belong to the group 2 of the periodic table. They are: beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra)
Answer: d. calcium
what happens to the carbon dioxide produced in breaking down pyruvic acid
The carbon dioxide produced during the breakdown of pyruvic acid is a byproduct of decarboxylation and the Krebs cycle. This CO2 is expelled from the cell as waste, while the remaining compounds continue through the process of cellular respiration to generate ATP, which provides energy for the cell.
The carbon dioxide produced during the breakdown of pyruvic acid plays a crucial role in the process of cellular respiration. Pyruvic acid, a three-carbon compound, is generated through glycolysis, the first stage of cellular respiration that occurs in the cytoplasm.
When pyruvic acid enters the mitochondria, it undergoes a process called decarboxylation, facilitated by the pyruvate dehydrogenase complex. During decarboxylation, one carbon atom is removed from the pyruvic acid molecule, forming carbon dioxide as a byproduct. This CO2 is subsequently released from the cell as waste.
Simultaneously, the remaining two-carbon molecule, called acetyl CoA, combines with oxaloacetate in the Krebs cycle (also known as the citric acid cycle or TCA cycle). Throughout the Krebs cycle, the carbon molecules undergo a series of reactions, which ultimately lead to the formation of additional CO2 molecules. These CO2 molecules are also released as waste products.
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UNA ONDA SE MUEVE CON UNA FRECUENCIA DE 2 (HZ), Y SU RAPIDEZ DE PROPAGACIÓN ES DE 20 (m/s). ¿Cuál ES LA LONGITUD DE ONDA.
How do scientists classify whether or not an object is a planet?
Answer:
The International Astronomical Union defined a planet as an object that: orbits the sun. has sufficient mass to be round, or nearly round
Explanation:
A balloon containing 0.040 mol of a gas with a volume of 5.0 ml was expanded to 1.0 l. which equation should you use to find the amount of gas added? v subscript 2 equals startfraction v subscript 1 n subscript 2 over n subscript 1 endfraction. n subscript 2 equals startfraction v subscript 2 n subscript 1 over v subscript 1 endfraction. n subscript 2 equals startfraction v subscript 1 n subscript 1 over v subscript 2 endfraction.
P, R, and T are constant, then the volume is directly proportional to the mole. Then the correct option is A.
What is an ideal gas equation?An ideal gas is a theoretical composed of a set of randomly moving gas particles that interacts only through elastic collision.
Given
A balloon containing 0.040 mol of a gas with a volume of 5.0 mL was expanded to 1.0 L.
\(V_1=5\ ml\)
\(V_2=1000\ ml\)
\(n_1=0.040\ mole\)
We know the equation of the ideal gas.
\(PV=nRT\)
where P, R, and T are the constant, then
\(\dfrac{V_2}{V_1}=\dfrac{n_2}{n_1}\)
\(V_2=n_2\times \dfrac{V_1}{n_1}\)
Thus, the correct option is A.
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Answer:
answer in picture
Explanation:
3. Calculate the concentration in g/dm3 of solution of NaOH containing 0.25 mole in 1dm3
The concentration of the NaOH solution is 10.00 g/dm³.
To calculate the concentration in g/dm³ of a solution of NaOH containing 0.25 moles in 1 dm³, we need to know the molar mass of NaOH.
The molar mass of NaOH is calculated as follows:
Na (Sodium) = 22.99 g/mol
O (Oxygen) = 16.00 g/mol
H (Hydrogen) = 1.01 g/mol
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol
Now, we can calculate the concentration (C) using the formula:
C = (moles of solute) / (volume of solution in dm³)
C = 0.25 moles / 1 dm³
C = 0.25 mol/dm³
To convert moles to grams, we can multiply the molar mass by the number of moles:
Concentration in g/dm³ = (0.25 mol/dm³) * (40.00 g/mol)
Concentration in g/dm³ = 10.00 g/dm³
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based on the activity series, what are the predicted products of this reaction?
Pt (s) + H2O (l) ----->
Answer:
dk
Explanation:
Propose the structure of a compound that exhibits the following 1H NMR data.
(1) C5H10O
1.09 δ (6H, doublet)
2.12 δ (3H, singlet)
2.58 δ (1H, septet)
(2) C5H12O
0.91 δ (3H, triplet)
1.19 δ (6H, singlet)
1.50 δ (2H, quartet)
2.24 δ (1H, singlet)
(3) C4H10O
0.90 δ (6H, doublet)
1.76 δ (1H, multiplet)
3.38 δ (2H, doublet)
3.92 δ (1H, singlet)
(4) C4H8O2
1.21 δ (6H, doublet)
2.59 δ (1H, septet)
11.38 δ (1H, singlet)
The structures of the compounds are:
(1) 2-methylbutan-2-ol
(2) 2-methyl-2-propanol
(3) 3-methyl-2-butanone
(4) 3-methylbutanoic acid
The 1H NMR data provided for each compound corresponds to their specific molecular structure. In compound (1), the doublet at 1.09 δ and singlet at 2.12 δ are indicative of a methyl group near a chiral carbon, while the septet at 2.58 δ suggests a CH group attached to two different carbons.
Compound (2) exhibits a singlet at 2.24 δ due to a hydroxyl group, while the triplet at 0.91 δ and singlet at 1.19 δ indicate methyl groups. In compound (3), the multiplet at 1.76 δ and doublet at 3.38 δ show the presence of a carbonyl group, and the doublet at 0.90 δ implies two methyl groups.
Lastly, compound (4) has a doublet at 1.21 δ representing two methyl groups, a septet at 2.59 δ suggesting a CH group, and a singlet at 11.38 δ due to the carboxylic acid proton.
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019 10.0 points Which response identifies a possible y for the last-filled electron in a magnesium ION? 1. 42,0,0 2. 42,0,–1 3. 43,0,1 4. 43,3,0 5. 3,1,1 6. 42,1,1
To determine the quantum numbers of the last electron in the magnesium ion (Mg2+), we need to first determine the electronic configuration of the ion.
What are the quantum numbers of the last electron in the magnesium ion?The question is incomplete but I have to look at the electron configuration of the magnesium ion.
Magnesium (Mg) has an electronic configuration of 1s2 2s2 2p6 3s2, which means it has two electrons in the 3s orbital. When magnesium loses two electrons to form the Mg2+ ion, these electrons are removed from the 3s orbital, leaving a filled 1s orbital, filled 2s orbital, filled 2p orbital, and empty 3s orbital.
The quantum numbers of the last electron in the Mg2+ ion can be determined as follows:
Principal quantum number (n): The last electron is in the 2p orbital, so its principal quantum number is n=1.
Azimuthal quantum number (l): The azimuthal quantum number specifies the shape of the orbital and is given by the formula l = n-1. Therefore, the last electron has an azimuthal quantum number of l=1
Magnetic quantum number (m): The magnetic quantum number specifies the orientation of the orbital in space and can take integer values from -l to +l. Therefore, the last electron in the Mg2+ ion has a magnetic quantum number of m=-1, 0 or 1, since there is only one electron in the 2p orbital and it is spherically symmetric.
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mercury thermometer should not be placed in the mouth of the children why?
Answer: If a pinch of mercury is consumed you will die from it so using a mercury thermometer is very unsafe if its breaks and a child consumes that mercury.
Explanation:
Don't use one
If the glass breaks and the mercury is not properly cleaned up, the little silvery ball within a mercury thermometer might be hazardous. As the mercury evaporates, it may pollute the air around and turn dangerous to both people and animals.
Children that have been exposed to mercury have lower IQs, hearing impairments, and worse coordination.
Long-term exposure worsens and exacerbates symptoms, which may lead to personality changes or even coma.
Mercury thermometers can be replaced by a number of things:
electronic thermometersGlass thermometers with gallium tinalcohol thermometers in glassThese non-mercury fever thermometers are significantly safer and equally accurate as mercury thermometers.
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aromatic protons produce signal(s) in the range of 7-8 ppm, as a result of an effect called .
Due to a phenomenon known as diamagnetic anisotropy, aromatic protons emit signal(s) in the range of 7-8 ppm.
In aromatic compounds with resonance in the 7–8 ppm range, this impact is more prominent. A ring current is the term for the movement of the p electrons in benzene, and it induces an extra magnetic field that helps the protons. While the signals attributable to its aromatic carbons were seen in the range from 128 to 133 ppm, those for the aromatic phthalate ring protons were seen in the range from 7.63 to 7.82 ppm. ... the cis/trans-cyclohexylene CH carbon signals were detected in the range of 70.8 to 72.3 ppm.
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WILL MARK BRAINLIEST!!
Need help plsss
6.32 KJ is how much heat is given off
Write and balance this equation. Solid iron reacts with fluorine gas to produce crystalline iron(III) fluoride.
Answer:
iron+flourine.............iron flouride
Fe+F2.............FeF3
the above reaction is not balanced
now to balance this reaction
2Fe+3F2...........2FeF3
now this reaction is balanced
The balanced equation is: 2Fe + 3F2 ⇒ 2FeF3
How to balance an equation?A chemical equation needs to be balanced if you want to make the wide variety of the atoms of the reactants equal to the variety of the atoms of the goods.
Given,
Iron + fluorine ⇒ Iron Flouride
Fe + F2 ⇒ FeF3
Now to balance this reaction:
2Fe + 3F2 ⇒ 2FeF3
This reaction is balanced.
What is iron fluoride used for?
This medicine is a mixture manufactured from nutrients, iron, and fluoride. it's miles utilized in infants and youngsters to deal with or prevent deficiency because of terrible weight loss programs or low tiers of fluoride in drinking water and other sources.
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consider the lead isotope 207pb. how many electrons are in a neutral 207pb atom?
Answer:
82
Explanation:
Lead (207) has 82 protons and 82 electrons, generally. As it is neutral, there will be no change in the number of electrons as the electrons will cancel out with the number of protons, so the number of electrons equals the atomic number of 207Pb, which is 82.
draw the organic product formed when 1−hexyne is treated with h2o, h2so4, and hgso4. click the draw structure button to launch the drawing utility.
The organic product formed when 1−hexyne is treated with H₂O, H₂SO₄, and HgSO₄ will be 2-hexanone (structure attached).
This reaction is an example of an oxymercuration reaction of the organic product 1−hexyne.
Oxymercuration is shown in three steps to the right. The nucleophilic double bond attacks the mercury ion, releasing an acetoxy group. The mercury ion's electron pair attacks carbon on the double bond, generating a positive-charged mercuronium ion. Mercury's dxz and 6s orbitals give electrons to the double bond's lowest unoccupied molecular orbitals.
In the second stage, the nucleophilic H₂O attacks the highly modified carbon, freeing its mercury-bonding electrons. Electrons neutralize mercury ions by collapsing. Water molecules have positive-charged oxygen.
In the third stage, the negatively charged acetoxy ion released in the first step attacks the hydrogen of the water group, generating the waste product HOAc. The two electrons in the oxygen-hydrogen link collapse into oxygen, neutralizing its charge and forming alcohol.
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If 7.50 mL of 0.125 M HCl are added to 100 mL of the original buffer described in the lab manual (50mL of 0.300 M NH3 with 50.0mL of 0.300M NH4CL, the pKb of NH3 is 4.74)
NH3 + H2o = NH4+ + OH-
What is the concentration of NH3 in the buffer *after* the addition of the HCl?
What is the concentration of NH4Cl in the buffer *after* the addition of the HCl?
What is the pH of the buffer solution *after* the addition of the HCl?
If 7.50 mL of 0.125 M NaOH are added to 100 mL of the original buffer described in the lab manual
(50mL of 0.300 M NH3 with 50.0mL of 0.300M NH4CL, the pKb of NH3 is 4.74)
NH3 + H2o = NH4+ + OH-
What is the concentration of NH3 in the buffer *after* the addition of the NaOH?
[ Choose ] 0 M 0.00938 M 8.11 9.28 4.80 9.31 0.148 M 7.00 0.159 M 0.140 M 0.131 M
What is the concentration of NH4Cl in the buffer *after* the addition of the NaOH?
[ Choose ] 0 M 0.00938 M 8.11 9.28 4.80 9.31 0.148 M 7.00 0.159 M 0.140 M 0.131 M
What is the pH of the buffer solution *after* the addition of the NaOH?
After adding 7.50 mL of 0.125 M HCl to the buffer, the concentration of NH3 in the buffer is 0.296 M, the concentration of NH4Cl in the buffer is 0.304 M, and the pH of the buffer solution is 9.33.
After adding 7.50 mL of 0.125 M NaOH to the buffer, the concentration of NH3 in the buffer is 0.309 M, the concentration of NH4Cl in the buffer is 0.291 M, and the pH of the buffer solution is 9.41.
To find the concentration of NH3 and NH4Cl in the buffer after the addition of HCl, we can use the Henderson-Hasselbalch equation:
pH = pKb + log([NH4+]/[NH3])
Before adding the HCl, the [NH4+] and [NH3] concentrations in the buffer are both 0.15 M (since they are both 50 mL of 0.3 M solutions that were mixed together). Using the pKb of NH3 (4.74), we can calculate the pH of the buffer before adding the HCl:
pH = 4.74 + log(0.15/0.15)
pH = 4.74
After adding 7.50 mL of 0.125 M HCl to the buffer, the moles of HCl added can be calculated as follows:
moles of HCl = concentration x volume = 0.125 M x 0.0075 L = 0.0009375 moles
Since HCl completely dissociates in water, it will react with the NH3 in the buffer to form NH4Cl and H2O:
HCl + NH3 → NH4Cl + H2O
The moles of NH3 that react with the added HCl can be calculated using stoichiometry:
moles of NH3 reacted = moles of HCl added = 0.0009375 moles
Therefore, the new concentration of NH3 in the buffer can be calculated as:
[NH3] = (moles of NH3 before - moles of NH3 reacted) / total volume
[NH3] = (0.15 M x 0.1 L - 0.0009375 moles) / 0.1 L + 0.0075 L
[NH3] = 0.296 M
Similarly, the new concentration of NH4Cl in the buffer can be calculated as:
[NH4Cl] = (moles of NH4Cl before + moles of NH4Cl formed) / total volume
[NH4Cl] = (0.15 M x 0.1 L + 0.0009375 moles) / 0.1 L + 0.0075 L
[NH4Cl] = 0.304 M
To calculate the new pH of the buffer solution, we can use the Henderson-Hasselbalch equation again:
pH = pKb + log([NH4+]/[NH3])
pH = 4.74 + log(0.304/0.296)
pH = 9.33
For the addition of NaOH, the same calculations can be performed, but in this case, NaOH reacts with NH4+ to form NH3 and H2O:
NaOH + NH4+ → NH3 + H2O + Na+
The moles of NaOH added can be calculated as:
moles of NaOH = concentration x volume = 0.125 M
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What are the names, symbols, and atomic numbers of the nonmetal elements that are NOT gasses?
ammonia gas and oxygen gas react to form water vapor and nitrogen monoxide gas. what volume of nitrogen monoxide would be produced by this reaction if 9.89 of oxygen were consumed?
4.20325g of oxygen was used.
The reaction described is represented chemically by the equation 4NH3 + 5O2 = 4NO + 6H2O.
What is ammonia gas?Ammonia produced by industry is used as fertilizer in agriculture to the tune of 80%. In addition to these uses, ammonia is made into polymers, explosives, textiles, insecticides, dyes, and other chemicals. It is also used to purify water sources.
As a result, 4 moles of NH3 and 5 moles of O2 react.
The molar mass of 1 mole of oxygen is 2 * 16 = 32g.
5 moles of oxygen are equal to 5 * 32, or 160g.
68g is equal to 4 (14 + 3*1) moles of NH3.
68g of NH3 reacts with 160g of O2 as a result.
However, we only have 9.89 g of oxygen.
68g and 160g interact.
9.89 and Xg react to form 4.20325g (Xg = 68*9.89/160).
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What is the molar concentration a a 12 % sodium chloride solution (MW 58.5)
The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.
To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.
First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.
In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.
To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.
We can start by calculating the number of moles of sodium chloride in 12 grams:
Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride
Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles
Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:
Volume of solution = mass of solution / density
Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L
Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:
Molar concentration = moles of solute / volume of solution
Molar concentration = 0.205 moles / 0.1 L = 2.05 M
Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.
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Conversion of 1 mol of acetyl-CoA to 2 mol of CO2 and CoA via the citric acid cycle results in the net production of:
a. 1 mol of citrate.
b. 1 mol of FADH2.
c. 1 mol of NADH.
d. 1 mol of oxaloacetate.
e. 7 mol of ATP.
The net production of 1 mol of acetyl-CoA to 2 mol of CO2 and CoA via the citric acid cycle results in the production of 1 mol of oxaloacetate. (D)
This is because oxaloacetate condenses with acetyl-CoA to form citrate, which then undergoes several reactions, producing energy in the form of ATP, reducing equivalents (NADH and FADH2), and regenerating oxaloacetate.
The citric acid cycle, also known as the Krebs cycle, is a sequence of chemical reactions that occurs in the mitochondria of cells. The cycle starts with the entry of acetyl-CoA and ends with the production of CO2, ATP, and reducing equivalents (NADH and FADH2).
Acetyl-CoA is first converted to citrate, which is then converted to isocitrate. Isocitrate undergoes oxidative decarboxylation, producing α-ketoglutarate and CO2. α-Ketoglutarate is then converted to succinyl-CoA, which is converted to succinate, fumarate, and malate, respectively.
Malate is then oxidized to produce oxaloacetate, which can condense with another acetyl-CoA to start the cycle again.The cycle produces a net yield of 1 ATP, 3 NADH, 1 FADH2, and 1 oxaloacetate for each acetyl-CoA that enters the cycle.
The NADH and FADH2 produced by the cycle are then used in oxidative phosphorylation to generate ATP, which is the main source of energy for the cell.(D)
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What are epimers?
How are glucose and manose epimers?
Please Help!
Answer:
Epimers are carbohydrates which vary in one position for the placement of the -OH groupExplanation:
they have a specific type of stereoisomers which have multiple stereo center's but differ from one another, they differ from each other by configuring at the c-2" atom . so, they are epimershow can you change the chemical equilibrium to benefit the company? what benefits will be realized? 15px
The benefits that companies can realize from altering chemical equilibria depend on the specific chemical reactions involved. One benefit is an increase in the yield of desired products, which can lead to increased profits. Another benefit is the ability to minimize waste by increasing the efficiency of the reaction.
Chemical equilibrium refers to a dynamic balance between the forward and backward reactions of a chemical process that takes place at a constant temperature.
As a result, it is critical for chemical processes and has a number of uses in industry.
The degree of conversion of a chemical reaction can be changed by altering the temperature, pressure, and concentration of the reactants.
This method can be utilized to alter the equilibrium of a chemical reaction. By eliminating or lowering the concentration of one of the reactants, a chemical reaction can be pushed to move forward. In addition, by increasing or decreasing the pressure of the system, a chemical reaction can be altered.
Changes in temperature can also affect the chemical reaction rates and equilibrium position.
Additionally, changing the equilibrium can lead to an increase in product purity by minimizing the presence of impurities.Overall, altering the chemical equilibrium can be a powerful tool for companies to improve their efficiency and profitability.
However, it must be used carefully to ensure that any changes made do not have unintended negative consequences.
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The mass of one mole of any substance: is the same for all elements but not molecules is equal to 6. 02 x 10 23 g is the same for all elements and molecules is equal to the sum of the atomic masses of every atom in the formula.
The mass of one mole of any substance: is equal to the sum of the atomic masses of every atom in the formula.
As far as we are aware, a substance always includes a 6.0233*10^23 number of atoms per mole.
Additionally, every element and every molecule has a different mass for one mole of any given compound.
Atomic mass units are equal to the mass of one mole of any substance. Alternately, we could say that it equals the total of the atomic masses of all the atoms in the formula.
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The question was incomplete. Check below the complete question.
The mass of one mole of any substance:
A.is equal to 6.02 x 1023 g
B.is equal to the sum of the atomic masses of every atom in the formula
C.is the same for all elements but not molecules
D.is the same for all elements and molecules
Answer : The correct option is, (B) is equal to the sum of the atomic masses of every atom in the formula.
Explanation :
As we know that, 1 mole of substance always contains number of atoms.
And the mass of one mole of any substance is different for all the elements and the molecules.
The mass of one moles of any substance is equal to the atomic mass unit. Or, we can say that it is equal to the sum of the atomic masses of every atoms in the given formula.
For example : The mass of one moles of water is, 18 gram/mole.
As the atomic mass of hydrogen and oxygen are, 1 g/mole and 16 g/mole. So, the mass of one moles of water is, 2(1 g/mole) + 16 g/mole = 18 g/mole.
Hence, the correct option is, (B) is equal to the sum of the atomic masses of every atom in the formula.
I need help asap!!! At least with the first part
Answer:
The correct answer -
a. Cd and Pb(NO3)2
b. Redox reactions
c. Pb and Cd(NO3)2
Explanation:
This is the reaction known as the redox or reduction-oxidation reaction of metals. In this particular reaction, there are two reactants Cadmium (III) in solid-state and lead (II) nitrate in the aqueous state. At the end of this reaction, the products that we get are lead (II) in solid-state and Cadmium (III) nitrate in the aqueous state.
cadmium (s)+ lead nitrate (aq) = lead (s) + cadmium nitrate (aq)
Cd (s) + Pb2+(aq) → Pb(s) + Cd2+(aq)
Here, Oxidizing agent is Pb2+ and the reducing agent is Cd.