Which product of photosynthesis is the food?

Oxygen

Carbon Dioxide


Water


Glucose​

The initial pressure exerted on the balloon was 8 atmospheres.

To find the initial pressure exerted on the balloon, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when temperature is constant. The formula for Boyle's Law is P1V1 = P2V2, where P1 and V1 represent the initial pressure and volume, and P2 and V2 represent the final pressure and volume.

In this case, we are given that the initial volume (V1) is 14 L and the final volume (V2) is double the initial volume (2 x V1). We are also given that the final pressure (P2) is 4 atmospheres. We need to find the initial pressure (P1).

Using the formula P1V1 = P2V2 and plugging in the given values, we have:

P1 * 14 = 4 * (2 * 14)

P1 * 14 = 4 * 28

P1 * 14 = 112

To isolate P1, we divide both sides of the equation by 14:

P1 = 112 / 14

P1 = 8

It's important to note that the unit of pressure in this case is atmospheres, as stated in the question. If the pressure unit had been different, appropriate unit conversions would have been necessary.

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Mendel's first generation pea plants with purple flowers would have had two alleles for flower color.

Alleles are different versions or variants of a gene that occupy the same position, or locus, on a chromosome. Each individual inherits two alleles for each gene, one from each parent, which can be either the same (homozygous) or different (heterozygous). These alleles can have different effects on the organism's phenotype (observable trait) and can be dominant or recessive, with dominant alleles masking the expression of recessive ones. For example, in humans, the gene for eye color has different alleles that produce different colors such as brown, blue, or green. The specific combination of alleles that an individual inherits determines their genotype, which in turn influences their phenotype. The study of alleles and their inheritance patterns is a fundamental concept in genetics and has important applications in fields such as medicine, agriculture, and evolutionary biology.

Here,

However, the specific alleles cannot be determined from this information alone. According to Mendel's laws of inheritance, each individual inherits two alleles for each trait, one from each parent. These alleles can be either the same (homozygous) or different (heterozygous). If the two alleles are different, one may be dominant and determine the organism's phenotype (observable trait), while the other may be recessive and not expressed in the phenotype. In the case of Mendel's purple-flowered pea plants, the specific alleles responsible for the purple flower color would have been determined through further experimentation and analysis.

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The molarity of the diluted solution is 0.33 M

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 0. 5 M

Volume of stock solution (V₁) = 100 mL

Volume of diluted solution (V₂) = 100 + 50 = 150 mL

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

0.5 × 100 = M₂ × 150

50 = M₂ × 150

Divide both side by 150

M₂ = 50 / 150

Therefore, the molarity of the diluted solution is 0.33 M

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The correct options that will result in mole are option B, C, and H

To know the options that will result in mole, do the following:

Ideal gas law states as follow:

PV = nRT

Where

PV = nRT

Make n the subject by dividing both sides by RT

n = PV / RT (option B)

Mole, mass and molar mass are related according to the following formula:

Mole = mass / molar mass (option C)

Molarity is defined as mole per unit volume as shown below:

Molarity = mole / volume

Make mole the subject by cross multiplying.

Mole = Molarity × volume (option H)

Thus, from the above illustrations, we can conclude that the correct options which will result in mole are option B, C, and H

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Answer:

the boiling point of solution at 3 decimal point is 100.329०C Ans.

Explanation:

given data -

molality of Nacl = 0.321 m

molal boiling point elevation constant (Kb) =0.512०C/m

# formula of change of boiling point of sample =

∆ Tb =i × Kb × m

Kb = molal boiling point of elevation constant

m = molality

i = vont's hoff factor.

Nacl is strong electrolyte and its 100% dissociate so the value of i for Nacl is 2

put value in the formula

∆ Tb = 2 × 0.512 ०C/m × 0.321m

= 0.3287

= 0.329०C

∆Tb = T'b - Tb

T'b = boiling point of solution

Tb= boiling point of solvent( water)

0.329०C = T'b - 100०c ( boiling point of water = 100०C)

T'b = 0.329०C + 100०C

= 100.329०C

hope this helps

Answer:

is there a picture or something?

Explanation:

Explanation:

Your question is incomplete please update it.

The ionization of the following acids can be represented as:

Tetraoxosulphate (VI) Acid (\(H_{2}SO_{4}\)) ionizes as H+ and SO4^2- ions.

Trioxonitrate (V) Acid (\(HNO_{3}\)) ionizes as H+ and \(NO_{3-}\) ions.

Ethanoic Acid (\(CH_{3}COOH\)) ionizes as H+ and \(CH_{3}COO^{-}\) ions.

Tetraoxosulphate (VI) Acid, also known as sulfuric acid (\(H_{2}SO_{4}\)), ionizes as follows:

\(H_{2}SO_{4}\) → \(H+\) + \(SO_{4}^{2-}\)

In this reaction, sulfuric acid donates two hydrogen ions (H+) to the solution, forming sulfate ions (\(SO_{4}^{2-}\)).

Trioxonitrate (V) Acid, commonly known as nitric acid (\(HNO_{3}\)), ionizes as follows:

\(HNO_{3}\) → \(H+_{}\) + \(NO_{3-}\)

Nitric acid dissociates to release one hydrogen ion (\(H+\)) and a nitrate ion  (\(NO_{3-}\)).

Ethanoic Acid, also known as acetic acid (\(CH_{3}COOH\)), ionizes as follows:

\(CH_{3}COOH\) → H+ + \(CH_{3}COO^{-}\)

Acetic acid donates a hydrogen ion (H+) to the solution, forming an acetate ion (\(CH_{3}COO^{-}\)).

In all cases, the acids dissociate in water, producing hydrogen ions (H+) as positively charged ions and their corresponding anions. The hydrogen ions are responsible for the acidic properties of these substances, while the anions contribute to the overall charge balance in the solution. The ionization of acids allows them to conduct electricity in aqueous solutions and react with other substances.

The question was incomplete. find the full content below:

Indicate the ionization of the following acids,

Tetraoxosulphate (VI) Acid

Trioxonitrate (V) Acid

Ethanoic Acid.​

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0.6 is the equilibrium constant for the given reaction.

To calculate the equilibrium constant (K) for the given reaction, we need to use the molar concentrations of the reactants and products at equilibrium. The equilibrium constant expression is given by:

\(K= [H_{2}O]^{2} / ([H_{2}^{2} * [O_{2}])\)

Given the moles of H2, O2, and H2O in the 8.1 L container, we can convert them to molar concentrations by dividing the number of moles by the volume:

[H2] = 1.83 moles / 8.1 L

[O2] = 2.33 moles / 8.1 L

[H2O] = 3.95 moles / 8.1 L

Substituting these values into the equilibrium constant expression, we have:

K = \((3.95 / 8.1)^{2}\) / (\((1.83 / 8.1)^{2}\) * (2.33 / 8.1))

Evaluating this expression and rounding to one decimal place, we find the equilibrium constant to be:

K ≈ 0.6

Therefore, the equilibrium constant for the given reaction is approximately 0.6.

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Answer:

Le Châtelier's principle states that when a chemical system at equilibrium is distributed by a change in  conditions, the equilibrium position will shift in a direction that tends to counteract  the change.

Therefore, when there is a change in pressure, the equilibrium will  counteract  the change by reducing/increasing the pressure through adjusting the no. of moles of gas.

Note: At constant temperature and volume the pressure of a gas is directly proportional to the number of moles of gas.

For example, when there's an increase in total pressure, the equilibrium position will shift to the side with a smaller no. of moles of gas so as to reduce the pressure.

Answer:

The equilibrium would shift to reduce the pressure change

Explanation:

Answer:

Isotopes are the atom of an element that have different numbers of neutrons but have a similar number of protons and electrons. The difference in the number of neutrons between the various isotopes means that various isotopes have different masses.

Explanation:

The oxidation number of Ag in Ag2O is +1.

In Ag2O, there are two silver atoms (Ag) and one oxygen atom (O). Oxygen is known to have an oxidation number of -2 in most compounds. Since the compound is neutral, the sum of the oxidation numbers of all the atoms must equal zero.

Therefore, the oxidation numbers of the two silver atoms must add up to +2 to balance out the -2 oxidation number of the oxygen atom. Since there are two silver atoms, each silver atom must have an oxidation number of +1 to yield a total oxidation number of +2 for the compound.

In Ag2O, the silver atoms lose one electron each to form Ag+ ions. This results in an oxidation number of +1 for each silver atom. The oxygen atom gains two electrons from the silver atoms to achieve a stable octet configuration, resulting in an oxidation number of -2 for the oxygen atom. The compound Ag2O is formed through the transfer of electrons, with each silver atom exhibiting an oxidation number of +1.

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Answer:

1.used to seperate solids from liquids, and is a act of pouring a mixture onto a membrane this allows the passage of liquid and results in the collection of a solid

2. the solution would passed through without losing and solids

3 would allow them to dry or on further hearing decompose

Explanation:

Answer:

May i ask what is the question?

Explanation:

The empirical formula tells us how many atoms of each element are in a molecule regardless of the structure of the molecule, that is, regardless of which element is bonded to which element or what type of bond there is. It is the simplest way to represent a molecule.

As far as I can see the molecule C6H12 is already represented by its empirical formula, so in this case, you don't have to use any formula. You know that there are 6 atoms of carbon and 12 atoms of hydrogen, that is the information that the empirical formula gives.

So, the empirical formula for C6H12 is C6H12

Answer:

The smaller numbers that result from measuring with larger units are easier to use .

That’s the one, good luck!

The smaller numbers that result from measuring with larger units are easier to use.

Light year is a unit of astronomical distance that measures the distance traveled by light in one year. The distance between stars can also be measured using parsecs.

The equivalent of this distance in various units is written as follows;

Using light year to represent the unit of distance is more concise because big measurement can be represented easily with small numbers using this large unit.

Thus, we can conclude that the smaller numbers that result from measuring with larger units are easier to use.

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The perchloric acid solutions has a concentration of 4.66 mol/L. How so much solute has been absorbed in the solvent is indicated by the solution's level of concentration.

The percentage of a material, like salt, that is present in a specific volume of a liquid or tissue, like blood. Less water is present, and the material becomes more concentrated. Whenever a person doesn't consume sufficient amounts of water, for instance, the salt concentration in their urine may increase.

Ba(OH)2 moles equal volume times concentration, or 23.4 mL times 0.100 mol/L, or 0.00234 mol.

We can deduce from the equation that m2 m of HClO4 react including one mole pf Ba(OH)2. Hence, the amount of moles of Concentrated h2so4 in the 4.66 mL aliquot could be calculated as

0.00234 mol Ba(OH)2 divided by 1 equals moles of HClO4. (1 mol Ba(OH)2 / 2 mol HClO4) 0.0217 mol is equal to (1 L / 1000 mL) (4.66 mL / 1)

The concentration of a perchloric acid can finally be determined as follows:

HClO4 concentration is calculated as follows: moles per liter = 0.0217 mol / 4.66 mL = 4.66 mol/L

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Answer:

b. In equilibrium with the liquid phase, the pressure exerted by a gas.

Explanation:

When a liquid is warmed up to a temperature , it starts vaporising . The liquid is turning into gas and gas is turning into liquid at different rates  . Initially the rate of former is higher but gradually the difference of rate between them decreases to zero . At this point the rate of conversion of liquid into gas and rate of conversion of gas into liquid becomes equal  . This is called dynamic equilibrium point .

If we change the temperature , the equilibrium gets disturbed .

At this point the pressure exerted by the gas is called the vapour pressure of the liquid .

So option b ) is correct .

At the equilibrium point, the pressure exerted by the gas molecules to the liquid molecules has been termed the Vapor pressure. Thus, statement b is correct.

The vaporization has been the process of conversion of liquid to the gaseous state with the rise in temperature. The liquids attaining a certain temperature have been vaporized into the gaseous state.

Initially, the gas phase has been less in concentration, thus the rate of formation of gas has been greater.

After a certain amount of time, the gas phase starts to cool down and converts to the liquid state. The rate of formation of the liquid has been slower.

The time when the rate of formation of liquid, and the rate of formation of gas has been equal is termed as the equilibrium point. At the equilibrium point, the pressure exerted by the gas molecules to the liquid molecules has been termed the Vapor pressure.

Thus, statement b is correct.

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The percent by mass of the carbon is 30.4%.

The term percentage has to do with the ratio of the mass of a particular atom to the total mass of the compound multiplied by one hundred. Thus the first step is to find the total mass or the molar mass of the compound.

Molar mass = 40 + 2(2(12) + 3(1) + 2(16))

= 40 + 2(24 + 3 + 32)

= 40 + 2(59)

= 40 +118

= 158

Thus the mass of carbon is;

4(12)/158 * 100/1

= 30.4%

Thus carbon is only about 30.4% by mass of the compound.

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Based on the given half-life, the amount of time it takes for 3/4 of a radioactive sample of an isotope of bromine to decay is 33 hours.

The time needed for a quantity to decrease to half of its initial value is known as the half-life. In nuclear physics, the phrase is frequently used to indicate how rapidly unstable atoms decay radioactively or how long stable atoms last.

Any substance that contains unstable atoms that release ionizing radiation during their natural decay is considered radioactive material.

Given the half-life of the radioactive sample of an isotope of bromine to be 16.5 hours. The amount of time it takes for 3/4 of a radioactive sample of an isotope of bromine to decay is calculated as follows:

After one half-life, half of the sample remains, and half decays

After two half-lives, 1/4 of the sample remains, and 3/4 decays

The time for two half-lives = 16.5 hours * 2

The time for two half-lives = 33 hours.

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Answer:

40

Explanation:

120 - 80 = 40

Answer:

the answer is 4.0moles

Explanation:

1mole of O2 produce 2moles of H2O/x mole will produce 8.0moles of H2O then the answer is 4.0moles.

The mass of carbon dioxide, CO₂ dissolved in the alcoholic drink, given that 216.0 g of H₂O and 9.2 g of ethanol is bottled by it is 49.72 grams

First, we shall determine the mole of 216.0 g of H₂O and 9.2 g of ethanol. Details below:

For H₂O

Mole = mass / molar mass

Mole of H₂O = 216 / 18

Mole of H₂O = 12 moles

For C₂H₅OH

Mole = mass / molar mass

Mole of C₂H₅OH = 9.2 / 46

Mole of C₂H₅OH = 0.2 mole

Next, we shall obtain the mole of CO₂. Details below:

Mole fraction of H₂O = Mole of H₂O / total mole

Total mole = Mole of H₂O / Mole fraction of H₂O

Total mole = 12 / 0.9

Total mole = 13.33

But

Total mole = mole of H₂O + mole of C₂H₅OH + mole of CO₂

13.33 = 12 + 0.2 + mole of CO₂

13.33 = 12.2 + mole of CO₂

Collect like term

Mole of CO₂ = 13.33 - 12.2

Mole of CO₂ = 1.13 mole

Finally, we shall determine the mass of CO₂. Details below:

Mass = Mole × molar mass

Mass of CO₂ = 1.13 × 44

Mass of CO₂ = 49.72 grams

Thus, we can conclude that the mass of CO₂ dissolved is 49.72 grams

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The percent yield of the reaction : 89.14%

Reaction of Ammonia and Oxygen in a lab :

4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

\(\dfrac{80}{17}=4.706\)

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\(\tt \dfrac{120}{32}=3.75\)

Mol ratio of reactants(to find limiting reatants) :

\(\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)\)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\(\tt \dfrac{6}{5}\times 3.75=4.5\)

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\(\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%\)

9.77 litres of NO2 are generated on average.

The balanced equation for the breakdown of N2O5 is as follows:

\(2N_2O_5(g) -- > 4NO_2(g) + O_2(g)\)

determine how many moles of N2O5 decompose:

\(V(N_2O_5) / Vm = n(N_2O_5)(N_2O_5)\)

where V(N2O5) = 4.86 dm3 is N2O5's volume and Vm(N2O5) is N2O5's molar volume under the circumstances stated in the ideal gas law:

\((R*T)/P = Vm = V/n\)

when the gas constant R is used.

the kelvin scale of temperature, T

The pressure is P.

The ideal gas law:

\(n(N_2O_5) = V(N2O5) / Vm(N_2O_5) = 4.86 dm3 / (24.46 L/mol) = 0.1982 mol\)

the number of moles of NO2 is:

\(n(NO_2 = 4/2 * n(N_2O_5) = 0.3964 mol\)

then,

\(n(NO_2 = 4/2 * n(N_2O_5) = 0.3964 mol\)

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250 L of 5.0% w/v glucose solution can be prepared using 125 g of glucose.

w/v = [ mass of solute (g) / volume of solution (mL) ] × 100

5.0 % w/v = [ 125 g / volume of solution (mL) ] × 100

volume of solution (mL) = [ 125 g / 5.0 % w/v ] x 100

volume of solution (mL) = [ 125 g / (5.0 / 100) ] x 100

volume of solution (mL) = [ 125 g / 0.05 ] x 100

Answer:

\(\Delta S_{source}>-1.204\frac{kJ}{K}\)

Explanation:

Hello!

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy:

\(s_1=s_{f,175kPa}+q*s_{fg,175kPa}\\\\s_1=1.4850\frac{kJ}{kg*K} +0.1*5.6865\frac{kJ}{kg*K}=2.0537\frac{kJ}{kg*K}\)

Now the entropy at the final state given the new 40-% quality:

\(s_2=s_{f,150kPa}+q*s_{fg,150kPa}\\\\s_2=1.4337\frac{kJ}{kg*K} +0.4*5.7894\frac{kJ}{kg*K}=3.7495\frac{kJ}{kg*K}\)

Next step is to compute the mass of steam given the specific volume of steam at 175 kPa and the 10% quality:

\(m_1=\frac{0.028m^3}{(0.001057+0.1*1.002643)\frac{m^3}{kg} } =0.274kg\\\\m_2=\frac{0.028m^3}{(0.001053+0.4*1.158347)\frac{m^3}{kg} } =0.0603kg\)

Then, we can write the entropy balance:

\(\Delta S_{source}+\frac{Q}{T_1} -\frac{Q}{T_2} +s_2m_2-s_1m_1-s_{fg}(m_2-m_1)>0\)

Whereas sfg stands for the entropy of the leaving steam to hold the pressure at 150 kPa and must be greater than 0; thus we plug in:

Which is such minimum entropy change of the heat-supplying source.

Best regards!

Answer:56%

Explanation:

In the dewpoint chart when you line it up it ends up at 56%

The relative humidity of the air when the dry temperature is about 4 degrees and the dew point is about -4 degrees C is 56%. Hence option  4 is correct.

The dew point is the temperature at which the air needs to be colled at a ta constant pressure in order to have an RH of 100%. The dew point is minus four degrees and the RH of the air is 4 degrees.

For the forces to initiate the air must get cooler and a constant addition of water pressure should be there. Thus substrating the temperature of the wet bulb, putting the thermometer on the dry bulb, and making use of the RH chart tells us that RH is 56%

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Answer:

The real answer is carbon dioxide. they breath carbon and let out oxygen for us to breath

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1, depending on which rate was used to calculate it.

The rate of the reaction is given by the equation:

Rate = -k[A]

where k is the rate constant and [A] is the concentration of the reactant.

Rate at t=140 s:

Rate = (8.00×10−2 M - 0 M) / (140 s - 0 s)

= 5.71×10−4 M/s

Rate at t=400 s:

Rate = (4.00×10−2 M - 0 M) / (400 s - 0 s)

= 1.00×10−4 M/s

Since this is a zero-order reaction, the rate of the reaction is constant, and we can use either rate to calculate the rate constant:

k = Rate / [A]

Using the rate at t=140 s:

k = 5.71×10−4 M/s / 8.00×10−2 M = 7.14×10−3 s−1

Using the rate at t=400 s:

k = 1.00×10−4 M/s / 4.00×10−2 M

= 2.50×10−3 s−1

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1.

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