Which process is an example of a physical change?
burning
rusting
flattening
decomposing

The answer is a. Short stroke filing.A flat surface may be obtained by the process is Short stroke filing.

Short stroke filing is the process of filing a flat surface. It is an iterative process that involves filing only a small amount of material in each stroke of the file. The file is moved in a back-and-forth motion, filing only on the forward stroke and skipping the return stroke. This process eliminates the need for filing multiple times in the same area, resulting in a smoother and flatter surface.This process involves filing in small, controlled strokes, in one direction only. To get the best results, it is important to use a file that is appropriate for the material being worked on and to keep the strokes short and consistent.

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The answer is a. Short stroke filing.A flat surface may be obtained by the process is Short stroke filing.

Short stroke filing is the process of filing a flat surface. It is an iterative process that involves filing only a small amount of material in each stroke of the file. The file is moved in a back-and-forth motion, filing only on the forward stroke and skipping the return stroke. This process eliminates the need for filing multiple times in the same area, resulting in a smoother and flatter surface.This process involves filing in small, controlled strokes, in one direction only. To get the best results, it is important to use a file that is appropriate for the material being worked on and to keep the strokes short and consistent.

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The equation U = qV can be used to calculate the change in potential energy, where q is the proton's charge and V is the difference in voltage or electric potential.

We utilise the equation V = Ed, where E is the electric field strength and d is the distance travelled in the field, to determine V. We get V = E(5-2) = E * 3 and U = qV = q * E * 3 when the given values are substituted.Electric Potential Difference (V or V): In an electric field, the amount of energy needed to transport a charge from one place to another is known as the electric potential difference. It is frequently represented by the symbol V and has volt-based units (V).

(E) Electric Field Strength the strength of the electric field

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ANSWER:

10.58 Nm

STEP-BY-STEP EXPLANATION:

Given:

Area (A) = 2.936 m²

Current (i) = 6.488 A

Magnetic field (B) = 1.108 T

Angle (θ)= 59.914°

To calculate the torque we must resort to the following formula:

We need to know the magnetic moment, as follows:

In this way we can calculate the torque:

Therefore, the magnitude of the torque on the loop is 10.58 Nm

Answer:

F = M ω^2 R     is the centripetal force on the ball

f = 7 / 10 = .70 / sec      revolutions / sec

ω = 2 pi f = 4.40 / sec

ah = F / m = 4.4^2 * 2 = 38.7 m/s^2

horizontal acceleration = 38.7 m/s^2

vertical acceleration = 9.80 m/s^2

a = (38.7^2 + 9.8^2)^1/2 = 39.9 m/s^2    total acceleration

The amplitude, restoring force and speed of an object undergoing simple harmonic  motion may have maximum magnitudes at the same instant of time.

Simple harmonic motion is a regular repeating motion. The acceleration of a simple harmonic motion is always directed towards the center of the motion.

There are three  quantities related to the object that can have maximum values at the same time and these are;

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The answer option which is an example of the law of multiple proportions is: B) Two different compounds formed from carbon and oxygen have the following mass ratios: 1.33 g O: 1 g C and 2.66 g O: 1 g C.

The Law of Multiple Proportions is also referred to as Dalton's Law and it states that when two chemical elements combine to form more than one chemical compound, the masses (weights) of one chemical element that combine with a fixed mass (weight) of the other chemical element will always be in a ratio of small whole numbers.

According to the Law of Multiple Proportions, when two chemical elements combine to form two different chemical compound, the masses (weights) of one chemical element that combine with 1 gram of the other chemical element can be expressed as a ratio of small whole numbers.

For example, carbon and oxygen react to form either carbon monoxide and carbon dioxide.

Carbon monoxide (CO):

12 grams of C = 16 grams of O.

1 gram of C = 1.33 gram of O.

Carbon dioxide (\(CO_2\)):

12 gram of C = 32 grams of O.

1 gram of C = 2.66 gram of O.

Ratio of oxygen (O) = 16:32 = 1:2 (Law of Multiple Proportions).

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Your question is lacking the necessary answer options, so I will be adding them here:

A. A sample of chlorine is found to contain three times as much Cl-35 as Cl-37.

B. Two different compounds formed from carbon and oxygen have the following mass ratios: 1.33 g O: 1 g C and 2.66 g O: 1 g C.

C. Two different samples of table salt are found to have the same ratio of sodium to chlorine.

D. The atomic mass of bromine is found to be 79.90 amu.

E. Nitrogen dioxide always has a mass ratio of 2.28 g O: 1 g N.

When two identical conducting spheres, one initially charged with Q and the other uncharged, are brought into contact, the final charge on each sphere will be Q/2.

When two identical conducting spheres are brought into contact, they will share their charge until they reach an equilibrium state. In this case, one sphere has an initial charge Q, while the other is initially uncharged.

When the spheres touch, the charges redistribute themselves in order to minimize the overall electrostatic potential energy. Since the spheres are identical, they will share the charge equally.

Thus, after the spheres come into contact, the total charge Q will be divided equally between the two spheres. Therefore, each sphere will end up with a charge of Q/2.

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The tension of the mass 1g and 40 cm long that plays the same note as a closed pipe of the same length is approximately 43.9 N.

To find the tension of a mass 1g and 40 cm long that plays the same note as a closed pipe of the same length, you'll need to compare the fundamental frequencies of both systems.

Step 1: Calculate the fundamental frequency of the closed pipe
The formula for the fundamental frequency (f) of a closed pipe is:

f = (2n - 1)v / 4L

where n is the harmonic number (for the fundamental frequency, n = 1), v is the speed of sound in air (approximately 343 m/s), and L is the length of the closed pipe (0.4 m).

f = (2(1) - 1)(343) / (4)(0.4)
f ≈ 214.375 Hz

Step 2: Calculate the tension of the string with the same fundamental frequency
The formula for the fundamental frequency of a string is:

f = (1 / 2L) × √(T / μ)

where L is the length of the string (0.4 m), T is the tension, and μ is the linear mass density of the string. Since the mass of the string is 1g (0.001 kg) and its length is 40 cm (0.4 m), μ can be calculated as:

μ = mass / length
μ = 0.001 kg / 0.4 m
μ ≈ 0.0025 kg/m

Now, we can solve for T using the fundamental frequency found in Step 1:

214.375 Hz = (1 / 0.8 m) × √(T / 0.0025 kg/m)

Rearranging the equation and squaring both sides:

T = 0.0025 kg/m × (0.8 m × 214.375 Hz)²
T ≈ 43.9 N

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Answer: we divide the vector by its magnitude.

Explanation:

Answer:

Approximately \(2.69\; {\rm A}\).

Explanation:

Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:

\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).

Electric current \(I\) is the rate of flow of electric charge.

In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:

\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).

Answer:

B

Explanation:

Speed is distance divided by time.

The error probability for an AWGN channel without fading can be calculated using the Q-function given as Q(x) = (1/√(2π)) ∫x∞ e^(-t²/2) dt. The probability of error can be represented as:P(e) = Q(T/√No)where Q(.) is the Q-function.

Given an AWGN channel without fading, the signal is y[m] = x[m] + w[m]For antipodal signaling (BPSK), x[m] = ±a, and w[m] CN(0, No).Let p(e) be the probability of error.

To calculate the error probability, let us use the concept of signal-to-noise ratio (SNR).SNR = Power of signal/ Power of noise = a²/ No.

We have to design the threshold value in such a way that if the received signal is less than or equal to the threshold, then we will consider that received signal as ‘-a’ otherwise ‘a’.Let the threshold value be T.

Thus, the probability of error can be calculated as:P(e) = P(received signal ≤ T | transmitted signal was ‘a’) + P(received signal > T | transmitted signal was ‘-a’).

This can be mathematically represented as:P(e) = Q(T/√No)where Q(.) is the Q-function given as Q(x) = (1/√(2π)) ∫x∞ e^(-t²/2) dt.

This is the main answer to the question

The error probability for an AWGN channel without fading can be calculated using the Q-function given as Q(x) = (1/√(2π)) ∫x∞ e^(-t²/2) dt. The probability of error can be represented as:P(e) = Q(T/√No)where Q(.) is the Q-function.

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Answer:

non-luminous

Explanation:

Moon doesn't give off light of its own, that's why the moon is considered a non-luminous body

Answer:

1. states

2. kinetic theory

3.particles cqlled atoms

4.motion

5.collide

thats all I remember

(a) To find the tension in the connecting cord with a horizontal force of 2.3 N, identify the forces acting on the system and the horizontal force will be equal to the tension in the cord.

1. Identify the forces acting on the system. There are two forces acting on the system: the horizontal force (2.3 N) and the tension in the cord (T).

2. Since the surface is frictionless and the pulley is massless and frictionless, the horizontal force will be equal to the tension in the cord. Therefore, T = 2.3 N.

So, the tension in the connecting cord is 2.3 N.

(b) To find the largest value of the magnitude of the horizontal force without the cord becoming slack, follow these steps:

1. Identify the forces acting on the system. There are two forces acting on the system: the horizontal force (F) and the tension in the cord (T).
2. In order for the cord to not become slack, the tension in the cord must be greater than or equal to zero. Therefore, T ≥ 0.
3. Since the surface is frictionless and the pulley is massless and frictionless, the horizontal force will be equal to the tension in the cord. Therefore, F = T.
4. Since T ≥ 0, it follows that F ≥ 0.

So, the largest value of the magnitude of the horizontal force without the cord becoming slack is any value greater than or equal to zero.

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Answer:2 increase

Explanation:

False. The Clean Water Act can still be applicable to ponds that are not adjacent to open water if they are considered "waters of the United States" under the act, which can include wetlands and other bodies of water that are connected to navigable waters.

The Clean Water Act (CWA) aims to protect all navigable waters in the United States, including ponds that may not be directly adjacent to open water. The CWA regulates the discharge of pollutants and requires permits for certain activities that could potentially harm water quality. Even if a pond is not adjacent to open water, it may still be protected under the CWA if it has a significant connection to other waters, such as through underground or surface water flow.

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Answer: 8000N

Explanation: since it is frictionless that means it has 100% efficiency therefore the mechanical advantage is 1 meaning the load equals to the effort

The prove of  Angle XYZ- Angle NYM is given below:

Note that from the image given;

Since ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.

The reflexive property is one that informs that any shape is regarded congruent to itself.

Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.

Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.

Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.

We have 2 angles Δ XYZ and Δ NYM:

Note that ∠YXZ ≡ ∠YNM

              ∠XYZ ≡ ∠NYM

So,  ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.

Therefore, The prove of  Angle XYZ- Angle NYM is given below:

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Answer:

1. parrael

2. corresponding angles theorem

3. NYM

4. AA

Explanation:

just took it

a. To estimate the smallest range of speeds for a sodium atom in a 1.0-mm-long box, we can use the uncertainty principle from quantum physics. The uncertainty principle states that there is a fundamental limit to the precision with which we can simultaneously measure the position and momentum of a particle.

For a particle confined within a box, the uncertainty principle implies that the product of the uncertainty in position (Δx) and the uncertainty in momentum (Δp) must be greater than or equal to a certain value, known as the reduced Planck's constant (h-bar).

Δx * Δp ≥ h-bar

In this case, the position uncertainty is given by the size of the box, Δx = 1.0 mm. The momentum uncertainty (Δp) can be related to the mass (m) of the sodium atom and its velocity (v) through the equation Δp = m * Δv, where Δv represents the range of speeds.

By rearranging the uncertainty principle equation, we can solve for the range of speeds:

Δv ≥ h-bar / (m * Δx)

Substituting the appropriate values, with the mass of a sodium atom being approximately 23 atomic mass units (AMU) and 1 AMU being approximately 1.66 x 10^-27 kg, and h-bar being approximately 1.05 x 10^-34 J·s, we can calculate the smallest range of speeds:

Δv ≥ (1.05 x 10^-34 J·s) / (23 * 1.66 x 10^-27 kg * 1.0 x 10^-3 m)

b. Even if we do our best to bring a group of sodium atoms to rest, individual atoms will have speeds that cannot be reduced to absolute zero due to the principles of quantum mechanics. This is known as the zero-point energy or zero-point motion. According to quantum physics, particles such as atoms possess a minimum amount of energy even at their lowest possible temperature, which is the ground state.

The zero-point energy arises from the uncertainty principle, which implies that there is always a minimum uncertainty in the position and momentum of a particle. This uncertainty leads to the continuous fluctuation of the particle's position and momentum, resulting in a non-zero average energy, even at absolute zero temperature.

Therefore, even if a group of sodium atoms is brought close to rest, the individual atoms will still have speeds associated with their zero-point motion.

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This means that the vector a direction would be pointing along the positive x-axis at an angle of 45 degrees from the positive x-axis.  

The direction of a vector is represented by its tail and its head. The tail of a vector points in the direction that the vector is moving, and the head of a vector points in the direction that the vector is pointing.

The direction of a vector, you need to know the magnitude (length) and direction of the vector. If you are given only the magnitude of a vector, you can use the vector's direction to determine its magnitude by dividing the magnitude by the magnitude of the vector's unit vector.

In the case of a vector, if the direction of the vector is given in degrees, you can use the following formula to convert the direction to radians:

angle = arctan(tan(angle/2))

Once you have the direction of the vector in radians, you can use the vector's tail and head to determine its direction in the coordinate system. The tail of a vector points along the negative x-axis and the head of a vector points along the positive x-axis. The direction of a vector can be found by taking the absolute value of the vector's tail and subtracting the absolute value of the vector's head. The result will be a vector pointing in the direction of the vector.

For example, if you are given the magnitude of a vector of 3 units, and the direction of the vector is given as 60 degrees, the vector's direction in radians would be:

angle = arctan(tan(60/2))

angle ≈ 45 degrees

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STP is defined as the standard temperature and pressure. These are some standard values given in 1982. the approximate value of n according to the ideal gas law will be 0.986.

The ideal gas equation is derived from the Boyle and Charles law states that the product of pressure and volume is directly propotional to the temperature at STP.

It is mathematically given as

\(\rm pv=nRT\)

P is the pressure =100kPa at STP.

R is universal gas constant=8.314 j/kgk

v is the volume=22.4 L=22.4×10³ m³

T is the temperature =273.15 K at STP

\(\rm pv=nRT\\\\\rm n=\frac{RT}{pv} \\\\\ \rm n=\frac{8.314\times273.15}{100\times10^3\times10^{-3}} \\\\\rm n=0.986\)

Hence the approximate value of n according to the ideal gas law will be 0.986.

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Answer:

1

Explanation:

1 mol = 22.4 L

Answer:

D. Sulfur hexafluoride.

Explanation:

Answer:

Edmond Locard

Explanation:

Hope this helps :)

Explanation:

The Shadow zone is the area of the earth

from angular distances of 104 to 140 degrees from a given earthquake that does not receive any direct P waves

Complete Question:

A long distance runner running a 5.0km track is pacing himself by running 4.5km at 9.0km/hr and the rest at 12.5km/hr. What is the average speed?​

Answer:

Average speed = 9.7333 km/h

Explanation:

Given the following data;

To find the average speed;

First of all, we would determine the time taken to cover distance A in speed A by using the formula;

\( Time \ A = \frac {Distance \; A}{Speed \; A} \)

Substituting the values into the formula, we have;

\( Time \ A = \frac {4.5}{9.5} \)

Time A = 0.4737 hours

Total distance = distance A + distance B

5 = 4.5 + distance B

Distance B = 5 - 4.5

Distance B = 0.5 Km

Next, we would determine the time to cover distance B in speed B;

\( Time \ B = \frac {0.5}{12.5} \)

Time A = 0.04 hours

Total time = time A + time B

Total time = 0.4737 + 0.04

Total time = 0.5137 hours

Now, we would solve for the average speed;

Mathematically, the average speed of an object is given by the formula;

\( Average \; speed = \frac {total \; distance}{total \; time} \)

\( Average \; speed = \frac {5}{0.5137} \)

Average speed = 9.7333 km/h