Due to the large specific heat capacity of water, Santa Monica Bay, off the coast of Los Angeles, experiences less seasonal temperature variation than the surrounding air.
What is specific heat capacity?
The amount of heat required to increase a substance's temperature by one degree Celsius (°C) in one gram is known as specific heat. Water has a high specific heat, which means that heating it up requires more energy than heating up other substances.
Specific heat capacity (symbol: c) in SI units is the quantity of heat in joules needed to elevate 1 gram of a substance by 1 Kelvin. J/kgK is another way to put it. It is also possible to express a specific heat capacity in terms of calories per gram of temperature in Celsius.
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500 gramos de un mineral con una riqueza en cinc del 65 % se hacen reaccionar con una disolucion de acido sulfurico de riqueza 96 % en peso y densidad 1823 kg/m3 . Calcula:
Answer:
Ver explicación abajo
Explanation:
LA pregunta esta incompleta, pero logré conseguir un ejercicio muy parecido a este con datos similares, y la pregunta que falta como tal son estas:
"a) La cantidad de sal producida.
b) Moléculas de hidrógeno obtenidas a 25 ºC y 740 mm Hg.
c) El volumen de la disolución de ácido necesario para la reacción."
Asumiendo que estos son los datos faltantes, hay que ver como resolver por parte:
a) Cantidad de sal producida.
En este caso debemos plantear la reacción que se lleva a cabo. Es un mineral que tiene Zinc y reacciona con acido sulfurico, por tanto la reacción que se lleva a cabo en teoría es:
Zn + H₂SO₄ -----------> ZnSO₄ + H₂
Entonces, queremos saber la cantidad de ZnSO₄ que se formó.
Para eso, debemos calcular primero cuantos gramos de zinc hay originalmente en la muestra, que son los que reaccionaron para formar esta sal, y luego los moles para que por medio de estequiometría, calculemos los moles de la sal.
Para la masa de Zinc, sabemos que el mineral contiene 65% de zinc o 0,65 entonces:
mZn = 0,65 * 500 = 325 g
Calculamos los moles usando la masa molecular de Zinc que es 65,37 g/mol:
moles = 325 / 65,37 = 4.97 moles
Ahora bien, como la reacción de arriba está bien balanceada, podemos asuimr por estequiometría que la relación Zn / ZnSO₄ es 1:1, asi que los moles de Zn serán los mismos de la sal por tanto:
moles Zn = moles ZnSO₄ = 4,97 moles
Calculando la masa molecular de ZnSO₄:
MM ZnSO₄ = 65,37 + 32 + (16 * 4) = 161,37 g/mol
Finalmente la masa de la sal es:
m ZnSO₄ = 4,97 * 161,37
mZnSO₄ = 802,01 gb) Moléculas de hidrógeno obtenidas
PAra este caso, ya tenemos los moles de Zn, y por estequiometría, todas las especies presentes están en relación 1:1, así que los moles de hidrógeno son los mismos de zinc. No es necesario el dato de temperatura y presión acá pues ya tenemos los moles.
Para conocer el número de moléculas, necesitamos el número de abogadro que es 6.02x10²³ por lo tanto las moléculas de hidrógeno:
Moléculas de hidrógeno = 6,02x10²³ * 4,97
Moléculas de hidrógeno = 2.99x10²⁴ moléculas de H₂c) Volúmen de ácido empleado
Finalmente para el ácido, como ya conocemos los moles empleados, podemos calcular la masa del ácido usando su peso molecular:
MM H₂SO₄ = (2*1) + 32 + (4*16) = 98 g/mol
m H₂SO₄ = 4,97 * 98 = 487,06 g
Ahora que ya sabemos su masa, solo calculamos la masa realmente usada (pues su %p/p es 96%) y con la densidad calculamos el volumen:
d = m/v
v = m/d
m H₂SO₄ (puro) = 487,96 * 0,96 = 467,58 g
El volumen será:
V = 467,58 g / 1,823
V = 256,49 mLEspero que esto te sirva, o te ayude como impulso a tu ejercicio real.
why polymer melting point transitions are broader than low molecular compounds?
Polymer melting point transitions are broader than those of low compounds because of their molecular structure and the forces holding them together.
Low molecular compounds have a simple, defined structure and are hmoleculareld together by intermolecular forces such as van der Waals forces, dipole-dipole interactions, and hydrogen bonding. When these forces are overcome, the compound transitions from solid to liquid.
Polymers, on the other hand, have a much more complex molecular structure with long chains of repeating units. These chains are held together by covalent bonds, which require much more energy to break than the intermolecular forces in low molecular compounds. As a result, polymers have a higher melting point than low molecular compounds.
Furthermore, the long chains in polymers are not perfectly aligned, meaning that some parts of the chains will require more energy to break than others. This leads to a broader melting point transition.
Additionally, some polymers may have different types of covalent bonds, resulting in different melting points for different parts of the polymer. These factors contribute to the broader melting point transition observed in polymers compared to low molecular compounds.
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the red is neutrons and the blue is protons...I'm pretty sure.
Answer:
Beryllium atom
Explanation:
In the kinetics of an iodine clock reaction procedure, the initial rate is calculated by multiplying the initial concentration of ______________ by half, and dividing by the elapsed time as measured with a ____________
In the kinetics of an iodine clock reaction procedure, the initial rate is calculated by multiplying the initial concentration of thiosulfate by half, and dividing by the elapsed time as measured with a stop watch.
Chemistry classes frequently employ the "clock reaction" to examine the rate at which reactions occur because of its striking color change from colorless to blue. When I2 and starch interact, a dark blue iodine/starch complex is created, which causes the color to change. With the aid of a stopwatch, the pace of reaction can be precisely calculated by noting the moment the blue complex first emerges.
The method of beginning rates is used in this experiment to establish the rate law for a reaction.
The primary reaction to be investigated is the oxidation of I- by S2O82-(persulfate) in aqueous solution, or the "iodine clock reaction":
Slow, rate-determining step in equation 1: 2I- (aq) + S2O82- (aq) I2 (aq) + 2SO42- (aq).
Equation 2's fast step: I2 (aq) + 2S2O32- 2I- (aq) + S4O62-
When the primary reaction produces a particular quantity of I2, the "clock" reaction will signal. Equation 2's molar ratio can be used to compute the amount of I2 produced prior to the color change from the known addition of S2O32-. The rate at which the concentration of I2 changes over time is calculated using Equation 1.
Thiosulfate and Stop Watch are the proper choices. As a result, the complete statement will read as follows: "In the kinetics of an Iodine Clock Reaction process, the Initial rate is computed by multiplying the initial concentration of the thiosulfate by half, and dividing by the elapsed time monitored using a stop watch."
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What are substitution reactions elimination reactions and addition reactions?
Answer:
Substitution reactions, elimination reactions, and addition reactions are types of organic reactions that occur when organic compounds undergo chemical changes.
1-Substitution reactions: involve the replacement of an atom or a group of atoms in a molecule with another atom or group of atoms.
2-Elimination reactions: involve the removal of a molecule or a group of atoms from a larger molecule to form a smaller molecule.
3-Addition reactions: involve the addition of one or more atoms or groups of atoms to a molecule to form a larger molecule.
Explanation:
Substitution, elimination, and addition reactions are types of organic reactions that occur when one or more chemical compounds react to form new compounds.
A substitution reaction occurs when one functional group is replaced by another functional group in a molecule. For example, when an alkane reacts with a halogen, such as chlorine, a substitution reaction occurs where the halogen replaces one of the hydrogen atoms in the alkane molecule.
An elimination reaction occurs when a molecule loses a small molecule, such as water, to form a new compound. For example, when an alcohol is heated with a strong acid, an elimination reaction occurs where the alcohol loses a water molecule to form an alkene.
An addition reaction occurs when a molecule adds to a double or triple bond to form a new compound. For example, when an alkene reacts with hydrogen gas in the presence of a catalyst, an addition reaction occurs where the hydrogen atoms are added to the double bond to form an alkane.
Answer:
Common types of reaction
Substitution: Replace sigma bond with another sigma bond. Elimination: Break two sigma bonds and form a new pi bond. Addition: Break a pi bond and form two new sigma bonds.
(01. 05 MC)
During an experiment a thermometer was placed in a beaker containing hydrogen peroxide. The following observations were recorded when yeast granules were added to hydrogen peroxide.
Observation 1: Fizzing and bubbling took place.
Observation 2: The temperature began to rise.
Based on the observation, justify the type of change (physical or chemical) that took place
When yeast granules were added to hydrogen peroxide, two observations were made: fizzing and bubbling took place, and the temperature began to rise. These observations suggest that a chemical change occurred.
Chemical changes involve a transformation of the molecular structure of a substance, resulting in the formation of new substances with different properties. In this case, the hydrogen peroxide likely reacted with the yeast granules to produce oxygen gas and water, which caused the fizzing and bubbling.
The increase in temperature may be a result of the energy released during the chemical reaction.
Physical changes, on the other hand, involve a change in the physical state or appearance of a substance, without any alteration to its molecular structure. For example, melting ice is a physical change, as the solid ice changes to liquid water, but the molecules themselves remain unchanged.
In summary, the observations of fizzing and bubbling, as well as the temperature increase, suggest that a chemical change occurred when yeast granules were added to hydrogen peroxide. This change likely involved the production of oxygen gas and water.
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More familiar name for hydrated magnesium silicate.
The more familiar name for hydrated magnesium silicate is Talc. Talc is a mineral that is formed through the alteration of serpentine, mafic rocks, and other magnesium-rich rocks in the presence of carbon dioxide and water. It is also known as soapstone and steatite, and it has a greasy or oily feel to it.
Talc is a mineral that is used in the manufacture of many consumer goods such as paint, paper, ceramics, cosmetics, and plastics. It is also used in the pharmaceutical and food industries. The natural beauty and softness of talc make it an ideal mineral for many uses.
Talc is a soft, silicate mineral that is used in many consumer products, including baby powder, make-up, and chewing gum. It is a naturally occurring mineral that is found in many places around the world, including the United States, China, and Brazil.
Talc is composed of hydrated magnesium silicate and has the chemical formula Mg3Si4O10(OH)2. It is a very soft mineral, with a Mohs hardness of 1, and it has a greasy or oily feel to it. This softness and greasiness make it an ideal mineral for many uses.
In the cosmetics industry, talc is used as a filler, to help products spread more easily, and to absorb moisture. It is also used in the manufacture of ceramics, paint, and plastics. In the food industry, it is used as a processing aid, to prevent caking, and to improve the texture of certain foods.
Talc is a naturally occurring mineral that is composed of hydrated magnesium silicate. It is used in many consumer products, including cosmetics, ceramics, paint, plastics, and food. Talc is a soft mineral that has a greasy or oily feel to it, and its natural beauty and softness make it an ideal mineral for many uses.
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Could someone help me answer these questions with the answer and typed steps for how each answer was found? I asked this question previously but, I could not read the handwritten answer.
7. A 25 g soil sample was extracted with 75 mL of NH4OAc (pH 7.0), and the filtrate was analyzed
on an atomic absorption unit. The following results were obtained:
100 mg/L Ca2+, 45 mg/L Mg2+, 85.5 mg/L K+, 94.2 mg/L Al3+ and 8.0 mg/L H+.
a. What is the CEC in cmol(+)/kg for this sample?
b. What is the % B.S. for this soil?
c. What is the % acid saturation for this soil sample?
The CEC for this soil sample is 675.2 cmol(+)/kg.
The % Base Saturation for this soil sample is approximately 136.62%.
The % Acid Saturation for this soil sample is approximately 60.55%.
To calculate the CEC, % Base Saturation (B.S.), and % Acid Saturation for the given soil sample:
a. Calculation of CEC (Cation Exchange Capacity):
CEC is the sum of exchangeable cations in the soil. From the given results, we have:
CEC = Ca2+ + Mg2+ + K+ + Al3+
CEC = (100 mg/L + 45 mg/L + 85.5 mg/L + 94.2 mg/L) / (25 g / 1000)
CEC = 168.7 mg / (25 g / 1000)
CEC = 675.2 cmol(+)/kg
b. Calculation of % Base Saturation (B.S.):
% B.S. represents the percentage of CEC occupied by base cations. In this case, we consider Ca2+, Mg2+, and K+ as base cations. The formula to calculate % B.S. is:
% B.S. = (Ca2+ + Mg2+ + K+) / CEC * 100
% B.S. = (100 mg/L + 45 mg/L + 85.5 mg/L) / (168.7 cmol(+)/kg) * 100
% B.S. = 230.5 mg / (168.7 cmol(+)/kg) * 100
% B.S. = 136.62%
c. Calculation of % Acid Saturation:
% Acid Saturation represents the percentage of CEC occupied by acid cations, in this case, H+ and Al3+. The formula to calculate % Acid Saturation is:
% Acid Saturation = (H+ + Al3+) / CEC * 100
% Acid Saturation = (8.0 mg/L + 94.2 mg/L) / (168.7 cmol(+)/kg) * 100
% Acid Saturation = 102.2 mg / (168.7 cmol(+)/kg) * 100
% Acid Saturation = 60.55%
Please note that the given values were in milligrams per liter (mg/L), and the CEC and % Saturation values were calculated assuming a conversion from mg/L to cmol(+)/kg using the mass of the soil sample (25 g).
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how many moles of water are produced if 1.76 mol of no2 is given off? 15.0 ml of 0.30 m sodium phosphate solution reacts with 20.0 ml of 0.20 m lead(ii) nitrate solution. what mass of precipitate will form?
The number of moles of water produced cannot be determined without the balanced equation. The mass of precipitate formed is approximately 1.08 grams.
To determine the number of moles of water produced when 1.76 mol of NO2 is given off, we need to know the balanced equation for the reaction. Without that information, it's not possible to provide an accurate answer. Please provide the balanced equation, and I can help you calculate the number of moles of water produced.
For the second part of your question, we have the reaction between sodium phosphate (Na3PO4) and lead(II) nitrate (Pb(NO3)2). The balanced equation for this reaction is:
3 Na3PO4 + 2 Pb(NO3)2 -> Pb3(PO4)2 + 6 NaNO3
From the balanced equation, we can see that the ratio of Na3PO4 to Pb3(PO4)2 is 3:1. Given that 15.0 mL of 0.30 M sodium phosphate solution (Na3PO4) is reacted with 20.0 mL of 0.20 M lead(II) nitrate solution (Pb(NO3)2), we can calculate the moles of each reactant.
Moles of Na3PO4 = (volume in liters) × (molarity)
= (15.0 mL ÷ 1000 mL/L) × 0.30 M
= 0.0045 moles
Moles of Pb(NO3)2 = (volume in liters) × (molarity)
= (20.0 mL ÷ 1000 mL/L) × 0.20 M
= 0.004 moles
Since the ratio of Na3PO4 to Pb3(PO4)2 is 3:1, we can see that 0.004 moles of Pb(NO3)2 will react with 0.004 moles/3 = 0.00133 moles of Na3PO4.
The molar mass of Pb3(PO4)2 can be calculated by adding the atomic masses of lead (Pb), phosphorus (P), and oxygen (O). The molar mass of Pb3(PO4)2 is approximately 811.20 g/mol.
The mass of precipitate formed can be calculated by multiplying the moles of Pb3(PO4)2 by its molar mass:
Mass of precipitate = (moles of Pb3(PO4)2) × (molar mass of Pb3(PO4)2)
= 0.00133 moles × 811.20 g/mol
≈ 1.08 grams
Therefore, approximately 1.08 grams of precipitate will form in this reaction.
Note: It's important to double-check the balanced equation and ensure the stoichiometry is accurate for the calculations.
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UCI Chemistry researchers, Prof. F. Sherwood Rowland and Dr. Mario Molina werefirst to discovered in 1973 that chlorofluorocarbons (CFCs) were depleting the Earth’sozone layer when released into the atmosphere. Once they reach the stratosphere, Clis released from the CFCs molecules by interaction with UV light. Free Cl atoms areable to react with ozone in a catalytic cycle that converts O3into the more stable O2.It is estimated that a single Cl atom is able to react with∼100000 O3molecules.Although CFCs production was banned in 1996, there are still a substantial numberof motor vehicle air conditioners (MVACs) that use CFC-12 (CF2Cl2) as refrigerant.The average CFC-12 emission rate from operating MVACs has been estimated tobe 59.5 mg per hour per vehicle (Zhang et al.Environ. Sci. Technol. Lett.2017).How much chlorine, in kg, is added to the atmosphere in a year due to 100 millionMVACs using CFC-12 as refrigerant?
Answer:
15.27895 x 10⁶kg of chlorine radical is added to the atmosphere in a year due to 100 million MVACs
Explanation:
Chlorofluorocarbons (CF₂Cl₂) from refrigerants produce chlorine radicals according to the following equation
CF₂Cl₂ → CF2Cl + Cl ⁻ .........(1)
From equation 1, one mole of CF₂Cl₂ produces one mole of Chlorine radical
From the question,
The emission rate of CF₂Cl₂ is 59.5mg/hour/MVAC
In one day the emission rate would be 59.5 x 24hours
= 1428mg/day
In one year, the emission rate would be 1428mg/day x 365days
= 521220mg/year
= 521.220g/year/MVAC
Therefore the emission rate for 100 million MVAC using CF₂CL₂ in a year is
= 52122 x 10⁶g/year/MVAC
= 52122 x 10³kg/year/MVAC
The molar mass of CF₂CL₂ = 120.913g/mol
No of moles of CF₂CL₂ = mass/ molar mass
= 52122 x 10⁶g / 120.913g/mol
= 431 x 10⁶ moles of CF₂Cl₂
From equation 1, since one mole of CF₂Cl₂ produces one mole of Chlorine radical, it implies that
431 x 10⁶ moles of CF₂Cl₂ would produce 431 x 10⁶ moles of chlorine radical,
Therefore, to find the mass of chlorine radical produced, we use the formula
No of moles of chlorine radical = mass/ molar mass
431 x10⁶ moles = mass of chlorine radical /molar mass of chlorine radical
431 x 10⁶ moles = mass/ 35.45g/mol
mass of chlorine = 431 x 10⁶ moles x 35.45 g/mol
= 15278.95 x 10⁶ g
In Kg, the mass = 15,278.95 x 10³kg of cholrine radical
= 15.27895 x 10⁶ Kg of chlorine radical
Annabelle was explaining the carbon cycle to her friend. She said that all the carbon
in the carbon dioxide we breathe out came from the same place originally. Is Annabelle
correct? Explain your answer using equations to describe the different processes in the
carbon cycle.
Answer: O2+6H12O6=CO2+ENERGY(ATP)
I DON'T THINK SHE IS CORRECT
Explanation:
on what part of the carbon cycle have humans had the greatest impact?
Answer:
Human activities have a tremendous impact on the carbon cycle. Burning fossil fuels, changing land use, and using limestone to make concrete all transfer significant quantities of carbon into the atmosphere.
Taking two positively charged objects and holding them close to one another creates a system with electric potential energy
One way to lower the electric potential energy in a system like this would be to
A increase the distance between the two charges.
B decrease the distance between the two charges.
C decrease the mass of one of the objects
D increase the mass of one of the objects
The circled sushi has algae
wrapped around it to hold it
together. What kind of algae is
this?
A. Yellow
B. Blue
C. Green
D. Orange
Answer:
Green
Explanation:
Describe the size of our Sun in relation to other stars and state the heaviest element that a star the size of ours would likely produce?
Answer:
Our sun is an averaged size star compare to other stars.. And the Iron are the heaviest element they can form.
Answer:
Our sun is an averaged size star compare to other stars.. And the Iron are the heaviest element they can form.
Which type of organism is responsible for performing the majority of nitrogen fixation?
Answer:
B. bacteria
Explanation:
they are responsible for the fixation of nitrogen
Answer:
the answer is B bacteria
Which two changes would make this reaction reactant-favored?
2H₂+02 2H₂O + energy
A. Reducing the pressure
B. Increasing the pressure
C. Reducing the temperature
D. Increasing the temperature
C. Reducing the temperature, is the two changes would make this reaction reactant-favored 2H₂+O₂ 2H₂O + energy
To make the given reaction reactant-favored, we need to shift the equilibrium towards the left side, favoring the formation of reactants (H₂ and O₂) rather than products (H₂O). This can be achieved by considering the impact of pressure and temperature on the reaction.
A. Reducing the pressure:
Reducing the pressure would not favor the reactants. According to Le Chatelier's principle, decreasing the pressure will shift the equilibrium towards the side with a higher number of moles of gas. In this case, both sides of the reaction have the same number of moles of gas (two moles), so reducing the pressure will not have a significant effect.
B. Increasing the pressure:
Increasing the pressure would not favor the reactants either. Again, according to Le Chatelier's principle, increasing the pressure will shift the equilibrium towards the side with fewer moles of gas. As both sides have the same number of moles of gas, changing the pressure will not impact the equilibrium.
C. Reducing the temperature:
Reducing the temperature would favor the reactants. The reaction is exothermic (releases energy), and according to Le Chatelier's principle, decreasing the temperature favors the reaction that produces heat. Therefore, reducing the temperature would shift the equilibrium towards the reactants (H₂ and O₂) side.
D. Increasing the temperature:
Increasing the temperature would not favor the reactants. In an exothermic reaction, increasing the temperature would shift the equilibrium towards the products (H₂O) side to absorb the additional heat.
In conclusion, reducing the temperature (option C) would make the reaction reactant-favored, favoring the formation of H₂ and O₂ rather than H₂O. Therefore, Option C is correct.
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Can the law of conservation of mass be applied when cooking? In one to two sentences, explain why or why not. Please give an example without water.
The law of conservation of mass is must be applied when cooking.
What is conservation of mass?Law of conservation of mass states that mass of any substance will change into another form without any loss of mass, means destroying of mass is impossible.
When we cook food then mass of conservation is applied there, for example we are boiling pulses with water then in that case the amount of formed liquid pulses is equal to the initial mass of solid pulse with water.
Hence law of conservation of mass is applicable during cooking.
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Given the following reaction, if 2.3 L of nitrogen completely react with an excess of oxygen, how many liters of N2O5 are produced, assuming no change in pressure or temperature? 2N2(g) + 5O2(g) → 2N2O5(g)
The reaction 2N2(g) + 5O2(g) → 2N2O5(g) indicates that for every 2 moles of nitrogen (N2) that react, 2 moles of nitrogen pentoxide (N2O5) are produced. Since the reaction is balanced in terms of moles, we can use the stoichiometry to determine the volume.
Given that 2.3 L of nitrogen (N2) react, we can calculate the volume of nitrogen pentoxide (N2O5) produced by using the ratio of the coefficients in the balanced equation. The molar ratio of nitrogen to nitrogen pentoxide is 2:2. Therefore, the volume of nitrogen pentoxide produced will also be 2.3 L. According to the stoichiometry of the balanced equation, 2 moles of N2 react to produce 2 moles of N2O5. Since the volume of gas is directly proportional to the number of moles (assuming constant pressure and temperature), the ratio between the volumes of N2 and N2O5 will also be 2:2. Therefore, the volume of N2O5 produced will be equal to the volume of N2 consumed, which is 2.3 L.
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Determine the maximum amount of NaNO3 that was produced during the experiment
To determine the maximum amount of NaNO3 produced during the experiment, we need to identify the limiting reactant. The balanced chemical equation for the reaction is:
2 NaCl(aq) + Pb(NO3)2(aq) → 2 NaNO3(aq) + PbCl2(s)
From the equation, we can see that the stoichiometric ratio between NaCl and NaNO3 is 2:2, meaning that 2 moles of NaCl react to produce 2 moles of NaNO3.
First, we need to calculate the moles of NaCl used in the experiment. We can use the given mass of NaCl and its molar mass to determine the moles:
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
= 5.00 g / 58.44 g/mol
= 0.0856 mol
Next, we can use the stoichiometric ratio to determine the moles of NaNO3 that would be produced from the moles of NaCl:
Moles of NaNO3 = Moles of NaCl
= 0.0856 mol
Finally, we can calculate the maximum amount of NaNO3 in grams:
Mass of NaNO3 = Moles of NaNO3 * Molar mass of NaNO3
= 0.0856 mol * (22.99 g/mol + 14.01 g/mol + 3 * 16.00 g/mol)
= 0.0856 mol * 85.01 g/mol
= 7.275 g
Therefore, the maximum amount of NaNO3 that was produced during the experiment is 7.275 grams.
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4. explain why very high temperatures are required to carry out the diels-alder reaction in this lab even though the dienophile has favorable functional groups.
The high temperature is likely required to provide the additional energy needed to overcome the energy barrier and promote the interaction of the diene and dienophile to undergo the Diels-Alder reaction.
The Diels-Alder reaction involves the formation of a cyclic molecule through the reaction of a diene and a dienophile. The reaction is typically exothermic and is known to occur readily at room temperature or slightly above. However, in some cases, higher temperatures are required to carry out the reaction.
In this particular lab, even though the dienophile has favorable functional groups, very high temperatures are required to carry out the Diels-Alder reaction. This is likely due to the electronic properties of the dienophile and diene involved in the reaction.
The Diels-Alder reaction is a concerted reaction that involves the interaction of the diene's highest occupied molecular orbital (HOMO) with the dienophile's lowest unoccupied molecular orbital (LUMO). The LUMO of the dienophile is typically located in the vicinity of the functional groups that make it a good dienophile
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The energy required to break the bonds for an exothermic reaction to occur is called the _ energy.
Answer:
This stored chemical energy, or heat content, of the system is known as its enthalpy.
Explanation:
Due to the absorption of energy when chemical bonds are broken, and the release of energy when chemical bonds are formed, chemical reactions almost always involve a change in energy between products and reactants.
Which of the following would qualify as matter?
Answer:
the water, gasoline, sand, and sugar
Explanation:
Answer:
Everything on the periodic table and Dark Matter all count as a form of "matter".
A gas sample is stored in a 2 liter container under 3 atmospheres of pressure at 28 C. If the gas is placed into a 5 liter container at 39 C, what will the pressure be?
Answer:
28c
Explanation:
Which of the following is the MOST accurate measurement for the length of an object that is actually 15.0 m long? A. 15.35 m B. O 15.2 m C. 14.55 m D. 14.5 m
The most accurate measurement for the length of an object of 15.0 m long is 15.2m. Option (B) is correct.
What are the accuracy and measurement?Accuracy is the measurement tolerance of the instrument in industrial instrumentation. It refers to the limits of the errors made when the instrument is used. Resolution is simply how fine the measuring instrument is set to read to tenths, hundreds, thousands, or whatever.
Measurement can be explained as the process of numerical evaluation of a dimension with standard measuring instruments. The elements of the measuring system involve instrumentation, calibration standards, human operator limitations, environmental influence, and features of the workpiece.
Given, the length of the object is equal to 15 meters. After being measured with an apparatus the only lies closest to 15 m can be considered as the most accurate measurement.
Therefore, the length of 15.2 m is the most accurate measurement for the length of an object with an actual length 15 m.
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what was the initial temperature displayed on the thermometer before the addition of 0.25 g of zinc to the hcl solution?
Without additional information or context, I am unable to provide an accurate answer to your question.
This information includes the initial temperature of the HCl solution and the volume or concentration of the solution. Unfortunately, without this data, it is not possible to provide an accurate initial temperature. Please provide the necessary details to assist you in finding the answer you seek.Please provide more details or clarify the situation. Additionally, please specify if you require a specific word count for the answer. To determine the initial temperature displayed on the thermometer before adding 0.25g of zinc to the HCl solution, you would need to know the starting conditions of the experiment. This information includes the initial temperature of the HCl solution and the volume or concentration of the solution. Unfortunately, without this data, it is not possible to provide an accurate initial temperature. Please provide the necessary details to assist you in finding the answer you seek. Without additional information or context, I am unable to provide an accurate answer to your question.
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13. What would be the boiling point in degrees celcius of the solution in number 12?
(Kb of water is 0-.512 °C/m)
The boiling point of the solution in number 12 would be 100.624 °C.
How do we determine the value?The boiling point of a solution depends on many factors, including the concentration of the solute and the nature of the solvent. The value you provided (Kb of water = 0.512 °C/m) is the molal boiling point elevation constant, which is used to calculate the change in boiling point of a solvent when a solute is added. Using the molar boiling point to multiply the number ascribed to the degree Celsius of the solution which is 12 plus the boiling point of water. which is 100..
Therefore, the correct answer is as given above
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The initial concentration of sodium oxalate, Na₂C₂O4 is 1.34 M. After 19.3 seconds its concentration is
0.276 M
(Triangle)Na₂C₂O4 =
Rate =
The rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.
To determine the rate of change of the concentration of sodium oxalate (Na₂C₂O4), we can use the rate equation:
Rate = (Δ[Na₂C₂O4]) / (Δt)
where Δ[Na₂C₂O4] represents the change in concentration of Na₂C₂O4 and Δt represents the change in time.
In this case, the initial concentration of Na₂C₂O4 is 1.34 M, and after 19.3 seconds, the concentration is 0.276 M.
Substituting the values into the rate equation, we have:
Rate = (0.276 M - 1.34 M) / (19.3 s - 0 s)
Rate = (-1.064 M) / (19.3 s)
Rate = -0.0551 M/s
Therefore, the rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.
The negative sign indicates that the concentration of Na₂C₂O4 is decreasing over time, as the reactant is being consumed in the reaction.
It's important to note that the rate of a reaction is influenced by various factors, such as the reaction mechanism, temperature, and presence of catalysts. The rate can be determined experimentally by measuring the change in concentration of a reactant or product over a specific time interval.
The given information allows us to calculate the rate of change for the specific reaction involving Na₂C₂O4. However, without additional information about the reaction, it is not possible to determine the exact nature or stoichiometry of the reaction, as well as any other reactants or products involved.
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The density of ice at its freezing point is 0.917 g/cm3. What is the mass of 2.5 cm3 of ice at this temperature?
A. 1.6 g
B. 2.3 g
C.2.7 g
D.3.4 g
Answer:
The answer is option BExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
From the question we have
mass = 0.917 × 2.5 = 2.2925
We have the final answer as
2.3 gHope this helps you
Answer:. 2.3 g
Explanation:
If the pH of a solution is 6.2, what would the pOH be?
O A. 7.8
B. 8.9
C. 12.4
D. 5.8
SUBMIT
Answer:
7.8
Explanation:
pH + pOH = 14
pOH = 14 - 6.2
= 7.8