Which Pattern is used in the following Code? (check one)
-----------------------------------------
class MyClass1 {
public void bar(double lba, int size) { System.out.print(lba+size); } }
-----------------------------------------
classMyClass2{
public void foo(double lba, int size) {
System.out.print( lba * size); }
}
-----------------------------------------
class MyClass3 {
private MyClass1 o1;
private MyClass2 o2; public MyClass3() {
this.o1 = new MyClass1();
this.o2 = new MyClass2();
}
public void doIt(double lba, int size) {
o1.bar(lba, size);
o2.foo(lba, size);
}
}
-----------------------------------------
public class TestRun { public static void main(String[] args) {
MyClass3 c = new MyClass3(); System.out.println(c.doIt(3, 3));
}
}
----------------------------------------
Command Pattern
State Pattern
Facade Pattern
Composite Pattern
Template Pattern
Decorator Pattern
Adapter Pattern
Observer Pattern

Answer:

True

Explanation:

nothing to really explain

Answer:

say in English plz I don't understand

OLAP (Online Analytical Processing) and visualization are powerful tools that can be used to support operational decision-making in many different ways.

Here are some ways in which OLAP and visualization can be used to support operational decision-making:

Overall, OLAP and visualization tools can be used to support operational decision-making by providing decision-makers with timely and relevant information, enabling them to make informed decisions based on data-driven insights.

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Answer:

Industrial  revolution too bad at english languge not fleunt so if say a whole story of this i will not make secene but answer is to it industrial revolution.

Explanation:

Ohm's Law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance of the conductor. Mathematically, Ohm's Law can be represented as:  V = I * R

a. The four basic units of electricity are:
- Current (I), measured in amperes (A)
- Voltage (V), measured in volts (V)
- Resistance (R), measured in ohms (Ω)
- Power (P), measured in watts (W)

b. Ohm's Law equation is: V = IR

c. To re-arrange Ohm's Law equation:
- To solve for current (I): I = V/R
- To solve for resistance (R): R = V/I

d. Power equations:
- P = VI
- P = I^2R
- P = V^2/R

e. Using the power equation, we can solve for current:
P = VI
60W = 12V x I
I = 5A

f. Using the power equation and resistance value:
P = I^2R
P = (3.3V)^2 / 0.25Ω
P = 43.56W

g. Using the power equation and current value:
P = VI
P = 120W / 24A
P = 5V

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A UML class diagram is a design visualization that represents classes, interfaces, associations, and objects, among other things. It provides an object-oriented view of a software system from its structure to its behavior.

M&M Enterprises is selling its agleclaps to customers through a network of company salespeople.

Each type of agleclap is bought from a particular vendor and is given an initial list price. Each salesperson services a separate group of customers and is allowed to offer them various discounts from list to induce sales. Each sale can include one or more types of agieclaps and can be paid for in any one of three ways:

(1) immediately in cash,

(2) on the 15th of the following month,

(3) over the course of six months.

When cash is received, a cashier deposits it into a company bank account. Sales are signaled by invoices, cash receipts by remittance advices.

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Answer:

blah blah blah sh ut up read learn

Certainly! Here are the major steps for the airfare project, including the description of the project, business rules, ER Model development, relational model development, and SQL code implementation:

**1. Description of the Project and Business Rules:**

- Provide a brief description of the airfare project, outlining its purpose, goals, and scope.

- Define the business rules that govern the project, such as the requirements for booking flights, managing customer information, handling payments, and any other relevant rules specific to the airfare domain.

**2. Develop the ER Model:**

- Create an Entity-Relationship (ER) model to represent the key entities and relationships in the airfare system.

- Identify entities such as customers, flights, airports, bookings, payments, and any other relevant entities based on the project requirements.

- Define the attributes for each entity, specifying the data types, keys, and any necessary constraints.

- Establish the relationships between entities using cardinality and participation constraints.

**3. Develop the Relational Model:**

- Based on the ER model, translate the entities, attributes, and relationships into a relational model.

- Determine the tables needed to represent each entity and their corresponding attributes.

- Identify primary and foreign keys for establishing relationships between tables.

- Define the data types and constraints for each attribute in the tables.

**4. SQL Code:**

- Implement the SQL code to create the necessary tables in a relational database management system (DBMS) based on the relational model.

- Write SQL statements to insert sample data into the tables, representing flights, airports, customers, bookings, payments, and any other relevant information.

- Construct SQL queries to perform various operations, such as retrieving flight information, booking flights, processing payments, and generating reports.

**Suggested Topics:**

1. E-Commerce Transaction: Design an airfare booking system where customers can search for flights, select seats, make payments, and receive booking confirmations.

2. Mobile App for Flight Management: Create a mobile application that allows users to check flight schedules, book flights, manage reservations, and receive notifications for flight updates.

Please note that the specific implementation details, database schema, and SQL queries will depend on the requirements and scope of your airfare project.

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Criteria define project goals, while constraints set boundaries and limitations, and both are important in the design process.

Define the term boundaries.

Boundaries refer to the limits or constraints that define the extent or scope of something, such as a system, process, or project. Boundaries can be physical, conceptual, or organizational and may be defined by external factors like laws, regulations, or standards, or by internal factors like resources, capabilities, or objectives. Boundaries can help to clarify responsibilities, prevent misunderstandings, and ensure that activities or outcomes are consistent with expectations and requirements.

The statement that is true about criteria and constraints is that they are both important factors to consider in the design process of a project.

Criteria are the desired features, functions, and performance requirements that a project must meet to be considered successful. They define the goals and objectives of the project and help to evaluate whether or not the project has achieved its intended purpose.

Constraints are the limitations and restrictions that affect the design and development of a project. They can be related to resources, such as time, budget, materials, and manpower, as well as technical, legal, ethical, and environmental considerations. Constraints set boundaries and parameters for the project and may require trade-offs or compromises to be made.

In the design process, criteria and constraints are used to guide decision-making and problem-solving. Designers must balance the desired criteria with the constraints that exist, to arrive at a solution that meets the project goals while also being feasible and practical to implement.

Therefore, both criteria and constraints are important and interrelated factors to consider in the design process of a project.

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The electrical panel schedules are located on EWR Plan number 8.

Hence, answer is A.

An electrical panel schedule refers to the listing of all circuits on a panelboard or switchboard. It should include information such as circuit breakers, panelboards, and what each breaker controls.

Electrical panel schedules assist with ensuring that there is no overloading of the circuits, which can result in serious problems such as electrical fires.

Thus, panel schedules are a significant aspect of any electrical installation, and they should be kept up to date and organized.

So, the correct answer is A.

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Based on the given options, the closest equation that can represent the deflection at the free end is yb=m0l22ei↑. This equation represents the deflection of a cantilever beam with a point load at the free end.

In this equation, yb is the deflection at the free end, m0 is the magnitude of the point load, l is the length of the beam, e is the modulus of elasticity, and i is the moment of inertia of the cross-section of the beam.

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The maximum magnitude of the load the beam can support is 547.16 N.

The maximum magnitude of the load the beam can support can be calculated using the formula:

p = 2 * τ * π * d^2 / (4 * n)

where:

τ is the maximum allowable shear stress (80 MPa)

d is the diameter of the pins (18 mm)

n is the number of pins in double shear

Converting the diameter to meters, we have:

d = 18 * 10^-3 m

Let's assume n=2 pins in double shear. Then,

p = 2 * 80 * 10^6 * π * (18 * 10^-3)^2 / (4 * 2)

p = 547.16 N

So, the maximum magnitude of the load the beam can support is 547.16 N.

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Answer:

The state you live in

The types of traffic that are subject to SPD state check are normal, high, and top priority. The types of traffic that are subject to SPD input queue check are also normal, high, and top priority.

In SPD (Selective Packet Discard), all kinds of traffic (normal, high, and top priority) are subject to SPD state check. This means that all traffic is checked to determine if the system is in a congested state and if selective packet discard is necessary.  However, only normal and high priority traffic are subject to SPD input queue check. This means that these types of traffic are checked to determine if they should be discarded in order to prevent the input queue from becoming full. Top priority traffic is not subject to SPD input queue check because it is considered to be the most important and should not be discarded.

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The most common applications for micro piles are structural foundation support, underpinning, wall support, and slope stabilization.

The master format is a common outline for organizing information about building materials and components. Its primary divisions include topics such as sitework, concrete, masonry, metals, wood, and plastics, among others.) Seismic retrofitting or strengthening is done to improve the structural capacities (strength, stiffness, ductility, stability, and integrity) of the structure so that the building's performance level can be raised to withstand the design earthquake consideration.

The mass concrete underpinning method is the traditional underpinning method that has been used for centuries. The method entails extending the old foundation to a stable stratum. The soil beneath the existing foundation is excavated in stages orpins in a controlled manner.

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Answer:

Unit of,

momentum = kg×m/s

momentum per unit area = kg×m/s×m² = kg/m×s

momentum per unit area per unit time= kg/ms²

force = kg×m/s²

force per unit area = kg×m/s²×m² = kg/ms²

Explanation:

When landing behind a large jet aircraft, it's important to plan your landing carefully. In general, it's recommended that you aim to touch down beyond the jet's touchdown point.

This will help to ensure that you have enough room to slow down and exit the runway safely. However, if there is any crosswind present, it's often a good idea to land on the windward side of the runway and prior to the jet's touchdown point. This will help to minimize the effects of the crosswind and ensure a safe landing. In any case, it's generally recommended that you aim to touch down at least 1,000 feet beyond the jet's touchdown point to ensure that you have enough runway to work with. By planning your landing carefully, you can help to ensure a safe and successful flight.

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To reduce concerns that could further impair your machine, use the appropriate formulas and methods at every point in this process.

To create an overall ratio of 656:1, a three-stage compound spur gear train can be formed with specific ratios between the gears. These ratios are 4:1, 4:1, and 41:1.

The quantities that correspond to these gears are as followed:

- First stage - N1 = 16 teeth and pair with N2 which has 64 teeth

- Second stage - N3 = 64 teeth and pair with N4 which entails 256 teeth

- Third stage - N5= 41 teeth and collaborate with N6 which contains 1641 teeth.

After specifying all the individual tooth numbers for each gear, several calculations must be performed using mathematical formulas such as CR (Contact Ratio) and NP_min (Minimum number of teeth on the pinion).

Additionally, it is possible to find the pitch diameters for each gear pair by multiplying its corresponding standard module value 'm' by their respective tooth count (N).

The values placed in millimeters would then result in the following:

- Pitch diameter (First Stage Gears): D1 = 32mm, D2 = 128mm

- Pitch diameter (Second Stage Gears): D3 = 128mm, D4 = 512mm

- Pitch diameter (Third Stage Gears): D5 = 82mm, D6 = 3282mm.

In addition to finding out each gear's appropriate pitch diameter, we need to acquire information regarding two critical geometric parameters; Addendum and Dedendum.

Depending on the gear type, they may take unique forms, although for ordinary cylindrical gears, ha equals m whereas hd equal's 1.25m.

Exceptions do exist that change these individually. To increase both ease and efficiency, the Center Distance for every set must also be found.

- Center distance (Between First and Second Set): C12 = (D1+D2)/2 = 80mm

- Center distance (Between Second and Third Set): C34 = (D3+D4)/2 = 320mm

- Center distance (Betwen Third and Fourth Set): C56 = (D5+D6)/2 = 1682mm.

After properly investigating the previous variables, it is also conceivable to discover other details regarding this specific design. Contact Ratio denotes how often two teeth interact with one another throughout their life cycle while NP_min determines how many teeth are needed on a pinion for no snags to occur due to pressure variations. Finally, we determine NP_min by using the formula:

Np_min = 2*(1+sqrt(2/(2+2*sqrt(2)))*m) ≈ 12 teeth.

To reduce concerns that could further impair your machine, use the appropriate formulas and methods at every point in this process.

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The two specialized civil engineers Rafe is LIKELY working with are B. a construction engineer and an urban engineer

Based on the context of Rafe working on a light rail system, the other two specialized civil engineers he is likely working with would be:

A construction engineer: This engineer would be responsible for overseeing the construction activities related to the light rail system, ensuring that the design plans are implemented correctly and managing the construction process.

An urban engineer: This engineer specializes in urban planning and design, focusing on the development and integration of transportation systems within urban environments. They would work closely with Rafe to ensure that the light rail system aligns with the city's overall urban planning goals and effectively integrates with existing infrastructure.

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 The radius of each plate were doubled, but their separation was unchanged than the voltmeter would read 120V.

Voltmeters allow you to safely measure the voltage or electrical potential difference  between two points in a circuit without changing the voltage of that circuit. The ability to measure voltage is critical to the design and maintenance of high technology, but it also has more general and practical applications.

A voltmeter, also known as a voltmeter, is an instrument used to measure the potential difference or voltage between two points in an electrical or electronic circuit. Some voltmeters are designed for use in DC circuits; others are  for alternating current (AC) circuits.

Therefore,

If the radius of each plate is doubled but the separation remains unchanged. The capacitance will become,

C = ε₀A/d

Here,

A is the surface area of capacitor.

The area is, A = 4\(\pi r^{2}\)

Substitute 2r for r

A = 4\(\pi\)(\(2r^{2}\))

    = 16\(\pi r^{2}\)

Then, the capacitance becomes,

C = ε₀ 4A/d

  = 4 ε₀A/d

The capacitance is inversely proportional to the voltage. It can be concluded by the formula.

Q = CV

V∝ 1/C

Then, the voltmeter shows the reading as,

\(V^{f} = \frac{1}{V}\)

Substitute 12.0 V for V

\(V^{f} = \frac{1}{4} (120V)\)

     = 3V

If the radius becomes twice the capacitor, then the capacitance becomes 4 times. The capacitance is inversely proportional to the voltage. The voltage becomes one fourth the total voltage.

A voltmeter shows the reading of 120V.

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.

Answer:

Water is pumped from a lake to a storage tank of 15 m above at a rate of 70 L/s while consuming 15.4 kW of electric power. Disregarding any frictional losses in the pipes and any changes in kinetic energy, determine (a) the overall efficiency of the pump-motor unit and (b) the pressure difference between the inlet and the exit of the pump.Explanation:

The best example of an energy storage element in a solar energy system is the hot water tank in a solar hot water system.

In a solar hot water system, solar collectors absorb sunlight and heat a fluid, such as water or a heat transfer fluid. The heated fluid is then stored in a hot water tank for later use, such as for domestic hot water or space heating. The hot water tank serves as an energy storage element, allowing the system to provide hot water or space heating even when sunlight is not available, such as at night or on cloudy days. While the other options listed may play important roles in solar energy systems, they do not serve as energy storage elements. The photovoltaic array in a solar electric system generates electricity directly from sunlight, rather than storing energy. The overhang in a passively cooled home and the insulated windows in a passively heated solar home help to reduce energy consumption, but do not store energy. The sun-tracking mirrors in a power tower system are used to concentrate sunlight onto a receiver to produce electricity, but do not store energy.

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The efficiency of the turbine is the ratio of the net work done by the turbine to the energy added as heat. It is represented by the formula Efficiency = (Net Work Done by the Turbine/ Energy Added as Heat) × 100%.

The efficiency of the turbine can be calculated as shown below : Given : Energy added as heat = 69 400 J Net work done by the turbine = 21 300 JE = (Net Work Done by the Turbine/ Energy Added as Heat) × 100% E = (21 300/69 400) × 100% E = 30.67%Therefore, the efficiency of the turbine is 30.67%.

Note: The efficiency of a turbine is defined as the ratio of the net work done by the turbine to the energy added as heat. It can be expressed as a decimal or as a percentage.

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Answer:

Analyzing building related carbon emissions remains as one of the most increasing interests in sustainability research. While majority of carbon footprint studies addressing buildings differ in system boundaries, scopes, GHGs and methodology selected, the increasing number of carbon footprint reporting in response to legal and business demand paved the way for worldwide acceptance and adoption of the Greenhouse Gas Protocol (GHG Protocol) set by the World Resources Institute (WRI) and World Business Council for Sustainable Development (WBCSD). Current research is an important attempt to quantify the carbon footprint of the U.S. residential and commercial buildings in accordance with carbon accounting standards and Scopes set by WRI, in which all possible indirect emissions are also considered. Emissions through the construction, use, and disposal phases were calculated for the benchmark year 2002 by using a comprehensive hybrid economic input–output life cycle analysis. The results indicate that emissions from direct purchases of electricity (Scope 2) with 48% have the highest carbon footprint in the U.S. buildings. Indirect emissions (Scope 3) with 32% are greater than direct emissions (Scope 1) with 20.4%. Commuting is the most influential activity among the Scope 3 emissions with more than 10% of the carbon footprint of the U.S. buildings overall. Construction supply chain is another important contributor to the U.S. building's carbon footprint with 6% share. Use phase emissions are found to be the highest with 91% of the total emissions through all of the life cycle phases of the U.S. buildings.

Explanation:

One of the areas of sustainability research that is receiving the greatest attention right now is the analysis of building-related carbon emissions. Although the bulk of studies on carbon footprints of buildings have different system limits, scopes, GHGs, and methodology choices.

Building, road, bridge, or other structure construction, as well as steel structure manufacturing, are all considered to be part of the category of "construction works."

Building for commercial use is referred to as commercial construction. Commercial construction includes building for shops, offices, and educational institutions.

Residential development is concentrated on creating homes. Residential construction includes buildings like houses, apartments, and housing complexes.

With a 6% share, the construction supply chain is a significant contributor to the carbon footprint of American buildings.

With 91% of all emissions from all phases of the life cycle of American structures, use phase emissions are determined to be the greatest.

Thus, this is the scope of residential and commercial construction.

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The unit weight of the saturated silty clay is approximately 34.625 kN/m³.

The formula is:
y = (1 + w) * G * \(y_w\)

We have the following variables

γ = Unit weight of the clay

w = Water content of the clay

G = Specific gravity of the clay particles

\(y_w\) = Unit weight of water

water content is given as (w) = 28%

Specific gravity (G) = 2.7

we can now calculate the unit weight of the clay:

γ = (1 + 0.28) * 2.7 * 9.81

γ = 34.625 kN/m³

Therefore, the unit weight of the saturated silty clay is approximately 34.625 kN/m³.

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Answer:

the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Explanation:

Given that;

depth 1 = 71 ft

depth 2 = 10 ft

pressure p = 17 psi = 2448 lb/ft²

depth h = 71 ft - 10 ft = 61 ft

we know that;

p = P_air + yh

where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )

so we substitute;

p = 2448 + ( 49.3 × 61 )

= 2448 + 3007.3

= 5455.3 lb/ft³

= 37.88 psi

Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi