Which ordered pair is NOT a point on the graph of f(x)=1/2. x-7
(1,-61/2)
(2,8)
(-2,-8)
(0,-7)

Answer:

$51.36

$77.04 i think

Step-by-step explanation:

Multiply the cost of the number of pairs of jeans by the sales tax amount, 7%.

cost of 2 pairs:   48 + 7/100 x 48 = $51.36

cost of 3 pairs:   72 + 7/100 x 72 = $77.04

Answer:

jjanation:jdgjdjgdjgjkdkidjgjghdjjghhkd

Answer:

900400*10=9004000

900400*10=9004000900400*10=9004000900400*10=9004000

Answer: 3 pounds of apple pie

Step-by-step explanation:

If there are 8 pies and each one weighs 6 ounces, then we can multiply 6 and 8 to get a total of 48 ounces. Then we would convert ounces to pounds. 48 ounces is 3 pounds.

There are factors that makes a statement to be true. The false statement is that the projected unit sales volumes of branded footwear per company in Europe-Africa in Years 11-13 are higher than in North America.

The factors to consider in knowing a company's unit sales and market share of products such as branded footwear in a specific geographic region includes;

From the study, the market for branded athletic footwear is projected to grow approximately 9-11% annually in Latin America and the Asia-Pacific and 5-7% annually in North America an Europe-Africa during the Year 11-15.

Therefore the above is false since their projected growth is the same percentage.

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The implicit general solution is 0.5y² = -0.5x² + 0.5x + C, here C should pass through the origin of the circle. The family of curves (T)  represents the integral curve. The graph (T) is represented below.

a. To find the implicit general solution of the given differential equation, we can integrate both sides with respect to x. Let's start by rewriting the equation:

yy' = -x + 1/2

Integrating both sides:

∫ yy' dx = ∫ (-x + 1/2) dx

Using integration by parts on the left side, let u = y and dv = y' dx:

\(\int u dv = uv - \int v du\\\\y\int dy = \int (-x + 1/2) dx\\\\1/2 y^2 = -1/2 x^2 + 1/2 x + C\\\\0.5y^2 = -0.5x^2+0.5x+C\)

Where C is the constant of integration. This is the implicit general solution of the given differential equation.

b. The family of curves (T) that represents the general solution in an orthonormal system is known as the integral curves of the differential equation.

c. To find the graph (T) that passes through the origin O(0, 0), we substitute the point (x, y) = (0, 0) into the implicit general solution and solve for C:

\(1/2(0)^2 = -1/2(0)^2 + 1/2(0) + C\\\\0 = 0 + 0 + C\\\\\C = 0\)

So the graph (T) that passes through the origin is given by:

\(1/2 y^2 = -1/2 x^2 + 1/2 x\)

This equation represents the specific curve that satisfies both the differential equation and the condition of passing through the origin.

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Answer:

12

Step-by-step explanation:

if x = 3

and y = 4

3 + 4 + 5 = 12

what grade is this

Answer:

1. 4

2.40

3. 28

4.11

5.12

6. 1

7. 1200

Step-by-step explanation:

The value of (gof)(12) is 2.602.

Given,

F(x) = log2x and g(x) = 2^x.

We need to find the value of (g-f)(12).

What is a composite function?

In a composite function, we have two functions where one function range becomes the domain for the other function.

We have f(x) and g(x).

The composite function is denoted by:

(g o f) (x) = g ( f(x) )

Where f: A  ⇒ B and g: B → C

We have,

F(x) = log2x and g(x) = 2^x

We need to find (g o f)(12)

Now,

Applying the composite formula

(g o f)(12)

= g ( f(12) )

= g ( 1.38)

= 2.602

f(x) = log2x

f(12) = log(2x12) = log 24 = 1.38

g(x) = 2^x

g(1.38) = 2^1.38 = 2.602

Thus the value of ( g o f ) (12) is 2.602.

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The probability that 2 or fewer in the sample will favor the project is  4.368 × 10⁻⁶ and Also The data seem to indicate that the percent favoring the increase in fees is less than 70%

According to the question,

It is given that according to the student's government

The probability that number of students in favor of increment in fees : p = 0.70

The probability that number of students against the increment : q = 0.30

Sample Size : n = 12

Number of students follows Binomial distribution

(a) We have to find the probability that 2 or fewer in the sample will favor the project

P( x ≤ 2) = P(0) + P(1) + P(2)

As we know ,

P(x) = ⁿCₓpˣq⁽ⁿ⁻ˣ⁾

=> P( x ≤ 2) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰

=>  P( x ≤ 2) = 1×(0.30)¹² + 12×(0.70)(0.30)¹¹  + 12×11/2 × (0.70)²(0.30)¹⁰

=> P( x ≤ 2) = (0.30)¹⁰ [ 0.09 + 0.21 + 0.48]

=>  P( x ≤ 2) = 5.9×10⁻⁶[0.78]

=>  P( x ≤ 2) = 4.368 × 10⁻⁶

Which is very close to zero

(b) The data doesn't support the student government claim.

The data seem to indicate that the percent favoring the increase in fees is less than 70%.

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The most reasonable explanation for why Medera received zero calls between 3pm and 5pm is that she turned the phone off while playing in a soccer game.

Number is an abstract concept used to count or measure something. It is present in many aspects of our lives, from counting the number of people in a room to measuring a distance between two points. Numbers are also used to represent information and to quantify facts. We use numbers in mathematics, science, engineering, business, and many other fields. Numbers are also used in everyday life, such as for telling time, counting items, and measuring distances.

The most reasonable explanation for why Medera received zero calls between the hours of 3pm and 5pm is that Medera turned the phone off while playing in a soccer game. This can be seen by looking at the histogram, which shows that there were zero calls received around this time, while Medera was likely playing in the game. The graph also shows that Medera usually receives a cluster of calls at certain times. This is also evidence that she turned her phone off while playing in the game, as it would be unlikely that she would receive no calls if her phone was still on. Additionally, it is unlikely that Medera's phone can only receive 22 calls a day, as this would be an unusually low limit. Furthermore, it is unlikely that Medera lost her phone for two hours, as this would not explain why there were zero calls received. Therefore, the most reasonable explanation for why Medera received zero calls between 3pm and 5pm is that she turned the phone off while playing in a soccer game.

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The hours when no calls were received were most likely when Madera turned off the phone while practising soccer.

According to the question,

Madera, a middle school student, got phone calls from 10 a.m. to 10 p.m. on one Saturday.

From the scenarios presented, the one that would suggest this would be when Medera turned off his phone while playing soccer. This is because, her phone was turned off, it was not receiving any phone signal, which meant that no inbound calls were received during that time. Medara lost her phone for two hours, but even though she didn't have it with her, the phone was still on and connected to a network, indicating that calls were still streaming.

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The correct answer is:

O Yes; 7/56 and 48/6 are proportional because 7 * 6 = 48 * 56.

To determine  if the truck can travel 48 miles with 6 gallons of fuel, we can compare the ratios of fuel consumption to distance traveled.

Given that the truck needs 7 gallons of fuel to travel 56 miles, we can express this as the ratio 7/56 (gallons/miles).

If we compare it to the second scenario where the truck is traveling 48 miles, we can express it as the ratio 6/48 (gallons/miles).

To check if they are proportional, we can cross-multiply: 7 * 48 = 6 * 56. If the cross-multiplication results in equal values, then the ratios are proportional.

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Answer:

178

Step-by-step explanation:

100 plus 78 equal s 179

Answer:

0.3

Step-by-step explanation:

x is the number to be added to 0.7 to have a sum of 1.

\(0.7 + x = 1\)

\(x = 1 - 0.7\)

\(x = 0.3\)

Answer:

It helps you ☺️☺️

Thank you ☺️☺️

The total number of possible outcomes is given by the expression 6n × 52, where n represents the number of marbles to choose from.

To determine the number of possible outcomes, we need to consider the number of outcomes for each event and then multiply them together.

1. Picking a marble: Let's assume there are n marbles to choose from. If there are n marbles, then the number of outcomes for this event is n.

2. Rolling a die: A standard die has 6 sides numbered 1 to 6. Therefore, the number of outcomes for this event is 6.

3. Picking a card: A standard deck of cards has 52 cards. Hence, the number of outcomes for this event is 52.

To find the total number of possible outcomes, we multiply the number of outcomes for each event together:

Total number of outcomes = (number of outcomes for picking a marble) × (number of outcomes for rolling a die) × (number of outcomes for picking a card)

Total number of outcomes = n × 6 × 52

Therefore, the total number of possible outcomes is given by the expression 6n × 52, where n represents the number of marbles to choose from.

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Answer:

Domain: 0,1,2

The relation is a Function.

Step-by-step explanation:

hope this helps

A relation may or  may not be a function.

The relation is given as:

\(\mathbf{(x,y) = \{(0,0),(1,1),(2,0)\}}\)

List out the x-values

\(\mathbf{x = \{0,1,2\}}\)

The above set means that the x-values starts from 0 and ends at 2.

Hence, the domain is: [0,2]

For a relation to be a function, all y-values of the relation must point to different x-values.

So, we can say that, the given relation is a function, because all y-values have unique x values

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Answer: 180 gallons needed

Step-by-step explanation:

Zykeith,

Assume x gallons of 50% antifreeze is needed

Final mixture is x + 60 gallons

Amount of antifreeze in mixture is 0.4*(x+60)

Amount of antifreeze added is .5x + .1*60 = .5x + 6

so .5x + 6 = .4(x + 60)

.5x -.4x = 24 -6

.1x = 18

x = 180

Let x be the number of gallons of the 50% antifreeze solution needed. We know that the resulting mixture will be 70 + x gallons. To get a 40% antifreeze mixture, we can set up the following equation:

\({\implies 0.5x + 0.1(70) = 0.4(70 + x)}\)

Simplifying the equation:

\(\qquad\implies 0.5x + 7 = 28 + 0.4x\)

\(\qquad\quad\implies 0.1x = 21\)

\(\qquad\qquad\implies \bold{x = 210}\)

\(\therefore\) We need 210 gallons of the 50% antifreeze solution to mix with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze.

\(\blue{\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\)

Given statement solution is :- The present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.

To calculate the present value of an investment with compound interest, we can use the formula for the present value of an annuity:

PV = A *\((1 - (1 + r)^(-n)) / r\)

Where:

PV = Present value

A = Annual payment or cash flow

r = Interest rate per period

n = Number of periods

In this case, the annual payment (A) is R13,000, the interest rate (r) is 10% per year, and the investment is made for 8 years (n).

Using the formula and substituting the given values, we can calculate the present value:

PV = \(13000 * (1 - (1 + 0.10)^(-8)) / 0.10\)

Calculating this expression:

PV = \(13000 * (1 - 1.10^(-8)) / 0.10\)

= 13000 * (1 - 0.46318) / 0.10

= 13000 * 0.53682 / 0.10

= 6977.66 / 0.10

= 69776.6

Therefore, the present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.

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For the expression \(x^64 + ax^b + 25\) to be a perfect square for all integer values of x, b must be 64, and a must be a perfect square, written as a = \(y^2.\)

To determine the values of a and b such that the expression\(x^64 + ax^b\) + 25 is a perfect square for all integer values of x, we need to analyze the properties of perfect squares.

A perfect square is an expression that can be written as the square of another expression. In this case, we want the given expression to be in the form of\((x^n)^2,\) where n is an even integer.

Let's examine the given expression: \(x^64 + ax^b\) + 25

For it to be a perfect square, the quadratic term \(ax^b\)must have the same exponent as the leading term\(x^6^4.\) This means b must be equal to 64.

So we have:\(x^64 + ax^64 + 25\)

Now, we can rewrite this as:\((x^32)^2 + 2(x^32) (\sqrt{a}) + (\sqrt{25})^2\)

By comparing this with the standard form of a perfect square, (\(x^n +\sqrt{k} )^2\), we can deduce that √a must be equal to x^32 and \(\sqrt{25}\) must be equal to \(\sqrt{k.}\)

Therefore, we have: \(\sqrt{a} = x^3^2\)and\(\sqrt{25} = \sqrt{k}\)

From the second equation, we know that k = 25.

Now, substituting the value of k back into the first equation, we have: \(\sqrt{a} = x^3^2\)

To satisfy this equation for all integer values of x, a must be a perfect square. Therefore, we can express a as a =\(y^2\), where y is an integer.

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Answer:

The expected number of hunters who hit the duck they aim at is 3.6

Step-by-step explanation:

Given;

number of hunters, n = 6

the probability of killing a duck, p = 0.6

The expected number of hunters who hit the duck they aim at?

In binomial distribution, the expected value is equal to the product of the number of trials and the probability of success.

The expected number of hunters who hit the duck they aim at is calculated as follows;

E = np

E = 0.6 x 6

E = 3.6

Therefore, the expected number of hunters who hit the duck they aim at is 3.6

Quadrilateral JKLM has sides with equal lengths (√85), and the slopes of opposite sides are equal. However, it is not a special type of quadrilateral like a rectangle or a square.

To describe quadrilateral JKLM, let's first plot the given points J(9, 7), K(2, 1), L(0, -8), and M(7, -2) on a coordinate plane:

J(9, 7) K(2, 1)

L(0, -8)   M(7, -2)

To find the slopes and lengths of each side of the quadrilateral, we can use the distance formula and the slope formula.

Slope of JK:

Slope (m) = (change in y) / (change in x)

m(JK) = (7 - 1) / (9 - 2) = 6/7

Length of JK:

Length (d) = √[(x2 - x1)^2 + (y2 - y1)^2]

d(JK) = √[(9 - 2)^2 + (7 - 1)^2] = √(49 + 36) = √85

Slope of KL:

m(KL) = (-8 - 1) / (0 - 2) = -9/2

Length of KL:

d(KL) = √[(0 - 2)^2 + (-8 - 1)^2] = √(4 + 81) = √85

Slope of LM:

m(LM) = (-2 - (-8)) / (7 - 0) = 6/7 (same as slope of JK)

Length of LM:

d(LM) = √[(7 - 0)^2 + (-2 - (-8))^2] = √(49 + 36) = √85

Slope of MJ:

m(MJ) = (7 - (-2)) / (9 - 7) = 9

Length of MJ:

d(MJ) = √[(7 - 9)^2 + (-2 - (-8))^2] = √(4 + 36) = √40

Based on the calculations, we can describe quadrilateral JKLM as follows:

The slope of JK and LM is 6/7.

The slope of KL is -9/2.

The slope of MJ is 9.

The length of each side (JK, KL, LM, MJ) is √85.

The quadrilateral is not a rectangle or a square since the slopes of opposite sides (JK and LM) are not perpendicular.

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(a). The graph of y = -f(x) is shown in the image below.

(b). The graph of y = g(-x) is shown in the image below.

By applying a reflection over the x-axis to the parent absolute value function g(x) = |x + 2| - 4, the transformed absolute value function can be written as follows;

y = -f(x)

y = -|x + 2| - 4

Part b.

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

x and y represent the data points.

m represent the slope.

First of all, we would determine the slope of this line;

Slope (m) = rise/run

Slope (m) = -2/4

Slope (m) = -1/2

At data point (0, 5) and a slope of -1/2, a linear equation for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 5 = -1/2(x - 0)

g(x) = -x/2 + 5, -4 ≤ x ≤ 4.

y = g(-x)

y = x/2 + 5, -4 ≤ x ≤ 4.

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Answer:

1052 is MLII, 450 is CDL, 952 is CMLII, and 942 is CMXLII.

Step-by-step explanation:

For 1052, M=1000 L=50 and II= 2 and if you add all those you get 1052. For 450, CD=400 and L=50 and if you add all those up then you get 450. For 952, CM=900 L=50 and II=2 and if you add all those up then you get 952. For 942, CM=900 XL=40 and II=2, and if you add all those up then you get 942.

Answer:

31.

Step-by-step explanation:

π(18)l = 558π

l = 558/18 = 31

Therefore the answer is 31.

9514 1404 393

Answer:

  (C) f(x) = 5x +57

Step-by-step explanation:

Heart rate increases as speed increases, so only equations with a positive x-coefficient are of interest. It is pretty easy to see that ...

  f(x) = x+57

doesn't give ...

  f(4) = 77

However, the other reasonable choice is ...

  f(x) = 5x +57

which does give f(4) = 77.

The cosine ratio is given as:

\(\cos(\theta) = \frac{\sqrt 3}{2}\)

See attachment for the graph of \(\cos(\theta) = \frac{\sqrt 3}{2}\) under the domain of [0,∞)

From the graph, we can see that some values of \(\theta\) when \(\cos(\theta) = \frac{\sqrt 3}{2}\) are:

\(\theta = \frac{\pi}{6}\)    \(\theta = \frac{11\pi}{6}\) and \(\theta = \frac{13\pi}{6}\)

We have:

θ = 495°

Convert to radians

\(\theta = 495 * \frac{\pi}{180}\)

Evaluate

\(\theta = \frac{11\pi}{4}\)

The value of sec θ is then calculated as:

\(\sec(\theta) = \sec(\frac{11\pi}{4})\)

Using a calculator, we have:

\(\sec(\theta) = -1.414\)

Hence, the value of \(\sec(\theta)\) is -1.414

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a)The value of  ∠b=64°.

b)The values of angles q, r, s, t are ∠q= 65°, ∠r=65°, ∠s=50°, ∠t=65°.

c)The value of  ∠B=72 degrees.

The same-side interior angles are additional if a transversal connects two parallel lines. Alternate interior angles are equivalent if a transversal connects two parallel lines. Corresponding angles are equal.

a) Given line PQ is parallel to ST.

   One of the theorems of parallel lines is, Corresponding angles are equal.

Here the corresponding angles are ∠a, ∠b.

so, ∠a=∠b

∴∠b=64°

b) It is given that lines B and C are parallel, according to one of the theorems of parallel lines, vertically opposite angles are equal. So, the angle opposite to 65° is also equal to 65°. Sum of the angles suspended by a line on another line is 180°. Therefore the other angle in the triangle is 180°-130°=50°.

Since the sum of interior angles in a triangle is 180°, the angle q will be:

   ∠q= 180°-(65°+50°)

    ∠q= 65°.

Vertically opposite angles are equal, therefore ∠q=∠r=65°.

∠s=180°-(65°+65°)

∠s=50°.

Corresponding angles are equal, therefore

130°=65°+∠t

∠t=65°.

c) Given lines A, and B are parallel. We know that the Corresponding angles are equal, therefore

3m=4m-24

⇒m=24

Therefore ∠B=4(24)-24

∠B=72 degrees.

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\( \begin{cases} \\ \large\bf{\green{ \implies}} \tt \: - \: \frac{1}{2} \: m \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - \frac{1 \: m}{2} \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 9 \: \times \: 2 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 18 \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{ \cancel- 18}{ \cancel - 1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{18}{1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: 18 \: \\ \end{cases}\)

Answer:6 pens are blue

Step-by-step explanation:because 14-8=6 pens would be left and would be blue

let's firstly convert the mixed fractions to improper fractions.

\(\stackrel{mixed}{3\frac{2}{3}}\implies \cfrac{3\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{11}{3}}~\hfill \stackrel{mixed}{2\frac{1}{4}} \implies \cfrac{2\cdot 4+1}{4} \implies \stackrel{improper}{\cfrac{9}{4}} \\\\[-0.35em] ~\dotfill\\\\ -\cfrac{11}{3}-\left( \cfrac{9}{4} \right)\implies -\cfrac{11}{3}+\cfrac{9}{4}\implies \cfrac{-(4)11~~ + ~~(3)9}{\underset{\textit{using this LCD}}{12}} \\\\\\ \cfrac{-44+27}{12}\implies \cfrac{-17}{12}\implies {\Large \begin{array}{llll} -1\frac{5}{12} \end{array}}\)