Which one of the following compounds produces a basic solution when
dissolved in water?
N₂
OF2
ZnCl2
Rb20
SO2

Considering the reaction stoichiometry and the definition of limiting reagent, the mass of NaNO₃ that is produced when 25.0 grams of lead (II) nitrate react with 15.0 grams of sodium iodide is 8.50 grams.

The balanced reaction is:

Pb(NO₃)₂ + 2 Nal → PbI₂ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

The molar mass of the compounds present in the reaction is:

Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:  

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 331 grams of Pb(NO₃)₂ reacts with 299.8 grams of NaI, 25 grams of Pb(NO₃)₂ reacts with how much mass of NaI?

\(mass of NaI=\frac{25 grams of Pb(NO_{3} )_{2} x299.8 grams of NaI}{331 grams of Pb(NO_{3} )_{2} }\)

mass of NaI= 22.64 grams

But 22.64 grams of NaI are not available, 15 grams are available. Since you have less mass than you need to react with 25 grams of Pb(NO₃)₂, NaI will be the limiting reagent.

Then, it is possible to determine the mass of NaNO₃ produced by another rule of three, taking into account the limiting reagent: if by stoichiometry 299.8 grams of NaI produce 170 grams of NaNO₃, 15 grams of NaI how much mass of NaNO₃ will be formed?

\(mass of NaNO_{3} =\frac{15 grams of NaIx170 grams of NaNO_{3}}{299.8 grams of NaI}\)

mass of NaNO₃= 8.50 grams

In summary, the mass of NaNO₃ that is produced when 25.0 grams of lead (II) nitrate react with 15.0 grams of sodium iodide is 8.50 grams.

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Answer: b) calcium sulfide

Explanation:

Answer:

residue is whatever remains after something else has been removed while filtrate is the liquid or solution that has passed through a filter, and which has been separated from the filtride.

filtration id done by placing a filter paper on the beaker or container then pour the filtride then let it settle and it will pass through and you will have the fitrate and residue

Explanation:

The density of nitrogen gas at 67.3 °C and 0.288 atm is approximately 0.0147 g/L.

Nitrogen are commonly used during sample preparation in chemical analysis and It also used to concentrate and reduce the volume of liquid sample.

The density of a gas can be calculated using the Ideal Gas Law:

PV = nRT

We can rearrange the equation to solve for the volume:

V = nRT / P

And then use the density formula:

density = mass / volume = m / V

where m is the mass of the gas and V is the volume.

Since the moles and the mass of a gas are related by its molecular weight (m = n * MW), we can substitute n * MW for m:

density = (n * MW) / V

Plugging in the values we get:

density = (n * 28.01) / (RT / P)

density = (n * 28.01 g/mol) / ((8.31 J/molK * (67.3 + 273.15 K)) / 0.288 atm)

density = (n * 28.01 g/mol) / (547.57 J/mol / 0.288 atm)

density = (n * 28.01 g/mol) / (1915.69 J/mol / atm)

density = (n * 28.01 g/mol) * (1 atm / 1915.69 J/mol)

density = 0.0147 g/L

Therefore, The density of nitrogen gas at 67.3 °C and 0.288 atm is approximately 0.0147 g/L.

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The density of the Nitrogen gas is 0.29 g/mol.

The Ideal gas law is a scientific equation that describes the behavior of an ideal gas, a theoretical gas made up of a large number of particles that do not interact with each other. The Ideal gas law states that the pressure, volume, and temperature of an ideal gas are directly proportional to each other.

Using the formula;

d = MP/RT

Density = d

Molar mass of the gas = M

Gas constant = R

Temperature = T

d= 28 g/mol * 0.288/0.082 * 340.3

d = 8.06/27.9

d = 0.29 g/mol

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Balance the half-reactions to guarantee that the number of electrons transferred in both reactions is the same:

NO3- + 8H+ + 10e- N2 + 4H2O H2 2H+ + 2e- NO3- + 8H+ + 10e-

The next step is to figure out how many electrons are moved when 145 molecules of H2 are oxidized. We can see from the balanced equation for the H2 half-reaction that 1 molecule of H2 makes 2 electrons:

2H+ + 2e- → H2

As a result, 145 molecules of H2 will yield:

145 molecular units H2 has two protons per molecule. 290 electrons Equals H2

Finally, we can use the denitrification reaction balanced equation to calculate how many molecules of N2 are created for 290 electrons:

1 molecule of N2 is produced by 10 electrons.

Therefore, 1 molecule N2 290 electrons/10 electrons = 29 molecules N2

29 molecules of N2 gas will be created.

To answer the second query, we must balance the half-reactions:

SO42- + 8H+ + 8e- H2S + 4H2O CO2 + 8H+ + 8e- CH3COO- + 2H2O SO42- + 8H+ + 8e- H2S + 4H2O

The balanced formulae show that 8 electrons are transferred in both half-reactions. As a result, in order to oxidize 48 molecules of CH3COO-, 6 molecules of SO42- must be reduced:

There are 48 nuclei CH3COO- 8 electrons per atom 384 protons = CH3CO-

384 electrons (eight electrons per atom) 48 units of SO42- SO42-

As a result, 48 molecules of CH3COO- reduced to CO2 will yield:

six electrons 4 H2O/molecule SO42- 24 units of SO42- H2O

The answer is that 24 molecules of water will be created.

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Answer:

lt serves as a home where crews of astronauts and cosmonauts live. The space station is also a unique science laboratory. Several nations worked together to build and use the space station. The space station is made of parts that were assembled in space by astronauts.

Explanation:

The strand 1 of hydrocarbons is used to produce plastic, hence option D is correct.

Raw resources like natural gas, oil, or plants that have been processed into ethane and propane are used to make plastics. The subsequent "cracking" procedure uses heat to transform ethane and propane into ethylene and propylene. To produce various polymers, these components are mixed.

Propylene is a substance found in large quantities in petroleum. In order to speed up chemical processes, refiners combine heated propylene with a catalyst to create plastic. Propylene molecules start to cluster together like beads on a thread as a result.

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Answer:

0 mg

Explanation:

after 24 days all of it would be gone.

Phosphorus only has a 24 day life span.

C. flow under dense and become more thick.

A substance that is tightly packed or has a high density.

The term "density" refers to the relationship between a substance's mass and the volume it takes up in space (volume). The mass, size, and arrangement of an object's atoms influence its density. The ratio of a substance's mass to its volume is said to be its density, or D.

Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. An object will frequently float as long as its density is less than that of the liquid.

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Answer:

dk

Explanation:

Answer:

2.3 mol of N2

Explanation:

mol N2 = 3.5 mol O2 x. 2 mol N2  

3 mol O2. = 2.3 mol N2.

False, oxygen is more electronegative than boron

What is electronegativity?

It is the tendency of an atom in a molecule to attract shared pair of electrons towards itself is known as electronegativity.

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The observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.

From the observation that the hole in the window is smaller on the outside than on the inside, Becca, as a forensic technician, might deduce the following:

The hole was caused by an impact from the outside: The smaller outside hole suggests that the force that created the hole originated from the outside and exerted more pressure on the window surface facing inward.

The object causing the hole was larger on the inside: The discrepancy in hole sizes implies that the object that struck the window had a larger size or diameter on the inside, and as it penetrated the glass, it compressed or fragmented the glass, resulting in a larger hole on the inside.

The object may have passed through the window: The difference in hole sizes indicates that the object may have penetrated the window, potentially passing through to the inside. This could suggest a break-in or an incident involving the window being struck from the outside.

Overall, the observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.

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Taking into account the reaction stoichiometry, 1 mole of H₂ can be produced by reacting 2 moles of HCI.

In first place, the balanced reaction is:

Mg + 2 HCl  → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

By reaction stoichiometry 2 moles of HCl form 1 mole of H₂.

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Answer:

o

Explanation:

it is not a gas because the particles do not move freely it may be a liquid or a solid partly and mostly liquidized.

Explanation:

Pressure = Force/Area

therefore,

P = 15/0.00372

= 4.03 X10^³N/m²

There is a nine-fold rise in the pace of the reaction when the concentration of F is tripled but the concentration of G stays the same. The response is in the second order relative to F.

If you increase one reactant's concentration in a third order reaction involving two reactants by three times, the rate rises by a factor of three. If a reactant is first order, its concentration will cause a doubling in the reaction's rate; a tripling in the reaction's rate, etc. If a reactant is third order, its rate of reaction will increase by a factor of 8 when its concentration is doubled (23 = 8), etc.

The concentration of a reactant does not impact the rate. The rate remains unchanged even if the concentration is doubled. The given rate law needs to be written first. The concentrations of A and B will be increased by three times each after that.

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Answer:

0.8 L

Explanation:

The volume of the stock solution needed to make 2.0 L of 0.20M MgSO4 is 0.8 L.

Answer:

32 mL

Explanation:

To answer this question we'll use Charles' law, which relates the temperature and volume of a gas at constant pressure:

V₁T₂=V₂T₁

Now we convert the given temperatures to K:

And given that V₁ = 45 mL, we can input the data:

And solve for V₂:

Answer:

Explanation:

The time spent in driving can be found by using the formula

\(t = \frac{d}{v} \\ \)

d is the distance

v is the velocity

From the question we have

\(t = \frac{2952}{82} \\ \)

We have the final answer as

Hope this helps you

The maximum amount of HF that can be formed is 0.312 mol. The formula for the limiting reagent is SiF4. The amount of excess H2O that was consumed is: n(H2O excess consumed) = 0.

Limiting reagent is the reactant that is completely used up in reaction and hence determines when the reaction stops.

SiF4(s) + 2 H2O(l) → 4 HF(aq) + SiO2(s)

Molar masses of SiF4 and H2O are:

SiF4: 28.09 + 4 x 19.00 = 104.09 g/mol

H2O: 2 x 1.01 + 16.00 = 18.02 g/mol

Number of moles of each reactant is:

n(SiF4) = 8.10 g / 104.09 g/mol = 0.0779 mol

n(H2O) = 5.90 g / 18.02 g/mol = 0.327 mol

For SiF4: n(HF) = 0.0779 mol SiF4 × (4 mol HF / 1 mol SiF4) = 0.312 mol HF

For H2O: n(HF) = 0.327 mol H2O × (4 mol HF / 2 mol H2O) = 0.654 mol HF

We see that H2O produces a larger amount of HF than SiF4, indicating that SiF4 is limiting reagent. Therefore, the maximum amount of HF that can be formed is 0.312 mol.

The formula for the limiting reagent is SiF4.

From the balanced equation, we see that 1 mol of SiF4 reacts with 2 mol of H2O to produce 4 mol of HF. Therefore, the amount of H2O required to react with 0.0779 mol of SiF4 is:

n(H2O) = 0.0779 mol SiF4 × (2 mol H2O / 1 mol SiF4) = 0.1558 mol H2O

The amount of excess H2O that was consumed is: n(H2O excess consumed) = 0.

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Answer:

Thermal To Potential

Explanation:

It is thermal to potential as the hot air aka thermal power is causing the balloon to rise and potential as it is in a state where it can be easily moved making kinetic but that is a potential.

Answer:

oceanic formation is the right answer.

Explanation:

this os becoz they slide a past each other and do not rub against each other

[H⁺]=6.696 x 10⁻⁵

pH = 4.174

Given

The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution

Required

the [H+]  and pH

Solution

Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids

For weak acid :

\(\tt [H^+]=\sqrt{Ka.M}\)

Input the value :

[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴

[H⁺]=6.696 x 10⁻⁵

pH = - log [H⁺]

pH = - log 6.696 x 10⁻⁵

pH = 5 - log 6.696

pH = 4.174

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer: For the balanced redox equation, you should add the half reactions.

Like this.

Explanation:

Was it helpful? Or do you need different answer?

Answer:

Ag2CrO4

silver chromate, 331.966 g/mol

Ag=65%, Cr=15% O=19%

CH4

Methane, 16 g/mol

C=75% H=25%

Ca3(PO4)2

calcium Phosphate, 310 g/mol

Ca=38.7% P=20% O=41.3%

C7H5N3O6

227 g/mol

C=37% H=2.2% N=18.5% O=42.3%

K2C6H5O7

BAIDAR citron, 267 g/mol

CoCl2

Cobalt (ll) Chloride, 129.93

Explanation:

\(molar \: mass = m \div n \\ (m = mass \: of \: a \: substance \: in \: gram \: ) \\( n = no. \: of \: moles)\)

Ag2CrO4

Ag=108, Cr=51.996, O=16

\(m = \frac{108 \times 2 + 51.996 + 16 \times 4}{1} \\ = 331.966\)

Ag percentage in Ag2CrO4

[(108x2)/331.966]x100

=65%

Cr percentage in Ag2CrO4

[51.966/331.966]x100

=15%

O percentage in Ag2CrO4

[(16x4)/331.966]x100

=19%

CH4

C=12 H=1

12+1x4=16 g/mol

C percentage in CH4

(12/16)x100

75%

H percentage in CH4

(4/16)x100

25%

Ca3(PO4)2

Ca=40 P=31 O=16

40x3+31x2+16x8

=310 g/mol

Ca % in Ca3(PO4)2

[(40x3) /310]x100

38.7%

P % in Ca3(PO4)2

[(31x2)/310]x100

20%

O % in Ca3(PO4)2

[(16x8)/310]x100

41.3%

C7H5N3O6

C=12 H=1 N=14 O=16

12x7+1x5+14x3+16x6

227 g/mol

C % in C7H5N3O6

[(12x7)/227]x100

37%

H % in C7H5N3O6

[(1x5)/227]x100

2.2%

N % in C7H5N3O6

[(14x3)/227]x100

18.5%

O % in C7H5N3O6

[(16x6)/227]

42.3%

please add this on brainleist it took me long time to write

Answer:

Matter is anything that has mass and takes up space.  Matter can change form through physical and chemical changes, but through any of these changes, matter is conserved. The same amount of matter exists before and after the change none is created or destroyed. This concept is called the Law of Conservation of Mass.