Which of these molecules acts as o2 reserve for the tissue energy needs?.

(a) Numerical value of the ratio 3GM/rc² at the surface of the sun is approximately 2.12 × 10⁻⁶; (b) Trajectory is a straight line; (c) Radius = r = 3GM = 3 × Gravitational Constant × Mass of Sun, that is  3.762 × 10²⁰ m³s⁻² kg.

(a) We need to find the numerical value of the ratio 3GM/rc² at the surface of the sun. Substitute the given values into the equation. The mass of the sun (M) is 2.0 × 10³⁰ kg. Radius (r) is 7 × 10⁵ km.

Convert the radius from kilometers to meters,

r = 7 × 10⁵ km = 7 × 10⁸⁸ m

Calculating the ratio.

Ratio = (3GM)/(rc²)

\(= \frac{3G(2(10^{30}))}{7(10^{8}3(10^{8}))} \\= \frac{(6.67(10^{-11}))3G(2(10^{30}))}{7(10^{8}3(10^{8}))} \\\\\)

= (13.34 × 10¹⁹)/(63 × 10²⁴)

≈ 2.12 × 10⁻⁶

Numerical value of the ratio 3GM/rc² at the surface of the sun is approximately 2.12 × 10⁻⁶.

(b) We neglect the right-hand side of the equation. That means the differential equation.

d'u = 0

Integrating both sides.

du = 0

Integrating again.

u = constant

This means that the trajectory is a straight line.

(c) We have to find the radius at which the trajectory of light forms a circular orbit around a black hole.

3GMu - u² = 0

3GMu = u²

Dividing both sides by u (assuming u ≠ 0).

3GM = u

Substituting u = 1/r.

3GM = 1/r

Rearranging the equation,

r = 3GM

3GM = 3 * (mass of the sun) * (gravitational constant)

Assuming the mass of the sun (M) is approximately 1.989 × 10³⁰ kg, we can compute,

3GM = 3 * (1.989 × 10³⁰ kg) * (6.67430 × 10⁻¹¹ m^3 kg⁻¹ s⁻²)

3GM ≈ 3.762 × 10²⁰ m³s⁻² kg

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Answer: I's either A. Matter no longer exists or D. Particles no longer move

Explanation:

Sorry if I get it wrong

Hope his helps :)

Answer:

d

Explanation:

He is going at the velocity of 40m/s even though he started at rest.

What is acceleration?

Acceleration is the rate at which velocity changes with respect to both speed as well as distance. If an object speeds up or down and is moving in a straight line, then the object is said to be accelerated. In a circular motion, the speed remains constant but the body is accelerated as the direction keeps on changing. The SI Unit is meter per second m/s2

Acceleration= 10m/s2

Initial velocity= 0m/s as the body started at rest.

Distance = 80 m

v2= u2+ 2aS

  = 02+ 2 10 80

  = 1600

v= 40m/s

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Your answer would be option 3/C

Heat is due to the motion of molecules.

There will not be any effect on rubber balls but if there will be metallic ball then emf will be generated in the ball and its falling speed will be reduced slightly.

Gravity attracts objects with mass to one another. We frequently consider the gravity of the Earth. This force holds the body in place. Any object with mass, on the other hand, has a gravitational effect on all other objects with mass. Gravity is measured by the acceleration it imparts to an object in free fall.

On the Earth's surface, the acceleration in free fall is approximately 9.8 metres (32 feet) per second. So, for every second that an object falls freely, its speed increases by approximately 9.8 metres per second. Gravity is a force that does not make contact with anything. Gravity does not require any contact with the object. Gravity affects all objects, even if they are not in contact with the ground.

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Answer:

32 m/s

Explanation:

The speed of a bus is 30 m/s due East wrt the passenger

He also sees a  passenger on the bus walking to the back at 2 m/s.

We need to find the passenger's velocity relative  to the bus. As the observer sees that the bus and the passenger are moving in opposite direction. Let v is the relative velocity. So,

v = 30 m/s + 2 m/s

v = 32 m/s

Hence, the passenger's velocity relative  to the bus is 32 m/s.

Answer:

The correct option is;

B. Subtract vectors A from C; \(F_{Net}\) = 12 N

Explanation:

The given parameters are;

The weight of the dresser = 250 N

The force applied by the man = 20 N = C

The frictional force provided by the carpet = 8 N = The component of the weight resisting motion = A

Therefore, the net force tending to put the dresser in motion, \(F_{Net}\), is given as follows;

\(F_{Net}\) = The force applied by the man, C - The frictional force provided by the carpet which is the component of the weight resisting motion, A

\(F_{Net}\) = C - A = 20 N - 8 N = 12 N

\(F_{Net}\) = 12 N

The resulting net force, \(F_{Net}\) = 12 N.

The resultant force can be obtained by subtracting vector C from Vector A and the value of net force is 12 N. Hence, option (C) is correct.

Given data:

The weight of man is, W = 250 N.

The magnitude of applied force is, F = 20 N.

The magnitude of frictional force is, f = 8 N.

As per the given problem and the diagram let the applied force be denoted by vector A, Then,

Magnitude of Vector A = 20 N

And the frictional force be denoted by vector C. Then,

Magnitude of Vector C = 8 N

We know that the role of frictional force is to oppose the motion or to oppose the effect of applied force. Then the resultant force is given as,

\(F_{net} = F-f\\\\F_{net} = 20 - 8\\\\F_{net} = 12 \;\rm N\)

Thus, we can conclude that the resultant force can be obtained by subtracting vector C from Vector A and the value of net force is 12 N. Hence, option (C) is correct.

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Answer:

24° north of east

Explanation:

tan(x)=90/200 ie x=arctan(90/200)=24°

So the plane took off 24° east.

Answer:

24° north of east

Explanation:

Hope this will help

A person's strength, speed, power, agility, flexibility, and endurance are all increased with cross training, which also helps to reduce the chance of injury.

Cross-training is the technique of preparing employees to perform duties that go outside of their typical responsibilities or to work in multiple different jobs. For instance, cross-training could be used to teach someone who works in collections how to work in billing, and the other way around.

This is based on the finding that strengthening one limb while exercising the opposite limb results in a phenomena known as cross-training, also known as the contralateral strength training effect.

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True. Cross training is a type of training routine that combines two or more different exercises into a workout to prevent injuries, burnout, and overuse.

What is the cross-training training method?

Cross-training is the technique of preparing employees to perform duties that go outside of their typical responsibilities or to work in multiple different jobs. For instance, cross-training could be used to teach someone who works in collections how to work in billing, and the other way around.

A piece of cardio training equipment is a cross trainer, commonly referred to as an elliptical trainer. It is a fantastic full-body exercise and works your arms and legs at the same time. Cross training and a cross trainer are very different from one another, however a cross trainer can play a significant role in a cross training regimen.

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The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

The given parameters:

The net force on the pail of water at the top of the vertical circle is calculated as follows;

\(T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s\)

Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s

We are given;

Mass of the pail of water; m = 2000 g = 2kg

Radius of the circle; r = 1 m

Tension exerted by string; T = 25 N

To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;

W - T = ma

Where;

W is weight = mg

T is tension on the string

Now, in circular motion, we know that;

Acceleration is; a = v²/r

Thus;

mg - T = m(v²/r)

Making v the subject of the formula gives us;

v = √[(r(T + mg)/m)

Plugging in the relevant values gives;

v = √[(1(25 + (2 * 9.8))/2)

v = 4.722 m/s

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The maximum kinetic energy is 0.91 eV

A Work Function of a Metal is the minimum energy required to liberate an electron from a metal surface. From the formula;

hF = hf + E

Given that a Barium has a work function of 2.48eV. What is the maximum kinetic energy ?

Convert eV to Joule by multiplying by 1.6 x \(10^{-19}\)

hf = 2.48 x 1.6 x \(10^{-19}\)

hf = 3.968 x \(10^{-19}\) J

If the metal is illuminated by UV light of wavelength 365nm,

E = hF = hc/λ

Where

Substitute all the parameters

hF = (6.6 x \(10^{-34}\) x  3 x \(10^{8}\)) / 365 x \(10^{-9}\)

hF = 1.98 x \(10^{-25}\) /  365 x \(10^{-9}\)

hF = 5.42 x \(10^{-19}\) Joule

The maximum kinetic energy will be

hF = hf + E

Make E the subject of formula

E = hF - hf

E = 5.42 x \(10^{-19}\) - 3.968 x \(10^{-19}\)

E = 1.452 x \(10^{-19}\) J

Convert Joule back to eV by dividing by 1.6 x \(10^{-19}\)

E = 1.452 x \(10^{-19}\) / 1.6 x \(10^{-19}\)

E = 0.9075 eV

Therefore, the maximum kinetic energy is 0.91 eV approximately

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Answer:

2 m/s/s

Explanation:

a= (vf-vi)/t

a = (26-22) / 2

a = 2 m/s/s

The Carolingian Empire began when Charlemagne was crowned by the Pope in 800.

This event marked the formal recognition of Charlemagne as the emperor of the Carolingian Empire, which encompassed a significant portion of Western Europe. Charlemagne's crowning by the Pope demonstrated the close relationship between the Carolingian rulers and the papacy, solidifying their authority and status as the dominant power in the region. The establishment of the Carolingian Empire under Charlemagne's rule marked a significant political and cultural development in Europe during the early Middle Ages.

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The oval shape of the galaxy identifies it as an elliptical galaxy (remember ellipses are circular).

An elliptical galaxy is a type of galaxy characterized by its smooth and featureless shape, resembling an elongated or flattened sphere, or an oval. Elliptical galaxies are among the three main types of galaxies, the other two being spiral galaxies and irregular galaxies.

Elliptical galaxies are typically composed of older stars, with very little gas and dust, and little or no ongoing star formation. They are classified according to their shape on the Hubble sequence, with the most spherical ellipticals being classified as E0, and the most elongated ones being classified as E7.

Elliptical galaxies range in size from small dwarf galaxies to giant ellipticals that can contain trillions of stars. They are believed to form through mergers of smaller galaxies, or through the collapse of gas and dust in the early universe. Elliptical galaxies are also often found at the centers of galaxy clusters, where they can play a role in shaping the structure and dynamics of the cluster.

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Answer:

26.5m/s²

Explanation:

Given parameters:

Tangential velocity of the object  = 23m/s

Radius of track = 20m

Unknown:

Acceleration = ?

Solution:

The acceleration of the body is its centripetal acceleration. It is given by;

  a  = \(\frac{v^{2} }{r}\)  

v is the tangential velocity

r is the

          a  = \(\frac{23^{2} }{20}\)   = 26.5m/s²

All of the following (radio waves, visible light, x-rays, and infrared light) travel at the speed of light, which is 299,792,458 meters per second. Therefore, none of them travel at the same speed.

Electromagnetic waves are a type of energy wave that consists of oscillating electric and magnetic fields, which propagate through space at the speed of light. They are created by the motion of charged particles, and they can travel through a vacuum or through various materials.

All of the options listed, including radio waves, visible light, X-rays, and infrared light, travel at the same speed, which is the speed of light in a vacuum and all of them are electromagnetic waves. This speed is approximately 299,792,458 meters per second (or about 186,282 miles per second).

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Answer:

Try To Burp Or Give The Baby Warm Drinks

Explanation:

Try to burp them by patting their back (beware they might spit up!)

Or change their position

Answer:

The correct choice is A. She should just create a long-term goal.

Answer:

Force = Mass x Acceleration. Since the acceleration of gravity is always constant at 9.81 m/s2, the force of gravity is constant as well, according to Newton. If the object is sitting motionless on the ground, then the net force (sum of all forces) acting on it is zero

Explanation:

sorry if it doesn't help

Answer:

they do not function appropriately in the tissue or organ they are a part of.

The statement that is true about cancer cells is They do not function appropriately in the tissue or organ they are a part of. Option C is the correct answer.

Cancer cells differ from normal cells in several ways. One of the key characteristics of cancer cells is that they lose their normal function and behavior within the tissue or organ they originate from. Option C is the correct answer.

Normal cells have specific roles and functions within the body, contributing to the overall health and proper functioning of the tissue or organ they are a part of. In contrast, cancer cells undergo a series of genetic mutations that disrupt their normal function. These mutations can lead to uncontrolled cell growth and division, which is a hallmark of cancer. As a result, cancer cells no longer perform the specialized functions of the tissue or organ they are derived from, and they can interfere with the normal functioning of nearby healthy cells.

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The complete question is, "What is TRUE about cancer cells?

a. They are just like normal cells except for the way they function.

b. They form an encapsulated tumor that keeps them in one area of the body

c. They do not function appropriately in the tissue or organ they are a part of.

d. The mutations in cancer cells are caused by environmental factors."

the structural properties that account for the two signals at 175 ppm in the 13C NMR spectrum. The 13C NMR spectrum provides information .about the chemical environment of carbon atoms.

in a molecule, but additional information and analysis are required to determine the exact structural features that account for a particular signal, such as knowledge of the molecule's chemical structure, other NMR spectra (such as 1H NMR), and an understanding of the coupling between carbon and proton nuclei. To develop an educated assessment of the signals in the 13C NMR spectrum, it is critical to analyze all of the available information from the three spectra. This might entail comparing the signals in the 13C NMR spectra. to those in the 1H NMR and/or other spectra, as well as an evaluation of the chemical shifts and coupling patterns of the signals under examination. Furthermore, the molecule structure, solvent, and sample conditions can all have an impact on the appearance of the NMR spectra, thus these parameters should be considered as well.

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If a sheet of aluminum foil is held in front of a radioactive source. Two types of radiation are detected on the other side. The alpha particle radiation will not be detected.

The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.

As given in the problem statement, if a sheet of aluminum foil is held in front of a radioactive source. Two types of radiation are detected on the other side, then we have to find which type of radiation will not be detected on the other side.

When a radioactive source is in front of a sheet of aluminum foil. On the opposite side, radiation of two different sorts is seen. There won't be any indication of alpha particle radiation.

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The average speed in miles per hour is 65 mph.

Total distance d = 2275 miles

Total time t = 45 hours

To calculate average velocity

v = d/t

where v is velocity, d is distance and t is time.

v = 2275/45

v = 65 mph.

Thus, the average speed in miles per hour is 65 mph.

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Answer:

A simple machine is a mechanical device that helps to amplify or modify force, speed, or direction of motion. One common example of a simple machine is a lever. A lever is a rigid bar that rotates around a fixed point called a fulcrum. Depending on the placement of the fulcrum, levers can act as force multipliers, speed multipliers, or direction multipliers.

Explanation:

As an example, consider a seesaw with a length of 4 meters and a fulcrum positioned in the middle. If a person weighing 100 kg sits on one end of the seesaw, the force they apply to the lever is 100 kg x 9.81 m/s^2 = 981 N. If they push down on their end of the seesaw with a force of 500 N, the seesaw will move upward because the force they apply is greater than the weight of the person. In this case, the seesaw is acting as a force multiplier, amplifying the force applied by the person.

Alternatively, if the same seesaw is used to launch a ball, the person on one end could apply a smaller force over a longer distance. For example, if they apply a force of 50 N over a distance of 2 meters, the ball will be launched with a force of 100 N (50 N x 2) but a lower speed due to the increased distance traveled. In this case, the seesaw is acting as a speed multiplier, increasing the speed of the ball by decreasing the force applied but increasing the distance traveled.

Finally, if the seesaw is used to change the direction of motion, the fulcrum can be moved to one end of the lever and the force applied to the other end can be redirected. For example, if the seesaw is used to lift a heavy object by placing the object on one end and applying force to the other end, the seesaw is acting as a direction multiplier, changing the direction of motion of the force applied.

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The gravitational potential energy is the work done or energy transfered per unit mass which is required to move an object to that location from a fixed reference point.

Schematic diagram:

The gravitational potential energy of the pendulum bob having mass m relative to its center position is given as,

Here, m is the mass of the bob pendulum, g is the acceleration due to gravity, and h is the height from surface.

Therefore, the gravitational potential energy of the pendulum bob relative to its normal center position when it is first released is mgh.

The period of the pendulum on the surface of Mars, where g = 3.71m/s², would be the same as the period on Earth, 1.70s.  The pendulum on the surface of Mars has a period of roughly 3.31 seconds, according to our calculation of this expression.

A basic pendulum's period is determined by the equation T = 2(L/g), where T is the period, L is the pendulum's length, and g is the acceleration brought on by gravity.

L = (T/(2))2g can be solved for on Earth with a period of 1.70s by rearranging the equation.

Using the same equation and the Mars surface gravity, g = 3.71m/s2, we can now get the period on Mars' surface: T\(_{mars}\) = 2(L/g\(_{mars}\)).

The equation T\(_{mars}\) = 2(((T/(2))2g)/(g\(_{mars}\))) is obtained by substituting the expression for L and the surface gravity of Mars.

T\(_{mars}\) = T(g/g_Mars), to simplify the formula.

T\(_{mars}\) = 1.70s(9.81m/s2 / 3.71m/s) is the result of plugging in the data. The pendulum on the surface of Mars has a period of roughly 3.31 seconds, according to our calculation of this expression.

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Answer:

it g hope it helps you out