Rock, metal, and ices comprised of substances like water, ammonia, and methane all solidified and became big enough to gravitationally pull hydrogen and helium gas from the Solar Nebula.
Does Nevada provide a solar tax credit?The Federal Solar Tax Credit, often known as the Residential Clean Energy Credit, is available to the majority of Nevadans. The price of installing solar panels can be written off by qualifying homeowners from their federal income taxes in 2022 by up to 30%.
Solar or gas is more affordable?The comparison between solar and natural gas reveals that solar is superior to natural gas in every way. Not a single one for average Australians! But it offers one key benefit for the powerful people in the fossil fuel industry.
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an incline projection can achive maximium horizontal horizontal range at an angle of projection,ፀ=45 why?
Answer:
Explanation:
For an incline projection made at angle of θ , expression of horizontal range R can be given by the following equation .
R = u² sin 2θ / g
u is initial velocity of throw .
For range R to be maximum , the value of sin 2θ must be maximum . The maximum value of sin of an angle is 1 , so
For maximum R ,
sin2θ = 1 = sin90
2θ = 90 .
θ = 45⁰ .
So for projection made at 45⁰ , horizontal range is maximum .
HELP URGENT- will give brainliest if correct
Answer:
6 km is the right answer
hope it helps you
Explanation:
please mark me as brainliest
What is the best flowers
Answer:
What are the best flowers? (My opinion)
Water liliesWhite rosesHydrangeaExplanation:
You're welcome.
Answer:
Tulips,
Lilies,
Lotuses on my opinion...
The force F shown in Figure 4.30 has a moment of 40 Nm about the pivot. Calculate the magnitude
of the force F.
\(\boxed{\sf \tau=rFsin\theta}\)
Put values
\(\\ \rm\hookrightarrow 40=2Fsin40\)
\(\\ \rm\hookrightarrow Fsin40=20\)
\(\\ \rm\hookrightarrow 0.64F=20\)
\(\\ \rm\hookrightarrow F=31.25N\)
The moment of force is 40 Nm here. The displacement is 2.5 m and the angle of inclination is 45°. The force about the pivot is then 28.2 N.
What is moment of force?Moment of force is the product of the force and distance from a fixed axis. Moment of force can be calculated for both balanced and unbalanced forces.
The expression for moment of force relating the distance d and force f with an angle of inclination θ is written as below:
moment of force = f d sin θ
Given that moment of force = 40 Nm
distance from the fixed axis from the figure = 2 m
angle of inclination = 45 °
40 Nm = 2 f sin 45.
20 = f sin 45
f = 20 N / sin 45
= 28.2 N
Therefore, the force about the pivot is 28.2 N.
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Would it be possible to direct the speeds that a coaster will reach before its ever placed on a track?How?
Yes, it is possible to determine the final speed of the rollercoaster if the initial speed and the height to be reached are known.
According the principle of conservation of energy, the total kinetic energy is equal to the total potential energy.
\(P.E _i + K.E_i = P.E_f + K.E_f \\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\g(0) + \frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\\frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\v_i^2 = 2gh_f + v_f^2\\\\v_i^2 - 2gh_f = v_f^2\\\\v_f = \sqrt{v_i^2 - 2gh_f}\)
where;
\(v_i\) is the initial velocity of the roller coaster\(v_f\) is the final velocity of the roller coaster\(h_f\) is maximum height reached by the roller coasterThus, it is possible to determine the final speed of the rollercoaster if the initial speed and the height to be reached are known.
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Describe the differences between a HALL effect sensor and a permanent magnet sensor. Which one is more accurate?
The difference is that Hall effect sensor detects the strength of a magnetic field perpendicular to it, while a permanent magnetic sensor detects the angle of a parallel magnetic field.
The permanent magnetic sensor tends to be more accurate as it has a bigger detectable area that has detects layout error.
What is a magnet?
A magnet is any material that produces a magnetic field. A magnet has north and south poles at opposite ends.
The difference between a hall effect magnet and a permanent magnet sensor is that hall effect detects magnetics fields perpendicular to it while a permanent magnet detects magnetic fields parallel to it.
In conclusion, the permanent magnet is more accurate as it has a wider detectable area.
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what would happen if both dogs pulled the rope with a force of 85 N?
the rope wouldnt move, the force of both dogs pulling us also called tension
A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?
Answer:
85
Explanation:
soln
given that;
frequency=17Hz
wavelength=5m
speed?
formula for wavelength is;
wavelength= speed/frequency
then ; making v the subject formula
we have that v=wavelength*frequency
v=17*5=>85ms
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Your are part of a team to help design the atrium of a new building.Your boss, the manager of the project, wants to suspend a 6.2 kg sculpture high over the room by hanging it from the ceiling using thin, clear fishing line (string) so that it will be difficult to see how the sculpture is held up. The only place to fasten the fishing line is to a wooden beam which runs around the edge of the room at the ceiling.The fishing line that she wants to use will hold 10 kg so she suggests attaching two lines to the sculpture to be safe. Each line would come from the opposite side of the ceiling to attach to the hanging sculpture. Her initial design has the first line making an angle of 12.67∘with the ceiling and the second line making an angle of 16.15∘ with the ceiling. She knows you took physics, so she asks you if her design can work.
How much force would the first line exert on the beam holding it up?
Assume that g=9.8 m/s−2.
Answer:
The answer is below
Explanation:
Given that the mass of the sculpture (m) = 6.2 kg, \(\theta_1=12.67^o,\theta_2=16.15^o\)
\(Sum\ of\ horizontal\ force\ is\ zero\ hence:\\\\T_1cos(\theta_1)=T_2cos(\theta_2)\\\\T_1=\frac{T_2cos(\theta_2)}{cos(\theta_1)}\\ \\Sum\ of\ vertical\ force\ is\ zero:\\\\T_1sin(\theta_1)+T_2sin(\theta_2)=mg\\\\\frac{T_2cos(\theta_2)}{cos(\theta_1)}sin(\theta_1)+T_2sin(\theta_2)=mg\\\\T_2=\frac{mg}{\frac{cos(\theta_2)}{cos(\theta_1)}sin(\theta_1)+sin\theta_2} \\\\T_2=\frac{6.2*9.81}{\frac{cos(16.15)}{cos(12.67)}sin(12.67)+sin16.15} =123.1\ N\\\\\)
\(T_1=\frac{T_2cos(\theta_2)}{cos(\theta_1)}=121.2\ N\)
How do you know that light travels faster than
sound? (Hint: Give an example of something that
produces sound and light at the same time.)
Answer:
Explanation:
Answer
How about a thunder storm. I don't know if you live in a city or out in the sticks as I do. Lighting is very obvious and it is not a good idea to be out when experiencing a thunderstorm, especially in an open field. You might be the only thing around that will cause the lightning to be connected to the ground.# Seconds later, you will hear the thunder which is quite harmless. If you live in the city, observing this is not quite so easy. There are all kinds of buildings around and some of them may block your view.
#The great golfer, Lee Travino, was "hit" by lightening storm twice while playing in tournaments.
A person pushes a box across a horizontal surface at a constant speed of 0.5 meter per second The box has
a mass of 40 kilograms, and the coefficient of sliding friction is 0.25. The power supplied to the box by the
person is
a. 0.2 W
c. 50 W
b. 5W
d. 100 W
Answer:
The correct option
(C) 50W
-
Hope it help's u :))!
If you pull with a constant force of 400n , how much mechanical work does it take to pull pinball launcher back 0.2meters
If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.
What is Work?In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.
The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given information in the question,
Force, f = 400 N
Displacement, d = 0.2 meters
\(Work done(W)=Force(f)*Displacement(d)\)
W = 400 × 0.2
W = 80 J.
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Complete each of the statements
A. Lines of force are lines used to represent ________ an ________ electric field
B. The intensity of an electric field is the coefficient between the _________ that in the field exerts on a test ___________ located at that point and the value of said charge
C. The electric field is uniform if at any point in the field its _________ and ________ is the same
D. The van der graff generator is a _________ machine which has two __________ that are driven by a _________ that generates a rotation
Answer:
A: magnitude and direction
B: Force that the field exerts on a test charge
C: its magnitude and direction is the same.
D: electrostatic machine
two rollers that are driven by a motor that generates a rotation
Explanation:
A model rocket flies horizontally off the edge of a cliff at a velocity of 80.0m/s. If the canyon below is 128.0 m deep, how far from the edge of the cliff does the model rocket land?
a. 112m
b. 225m
c. 337m
d. 409m
Answer:
c. 337
Explanation:
can someone answer my question
You push a cart with mass 15 kg forward, giving it an acceleration of 3 m/s2
How much force did you apply?
A. 0.2N
B. 18 N
C. 45 N
D. 5N
Answer:
C 45 N
Explanation:
F = ma
F = 15 x 3 = 45 N
In a 41 s interval, 580 hailstones strike a glass window of area 1.346 m2 at an angle 31◦ to the window surface. Each hailstone has a mass of 7 g and speed of 6.7 m/s. If the collisions are elastic, find the average force on the window. Answer in units of N.
Answer:
The number of hailstones striking the window per unit time is:
n = 580 hailstones / 41 s = 14.1463 hailstones/s
The mass of each hailstone is 7 g = 0.007 kg, and its speed is 6.7 m/s. The kinetic energy of each hailstone is:
K = (1/2) * m * v^2 = (1/2) * 0.007 kg * (6.7 m/s)^2 = 0.167 N*m
The angle of incidence is 31°, so the angle between the hailstones and the normal to the window is 59°. The average force on the window is the rate of change of momentum of the hailstones. The momentum of each hailstone before the collision is:
p1 = m * v * cos(59°) * (-i) + m * v * sin(59°) * j
where i and j are the unit vectors in the x- and y-directions, respectively. The negative sign in front of the i-vector indicates that the hailstone is moving to the left (in the negative x-direction).
The momentum of each hailstone after the collision is:
p2 = m * v * cos(59°) * i + m * v * sin(59°) * j
The change in momentum of each hailstone is:
Δp = p2 - p1 = 2 * m * v * cos(59°) * i
The rate of change of momentum (i.e., the force) is:
F = n * Δp / Δt
where Δt is the time for each hailstone to strike the window. This time is equal to the width of the window divided by the component of the velocity perpendicular to the window, which is:
Δt = 1.346 m / (v * sin(59°)) = 1.346 m / (6.7 m/s * sin(59°)) = 0.139 s
Substituting the values, we get:
F = 14.1463 hailstones/s * 2 * 0.007 kg * 6.7 m/s * cos(59°) * (-i) / 0.139 s
F = 28.051 N * i
Therefore, the average force on the window is 28.051 N, in the negative x-direction.
Explanation:
The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths (the reddest colors) to the shortest wavelengths (the deepest violet colors) our eyes can detect. Wavelengths near 655 nm are perceived as red. Those near 515 nm are green and those near 475 nm are blue. Calculate the frequency of light (in Hz) with a wavelength of 655 nm, 515 nm, and 475 nm.
HINT
(a)
655 nm
Hz
(b)
515 nm
Hz
(c)
475 nm
Hz
Answer:
The frequency of light can be calculated using the formula:
`c = λv`
Where `c` is the speed of light in a vacuum, `λ` is the wavelength of light, and `v` is the frequency of light.
The speed of light in a vacuum is `3.00 × 10^8 m/s`.
To convert the wavelength from nanometers to meters, we need to divide by `1 × 10^9`.
Thus, the frequency of light with a wavelength of 655 nm is:
`v = c/λ`
`v = (3.00 × 10^8 m/s)/(655 × 10^-9 m)`
`v = 4.58 × 10^14 Hz`
Therefore, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`.
Similarly, the frequency of light with a wavelength of 515 nm is:
`v = c/λ`
`v = (3.00 × 10^8 m/s)/(515 × 10^-9 m)`
`v = 5.83 × 10^14 Hz`
Therefore, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz`.
Finally, the frequency of light with a wavelength of 475 nm is:
`v = c/λ`
`v = (3.00 × 10^8 m/s)/(475 × 10^-9 m)`
`v = 6.32 × 10^14 Hz`
Therefore, the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.
So, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz` and the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.
b. Density and relative density.
Explanation:
density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC
que estudia la estática?
Is Solar Energy renewable? Why or why not? Use in your own words.
Answer:
Solar energy is renewable.
Explanation:
If something is renewable, it is generated faster than it can be reasonably used or won't run out for longer than it would be used. Solar falls into the latter category. Using solar panels won't deplete the sun and the sun will likely be around for much longer than we will.
What is also a product in the chemical reaction of fusion?
A. Energy
B. Water
C. Sugar
D. Carbon dioxide
Answer:
D.
Explanation:
A
because energy is also a product
a girl whose mass is 40kg walk up a flight of 20steps each 15mm hight in 10seconds.find power developed by the girl showing the solution
Answer: Approximately 11.76 joules per second
=========================================================
Work Shown:
Mass = 40 kg
Force pulling down = (mass)*(gravity) = 40*9.8 = 392 newtons
Roughly 392 newtons of force are pulling down on her.
To climb the steps, she must apply 392 newtons of force upward.
---------------
Displacement = 20*(15 mm) = 300 mm = 0.3 m
Work = Force*Displacement
Work = 392*0.3
Work = 117.6 joules of energy
---------------
Power = (Work)/(Time)
Power = (117.6 joules)/(10 seconds)
Power = (117.6/10) joules per second
Power = 11.76 joules per second, which is approximate
The value of mass remains constant but weight changes place to place why
Explanation:
No matter where you are in the universe, your mass is always the same: mass is a measure of the amount of matter which makes up an object. Weight, however, changes because it is a measure of the force between an object and body on which an object resides (whether that body is the Earth, the Moon, Mars, et cetera).
Explanation:
Hence, weight of a body will change from one place to another place because the value of g is different in different places. For example, the value of g on moon is 1/6 times of the value of g on earth. As mass is independent of g , so it will not change from place to place.
The small spherical planet called "Glob" has a mass of 7.88×10^18 kg and a radius of 6.32×10^4 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×10^3 m, above the surface of the planet, before it falls back down.
1. What was the initial speed of the rock as it left the astronaut's hand? (Glob has no atmosphere, so no energy is lost to air friction. G = 6.67×10^-11 Nm2/kg2.)
2. A 36.0 kg satellite is in a circular orbit with a radius of 1.45×10^5 m around the planet Glob. Calculate the speed of the satellite.
Answer: The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down.
1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.
2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.
Explanation: To find the answer, we need to know about the different equations of planetary motion.
How to find the initial speed of the rock as it left the astronaut's hand?We have the expression for the initial velocity as,\(v=\sqrt{2gh}\)
Thus, to find v, we have to find the acceleration due to gravity of glob. For this, we have,\(g_g=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2}= 0.132\)
Now, the velocity will become,\(v=\sqrt{2*0.132*1.44*10^3} =19.46 m/s\)
How to find the speed of the satellite?As we know that, by equating both centripetal force and the gravitational force, we get the equation of speed of a satellite as,\(v=\sqrt{\frac{GM}{r} } =\sqrt{\frac{6.67*10^{-11}*7.88*10^{18}}{1.45*10^5} } =3.624km/s\)
Thus, we can conclude that,
1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.
2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.
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The tiny planet known as "Glob" has a radius of 6.32× 10^4 meters and a mass of 7.88× 10^18 kg. On Glob's surface, an astronaut launches a rock straight upward. Before falling back down, the rock rises to a maximum height of 1.44×10^3 m above the planet's surface.
1) The rock was moving at 19.46 m/s when it first left the astronaut's palm.
2) A 36.0 kg spacecraft is orbiting the planet Glob in a sphere with a radius of 1.45 105 meters. The satellite is moving at 3.624 km/s at that point.
Understanding the planetary motion equations is necessary in order to determine the solution.
How to determine the rock's original speed when it left the astronaut's hand?The starting velocity's expression is as follows:\(V=\sqrt{2gh}\)
So, in order to determine v, we must determine the acceleration of glob caused by gravity. We already have,\(a=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2} \\a=0.132m/s^2\)
The velocity will now change to,\(V=\sqrt{2*0.132*1.44*10^3} =19.46m/s\)
How can I determine the satellite's speed?As we are aware, the centripetal force and gravitational force are equivalent, and thus leads to the following satellite speed equation:\(v=\sqrt{\frac{GM}{r} } =3,624km/s\\where,\\M=7.88*10^{18}kg\)
Consequently, we can say that
1) The rock was moving at 19.46 m/s when it first left the astronaut's palm.
2) A 36.0 kg spacecraft is orbiting the planet Glob in a sphere with a radius of 1.45 105 meters. The satellite is moving at 3.624 km/s at that point.
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a device that spreads light into different wavelengths is a what?
maybe a spectrograph ?
A rifle is aimed horizontally at the center of a large target 60 m away. The initial speed of the bullet is 240 m/s. What is the distance from the center of the target to the point where the bullet strikes the target
Answer:
The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.
Explanation:
Given;
the position of center of the target, x₀ = 60 m
initial velocity of the bullet, u = 240 m/s
The time the bullet strikes the center of the large target is calculated as;
\(t = \frac{x_o}{u} =\frac{60}{240} = 0.25 \ s\)
The distance from the center of the target to the point where the bullet strikes the target is calculated as;
x = vt + ¹/₂gt²
where;
v is the final velocity of the bullet when it strikes the target = 0
x = 0 + ¹/₂(9.8)(0.25²)
x = 0.31 m
Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.
-0,32 m - 4.2 At the instant the marble leaves the canon, the canon starts moving backwards (recoils) at a constant velocity. 4.1 State the principle of conservation of linear momentum in words. that is stationary canon is placed 0,32 m from a fixed bare After firing, the canon takes 0,33 s to collide with a barrier at a distance of 0,32 m. Calculate the speed the: W< 1 >E S 4.2.1 Canon collides with the barrier
The cannon will completely stop when it collides with the barrier.
To calculate the speed at which the cannon collides with the barrier, we can follow these step-by-step calculations:
Determine the initial momentum of the system.
Since the cannon is initially stationary, the initial momentum is zero.
Apply the conservation of linear momentum.
According to the principle of conservation of linear momentum, the initial momentum of the system (zero) is equal to the final momentum of the system. The final momentum is the momentum of the cannon after firing.
Calculate the final momentum of the system.
Let's assume the mass of the cannon is represented by 'm' and the final velocity of the cannon is represented by 'v'. The final momentum of the system is given by: final momentum = m × v.
Set up the equation.
Since the initial momentum is zero, we have: 0 = m × v.
Solve for the final velocity of the cannon.
Dividing both sides of the equation by 'm', we get: v = 0.
Interpret the result.
The calculation shows that the final velocity of the cannon is zero. This means that the cannon comes to a complete stop when it collides with the barrier.
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explain the main development stages of the tropical hurricanes/cyclones and discuss their impacts according to the Saffir Simpson Hurricane Wind Scale
Answer:
The Saffir-Simpson Hurricane Wind Scale is a 1 to 5 rating based only on a hurricane's maximum sustained wind speed. This scale does not take into account other potentially deadly hazards such as storm surge, rainfall flooding, and tornadoes.
The Saffir-Simpson Hurricane Wind Scale estimates potential property damage. While all hurricanes produce life-threatening winds, hurricanes rated Category 3 and higher are known as major hurricanes*. Major hurricanes can cause devastating to catastrophic wind damage and significant loss of life simply due to the strength of their winds. Hurricanes of all categories can produce deadly storm surge, rain-induced floods, and tornadoes. These hazards require people to take protective action, including evacuating from areas vulnerable to storm surge.
Explanation:
pls mark as branlist.
Tropical hurricanes or cyclones are usually destructive with great wind speeds of 3 and above according to the Saffir Simpson Hurricane Wind Scale with huge amounts of rainfall resulting in flooding.
What is the Saffir Simpson Hurricane Wind Scale?The Saffir Simpson Hurricane Wind Scale is scale that classifies wind based on wind speed using a scale of 1-5.
This scale does not take into account wind surge, amount of rainfall and other characteristics of storms.
Storms rated 3 and above are particularly strong and destructive.
Those rated below 3 are mild and less destructive.
Tropical hurricanes or cyclones are usually destructive with great wind speeds of 3 and above according to the Saffir Simpson Hurricane Wind Scale with huge amounts of rainfall resulting in flooding.
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what are the property of the image formed by plane mirror
of class 10
Answer:
» The image is laterally inverted.
» The image is upright.
» The image geometry is same as object geometry.
» Image distance is same as object distance.
» Image is not real, it's virtual ( not formed on screen ).
\(.\)