which of these is an example of a description of speed?
a. An airplane traveled west from New York to Los Angeles
b. An apple fell from the three and then rolled 1-meter north
c. The average Olympic sprinter runs 8 m/s
d. A train traveled east at 200 mph from Albuquerque to Dallas​

Answers

Answer 1
Answer:
The answer is d cause it says that train travel 200 meters per hour
Answer 2
D) a train traveled east at 200 mph from Albuquerque to Dallas

Related Questions

the diagram below shows several forced acting on a small object the direction of the object acceleration is towards​

the diagram below shows several forced acting on a small object the direction of the object acceleration

Answers

The direction of the object acceleration is towards​ North West.

The given parameters:

Force at North, = 4 NForce at South, = 1 NForce at East, = 3 NForce at West, = 5 N, and 1 N

What is a net force?A net force is the sum of all the forces acting on an object.

The net force on the object is calculated as follows;

Vertical axis, = 4 N - 1 N = 3N north

horizontal axis, = 3 - (5 + 1)  = 3N west

The direction of the resultant force is North west

Thus, the direction of the object acceleration is towards​ North West.

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NEED HELP A 400 Ω resistor is connected across 200 V. What current will flow?Single choice.
(2 Points)

0.25 A

0.5 A

2.0 A

4.0 A

Answers

Answer: 0.5A

Explanation:

According to Ohm's law, the Voltage(V) when a current flows through a resistor can be calculated by using the formula:

V = IR

where,

V = Voltage = 200V

I = current in amps (A)

R = resistance in ohms (Ω) = 400Ω

Current = Voltage / Resistance

I = V/R

I = 200/400

I = 0.5A

Therefore, the current is 0.5 Ampere

What happens when an electron moves from a lower energy state to a higher energy state?

Answers

Answer:

Energy is absorbed by the atom

A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 33. 1 ◦C. In an attempt to cool the liquid, which has a mass of 185 g , 90. 3 g of ice at 0. 0 ◦C is added. At the time at which the temperature of the tea is 26. 3 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg · ◦ C. Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g. (2 significant digits pls)

Answers

The mass of the remaining ice in the jar is 45 g (to 2 significant digits).

Heat lost by tea = heat gained by ice

\(m_tea * c_tea * (T_f - T_i) = m_ice * c_ice * (T_f - 0) + m_ice * L_f\)

Substituting the given values, we get:

\(185 g * 4186 J/kg. C * (26.3 .C - 33.1.C) = m_ice * 4186 J/kg .C * (26.3 .C - 0C) + m_ice * 334 J/g\)

Simplifying and solving for m_ice, we get:

\(185 g * 4186 J/kg. C * (26.3 .C - 33.1.C) = m_ice * 4186 J/kg .C * (26.3 .C - 0C) + m_ice * 334 J/g\)

\(m_ice\)= 45 g

Mass is a fundamental property of matter that determines how it interacts with other objects through gravitational and inertial forces. Mass is often defined as the amount of matter in an object, measured in units such as kilograms (kg), grams (g), or pounds (lbs). Mass is also a key factor in determining the behavior of objects in gravitational fields.

Mass is a scalar quantity, which means it has only a magnitude and no direction. In contrast, force is a vector quantity, with both magnitude and direction. According to Newton's laws of motion, the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. This means that objects with more mass require more force to achieve the same acceleration as objects with less mass.

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What unit is force always in?
Pounds
Kilograms
Meters
Newtons

Answers

The answer would be newtons.

A block of mass 0.2 kg is launched by a spring k1 = 2.0 N/m as shown below. The block moves along a frictionless horizontal table and pushes another spring, k2 = 1.1 N/m , to the maximum deflection x . If the initial deflection of the spring k1 is 0.050 m , what is the maximum deflection of spring k2 ?

Answers

Please mark brainliest if the answer is true

We can use conservation of mechanical energy to solve this problem. At the point where the block is launched from the spring, all the energy is in the form of potential energy stored in the spring. When the block reaches the maximum deflection x of spring k2, all the energy is in the form of potential energy stored in spring k2.

The potential energy stored in a spring is given by U = (1/2) k x^2, where k is the spring constant and x is the deflection from the equilibrium position.

At the initial point, the potential energy stored in spring k1 is:

U1 = (1/2) k1 x1^2
= (1/2) (2.0 N/m) (0.050 m)^2
= 0.000125 J

At the point where the block reaches the maximum deflection x of spring k2, the potential energy stored in spring k2 is:

U2 = (1/2) k2 x^2

Conservation of energy tells us that the potential energy at the two points must be equal:

U1 = U2

Substituting in the values for U1 and k2, we get:

0.000125 J = (1/2) (1.1 N/m) x^2

Solving for x, we get:

x^2 = (0.000125 J) / (0.55 N/m)
x^2 = 0.0002273
x = 0.0151 m

Therefore, the maximum deflection of spring k2 is 0.0151 m.

The maximum deflection of the spring k2 is approximately 0.31 m.

What is spring constant?

The spring constant, k, is a measure of the spring's stiffness. It varies depending on the spring and material. The greater the spring constant, the stiffer the spring and more difficult to stretch.

To solve this problem, we can use conservation of energy and Hooke's law.

1/2 k1 x\(1^2\) = 1/2 m \(v^2\)

v = \((2 k1 x1 / m)^{0.5\) = \((2 x 2.0 N/m x 0.050 m / 0.2 kg)^{0.5\) ≈ 0.5 m/s

1/2 m \(v^2\) = 1/2 k2 \(x^2\)

x = \((m v^2/ k2)^{0.5\) =\((0.2 kg x (0.5 m/s)^2 / 1.1 N/m)^{0.5\) ≈ 0.31 m

Therefore, the maximum deflection of the spring k2 is approximately 0.31 m.

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As a fish swims deeper into the ocean, the pressure on its body is

a. decreases
b.increases

Answers

Answer: increases

Because more water is pushing on an object as it goes more beneath the surface, there is more pressure on the object. Therefore, the pressure increases with depth.

So, your answer is b: increases.

As a fish swims deeper into the ocean, the pressure on its body is:

b.increases

The pressure on the upper surface of the water is the lowest where there is not so much water as of little water pressure, along with a little atmospheric pressure, but if you go deep inside the water the pressure will increases. As on the lower surface of water, the pressure is highest due to heavy water pressure from upwards along with atmospheric pressure. So if a fish swims deeper into an ocean the water will exert more pressure than it is on the upper, to the body of the fish, so the pressure increases.

Rank these objects from left to right based on the distance from the Sun at which they are presumed to have formed, from nearest to farthest.
a typical asteroid in the asteroid belt, a typical Oort cloud object, a typical Kuiper belt object

Answers

Based on the distance from the Sun at which they are presumed to have formed, the objects can be ranked as follows (from nearest to farthest):

1. A typical asteroid in the asteroid belt
2. A typical Kuiper belt object
3. A typical Oort cloud object

A typical asteroid in the asteroid belt: The asteroid belt is a region of the solar system between the orbits of Mars and Jupiter, and most asteroids are thought to have formed in this region.

A typical Kuiper belt object: The Kuiper belt is a region of the solar system beyond the orbit of Neptune that contains many small icy bodies, including dwarf planets like Pluto.

A typical Oort cloud object: The Oort cloud is a hypothetical region of the solar system far beyond the Kuiper belt, where many comets are thought to originate. Oort cloud objects are believed to have formed at the very edges of the early solar system and to have been scattered to their current positions by the gravitational influence of the gas giants.

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the two masses in the figure are released from rest. after mass has fallen , it is moving with a speed of . mass has a mass of an mass has a mass of , and the pulley is frictionless. how much work is done during this time interval by the frictional force on block ?

Answers

Two masses m1=5 kg and m2=10 kg, connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of the horizontal surface is 0.15. The minimum weight m1 should be put on top of m2 to stop the motion seen in the image below.

From FBD of mass m1

​we get t=5g

to stop the motion T≤μ(m2 +m)g

=>5g≤0.15(10+m)g

=>m≥23.3kg

so the minimum mass that can stop motion is 23.3kg.

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the two masses in the figure are released from rest. after mass has fallen , it is moving with a speed

Write a message to Mr. Chang explaining why the groundwater heating system will warm the school more than the water heater system. Use evidence to support your claim. For each piece of evidence you use, explain how the evidence supports your claim.

Answers

Answer:

For, heating purposes more the quantity of  water more will be the heating. Clearly, underground heating would have more water and hence, it will have edge over the  water heater system.

Moreover, for things at the same temperature, the thing with more molecules has more total kinetic energy (thermal energy) than the thing with fewer molecules. The groundwater heating system uses heat from the heat stored naturally in groundwater or aquifers. Thus, saving the cost of power required to heat in normal water heater.

Explanation:

The groundwater heating system will warm the school more than the water heater system due to the fact that it uses more water more than the other system.

Based on the complete question, it should be noted that the addition of energy leads to an increase in motion which results in the rise in temperature.

The groundwater heating system will warm the school more than the water heater system due to the fact that it uses more water more than the other system even though its water isn't as warm as in the other system.

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Fy is the reaction force from Plate Y. What Statement best describes the action and reaction forces on the plates? Tectonic plates

Answers

Answer:

According to Newton's third law of motion, the reaction force is equal to the action force.

Explanation:

Newton's third law of motion states that for every action there is an equal and opposite reaction. This means that if one object exerts a force on a second object, the second object exerts an equal force in the opposite direction. When Plate X pushes on Plate Y with the action force (Fx), Plate Y must push back with an equal force (Fy).

Therefore, the best explanation is that according to Newton's third law of motion, the reaction force is equal to the action force.

For every action, there has equal and opposite reaction - this statement best describes the action and reaction forces on the plates.

What is Newton's 3rd law of motion?

As a result of this interaction, there are two forces: one from plate X and one from plate Y. The third law of motion of Newton deals with these two forces, which are referred to as action and reaction forces. Newton's third law is officially expressed as follows: There is an equal and opposite reaction to every action.

The implication of the statement is that there are always two forces acting on the two interacting objects. The force acting on the first object is equal in size to the force acting on the second. The force acting on the first object is acting in the opposite direction to the force acting on the second object. Force pairs—equal and opposing action-reaction force pairs—always exist in pairs.

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a 83.0-kg person is riding in a car moving at 20.0 m/s when the car runs into a bridge abutment. calculate the average force on the person if he is stopped by a padded dashboard that compresses an average of 1.00 cm.

Answers

The average force applied to the person when he stopped by a padded dashboard is 166×10⁴ N.

An external force is an agent that has the power to alter the body in moving or resting conditions. It can also be described as a push or a pull. It is a vector quantity so it has both direction and magnitude.

The formula to calculate the force applied on an object is F=m×a. Where F is force, a is the acceleration, and m is the mass of an object,

Given mass (m) is 83 kg, initial velocity (u) is 20 m/s, and displacement (s) is 1 cm.

When the dashboard is compressed to stop a car, then the acceleration is calculated using the formula v²=u²+2as where v is final velocity, u is initial velocity, a is acceleration, and s is displacement. Initially, the final velocity is zero. Solving we get,

\(\begin{aligned}0&=u^2+2as\\u^2&=-2as\\20^2&=-2\times a\times0.01\\a&=\mathrm{-20000\;m/s^2}\end{aligned}\)

The negative sign indicates that the car is slowing down or decelerating.

The average force on the person riding the car is given by,

\(\begin{aligned}F&=83\times 20000\\&=\mathrm{166\times 10^4\;N}\end{aligned}\)

The answer is 166×10⁴ N.

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a 7.80 nc charge is located 1.69 m from a 4.54 nc point charge. (a) find the magnitude of the electrostatic force that one charge exerts on the other.

Answers

The electric force acting on a 7.80 nc charge that is located 1.69 m from a 4.54 nc point charge is: 1.115*10^-7 N

To solve this exercise the electric force formula and the procedure we will use is:

F = (k * q1 * q2)/r²

Where:

F = electric forcek = coulomb constantq1 = charge 1q2 = charge 2r = separation distance of the charges

Information about the problem:

q1= 7.80 ncq2= 4.54 ncr = 1.69 mF =?k= 9 *10^9 N*m²/C²1 C = 1*10^ 9 nC

By converting the the values of the charges (q1) and (q2) from (nC) to (C) and we have that:

q1= 7.80 nC * 1 C/ 1*10^ 9 nC

q1= 7.8*10^ -9 C

q2= 4.54 nC * 1 C/ 1*10^ 9 nC

q2= 4.54 *10^ -9 C

We apply the electric force formula we have:

F = (k * q1 * q2)/r²

F = [(9 *10^9 N*m²/C² * (7.8*10^ -9 C) * (4.54 *10^ -9 C)]/ (1.69 m)²

F = 3.187*10^-7 N*m² /2.8561 m²

F = 1.115*10^-7 N

What is electric force?

In physics the electric force is the force that attracts or repels two charges (q) separated at a distance called (r), this is expressed in the international system of units in Newton.

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a 7.80 nc charge is located 1.69 m from a 4.54 nc point charge. (a) find the magnitude of the electrostatic

You run around neyland stadium. when you are halfway around the stadium, which value cannot be 0?
a) instantaneous speed
b) average speed
c) instantaneous acceleration
d) average acceleration

Answers

When you are halfway around the stadium, average speed value cannot be 0.

Average speed = Total distance travelled / Time taken.

Since you ran halfway across the stadium, a certain amount of distance has been covered. The only way the average speed can be zero is if you remained stationary over a given interval of time.

In a distance-time graph, at the halfway point in the stadium, slope is equal to zero. So, Instantaneous speed is zero. In a Velocity-time graph, at the halfway point in the stadium, slope is equal to zero. So, Instantaneous acceleration is zero. In a Velocity ( w.r.t. time )-time graph, at the halfway point in the stadium, slope is equal to zero. So, Average acceleration is zero.

Therefore, when you are halfway around the stadium, average speed value cannot be 0.

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A5 kg football is launched 45 degrees above the horizontal at a speed of 26 m/s.
What is the time of flight for the football from the point it left the ground until it hit the ground?

Answers

time to teach the highest point t
V = u + at
0= 26 Sin (45) - 9.8 t
9.8 t = 18.4
t = 1.88 seconds.
Total time in flight = 2 x 1.88 = 3.76 s

Help!! will give brainliest

Help!! will give brainliest

Answers

The area of each cylinder is 50.27 in² and 113.10 in² for both input and output respectively.

The pressure in the system is 1.98 psi.

The force the output cylinder can lift is 225 lb.

The mechanical advantage of the system is 2.25.

How to solve mechanical advantage?

I) The area of a circle is calculated by the formula:

Area = πr²

Where π = mathematical constant with an approximate value of 3.14, and r = radius of the circle.

The radius of the input cylinder is 4 inches, so the area of the input cylinder is:

Ain = πr² = 3.14 × 4² = 50.27 in²

The radius of the output cylinder is 12 inches, so the area of the output cylinder is:

Aout = πr² = 3.14 × 12² = 113.10 in²

II) Pressure is calculated by the formula:

Pressure = Force / Area

The force applied to the input cylinder is 100 pounds, and the area of the input cylinder is 50.27 square inches, so the pressure in the system is:

P = F / A = 100 lb / 50.27 in² = 1.98 psi

III) The mechanical advantage of a hydraulic press is calculated by the formula:

MA = Aout / Ain

The area of the output cylinder is 113.10 square inches, and the area of the input cylinder is 50.27 square inches, so the mechanical advantage of the system is:

MA = Aout / Ain = 113.10 in² / 50.27 in² = 2.25

The force that the output cylinder can lift is equal to the force applied to the input cylinder multiplied by the mechanical advantage of the system.

So, the force that the output cylinder can lift is:

Fout = Fin × MA = 100 lb × 2.25 = 225 lb

IV) The mechanical advantage of a hydraulic press is the ratio of the force that the output cylinder can lift to the force that is applied to the input cylinder. In this case, the mechanical advantage of the system is 2.25. This means that the output cylinder can lift 2.25 times as much force as is applied to the input cylinder.

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please help i give brainest but i need help asap

please help i give brainest but i need help asap

Answers

Answer:

Surface

Explanation:

Rayleigh Waves—surface waves that move in an elliptical motion, producing both a vertical and horizontal component of motion in the direction of wave propagation. Particle motion consists of elliptical motions (generally retrograde elliptical) in the vertical plane and parallel to the direction of propagation.

Bob walks to Jack's house. He walks 900 meters East then realizes that he walked too far. He turns around and walks 300 meters West. The entire walk takes him 15 seconds. What was his speed per second?

Answers

Bob's average speed was 80 m/s.

His average velocity was 40 m/s East.

The magnitude of his velocity was almost 4 times as fast as Usain Bolt's world record in the 100 meters, or about 89 mph. His speed was double that.

Particles q1 = -66.3 UC, q2 = +108 uC, and 93 = -43.2 uC are in a line. Particles q1 and q2 are separated by 0.550 m and particles q2 and q3 are separated by 0.550 m. What is the net force on particle q2?

Answers

The sum total of all forces which are acting on an object is known as the net force. A mass can accelerate due to the net force.

What is net force?

The net force can be defined as the sum total of all the forces which are acting on an object. Net force can accelerate a mass. Some other force also act on an object either at rest or motion.

Here, r₁₂ = 0.550m r₂₃ = 0.550m. Then the distance from the first charge to the third one will be:

r₁₃ = r₁₂ + r₂₃ = 0.550 + 0.550 = 1.1m

According to the Coulomb's law, the net force on particle q₂ will be equal to the sum of the forces on particle q₂ from the particle q₁ and q₃.

F₃+ = F₁₃ +F₂₃ = q₁q₂/r²₁₃ + k q₃q₂/r²₂₃

Where, k = 9 × 10⁹ N m²/C²

Substituting numerical values, we obtain:

F₃ = 9 × 10⁹ (-66.3 × 10⁻⁶)(-43.2 × 9 × 10⁻⁶)/ 1.45² + 9 × 10⁹ × 108 × 10⁻⁶ (-43.2 × 10⁻⁶) / 0.550²

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Hello people ~
Which of the following statement is true?
(a) Electrostatic force is a conservative force.
(b) Potential at a point is the work done per unit charge in bringing a charge from any point to infinity.
(c) Electrostatic force is non-conservative
(d) Potential is the product of charge and work.

Answers

Answer:

In case of electrostatic force, the work done is independent of path, it only depends on the final and initial positions of the charge. This path independent nature makes electrostatic force a conservative force. Thus, the option a becomes true, and the opposite statement (ie.

Answer:

Option A

Explanation:

As we know that electrostatic force is path independent

It is the force present between the charges of atoms .

Hence it's conservative force.

Un texto de opinión sobre la situación actual del rol de la mujer, el trabajo y las situaciones de violencia en el contexto de Pandemia. Cambió la situación de las mujeres?

Answers

Explanation:

Los derechos de las mujeres fueron conquistados a través de importantes luchas llevadas a cabo por mujeres, como el movimiento feminista que tuvo lugar a fines del siglo XIX, cuyo principal reclamo fue el derecho al voto de las mujeres.

Con el tiempo, las mujeres ganaron más derechos y una mayor participación en el mercado laboral y en puestos importantes de la sociedad. Pero aún queda mucho por cambiar, ya que las estadísticas aún muestran que hay pocas mujeres en posiciones de poder en relación a los hombres, y el salario de una mujer que ocupa el mismo puesto que un hombre es siempre menor.

Dado que la sociedad se concibió a través de parámetros sexistas, lo que continúa en la actualidad, es claro que en la pandemia específicamente que generó crisis económicas en todo el mundo, se vio a una gran cantidad de mujeres perder sus empleos, además del expresivo número de casos de violencia doméstica que se agravaron en el período de aislamiento social.

Así que estos hechos solo demuestran que la lucha por la igualdad de género y los derechos de las mujeres aún están en sus inicios, a pesar de muchos logros que las mujeres aún deben luchar por lo básico, que es el apoyo social y político además de una legislación más estricta que castiga con más rigor a las agresoras. Las mujeres deben estar protegidas por la ley y las instituciones y los medios de comunicación deben abordar más el tema y promover el feminismo como una lucha por la igualdad.

The work done on an object is equal to the force times the distance moved in the direction of the force. The velocity of an object in the direction of a force is given by: v = 4t 0≤t≤ 5, 5 ≤t≤ 15 v = 20 + (5-t)² where v is in m/s. With step size h=0. 25, determine the work done if a constant force of 200 N is applied for all t a) using Simpson's 1/3 rule (composite formula) b) using the MATLAB function trapz

Answers

A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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Which statement about this figure is false


A. Line E represents a fault line.


B. Layer C is the youngest layer.


C. d,ike K is older than layer I.


D. The fault occurred after layer F formed.

Which statement about this figure is falseA. Line E represents a fault line.B. Layer C is the youngest

Answers

The statement about the figure that is false is that d,ike K is older than layer I. That is option C.

What is cross-cutting relationships in geology?

Cross-cutting relationships is a principle that when a body pass through different layers in geology, it is usually younger than all the layers it passed through.

That is to say that, d,ike K is younger than layer I, D and B which it passed through.

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Answer:

If it's not C then it HAS to be B.

Explanation:

By deductive reasoning.

A Over ordinary temperature ranges, the resistance of most metals such as copper increases as the metal gets hotter. O decreases as the metal gets hotter. is a maximum at 20°C. is independent of the temperature of the metal. Submit Request Answer Provide Feedback

Answers

The correct option is A: Over ordinary temperature ranges, the resistance of most metals such as copper increases as the metal gets hotter.

Most metals including copper have a temperature coefficient of resistance, which means that their resistance increases with temperature. Over ordinary temperature ranges, the resistance of most metals such as copper increases as the metal gets hotter. For instance, an increase in temperature results in an increase in the number of collisions of free electrons with ions, which makes the free electrons move at a slower rate through the material. This reduces the drift current, causing an increase in resistance. When temperature decreases, the opposite occurs and resistance decreases. This temperature dependence is critical for temperature sensors, temperature control devices, and temperature compensation circuits.The maximum amount of resistance that a metal can provide is proportional to its size, type, and composition. However, the resistance of metals increases at lower temperatures. They behave like superconductors and lose all of their electrical resistance at extremely low temperatures.

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a wooden block of mass 1200g, which moves on a horizontal surface, is subjected to a frictional force of 3 N. How much frictional force will act on the block if we put a 500g weight on it?​

Answers

Answer:

Approximately \(4.25\; {\rm N}\) as long as the wooden block continues moving.

Explanation:

Since the wooden block is moving, the friction on the block will be kinetic friction. This friction will be proportional to the magnitude of the normal force on the block. Specifically:

\(\begin{aligned}& (\text{kinetic friction}) \\ =\; & (\text{normal force})\, (\text{kinetic friction coefficient $\mu_{k}$}) \end{aligned}\).

In this question, since the surface is horizontal, the only vertical forces on this block will be:

Weight of the block \((\text{weight}) = (\text{mass})\, g\) where \(g\) is the gravitational field strength, andNormal force on the block.

These two forces will balance each other. Thus, \((\text{normal force}) = (\text{weight})\).

\(\begin{aligned}(\text{normal force}) &= (\text{weight}) \\ &= (\text{mass})\, g\end{aligned}\).

Substitute to obtain:

\(\begin{aligned}& (\text{kinetic friction}) \\ =\; & (\text{normal force})\, (\text{kinetic friction coefficient $\mu_{k}$}) \\ =\; & (\text{mass})\, (\text{kinetic friction coefficient $\mu_{k}$})\, g\end{aligned}\).

In other words, the kinetic friction on the block is proportional to the mass. As long as the block continues moving, increasing mass from \(1200\; {\rm g}\) to \((1200 + 500)\; {\rm g} = 1700\; {\rm g}\) will increase friction to \((1700 / 1200) = (17/12)\) the initial value, \((17/12)\, (3\; {\rm N}) \approx 4.25\; {\rm N}\).

What has gravity led scientists to understand?

Answers

Answer:

Gravity is a non-contact force that was observed famously by Sir Isaac Newton, who watched an apple falling from a tree to the ground. ... Newton was the first to realise that gravity existed in space and it was the force which holds the Moon in orbit around the Earth and planets in orbit around the Sun.

Answer:

Newton's theory had prove that all objects, as small as an apple and as large as a planet, are subjected to gravity. Gravity helped to keep the planets rotating around the sun and creates the ebbs and flows of rivers and tides.

NEED HELP ASAP 40 POINTS L!!!! Jaden is interested in learning more about the basics of astrono ny and looking more closely at the sky all by himself. He wantS to get a basic starter telescope to help him with this endeavor, and his teacher SuggestS an organization that might be able to help him with this. What organization is Jaden's teacher likely referring to? The Little Astronomers Celestial Sightseeing Group The Beginning Astronomy Organization Astronomers Without BordersS​

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The little Astronomers

a small but rigid u shaped wire carrying a 5.0 a current is placed inside a solenoid the solenoid is 17 cm long and has 800 loops of wire and the current in each loop is

Answers

The current in each loop of the solenoid is 6.25 A. current is placed inside the solenoid, we can assume that the current passing through each loop is the same.

The solenoid is 17 cm long and has 800 loops of wire. Since the wire carrying the 5.0 A current is placed inside the solenoid, we can assume that the current passing through each loop is the same.

To find the current in each loop, we can use the formula:

I_solenoid = N * I_wire

Where:

I_solenoid is the current in the solenoid,

N is the number of loops,

I_wire is the current in the wire.

Plugging in the values, we have:

I_solenoid = 800 * I_wire

5.0 A = 800 * I_wire

Solving for I_wire, we get:

I_wire = 5.0 A / 800 = 0.00625 A

Therefore, the current in each loop of the solenoid is 6.25 A.

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what is the probable origin of the dark colored features in this image of the surface of mars? it is about 20 km across.

Answers

The probable origin of the dark colored features in the surface of mars for about 20 kilometers across are dunes shaped by the wind.

Explanation:

Dunes are familiar features on Earth and they also occur on Mars, Venus, and Saturn's moon, Titan. What all these bodies have in common is an atmosphere, plus substantial amounts of loose sand-size particles. Of all the extraterrestrial dunes scientists know about, those on Mars are the most closely studied.

A dune is a heap of sand piled up and shaped by the wind. (Underwater dunes exist on Earth, but we can ignore these in regard to today's Mars.) The word "dune" implies a substantial size — at least several meters (yards) high. But small ripples of sand only a few centimeters (inches) high are made in the same way from the same materials. The difference lies mainly in the supply of particles and how much time the wind has had to work on them.

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An airplane flying horizontally at a constant 200 m/s makes a banked u-turn that takes 4.0 min. what bank angle is required? what is the percentage increase in the perceived weight of the passengers? assume that the plane has a lift force which is oriented perpendicular to the wings.

Answers

An aero plane flying horizontally at a constant speed of 200 m/s makes a banked u-turn in 4.0 minutes, increasing the perceived weight of the passengers by 13.33%.

Speed must be a scalar variable because there is no directional component. The total distance travelled and the total time needed to travel that distance are used to compute average speed in physics. Speed is the rate of change in location of an item, expressed in metres per second. Distance travelled in a unit of time is referred to as speed. It is the rate of movement of an object. Speed is a scalar quantity and the velocity vector's magnitude.

percentage increase = N/mg *100

percentage increase = mg/cos(0)/mg *100

percentage increase = 1/cos(28)*100

percentage increase = 13.3%

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